Insert a space in the string

Similar Questions

• regular expression to exclude spaces in the string

  Now that I'm that sleazy, I need help with a regular expression.

  They must pass (or permutations it):

  [00123]

  [R012]

  [r083]

  These should fail (or permutations it):

  [test]

  [I was here]

  [098 876]

  Ooh [29873 eifvuh]]

  I have most of it (the ' [' must be first; the '] "must be the last;) There must be some middle numbers, but I can't write an expression that will fail if there are 1 or more spaces in the string.

  Thank you!

  Tay

  Several possibilities: try this regular expression.

  ^\[[a-za-Z]*[0-9]+[a-zA-Z0-9]*\]$

• Count the spaces in the string...

  Hi, I use "PL/SQL Developer" program.
  I need to count the number of spaces in the string...
  Can someone help me with this...?
  
  String, for example: 'One AsdA qwe' should return number = 2 - (2 spaces in this string)

  Raivis wrote:
  Hi, I use "PL/SQL Developer" program.
  I need to count the number of spaces in the string...
  Can someone help me with this...?

  String, for example: 'One AsdA qwe' should return number = 2 - (2 spaces in this string)

  This should do it.

  LENGTH() - LENGTH(REPLACE(, ' '))
  

• Insert a space in a string

  I need to insert a space after every eight characters in a string.
  For example:

  < cfset mytoken = "ABCDEFGHIJKLMNOPQRSTUVWXYZABCDEFGHIJKLMNOPQRSTUVWXYZABCD" >

  < cfoutput >
  < cfset replaceChar = "" >
  < cfset mytoken = Insert (replaceChar, mytoken, 8) >
  < cfset mytoken = Insert (replaceChar, mytoken, 17) >
  < cfset mytoken = Insert (replaceChar, mytoken, 26) >
  < cfset mytoken = Insert (replaceChar, mytoken, 35) >
  < cfset mytoken = Insert (replaceChar, mytoken, 44) >
  < cfset mytoken = Insert (replaceChar, mytoken, 53) >
  < cfset mytoken = Insert (replaceChar, mytoken, 62) >
  MyToken: #mytoken # < br / >

  
  The above gives me results as
  MyToken:ABCDEFGH QRSTUVWX YZABCDEF GHIJKLMN OPQRSTUV WXYZABCD IJKLMNOP

  
  Can I get the same result by using a regular expression and reduce code?

  Not quite, but almost. This:

  reReplaceNoCase (mytoken, "([a-z][0-9]{1,8})", "\1", "all")

  Means "a letter, followed by one to eight digits. You need:

  reReplaceNoCase (mytoken, "([a-z |)") (0-9]_{1,8}) ', '\1', 'all')

  That means one-to-eight letters or numbers. As Adam pointed out earlier, you can further simplify:

  reReplaceNoCase (mytoken, "([a-z |)") (0-9]_{8}) ', '\1', 'all')

• Remove the spaces from the string

  Hello
  Does anyone have a simple routine/function to remove all but 1 space between "words" (row charactives no spaces).
  
  For example, I would convert the string (I used '.' as a 'space'):
  
  'This... too... a lot of people of spaces' to
  'This.has.too.many.spaces '.
  
  I need this to compare strings of registration where a user can hit the space bar one extra time or 2.
  
  Thanks in advance.

  hefterr wrote:
  > Thank you Dan. This seems good.
  > Can I use...
  > Is not sure the quotes for 2
  > spaces

  You need quotes replacement in case of nesting them like this... Make your choice.

  
  OR
  

• Trim white spaces in the string.

  Hi all
  
  I want to know how to cut the white space in the whole of the line when reading the file. For that, the threshold is,
  
  October 7, 2010, DRI DEV, 07A0002EE, BIOS 0.75FAWARM 2.003, DRI, 215461 D, 2.0.5-O,, manson, COMPUTING equipment, 07A0002EE '
  I use the regexp_replace function. but I'm not able to use the appropriately. See the following query:
  
  Select trim (regexp_replace (October 7, 2010, DRI DEV, 07A0002EE, BIOS 0.75FAWARM 2.003, DRI, 215461 D, 2.0.5-O,, manson, COMPUTING equipment, 07A0002EE ',' [[: space :]]')) text]]))
  Double;
  
  o/p: 10/7/2010,,DRIDEV,,07A0002EE,BIOS0.75FAWARM2.003,DRI,,215461D,2.0.5-O,,,manson,GearIT,07A0002EE. Here, the space also replacement including white spaces. I don't want to replace only the remaining spaces space need as expected o/p.
  
  EXPECTED O/p: 07/10/2010, DRI DEV, 07A0002EE, BIOS0.75FAWARM2.003, DRI, 215461 D, 2.0.5-O,, manson, Gear IT, 07A0002EE
  
  Oracle version:
  
  Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - 64bi
  PL/SQL Release 10.2.0.4.0 - Production
  CORE 10.2.0.4.0 Production
  AMT for IBM/AIX RISC System/6000: release 10.2.0.4.0 - production
  NLSRTL Version 10.2.0.4.0 - Production
  
  Please help me.
  
  
  
  Thanks in advance!
  
  Kind regards
  Florian...

  select
  regexp_replace(
    regexp_replace('10/7/2010,,DRI DEV,,07A0002EE                           ,BIOS 0.75FAWARM 2.003     ,DRI,,215461 D ,2.0.5-O     ,,,,manson,Gear IT,07A0002EE'
    ,'^\s+|\s+$')
  ,'\s*,\s*'
  ,',')
   from dual
  

  Kind regards
  Sayan M.

• How can we remove the present space in the string in BlackBerry?

  Hello

  Suppose I have string like "New York". How can I remove the space between and do like "New York". As BlackBerry does not support the Java replaceAll() method, I am not able to do.

  Thank you...

  StringUtilities.removeChars (...)

• Print every word in the new line for a space in a string

  Hi all

  I would print every word in the new line, if there is a space in the string.

  Is there a better way using regexp?

  declare

  number of v_count;

  v_text varchar2 (1000): = 'Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - Production | " ';

  v_single_text varchar2 (1000);

  number of v_space_pos;

  Start

  Select regexp_count (v_text,' ') in double v_count;

  While v_count > 0

  loop

  v_space_pos: = instr (v_text,' ');

  v_single_text: = substr(v_text,1,v_space_pos-1);

  dbms_output.put_line (v_single_text);

  v_text: = substr (v_text, v_space_pos + 1);

  v_count: = v_count-1;

  end loop;

  end;

  Thank you

  Rambeau

  HI - try as

  with t as (select 'Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - Production' |) "" double str)

  Select regexp_substr (str,'[^] +', 1, level)

  t

  connect by level<=regexp_count(str,'[^>

• Spaces in the domain LDAP OR

  Hello

  I am running SSL VPN on a asa 5520 (V8.2.5) with LDAP authentication and everything works fine but now the AD people changed its name in groups and they added a "" "in white" in one of the fields when I set up the group I get an error.

  for example:

  It works:

  map-value memberOf CN = VPN_SSL_ABC, OU = external, OU = XXX, DC = ext, DC = local ABCPolicy

  but this is not:

  map-value memberOf CN = VPN_SSL_ABC, OU = external group, OU = XXX, DC = ext, DC = local ABCPolicy

  Is it possible to insert a space in the field of the OU?

  Thanks in advance

  Giovanni

  Yes, just put the quotes for the attribute memberOf as follows:

  map-value memberOf "CN = VPN_SSL_ABC, OU = external group, OU = XXX, DC = ext, DC = local" ABCPolicy

• I'm trying to extract the strings and load them into a text-helpplease file

  I'm trying to extract the strings and load them into a file text without space between them - see below
  
  p_csa = ISCC M4 DP
  
  where p_csa is a tring to load into a text file
  
  
  
  Code:
  
  SELECT SUBSTR (p_csa, 0, 0) INTO v_telco FROM DUAL;
  SELECT SUBSTR (p_csa, 1, 4) INTO v_comp FROM DUAL;
  SELECT SUBSTR (p_csa, 5.3) INTO v_csa_prefix FROM DUAL;
  SELECT SUBSTR (p_csa, 8, 4) INTO v_csa_type FROM DUAL;
  
  fileidinvoice: = UTL_FILE. FOPEN (c_data_location, filenameinvoice, 'W');
  fileidlog: = UTL_FILE. FOPEN (c_data_location, filenamelog, 'W');
  
  UTL_FILE. PUT_LINE)
  fileidinvoice, v_telco | » '|| v_comp | "|" | v_csa_prefix: "| v_csa_type);
  
  
  -the content of the file-
  
  ISCC M4 DP
  
  =====================
  I want to remove the space between the chain above for the content of the file should look like this:
  
  -the content of the file-
  
  GCSIM4DP

  Hello

  976253 wrote:
  I'm trying to extract the strings and load them into a file text without space between them - see below

  p_csa = ISCC M4 DP

  where p_csa is a tring to load into a text file

  Code:

  SELECT SUBSTR (p_csa, 0, 0) INTO v_telco FROM DUAL;

  Is it always NULL?

  SELECT SUBSTR (p_csa, 1, 4) INTO v_comp FROM DUAL;

  You don't need the double table much in PL/SQL. You can simply say

  v_comp := SUBSTR (p_csa, 1, 4);
  

  Almost all integrated single-row functions work in PL/SQL. (NVL2 is the only one I know who does not work in PL/SQL).

  SELECT SUBSTR (p_csa, 5.3) INTO v_csa_prefix FROM DUAL;
  SELECT SUBSTR (p_csa, 8, 4) INTO v_csa_type FROM DUAL;

  fileidinvoice: = UTL_FILE. FOPEN (c_data_location, filenameinvoice, 'W');
  fileidlog: = UTL_FILE. FOPEN (c_data_location, filenamelog, 'W');

  UTL_FILE. PUT_LINE)
  fileidinvoice, v_telco | » '|| v_comp | "|" | v_csa_prefix: "| v_csa_type);

  What are you trying to do here? For example, what you're trying to put between c_comp and v_csa_prefix?

  -the content of the file-

  ISCC M4 DP

  =====================
  I want to remove the space between the chain above for the content of the file should look like this:

  -the content of the file-

  GCSIM4DP

  If you don't want space, then only concatenate all the spaces in the string before you write it and REPLACE allows you to delete all the spaces that have been copied from p_csa. For example:

  UTL_FILE.PUT_LINE ( fileidinvoice
              , REPLACE ( v_telco || v_comp
                                      || v_csa_prefix
                            || v_csa_type
                     , ' '
                     )
              );
  

  I guess you need the v_comp of separate variables, the v_csa_prefix and the v_csa_type for something.

  I hope that answers your question.
  If this isn't the case, after a complete script that people can run to recreate the problem and test their ideas. Display the results you want (in other words, the contents of the file created).
  Always say what version of Oracle you are using (for example, 11.2.0.3.0).
  See the FAQ forum {message identifier: = 9360002}

• Words in the string?

  I have a string

  for example: ' Welcome to flash forums!

  I need a function that returns the number of words (sperated by spaces)

  The string is not user entered, so if I need to understand something between words to achieve this, it is possible...

  Thank you.

  Use the string split method

  var st:String = ' Welcome to flash forums! "

  Var words: Array = st.split("");

  trace (Words.Length);

• some omitted spaces after the conversion of x 5

  I recently converted my 5 x aid project to version 7. After the conversion, some, not all, display of words merged compiled help, but does appear like that in Design view or when previewing in the topic. Normally, it happens after a word that is bold, or a hyperlink. When I look at the html code, it seems to be formatted correctly, in the following example, only the words Option display in bold management:
  
  Design/Preview menu screen - management Option
  HTML - < span style = "' make-weight: bold;" > </span > management option menu "
  Compiled help - Option Managementmenu
  
  The only way to add space is to insert a space before the/span tag. Of course, in the case of hyperlinks, it extends the hyperlink in space. It occurs sporadically throughout the project, and it will take me forever to try to capture all these occurrences. Anyone have any ideas on how to solve this problem? It also seems to be the case sometimes when I copy and paste from Word.
  
  Thank you very much for your help - Janet

  Yes, I always had the same results after you apply two patches. However, I installed version 8, and who took care of the problem. Thanks for the idea!

• Insert a space character between each character in a string

  I have an array of length variant.  Each element of the array contains a string.  I want to put a space character "" between each character of each string in the array.  The length of the string in each element of the array varies.

  I played with nested for loops with registers to lag and feedback without success and began to think that I do it's too difficult.

  Thank you

  Mike

  (Lucither: your code will make any element of the array to an empty string.) It does not insert space between characters as needed.)

  There are nice solutions already posted above, here's another at random.

  

• If my insert takes the free space above the pctfree?

  Hi guys,.
  
  If I have my pctfree set at 25%, my block is currently used by 70%, and I do an insert that will leave free of only 5%, Oracle will migrate the line that I inserted, while 25% is still free?
  
  Thank you

  OGUY,

  Oracle will string your line. Migration is happening with the Update statement, not with the insert command. If you insert a line that exceeds the free space of the block, oracle will be chaining line in multi parts be stored.

  HTH
  Aman...

• I have a MacBook Pro.  Is there a way to implement a rarely used keyboard key that - WHENEVER - it is pressed the computer will insert the string, predetermined character at the cursor position?

  I have a MacBook Pro.  Is there a way to implement a rarely used keyboard key that - WHENEVER - it is pressed the computer will insert the string, predetermined character at the cursor position?

  Yes. You can add in system preferences > keyboard > text.