INSERT INTO statement does not

Similar Questions

• Simple Insert statement does not

  This problem is just driving me crazy. I don't know what I'm doing wrong here. The code works fine on my localhost, but gives the problem on the site online. It's a simple insert like this:
  
  insert into tblSubImages (productid, title, subdescription, image, location) values (#form.productid #, ' #form.title #',' #form.subdescription #',' #uploadedimage # ", #form.place #")
  
  The error I m to looks like this:
  
  Syntax error in INSERT INTO statement.
  
  The error occurred in D:\Hosting\davedhillon\superprinters\admin\addaditional.cfm: line 11
  
  9: < cfset uploadedImage = cffile.serverfile >
  10: < cfquery name = "insertadditional" datasource = "#super.dsn #" >
  11: insertion in values(#form.productid#,'#form.title#','#form.subdescription#','#uploadedimage#') tblSubImages (productid, title, subdescription, image)
  12: < / cfquery >
  13:
  
  
  
  --------------------------------------------------------------------------------
  
  SQL insert into values(1,'ewr','werw','FamilyRoomBedroom.jpg') tblSubImages (productid, title, subdescription, image)
  Davedhillon_accesscf_super DATA source
  VENDORERRORCODE 3092
  
  You can see that it is the simple insert statement that I worked with so many times. Why he started giving problems all of a sudden?
  
  Thank you

  'Image' can be a reserved word. What happens if you do this?

  insert into tblSubImages (productid, title, subdescription, [image])
  values (...)

• Comment of "Syntax error in INSERT INTO statement." validation error.

  I had this working perfectly on MySQL. Then I was told that I had to do with a mdb database in Access, now the errors pop up like crazy. I fixed all of them except this one, I get a "syntax error in INSERT INTO statement." When I try to post a comment on a post in my mini-blog site.

  The thing is, I use almost the same code for the comments I make blog themselves. The positions work fine, the comments are not.

  He said that the error is on my page addcomment_process as 119. It is the following (line 119 is underlined, bold line is also bolded in the error message):

  < name cfquery = "input_comments."

  DataSource = "" #DSN # ""

  username = "" #DSNUSER # ""

  password = "#DSNPASS #" >

  INSERT INTO (comments)

  speaker,

  Comment,

  DateTime,

  post_id

  )

  VALUES)

  "#form.commenter #"

  "#form.comment #"

  "#form.datetime #"

  "#form.post_id #".

  )

  < / cfquery >

  It is all fine data, by simply inserting not, because it says:

  "INSERT INTO comments (speaker, comment, datetime, post_id) VALUES ('Anonymous', 'test commentary.', 25 April 12 22:55 ', ' 2').

  It worked perfectly, when it was a MySQL database, now I keep getting errors present a part of the site now that it is MDB. Anyone know what is happening?

  DateTime is a reserved word in Access.

  --

  Adam

• I have a new computer running windows but 10, 13 photoshop elements disc.  Insert the disc does not start something going and looking at the files I do not see an installation executable.

  I have a new computer running windows but 10, 13 photoshop elements disc.  Insert the disc does not start something going and looking at the files I do not see an installation executable.  I don't know what to do.

  Download from Download Photoshop Elements | 14, 13, 12, 11, 10

  Install and enter your serial number.

• Active state does not properly in Chrome

  Hello

  I recently exported the site I created in HTML and everything seems to work well. The only problem I encounter is that active State does not work in Chrome. When I scroll to the bottom of the page, the color of the active state is not reflected. This does not work in IE, Safari and Firefox. Really need this to be resolved soon. Help, please!

  Thank you!

  Ryan

  Hi whyax84 and Zak.

  Download Yes it indeed solved the problem for chrome. Thank you very much!

  Kelvin

• ORA-13780: SQL statement does not exist

  Hello
  on the 11g R2, I get the following message:
  

  SQL> variable stmt_task VARCHAR2(64);
  SQL> EXEC :stmt_task := DBMS_SQLTUNE.CREATE_TUNING_TASK(sql_id => 'gh9p77g1fr0kd');
  BEGIN :stmt_task := DBMS_SQLTUNE.CREATE_TUNING_TASK(sql_id => 'gh9p77g1fr0kd'); END;
  
  *
  ERROR at line 1:
  ORA-13780: SQL statement does not exist.
  ORA-06512: at "SYS.DBMS_SYS_ERROR", line 79
  ORA-06512: at "SYS.PRVT_SQLADV_INFRA", line 125
  ORA-06512: at "SYS.DBMS_SQLTUNE", line 655
  ORA-06512: at line 1

  Any idea?
  
  Thank you.

  Sql and the sql_id execution plan has been emptied out of the shared pool, so oracle could not find it.

  -Thank you

• Rollover State does not not on active state

  Hi, I have a problem with the menu States. The rollover State does not work when a menu item is in its active state. This is supposed to happen or is there a solution to this?

  Thank you.

  Hello

  This works as expected. Active state removes change it to any other State on the interaction of the mouse and other States work only on the links that are currently in Normal condition.

  See also: https://forums.adobe.com/thread/1136562

  See you soon,.

  Vikas

• Menu rollover State does not have the button active parent

  My menu rollover State does not work the button parent in my menu while I'm on a page of the child. I didn't have any currently active States in the menu. How can I get the parent menu to respect the rollover State even while I'm on one of the child pages?

  Please check this thread:

  https://forums.Adobe.com/message/6148234#6148234

  Thank you

  Sanjit

• Delete statement does not work properly

  Hello
  
  The following delete statement does not work correctly.
  If I press DELETE will delete everything in the table of categories
  I don't know whats wrong with it.
  -Delete category line if there is not the infrastructure to support-
  IF: P12_DFCY_SEQNO4 IS NOT NULL AND: P12_DFCY_CATG_C = "7" THEN
  REMOVE FROM DFCY_CATG
  IF NOT EXISTS (SELECT I.DFCY_SEQNO
  OF DFCY_CATG C, DFCY_CATG_INFRSTRCTR I
  WHERE C.DFCY_SEQNO = I.DFCY_SEQNO
  AND: P12_DFCY_SEQNO4 = I.DFCY_SEQNO);
  end if;
  
  Thank you
  Mary

  You probably the where more clause:

  DELETE FROM DFCY_CATG
  WHERE C.DFCY_SEQNO = :P12_DFCY_SEQNO4
  AND NOT EXISTS(SELECT I.DFCY_SEQNO
  FROM DFCY_CATG C, DFCY_CATG_INFRSTRCTR I
  WHERE C.DFCY_SEQNO = I.DFCY_SEQNO
  AND :P12_DFCY_SEQNO4 = I.DFCY_SEQNO);
  

  Not sure if this is the exact name of your column in the table, but that limit the scope of deleting just a record that you control.

  Hope it will be useful,

  Aaron

• Statement INSERT INTO stuck, do not insert data

  8174 (former ancient db) version on Solaris 8
  
  Below work was running fine, until toady, nothing seems to have changed, no idea how to solve this problem? I check all the tablespace/file system, made the switches of the logfile etc and checked alert logfile, no idea yet...
  
  
  
  SQL > select count (*) FROM findata.averion_etc_mapping_v;
  COUNT (*)
  ----------
  26352
  
  SQL > select count (*) in the findata.etc_pjtran_summary;
  COUNT (*)
  ----------
  0
  
  
  SQL > @updpjtran.sql;
  SQL > SET FEEDBACK ON
  SQL >
  SQL > SPOOL /u06/users/db/oracle/updpjtran.lis
  SQL >
  SQL> -- =============================================================================================================
  SQL >-Script:
  SQL >-author: EOKALI
  SQL >-Date: July 1, 2008
  SQL >-reason: calls PC to update the value of the quantity of Deltek data in the PJTRAN table
  SQL >--
  SQL >--
  SQL >--
  SQL >-changes
  SQL >-version: < X.X.XX >.
  SQL >-change number: change source control number >.
  SQL >-change Date: DD-MON-YYYY >.
  SQL >-author of change: author of modification of the source code >.
  SQL >-change Desc: Description of modification of the source code >.
  SQL >-change Params: NewCode = < YES/NO >
  SQL >-ModifyCode = < YES/NO >
  SQL >-DeleteCode = < YES/NO >
  SQL >-SingleChange = < YES/NO >
  SQL >-GlobalChange = < YES/NO >
  SQL> -- =============================================================================================
  SQL >
  SQL >
  SQL> -- ============================================================================================================
  SQL >-time
  SQL> -- ============================================================================================================
  SQL >--
  SQL > SELECT TO_CHAR (SYSDATE, ' DD/MM/YYYY HH24:MI:SS') "Todays Date and time is:
  2 double;
  
  Today's Date/time is
  -------------------
  13/06/2012-13:30:33
  
  1 selected line.
  
  SQL >
  SQL> -- ============================================================================================================
  SQL >
  SQL >-moved from script to FINSBO1 box
  SQL >
  SQL >-UPDATE findata.averion_pjtran_cp
  SQL >-amount FIXED = units * findata.averion_calclaborrate_mod (company_id empl_id proj_id, laborclass, trans_date)
  SQL >-WHERE source = 'DELTEK.
  SQL >
  SQL >-COMMIT;
  SQL >
  SQL> -- ============================================================================================================
  SQL >-update the summary table for the tool ETC. necessary for the performance summary table
  SQL> -- ============================================================================================================
  SQL >
  SQL > DELETE FROM findata.etc_pjtran_summary;
  
  0 rows deleted.
  
  SQL >
  SQL > COMMIT;
  
  Validation complete.
  
  SQL >
  SQL > INSERT INTO findata.etc_pjtran_summary
  2 (project,
  3 seqnum,
  etc_activity 4,.
  5 actualhrs,
  actualamt 6,.
  7 budgethrs,
  8 budgetamt)
  9. SELECT
  Project 10,
  11 seqnum,
  etc_activity 12,
  13 findata.etc_pkg.acthrs_byactivity (project, seqnum) acthrs,
  14 findata.etc_pkg.actamt_byactivity (project, seqnum) actamt,
  15 findata.etc_pkg.bdgthrs_byactivity (project, seqnum) bdgthrs,
  16 findata.etc_pkg.bdgtamt_byactivity (project, seqnum) bdgtamt
  17 FROM findata.averion_etc_mapping_v
  18 project GROUP, seqnum, etc_activity;

  DBA2011 wrote:
  8174 (former ancient db) version on Solaris 8

  Tough - very old version. I must rememeber what will work in v8...

  From your post, I understand that the INSERT locks just without activity - a new development. Nothing has changed since the last sucessful run? If so, then what?

  Some ideas of related questions:
  1. can you run the SQL by itself without the INSERT to see if the SELECTION is the problem? If so how long does it take?
  2. is the locked table?
  3. is there that expect everything from events that occur during the insertion process?
  4. how much time do you expect it to end?

  Later: what part was right?

  Published by: riedelme on June 13, 2012 12:10

• With multi-page session state does not save

  Hello
  
  I built an online form using apex that has 4 pages. The first 3 pages save in a session state on the last page running a process that inserts the data of 4 pages in the table. The first 3 pages are set to present an update of SQL.
  
  The issue I'm having is that when I want to go back to a page within the session using the previous buttons, I created, the values of the previous page is no longer present in the fields (all fields are now empty). I got to the origin of the previous button to submit and then redirect to the previous page when clicking on the value. Then I tried just to set the button to redirect to the previous page without presenting and then it does not still work. Anyone know what could be causing this? Your help is very appreciated.
  
  Thank you
  MICAH

  Hi Mika,

  Have you checked the source of the page elements in your form to make sure that they are not using "Always replace any value stored in session state". If this field is selected in the menu drop-down, then they will be wiped off.

  Thank you

  Paul

• OrderID if else statement does not

  I have a page of payment if I orderID does not exist I want to create a new command id or if the orderID is using the current order id, but if it is not an empty order it does not give you a new command id

  Check if there is already an order

  $query = 'SELECT payment_id FROM host_payments WHERE payment_userid = %s AND payment_transaction_status = AND payment_amount_due = payment_type = LIMIT 1 %s AND %s %s';

  $query = sprintf ($query $userid, $transaction_status, $amount_due, $payment_type);

  $results = mysql_query ($query);

  If (mysql_num_rows ($Results) > 0)

  {

  While ($Row = mysql_fetch_array ($Results))

  {

  $existing_payment_id = $row ['payment_id'];

  }

  }

  on the other

  {

  Create order

  $query = "INSERT INTO host_payments (payment_userid, payment_created_timestamp, payment_amount_due, payment_transaction_status, payment_type) VALUES (%s, %s, %s, %s %s)";

  $query = sprintf ($query $userid, $timestamp, $amount_due, $transaction_status, $payment_type);

  $results = mysql_query ($query);

  $query = 'SELECT payment_id FROM host_payments WHERE payment_userid = %s AND payment_created_timestamp = AND payment_amount_due = payment_type = LIMIT 1 %s AND %s %s';

  $query = sprintf ($query $userid, $timestamp, $amount_due, $payment_type);

  $results = mysql_query ($query);

  While ($Row = mysql_fetch_array ($Results))

  {

  $payment_id = $row ['payment_id'];

  }

  }

  then

  If (isset ($existing_payment_id) & &! empty ($existing_payment_id))

  {

  $ORDERID = $existing_payment_id;

  }

  on the other

  {

  $ORDERID = $payment_id;

  }

  $ORDERID = $payment_id; $existing_payment_id;

  the variable I want to use at the end to send the bridge is so $ORDERID

  > I need to take on more script for your suggestion to work?

  You follow one of my last two suggestions!

  Try this.

  Check if there is already an order

  $query = 'SELECT payment_id FROM host_payments WHERE payment_userid = %s AND payment_transaction_status = AND payment_amount_due = payment_type = LIMIT 1 %s AND %s %s';

  $query = sprintf ($query $userid, $transaction_status, $amount_due, $payment_type);

  $results = mysql_query ($query);

  If (mysql_num_rows ($Results) > 0)

  {

  $row = mysql_fetch_array ($results)

  $ORDERID = $row ['payment_id'];

  }

  on the other

  {

  Create order

  $query = "INSERT INTO host_payments (payment_userid, payment_created_timestamp, payment_amount_due, payment_transaction_status, payment_type) VALUES (%s, %s, %s, %s %s)";

  $query = sprintf ($query $userid, $timestamp, $amount_due, $transaction_status, $payment_type);

  $results = mysql_query ($query);

  $ORDERID = mysql_insert_id();

  }

• insert this line does not exist

  Hi all
  
  I need to insert a line using the daily procedure. Insert must only be performed when this line does not exist in the table. Please suggest me a decision. I know it's simple question, sorry for disturbing (Burns my brain).

  Hello

  Use MERGE.
  http://download.Oracle.com/docs/CD/B28359_01/server.111/b28286/statements_9016.htm#sthref9082
  If you use Oracle 10 (or higher) then you don't need a section "WHEN MATCHED.

  If you want to know, post a small example of data (CREATE TABLE and INSERT statements, showing all the tables involved, as they exist prior to the INSERTs in question). Put one or two unconditional instructions INSERT (including an example of each matching rows found and not found) and the results you want (that is, the content of the table changed after the INSERTs).
  Always tell what version of Oracle you are using.

• Insert using TO_NUMBER does not seem to accept the decimal value

  Oracle 10g
  
  I'm trying to insert a decimal value in a table from another table oracle oracle. The column of the source table is a data type
  

      "PLOTSIZE10_30CM"    VARCHAR2(4 BYTE),
      "PLOTSIZE30_50CM"    VARCHAR2(4 BYTE),
      "PLOTSIZE50CM"       VARCHAR2(3 BYTE),

  The destination table contains the following:

      "PLOT_SIZE_10_30CM" NUMBER(7,0),
      "PLOT_SIZE_30_50CM" NUMBER(7,0),
      "PLOT_SIZE_50CM"    NUMBER(7,0),

  When I run the insert statement as the following decimal values are not inserted into the destination table.
  

  SQL> SELECT DISTINCT PLOTSIZE50CM FROM IMPORT_DATA WHERE STAND_ID = 23;
  
  PLO
  ---
  0.2
  
  SQL>
  SQL> INSERT INTO
    2  psp_plot_measurements
    3  ( species_major
    4  , plot_location_id
    5  , codominant_height
    6  , regen_density_primary_code
    7  , regen_density_secondary_code
    8  , PLOT_SIZE_10_30CM
    9  , PLOT_SIZE_30_50CM
   10  , PLOT_SIZE_50CM
   11  )
   12  SELECT DISTINCT species_major
   13       , '2'
   14       , height_codom
   15       , regen_prim
   16       , regen_sec
   17       , TO_NUMBER(plotsize10_30cm)
   18       , TO_NUMBER(plotsize30_50cm)
   19       , TO_NUMBER(plotsize50cm)
   20    FROM import_data
   21    WHERE stand_id = 23;
  
  1 row created.
  
  SQL>
  SQL> SELECT PLOT_SIZE_50CM FROM PSP_PLOT_MEASUREMENTS;
  
  PLOT_SIZE_50CM
  --------------
               0

  See you soon
  Ben

  Hi Ben,

  If the destination table have the column as a Number (7.0) and then how you can store a decimal value.

  The destination table contains the following:

  "PLOT_SIZE_10_30CM" NUMBER(7,0),
  "PLOT_SIZE_30_50CM" NUMBER(7,0),
  "PLOT_SIZE_50CM"    NUMBER(7,0),
  

  Look at sample scenario-

  SQL> CREATE TABLE TEST1(COL NUMBER(7,0));
  
  Table created.
  
  SQL> CREATE TABLE TEST2(COL NUMBER(7,1));
  
  Table created.
  
  SQL> INSERT INTO TEST1(COL) VALUES(1.234);
  
  1 row created.
  
  SQL> INSERT INTO TEST2(COL) VALUES(1.234);
  
  1 row created.
  
  SQL> INSERT INTO TEST1(COL) VALUES(0.234);
  
  1 row created.
  
  SQL> INSERT INTO TEST2(COL) VALUES(0.234);
  
  1 row created.
  
  SQL> SELECT * FROM TEST1;
  
         COL
  ----------
           1
           0
  
  SQL> SELECT * FROM TEST2;
  
         COL
  ----------
         1.2
          .2
  
  SQL>
  

  If you want to store the decimal value, you must modify the destination table.

• using nested case statement does not get the right result

  Hello all;
  
  I have a sample of data similar to below
  

  create table t3
  ( 
         id varchar2(200),
         qty number(30),
         qty2 number(30)
  ); 

   insert into t3
     (id, qty, qty2)
   values
     ('A', 10, null);
   
    insert into t3
     (id, qty, qty2)
   values
     ('A', 20, null);
     
   insert into t3
     (id, qty, qty2)
   values
     ('B', null, 5);
     
  insert into t3
     (id, qty, qty2)
   values
     ('B', null, 5);
     
   insert into t3
     (id, qty, qty2)
   values
     ('C', null, -5);
     
  insert into t3
     (id, qty, qty2)
   values
     ('C', null, 5);
  
  
   insert into t3
     (id, qty, qty2)
   values
     ('D', -1, -2);
     
  insert into t3
     (id, qty, qty2)
   values
     ('D', 1, 4);

  This is what looks like data
  

  ID  QTY  QTY2
  A    10
  A    20
  B              5
  B              5
  C             -5
  C              5
  D    1        4
  D   -1       -2

  It is the output that I desired below
  

  ID    Status 
  A      Fail
  B      Fail
  C      Pass
  D      Fail

  A is a failure because the sum of the 2 has the value zero, where the summation of the qty was used to determine the State and because the sum of the quantity is not equal to zero, then, it is a failure
  D is a failure because even if the sum of the Qty 1 equals zero, we must make use of summation of the qty 2 instead because he is not null to determine the status and the summation of the qty is 2, where a failure
  etc.
  
  I tried write something but can not make it work
  

  select case when sum(v.qty) is not null
              and sum(v.qty) = 0 then 'Pass'
              when sum(v.qty) is not null
              and sum(v.qty) != 0 then 'Fail'
         else
           case when sum(v.qty2) is not null
             and sum(v.qty2) = 0 then 'Pass'
             else
              when sum(v.qty2) is not null 
                and sum(v.qty2) != 0 then 'Fail'
                end as status
            end as status
  
  
   from t3 v;

  any help is appreciated. Thank you.

  Try this,

  SELECT ID,
         CASE WHEN NVL(SUM (qty2),1) !=0 THEN 'fail'
              WHEN NVL(SUM (qty),0) != 0 THEN 'fail'
              ELSE 'pass'
         END
    FROM t3
  GROUP BY ID
  
  OUTPUT
  -------------
  
  ID RESULT
  -- ------
  A  fail
  B  fail
  C  pass
  D  fail
  Z  fail
  

  G.