OrderID if else statement does not
I have a page of payment if I orderID does not exist I want to create a new command id or if the orderID is using the current order id, but if it is not an empty order it does not give you a new command id
Check if there is already an order
$query = 'SELECT payment_id FROM host_payments WHERE payment_userid = %s AND payment_transaction_status = AND payment_amount_due = payment_type = LIMIT 1 %s AND %s %s';
$query = sprintf ($query $userid, $transaction_status, $amount_due, $payment_type);
$results = mysql_query ($query);
If (mysql_num_rows ($Results) > 0)
{
While ($Row = mysql_fetch_array ($Results))
{
$existing_payment_id = $row ['payment_id'];
}
}
on the other
{
Create order
$query = "INSERT INTO host_payments (payment_userid, payment_created_timestamp, payment_amount_due, payment_transaction_status, payment_type) VALUES (%s, %s, %s, %s %s)";
$query = sprintf ($query $userid, $timestamp, $amount_due, $transaction_status, $payment_type);
$results = mysql_query ($query);
$query = 'SELECT payment_id FROM host_payments WHERE payment_userid = %s AND payment_created_timestamp = AND payment_amount_due = payment_type = LIMIT 1 %s AND %s %s';
$query = sprintf ($query $userid, $timestamp, $amount_due, $payment_type);
$results = mysql_query ($query);
While ($Row = mysql_fetch_array ($Results))
{
$payment_id = $row ['payment_id'];
}
}
then
If (isset ($existing_payment_id) & &! empty ($existing_payment_id))
{
$ORDERID = $existing_payment_id;
}
on the other
{
$ORDERID = $payment_id;
}
$ORDERID = $payment_id; $existing_payment_id;
the variable I want to use at the end to send the bridge is so $ORDERID
> I need to take on more script for your suggestion to work?
You follow one of my last two suggestions!
Try this.
Check if there is already an order
$query = 'SELECT payment_id FROM host_payments WHERE payment_userid = %s AND payment_transaction_status = AND payment_amount_due = payment_type = LIMIT 1 %s AND %s %s';
$query = sprintf ($query $userid, $transaction_status, $amount_due, $payment_type);
$results = mysql_query ($query);
If (mysql_num_rows ($Results) > 0)
{
$row = mysql_fetch_array ($results)
$ORDERID = $row ['payment_id'];
}
on the other
{
Create order
$query = "INSERT INTO host_payments (payment_userid, payment_created_timestamp, payment_amount_due, payment_transaction_status, payment_type) VALUES (%s, %s, %s, %s %s)";
$query = sprintf ($query $userid, $timestamp, $amount_due, $transaction_status, $payment_type);
$results = mysql_query ($query);
$ORDERID = mysql_insert_id();
}
Tags: Dreamweaver
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