interpolation again to continue where the last tween left?

I have a clip with a tween on its X position on mouse over. This point will go up in the air on mouse... then fall and bounce on mouse over. For example, this could be a ball. My problem is that if if I mouse over this ball to lift into the air and then the mouse on... He'll do the interpolation any rebound but if I smile back on this front ball of the mouse on the Tween is complete interpolation will access the end and does not work properly. I have my sure there must be a post any on this already, but I was unable to locate a (sorry)... What I need to happen is for the mouse on interpolation from there where the mouse on tween left to. If the ball is wriggling on it will start to fall and then if back quiver on it immediately back into the air from where the mouse on tween left of... does that make sense? its really hard for me to explain this. Maybe an example is necessary. ( http://videos.sonicelectronix.com/cbennett/ball/ball.html )

I think on the mouse on the balls that must depend on the mouse Y and mouse out in the X position, the ball must fall.  There are probably a few things that I do wrong here but if someone could point me to please you in the right direction would be great! Thank you

import fl.transitions.Tween;
import fl.transitions.easing.*;

var bounceTween:Tween;

this.addEventListener(MouseEvent.MOUSE_OVER, ballOver, false,0,true);
function ballOver(e:MouseEvent):void{
     bounceTween = new Tween( e.target, "y", None.easeNone,148,50,5);
}

this.addEventListener(MouseEvent.MOUSE_OUT, ballOut, false,0,true);
function ballOut(e:MouseEvent):void{
     bounceTween = new Tween( e.target, "y", Bounce.easeOut,50,148,20);
}

Make one Tween to pick up where another left you normally specify just the starting point than the current value of the object: e.target.y rather than a fixed value.  I don't know if you can send the object like a movieclip in this case.

Tags: Adobe Animate

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