Interval partitioning

Hello

Please let me know if an interval of partitioning can be created on a table for all the two weeks?

DB version is 11g.

Thank you

Because the interval partitioning allows you to specify the size range (read the documentation for it)
and that a fortnight is 14 days by the usual definition

Then, the 'yes '.

Tags: Database

Similar Questions

Impact of setting the interval partitioning off and then on again

Hi all
Have discovered that to split the partitions of a partitioned table Beach-interval, in that we need to define the partitioning interval all issue the command split then on again.
e, g.
ALTER TABLE retailer_transaction SET INTERVAL ();
ALTER TABLE POR2_retailer_transaction
SPLIT PARTITION PART_400012 AT (TO_DATE (' 2020-09-01 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN '))
INTO (PARTITION PART_202008,
PART_400012 PARTITION)
ALTER TABLE retailer_transaction SET INTERVAL (NUMTOYMINTERVAL(1,'MONTH'))
Everything we need to pay attention to that?
Using oracle 11.2.0.3
Thank you

You can NOT split the LAST (most HIGH_VALUE) partition of a partitioned table interval interval. You can only separate partitions BEFORE the last. Which converts also all partitions from the bottom (split and below) for the partitions of the RANGE.

If interval partitioning will only apply to data added above the transition point (the score higher.

To return to your original question. To split the LAST interval follow the procedure described in your original post

1. range partitioning

2 split the partitioning

3 set the partitioning interval on

Conclusion with this however when adding data back to a nine month doesn't automatically create the partition again.

This "new month" MUST BE above the point of passage for a new partition to create. In your code example, this point of transition is for the year 4000.

This works very well for me:

ALTER TABLE sales PARTITION RENAME SYS_P1122 to SALE_400012

ALTER TABLE sale SET INTERVAL ();

ALTER TABLE SPLIT PARTITION for sale

SALE_400012 TO (TO_DATE('01/02/2020','DD/MM/YYYY')) IN

(

SALE_202001 PARTITION,

SALE_400012 PARTITION

);

ALTER TABLE sale SET INTERVAL (NUMTOYMINTERVAL(1,'MONTH'))

INSERT INTO sales

(SALES_DATE, STORE_NUM, QTY_SOLD)

values (to_date('31/12/4001','DD/,MM/YYYY'), 1, 10);

This last INSERT statement above creates a NEW partition because the date (31/12/4001) is above the transition point.

Looks like you want to move the transition point downwards. That is - you were using this year there date of 4000 as a 'catch all '.

1. set the partitioning interval

2 split that last partition into two NEW partitions (new names) by using a VALUE that is high enough to contain ALL the data you have in this last partition.

3. remove the last partition - it should now be empty

4. turn on range partitioning

Now, any data that you insert above this NEW point of transition (the limit that you used for the new partition) it will create a new partition of the interval. Make sure the border is really an end of month, if that's what you want.

If your data sample had this

INSERT INTO sales

(SALES_DATE, STORE_NUM, QTY_SOLD)

values (to_date('05/10/2016','DD/,MM/YYYY'), 1, 10);

INSERT INTO sales

(SALES_DATE, STORE_NUM, QTY_SOLD)

values (to_date('31/12/4000','DD/,MM/YYYY'), 1, 10);

So for the step #2 above use split date 06/2016 so that the line above for 10/05/2106 goes to the new partition and 12/31/4000 stays in the old.

Then, drag this old and lines in it (31/12/4000).

You can NOT split the last partition if interval is always on because it is the last partition interval.

And as long as you have given for 12/31/4000, you will get no new partitions unless you insert was more TOP than this.

So if you want partitioning interval to activate again 06/2016 that higher data would be deleted and the score he falls.

You have discovered only among "traps" with the help of partitioning of the interval. Oracle will happily create new partition needed to keep the data. If ANYONE, even accidentally, between a date as 12/31/4000 that nobody would ever know until the new data seem to DISAPPEAR for some use cases.

This is because all data will start to enter this new partition ACCIDENTALLY created instead of a partition for the month, it's part.

And, and you have discovered, you cannot split this partition directly.

Delayed segment creation can allow you to pre-create the partitions ahead without actually affecting the segment for them until the first row is inserted.

Interval partitioning will create the appropriate partitions but not if someone accidentally or intentionally, data will be a valuable capitalized in the table.

Range of interval partitioning on yrwk?

Hello

Using oracle 11.2.0.3

We build a large table and many queries will be such, that we want to divide this query on yearweek on yearweek.

While we could manually add is the partitions possible to have range interval partitioning for this?

If so, how - have used the interval with columns date range partitioning

If was months would be nice, but a few years we have 52 and 53 weeks a few years - we have another table of calendar that tells us the number of weeks but not sure if we could use yrwk + interval partitioning

Thank you

Your question is not clear enough. The partitioning key can be a single column of the table name and it must be of NUMBER or DATE type. Assuming that your week of the year is a column for the number.

SQL> --My datbase version.
SQL> ---------------------
SQL> SELECT * FROM v$version;

BANNER
--------------------------------------------------------------------------------
Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production
PL/SQL Release 11.2.0.1.0 - Production
CORE    11.2.0.1.0      Production
TNS for Linux: Version 11.2.0.1.0 - Production
NLSRTL Version 11.2.0.1.0 - Production

SQL> DROP TABLE rng_int_part purge;

Table dropped.

SQL> ed
Wrote file afiedt.buf

  1  CREATE TABLE rng_int_part
  2    (
  3      yrwk NUMBER,
  4      col2 VARCHAR2(1)
  5    )
  6    partition BY range
  7    (
  8      yrwk
  9    )
 10    interval
 11    (
 12      1
 13    )
 14    (
 15      partition p_201402 VALUES less than (201401),
 16      partition p_201403 VALUES less than (201402)
 17*   )
SQL> /

Table created.

SQL> set line 200
SQL> ed
Wrote file afiedt.buf

  1  SELECT table_name,
  2    partition_name,
  3    high_value
  4  FROM user_tab_partitions
  5* WHERE table_name='RNG_INT_PART'
SQL> /

TABLE_NAME                     PARTITION_NAME                 HIGH_VALUE
------------------------------ ------------------------------ --------------------------------------------------------------------------------
RNG_INT_PART                   P_201402                       201401
RNG_INT_PART                   P_201403                       201402

SQL> INSERT INTO rng_int_part VALUES
  (201401,'A'
  )  2
SQL> /
  (201401,'A'
            *
ERROR at line 2:
ORA-00917: missing comma

SQL> ed
Wrote file afiedt.buf

  1  INSERT INTO rng_int_part VALUES
  2    (201401,'A'
  3*   )
SQL> /

1 row created.

SQL> ed
Wrote file afiedt.buf

  1  INSERT INTO rng_int_part VALUES
  2    (201401,'B'
  3*   )
SQL> /

1 row created.

SQL> ed
Wrote file afiedt.buf

  1  SELECT table_name,
  2    partition_name,
  3    high_value
  4  FROM user_tab_partitions
  5* WHERE table_name='RNG_INT_PART'
SQL> /

TABLE_NAME                     PARTITION_NAME                 HIGH_VALUE
------------------------------ ------------------------------ --------------------------------------------------------------------------------
RNG_INT_PART                   P_201402                       201401
RNG_INT_PART                   P_201403                       201402

SQL> ed
Wrote file afiedt.buf

  1  INSERT INTO rng_int_part VALUES
  2    (201403,'A'
  3*   )
SQL> /

1 row created.

SQL> commit;

Commit complete.

SQL> ed
Wrote file afiedt.buf

  1  SELECT table_name,
  2    partition_name,
  3    high_value
  4  FROM user_tab_partitions
  5* WHERE table_name='RNG_INT_PART'
SQL> /

TABLE_NAME                     PARTITION_NAME                 HIGH_VALUE
------------------------------ ------------------------------ --------------------------------------------------------------------------------
RNG_INT_PART                   P_201402                       201401
RNG_INT_PART                   P_201403                       201402
RNG_INT_PART                   SYS_P25                        201404

SQL> ed
Wrote file afiedt.buf

  1  INSERT INTO rng_int_part VALUES
  2    (201452,'A'
  3    )
  4  /
  5  INSERT INTO rng_int_part VALUES
  6    (201501,'A'
  7*   )
  8  /
/
*
ERROR at line 4:
ORA-00933: SQL command not properly ended

SQL> ed
Wrote file afiedt.buf

  1  INSERT INTO rng_int_part VALUES
  2    (201452,'A'
  3*   )
SQL> /

1 row created.

SQL>
SQL> commit;

Commit complete.

SQL> ed
Wrote file afiedt.buf

  1  INSERT INTO rng_int_part VALUES
  2    (201501,'A'
  3*   )
SQL> /

1 row created.

SQL> commit;

Commit complete.

SQL> ed
Wrote file afiedt.buf

  1  SELECT table_name,
  2    partition_name,
  3    high_value
  4  FROM user_tab_partitions
  5* WHERE table_name='RNG_INT_PART'
SQL> /

TABLE_NAME                     PARTITION_NAME                 HIGH_VALUE
------------------------------ ------------------------------ --------------------------------------------------------------------------------
RNG_INT_PART                   P_201402                       201401
RNG_INT_PART                   P_201403                       201402
RNG_INT_PART                   SYS_P25                        201404
RNG_INT_PART                   SYS_P26                        201453
RNG_INT_PART                   SYS_P27                        201502

SQL>

How to create the INTERVAL partitioning using EM?

Hi guys
I'm still not able to use the INTERVAL partitioning using EM. Is it possible to do?
Oracle 11 g 2 on Linux
Thank you
John

Hi John,.

I don't think it's possible, that the option of partition of the range seems to have things that make you think of it would generate the definition as the partitioning interval but it doesn't.

I'm on 12.1.0.3 of the SGC and 12.1.0.5 DB plugin so I'm sure it's 'missing' features for the moment.

See you soon,.

Rich

Interval partitioning using the key of the virtual column

Hi guys
I have a series of tables that I propose to the partition.
Each table has a year and a period (equivalent to a month) and I intend using those as my partition keys - year as the partition and the period as the subpartition.
The distribution will be actually:
2015
001
002
...
012
2016
001
002
...
012
etc...
I would use range partitioning for the year, because it would make the maintenance of the partition a breeze. Only one problem - the field is of type varchar, and is not modifiable as its legacy applications that have become bigger than Ben Hurr and more tangled than a Ben Hurr size flat spaghetti.
It is hence the idea of virtual column between in game - I could create a virtual column in these tables to convert the field to digital and then partition on it instead.
My question-if the year of origin varchar column is included in the where clause of a query, is the optimizer based on CSSTidy smart enough to realize that the virtual column used for the partition key is based on this column and use pruning of partition to improve performance? Or queries must refer to the virtual column to make it work? Also, the virtual column should be indexed to make it work?
Thanks in advance.

Simon

orclz >

orclz > create table pt (v1 varchar2 (1) c1 as (to_number (v1)), number of c2)

2 partition by range (c1) interval (1)

subpartition by hash (c2) subpartitions 4 3

4 (partition p1 values less than (1))

5.

Table created.

orclz > set autot on explain

orclz > select * PT where v1 = '0';

no selected line

Execution plan

----------------------------------------------------------

Hash value of plan: 711571056

--------------------------------------------------------------------------------------------

| ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

--------------------------------------------------------------------------------------------

| 0 | SELECT STATEMENT |      |    82. 2296 |    29 (0) | 00:00:01 |      |      |

| 1. RANGE OF PARTITION ALL THE |      |    82. 2296 |    29 (0) | 00:00:01 |    1. 1048575.

| 2. HASH PARTITION ALL |      |    82. 2296 |    29 (0) | 00:00:01 |    1.    4.

|* 3 |    TABLE ACCESS FULL | PT |    82. 2296 |    29 (0) | 00:00:01 |    1. 1048575.

--------------------------------------------------------------------------------------------

Information of predicates (identified by the operation identity card):

---------------------------------------------------

3 - filter ("V1" = '0')

orclz > select * PT where c1 = 0;

no selected line

Execution plan

----------------------------------------------------------

Hash value of plan: 1726115854

-----------------------------------------------------------------------------------------------

| ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

-----------------------------------------------------------------------------------------------

| 0 | SELECT STATEMENT |      |    82. 2296 |    29 (0) | 00:00:01 |      |      |

| 1. RANGE OF SINGLE PARTITION |      |    82. 2296 |    29 (0) | 00:00:01 |    1.    1.

| 2. HASH PARTITION ALL |      |    82. 2296 |    29 (0) | 00:00:01 |    1.    4.

|* 3 |    TABLE ACCESS FULL | PT |    82. 2296 |    29 (0) | 00:00:01 |    1.    4.

-----------------------------------------------------------------------------------------------

Information of predicates (identified by the operation identity card):

---------------------------------------------------

3 - filter ("C1" = 0)

--

John Watson

Oracle Certified Master s/n

Interval partitioning: excessive value PARTITION_COUNT

Hello
My apologies if this question is in the wrong place - I wasn't sure where to ask.
I am trying to create a partitioned table of interval:
CREATE TABLE my_test
(my_column VARCHAR2 (10))
created_date TIMESTAMP
)
PARTITION OF RANGE (created_date)
INTERVAL (NUMTOYMINTERVAL (1, 'MONTH'))
(
PARTITION part_01 VALUES LESS THAN (TO_DATE('01-DEC-2014','DD-MON-YYYY'))
);
The table has only 1 row in it, with a value of created_date a month ago. So I expect to create only a single partition, which includes the rank and a new monthly from December, when data is added.
When I have a user_part_tables request, is aware that the table has 1 048 575 partitions in the PARTITION_COUNT column.
What I am doing wrong?
Oracle version: Enterprise Edition Release 11.2.0.3.0
Thanks in advance for any help.

Discovered that the value is actually provided for in the PARTITION_COUNT of user_part_tables: this is the maximum possible scores. The number of existing partitions are in user_tab_partitions.

Partition wise joined possible with partitions of the interval?

Hello
I want to know the score wise join (NTC) is possible with interval partitioning - I can't find an explicit statement that he isn't, but I can't make it work - I did a simple test case to illustrate the issue.
below, I have 2 create table scripts - 1 for the case of interval and 1 for the case of hash - I then a simple query on these 2 objects which should produce a NTC.
In the case of hash, it works very well (see screenshot 2nd with a set of slaves), the first screenshot shows the case of the interval where I find myself with 2 sets of slaves and no NTC.
No idea if this is possible and I just missed something?
(for the test case choose the names of schema/storage appropriate for your system)
Oh and version (I almost forgot... :-))-East 11.2.0.4.1 SLES 11)
See you soon,.
Rich
-case interval
CREATE TABLE 'SB_DWH_IN '. "' TEST1 '.
TABLESPACE "SB_DWH_INTEGRATION".
PARTITION BY RANGE ("OBJECT_ID") INTERVAL (10000)
(PARTITION 'LESS_THAN_ZERO' VALUES LESS THAN (0) TABLESPACE "SB_DWH_INTEGRATION")
in select * from DBA_OBJECTS where object_id is not null;
CREATE TABLE 'SB_DWH_IN '. "" TEST2 ".
TABLESPACE "SB_DWH_INTEGRATION".
PARTITION BY RANGE ("OBJECT_ID") INTERVAL (10000)
(PARTITION 'LESS_THAN_ZERO' VALUES LESS THAN (0) TABLESPACE "SB_DWH_INTEGRATION")
in select * from DBA_OBJECTS where object_id is not null;
-case of hash
CREATE TABLE 'SB_DWH_IN '. "' TEST1 '.
TABLESPACE "SB_DWH_INTEGRATION".
8 partitions PARTITION OF HASH ("OBJECT_ID")
store in ("SB_DWH_INTEGRATION")
in select * from DBA_OBJECTS where object_id is not null;
CREATE TABLE 'SB_DWH_IN '. "" TEST2 ".
TABLESPACE "SB_DWH_INTEGRATION".
8 partitions PARTITION OF HASH ("OBJECT_ID")
store in ("SB_DWH_INTEGRATION")
in select * from DBA_OBJECTS where object_id is not null;
-query to run
Select / * + PARALLEL(TEST2,8) PARALLEL(TEST1,8) * / *.
of 'SB_DWH_IN '. "" TEST2 ","SB_DWH_IN ". "' TEST1 '.
where TEST1.object_id = test2.object_id

It is planned and a consequence of the estimate of the number of parallel slaves.

To the parallel 41 each slave made 3 passes (i.e. sleeves 3 partitions).

Add a partition (by table), and a set of slaves will have to manage a 4th pass: the cost of the query using NTC would increase from 33 percent even if the modification of the data is less than 0.8%.

I guess that in the production Oracle distributes your lines of 1 M for a hash join.

Because the decision is encrypted, it is possible that a very extreme tilt in partition in the table sizes billion line might overthrow the optimizer in a non - NTC join - but I have not tested that.

If you want to force the plan John Watson suggestion for a hint of pq_distribute is relevant. To cover all the bases and call your tables SMALL and LARGE

/*+

leading (FAT kid)

USE_HASH (large)

no_swap_join_inputs (large)

PQ_DISTRIBUTE (wide none none)

*/

If it's legal, that should do it.

Concerning

Jonathan Lewis

Creating a partitioned table to an existing table interval.

Hello
Is there a way I can create a partitioned table interval of an existing table using DEC? I know how to create a partitioned table in range.
create the table range_partitioned_table
partition by range (date_column)
(
partition p1 lower ((to_date (' 08/01/2012 ',' mm/dd/yyyy'))),
lower partition p2 values (to_date (' 09/01/2012 ',' mm/dd/yyyy')),
PN VALUES LESS THAN (MAXVALUE) PARTITION
)
AS SELECT * from existing_table;
Is there a similar way to the Interval partition an existing table?

create the table interval_partitioned_table

partition by range (date_column)

interval (provide the interval)

(

partition p1 lower ((to_date (' 08/01/2012 ',' mm/dd/yyyy'))),

partition p2 values less (to_date (' 09/01/2012 ',' mm/dd/yyyy')),

-PN SCORE VALUES LESS THAN (MAXVALUE)

)

AS SELECT * from existing_table;

For example:

SQL > create table interval_partitioned_table
2 partition by range (hiredate)
interval of 3 (numtoyminterval(1,'YEAR'))
(4)
5 score below p1 ((to_date (' 08/01/2012 ',' mm/dd/yyyy'))),
6 partition p2 values less (to_date (' 09/01/2012 ',' mm/dd/yyyy')),
7 - PARTITION pN VALUES LESS THAN (MAXVALUE)
8)
9 AS SELECT * FROM emp;

Table created.

SQL >

SY.

How to search the dictionary of data for the partitions of the interval?

Oracle 11.2.0.3
When I have a DBA_PART_TABLES request. PARTITIONING_TYPE he says "beach". I want to be able to differential an interval of other partitions of range based in the data dictionary?

used this example. Watch "range".
http://www.rittmanmead.com/2008/09/investigating-Oracle-11g-interval-partitioning/
Oracle Docs list 'SYSTEM' as a partitioning_type that I thought would be intervals.
ALL_PART_TABLES
[code]
1 CREATE TABLE interval_sales
2 (prod_id NUMBER (6))
3, cust_id NUMBER
4, time_id DATE
5, channel_id char (1)
6, promo_id NUMBER (6)
7, quantity_sold NUMBER (3)
8, amount_sold NUMBER (10.2)
9 )
10 PARTITION BY RANGE (time_id)
INTERVAL OF 11 (NUMTOYMINTERVAL (1, 'MONTH'))
12 (PARTITION p0 VALUES LESS THAN (TO_DATE (' 01/01/2005 ',' DD-MM-YYYY "")),)
13 PARTITION p1 VALUES LESS THAN (TO_DATE (' 01/01/2006 ',' DD-MM-YYYY ""));
14 p2 PARTITION VALUES LESS THAN (TO_DATE (' 07/01/2006 ',' DD-MM-YYYY ""));
15 * PARTITION p3 VALUES LESS THAN (TO_DATE (' 01/01/2007 ',' DD-MM-YYYY "")))
SQL > /.
Table created.
Elapsed time: 00:00:00.01
SQL > select partitioning_type from the user_part_tables where table_name = 'INTERVAL_SALES ';
PARTITION
---------
RANGE
[/ code]
```
CREATE TABLE junk1
   ( id         NUMBER )
   PARTITION BY RANGE (id)
   INTERVAL(5)
     ( PARTITION p0 VALUES LESS THAN (5),
       PARTITION p1 VALUES LESS THAN (10),
       PARTITION p2 VALUES LESS THAN (15),
       PARTITION p3 VALUES LESS THAN (20) )
/

CREATE TABLE junk2
   ( id         NUMBER )
   PARTITION BY RANGE (id)
     ( PARTITION p0 VALUES LESS THAN (5),
       PARTITION p1 VALUES LESS THAN (10),
       PARTITION p2 VALUES LESS THAN (15),
       PARTITION p3 VALUES LESS THAN (20) )
/

select owner, table_name, partitioning_type, interval
  from dba_part_tables
 where table_name in ('JUNK1', 'JUNK2')
/
```
TABLE_NAME OWNER PARTITIONING_TYPE INTERVAL

------------------------------ ------------------------------ ----------------- --------------------

GREGS JUNK1 RANGE 5

GREGS JUNK2 RANGE

2 selected lines.

partition interval on the data type TIMESTAMP PrimaryKey
question:
Need example of Oracle Interval partitioning on the TIMESTAMP data type of primary key, including the LOCAL INDEX generated by partitioned interval key functional

Published by: oracletune on April 17, 2013 07:51
>
* It seems that interval of time STAMP partitioning is not supported:
>
This is not correct.
>
Partitioning interval is limited to a partition key unique to a numeric or date range.
>
The above is YOUR text and is NOT what the doc.

The VLDB and partitioning Guide
http://docs.Oracle.com/CD/E18283_01/server.112/e16541/part_admin001.htm#BAJHFFBE
>
For the partitioning of the interval, the partitioning key can be a single column of the table name, and it must be the number or DATE type.
>
Which must be read carefully. It is said should be "NUMBER or DATE type. Note that 'DATE type' does NOT mean 'Type of DATE data. A TIMESTAMP (but not TIMESTAMP WITH TIMEZONE) are a type of DATE. It's confusing and the doc must could be formulated differently.

This code is very well:
```
drop table test_part_timestamp

CREATE TABLE TEST_PART_TIMESTAMP
(
PRODUCT_ID NUMBER,
DESCRIPTION VARCHAR2(20 BYTE),
CREATE_DATE TIMESTAMP(6)
)
PARTITION BY RANGE (CREATE_DATE)
INTERVAL(NUMTOYMINTERVAL(1, 'MONTH'))
(
PARTITION OLD_DATA VALUES LESS THAN (TIMESTAMP' 2013-01-01 00:00:00'),
PARTITION P_2013_JAN VALUES LESS THAN (TIMESTAMP' 2013-02-01 00:00:00')
)
```

Range of partitioning of the interval
Hello

Using Oracle 11.20.3
We want to have a table partitioned composite range-hash, a partition for each month.

However, want to esnure are still a tehrfore partition would use range interval partitioning.

Have a few questions, if I say 201301 to 201312 but get intellectualization rosw partition with a value date in June 2014 it create
a new partition for each month IE 201401, 201402 etc. or just a 201406?

Wanyt esnure system can automatically dial with a scenario

Daty1 have partitions 201301 to 201312

Day 2 get record for 201406 (June 2014)

Day 3 get record for 201403 (March 2014)

We have no control over the date range, we were able to get but don't want to tpo have to manually create partitions BOF tehse all dates in advance - want system she managed automatically.

Also you can just rename it the names of system partition generated to something more useful later.
Yes, the creation of partitions of the interval is 'rare' - a given partition will be created only when necessary. (This should be easy to try, by the way).

modify an existing table to selectively the partition interval range
I'm using Oracle 11.2.0.3.

I have an existing table that has parition interval range.

example:
```
 
create table Log( ts date, level  varchar2(20), scr varchar2(2000))PARTITION BY RANGE (TS)
INTERVAL( NUMTODSINTERVAL(1,'DAY'))
```
Currently, we have the log of the table that is the partition of the range by day and we drop old parition to a week. However, we want to change this to persist the records in the table of WHICH = LEVEL "IMPORTANT."

What is the best way to achieve this?
>
Is it possible to modify the existing interval partition table to add partition in the list?
>
Only using the DBMS_REDEFINITION to do online. And that always involves the creation of a "provisional" table

If you have a window of failure just to create a new partitioned table the way you want to and INSERT the data into it. You should be able to use a DEC to do if you want. You may not use swap partition since all data must be physically moved.
>
Can we do list-interval partition table i.e. (with partition interval as partition sup)?
>
No - subpartitioning of interval is not currently supported.

Here is the code example of a partitioned table by using the RANGE-interval LIST. It uses a VIRTUAL column, but you can ignore it for your use case
```
DROP TABLE mytable;

CREATE TABLE mytable
(
CREATION_DATE TIMESTAMP(6),
LAST_MODIFIED_DATE TIMESTAMP(6),
CREATION_DAY NUMBER(2) GENERATED ALWAYS AS (TO_NUMBER(TO_CHAR(CREATION_DATE, 'DD'))) VIRTUAL
)
PARTITION BY RANGE (LAST_MODIFIED_DATE) INTERVAL(NUMTOYMINTERVAL(1, 'MONTH'))
SUBPARTITION BY LIST (CREATION_DAY)
   SUBPARTITION TEMPLATE
   ( SUBPARTITION days_1_5 VALUES (1,2,3,4,5)
   , SUBPARTITION days_6_10 VALUES (6,7,8,9,10)
   , SUBPARTITION days_11_15 VALUES (11,12,13,14,15)
   , SUBPARTITION days_16_20 VALUES (16,17,18,19,20)
   , SUBPARTITION days_21_25 VALUES (21,22,23,24,25)
   , SUBPARTITION days_26_31 VALUES (26,27,28,29,30,31)
   )
(
   PARTITION prior_to_2013 VALUES LESS THAN (TO_DATE('2013-01-01', 'YYYY-MM-DD'))
)
```

Partition by month in number interval
I have a table partitioned on a numeric field. Numeric values are Dates in the format YYYYMM (so 201105 for May 2011).

My question is can I configure a Partition interval that can increment based on this format? I can't use NUMTOYMINTERVAL because it is a NUMERIC field, but I also can't just use INTERVAL (1), since 201112 does not correctly increment to 201201 for this format.

How can I set this up to work or is this even possible?

Thanks for any help or advice!
Lazzrith, I think that your assumption that you can not use an interval of 1 is incorrect. I see no reason not to use 1 as the interval. The whole point of the interval partitioning is that Oracle will automatically create to store the data in your table and nothing besides that data in your partition table. So like 201112 rolls in 201201 and start to insert lines with the dates of 2012, your table will get a new partition for the range 201201. You won't get also the scores for 201113, 201114,..., 201199 because there is no date into your table. As long as you don't accidentally insert a line with an invalid date, you will get exactly one partition for each month of the year, no more, no less.

Disable LOGGING for partition table based on the automatic INTERVAL
Hello

I created a database table of paritioned range interval with NOLOGGING as the default attribute for the table as well as the tablespace definition.

When ORACLE automatically creates a new partition for this table, it activates the LOGGING for this automatic partition even if the table definition says anything else.

How can I go about changing this behavior? Is it still possible?

FYI my platform is 11 GR 1 (11.1.0.7) material on SUN SOLARIS 10 SPARC.

Any help will be appreciated.
Right, so refer to a new feature of Oracle 11 g partitioning called 'partitioning interval. "

+"+
+ The interval partitioning: A new strategy of partitioning in Oracle Database 11g, +.
+ Interval partitioning extends the functionality of the method range to define equipartitioned +.
+ ranges using a definition of the interval. Rather than specify individual +.
+ going to explicitly, Oracle will create any partition automatically as needed.
+ every time the data of a partition are inserted for the first time. Interval +.
+ a lot of partitioning improves maneuverability of a partitioned table. For +.
example, + a partitioned table interval could be set so that Oracle creates a +.
+ new partition for each month in a calendar year; a partition is then automatically +.
+ created for "September 2007" as soon as the first record in this month is inserted.
+ in the database. +
+ The techniques available for a partitioned table interval are interval, interval-+.
+ List, range-Hash, and interval range. +
+"+
```
In order to disable interval partitioning on the transactions table, use:

ALTER TABLE transactions SET INTERVAL ();
```
http://download.Oracle.com/docs/CD/B28359_01/server.111/b32024/part_admin.htm

Disable partitioning interval on this table, create a procedure to run every day we'll say, to create a new partition and chop the old partition of the appropriate table. I presume that the automatic partitioning interval creates the partition with the logging by default option without checking the parameters in the table. I have seen no information on this in the Oracle documentation.

Hope that helps.

Ogan

Partitioning of an existing partitioned table

Dear Experts,
I have a problem with redefinition of partitioning of an existing partitioned table. I have a parent table separated by a virtual column by range:
CREATE THE PARENT TABLE
(
PARENT_ID NUMBER NOT NULL,
INSERT_TIMESTAMP TIMESTAMP (6) NOT NULL,
CLOB PARENT_DATA NOT NULL,
BATCH NUMBER,
DATE of INSERT_DATE generated always as (TRUNC("INSERT_TIMESTAMP"))
)
LOB (PARENT_DATA) AS STORE NAVIGATION (ACTIVATE ONLINE STORAGE)
PARTITION BY RANGE (INSERT_DATE)
(
P2015_11 PARTITION VALUES LESS THAN (TO_DATE (' 2015-12-01 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN '))
CRAFT STORE (PARENT_DATA) AS (SECUREFILE
ACTIVATE THE ONLINE STORAGE),
P2015_12 PARTITION VALUES LESS THAN (TO_DATE (' 2016-01-01 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN '))
CRAFT STORE (PARENT_DATA) AS (SECUREFILE
ACTIVATE THE ONLINE STORAGE),
P2016_01 PARTITION VALUES LESS THAN (TO_DATE (' 2016-02-01 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN '))
CRAFT STORE (PARENT_DATA) AS (SECUREFILE
ALLOW ONLINE STORAGE,
PARTITION P_DEFAULT VALUES LESS THAN (MAXVALUE)
CRAFT STORE (PARENT_DATA) AS (SECUREFILE
ALLOW ONLINE STORAGE
))
);
and a child table partitioned by reference:
CREATE ACCOUNTS FROM THE TABLE. CHILD
(
PARENT_ID NUMBER NOT NULL,
DATAACC DATAACC_TBL,
CREATION_DATE DATE,
CONSTRAINT PARENT_D_E_PRT_FK
FOREIGN KEY (PARENT_ID)
(PARENT_ID) REFERENCES PARENT
ENABLE VALIDATE
)
NESTED TABLE, STORE DATAACC AS DATAACC_NT
PARTITION OF REFERENCE (PARENT_D_E_PRT_FK)
(
P2015_11 PARTITION,
P2015_12 PARTITION,
P2016_01 PARTITION,
PARTITION P_DEFAULT);
However, now in Oracle 12 c I am able to use the reference interval partitioning. How can I redefine the partitioning of the parent table so that there can be scope-level?
Thank you for your help.
Best regards, Atanas.

To change range partition to partition interval, the table should not have MAXVALUE partition... Follow the steps below to convert to partition interval

(1) check if all data of the MAXVALUE partition (p_default) using query below

SELECT COUNT (*) FROM parent PARTITION (p_default).

(2) if there is no trace in the p_default partition, drop the help below

ALTER TABLE DROP PARTITION parent p_default;

(3) use the clause SET INTERVAL to convert the range partition partition interval as below

ALTER TABLE parent SET INTERVAL (NUMTOYMINTERVAL(1,'MONTH'));

I guess, you have the range partition up to until, so there should not be any folder in p_default partition.

Interval partitioning

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