Interval partitioning: excessive value PARTITION_COUNT

Similar Questions

• Interval partitioning using the key of the virtual column

  Hi guys

  I have a series of tables that I propose to the partition.

  Each table has a year and a period (equivalent to a month) and I intend using those as my partition keys - year as the partition and the period as the subpartition.

  The distribution will be actually:

  2015

  001

  002

  ...

  012

  2016

  001

  002

  ...

  012

  etc...

  I would use range partitioning for the year, because it would make the maintenance of the partition a breeze.  Only one problem - the field is of type varchar, and is not modifiable as its legacy applications that have become bigger than Ben Hurr and more tangled than a Ben Hurr size flat spaghetti.

  It is hence the idea of virtual column between in game - I could create a virtual column in these tables to convert the field to digital and then partition on it instead.

  My question-if the year of origin varchar column is included in the where clause of a query, is the optimizer based on CSSTidy smart enough to realize that the virtual column used for the partition key is based on this column and use pruning of partition to improve performance?  Or queries must refer to the virtual column to make it work?  Also, the virtual column should be indexed to make it work?

  Thanks in advance.

  
  

  Simon
  

  orclz >

  orclz > create table pt (v1 varchar2 (1) c1 as (to_number (v1)), number of c2)

  2 partition by range (c1) interval (1)

  subpartition by hash (c2) subpartitions 4 3

  4 (partition p1 values less than (1))

  5.

  Table created.

  orclz > set autot on explain

  orclz > select * PT where v1 = '0';

  no selected line

  Execution plan

  ----------------------------------------------------------

  Hash value of plan: 711571056

  --------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

  --------------------------------------------------------------------------------------------

  |  0 | SELECT STATEMENT |      |    82.  2296 |    29 (0) | 00:00:01 |      |      |

  |  1.  RANGE OF PARTITION ALL THE |      |    82.  2296 |    29 (0) | 00:00:01 |    1. 1048575.

  |  2.  HASH PARTITION ALL |      |    82.  2296 |    29 (0) | 00:00:01 |    1.    4.

  |*  3 |    TABLE ACCESS FULL | PT |    82.  2296 |    29 (0) | 00:00:01 |    1. 1048575.

  --------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  3 - filter ("V1" = '0')

  orclz > select * PT where c1 = 0;

  no selected line

  Execution plan

  ----------------------------------------------------------

  Hash value of plan: 1726115854

  -----------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

  -----------------------------------------------------------------------------------------------

  |  0 | SELECT STATEMENT |      |    82.  2296 |    29 (0) | 00:00:01 |      |      |

  |  1.  RANGE OF SINGLE PARTITION |      |    82.  2296 |    29 (0) | 00:00:01 |    1.    1.

  |  2.  HASH PARTITION ALL |      |    82.  2296 |    29 (0) | 00:00:01 |    1.    4.

  |*  3 |    TABLE ACCESS FULL | PT |    82.  2296 |    29 (0) | 00:00:01 |    1.    4.

  -----------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  3 - filter ("C1" = 0)

  --

  John Watson

  Oracle Certified Master s/n

• Impact of setting the interval partitioning off and then on again

  Hi all

  Have discovered that to split the partitions of a partitioned table Beach-interval, in that we need to define the partitioning interval all issue the command split then on again.

  e, g.

  ALTER TABLE retailer_transaction SET INTERVAL ();

  ALTER TABLE POR2_retailer_transaction

  SPLIT PARTITION PART_400012 AT (TO_DATE (' 2020-09-01 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN '))

  INTO (PARTITION PART_202008,

  PART_400012 PARTITION)

  ALTER TABLE retailer_transaction SET INTERVAL (NUMTOYMINTERVAL(1,'MONTH'))

  Everything we need to pay attention to that?

  Using oracle 11.2.0.3

  Thank you

  You can NOT split the LAST (most HIGH_VALUE) partition of a partitioned table interval interval. You can only separate partitions BEFORE the last. Which converts also all partitions from the bottom (split and below) for the partitions of the RANGE.

  If interval partitioning will only apply to data added above the transition point (the score higher.

  To return to your original question. To split the LAST interval follow the procedure described in your original post

  1. range partitioning

  2 split the partitioning

  3 set the partitioning interval on

  Conclusion with this however when adding data back to a nine month doesn't automatically create the partition again.

  This "new month" MUST BE above the point of passage for a new partition to create. In your code example, this point of transition is for the year 4000.

  This works very well for me:

  ALTER TABLE sales PARTITION RENAME SYS_P1122 to SALE_400012

  ALTER TABLE sale SET INTERVAL ();

  ALTER TABLE SPLIT PARTITION for sale

  SALE_400012 TO (TO_DATE('01/02/2020','DD/MM/YYYY')) IN

  (

  SALE_202001 PARTITION,

  SALE_400012 PARTITION

  );

  ALTER TABLE sale SET INTERVAL (NUMTOYMINTERVAL(1,'MONTH'))

  INSERT INTO sales

  (SALES_DATE, STORE_NUM, QTY_SOLD)

  values (to_date('31/12/4001','DD/,MM/YYYY'), 1, 10);

  This last INSERT statement above creates a NEW partition because the date (31/12/4001) is above the transition point.

  Looks like you want to move the transition point downwards. That is - you were using this year there date of 4000 as a 'catch all '.

  1. set the partitioning interval

  2 split that last partition into two NEW partitions (new names) by using a VALUE that is high enough to contain ALL the data you have in this last partition.

  3. remove the last partition - it should now be empty

  4. turn on range partitioning

  Now, any data that you insert above this NEW point of transition (the limit that you used for the new partition) it will create a new partition of the interval. Make sure the border is really an end of month, if that's what you want.

  If your data sample had this

  INSERT INTO sales

  (SALES_DATE, STORE_NUM, QTY_SOLD)

  values (to_date('05/10/2016','DD/,MM/YYYY'), 1, 10);

  INSERT INTO sales

  (SALES_DATE, STORE_NUM, QTY_SOLD)

  values (to_date('31/12/4000','DD/,MM/YYYY'), 1, 10);

  So for the step #2 above use split date 06/2016 so that the line above for 10/05/2106 goes to the new partition and 12/31/4000 stays in the old.

  Then, drag this old and lines in it (31/12/4000).

  You can NOT split the last partition if interval is always on because it is the last partition interval.

  And as long as you have given for 12/31/4000, you will get no new partitions unless you insert was more TOP than this.

  So if you want partitioning interval to activate again 06/2016 that higher data would be deleted and the score he falls.

  You have discovered only among "traps" with the help of partitioning of the interval. Oracle will happily create new partition needed to keep the data. If ANYONE, even accidentally, between a date as 12/31/4000 that nobody would ever know until the new data seem to DISAPPEAR for some use cases.

  This is because all data will start to enter this new partition ACCIDENTALLY created instead of a partition for the month, it's part.

  And, and you have discovered, you cannot split this partition directly.

  Delayed segment creation can allow you to pre-create the partitions ahead without actually affecting the segment for them until the first row is inserted.

  Interval partitioning will create the appropriate partitions but not if someone accidentally or intentionally, data will be a valuable capitalized in the table.

• Range of interval partitioning on yrwk?

  Hello

  Using oracle 11.2.0.3

  We build a large table and many queries will be such, that we want to divide this query on yearweek on yearweek.

  While we could manually add is the partitions possible to have range interval partitioning for this?

  If so, how - have used the interval with columns date range partitioning

  If was months would be nice, but a few years we have 52 and 53 weeks a few years - we have another table of calendar that tells us the number of weeks but not sure if we could use yrwk + interval partitioning

  Thank you

  Your question is not clear enough. The partitioning key can be a single column of the table name and it must be of NUMBER or DATE type. Assuming that your week of the year is a column for the number.

  SQL> --My datbase version.
  SQL> ---------------------
  SQL> SELECT * FROM v$version;
  
  BANNER
  --------------------------------------------------------------------------------
  Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - 64bit Production
  PL/SQL Release 11.2.0.1.0 - Production
  CORE    11.2.0.1.0      Production
  TNS for Linux: Version 11.2.0.1.0 - Production
  NLSRTL Version 11.2.0.1.0 - Production
  
  SQL> DROP TABLE rng_int_part purge;
  
  Table dropped.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  CREATE TABLE rng_int_part
    2    (
    3      yrwk NUMBER,
    4      col2 VARCHAR2(1)
    5    )
    6    partition BY range
    7    (
    8      yrwk
    9    )
   10    interval
   11    (
   12      1
   13    )
   14    (
   15      partition p_201402 VALUES less than (201401),
   16      partition p_201403 VALUES less than (201402)
   17*   )
  SQL> /
  
  Table created.
  
  SQL> set line 200
  SQL> ed
  Wrote file afiedt.buf
  
    1  SELECT table_name,
    2    partition_name,
    3    high_value
    4  FROM user_tab_partitions
    5* WHERE table_name='RNG_INT_PART'
  SQL> /
  
  TABLE_NAME                     PARTITION_NAME                 HIGH_VALUE
  ------------------------------ ------------------------------ --------------------------------------------------------------------------------
  RNG_INT_PART                   P_201402                       201401
  RNG_INT_PART                   P_201403                       201402
  
  SQL> INSERT INTO rng_int_part VALUES
    (201401,'A'
    )  2
  SQL> /
    (201401,'A'
              *
  ERROR at line 2:
  ORA-00917: missing comma
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  INSERT INTO rng_int_part VALUES
    2    (201401,'A'
    3*   )
  SQL> /
  
  1 row created.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  INSERT INTO rng_int_part VALUES
    2    (201401,'B'
    3*   )
  SQL> /
  
  1 row created.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  SELECT table_name,
    2    partition_name,
    3    high_value
    4  FROM user_tab_partitions
    5* WHERE table_name='RNG_INT_PART'
  SQL> /
  
  TABLE_NAME                     PARTITION_NAME                 HIGH_VALUE
  ------------------------------ ------------------------------ --------------------------------------------------------------------------------
  RNG_INT_PART                   P_201402                       201401
  RNG_INT_PART                   P_201403                       201402
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  INSERT INTO rng_int_part VALUES
    2    (201403,'A'
    3*   )
  SQL> /
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  SELECT table_name,
    2    partition_name,
    3    high_value
    4  FROM user_tab_partitions
    5* WHERE table_name='RNG_INT_PART'
  SQL> /
  
  TABLE_NAME                     PARTITION_NAME                 HIGH_VALUE
  ------------------------------ ------------------------------ --------------------------------------------------------------------------------
  RNG_INT_PART                   P_201402                       201401
  RNG_INT_PART                   P_201403                       201402
  RNG_INT_PART                   SYS_P25                        201404
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  INSERT INTO rng_int_part VALUES
    2    (201452,'A'
    3    )
    4  /
    5  INSERT INTO rng_int_part VALUES
    6    (201501,'A'
    7*   )
    8  /
  /
  *
  ERROR at line 4:
  ORA-00933: SQL command not properly ended
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  INSERT INTO rng_int_part VALUES
    2    (201452,'A'
    3*   )
  SQL> /
  
  1 row created.
  
  SQL>
  SQL> commit;
  
  Commit complete.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  INSERT INTO rng_int_part VALUES
    2    (201501,'A'
    3*   )
  SQL> /
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  
  SQL> ed
  Wrote file afiedt.buf
  
    1  SELECT table_name,
    2    partition_name,
    3    high_value
    4  FROM user_tab_partitions
    5* WHERE table_name='RNG_INT_PART'
  SQL> /
  
  TABLE_NAME                     PARTITION_NAME                 HIGH_VALUE
  ------------------------------ ------------------------------ --------------------------------------------------------------------------------
  RNG_INT_PART                   P_201402                       201401
  RNG_INT_PART                   P_201403                       201402
  RNG_INT_PART                   SYS_P25                        201404
  RNG_INT_PART                   SYS_P26                        201453
  RNG_INT_PART                   SYS_P27                        201502
  
  SQL> 
  

• How to create the INTERVAL partitioning using EM?

  Hi guys

  I'm still not able to use the INTERVAL partitioning using EM. Is it possible to do?

  Oracle 11 g 2 on Linux

  Thank you

  John

  Hi John,.

  I don't think it's possible, that the option of partition of the range seems to have things that make you think of it would generate the definition as the partitioning interval but it doesn't.

  I'm on 12.1.0.3 of the SGC and 12.1.0.5 DB plugin so I'm sure it's 'missing' features for the moment.

  See you soon,.

  Rich

• Interval partitioning

  Hello
  
  Please let me know if an interval of partitioning can be created on a table for all the two weeks?
  
  DB version is 11g.
  
  Thank you

  Because the interval partitioning allows you to specify the size range (read the documentation for it)
  and that a fortnight is 14 days by the usual definition

  Then, the 'yes '.

• With the help of INTERVAL with the value of the column in to_char?

  I have a table with data having a datetime value in a column and a zone in the next column offset, designated as an integer (-6, - 7, etc.) I need to get the value of real time for use in queries, but I can't seem to find a way to do this without creating my own function to do so.
  
  Basically, I have to be able to do something like this:
  

  SELECT LOCATION_DATE + INTERVAL LOCATION_TIMEZONE HOUR from tablex

  LOCATION_DATE and LOCATION_TIMEZONE are columns in tablex
  
  
  This function seems to work:

  CREATE OR REPLACE FUNCTION FN_SHIFTDATE(dt DATE, tz VARCHAR2)
    RETURN DATE
  IS
    f_dt      DATE;
    f_tz      VARCHAR2(3);
    v_sql     VARCHAR2(500);
    r_dt      DATE;
  BEGIN
    f_dt      := dt;
    f_tz      := tz;
    v_sql  := 'select to_date('''|| to_char(f_dt,'MM/DD/YYYY HH24:MI:SS')||''',''MM/DD/YYYY HH24:MI:SS'')'||'+INTERVAL '''|| f_tz ||''' HOUR from dual';
    EXECUTE IMMEDIATE v_sql into r_dt;
    RETURN r_dt;
  END;
  /

  I was just curious if there was a way to do it directly in SQL without having to call a function every time to slow down the query.

  So, you want to just add a number of hours on a date?

  select LOCATION_DATE + LOCATION_TIMEZONE/24 NEW_TIME from tablex
  

  Max
  http://oracleitalia.WordPress.com

  Published by: Massimo Ruocchio, February 19, 2010 12:21 AM

• How to get details of partition interval value. In what its stored dictionary.

  I have create table statement below. I want details on interval value. Where it is stored in the oracle Table.

  Please let me know one.

  CREATE TABLE PARTITION_T1 (ID NUMBER, VARCHAR2 ADDRESS (1000))

  PARTITION OF RANGE (ID)

  INTERVAL (10)

  SUBPARTITION BY LIST (ADDRESS)

  (PARTITION P1 VALUES LESS THAN (30))

  (SUBPARTITION S_P1 VALUES ('BDM', 'DEL'))) ;

  What dictionary its INTERVAL (10) stored value retail.

  Select the INTERVAL from dba_part_tables where table_name = 'PARTITION_T2 ';

  I got the result.

• Partition wise joined possible with partitions of the interval?

  Hello

  I want to know the score wise join (NTC) is possible with interval partitioning - I can't find an explicit statement that he isn't, but I can't make it work - I did a simple test case to illustrate the issue.

  below, I have 2 create table scripts - 1 for the case of interval and 1 for the case of hash - I then a simple query on these 2 objects which should produce a NTC.

  In the case of hash, it works very well (see screenshot 2nd with a set of slaves), the first screenshot shows the case of the interval where I find myself with 2 sets of slaves and no NTC.

  No idea if this is possible and I just missed something?

  (for the test case choose the names of schema/storage appropriate for your system)

  Oh and version (I almost forgot... :-))-East 11.2.0.4.1 SLES 11)

  See you soon,.

  Rich

  -case interval

  CREATE TABLE 'SB_DWH_IN '. "' TEST1 '.

  TABLESPACE "SB_DWH_INTEGRATION".

  PARTITION BY RANGE ("OBJECT_ID") INTERVAL (10000)

  (PARTITION 'LESS_THAN_ZERO' VALUES LESS THAN (0) TABLESPACE "SB_DWH_INTEGRATION")

  in select * from DBA_OBJECTS where object_id is not null;

  CREATE TABLE 'SB_DWH_IN '. "" TEST2 ".

  TABLESPACE "SB_DWH_INTEGRATION".

  PARTITION BY RANGE ("OBJECT_ID") INTERVAL (10000)

  (PARTITION 'LESS_THAN_ZERO' VALUES LESS THAN (0) TABLESPACE "SB_DWH_INTEGRATION")

  in select * from DBA_OBJECTS where object_id is not null;

  -case of hash

  CREATE TABLE 'SB_DWH_IN '. "' TEST1 '.

  TABLESPACE "SB_DWH_INTEGRATION".

  8 partitions PARTITION OF HASH ("OBJECT_ID")

  store in ("SB_DWH_INTEGRATION")

  in select * from DBA_OBJECTS where object_id is not null;

  CREATE TABLE 'SB_DWH_IN '. "" TEST2 ".

  TABLESPACE "SB_DWH_INTEGRATION".

  8 partitions PARTITION OF HASH ("OBJECT_ID")

  store in ("SB_DWH_INTEGRATION")

  in select * from DBA_OBJECTS where object_id is not null;

  -query to run

  Select / * + PARALLEL(TEST2,8) PARALLEL(TEST1,8) * / *.

  of 'SB_DWH_IN '. "" TEST2 ","SB_DWH_IN ". "' TEST1 '.

  where TEST1.object_id = test2.object_id

  

  

  It is planned and a consequence of the estimate of the number of parallel slaves.

  To the parallel 41 each slave made 3 passes (i.e. sleeves 3 partitions).

  Add a partition (by table), and a set of slaves will have to manage a 4th pass: the cost of the query using NTC would increase from 33 percent even if the modification of the data is less than 0.8%.

  I guess that in the production Oracle distributes your lines of 1 M for a hash join.

  Because the decision is encrypted, it is possible that a very extreme tilt in partition in the table sizes billion line might overthrow the optimizer in a non - NTC join - but I have not tested that.

  If you want to force the plan John Watson suggestion for a hint of pq_distribute is relevant.  To cover all the bases and call your tables SMALL and LARGE

  /*+

  leading (FAT kid)

  USE_HASH (large)

  no_swap_join_inputs (large)

  PQ_DISTRIBUTE (wide none none)

  */

  If it's legal, that should do it.

  Concerning

  Jonathan Lewis

• Dynamically partition a table based on different values of a specific column: possible?

  I'll start by explaining my problem, so that you can have a global vision of the problem and perhaps suggest another solution. Problem: I have 2 tables with millions of records. Records are added daily, and so each row in each table has a column of "insertion_date".

  C1 C2 ... C10 insertion_date (type date, ofc)
  

  lines are cleaned according to the insertion_date parameter. This can happen in two ways:

  1 - whenever an application error appears. In this case delete is based on a single day and would be like:

  delete from T1 where insertion_date=##;
  

  in other words remove us the lines added and then restart the program (business logic, can't change it)

  2. every two weeks the data associated with these two weeks are deleted because will be most used:

  delete from T1 where insertion_date between ## and ##; (a two weeks period here)   
  

  Delete is currently very slow: it takes abot 8 minutes just to remove approximately 5 M of records (with the same insertion_date), I can't even imagine the time required to delete records more.

  So, here's my idea!

  I would partition my DB according to the value of insertion_date.

  To remove case 1 I would simply delete the partion associated with this insertion date, to remove scores of cases 2 associates at that interval.

  For the needs of my application at most 15 were leaving are present each time (maybe 20 if I want to keep last at least 5 days of data), so the documented limit of 64000 partitions is not a problem.

  Real problem is that I do not know insertion_date values in advance, so my question: is it possible to automatically create a new partition every time presents itself a new value of insertion_date?

  And please correct me if I'm wrong, if I accomplish partitioning that I wouldn't need to edit above right queries? I know just the faster removal time am I correct?

  No - it isn't bog standard range partitioning partitioning interval

  But perhaps you're citing 9i documentation for a reason?

  It is a feature of 11g... then only about 10 years.

  create table t1
  (col1  date)
  partition by range (col1) interval (numtodsinterval(1,'DAY'))
  (partition po values less than (to_date('01-01-2015','DD-MM-YYYY')));
  
  table T1 created.
  
  select table_name, partition_name, high_value from user_tab_partitions where table_name = 'T1';
  
  TABLE_NAME                     PARTITION_NAME                 HIGH_VALUE
  ------------------------------ ------------------------------ --------------------------------------------------------------------------------
  T1                             PO                             TO_DATE(' 2015-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA...'
  
  insert into t1
  select trunc(sysdate,'MM')+rownum-1
  from   dual
  connect by  rownum <= 10;
  
  select table_name, partition_name, high_value from user_tab_partitions where table_name = 'T1';
  
  TABLE_NAME                     PARTITION_NAME                 HIGH_VALUE
  ------------------------------ ------------------------------ --------------------------------------------------------------------------------
  T1                             PO                             TO_DATE(' 2015-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA...'
  T1                             SYS_P450383                    TO_DATE(' 2015-07-02 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA...'
  T1                             SYS_P450384                    TO_DATE(' 2015-07-03 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450385                    TO_DATE(' 2015-07-04 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450386                    TO_DATE(' 2015-07-05 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450387                    TO_DATE(' 2015-07-06 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450388                    TO_DATE(' 2015-07-07 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450389                    TO_DATE(' 2015-07-08 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450390                    TO_DATE(' 2015-07-09 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450391                    TO_DATE(' 2015-07-10 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450392                    TO_DATE(' 2015-07-11 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  

• Query for the partitions of the interval, system and reference

  Hi, I want to ask some of range partitions, system and reference information.

  In the partition of the interval, the script looks like this

  CREATE TABLE interval_sales

  (prod_id NUMBER (6))

  cust_id NUMBER

  time_id DATE

  )

  PARTITION OF RANGE (time_id)

  INTERVAL (NUMTOYMINTERVAL (1, 'MONTH'))

  (PARTITION p0 VALUES LESS THAN (TO_DATE (' 01/01/2005 ',' DD-MM-YYYY "")));

  I would like to write a query to find the expression of the interval "MONTHS" but could not find what he makes.

  In the reference partition, the script looks like this

  CREATE TABLE child_tab)

  ID NUMBER NOT NULL,

  parent_tab_id NUMBER NOT NULL,

  code VARCHAR2 (10),

  Description VARCHAR2 (50).

  CREATED_DATE DATE,

  CONSTRAINT child_tab_pk PRIMARY KEY (id),

  CONSTRAINT child_parent_tab_fk FOREIGN KEY (parent_tab_id)

  REFERENCES parent_tab (id)

  )

  PARTITION BY REFERENCE (child_parent_tab_fk);

  I want to write a query to find the foreign key name 'child_parent_tab_fk' after the PARTITION BY REFERENCE to the last line, but have no luck so far.

  In the end, I want to achieve this goal:

  If (interval_partitioning_type)

  Assign the interval expression to a string variable

  Another yew (reference_partitioning_type)

  Set the foreign key to a variable of type of foreign key

  Is there a way to get the type of partitioning? (interval and reference here)

  Please advise,

  Jack

  You can query ALL_PART_TABLES

  REF_PTN_CONSTRAINT_NAME	VARCHAR2(30)		Name of the referential partitioning constraint for partitioned tables reference
  INTERVAL	VARCHAR2(1000)		The value of the interval chain

• Select to partition interval

  Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production

  I have a partitioned table of interval on a range of numbers and to select the data of a partition for a specific value is

  CREATE TABLE part_test(part_key       NUMBER
                        ,part_data      VARCHAR2(10)
                        )
  PARTITION BY RANGE (part_key)
    INTERVAL ( 1 )
    (PARTITION p_base VALUES LESS THAN (0));
  
  INSERT INTO part_test(part_key, part_data)
  VALUES      (-1, '-1');
  INSERT INTO part_test(part_key, part_data)
  VALUES      (0, '0');
  INSERT INTO part_test(part_key, part_data)
  VALUES      (1, '1');
  INSERT INTO part_test(part_key, part_data)
  VALUES      (2, '2');
  COMMIT;
  
  SELECT *
  FROM   part_test PARTITION FOR(1);
  

  What I really want to select the partition is based on a value in another table to be

  CREATE TABLE part_value (part_key NUMBER);
  
  INSERT INTO part_value(part_key)
  VALUES      (1);
  COMMIT;
  
  SELECT *
  FROM   part_test PARTITION FOR(select part_key from part_value);
  

  It gives ORA-00936: lack of expression.  I could use dynamic sql statements to create the query (or generate a view), but it would save instead.  Any ideas if this can be achieved by a simple sql statement?

  Thank you.

  You try something like:

  SELECT *.

  OF part_test pt, part_value pv

  where pt.part_key = pv.part_key

  In most cases a particular partition will be only accessible, no full table scans (not true in all scenarios, however)

• Creating a partitioned table to an existing table interval.

  Hello

  Is there a way I can create a partitioned table interval of an existing table using DEC? I know how to create a partitioned table in range.

  create the table range_partitioned_table

  partition by range (date_column)

  (

  partition p1 lower ((to_date (' 08/01/2012 ',' mm/dd/yyyy'))),

  lower partition p2 values (to_date (' 09/01/2012 ',' mm/dd/yyyy')),

  PN VALUES LESS THAN (MAXVALUE) PARTITION

  )

  AS SELECT * from existing_table;

  Is there a similar way to the Interval partition an existing table?

  create the table interval_partitioned_table

  partition by range (date_column)

  interval (provide the interval)

  (

  partition p1 lower ((to_date (' 08/01/2012 ',' mm/dd/yyyy'))),

  partition p2 values less (to_date (' 09/01/2012 ',' mm/dd/yyyy')),

  -PN SCORE VALUES LESS THAN (MAXVALUE)

  )

  AS SELECT * from existing_table;

  For example:

  SQL > create table interval_partitioned_table
  2 partition by range (hiredate)
  interval of 3 (numtoyminterval(1,'YEAR'))
  (4)
  5 score below p1 ((to_date (' 08/01/2012 ',' mm/dd/yyyy'))),
  6 partition p2 values less (to_date (' 09/01/2012 ',' mm/dd/yyyy')),
  7 - PARTITION pN VALUES LESS THAN (MAXVALUE)
  8)
  9 AS SELECT * FROM emp;

  Table created.

  SQL >

  SY.

• Size of partition on interval range partitioned Table happens when SYSDATE is used in a Where Clause

  We have tables interval range partitioned on a DATE, with a partition for each day column - very standard and straight out of doc Oracle.

  A 3rd party application queries the tables to find the number of rows based on the date range that is located on the column used for the partition key.

  This application uses the date range specified from the current date - i.e. for last two days would be «...» StartDate > SYSDATE-2 "- but the partition size is irrelevant and the explain command plan shows that each partition is included."

  In presenting the request uses the date in a variable partition size location and query table is obviously much better.

  DB is 11.2.0.3 on RHEL6, and default settings - i.e. nothing that could influence the behavior of the optimizer to something unusual.

  I can't work on why this would be the case. It is very easy to reproduce with cases of simple test below.

  I would be very interested to hear any views on why it's that way and if anything can be done to allow the size of the partition to work with a query including SYSDATE because it would be difficult to get the application code has changed.

  In addition to make a case to change the code, I need an explanation of why query using SYSDATE is not advisable and I know this information.

  (1) create a simple partitioned table

  CREATETABLE part_test
     (id                      NUMBER NOT NULL,
      starttime               DATE NOT NULL,
      CONSTRAINT pk_part_test PRIMARY KEY (id)) 
  PARTITION BY RANGE (starttime) INTERVAL (NUMTODSINTERVAL(1,'day')) (PARTITION p0 VALUES LESS THAN (TO_DATE('01-01-2013','DD-MM-YYYY')));
  

  (2) fill in the rows of the table 1 million distributed among 10 partitions

  BEGIN
      FOR i IN 1..1000000
      LOOP
          INSERT INTO part_test (id, starttime) VALUES (i, SYSDATE - DBMS_RANDOM.value(low => 1, high => 10));
      END LOOP;
  END;
  /
  EXEC dbms_stats.gather_table_stats('SUPER_CONF','PART_TEST');
  

  (3) to query the Table of data from the last 2 days using SYSDATE in paragraph

  EXPLAIN PLAN FOR 
  SELECT  count(*) 
  FROM    part_test
  WHERE   starttime >= SYSDATE - 2;
  

  -------------------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

  -------------------------------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |           |     1.     3 ×  7895 (1) | 00:00:01 |       |       |

  |   1.  GLOBAL TRI |           |     1.     3 ×            |          |       |       |

  |   2.   RANGE OF PARTITION ITERATOR.           |   111K |   867K |  7895 (1) | 00:00:01 |   KEY | 1048575.

  |*  3 |    TABLE ACCESS FULL | PART_TEST |   111K |   867K |  7895 (1) | 00:00:01 |   KEY | 1048575.

  -------------------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  3 - filter("STARTTIME">=SYSDATE@!-2)

  (4) now do the same query, but with SYSDATE - 2 presented as a literal value.

  This query returns the same response but very different cost.

  EXPLAIN PLAN FOR
  SELECT count(*) 
  FROM part_test
  WHERE starttime >= (to_date('23122013:0950','DDMMYYYY:HH24MI'))-2;
  

  -------------------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

  -------------------------------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |           |     1.     8.   131 (0) | 00:00:01 |       |       |

  |   1.  GLOBAL TRI |           |     1.     8.            |          |       |       |

  |   2.   RANGE OF PARTITION ITERATOR.           |   111K |   867K |   131 (0) | 00:00:01 |   356 . 1048575.

  |*  3 |    TABLE ACCESS FULL | PART_TEST |   111K |   867K |   131 (0) | 00:00:01 |   356 | 1048575.

  -------------------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  3 filter ("STARTTIME" > = TO_DATE (' 2013-12-21 09:50 ',' syyyy-mm-dd hh24:mi:ss'))))

  Thank you in anticipation

  Jim

  sysdate is not constant and its value may change from time optimization of execution; but the optimizer can deduce that he will be a known running value and then produce a plan that will make the size of partition running.  This is the meaning of 'KEY' in the column pstart – the partition of departure will be known at run time and the size of partition will take place in order to eliminate the previous partitions.

  Concerning

  Jonathan Lewis

• Partition on a column for the number interval

  Hi team, 11 2 GR.,

  We have to partition an existing table in size 20g, but the partition key column is NUMBER type and the data stored in the date format unix.

  I would like to create a monthly as partition table below. But not able to create. The reflections and suggestions pls?

  create the table () students

  ENTRY_ID number (5.1).

  NAME varchar2 (30 BYTE)

  )

  partition by range (fun_unix_to_date (ENTRY_ID))-> fun_unix_to_date is a custom function to convert unix timestamp to date format.

  INTERVAL (100)

  (PARTITION CATCH_ALL values LESS (to_date('01-MAR-12','DD-MON-YY')));

  ERROR on line 5:

  ORA-00907: lack of right parenthesis

  Thank you

  Thanks for the link Stefan. Really useful for me.