Range of interval partitioning on yrwk?

Similar Questions

• Interval partitioning using the key of the virtual column

  Hi guys

  I have a series of tables that I propose to the partition.

  Each table has a year and a period (equivalent to a month) and I intend using those as my partition keys - year as the partition and the period as the subpartition.

  The distribution will be actually:

  2015

  001

  002

  ...

  012

  2016

  001

  002

  ...

  012

  etc...

  I would use range partitioning for the year, because it would make the maintenance of the partition a breeze.  Only one problem - the field is of type varchar, and is not modifiable as its legacy applications that have become bigger than Ben Hurr and more tangled than a Ben Hurr size flat spaghetti.

  It is hence the idea of virtual column between in game - I could create a virtual column in these tables to convert the field to digital and then partition on it instead.

  My question-if the year of origin varchar column is included in the where clause of a query, is the optimizer based on CSSTidy smart enough to realize that the virtual column used for the partition key is based on this column and use pruning of partition to improve performance?  Or queries must refer to the virtual column to make it work?  Also, the virtual column should be indexed to make it work?

  Thanks in advance.

  
  

  Simon
  

  orclz >

  orclz > create table pt (v1 varchar2 (1) c1 as (to_number (v1)), number of c2)

  2 partition by range (c1) interval (1)

  subpartition by hash (c2) subpartitions 4 3

  4 (partition p1 values less than (1))

  5.

  Table created.

  orclz > set autot on explain

  orclz > select * PT where v1 = '0';

  no selected line

  Execution plan

  ----------------------------------------------------------

  Hash value of plan: 711571056

  --------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

  --------------------------------------------------------------------------------------------

  |  0 | SELECT STATEMENT |      |    82.  2296 |    29 (0) | 00:00:01 |      |      |

  |  1.  RANGE OF PARTITION ALL THE |      |    82.  2296 |    29 (0) | 00:00:01 |    1. 1048575.

  |  2.  HASH PARTITION ALL |      |    82.  2296 |    29 (0) | 00:00:01 |    1.    4.

  |*  3 |    TABLE ACCESS FULL | PT |    82.  2296 |    29 (0) | 00:00:01 |    1. 1048575.

  --------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  3 - filter ("V1" = '0')

  orclz > select * PT where c1 = 0;

  no selected line

  Execution plan

  ----------------------------------------------------------

  Hash value of plan: 1726115854

  -----------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

  -----------------------------------------------------------------------------------------------

  |  0 | SELECT STATEMENT |      |    82.  2296 |    29 (0) | 00:00:01 |      |      |

  |  1.  RANGE OF SINGLE PARTITION |      |    82.  2296 |    29 (0) | 00:00:01 |    1.    1.

  |  2.  HASH PARTITION ALL |      |    82.  2296 |    29 (0) | 00:00:01 |    1.    4.

  |*  3 |    TABLE ACCESS FULL | PT |    82.  2296 |    29 (0) | 00:00:01 |    1.    4.

  -----------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  3 - filter ("C1" = 0)

  --

  John Watson

  Oracle Certified Master s/n

• Impact of setting the interval partitioning off and then on again

  Hi all

  Have discovered that to split the partitions of a partitioned table Beach-interval, in that we need to define the partitioning interval all issue the command split then on again.

  e, g.

  ALTER TABLE retailer_transaction SET INTERVAL ();

  ALTER TABLE POR2_retailer_transaction

  SPLIT PARTITION PART_400012 AT (TO_DATE (' 2020-09-01 00:00:00 ',' SYYYY-MM-DD HH24:MI:SS ',' NLS_CALENDAR = GREGORIAN '))

  INTO (PARTITION PART_202008,

  PART_400012 PARTITION)

  ALTER TABLE retailer_transaction SET INTERVAL (NUMTOYMINTERVAL(1,'MONTH'))

  Everything we need to pay attention to that?

  Using oracle 11.2.0.3

  Thank you

  You can NOT split the LAST (most HIGH_VALUE) partition of a partitioned table interval interval. You can only separate partitions BEFORE the last. Which converts also all partitions from the bottom (split and below) for the partitions of the RANGE.

  If interval partitioning will only apply to data added above the transition point (the score higher.

  To return to your original question. To split the LAST interval follow the procedure described in your original post

  1. range partitioning

  2 split the partitioning

  3 set the partitioning interval on

  Conclusion with this however when adding data back to a nine month doesn't automatically create the partition again.

  This "new month" MUST BE above the point of passage for a new partition to create. In your code example, this point of transition is for the year 4000.

  This works very well for me:

  ALTER TABLE sales PARTITION RENAME SYS_P1122 to SALE_400012

  ALTER TABLE sale SET INTERVAL ();

  ALTER TABLE SPLIT PARTITION for sale

  SALE_400012 TO (TO_DATE('01/02/2020','DD/MM/YYYY')) IN

  (

  SALE_202001 PARTITION,

  SALE_400012 PARTITION

  );

  ALTER TABLE sale SET INTERVAL (NUMTOYMINTERVAL(1,'MONTH'))

  INSERT INTO sales

  (SALES_DATE, STORE_NUM, QTY_SOLD)

  values (to_date('31/12/4001','DD/,MM/YYYY'), 1, 10);

  This last INSERT statement above creates a NEW partition because the date (31/12/4001) is above the transition point.

  Looks like you want to move the transition point downwards. That is - you were using this year there date of 4000 as a 'catch all '.

  1. set the partitioning interval

  2 split that last partition into two NEW partitions (new names) by using a VALUE that is high enough to contain ALL the data you have in this last partition.

  3. remove the last partition - it should now be empty

  4. turn on range partitioning

  Now, any data that you insert above this NEW point of transition (the limit that you used for the new partition) it will create a new partition of the interval. Make sure the border is really an end of month, if that's what you want.

  If your data sample had this

  INSERT INTO sales

  (SALES_DATE, STORE_NUM, QTY_SOLD)

  values (to_date('05/10/2016','DD/,MM/YYYY'), 1, 10);

  INSERT INTO sales

  (SALES_DATE, STORE_NUM, QTY_SOLD)

  values (to_date('31/12/4000','DD/,MM/YYYY'), 1, 10);

  So for the step #2 above use split date 06/2016 so that the line above for 10/05/2106 goes to the new partition and 12/31/4000 stays in the old.

  Then, drag this old and lines in it (31/12/4000).

  You can NOT split the last partition if interval is always on because it is the last partition interval.

  And as long as you have given for 12/31/4000, you will get no new partitions unless you insert was more TOP than this.

  So if you want partitioning interval to activate again 06/2016 that higher data would be deleted and the score he falls.

  You have discovered only among "traps" with the help of partitioning of the interval. Oracle will happily create new partition needed to keep the data. If ANYONE, even accidentally, between a date as 12/31/4000 that nobody would ever know until the new data seem to DISAPPEAR for some use cases.

  This is because all data will start to enter this new partition ACCIDENTALLY created instead of a partition for the month, it's part.

  And, and you have discovered, you cannot split this partition directly.

  Delayed segment creation can allow you to pre-create the partitions ahead without actually affecting the segment for them until the first row is inserted.

  Interval partitioning will create the appropriate partitions but not if someone accidentally or intentionally, data will be a valuable capitalized in the table.

• How to create the INTERVAL partitioning using EM?

  Hi guys

  I'm still not able to use the INTERVAL partitioning using EM. Is it possible to do?

  Oracle 11 g 2 on Linux

  Thank you

  John

  Hi John,.

  I don't think it's possible, that the option of partition of the range seems to have things that make you think of it would generate the definition as the partitioning interval but it doesn't.

  I'm on 12.1.0.3 of the SGC and 12.1.0.5 DB plugin so I'm sure it's 'missing' features for the moment.

  See you soon,.

  Rich

• Interval partitioning

  Hello
  
  Please let me know if an interval of partitioning can be created on a table for all the two weeks?
  
  DB version is 11g.
  
  Thank you

  Because the interval partitioning allows you to specify the size range (read the documentation for it)
  and that a fortnight is 14 days by the usual definition

  Then, the 'yes '.

• Interval partitioning: excessive value PARTITION_COUNT

  Hello

  My apologies if this question is in the wrong place - I wasn't sure where to ask.

  I am trying to create a partitioned table of interval:

  CREATE TABLE my_test

  (my_column VARCHAR2 (10))

  created_date TIMESTAMP

  )

  PARTITION OF RANGE (created_date)

  INTERVAL (NUMTOYMINTERVAL (1, 'MONTH'))

  (

  PARTITION part_01 VALUES LESS THAN (TO_DATE('01-DEC-2014','DD-MON-YYYY'))

  );

  The table has only 1 row in it, with a value of created_date a month ago. So I expect to create only a single partition, which includes the rank and a new monthly from December, when data is added.

  When I have a user_part_tables request, is aware that the table has 1 048 575 partitions in the PARTITION_COUNT column.

  What I am doing wrong?

  Oracle version: Enterprise Edition Release 11.2.0.3.0

  Thanks in advance for any help.

  Discovered that the value is actually provided for in the PARTITION_COUNT of user_part_tables: this is the maximum possible scores. The number of existing partitions are in user_tab_partitions.

• I need to change the column of the range on my partition table

  Hello
  
  I created a partition table, but I need to change column of the range "CREATED" to "PREPARED". Two of them date format, but I can't modify this table.
  
  PARTITION OF RANGE (CREATED)--> I need to change column "CREATED" as "PREPARED".
  (
  INV08 PARTITION VALUES LESS (TO_DATE('01-SEP-2010','DD-MON-YYYY')).
  INV09 PARTITION VALUES LESS (TO_DATE('01-OCT-2010','DD-MON-YYYY')).
  INV10 PARTITION VALUES LESS (TO_DATE('01-NOV-2010','DD-MON-YYYY')).
  PARTITION INV VALUES LESS THAN (MAXVALUE)
  )
  
  How can I do?
  
  Published by: user567352 on December 23, 2010 04:10

  Hello

  As far as I know, dbms_redefinition didn't even know about the partitioning:

  1. you create a new empty table that matches your need + (that is where you defined you new partition key) +.
  2. you start the names of submiting of redefinition of existing and newly created table 'interim' table
  3. you leave enough time to get the work done
  4. you have finished redefining (the name of the table are swapped)
  And voila!

  Be sure to test thorougly the process of redefinition and the performance impact that may occur until you make it to your production !
  ;-)

• Interval question partition and subpartition - range

  11.2.0.4

  (separate issue than my other storage)

  You can partition a table by day apart and subpartition and then by a field ID, a sequential ID in single digits?  I want a subpartition for each code.  something lije

  CREATE TABLE detail_tab

  (prod_id NUMBER (6))

  date of create_ts

  )

  PARTITION OF RANGE (create_ts) INTERVAL (NUMTODSINTERVAL(1,'DAY'))

  SUBPARTITION BY RANGE (prod_id) interval (1)

  Ive read the docs http://docs.oracle.com/cd/E18283_01/server.112/e16541/part_admin001.htm#insertedID5 but you see is not the one I want.  IM thinking the closest, I can get to it is a hash range

  
  

  
  

  OK - so FYI stock, you should have a LIMITED identity series: your "id" is probably in the ticker.

  Oracle can manage thousands of partitions.

  For example, to create a partitioned table range-list with each list being one, or several, stock ID. Just hardcode the IDs. Or generate the DDL from a table with a game master of ID.

  Creation of segment use deferred for segments are not created until there are at least a lines for the subpartition.

  Remember, however, you must handle everything by SEGMENT. This means the subpartitions. So all this rollilng off be for hundreds of ID stock.

  You should analyze your processes to determine the "roll-off" exact criteria you need. Group stocks into the partition even if they can get out.

  Also - you can use 'tricks' as the creation of CUSTOM symbols that truly represent AGGREGATE data from stocks of one or more.

  We used to store weekly data by using a value DATE when markets aren't open yet. Activity on these dates were given aggregate rather than granular data.

• Size of partition on interval range partitioned Table happens when SYSDATE is used in a Where Clause

  We have tables interval range partitioned on a DATE, with a partition for each day column - very standard and straight out of doc Oracle.

  A 3rd party application queries the tables to find the number of rows based on the date range that is located on the column used for the partition key.

  This application uses the date range specified from the current date - i.e. for last two days would be «...» StartDate > SYSDATE-2 "- but the partition size is irrelevant and the explain command plan shows that each partition is included."

  In presenting the request uses the date in a variable partition size location and query table is obviously much better.

  DB is 11.2.0.3 on RHEL6, and default settings - i.e. nothing that could influence the behavior of the optimizer to something unusual.

  I can't work on why this would be the case. It is very easy to reproduce with cases of simple test below.

  I would be very interested to hear any views on why it's that way and if anything can be done to allow the size of the partition to work with a query including SYSDATE because it would be difficult to get the application code has changed.

  In addition to make a case to change the code, I need an explanation of why query using SYSDATE is not advisable and I know this information.

  (1) create a simple partitioned table

  CREATETABLE part_test
     (id                      NUMBER NOT NULL,
      starttime               DATE NOT NULL,
      CONSTRAINT pk_part_test PRIMARY KEY (id)) 
  PARTITION BY RANGE (starttime) INTERVAL (NUMTODSINTERVAL(1,'day')) (PARTITION p0 VALUES LESS THAN (TO_DATE('01-01-2013','DD-MM-YYYY')));
  

  (2) fill in the rows of the table 1 million distributed among 10 partitions

  BEGIN
      FOR i IN 1..1000000
      LOOP
          INSERT INTO part_test (id, starttime) VALUES (i, SYSDATE - DBMS_RANDOM.value(low => 1, high => 10));
      END LOOP;
  END;
  /
  EXEC dbms_stats.gather_table_stats('SUPER_CONF','PART_TEST');
  

  (3) to query the Table of data from the last 2 days using SYSDATE in paragraph

  EXPLAIN PLAN FOR 
  SELECT  count(*) 
  FROM    part_test
  WHERE   starttime >= SYSDATE - 2;
  

  -------------------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

  -------------------------------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |           |     1.     3 ×  7895 (1) | 00:00:01 |       |       |

  |   1.  GLOBAL TRI |           |     1.     3 ×            |          |       |       |

  |   2.   RANGE OF PARTITION ITERATOR.           |   111K |   867K |  7895 (1) | 00:00:01 |   KEY | 1048575.

  |*  3 |    TABLE ACCESS FULL | PART_TEST |   111K |   867K |  7895 (1) | 00:00:01 |   KEY | 1048575.

  -------------------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  3 - filter("STARTTIME">=SYSDATE@!-2)

  (4) now do the same query, but with SYSDATE - 2 presented as a literal value.

  This query returns the same response but very different cost.

  EXPLAIN PLAN FOR
  SELECT count(*) 
  FROM part_test
  WHERE starttime >= (to_date('23122013:0950','DDMMYYYY:HH24MI'))-2;
  

  -------------------------------------------------------------------------------------------------------

  | ID | Operation | Name | Lines | Bytes | Cost (% CPU). Time | Pstart. Pstop |

  -------------------------------------------------------------------------------------------------------

  |   0 | SELECT STATEMENT |           |     1.     8.   131 (0) | 00:00:01 |       |       |

  |   1.  GLOBAL TRI |           |     1.     8.            |          |       |       |

  |   2.   RANGE OF PARTITION ITERATOR.           |   111K |   867K |   131 (0) | 00:00:01 |   356 . 1048575.

  |*  3 |    TABLE ACCESS FULL | PART_TEST |   111K |   867K |   131 (0) | 00:00:01 |   356 | 1048575.

  -------------------------------------------------------------------------------------------------------

  Information of predicates (identified by the operation identity card):

  ---------------------------------------------------

  3 filter ("STARTTIME" > = TO_DATE (' 2013-12-21 09:50 ',' syyyy-mm-dd hh24:mi:ss'))))

  Thank you in anticipation

  Jim

  sysdate is not constant and its value may change from time optimization of execution; but the optimizer can deduce that he will be a known running value and then produce a plan that will make the size of partition running.  This is the meaning of 'KEY' in the column pstart – the partition of departure will be known at run time and the size of partition will take place in order to eliminate the previous partitions.

  Concerning

  Jonathan Lewis

• Range of partitioning of the interval

  Hello
  
  
  Using Oracle 11.20.3
  We want to have a table partitioned composite range-hash, a partition for each month.
  
  However, want to esnure are still a tehrfore partition would use range interval partitioning.
  
  Have a few questions, if I say 201301 to 201312 but get intellectualization rosw partition with a value date in June 2014 it create
  a new partition for each month IE 201401, 201402 etc. or just a 201406?
  
  Wanyt esnure system can automatically dial with a scenario
  
  Daty1 have partitions 201301 to 201312
  
  Day 2 get record for 201406 (June 2014)
  
  Day 3 get record for 201403 (March 2014)
  
  
  We have no control over the date range, we were able to get but don't want to tpo have to manually create partitions BOF tehse all dates in advance - want system she managed automatically.
  
  Also you can just rename it the names of system partition generated to something more useful later.

  Yes, the creation of partitions of the interval is 'rare' - a given partition will be created only when necessary. (This should be easy to try, by the way).

• modify an existing table to selectively the partition interval range

  I'm using Oracle 11.2.0.3.
  
  I have an existing table that has parition interval range.
  
  example:

   
  create table Log( ts date, level  varchar2(20), scr varchar2(2000))PARTITION BY RANGE (TS)
  INTERVAL( NUMTODSINTERVAL(1,'DAY'))

  Currently, we have the log of the table that is the partition of the range by day and we drop old parition to a week. However, we want to change this to persist the records in the table of WHICH = LEVEL "IMPORTANT."
  
  What is the best way to achieve this?

  >
  Is it possible to modify the existing interval partition table to add partition in the list?
  >
  Only using the DBMS_REDEFINITION to do online. And that always involves the creation of a "provisional" table

  If you have a window of failure just to create a new partitioned table the way you want to and INSERT the data into it. You should be able to use a DEC to do if you want. You may not use swap partition since all data must be physically moved.
  >
  Can we do list-interval partition table i.e. (with partition interval as partition sup)?
  >
  No - subpartitioning of interval is not currently supported.

  Here is the code example of a partitioned table by using the RANGE-interval LIST. It uses a VIRTUAL column, but you can ignore it for your use case

  DROP TABLE mytable;
  
  CREATE TABLE mytable
  (
  CREATION_DATE TIMESTAMP(6),
  LAST_MODIFIED_DATE TIMESTAMP(6),
  CREATION_DAY NUMBER(2) GENERATED ALWAYS AS (TO_NUMBER(TO_CHAR(CREATION_DATE, 'DD'))) VIRTUAL
  )
  PARTITION BY RANGE (LAST_MODIFIED_DATE) INTERVAL(NUMTOYMINTERVAL(1, 'MONTH'))
  SUBPARTITION BY LIST (CREATION_DAY)
     SUBPARTITION TEMPLATE
     ( SUBPARTITION days_1_5 VALUES (1,2,3,4,5)
     , SUBPARTITION days_6_10 VALUES (6,7,8,9,10)
     , SUBPARTITION days_11_15 VALUES (11,12,13,14,15)
     , SUBPARTITION days_16_20 VALUES (16,17,18,19,20)
     , SUBPARTITION days_21_25 VALUES (21,22,23,24,25)
     , SUBPARTITION days_26_31 VALUES (26,27,28,29,30,31)
     )
  (
     PARTITION prior_to_2013 VALUES LESS THAN (TO_DATE('2013-01-01', 'YYYY-MM-DD'))
  )
  

• Try to convert the partitioned Table of interval in the range... Swap partition...

  Requirement:
  
  Interval of replacement partitioned Table by range partitioned Table
  

  DROP TABLE A;
  
  CREATE TABLE A
  (
     a              NUMBER,
     CreationDate   DATE
  )
  PARTITION BY RANGE (CreationDate)
     INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
     (PARTITION P_FIRST
         VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));
  
  
  INSERT INTO A
       VALUES (1, SYSDATE);
  
  INSERT INTO A
       VALUES (1, SYSDATE - 30);
  
  INSERT INTO A
       VALUES (1, SYSDATE - 60);

  I need to change this partitioned Table apart to a partitioned range Table. I can do using the EXCHANGE PARTITION. Like if I use the classic method to create another table range partitioned, then:
  
  

  DROP TABLE A_Range
  CREATE TABLE A_Range
  (
  a NUMBER,
  CreationDate DATE
  )
  PARTITION BY RANGE (CreationDate)
     (partition MAX values less than (MAXVALUE));
  
  Insert  /*+ append */  into A_Range Select * from A; --This Step takes very very long..Trying to cut it short using Exchange Partition.

  Problems:
  
  I can't do
  

   ALTER TABLE A_Range
    EXCHANGE PARTITION MAX
    WITH TABLE A
    WITHOUT VALIDATION;
   

  ORA-14095: ALTER TABLE CHANGE requires a not partitioned table nonclustered
  This is because the tables are partitioned. So it does not allow me.
  
  If I instead:
  
  
  Create a table that is not partitioned for exchanging data by partition.
  

    Create Table A_Temp as Select * from A;
    
     ALTER TABLE A_Range
    EXCHANGE PARTITION MAX
    WITH TABLE A_TEMP
    WITHOUT VALIDATION;
     
    select count(*) from A_Range partition(MAX);
   

  -The problem is that all the data is in MAX Partition.
  Even after the creation of a large number of partitions by walls of separation, the data is still in MAX Partition only.
  
  So:
  
  -What we cannot replace a partitioned Table to the Table partitioned using the EXCHANGE PARTITION range interval. that is, we have to insert in...
  -We can do it, but I'm missing something here.
  -If all the data is in MAX Partition due to "WITHOUT VALIDATION", can say us be redistributed in the right type of range partitions.

  You must pre-create the partitions in a_range and then swap one for one for a tmp, and then to arange. With the help of your sample (thanks to proviing code, incidentally).

  SQL> CREATE TABLE A
    2  (
    3     a              NUMBER,
    4     CreationDate   DATE
    5  )
    6  PARTITION BY RANGE (CreationDate)
    7     INTERVAL ( NUMTODSINTERVAL (30, 'DAY') )
    8     (PARTITION P_FIRST
    9         VALUES LESS THAN (TIMESTAMP ' 2001-01-01 00:00:00'));
  
  Table created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE);
  
  1 row created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE - 30);
  
  1 row created.
  
  SQL> INSERT INTO A VALUES (1, SYSDATE - 60);
  
  1 row created.
  
  SQL> commit;
  
  Commit complete.
  

  You can find the form of existing partitions assistance:

  SQL> select table_name, partition_name, high_value
    2  from user_tab_partitions
    3  where table_name = 'A';
  
  TABLE_NAME PARTITION_NAME HIGH_VALUE
  ---------- -------------- --------------------------------------------------------------------------------
  A          P_FIRST        TO_DATE(' 2001-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P44        TO_DATE(' 2013-01-28 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P45        TO_DATE(' 2012-12-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  A          SYS_P46        TO_DATE(' 2012-11-29 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA
  

  You can then create the table a_range with apporopriate partitions. Note that you may need to create additional in a_range partitions because the partitioning interval does not create the partitions has no data for, even if that leaves 'holes' in the partitioning scheme. So, on that basis:

  SQL> CREATE TABLE A_Range (
    2     a NUMBER,
    3     CreationDate DATE)
    4  PARTITION BY RANGE (CreationDate)
    5     (partition Nov_2012 values less than (to_date('30-nov-2012', 'dd-mon-yyyy')),
    6      partition Dec_2012 values less than (to_date('31-dec-2012', 'dd-mon-yyyy')),
    7      partition Jan_2013 values less than (to_date('31-jan-2013', 'dd-mon-yyyy')),
    8      partition MAX values less than (MAXVALUE));
  
  Table created.
  

  Now, create a regular table to use in the constituencies:

  SQL> CREATE TABLE A_tmp (
    2     a              NUMBER,
    3     CreationDate   DATE);
  
  Table created.
  

  and all partitions in Exchange:

  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p44
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION jan_2013
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p45
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION dec_2012
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A
    2    EXCHANGE PARTITION sys_p46
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> ALTER TABLE A_Range
    2    EXCHANGE PARTITION nov_2012
    3    WITH TABLE A_tmp;
  
  Table altered.
  
  SQL> select * from a;
  
  no rows selected
  
  SQL> select * from a_range;
  
           A CREATIOND
  ---------- ---------
           1 23-NOV-12
           1 23-DEC-12
           1 22-JAN-13
  

  John

• Partition wise joined possible with partitions of the interval?

  Hello

  I want to know the score wise join (NTC) is possible with interval partitioning - I can't find an explicit statement that he isn't, but I can't make it work - I did a simple test case to illustrate the issue.

  below, I have 2 create table scripts - 1 for the case of interval and 1 for the case of hash - I then a simple query on these 2 objects which should produce a NTC.

  In the case of hash, it works very well (see screenshot 2nd with a set of slaves), the first screenshot shows the case of the interval where I find myself with 2 sets of slaves and no NTC.

  No idea if this is possible and I just missed something?

  (for the test case choose the names of schema/storage appropriate for your system)

  Oh and version (I almost forgot... :-))-East 11.2.0.4.1 SLES 11)

  See you soon,.

  Rich

  -case interval

  CREATE TABLE 'SB_DWH_IN '. "' TEST1 '.

  TABLESPACE "SB_DWH_INTEGRATION".

  PARTITION BY RANGE ("OBJECT_ID") INTERVAL (10000)

  (PARTITION 'LESS_THAN_ZERO' VALUES LESS THAN (0) TABLESPACE "SB_DWH_INTEGRATION")

  in select * from DBA_OBJECTS where object_id is not null;

  CREATE TABLE 'SB_DWH_IN '. "" TEST2 ".

  TABLESPACE "SB_DWH_INTEGRATION".

  PARTITION BY RANGE ("OBJECT_ID") INTERVAL (10000)

  (PARTITION 'LESS_THAN_ZERO' VALUES LESS THAN (0) TABLESPACE "SB_DWH_INTEGRATION")

  in select * from DBA_OBJECTS where object_id is not null;

  -case of hash

  CREATE TABLE 'SB_DWH_IN '. "' TEST1 '.

  TABLESPACE "SB_DWH_INTEGRATION".

  8 partitions PARTITION OF HASH ("OBJECT_ID")

  store in ("SB_DWH_INTEGRATION")

  in select * from DBA_OBJECTS where object_id is not null;

  CREATE TABLE 'SB_DWH_IN '. "" TEST2 ".

  TABLESPACE "SB_DWH_INTEGRATION".

  8 partitions PARTITION OF HASH ("OBJECT_ID")

  store in ("SB_DWH_INTEGRATION")

  in select * from DBA_OBJECTS where object_id is not null;

  -query to run

  Select / * + PARALLEL(TEST2,8) PARALLEL(TEST1,8) * / *.

  of 'SB_DWH_IN '. "" TEST2 ","SB_DWH_IN ". "' TEST1 '.

  where TEST1.object_id = test2.object_id

  

  

  It is planned and a consequence of the estimate of the number of parallel slaves.

  To the parallel 41 each slave made 3 passes (i.e. sleeves 3 partitions).

  Add a partition (by table), and a set of slaves will have to manage a 4th pass: the cost of the query using NTC would increase from 33 percent even if the modification of the data is less than 0.8%.

  I guess that in the production Oracle distributes your lines of 1 M for a hash join.

  Because the decision is encrypted, it is possible that a very extreme tilt in partition in the table sizes billion line might overthrow the optimizer in a non - NTC join - but I have not tested that.

  If you want to force the plan John Watson suggestion for a hint of pq_distribute is relevant.  To cover all the bases and call your tables SMALL and LARGE

  /*+

  leading (FAT kid)

  USE_HASH (large)

  no_swap_join_inputs (large)

  PQ_DISTRIBUTE (wide none none)

  */

  If it's legal, that should do it.

  Concerning

  Jonathan Lewis

• Select to partition interval

  Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production

  I have a partitioned table of interval on a range of numbers and to select the data of a partition for a specific value is

  CREATE TABLE part_test(part_key       NUMBER
                        ,part_data      VARCHAR2(10)
                        )
  PARTITION BY RANGE (part_key)
    INTERVAL ( 1 )
    (PARTITION p_base VALUES LESS THAN (0));
  
  INSERT INTO part_test(part_key, part_data)
  VALUES      (-1, '-1');
  INSERT INTO part_test(part_key, part_data)
  VALUES      (0, '0');
  INSERT INTO part_test(part_key, part_data)
  VALUES      (1, '1');
  INSERT INTO part_test(part_key, part_data)
  VALUES      (2, '2');
  COMMIT;
  
  SELECT *
  FROM   part_test PARTITION FOR(1);
  

  What I really want to select the partition is based on a value in another table to be

  CREATE TABLE part_value (part_key NUMBER);
  
  INSERT INTO part_value(part_key)
  VALUES      (1);
  COMMIT;
  
  SELECT *
  FROM   part_test PARTITION FOR(select part_key from part_value);
  

  It gives ORA-00936: lack of expression.  I could use dynamic sql statements to create the query (or generate a view), but it would save instead.  Any ideas if this can be achieved by a simple sql statement?

  Thank you.

  You try something like:

  SELECT *.

  OF part_test pt, part_value pv

  where pt.part_key = pv.part_key

  In most cases a particular partition will be only accessible, no full table scans (not true in all scenarios, however)

• Creating a partitioned table to an existing table interval.

  Hello

  Is there a way I can create a partitioned table interval of an existing table using DEC? I know how to create a partitioned table in range.

  create the table range_partitioned_table

  partition by range (date_column)

  (

  partition p1 lower ((to_date (' 08/01/2012 ',' mm/dd/yyyy'))),

  lower partition p2 values (to_date (' 09/01/2012 ',' mm/dd/yyyy')),

  PN VALUES LESS THAN (MAXVALUE) PARTITION

  )

  AS SELECT * from existing_table;

  Is there a similar way to the Interval partition an existing table?

  create the table interval_partitioned_table

  partition by range (date_column)

  interval (provide the interval)

  (

  partition p1 lower ((to_date (' 08/01/2012 ',' mm/dd/yyyy'))),

  partition p2 values less (to_date (' 09/01/2012 ',' mm/dd/yyyy')),

  -PN SCORE VALUES LESS THAN (MAXVALUE)

  )

  AS SELECT * from existing_table;

  For example:

  SQL > create table interval_partitioned_table
  2 partition by range (hiredate)
  interval of 3 (numtoyminterval(1,'YEAR'))
  (4)
  5 score below p1 ((to_date (' 08/01/2012 ',' mm/dd/yyyy'))),
  6 partition p2 values less (to_date (' 09/01/2012 ',' mm/dd/yyyy')),
  7 - PARTITION pN VALUES LESS THAN (MAXVALUE)
  8)
  9 AS SELECT * FROM emp;

  Table created.

  SQL >

  SY.