Is it possible to image export batch have the same area?

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  ), ()

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  SELECT DEPT_ID,

  RTRIM (XMLAGG (XMLELEMENT(A,VALS||',')). Extract ('//Text ()'), ',') COLUMNS_WITH_DUPLICATE

  DE)

  SELECT * FROM)

  SELECT DEPT_ID,

  EMP_ID,

  Date of birth

  CITY,

  STATE,

  COUNTRY

  DE)

  SELECT DEPT_ID,

  EMP_ID,

  Date of birth

  CITY,

  STATE,

  COUNTRIES,

  COUNT (*) OVER(PARTITION BY DEPT_ID ORDER BY EMP_ID DESC,DOB DESC,CITY DESC,STATE DESC, COUNTRY DESC) RN

  DE)

  SELECT DEPT_ID,

  CASE WHEN(CEID>1) AND THEN 'YES' ELSE 'NO' END AS EMP_ID.

  CASE WHEN(CDOB>1) THEN 'YES' ELSE 'NO' END AS DATE OF BIRTH,

  CASE WHEN(CCITY>1) AND THEN 'YES' ELSE 'NO' END AS CITY.

  CASE WHEN(CSTATE>1) AND THEN 'YES' ELSE 'NO' END AS STATE.

  CASE WHEN(CCOUNTRY>1) THEN 'YES' ELSE 'NO' END AS A COUNTRY

  DE)

  SELECT DISTINCT

  DEPT_ID,

  CEID,

  CDOB,

  CITY,

  CSTATE,

  CCOUNTRY

  DE)

  SELECT DEPT_ID,

  COUNT (*) TO THE CEID (DEPT_ID PARTITION, EMP_ID),.

  COUNT (*) ON CDOB (DEPT_ID SCORE, DATE OF BIRTH),

  COUNT (*) ON THE CITY (DEPT_ID PARTITION, CITY),

  COUNT (*) ON CSTATE (DEPT_ID PARTITION, STATE).

  COUNT (*) ON CCOUNTRY (DEPT_ID, COUNTRY PARTITION)

  FROM T1)))

  WHERE RN = 1)

  UNPIVOT (CLO FOR (VALS) IN (EMP_ID, DATE OF BIRTH, CITY, STATE, COUNTRY)))

  WHERE COLS = "YES".

  DEPT_ID GROUP;

  OUTPUT:

  DEPT_ID COLUMNS_WITH_DUPLICATE
  --------- ------------------------

  1 CITY, COUNTRY, STATE
  2 CITY, COUNTRY, STATE
  3 CITY, COUNTRY, STATE

  Post edited by: Parth272025

• Problems to import still Images; Convert all in the SAME Image

  Hello

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  Hello
  
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  CREATE TABLE manager (
   id      number primary key,
   name      varchar2(100));
  
  -- child table 
  CREATE TABLE employee (
   id          number primary key,
   name      varchar2(100));
  
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   manager_id          NUMBER, 
   employee_id      NUMBER,
   CONSTRAINT join_table_pk PRIMARY KEY (manager_id, employee_id),
   CONSTRAINT manager_fk FOREIGN KEY (manager_id) REFERENCES manager(id),
   CONSTRAINT employee_fk FOREIGN KEY (employee_id) REFERENCES employee(id) 
   );
  
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  INSERT INTO manager (id, name) VALUES (1, 'John');
  INSERT INTO manager (id, name) VALUES (2, 'Bob');
  INSERT INTO manager (id, name) VALUES (3, 'Mary');
  INSERT INTO manager (id, name) VALUES (4, 'Sue');
  INSERT INTO manager (id, name) VALUES (5, 'Alan');
  INSERT INTO manager (id, name) VALUES (6, 'Mike');
  
  -- Insert some employees 
  INSERT INTO employee (id, name) VALUES (101, 'Paul');
  INSERT INTO employee (id, name) VALUES (102, 'Simon');
  INSERT INTO employee (id, name) VALUES (103, 'Ken');
  INSERT INTO employee (id, name) VALUES (104, 'Kevin');
  INSERT INTO employee (id, name) VALUES (105, 'Jack');
  INSERT INTO employee (id, name) VALUES (106, 'Jennifer');
  INSERT INTO employee (id, name) VALUES (107, 'Tim');
  
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  INSERT INTO join_table (manager_id, employee_id) VALUES (1, 101);
  INSERT INTO join_table (manager_id, employee_id) VALUES (1, 102);
  INSERT INTO join_table (manager_id, employee_id) VALUES (1, 103);
  -- Bob manages Paul, Simon, Kevin, Jack
  INSERT INTO join_table (manager_id, employee_id) VALUES (2, 101);
  INSERT INTO join_table (manager_id, employee_id) VALUES (2, 102);
  INSERT INTO join_table (manager_id, employee_id) VALUES (2, 104);
  INSERT INTO join_table (manager_id, employee_id) VALUES (2, 105);
  -- Mary manages Jennifer, Tim
  INSERT INTO join_table (manager_id, employee_id) VALUES (3, 106);
  INSERT INTO join_table (manager_id, employee_id) VALUES (3, 107);
  -- Sue manages Jennifer, Tim
  INSERT INTO join_table (manager_id, employee_id) VALUES (4, 106);
  INSERT INTO join_table (manager_id, employee_id) VALUES (4, 107);
  -- Alan manages Paul, Simon, Ken, Jennifer, Tim
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 101);
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 102);
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 103);
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 106);
  INSERT INTO join_table (manager_id, employee_id) VALUES (5, 107);
  -- Mike manages Paul, Simon, Ken
  INSERT INTO join_table (manager_id, employee_id) VALUES (6, 101);
  INSERT INTO join_table (manager_id, employee_id) VALUES (6, 102);
  INSERT INTO join_table (manager_id, employee_id) VALUES (6, 103);
  
  -- For sanity
  CREATE UNIQUE INDEX employee_name_uidx ON employee(name);

  If I ask for Manager John, so I want to find other managers who manage the exact list and even employees.
  Answer should be Mike.
  If I ask for Manager of Mary, the answer should be Sue.
  
  This query will give me the list of managers who manage some of the same employees as John, but not the same employees accurate...

  SELECT DISTINCT m.name AS manager
  FROM manager m, join_table jt, employee e
  WHERE m.id = jt.manager_id
  AND jt.employee_id = e.id
  AND e.id IN (
       SELECT e.id
       FROM manager m, join_table jt, employee e
       WHERE m.id = jt.manager_id
       AND jt.employee_id = e.id
       AND m.name = 'John')
  ORDER BY 1;

  I thought about using set operations to find managers with a list of employees less than my employees is null and where my employees under their list of employees is null. But there must be an easier way more elegant.
  Any ideas?
  BTW, I need to run as a batch on tables with > 20 million rows so the efficiency of queries is key.

  What about...

  WITH manager_list AS
  (
   SELECT name,
          LTRIM(MAX(SYS_CONNECT_BY_PATH(id,','))
          KEEP (DENSE_RANK LAST ORDER BY curr),',') AS employees
   FROM   (SELECT m.name,
                  e.id,
                  ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) AS curr,
                  ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) -1 AS prev
           FROM   manager m,
                  join_table jt,
                  employee e
    WHERE m.id           = jt.manager_id
    AND   jt.employee_id = e.id
    AND   m.name = :P_MANAGER)
    GROUP BY name
    CONNECT BY prev = PRIOR curr AND name = PRIOR name
    START WITH curr = 1
  ), all_list AS
  (
   SELECT name,
          LTRIM(MAX(SYS_CONNECT_BY_PATH(id,','))
          KEEP (DENSE_RANK LAST ORDER BY curr),',') AS employees
   FROM   (SELECT m.name,
                  e.id,
                  ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) AS curr,
                  ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) -1 AS prev
           FROM   manager m,
                  join_table jt,
                  employee e
    WHERE m.id           = jt.manager_id
    AND   jt.employee_id = e.id)
    GROUP BY name
    CONNECT BY prev = PRIOR curr AND name = PRIOR name
    START WITH curr = 1
  )
  SELECT a.*
  FROM   manager_list m,
         all_list a
  WHERE  m.employees = a.employees
  

  Would be easier in 11g, but I do not have a facility here so this is based on 10g.

  See you soon

  Ben

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