Iterate through each page of pagination. Apex 4.2.6

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  When I click on a file I want in the Pages, the program passes through each file that I created before he gets to the one I want.  Is it possible to go directly to the file you want?

  Open the Pages with the SHIFT key is pressed, so it is not reopen previously open documents or close all your open documents before leaving the Pages.

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• How user name passed to each page of the application of the APEX

  Hello world
  
  I want to understand, how the user name is passed to every page of the application of the apex. On each page we see the user name, the logout button. Reason I asked, I want to understand the concept and I would pass the role assciated with username. So what is the best way to switch roles as associated with the username.
  
  Thank you

  Karam,

  If you want to be included in the simplest model is to create an element of the application in the shared components, for example:

  MY_VARIABLE

  in the model, you can use & MY_VARIABLE. just like & APP_USER.

  You can set the session in pl/sql variable, for example by:

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• detect pageitems groups and iterate through the items in each group

  Hello

  I can use some help with a script that I'm trying. The script creates a new layer based on a fill color of objects and then move the item to the new layer.

  What I can't understand is how to check if a pageItem is a group, and if so, scroll through all the objects within the group. What I have so far (snippit) is:

  var doc = app.activeDocument;
  var LayerName = "0";
  var MyArray = new Array;
  
  for ( j=0; j < Counter; j++ ) 
      {
      CurrentItem = doc.pageItems[j];
      if (CurrentItem.typename != "GroupItem" && CurrentItem.typename != "CompoundPathItem" && CurrentItem.parent.typename != "GroupItem" && CurrentItem.parent.typename != "CompoundPathItem") 
         {  
          LayerName = ConstructLayerNameBasedOnFillColor( CurrentItem );
          CurrentItem.move( app.activeDocument.layers.getByName( LayerName ), ElementPlacement.PLACEATBEGINNING );
         }
        else 
         {  
          if (CurrentItem.typename == "GroupItem") //  seems to be wrong as it also returns true for an item within the group
          { 
           myArray = [];
              for ................ // cycle through each item within the group
               {
                LayerName = ConstructLayerNameBasedOnFillColor( CurrentGroupItem );
                MyArray.push(LayerName);
               }
           LayerName = GetMostCommonColor(MyArray);
           ................. // move the group (including all items within the group) to layer LayerName
            }
         } 
      }
  

  Is the part that I need help:

  1:  if (CurrentItem.typename == "GroupItem") //  seems to be wrong as it also returns true for an item within the group
  2:     { 
  3:     myArray = [];
  4:      for ................ // cycle through each item within the group
  5:         {
  6:          LayerName = ConstructLayerNameBasedOnFillColor( CurrentGroupItem );
  7:          MyArray.push(LayerName);
  8:         }
  9:     LayerName = GetMostCommonColor(MyArray);
  10:     ................. // move the group (including all items within the group) to layer LayerName
  11:    }
  

  line 1: how to check if the pageItem is a group

  line 4: scroll all the items in the Group

  line 10: move the group to a new layer

  Any help is appreciated.

  Have you tried running the loop backwards in the case where the index is messed up.

   m=0; m < CurrentItem.pageItems.length-1; m-- 
  

• Browse through the pages

  Hello

  I'm creating a native application that has a list of items. When an item is selected, navigates to a particular page. I could not navigate to another page. Please help me with the code to navigate through the pages. Here is my code.

  import bb.cascades 1.0
  NavigationPane {}
  ID: head

  {Page}
  content: {container
  ImageView {}

  }
  {To ListView
  dataModel: {XmlDataModel}
  Source: "items.xml".
  }
  listItemComponents:]
  {ListItemComponent}
  type: "header.
  {To header

  Title: ListItemData.title
  subtitles: ListItemData.subtitle
  verticalAlignment: VerticalAlignment.Center
  horizontalAlignment: P

  }
  },
  {ListItemComponent}
  type: "listItem".
  {StandardListItem}
  Title: ListItemData.title
  Description: ListItemData.subtitle
  status: ListItemData.status
  imageSource: ListItemData.imagepath

  }
  }
  ]
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  navigateTo (one)

  }
  }

  }
  }
  attachedObjects:]
  {Page}
  IDdon't
  {Of container
  {Label
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  }
  ImageView {}
  imageSource: "asset:///1.jpg."
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  }
  }
  }
  ]
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• Prevent the user from changing the page in URL - Apex 5

  Dear community of Apex,

  We seek to protect our handling of URL pages.  The protection of session state is enabled, and each page has page value «Arguments must have Checksum» access protection  However, the documentation seems to discuss in order to prevent the user from element values in the URL.  We want to prevent the user to change the page ID in the URL.  Currently, a user is able to hack the URL and take in the middle of a wizard process for example.  Is it possible to stop this?  Other that an element of creative previous train stop check.

  * Version: Application Express 5.0.1.00.06

  Thank you

  Barry

  bSamuel wrote:

  We seek to protect our handling of URL pages.  The protection of session state is enabled, and each page has page value «Arguments must have Checksum» access protection  However, the documentation seems to discuss in order to prevent the user from element values in the URL.  We want to prevent the user to change the page ID in the URL.  Currently, a user is able to hack the URL and take in the middle of a wizard process for example.  Is it possible to stop this?  Other that an element of creative previous train stop check.

  Hi Barry

  Affecting the security attribute Access Page Protection page No. URL Access and navigate between pages using the type of the Page Management Branch (uncheck the option creates a branch using redirection page in the Wizard) will avoid this:

  No URL access -Page can not be found using a URL, but the page can be the target of a type of Page Management Branch, is not doing a URL redirect.

  It is a little more restrictive that a normal direction of the session state values cannot be positioned or erased declaratively in the branch, but is not often necessary in a several step wizard, and it's pretty simple to work round using prior processes - or post-branche or by referencing the item values directly from other pages.

• How to display the watermark to each page number?

  Hello.

  app.documents.item(0).watermarkPreferences.watermarkText = "page";
  app.documents.item(0).watermarkPreferences.watermarkVisibility = true;
  
  

  These are all same watermark settings.

  It is impossible to set a nonzero value of the element.

  I want to display the watermark to each page number.

  If there is no way, I want to create this similar feature.

  Any ideas?

  And please tell me if the function already exists.

  Thank you.

  I think I know what you want.

  You need a different watermark to each page of a document.

  Which seems not be possible since watermarkPreference is not a preference of page but a preference document.

  If you need this for the PDF export for example, you can export single pages in single PDF files and change the watermarkText according to the name of the page you are currently exporting.

  After the export of all pages you could assemble in Acrobat Pro. Or place them in InDesign page-by-page and export again to a multipage PDF document.

  // ExportPages-ChangeWatermarkForEveryPage.jsx
  // Uwe Laubender
  
  /**
  * @@@BUILDINFO@@@ ExportPages-ChangeWatermarkForEveryPage.jsx !Version! Mon Dec 14 2015 20:28:23 GMT+0100
  */
  
  var doc = app.documents[0];
  var pages = doc.pages.everyItem().getElements();
  
  // You can also assign a preset by its name
  // For simplicity here the second preset listed in assigned:
  var pdfExportPreset = app.pdfExportPresets[1];
  
  // Loop through all the pages:
  
  for(var n=0;n
  Hope, that helps.
  Uwe
  		   

• Browse through the pages and add the text box

  I'm trying to navigate through the pages of a document (to simplify, let's say there are 5 pages) and perform certain tasks (for simplicity, say add a text box) on each page.

  Using VBScript, my thoughts are something like:

  Define myPages = myDocument.Pages

  I have = 1

  do until I have 5 >

  myPages.Item (i). Select()

  Set myTextFrame = myDocument.ActivePage.TextFrames.Add

  myTextFrame.Contents = "Hello, World".

  i = i + 1

  loop

  
  

  should work.

  
  

  But the best I can do (when I'm not getting syntax error messages) is to get the written text several times on one page.

  
  

  I know that there is a simple solution that I'm missing.

  
  

  Any suggestions?

  
  

  Thank you.

  You should probably add () after adding

  P.

• I have a downloaded .pdf file. When I click on a page (this happens for each page) he follows me to a link open my browser. How should you remove that? I tried to delete all the hyperlinkes but remained! Thank you.

  I have a downloaded .pdf file. When I click on a page (this happens for each page) he follows me to a link open my browser. How shoul delete who? I tried to delete all the hyperlinkes but remained! Thank you.

  After seeing a few screenshots of the file I think I see what's happening now. There is a watermark diagonal URL through the page that is converted to a link automatically by the application. Disable it go to Edition - Preferences - general and uncheck the box that says "create links from URLS".

• How to force the vertical scroll bar to display on each page?

  Hello

  Is it possible to force the vertical scroll bar appears on each page, even if it is not needed?

  I have a site with pages larger than the browser window, and others which are smaller. The scroll bar appears only on adults and forcing elements from left to right on the left to navigate through the pages.

  Any help would be appreciated.

  Thanks in advance

  VM

  In the section header of Page Properties try adding the following code:

• Pages multiple Global apex 4.2

  Hello
  I read that Apex 4.2 would allow several comprehensive pages. I can think of a use case where you have multiple global pages, each with menus / common features for one aspect of an application.
  Now, I find that once I have create a global page, I can't create a new one. I would like clarification on this feature. What is a global page by application or a global page by the user interface (i.e. Desktop/Mobile)?
  How does the device?
  Kofi

  Kofi Hi,

  As stated in the User Guide of APEX, specifically in the section creating a global Page to display items on each Page in Chapter 12, /e35125/ui_allpgs.htm#CJHIJBDG of http://docs.oracle.com/cd/E37097_01/doc/ ofdoc.42, you can create a separate global page for each UI associated with your application. For example, if your application contains a desk and a Mobile User Interface, you can create a global page for desktop computer and another for Mobile. For an example, take a look at the sample database Application that was installed by default with 4.2 in your workspace. The page overall desktop is 0, and the Global Mobile page is 199.

  I hope this helps.

  Kind regards
  Hilary

• Limitation of the APEX: sharing pages between several APEX applications

  I was hoping if someone with a little more experience architect APEX could comment on some of the limitations that I see and I have to make good decisions, working around the problem.
  
  Any suggestions are welcome.
  
  One of the limitations I've seen, it's how APEX handles applications and pages. Each application appears as an island, it has its own set of pages, the processes of connection, templates, CSS, JS, references etc.. Regarding the CSS and Javascript, you can be defined in a central location, but still, every new developed APEX application must be configured to make use of your 'standard '.
  
  The more traditional web solutions showing each as stand-alone web page and any web page can call/reference any other page and pass information to session between them.
  
  With APEX, however this doesn't seem to be the case.
  
  A solution would be to have a huge demand for APEX, where all the pages are the property of this unique application.
  
  Unfortunately, we use of APEX and EBS R11 (& R12) together; all APEX applications are started in the menus of the EBS. I had drawn a SSO solution between the two (without using oracle SSO). However, each APEX application is unique, as small modules instead of complete applications. In other words, we tend to use APEX as an alternative for Oracle Forms - each APEX application is a standalone program.
  
  I always wanted to be able to apply the same connection process and look and feel in the brand new APEX app we write.
  
  The way I went to this subject has been meticulously creating a 'model' APEX application. Embedded in the application of this model are all our shared CSS, JS and models that apply the site appearance. It also contains our custom library of signature unique code and debugging custom logger (think log4j but for APEX).
  
  So whenever a developer began work on a new APEX application, they start by cloning the model and automatically inherit all the functionally and website presentation.
  
  My concern is if this is really the best way to do it, or if I'm missing something?
  
  I am also concerned move forward when I wants to establish the change in appearance across all of our web applications that I need to touch each APEX application since. I'm trying to mitigate this by ensuring that almost all the programming logic is contained in packages of PL/SQL, CSS and Javascript only referenced and external application of the APEX. But this does not always with models, or with a logic that is rooted in the actual pages of the APEX etc.
  
  At least APEX allows you to easily enough copy pages between applications, but it does compare not just to have a single page shared between all applications of the APEX.
  
  Is there a better way to go about this?

  Hi attis.

  I think you can't really compare a module with an APEX application forms. I wouldn't say to create an APEX application every time when you have created a module of forms in the past.
  A forms module is just a few pages of an application to the APEX. Then you really should have more then a few pages in an APEX application. Certainly, a huge application is also not the way to go, but I group them for example by logical areas such as HR, logistics, order...

  As Sc0tt already mentioned, you must use the 'Subscribe' mechanism of shared components to make it easier to update all your applications with the model updates. But there is more, you should also share your user name and just have in one place and use the "simple APEX based SSO" that allows all applications within a workspace can share the same session. Simply set the 'Cookie' namesake in your authentication for all your applications and when you bind an application to another and include a valid session id you should not have to log in again and you can also set the session state in that other application.

  So here's what I'd do

  (1) creating a master application that contains
  (a) your theme and other components shared that you want to share
  (b) must be also some basic navigation lists to navigate between your applications...
  (c) create a sign with the name "Redirect to connect main app" and type accounts APEX (no matter) where you define the name of 'Cookie' to 'Cbx_missmost' and the URL of invalid session to the login page of your creation 'hand connection app '. For example: f? p = 9999:101: & SESSION.

  (2) create a model application which is a copy of the claim, but where change you the "subscription" of your models, authentication scheme and components shared in the main application. This will serve as your App developers if they want to create a new application.

  (3) create your 'hand connection app' (eg. app 9999 id) by
  ) a copy of your new model application
  (b) remove the inside authentication scheme (this is just made for this main connection app)
  (c) create a new type to use. But important: set the name of 'Cookie' to 'Cbx_missmost '. This will ensure that all applications have the same session cookie.
  (d) If you use APEX 4.1.1 you will automatically be redirected to the calling application after successful login.

  (4) start to create new applications by copying your 'model' application that contains all subscriptions.

  (5) If you run this application, it automatically redirects to your main connection application if the current session is not valid. This will avoid to have the same logic of authentication in your applications.

  (6) If you need to change your templates or shared components you just do in the "master" application and click on the "publish" button to push the changes for all your applications.

  But still, try to avoid many small applications, I think that make handling just unnecessarily complicated. It is an APEX application has a few hundred pages. For example, our APEX app Builder (app 4000) has more than 1260 pages.

  Concerning
  Patrick
  -----------
  My Blog: http://www.inside-oracle-apex.com
  APEX Plug-Ins: http://apex.oracle.com/plugins
  Twitter: http://www.twitter.com/patrickwolf

• Is it possible to copy a part of a page from the APEX with a public procedure of APEX stored?

  The element is a grid view control and it ist does not part of each page.
  I copy the element of grid view several times. After that, I have to change a lot of settings in the copied grid views. Normally, I do this the APEX constructor GUID clicking over and clicking on...
  
  
  I would copy the perspective grid in a more comfortable way (means without clicking) in a stored procedure by calling procedures PL/SQL to the APEX (such as the GUID of the APEX Builder).
  
  
  There are all the public stored procedures to do?

  It would be preferable to this post in the forum of the APEX on OTN
  Steve

• Count the total number of specific words on each page

  I have a script that counts the number of times where the word 'Manager' is displayed on each page of a report.

  This is what is returned in the console after running the script:

  Count the number of managers 1 Page number 1

  Count the number of managers 2 Page number 1

  Count the number of managers 3 Page number 1

  Count the number of managers 4 Page number 1

  Count the number of managers 5 Page number 1

  Count the number of managers 1 Page number 2

  Count the number of managers 2 Page number 2

  Count the number of managers 3 Page number 2

  I need the console to report with only the total number of times that the word Manager appears on each page (once) and not iterate over each of them.

  Can someone please advise how this can be achieved?

  Script as follows:

  var this.numPages = NUMPAGES;

  for (var k = 0; k < numpages; k ++)
  {
  {
  numWords var = this.getPageNumWords (k);

  var number = 0;

  for (var i = 0; i < numWords; i ++)
  {
  var ckWord = this.getPageNthWord (k, i, true);
  var q = this.getPageNthWordQuads (k, i);
  Convert quads in the rotation by default user space
  Userspace used by links.
  m = (new Matrix2D).fromRotated(this,0);
  mInv = m.invert)
  r = mInv.transform (q)
  r = r.ToString)
  r = r.split(",");
  If (ckWord = "Manager")
  {
  Count ++;
  Console.println ("Count none managers" + count + "Number of Page" + (k + 1));
  }
  }
  }
  }

  Just move the statement outside the inner loop:

  var this.numPages = NUMPAGES;

  for (var k = 0; k)< numpages;="" k++)="">

  numWords var = this.getPageNumWords (k);

  var number = 0;

  for (var i = 0; i)< numwords;="" i++)="">

  var ckWord = this.getPageNthWord (k, i, true);

  var q = this.getPageNthWordQuads (k, i);

  If (ckWord = 'Manager') {}

  Count ++;

  }

  }

  Console.println ("Count none managers" + count + "Number of Page" + (k + 1));

  }