joining 2 tables help

table one

MACHINE DATE_START, DATE_END
-------------------------------------------------------------------------
M5 11/10/10 13:00 11/10/10 18:00


table b

PRODUCTION_DAY DATE_START, DATE_END MACHINE UPDATE
----------------------------------------------------------------------------------------------------------
11/10/2010 11/10/10 13:30 11/10/10 14:30 M5 1
11/10/10 14:30 10/11/10 17:30 M5 1
11/10/10 17:30 10/11/10 18:00 M5 1
11/10/10 18:00 11/10/10 19:00 M5 1

Is there a way to join the 2 tables above, based on the machine and date_start.
tableA has always 1 record and table B has several records for the record in table A.

Try this:

IM assuming your table A will be only a start for one machine per day. For the same machine from table one you will have several times start and end in table B.

Select * from table a, table b where to_char(a.DATE_START,'J') = to_char(B.DATE_START,'J') and a.MACHINE = b.MACHINE

This query you will get all the child records of table B based on the DATE_START (just the date, excluding timestamp) of table A.

to_char(a.DATE_START,'J') returns a number that is unique for the given day.

Ex: Select double to_char(sysdate,'J');

Let me know how you go with it.

Tags: Database

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    uavlsum - view
    uabpymt - table

    The script view below:
    CREATE OR REPLACE VIEW UAVLSUM
    
(UAVLSUM_CUST_CODE, UAVLSUM_PREM_CODE, UAVLSUM_AMOUNT, UAVLSUM_BALANCE)
    
AS 
    
SELECT cust_code,
    
       prem_code,
    
       SUM(amount),
    
       SUM(balance)
    
FROM (
    
SELECT uabopen_cust_code cust_code,
    
       uabopen_prem_code prem_code,
    
       uabopen_billed_chg amount,
    
       uabopen_balance balance
    
FROM   uimsmgr.uabopen
    
UNION ALL
    
SELECT uabpymt_cust_code,
    
       uabpymt_prem_code,
    
       uabpymt_amount * -1,
    
       uabpymt_balance * -1
    
FROM   uimsmgr.uabpymt
    
UNION ALL
    
SELECT uabadje_cust_code,
    
       uabadje_prem_code,
    
       uabadje_balance,
    
       to_number(0)
    
FROM   uimsmgr.uabadje
    
WHERE  uabadje_balance <> 0)
    
GROUP BY cust_code,
    
         prem_code

    samuraibala wrote:
    Find the below out of the plan to explain that we get from the execution of the query

    You use the RULE-based optimizer. What version of Oracle (4-digit, e.g. 9.2.0.8) are you using?

    The execution plan essentially uses the UNION ALL like table to get the corresponding lines of UABPYMT via an index seek according to join at the wheel. According to the number of rows returned by the UNION ALL and grouping factor / selectivity of the index, this could be quite ineffective.

    In addition the GROUP BY operation obviously was merged in the main query, so a NO_MERGE hint could help reduce the number of rows from the source line of conduct UNION ALL:

    SELECT /*+ NO_MERGE (l) */ *
FROM uabpymt p, uavlsum l
...

    With the help of the COST based optimizer might give better results.

    Kind regards
    Randolf

    Oracle related blog stuff:
    http://Oracle-Randolf.blogspot.com/

    SQLTools ++ for Oracle (Open source Oracle GUI for Windows):
    http://www.sqltools-plusplus.org:7676 /.
    http://sourceforge.NET/projects/SQLT-pp/

  • Join the tables in the responses

    I would like to know if it is possible to join the tables together as below in the answers?

    Select a.Field1, b.Field1
    FROM tableA an outer join left tableA b on
    a.Field1 = b.Field

    If you want to make an INNER JOIN, and then type INNER JOIN instead of LEFT INNER JOIN.

    If you want to left outer join and LEFT OUTER JOIN instead of INTERNAL LEFT JOIN type.

    Nothing asked as a left inner join. That is why it gives error + [nQSError: 27002] near +.

    Thank you

  • Outer Join and joining several Tables

    Hello

    Oracle Database 10 g Express Edition Release 10.2.0.1.0 - product

    I have three tables AddProject, AssociateProjectLead, AddAssociate. Now I'm generating a report who will join AddProject and AssociateProjectLead for a list of all the projects, even if it doenst have a project coordinator. I used the outer join for this. However, if I want the name of the project leader, I need to search for AddAssociate table. By joining this table also, the outer join is no longer valid. Please see the result below

    CREATE TABLE  "ADDPROJECT" 
   (     "VERSIONNO" NUMBER(*,0), 
     "PROJID" VARCHAR2(20), 
     "PROJNAME" VARCHAR2(60), 
     "PROJSTARTDATE" DATE, 
     "PROJSTATUS" VARCHAR2(20), 
     "PROJENDDATE" DATE, 
     "PROJENDTYPE" VARCHAR2(20), 
     "PROJENDREASON" VARCHAR2(1000), 
     "UCPROJECTMANAGER" VARCHAR2(20), 
     "FROMDATE" DATE, 
     "TODATE" DATE, 
     "SRCHFIELD" VARCHAR2(20), 
     "OPERATOR" VARCHAR2(20), 
     "PARENTPROJID" VARCHAR2(20), 
     "PROJHIDDENDATE" VARCHAR2(20), 
      CONSTRAINT "PK_B36" PRIMARY KEY ("PROJID", "PROJHIDDENDATE") ENABLE
   )


CREATE TABLE  "ADDASSOCIATE" 
   (     "VERSIONNO" NUMBER(*,0), 
     "ASSOCIATEID" NUMBER(9,0) NOT NULL ENABLE, 
     "ASSOCIATENAME" VARCHAR2(100) NOT NULL ENABLE, 
     "CTOJOINDATE" DATE, 
     "STATUS" VARCHAR2(20), 
     "ENDDATE" DATE, 
     "SRCHFIELD" VARCHAR2(20), 
     "OPERATOR" VARCHAR2(20), 
     "FROMDATE" DATE, 
     "TODATE" DATE, 
      CONSTRAINT "PK_B23" PRIMARY KEY ("ASSOCIATEID") ENABLE
   )

CREATE TABLE  "ASSOCIATEPROJECTLEAD" 
   (     "VERSIONNO" NUMBER(*,0), 
     "PROJLEADASSOID" NUMBER(9,0), 
     "PROJID" VARCHAR2(20), 
     "ASSOCIATEID" NUMBER(9,0), 
     "PROJLEADSTARTDATE" DATE, 
     "STATUS" VARCHAR2(20), 
     "ASSOCPROJHIDDENDATE" VARCHAR2(20), 
     "PROJHIDDENDATE" VARCHAR2(20), 
     "ENDDATE" DATE, 
      CONSTRAINT "PK_B40" PRIMARY KEY ("ASSOCIATEID", "PROJID", "ASSOCPROJHIDDENDATE") ENABLE
   )


elect ap.projid,apl.associateid
from addproject ap, associateprojectlead apl
where ap.projid = apl.projid(+)
and ap.projhiddendate = apl.projhiddendate(+)


PROJID ASSOCIATEID 
Proj08 75825 
Proj09 75825 
Proj10 75825 
Proj11 75825 
Proj12 259811 
Proj01 103035 
Proj02 103035 
Proj03 320092 
Proj04 320092 
Proj05 120974 
Proj06 367393 
Proj07 117618 
Proj07 224882 
Proj07 246652 
prj001 -  
prj001 -  

16 rows returned in 0.00 seconds


select ap.projid,apl.associateid,aa.associatename
from addproject ap, associateprojectlead apl,addassociate aa
where ap.projid = apl.projid(+)
and ap.projhiddendate = apl.projhiddendate(+)
and apl.associateid = aa.associateid


PROJID ASSOCIATEID ASSOCIATENAME 
Proj11 75825 Amarendra Kumar Singh 
Proj10 75825 Amarendra Kumar Singh 
Proj09 75825 Amarendra Kumar Singh 
Proj08 75825 Amarendra Kumar Singh 
Proj02 103035 Rajesh Jayaprakash 
Proj01 103035 Rajesh Jayaprakash 
Proj07 117618 Chetan Malhotra 
Proj05 120974 Perumal Rajaram 
Proj07 224882 Dilshad Ahmad 
Proj07 246652 Shankar Kausley 
Proj12 259811 Arunchandar Arun Vasan 
Proj04 320092 Venkatesh Sarangan 
Proj03 320092 Venkatesh Sarangan 
Proj06 367393 Venkata Ramakrishna P 

14 rows returned in 0.00 seconds
    How can I select all the values in table AddProject?

    Published by: Pramukh on August 23, 2012 12:18

    Hello

    I could get the result with a bit of modification

    select ap.projid,
       apl.associateid,
       aa.associatename
  from addproject ap
       left outer join
       associateprojectlead apl
    on ap.projid = apl.projid
   and ap.projhiddendate = apl.projhiddendate
       left outer join
       addassociate aa
    on apl.associateid = aa.associateid

    As a follow-up, I have a request more. In the report form, the user can select a particular project ID and the report should be generated as a result. For example;-he wants to see the results of the only "Proj08". I get the output as below, while the result should display only the details of 'Proj08 '.

    select ap.projid,
       apl.associateid,
       aa.associatename
  from addproject ap
       left outer join
       associateprojectlead apl
    on ap.projid = apl.projid
   and ap.projhiddendate = apl.projhiddendate
   and ap.projID = 'Proj08'
       left outer join
       addassociate aa
    on apl.associateid = aa.associateid
ORDER BY ap.projID

PROJID ASSOCIATEID ASSOCIATENAME
Proj01 -  -
Proj02 -  -
Proj03 -  -
Proj04 -  -
Proj05 -  -
Proj06 -  -
Proj07 -  -
Proj08 75825 Amarendra Kumar Singh
Proj09 -  -
Proj10 -  -
Proj11 -  -
Proj12 -  -
prj001 -  -
prj001 -  -

  • Outer join, 3 tables

    Please see the attached link for table structures and data of the sample.

    There will be several lines in the table of SALES with different SALETYPEs. There may be several lines in the table RETURNS, corresponding to some of the points of SALE. RETURNS the table has a foreign key to the SALE. The report that I am trying to generate with a select sql statement must include a line for each type of sale (from table SALETYPE) and the sum of sale amounts corresponding to this type of sale of the SALES table. The table may not return the entries for all types of sales and the amount of Scripture must be reported as zero. The SQL I use is below, but does not work. I hope that I have explained this correctly. Please see the doc attached for typical data that I work with. Can someone please?

    https://spreadsheets.Google.com/pub?key=0AnDmnUJXOChwdGF2ZjdjdHFtMGF1MkJ3MWtjQ2JfUmc & hl = in & Single = true & gid = 0 & output = html

    Select SUM (s.amount) as sum_amount, t.sale_type from SALES s, SALETYPE t, r RETURNS
    where s.id = r.id
    and s.sale_type_id = t.id
    T.sale_type group;

    Published by: 801941 on October 12, 2010 15:02

    Hello - the second displays almost had. what you want to do is joining several tables at once - impossible with the syntax of the oracle, but possible if you use ANSI SQL.

    Wrote file afiedt.buf

  1  WITH s AS
  2   (SELECT 1 id, 1 sale_type_id, 10 amount   FROM dual
  3    UNION ALL
  4    SELECT 2, 1, 10  FROM dual
  5    UNION ALL
  6    SELECT 3, 2, 10   FROM dual
  7    UNION ALL
  8    SELECT 4, 2, 10   FROM dual
  9    UNION ALL
 10    SELECT 5, 3, 10    FROM dual
 11    UNION ALL
 12    SELECT 6, 4, 10 FROM dual),
 13  r AS
 14   (SELECT 2 sale_id   FROM dual
 15    UNION ALL
 16    SELECT 3 FROM dual
 17    UNION ALL
 18    SELECT 4 FROM dual),
 19  t AS
 20   (SELECT 1 sale_type_id, 100 sale_type    FROM dual
 21    UNION ALL
 22    SELECT 2, 200    FROM dual
 23    UNION ALL
 24    SELECT 3, 300    FROM dual
 25    UNION ALL
 26    SELECT 4, 400 FROM dual)
 27  SELECT nvl(SUM(s.amount),0) total_amount, t.sale_type
 28    FROM t
 29     join r on (1=1)
 30     left outer join s on (s.id = r.sale_id and s.sale_type_id = t.sale_type_id)
 31   --WHERE s.id(+) = r.sale_id
 32  --   AND s.sale_type_id(+) = t.sale_type_id
 33   GROUP BY t.sale_type
 34*  order by t.sale_type
SQL> /

TOTAL_AMOUNT  SALE_TYPE
------------ ----------
          10        100
          20        200
           0        300
           0        400

4 rows selected.

    The two commented lines are what you are trying to achieve using the syntax of the oracle, but which will give you an error.

  • Join of tables?

    Hello


    My 1st question
    Sometimes i have hard time in deciding the weather to use equi join or left join or right join ?? 

After looking at the data model i can understand how the tables can be joined on what attribute but i lack in making decision weather to use left join or right join for one to many or many to one relationships 

I know the concept of right join and left join but i get confused in what scenario i need to use left join or right join and what join to use for one to many relationships or many to one relationships

If you have any techniques or suggetions how to use them that will be great!!
    My 2nd question




    ___Table1___ TableA
    | | | |
    Table2, table3 table 4 < - TableC - TableB-|

    Table 1 a 1 of many relationships of table2, table 3, table 4

    I, e Table1-> table 2, table 3, table 4

    Table A has many relationships in table 1 B, i, e TableA-> table B

    Table B has 1 in-several in Table C, i, e table B-> table C

    Table C has many relationships in table 4, i, e 1 C table-> table 4


    I know the attributes to use to join these tables, but my question is what join what I use left join or right join or Equi join (I don't think I can use this)


    Something like that in my SQL query in where clause (I don't know if this is right).

    Where
    Table1. ID = table2. ID
    or table1.my_field = table3.id
    or table1.my_field = table4.id
    or tableA. ID = tableB.id---(ce que je dois opérateur OR ou opérateur AND???)
    or tableB.id = TableC.id
    or tablec.id = table4.id

    I don't know if this right or do I have to use the left join on right join or and or operator operator 'OR' is something I m really confued subject.




    Any advice greatly appriciated thank you!

    Published by: user642297 on May 12, 2010 09:49

    Published by: user642297 on May 12, 2010 09:51

    Apart from referring to various documents and examples...
    Use the following examples as 'Playground' and experience to get an idea of the various "joins".

    -- SETUP for examples...
drop table A;
drop table B;
drop table C;

create table a (ca int, sa varchar2(50));

create table b (cb int, sb varchar2(50));

create table c (cc int, sc varchar2(50));

insert into A
select * from
(
select level myid, to_char( to_date( level,'J'),'Jsp') mystr
from dual connect by level < 11
);
commit;

insert into B
select * from
(
select level myid, to_char( to_date( level,'J'),'Jsp') mystr
from dual connect by level < 21
)
where mod(myid,2) = 0;
commit;

insert into C
select * from
(
select level myid, to_char( to_date( level,'J'),'Jsp') mystr
from dual connect by level < 11
)
where myid < 6;
commit;

-- Verify the setup
select * from A;

select * from B;

select * from C;

-- **************************************************************
-- Requirement EQUI JOIN 1. (AKA INNER JOIN)
-- To select rows from A and MATCHING rows from B
-- use A JOIN B or B JOIN A
--
-- ANSI SQL syntax
select * from
A JOIN B
on (A.CA = B.CB)
;
-- **** OR ****
select * from
B JOIN A
on (A.CA = B.CB)
;
-- OR Traditional Oracle syntax
select * from A, B
where A.CA = B.CB
;

-- **************************************************************
-- Requirement EQUI JOIN 2. (AKA INNER JOIN)
-- To select rows from A and MATCHING rows from B and matching
-- rows from C
-- use A JOIN B JOIN C
--
-- ANSI SQL syntax
select * from
A JOIN B
on (A.CA = B.CB)
JOIN C
on(B.CB = C.CC)
;
-- OR Traditional Oracle syntax
select * from A, B, C
where A.CA = B.CB
  and B.CB = C.CC
;

-- **************************************************************
-- Requirement OUTER JOIN 1.
-- To select ALL rows from A and ONLY MATCHING rows from B
-- use A LEFT OUTER JOIN B or B RIGHT OUTER JOIN A
--
-- The columns for table B will have NULL value where a
-- match for A is not found
--
-- ANSI SQL syntax
select * from
A LEFT OUTER JOIN B
on (A.CA = B.CB)
;
-- **** OR ****
select * from
B RIGHT OUTER JOIN A
on (A.CA = B.CB)
;
-- OR Traditional Oracle syntax
select * from A, B
where A.CA = B.CB(+)
;
----------------------------------------------------------
-- The queries above are EQUIVALENT - return the same
-- result set.
-- **** However note the "order" in which the rows are
--      returned by default.
----------------------------------------------------------

-- **************************************************************
-- Requirement OUTER JOIN 2.
-- To select ALL rows from B and ONLY MATCHING rows from A
-- use B LEFT OUTER JOIN A or A RIGHT OUTER JOIN B
--
-- The columns for table A will have NULL value where a
-- match for B is not found
--
-- ANSI SQL syntax
select * from
B LEFT OUTER JOIN A
on (A.CA = B.CB)
;
-- **** OR ****
select * from
A RIGHT OUTER JOIN B
on (A.CA = B.CB)
;
-- Traditional Oracle syntax
select * from A, B
where A.CA(+) = B.CB
;

-- **************************************************************
-- Requirement OUTER JOIN 3.
-- To select ALL rows from A and ONLY MATCHING rows from B
-- AND select those rows from C that match rows from B
--
-- ANSI SQL syntax
select * from
A LEFT OUTER JOIN B
on (A.CA = B.CB)
 LEFT OUTER JOIN C
on (B.CB = C.CC)
;
-- OR Traditional Oracle syntax
select * from A, B, C
where A.CA = B.CB(+)
  and B.CB = C.CC(+)
;
----------------------------------------------------------
-- and So on...

-- **************************************************************
-- Requirement FULL JOIN 3.
-- To select ALL rows from A and ALL rows from B
-- AND MATCH the rows from A and B that match, but return even
-- the unmatching rows.
--
-- ANSI SQL syntax
select * from
A FULL OUTER JOIN B
on (A.CA = B.CB)
;
-- OR Traditional Oracle syntax
-- There is no equivalent for FULL OUTER join in traditional
-- syntax. (Though it can be achieved using other means)
-----------------------------------------------------------------

    VR,
    Sudhakar B.

  • Joining MySQL Tables

    I have a MySQL table that contains two user, each a different user id. I want to make a query that joins the table containing the table user to retrieve user names corresponding to these two user id how is this possible?

    "AngryCloud" wrote in message
    News:fgg691$1JT$1@forums. Macromedia.com...
    > Sorry, I do not think that my question I explained that well. Let me rephrase:
    >
    > I have a MySQL table that contains two user id, each other
    > user.
    > Each of the id is in another column. I want to make a query that
    > joins
    > user table that contains the table to retrieve the corresponding user names to the
    > time
    > user
    >
    > Lets say I have a table called Messages. A record in the salons of tables the
    > ID recipient is 26 'and the sender ID is 14'. I want to create a query
    > who
    > joins the table of Messages containing the data of the user table to get the names of users of
    > each
    > these users.
    >
    > Just for possible yet understand, let me show you an example query
    > who
    > doesn't make any sense, but it might be useful to describe what I'm trying
    > reach.
    >
    > 'SELECT messages.recipient_id, messages.sender_id, messages.message,
    > user_data.username
    > MESSAGES
    > User_data LEFT JOIN ON messages.recipient_id = user_data.id
    ' > User_data LEFT JOIN ON messages.sender_id = user_data.id.

    in fact it makes sense, but you must apply aliases for tables
    and columns

    SELECT messages.recipient_id, messages.sender_id, messages.message,
    recipient_data. UserName as beneficiary, sender_data.username as sender
    ((MESSAGES
    User_data LEFT JOIN AS recipient_data ON messages.recipient_id =
    USER_DATA.ID)
    User_data LEFT JOIN AS sender_data ON messages.sender_id = user_data.id)

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