Join view Table

Hello

My doubt is that I can join the table with view in the sub clause where condition in the query. If so, the query below will take 4 hrs to run it. I can do the below query to write under the simpler name?
SELECT *

  FROM uabpymt p, uavlsum l

 WHERE uabpymt_appl_ind = 'N'

   AND uabpymt_amount > 5

   AND l.uavlsum_balance < 0

   AND l.uavlsum_cust_code = p.uabpymt_cust_code

   AND l.uavlsum_prem_code = p.uabpymt_prem_code
uavlsum - view
uabpymt - table

The script view below:
CREATE OR REPLACE VIEW UAVLSUM

(UAVLSUM_CUST_CODE, UAVLSUM_PREM_CODE, UAVLSUM_AMOUNT, UAVLSUM_BALANCE)

AS 

SELECT cust_code,

       prem_code,

       SUM(amount),

       SUM(balance)

FROM (

SELECT uabopen_cust_code cust_code,

       uabopen_prem_code prem_code,

       uabopen_billed_chg amount,

       uabopen_balance balance

FROM   uimsmgr.uabopen

UNION ALL

SELECT uabpymt_cust_code,

       uabpymt_prem_code,

       uabpymt_amount * -1,

       uabpymt_balance * -1

FROM   uimsmgr.uabpymt

UNION ALL

SELECT uabadje_cust_code,

       uabadje_prem_code,

       uabadje_balance,

       to_number(0)

FROM   uimsmgr.uabadje

WHERE  uabadje_balance <> 0)

GROUP BY cust_code,

         prem_code

samuraibala wrote:
Find the below out of the plan to explain that we get from the execution of the query

You use the RULE-based optimizer. What version of Oracle (4-digit, e.g. 9.2.0.8) are you using?

The execution plan essentially uses the UNION ALL like table to get the corresponding lines of UABPYMT via an index seek according to join at the wheel. According to the number of rows returned by the UNION ALL and grouping factor / selectivity of the index, this could be quite ineffective.

In addition the GROUP BY operation obviously was merged in the main query, so a NO_MERGE hint could help reduce the number of rows from the source line of conduct UNION ALL:

SELECT /*+ NO_MERGE (l) */ *
FROM uabpymt p, uavlsum l
...

With the help of the COST based optimizer might give better results.

Kind regards
Randolf

Oracle related blog stuff:
http://Oracle-Randolf.blogspot.com/

SQLTools ++ for Oracle (Open source Oracle GUI for Windows):
http://www.sqltools-plusplus.org:7676 /.
http://sourceforge.NET/projects/SQLT-pp/

Tags: Database

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e."ROWID",
e."EMPNO",
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e."JOB"
from "#OWNER#"."EMP" e, dept d
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     "PROJID" VARCHAR2(20), 
     "ASSOCIATEID" NUMBER(9,0), 
     "PROJLEADSTARTDATE" DATE, 
     "STATUS" VARCHAR2(20), 
     "ASSOCPROJHIDDENDATE" VARCHAR2(20), 
     "PROJHIDDENDATE" VARCHAR2(20), 
     "ENDDATE" DATE, 
      CONSTRAINT "PK_B40" PRIMARY KEY ("ASSOCIATEID", "PROJID", "ASSOCPROJHIDDENDATE") ENABLE
   )


elect ap.projid,apl.associateid
from addproject ap, associateprojectlead apl
where ap.projid = apl.projid(+)
and ap.projhiddendate = apl.projhiddendate(+)


PROJID ASSOCIATEID 
Proj08 75825 
Proj09 75825 
Proj10 75825 
Proj11 75825 
Proj12 259811 
Proj01 103035 
Proj02 103035 
Proj03 320092 
Proj04 320092 
Proj05 120974 
Proj06 367393 
Proj07 117618 
Proj07 224882 
Proj07 246652 
prj001 -  
prj001 -  

16 rows returned in 0.00 seconds


select ap.projid,apl.associateid,aa.associatename
from addproject ap, associateprojectlead apl,addassociate aa
where ap.projid = apl.projid(+)
and ap.projhiddendate = apl.projhiddendate(+)
and apl.associateid = aa.associateid


PROJID ASSOCIATEID ASSOCIATENAME 
Proj11 75825 Amarendra Kumar Singh 
Proj10 75825 Amarendra Kumar Singh 
Proj09 75825 Amarendra Kumar Singh 
Proj08 75825 Amarendra Kumar Singh 
Proj02 103035 Rajesh Jayaprakash 
Proj01 103035 Rajesh Jayaprakash 
Proj07 117618 Chetan Malhotra 
Proj05 120974 Perumal Rajaram 
Proj07 224882 Dilshad Ahmad 
Proj07 246652 Shankar Kausley 
Proj12 259811 Arunchandar Arun Vasan 
Proj04 320092 Venkatesh Sarangan 
Proj03 320092 Venkatesh Sarangan 
Proj06 367393 Venkata Ramakrishna P 

14 rows returned in 0.00 seconds
    How can I select all the values in table AddProject?

    Published by: Pramukh on August 23, 2012 12:18

    Hello

    I could get the result with a bit of modification

    select ap.projid,
       apl.associateid,
       aa.associatename
  from addproject ap
       left outer join
       associateprojectlead apl
    on ap.projid = apl.projid
   and ap.projhiddendate = apl.projhiddendate
       left outer join
       addassociate aa
    on apl.associateid = aa.associateid

    As a follow-up, I have a request more. In the report form, the user can select a particular project ID and the report should be generated as a result. For example;-he wants to see the results of the only "Proj08". I get the output as below, while the result should display only the details of 'Proj08 '.

    select ap.projid,
       apl.associateid,
       aa.associatename
  from addproject ap
       left outer join
       associateprojectlead apl
    on ap.projid = apl.projid
   and ap.projhiddendate = apl.projhiddendate
   and ap.projID = 'Proj08'
       left outer join
       addassociate aa
    on apl.associateid = aa.associateid
ORDER BY ap.projID

PROJID ASSOCIATEID ASSOCIATENAME
Proj01 -  -
Proj02 -  -
Proj03 -  -
Proj04 -  -
Proj05 -  -
Proj06 -  -
Proj07 -  -
Proj08 75825 Amarendra Kumar Singh
Proj09 -  -
Proj10 -  -
Proj11 -  -
Proj12 -  -
prj001 -  -
prj001 -  -

  • date max with multiple joins of tables

    Looking for expert advice on the use of max (date) with multiple joins of tables. Several people have tried (and failed) - HELP Please!

    The goal is to retrieve the most current joined line of NBRJOBS_EFFECTIVE_DATE for each unique NBRJOBS_PIDM. There are several lines by PIDM with various EFFECTIVE_DATEs. The following SQL returns about 1/3 of the files and there are also some multiples.

    The keys are PIDM, POSN and suff

    Select NBRJOBS. NBRJOBS.*,
    NBRBJOB. NBRBJOB.*
    of POSNCTL. Inner join of NBRBJOB NBRBJOB POSNCTL. NBRJOBS NBRJOBS on (NBRBJOB. NBRBJOB_PIDM = NBRJOBS. NBRJOBS_PIDM) and (NBRBJOB. NBRBJOB_POSN = NBRJOBS. NBRJOBS_POSN) and (NBRBJOB. NBRBJOB_SUFF = NBRJOBS. NBRJOBS_SUFF)
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    and NBRBJOB. NBRBJOB_CONTRACT_TYPE = 'P '.
    and NBRJOBS. NBRJOBS_EFFECTIVE_DATE =
    (select Max (NBRJOBS1. NBRJOBS_EFFECTIVE_DATE) as 'EffectDate '.
    of POSNCTL. NBRJOBS NBRJOBS1
    where NBRJOBS1. NBRJOBS_PIDM = NBRJOBS. NBRJOBS_PIDM
    and NBRJOBS1. NBRJOBS_POSN = NBRJOBS. NBRJOBS_POSN
    and NBRJOBS1. NBRJOBS_SUFF = NBRJOBS. NBRJOBS_SUFF
    and NBRJOBS1. NBRJOBS_SUFF <>'LS '.
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    order of NBRJOBS. NBRJOBS_PIDM

    Welcome to the forum!

    We don't know what you are trying to do.
    You want all of the columns in the rows where NBRJOBS_EFFECTIVE_DATE is the date limit before a given date (November 15, 2011 in this example) for all rows in the result set with this NBRJOBS_PIDM? If so, here is one way:

    with         GOT_R_NUM     as
(
     select       NBRJOBS.NBRJOBS.*,
            NBRBJOB.NBRBJOB.*     -- You may have to give aliases, so that every column has a unique name
     ,       rank () over ( partition by  NBRJOBS.NBRJOBS_PIDM
                               order by      NBRJOBS.NBRJOBS_EFFECTIVE_DATE     desc
                      )             as R_NUM
     from          POSNCTL.NBRBJOB NBRBJOB
     inner join      POSNCTL.NBRJOBS NBRJOBS       on    (NBRBJOB.NBRBJOB_PIDM = NBRJOBS.NBRJOBS_PIDM)
                                        and      (NBRBJOB.NBRBJOB_POSN = NBRJOBS.NBRJOBS_POSN)
                                  and      (NBRBJOB.NBRBJOB_SUFF = NBRJOBS.NBRJOBS_SUFF)
     where       NBRJOBS.NBRJOBS_SUFF             != 'LS'       -- Is this what you meant?
     and        NBRBJOB.NBRBJOB_CONTRACT_TYPE   ='P'
     and       NBRJOBS.NBRJOBS_EFFECTIVE_DATE  <= to_date ('2011/11/15', 'yyyy/mm/dd')
)
select       *     -- Or list all columns except R_NUM
from       GOT_R_NUM
where       R_NUM          = 1
order by  NBRJOBS_PIDM
;

    Normally this site does not display the <>inequality operator; He thinks it's some kind of beacon.
    Whenever you post on this site, use the other inequality operator (equivalent), *! = *.

    I hope that answers your question.
    If not, post a small example of data (CREATE TABLE and INSERT, only relevant columns instructions) for all the tables involved and the results desired from these data.
    Explain, using specific examples, how you get these results from these data.
    Always tell what version of Oracle you are using.
    You will get better results faster if you always include this information whenever you have a problem.

  • BAD RESULTS WITH OUTER JOINS AND TABLES WITH A CHECK CONSTRAINT

    HII All,
    Could any such a me when we encounter this bug? Please help me with a simple example so that I can search for them in my PB.


    Bug:-8447623

    Bug / / Desc: BAD RESULTS WITH OUTER JOINS AND TABLES WITH a CHECK CONSTRAINT


    I ran the outer joins with check queries constraint 11G 11.1.0.7.0 and 10 g 2, but the result is the same. Need to know the scenario where I will face this bug of your experts and people who have already experienced this bug.


    Version: -.
    SQL> select * from v$version;

BANNER
--------------------------------------------------------------------------------
Oracle Database 11g Enterprise Edition Release 11.1.0.7.0 - 64bit Production
PL/SQL Release 11.1.0.7.0 - Production
CORE    11.1.0.7.0      Production
TNS for Solaris: Version 11.1.0.7.0 - Production
NLSRTL Version 11.1.0.7.0 - Production

    Why do you not use the description of the bug test case in Metalink (we obviously can't post it here because it would violate the copyright of Metalink)? Your test case is not a candidate for the elimination of the join, so he did not have the bug.

    Have you really read the description of the bug in Metalink rather than just looking at the title of the bug? The bug itself is quite clear that a query plan that involves the elimination of the join is a necessary condition. The title of bug nothing will never tell the whole story.

    If you try to work through a few tens of thousands of bugs in 11.1.0.7, of which many are not published, trying to determine whether your application would be affected by the bug? Wouldn't be order of magnitude easier to upgrade the application to 11.1.0.7 in a test environment and test the application to see what, if anything, breaks? Understand that the vast majority of the problems that people experience during an upgrade are not the result of bugs - they are the result of changes in behaviour documented as changes in query plans. And among those who encounter bugs, a relatively large fraction of the new variety. Even if you have completed the Herculean task of verifying each bug on your code base, which would not significantly easier upgrade. In addition, at the time wherever you actually performed this analysis, Oracle reportedly released 3 or 4 new versions.

    And at this stage would be unwise to consider an upgrade to 11.2?

    Justin

  • How to join the table in screens LCD

    Hello

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    I run LCDS3 and tomcat.

    Any help is appricitated

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    Address (address, State, country, postal code)

    If you want to display data below in your data grid

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  • Outer join, 3 tables

    Please see the attached link for table structures and data of the sample.

    There will be several lines in the table of SALES with different SALETYPEs. There may be several lines in the table RETURNS, corresponding to some of the points of SALE. RETURNS the table has a foreign key to the SALE. The report that I am trying to generate with a select sql statement must include a line for each type of sale (from table SALETYPE) and the sum of sale amounts corresponding to this type of sale of the SALES table. The table may not return the entries for all types of sales and the amount of Scripture must be reported as zero. The SQL I use is below, but does not work. I hope that I have explained this correctly. Please see the doc attached for typical data that I work with. Can someone please?

    https://spreadsheets.Google.com/pub?key=0AnDmnUJXOChwdGF2ZjdjdHFtMGF1MkJ3MWtjQ2JfUmc & hl = in & Single = true & gid = 0 & output = html

    Select SUM (s.amount) as sum_amount, t.sale_type from SALES s, SALETYPE t, r RETURNS
    where s.id = r.id
    and s.sale_type_id = t.id
    T.sale_type group;

    Published by: 801941 on October 12, 2010 15:02

    Hello - the second displays almost had. what you want to do is joining several tables at once - impossible with the syntax of the oracle, but possible if you use ANSI SQL.

    Wrote file afiedt.buf

  1  WITH s AS
  2   (SELECT 1 id, 1 sale_type_id, 10 amount   FROM dual
  3    UNION ALL
  4    SELECT 2, 1, 10  FROM dual
  5    UNION ALL
  6    SELECT 3, 2, 10   FROM dual
  7    UNION ALL
  8    SELECT 4, 2, 10   FROM dual
  9    UNION ALL
 10    SELECT 5, 3, 10    FROM dual
 11    UNION ALL
 12    SELECT 6, 4, 10 FROM dual),
 13  r AS
 14   (SELECT 2 sale_id   FROM dual
 15    UNION ALL
 16    SELECT 3 FROM dual
 17    UNION ALL
 18    SELECT 4 FROM dual),
 19  t AS
 20   (SELECT 1 sale_type_id, 100 sale_type    FROM dual
 21    UNION ALL
 22    SELECT 2, 200    FROM dual
 23    UNION ALL
 24    SELECT 3, 300    FROM dual
 25    UNION ALL
 26    SELECT 4, 400 FROM dual)
 27  SELECT nvl(SUM(s.amount),0) total_amount, t.sale_type
 28    FROM t
 29     join r on (1=1)
 30     left outer join s on (s.id = r.sale_id and s.sale_type_id = t.sale_type_id)
 31   --WHERE s.id(+) = r.sale_id
 32  --   AND s.sale_type_id(+) = t.sale_type_id
 33   GROUP BY t.sale_type
 34*  order by t.sale_type
SQL> /

TOTAL_AMOUNT  SALE_TYPE
------------ ----------
          10        100
          20        200
           0        300
           0        400

4 rows selected.

    The two commented lines are what you are trying to achieve using the syntax of the oracle, but which will give you an error.

  • Join of tables?

    Hello


    My 1st question
    Sometimes i have hard time in deciding the weather to use equi join or left join or right join ?? 

After looking at the data model i can understand how the tables can be joined on what attribute but i lack in making decision weather to use left join or right join for one to many or many to one relationships 

I know the concept of right join and left join but i get confused in what scenario i need to use left join or right join and what join to use for one to many relationships or many to one relationships

If you have any techniques or suggetions how to use them that will be great!!
    My 2nd question




    ___Table1___ TableA
    | | | |
    Table2, table3 table 4 < - TableC - TableB-|

    Table 1 a 1 of many relationships of table2, table 3, table 4

    I, e Table1-> table 2, table 3, table 4

    Table A has many relationships in table 1 B, i, e TableA-> table B

    Table B has 1 in-several in Table C, i, e table B-> table C

    Table C has many relationships in table 4, i, e 1 C table-> table 4


    I know the attributes to use to join these tables, but my question is what join what I use left join or right join or Equi join (I don't think I can use this)


    Something like that in my SQL query in where clause (I don't know if this is right).

    Where
    Table1. ID = table2. ID
    or table1.my_field = table3.id
    or table1.my_field = table4.id
    or tableA. ID = tableB.id---(ce que je dois opérateur OR ou opérateur AND???)
    or tableB.id = TableC.id
    or tablec.id = table4.id

    I don't know if this right or do I have to use the left join on right join or and or operator operator 'OR' is something I m really confued subject.




    Any advice greatly appriciated thank you!

    Published by: user642297 on May 12, 2010 09:49

    Published by: user642297 on May 12, 2010 09:51

    Apart from referring to various documents and examples...
    Use the following examples as 'Playground' and experience to get an idea of the various "joins".

    -- SETUP for examples...
drop table A;
drop table B;
drop table C;

create table a (ca int, sa varchar2(50));

create table b (cb int, sb varchar2(50));

create table c (cc int, sc varchar2(50));

insert into A
select * from
(
select level myid, to_char( to_date( level,'J'),'Jsp') mystr
from dual connect by level < 11
);
commit;

insert into B
select * from
(
select level myid, to_char( to_date( level,'J'),'Jsp') mystr
from dual connect by level < 21
)
where mod(myid,2) = 0;
commit;

insert into C
select * from
(
select level myid, to_char( to_date( level,'J'),'Jsp') mystr
from dual connect by level < 11
)
where myid < 6;
commit;

-- Verify the setup
select * from A;

select * from B;

select * from C;

-- **************************************************************
-- Requirement EQUI JOIN 1. (AKA INNER JOIN)
-- To select rows from A and MATCHING rows from B
-- use A JOIN B or B JOIN A
--
-- ANSI SQL syntax
select * from
A JOIN B
on (A.CA = B.CB)
;
-- **** OR ****
select * from
B JOIN A
on (A.CA = B.CB)
;
-- OR Traditional Oracle syntax
select * from A, B
where A.CA = B.CB
;

-- **************************************************************
-- Requirement EQUI JOIN 2. (AKA INNER JOIN)
-- To select rows from A and MATCHING rows from B and matching
-- rows from C
-- use A JOIN B JOIN C
--
-- ANSI SQL syntax
select * from
A JOIN B
on (A.CA = B.CB)
JOIN C
on(B.CB = C.CC)
;
-- OR Traditional Oracle syntax
select * from A, B, C
where A.CA = B.CB
  and B.CB = C.CC
;

-- **************************************************************
-- Requirement OUTER JOIN 1.
-- To select ALL rows from A and ONLY MATCHING rows from B
-- use A LEFT OUTER JOIN B or B RIGHT OUTER JOIN A
--
-- The columns for table B will have NULL value where a
-- match for A is not found
--
-- ANSI SQL syntax
select * from
A LEFT OUTER JOIN B
on (A.CA = B.CB)
;
-- **** OR ****
select * from
B RIGHT OUTER JOIN A
on (A.CA = B.CB)
;
-- OR Traditional Oracle syntax
select * from A, B
where A.CA = B.CB(+)
;
----------------------------------------------------------
-- The queries above are EQUIVALENT - return the same
-- result set.
-- **** However note the "order" in which the rows are
--      returned by default.
----------------------------------------------------------

-- **************************************************************
-- Requirement OUTER JOIN 2.
-- To select ALL rows from B and ONLY MATCHING rows from A
-- use B LEFT OUTER JOIN A or A RIGHT OUTER JOIN B
--
-- The columns for table A will have NULL value where a
-- match for B is not found
--
-- ANSI SQL syntax
select * from
B LEFT OUTER JOIN A
on (A.CA = B.CB)
;
-- **** OR ****
select * from
A RIGHT OUTER JOIN B
on (A.CA = B.CB)
;
-- Traditional Oracle syntax
select * from A, B
where A.CA(+) = B.CB
;

-- **************************************************************
-- Requirement OUTER JOIN 3.
-- To select ALL rows from A and ONLY MATCHING rows from B
-- AND select those rows from C that match rows from B
--
-- ANSI SQL syntax
select * from
A LEFT OUTER JOIN B
on (A.CA = B.CB)
 LEFT OUTER JOIN C
on (B.CB = C.CC)
;
-- OR Traditional Oracle syntax
select * from A, B, C
where A.CA = B.CB(+)
  and B.CB = C.CC(+)
;
----------------------------------------------------------
-- and So on...

-- **************************************************************
-- Requirement FULL JOIN 3.
-- To select ALL rows from A and ALL rows from B
-- AND MATCH the rows from A and B that match, but return even
-- the unmatching rows.
--
-- ANSI SQL syntax
select * from
A FULL OUTER JOIN B
on (A.CA = B.CB)
;
-- OR Traditional Oracle syntax
-- There is no equivalent for FULL OUTER join in traditional
-- syntax. (Though it can be achieved using other means)
-----------------------------------------------------------------

    VR,
    Sudhakar B.

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    "AngryCloud" wrote in message
    News:fgg691$1JT$1@forums. Macromedia.com...
    > Sorry, I do not think that my question I explained that well. Let me rephrase:
    >
    > I have a MySQL table that contains two user id, each other
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    > user
    >
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    > joins the table of Messages containing the data of the user table to get the names of users of
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    > these users.
    >
    > Just for possible yet understand, let me show you an example query
    > who
    > doesn't make any sense, but it might be useful to describe what I'm trying
    > reach.
    >
    > 'SELECT messages.recipient_id, messages.sender_id, messages.message,
    > user_data.username
    > MESSAGES
    > User_data LEFT JOIN ON messages.recipient_id = user_data.id
    ' > User_data LEFT JOIN ON messages.sender_id = user_data.id.

    in fact it makes sense, but you must apply aliases for tables
    and columns

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