Left outer join error 2

Similar Questions

• Get the error invalid identifier in the left outer join

  I wrote a query and get the invalid identifier error during execution:
  the exact error is: ORA-00904: "D". "" ACCT_NO ": invalid identifier
  This query is not able to access the parent table alias in the subquery of the left outer join.
  
  This is the query:
  SELECT D.PROD_DESC_TX, BASE. ASSET_NUM, BASE. PROD_ID, BASE.NAME
  OF TABLE1 D
  LEFT OUTER JOIN
  (
  SELECT ASSET_NUM, PROD_ID, B.SID
  FROM TABLE2 E
  JOIN IN-HOUSE TABLE3 HAS IT E.PROD_ID = A.ROW_ID
  JOIN INTERNAL TABLE 4 C ON A.PAR_PROD_INT_ID = C.ROW_ID
  INTERNAL TABLE5 JOIN B ON C.ROW_ID = B.PAR_ROW_ID
  AND B.TYPE = 'VALUE '.
  AND B.NAME = 'VALUE '.
  WHERE E.ASSET_NUM = ((CASE WHEN LTRIM (RTRIM (D.BANK_NO)) = '021 ' THEN '021' ELSE ' 020' END) |) LTRIM (RTRIM (D.APPL_CD)). LTRIM (RTRIM (D.ACCT_NO)))
  ) BASE ON ((CASE WHEN LTRIM (RTRIM (D.BANK_NO)) = '021 ' THEN '021' ELSE ' 020' END) |) LTRIM (RTRIM (D.APPL_CD)). LTRIM (RTRIM (D.ACCT_NO))) = BASE. ASSET_NUM
  WHERE D.BANK_NO = 'VALUE '.
  AND D.APPL_CD = 'VALUE '.
  AND D.ACCT_NO = 'VALUE '.
  
  Edited by: user648525 13 Sep, 2011 01:21

  I can easily look at your request at this time (using my iPhone on a train).

  But trying out this line in the WHERE (the one with the invalid reference) clause in the main query.

  Who is... in the view of inline, use only the logic of the join (the clauses).

  Overflow the filtering logic (WHERE clause) to the main request. You may need to select some additional inline view columns to make these references work.

• Query of queries: error when you try to fake Left Outer Join

  Hello

  I'm trying to reproduce a left outer join, combining two query of queries using a method I find here

  However, I get an error message...

  Here is the code I use...

  < cfquery dbtype = "query" name = "qry" >
  SELECT *.
  OF returnQry, returnQry2
  WHERE returnQry.mediumImage = returnQry2.mediumImage
  ORDER BY returnQry.name
  < / cfquery >
  
  < name cfquery = "returnQry3", dbtype = "#application.mx #" >
  SELECT *.
  OF trackmeanings t
  < / cfquery >

  < cfquery dbtype = "query" name = "endQry" >
  SELECT name, nameRcd, mediumImage, comments COUNT (sMessage)
  OF qry, returnQry3
  WHERE qry.name = returnQry3.sNameTrack
  
  UNION
  
  SELECT name, nameRcd, mediumImage, comments COUNT (sMessage)
  OF qry, returnQry3
  WHERE #qry.name # NOT IN (#QuotedValueList (returnQry3.sNameTrack) #)
  GROUP BY name, nameRcd, mediumImage
  < / cfquery >

  When I try to use the query output in a page, I get the error message "incorrect conditional expression, waiting for an a [as |]» null | between | in | "comparison condition.

  Anyone have any ideas?

  Thank you very much

  The items in the list should be cited.  Since you are using quotedvaluelist, it's weird that they aren't.  However, if you use cfqueryparam, list = Yes, you should have better luck.  Among other things, it will protect you against the apostrophe in names.

• Left Outer Join help...

  Hello world

  I'm still trying to learn the SQL, and I can not specifically with the left outer join.  I normally join tables using equijoin, but I don't get the right data set returns, and designed with the help of a left or right outer join would solve the problem...

  Here is my SQL that works properly with 1 left outer join.  I build the slow query in the SQL following, you will see where I see the error.  I don't expect you to understand the data and the columns, I'm trying to join, I think the problems I encounter are related to syntax, and I hope that you can find where are my syntax errors.

  Select

  s.Name as "Pseudonym,"

  SV.view_name as "name of the view.

  s_view. Name

  Of

  s s_screen,

  s_screen_view sv

  outer join left s_view

  WE (sv.view_name = s_view.name)

  where

  SV.screen_id = ' 1-866 A - 1X3LU' and

  s.ROW_ID = sv.screen_id and

  s.repository_id = ' 866 A-1-1"and

  s_view.repository_id = ' A-1-1 866 ";

  Here is the SQL code where I encounter the following error...

  Error:

  ORA-00904: "SV". "" View_name ": invalid identifier

  00904, 00000 - '% s: invalid identifier '.

  * Cause:

  * Action:

  Error on line: column 14: 7

  Problematic SQL:

  Select

  s.Name as "Pseudonym,"

  SV.view_name as "name of the view.

  s_view. Name,

  s_applet. Name as Applet

  -b.SID like "name of the cmdlet.

  Of

  s s_screen,

  s_screen_view sv,

  wti s_view_wtmpl_it

  outer join left s_view

  WE (sv.view_name = s_view.name)

  outer join left s_applet

  WE (wti.name = s_applet.name)

  where

  SV.screen_id = ' 1-866 A - 1X3LU' and

  s.ROW_ID = sv.screen_id and

  s.repository_id = ' 866 A-1-1"and

  s_view.repository_id = ' A-1-1 866 ";

  Thanks in advance for your help.

  Chris

  > ORA-00904: "S_VIEW_WEB_TMPL." "" ROW_ID ": invalid identifier

  I don't see this table in your FROM clause.

• Problem with XMLTABLE and LEFT OUTER JOIN

  Hi all.
  
  I have a problem with XMLTABLE and LEFT OUTER JOIN, in 11g it returns the correct result, but in 10g it doesn't, it is illustrated as a INNER JOIN.
  

  SELECT * FROM v$version;
  
  Oracle Database 11g Enterprise Edition Release 11.2.0.1.0 - Production
  PL/SQL Release 11.2.0.1.0 - Production
  "CORE     11.2.0.1.0     Production"
  TNS for Linux: Version 11.2.0.1.0 - Production
  NLSRTL Version 11.2.0.1.0 - Production
  
  --test for 11g
  
  CREATE TABLE XML_TEST(
       ID NUMBER(2,0),
       XML XMLTYPE
  );
  
  INSERT INTO XML_TEST
  VALUES
  (
       1,
       XMLTYPE
       ('
            <msg>
                 <data>
                      <fields>
                           <id>g1</id>
                           <dat>data1</dat>
                      </fields>
                 </data>
            </msg>
       ')
  );
  
  INSERT INTO XML_TEST
  VALUES
  (
       2,
       XMLTYPE
       ('
            <msg>
                 <data>
                      <fields>
                           <id>g2</id>
                           <dat>data2</dat>
                      </fields>
                 </data>
            </msg>
       ')
  );
  
  INSERT INTO XML_TEST
  VALUES
  (
       3,
       XMLTYPE
       ('
            <msg>
                 <data>
                      <fields>
                           <id>g3</id>
                           <dat>data3</dat>
                      </fields>
                      <fields>
                           <id>g4</id>
                           <dat>data4</dat>
                      </fields>
                      <fields>
                           <dat>data5</dat>
                      </fields>
                 </data>
            </msg>
       ')
  );
  
  SELECT
       t.id,
       x.dat,
       y.seqno,
       y.id_real
  FROM
       xml_test t,
       XMLTABLE
       (
            '/msg/data/fields'
            passing t.xml
            columns
                 dat VARCHAR2(10) path 'dat',
                 id XMLTYPE path 'id'
       )x LEFT OUTER JOIN
       XMLTABLE
       (
            'id'
            passing x.id
            columns
                 seqno FOR ORDINALITY,
                 id_real VARCHAR2(30) PATH '.'
       )y ON 1=1
  ;
  
  ID     DAT     SEQNO     ID_REAL
  --     -----     -----     -------
  1     data1     1     g1
  2     data2     1     g2
  3     data3     1     g3
  3     data4     1     g4
  3     data5          

  This is all nice, now the problem:
  

  Oracle Database 10g Enterprise Edition Release 10.2.0.1.0 - 64bi
  PL/SQL Release 10.2.0.1.0 - Production
  "CORE     10.2.0.1.0     Production"
  TNS for HPUX: Version 10.2.0.1.0 - Production
  NLSRTL Version 10.2.0.1.0 - Production
  
  --exactly the same environment as 11g (tables and rows)
  SELECT
       t.id,
       x.dat,
       y.seqno,
       y.id_real
  FROM
       xml_test t,
       XMLTABLE
       (
            '/msg/data/fields'
            passing t.xml
            columns
                 dat VARCHAR2(10) path 'dat',
                 id XMLTYPE path 'id'
       )x LEFT OUTER JOIN
       XMLTABLE
       (
            'id'
            passing x.id
            columns
                 seqno FOR ORDINALITY,
                 id_real VARCHAR2(30) PATH '.'
       )y ON 1=1
  ;
  
  ID     DAT     SEQNO     ID_REAL
  --     -----     -----     -------
  1     data1     1     g1
  2     data2     1     g2
  3     data3     1     g3
  3     data4     1     g4

  As you can see in 10g that I don't have the last row, it seems that Oracle 10 g does not recognize the LEFT OUTER JOIN.
  
  Is this a bug?, Metalink says that sometimes we can have an ORA-0600, but in this case there is no error results returned, just incorrect.
  
  Help, please.
  
  Kind regards.

  What about try the original Oracle method for outer joins? Using (+) without the extra space

  XMLTABLE(...COLUMNS ... id XMLTYPE PATH ... ) x,
  XMLTABLE(... PASSING x.id ...) (+) y
  

• using (+) or left outer join

  Dear Expert;
  
  I've been playing by using the two symbol... and realized that they do the same thing... Is it true...? or am I wrong.
  
  Thank you.

  Hello

  user13328581 wrote:
  Dear Expert;

  I've been playing by using the two symbol... and realized that they do the same thing... Is it true...? or am I wrong.

  They all have two outer joins. The + rating was the original way to do it in Oracle. LEFT, RIGHT, and FULL OUTER JOIN introduced in Oracle 9, but the old way is still supported.

  There are some situations (such as an outer join complete and outer-join a table to two different tables) that are better with the ANSI syntax (it's LEFT OUTER JOIN). It is possible to get the same results using +, but it must be combersome and/or inefficient workarounds. I suggest that you use always LEFT OUTER JOIN (or FULL OUTER JOIN, or, on occasions RIGHT OUTER JOIN). I think that you will find it easier and less error-prone.

• LEFT OUTER JOIN, trigger after QUERY problem

  Hello
  
  Guide to please the following
  
  I wrote under query in QUERY after a BLOCK of TABULAR DATA, not as a single text element, called INVENTORY_ITEM
  
  Select c.cat |' '|| s.SubCat |' '|| L1.lvl1 POINT IN: DATABLOCK. INVENTORY_ITEM
  of itemcat c
  LEFT OUTER JOIN itemsubcat s on (c.catid = s.catid)
  LEFT OUTER JOIN lvl1 l1 on (s.subcatid = l1.subcatid)
  
  When I compile the module an error is generated
  
  «* ' Met the 'LEFT' symbol when waiting for one of the following values for the group with intersect less order start union where connect '.» *
  
  Top query works fine with ORACLE SQL DEVELOPER.
  
  Any solution please.
  
  Kind regards

  Difference

• LEFT OUTER JOIN SYNTAX?

  Connected to:
  Oracle Database 10g Enterprise Edition Release 10.2.0.4.0 - Production 64-bit
  With partitioning, OLAP, Data Mining and Real Application Testing options
  
  When I run:
  SELECT ACCF. SPECIMEN_ID as ACC_ID,
  ACCF. PREFIX,
  ACCF. SPECIMEN_NBR as ACC_NBR,
  RP. PHYSICIAN_ID as REFPHY_BUS_KEY,
  ACCF. SIGNOUTLOC,
  THE. Location_id as LAB_BUS_KEY,
  ACCF. COLLDATE as ACC_SPCMN_COLL_DT_ID,
  ACCF. ACDATE as ACC_CREATED_DT_ID,
  ACCF. SODATEORIG as ACC_ORIG_SIGNOUT_DT_ID,
  ACCF. SODATE as ACC_SIGNOUT_DT_ID
  OF ACC_FACT_WS ACCF.
  REFPHY_WS RP,
  THE LAB_WS
  WHERE ACCF. BLINK = RP. PHYSICIAN_ID
  AND ACCF. ACDATE > to_date('2010-06-17','YYYY-MM-DD')
  AND ACCF. PREFIX = A '
  AND ACCF. SIGNOUTLOC = (LOUISIANA). LOCATION_ID
  
  It works fine, but I really have an outer join on LAB_WS.
  When I run with an outer join, I get:
  SQL > SELECT ACCF. SPECIMEN_ID as ACC_ID,
  2 ACCF. PREFIX,
  3 ACCF. SPECIMEN_NBR as ACC_NBR,
  4. PR PHYSICIAN_ID as REFPHY_BUS_KEY,
  5 ACCF. SIGNOUTLOC,
  6. THE. Location_id as LAB_BUS_KEY,
  ACCF 7. COLLDATE as ACC_SPCMN_COLL_DT_ID,
  ACCF 8. ACDATE as ACC_CREATED_DT_ID,
  ACCF 9. SODATEORIG as ACC_ORIG_SIGNOUT_DT_ID,
  ACCF 10. SODATE as ACC_SIGNOUT_DT_ID
  11 ACC_FACT_WS ACCF,
  12 REFPHY_WS RP
  13 LEFT OUTER JOIN LAB_WS ON ACCF. SIGNOUTLOC = (LOUISIANA). LOCATION_ID
  14. WHERE ACCF. BLINK = RP. PHYSICIAN_ID
  15 AND ACCF. ACDATE > to_date('2010-06-17','YYYY-MM-DD')
  16 AND ACCF. PREFIX = A ';
  LEFT OUTER JOIN LAB_WS ON ACCF. SIGNOUTLOC = (LOUISIANA). LOCATION_ID
  *
  ERROR on line 13:
  ORA-00904: "ACCF. "" SIGNOUTLOC ": invalid identifier
  
  The previous query shows ACCF. SIGNOUTLOC is not the problem.
  What is the problem and how to fix it?
  Note: the syntax of the old outer join is not an option. The query will be finally 9 outer joins.
  
  Thank you
  Jon Jacobs

  Hello

  You are mixing syntax to join Oracle with ANSI, which is sometimes delicate.
  Best is to use a unique syntax, for example ANSI:

  ...
  FROM ACC_FACT_WS ACCF
       JOIN REFPHY_WS RP ON ACCF.CLIN = RP.PHYSICIAN_ID
       LEFT OUTER JOIN LAB_WS LA on ACCF.SIGNOUTLOC = LA.LOCATION_ID
  WHERE ACCF.ACDATE > to_date('2010-06-17','YYYY-MM-DD')
  AND ACCF.PREFIX = 'D'
  

• Left outer join on a derived Table

  Hello:
  
  I get an "ORA-00905: lack of keyword" error when I run the following query - don't know what I'm doing wrong here - any suggesstions will be very useful
  
  Thank you
  
  
  SELECT count (*)
  FROM aradmin.ast_asset a left outer join
  (
  Select audit_hist_asset, Deploy_Time
  of (a.asset_entry_id select audit_hist_asset, to_localtime (a.change_date, 'IS') Deploy_Time,)
  ROW_NUMBER() over (partition by order of a.change_date a.asset_entry_id) rn
  of aradmin.ast_bms_audit_history one
  where a.change_type = 'status '.
  and a.change_to = 'Deployed')
  where rn = 1
  ) AS b
  On a.asset_entry_id = b.audit_hist_asset

  Hello

  Good job on putting in shape! It is easier to read now.

  The error message included a line number? You use a.asset_entry_id in two different places, to refer to two different tables. Who is confused, but niot necessarily a mistake. You should use different tables for aradmin.ast_asset aliases in the main query and aradmin.ast_bms_audit_history in the internal subquery.

  Two of these tables have a column called asset_entry_id?

• Oracle: Use LEFT OUTER JOIN, but convert the data to an external list

  Hello, all,.

  I know it can be done; I just don't remember how I got it done, oh there are so many years.

  Assumes that the tables exist for groups and individuals.  People can belong to several groups.

  SELECT g.groupName, p.lastName || ', ' || p.firstName as fullName
  FROM groups g LEFT OUTER JOIN groupPersonAssociation gpa ON gpa.groupID = g.groupID
                LEFT OUTER JOIN person p ON p.personID = gpa.personID
  ORDER BY g.groupName, fullName
  

  This gives us:

  Group One          Alpha, Daniel
  Group One          Bravo, Charles
  Group One          Charlie, Chuck
  Group Two          Beta, Alpha
  Group Two          Delta, Bonnie
  Group Three        Echo, Bunny
  Group Three        Golf, Samuel
  Group Three        November, Stan
  

  How word the SQL to get the data as:

  Group One          Alpha, Daniel | Bravo, Charles | Charlie, Chuck
  Group Two          Beta, Alpha | Delta, Bonnie
  Group Three        Echo, Bunny | Golf, Samuel | November, Stan
  

  V/r,

  ^_^

  I finally thought to it.  I was using incorrect keywords on Google.

  SELECT g.groupName, LISTAGG(p.lastName || ', ' || p.firstName,' | ') WITHIN GROUP (ORDER BY g.groupName) "fullName"
  FROM groups g LEFT OUTER JOIN groupPersonAssociation gpa ON ggpa.groupID = g.groupID
                LEFT OUTER JOIN person p ON p.personID = gpa.personID
  GROUP BY g.groupName
  ORDER BY g.groupName, fullName  
  

  Just in case someone else is going through this same desire.

  HTH,

  ^_^

• doubt left outer join

  Hi all

  I use under version

  Connected to Oracle Database 11g Express Edition Release 11.2.0.2.0

  SQL > SELECT E.ENAME,.

  2 D.DEPTNO,

  3 D.LOC

  4. TO EMP E,.

  DEPT 5 D

  6. WHERE = E.DEPTNO D.DEPTNO (+);

  ENAME, DEPTNO LOC

  ---------- ------ -------------

  DALLAS SMITH 20

  ALLEN 30 CHICAGO

  WARD 30 CHICAGO

  20 DALLAS JONES

  MARTIN 30 CHICAGO

  BLAKE 30 CHICAGO

  CLARK 10 NEW YORK

  SCOTT 20 DALLAS

  THE 10 NEW YORK KING

  TURNER 30 CHICAGO

  20 DALLAS ADAMS

  JAMES 30 CHICAGO

  FORD 20 DALLAS

  MILLER 10 NEW YORK

  40 BOSTON

  15 selected lines

  -----------------------------------------------------------------------------------------------------------------------------

  SQL > SELECT E.ENAME,.

  2 D.DEPTNO,

  3 D.LOC

  4. TO EMP E

  5 LEFT OUTER JOIN

  D 6 DEPT

  7. THE E.DEPTNO = D.DEPTNO;

  ENAME, DEPTNO LOC

  ---------- ------ -------------

  MILLER 10 NEW YORK

  THE 10 NEW YORK KING

  CLARK 10 NEW YORK

  FORD 20 DALLAS

  20 DALLAS ADAMS

  SCOTT 20 DALLAS

  20 DALLAS JONES

  DALLAS SMITH 20

  JAMES 30 CHICAGO

  TURNER 30 CHICAGO

  BLAKE 30 CHICAGO

  MARTIN 30 CHICAGO

  WARD 30 CHICAGO

  ALLEN 30 CHICAGO

  14 selected lines

  My doubt is both are same query is the same, is in ansi format and is in the format of the Oracle,.

  but the results are different.

  For the first query null is coming for unmatched records in the dept table

  but in the second query, it does not come

  Thank you

  Hello

  2947022 wrote:

  Hi all

  I use under version

  Connected to Oracle Database 11g Express Edition Release 11.2.0.2.0

  SQL > SELECT E.ENAME,.

  2 D.DEPTNO,

  3 D.LOC

  4. TO EMP E,.

  DEPT 5 D

  6. WHERE = E.DEPTNO D.DEPTNO (+);

  ENAME, DEPTNO LOC

  ---------- ------ -------------

  DALLAS SMITH 20

  ALLEN 30 CHICAGO

  WARD 30 CHICAGO

  20 DALLAS JONES

  MARTIN 30 CHICAGO

  BLAKE 30 CHICAGO

  CLARK 10 NEW YORK

  SCOTT 20 DALLAS

  THE 10 NEW YORK KING

  TURNER 30 CHICAGO

  20 DALLAS ADAMS

  JAMES 30 CHICAGO

  FORD 20 DALLAS

  MILLER 10 NEW YORK

  40 BOSTON

  15 selected lines

  -----------------------------------------------------------------------------------------------------------------------------

  SQL > SELECT E.ENAME,.

  2 D.DEPTNO,

  3 D.LOC

  4. TO EMP E

  5 LEFT OUTER JOIN

  D 6 DEPT

  7. THE E.DEPTNO = D.DEPTNO;

  ENAME, DEPTNO LOC

  ---------- ------ -------------

  MILLER 10 NEW YORK

  THE 10 NEW YORK KING

  CLARK 10 NEW YORK

  FORD 20 DALLAS

  20 DALLAS ADAMS

  SCOTT 20 DALLAS

  20 DALLAS JONES

  DALLAS SMITH 20

  JAMES 30 CHICAGO

  TURNER 30 CHICAGO

  BLAKE 30 CHICAGO

  MARTIN 30 CHICAGO

  WARD 30 CHICAGO

  ALLEN 30 CHICAGO

  14 selected lines

  My doubt is both are same query is the same, is in ansi format and is in the format of the Oracle,.

  but the results are different.

  For the first query null is coming for unmatched records in the dept table

  but in the second query, it does not come

  Thank you

  In fact, these requests are not the same.

  The first is to find all the lines of the Department, with the corresponding lines of PGE (when there are).  This is equivalent to «FROM dept LEFT OUTER JOIN emp...» ».

  The second is to find all the rows in the emp of the lines of the Department (when there are any).  This is equivalent to «...» WHERE e.deptno = d.deptno (+).

• Bad result in a left outer join in 12.1.0.2

  Hallo,

  We discovered a strange behaviour in a query. The query provides values in a column of outer join where there is no corresponding value in the table is attached to the outside.

  When you expand this request by the "ORDER BY" then this query gives the correct result.

  Example:

  SQL > desc tb_a
  Name                                Null?    Typ
  -------------------------------------------- ----------------------------
  ID NOT NULL NUMBER (19)

  SQL > desc tb_b
  Name                                Null?    Typ
  -------------------------------------------- ----------------------------
  CLOSED NOT NULL NUMBER (1)
  ID NOT NULL NUMBER (19)

  CCS_APPLICATION@icw01> select * from tb_a where id in (4148,4141,4195);

  ID
  ----------
  4148
  4141
  4195

  CCS_APPLICATION@icw01> select * from tb_b where id in (4148,4141,4195);

  INTERNAL ID
  ---------- ----------
  4148 0

  CCS_APPLICATION@icw01> SELECT
  2      b.id                            AS b_id,
  3      a.id                            AS a_id,
  4 b.closed AS b_closed
  5
  6 tb_a a
  7 LEFT OUTER JOIN tb_b b ON a.id = b.id
  8 WHERE a.id IN (4148, 4195, 4141)
  9 ORDER BY ASC a.id
  10;

  B_ID ALLOCATION A_ID B_CLOSED
  ---------- ---------- ----------
  4141
  4148 4148 0
  4195

  CCS_APPLICATION@icw01> SELECT
  2      b.id                            AS b_id,
  3      a.id                            AS a_id,
  4 b.closed AS b_closed
  5
  6 tb_a a
  7 LEFT OUTER JOIN tb_b b ON a.id = b.id
  8 WHERE a.id IN (4148, 4195, 4141)
  9 - ORDER BY ASC a.id
  10;

  B_ID ALLOCATION A_ID B_CLOSED
  ---------- ---------- ----------
  4148 4148 0
  4141 4141
  4195 4195

  instance parameter:

  VALUE OF TYPE NAME

  ------------------------------------ ----------- ------------------------------

  compatible string 12.1.0.2.0

  optimizer_features_enable string 12.1.0.2

  After ""alter system set optimizer_features_enable = ' 11.2.0.4 ';"  the query provides the correct result in both cases (ordered and unordered).

  Now the final question: is this a bug?

  1480970 wrote:

  Hallo!  Yes, I searched the Support of Oracle. I found some similar entries, but not an exact match. To fix some issues

  with 12.1.0.2.

  There is another interesting clue when look you on the execution plan:

  Note

  -----

  -the dynamic statistics used: dynamic sampling (level = 2)

  - This is an adaptation plan

  We have disabled (= FALSE) optimizer_adaptive_features and the query provides the correct values.

  This could be a solution for us.

  Looks like a pretty tight match for bug 18430870, even if it affects the two 12.1.0.1 and 12.1.0.2, which contradicts the Martin trial against 12.1.0.1.

  The description of the bug mentions disabling "_projection_pushdown" (set to false) should also be a viable solution, perhaps if you want to give that a try and see if it is a different bug or not.

  There are also a number of one-time fixes already available for download, maybe your version / platform is already covered, if the bug applies.

  Randolf

• Left Outer Join DR.

  Hi Experts,

  I have a requirement that says - see the chart for the past 10 days, regardless the presence data table in fact.
  Lets consider an example - Time_dim product, are my dimension tables, Purchase_Order is my fact table.

  I did it for external Purchase_Order in left RPD with TIME_DIM and inner join with the PRODUCT table.  and execution of query of exit-
  Select T.Date, P.item, count (distinct PO.order_no)
  TIME_DIM t, PRODUCT P, PURCHASE_ORDER PO
  where T.date_key = PO.date_key
  and P.item = in. agenda
  and P.item = 'laptop ';

  The query generated by OBIEE left outer join, but when the condition P.item = "Notebook" included in the query, and if there are no orders for this product in one of the date, that date will not come in the result set.

  the query to be generated by the OBIEE is-

  
  Select T.Date, PO.item, count (distinct PO.order_no)
  TIME_DIM t,.
  (SELECT P.ITEM, IN. ORDER_NO
  PRODUCT P, PO PURCHASE_ORDER
  WHERE P.item = in. agenda
  and P.item = 'Laptop') IN.
  WHERE T.date_key = PO.date_key (+);

  How to design the RPD to achieve this. All pray to advise on this. Thanks in advance.

  Thank you
  Chantal

  Hello

  You are on 11.1.1.7?

  I would say that your condition can be made without using external and maintenance of product and the standard between the FACT dimension, time inner join join.

  If you enable your property analysis OBIEE "Include Null values" will automatically return all the elements of time and product matching your filter (so you'll need to add a filter on 'Date' to limit it to the last 10 days or you will have a unique day of your time dimension).

  If you filter then on "Laptop", even if there is not a single value in order for "Laptop" in the last 10 days, he will be there on the screen.

  Easy, clean and you keep your inner join between the facts and Dimensions.

  Take a look at this example, I just did on SampleApp 406:

  

  Selection of 12 months (year 2010) and a customer (id = 89) and income. The model has only an inner join. I activate the option "Include Null values" and here is the result.

  

  A line with cells only empty because there is not a single revenue for customer 89 in 2010. This is exactly your condition.

  Honestly, do not touch your model using the outer join, you will have more side effects than benefits. Every single scan will do the outer join and you'll have a lot of data 'empty' return of the DB (more large data set containing just the null values) and probably you need the outer join in 15 to 25% of your analysis.

  Keep things simple, it will be faster and easier to maintain.

• Modeling of the left outer join

  Hello world

  I'm tender hand to you guys for a modeling help

  I have a FACT, the customers, the Dim_Date and CUST_ADDRESS of tables to model

  Fact and the client are joined through CUST_ID

  FACT and DATE are joined through DATE_ID

  CUST_ADDRESS must be attached to the top of the model through CUST_ID, DATE_ID and this join must be Left outer because sometimes the address does not exist or is not current, which means DATE_ID could be different between Dim_Date and CUST_ADDRESS

  If it were to join internal, model would have been easy, because of the outside left that I am unable to model, it's pretty good.

  Application under
  Select D.DATE, C.CUST_NAME, CA. ADDRESS, F.AMOUNT
  Of
  F FACT
  JOIN THE
  CUSTOMER C
  ON C.CUST_ID = F.CUST_ID
  JOIN THE
  DIM_DATE D
  ON F.DATE_ID = D.DATE_ID
  LEFT OUTER JOIN
  CUST_ADDRESS CA
  ON C.CUST_ID = CA. CUST_ID AND C.DATE_ID = D.DATE_ID

  Thanks in advance

  When I add the CUSTOMER and in FACT LTS CUST_ADDRESS

  Stop it!

  Don't add CUSTOMER and CUST_ADDRESS in the FACT of LTS. Why would add you to the LTS DO?

  You design a management model: CUSTOMER is a dimension and it has its own logical table this logic table join with a logical join in the activity diagram. Ditto for CUST_ADDRESS.

  So the change, I missed earlier is CUST_ADDRESS contains no Cust_ID (ACTUALLY existing), but contains a Cust_NO, and the table to translate Cust_NO in Cust_ID is CUSTOMER?

  No problem...

  Let's start with a new alias of CUSTOMER (to keep more simple to understand at the moment), call as you want, but this new alias will be the link between the FACT and CUST_ADDRESS.

  In LTS of the dimension 'Address', you have CUST_ADDRESS initially, add an inner join on the new alias that you created in the LTS of the CUSTOMER. So now your 'Address' logical dimension contains the Cust_NO and Cust_ID and this will make the join to FACT.

  Between CUST_ADDRESS and the CLIENT, you can keep an inner join, because the target is not not for get the address of the customer, but is having the Cust_ID in the address line.

  Give it a try at that.

  But do not add these tables in the LTS, they are logical dimensions.

• Help for a LEFT OUTER JOIN query

  Hello, all,.

  I'm having some trouble setting up an Oracle 11 g Server SQL query, and I could use some help.

  Let's say tableA is blogs; tableC is comments for blog entries; tableB is the associative array:

  tableA
  blogID        blogTitle       blogBody      dateEntered
  1             This is a test  More text...  2016-05-20 11:11:11
  2             More testing    Still more!   2016-05-19 10:10:10
  3             Third charm!!   Blah, blah.   2016-05-18 09:09:09
  

  tableC
  commID        userID          userText      dateEntered
  10            Bravo           I like it!    2016-05-20 11:21:31
  11            Charlie         I don't!      2016-05-20 11:31:51
  12            Alpha           Do it again!  2016-05-19 10:20:30
  13            Bravo           Still more?   2016-05-19 10:30:50
  14            Charlie         So, what?     2016-05-19 10:35:45
  15            Bravo           Blah, what?   2016-05-18 09:10:11
  16            Alpha           Magic number! 2016-05-18 09:11:13
  

  tableB
  blogID        commID
  1             10
  1             11
  1             12
  2             13
  2             14
  3             15
  3             16
  
  
  
  

  I'm trying to get blogID, blogTitle, blogBody and the number of comments for each blog entry.  But, since I'm on to_char() for date and COUNT (commID) for the total number of comments, I am not "a group by expression.

  Here is an example of pseudo-SQL of what I'm trying.

  SELECT a.blogID, a.blogTitle, a.blogBody, to_char(a.dateEntered,'YYYY-MM-DD HH24:MI:SS') as dateEntered, COUNT(c.commID) as total
  FROM tableA a LEFT OUTER JOIN tableB b ON b.blog_ID = a.blog_ID
                LEFT OUTER JOIN tableC c ON c.commID = b.commID
  WHERE a.blogID = '1'
  GROUP BY blogID, blogTitle, blogBody
  ORDER BY to_date(dateEntered,'MM-DD-YYYY HH24:MI:SS') desc
  

  I'm sure it's something simple, but I just DO NOT see it.  Can you help me?

  V/r,

  ^_^

  Try:

  GROUP BY a.blogID, a.blogTitle, a.blogBody, to_char(a.dateEntered,'YYYY-MM-DD HH24:MI:SS')
  

  See you soon

  Eddie