less union set operators

Similar Questions

• How to use SET operators?

  I am a student in learning ORACLE and just, we covered the SET operators (UNION, UNION ALL, LESS, LESS ALL, INTERSECT). I'm having a very hard time to understand how to use them. We are id list of supervisors of all employees who are not managers of grocery store. Tables:
  
  Table Employee (ID = SUPERVISOR_ID)
  -------------
  ID
  STORE_NUMBER
  TITLE (the store manager is one of them)
  EMPLOYEE
  
  Store table
  ----------------
  STORE_NUMBER
  MANAGER_ID
  
  
  How to do this using a game operator? Can someone help me please?
  
  Thank you

  SELECT id, store_number from employee_table
  less
  Select manager_id, store_number store_table

  http://LRC.surcollege.NET/eBooks/Arabic_Books/Oracle/books/introduction%20To%20Oracle9i_SQL-instructor%20Guide%20Volume%202.PDF
  Part 15

  Published by: Adigozalov Qurban 5 December 2010 23:16

  Published by: Adigozalov Qurban 5 December 2010 23:17

• Reg: Without SET operators

  All,

  How to find the nums, which contains the onum 'x' and 'y' and 'z' (three in combination).

  WITH t1 AS

  (SELECT 1 nums, 'x' double onum

  UNION

  SELECT 1 nums 'y' onum dual FROM

  UNION

  SELECT 1 nums, 'z' onum FROM dual

  UNION

  SELECT 2 nums, 'x' double onum

  UNION

  SELECT 2 nums, 'z' onum FROM dual

  UNION

  SELECT 2 nums, 'a' onum dual FROM

  )

  SELECT * FROM t1;

  I wrote this below one. Another way without using the set operators.

  Nums SELECT FROM t1 WHERE onum = 'x '.

  INTERSECT

  Nums SELECT FROM t1 WHERE onum = 'y '.

  INTERSECT

  Nums SELECT FROM t1 WHERE onum = "z";

  Thank you

  Why not use the value operators?

  In any case, try:

  Select the nums

  from t1

  where onum in ('x', 'y', 'z')

  having count (*) = 3

  Group of nums;

  Note: it depends on here are not duplicated nes/onums - it is not the same

  What to do with crosses, he gives the same answer with your data set.

  Or as others have said

  Select the nums

  from t1

  where onum in ('x', 'y', 'z')

  having count (distinct onum) = 3

  Group of nums;

  (missed that one!)

  Post edited by: Paul Horth

• Using Clob in the Union query

  Hello everyone, have a look at the statements below and let me know what wrong with my approach.

  CREATE TABLE test
  (column1 CLOB);
  
  
  INSERT INTO test 
  SELECT to_clob('This is test') FROM dual;
  

  When I run the query below, I get data types incompatible error (ORA-00932). Help, please.

  SELECT to_clob('This is test two') FROM dual 
  UNION
  SELECT column1 FROM test;
  

  Kind regards

  Shiva.

  Hey Shiva,

  Copied from documentation

  http://docs.Oracle.com/CD/B19306_01/server.102/b14200/queries004.htm

  Restrictions on operators define the set operators are subject to the following restrictions:

  • Set operators are not valid on columns of type BLOB , CLOB , BFILE , VARRAY , or a nested table.
  • The UNION , INTERSECT , and MINUS operators are not valid on LONG columns.
  • If the selection list prior the operator set contains an expression, you must provide an alias for the expression column to refer in the order_by_clause .
  • You cannot specify also the for_update_clause with the set operators.
  • You cannot specify the order_by_clause in the subquery of these operators.
  • You cannot use these operators in SELECT statements containing the TABLE expressions collection.

• Select with LESS vs two VARRAYS with MULTISET

  Hi all
  
  I just wanted to know, which one of the two following is faster and results in better performance.
  
  1. SELECT statement containing 200 + columns in a Table with operator LESS. (TWO SELECTS with operator between them LESS)
  
  2. loading of the individual SELECT statement (with some LESS) result sets in two different VARRAYS and then use these two operators of type MULTISET.
  
  That one is faster and uses less memeory?
  
  Thank you
  REDA

  Direct SQL is still fast compared to the PLSQL. When you use varrays, there will be change of context. Even if you use Bulk collect for loading data yu have to put a limit of 1000 and not beyond.

• Order by in the Union

  Hi all
  
  If we do not specify the order of the UNION/UNION ALL clause then what is the default order of data
  
  Select Stmnt1
  UNION
  Select Stmnt2
  
  
  
  Select Stmnt1
  UNION ALL
  Select Stmnt2
  
  I use the version 10G AND 11 G
  
  Thank you

  Hi Smidreb,

  According to the oracle docs (so you can test also),

  You cannot specify the order_by_clause in the subquery of the SET operators (IE in your UNION/UNION ALL cases).

  So if your question

  select col1,col2... from t1 order by col1
  union
  select col1,col2... from t2 order by col1
  

  OR

  select col1,col2... from t1 order by col1
  union ALL
  select col1,col2... from t2 order by col1
  

  The two queries above will give errors. So that something of not authorized by Oracle. If you think a bit you will come to know why it is so.

  But even if you need ordered result, you can achieve as below (drafting of an outer query):

  Select * from (
  select col1,col2... from t1
  union/UNION ALL
  select col1,col2... from t2
  )
   order by col1;
  

  Come to your original question, what will happen if you do not specify order by?
  Now you know u cann't apply the order of. Also, you know how u can apply, if you wish.

  Also without a prescription by Oracle does not guarantee any order--> FACT.

  Now, the answer is obvious.

  Published by: J2EE_Life on January 28, 2012 08:48

  Published by: J2EE_Life on January 28, 2012 08:49

• Operator fixed LESS

  Hello
  
  I was looking through the examples of the manual and found this an odd individual:
  

  Example 19–16 Set Operators: MINUS Query
  <query id="q1BBAQuery"><![CDATA[
  R1 MINUS R2
  ]]></query>
  Example 19–17 Set Operators: MINUS Relation Input R1
  Timestamp Tuple Kind Tuple
  1500: + 10,40
  2000: + 10,30
  2000: - 10,40
  3000: - 10,30
  Example 19–18 Set Operators: MINUS Relation Input R2
  Timestamp Tuple Kind Tuple
  1000: + 11,20
  2000: + 10,40
  3000: - 10,30
  Example 19–19 Set Operators: MINUS Relation Output
  Timestamp Tuple Kind Tuple
  1000: + 10,40.0
  2000: - 10,40.0

  Why is the tuple inserted 10.40 to 1000? It's LESS the difference when R2 (t) is subtracted from the R1 (t)?

  This seems to be a bug in documentation.

  Output for the above query should be:
  1500: + 10,40.0
  2000: + 10,30.0
  2000:-10,40.0

  Thank you best regards &,.
  Sandeep

  Published by: Sandeep Bishnoi on April 1st, 2011 17:58

• jQuery more/less doesn't work do not

  http://digitaldealershipsystem.com/news-test.html

  I tried a lot of alternatives. I'm trying to have a more or less the button next to the text to display the paragraph which is hidden.

  Currently I have a 'show' command that is not practical in the scripts. (seen here: ) http://digitaldealershipsystem.com/news.html )

  Here is what I use:

  $(function() {})

  The height of the block content when it is not developed

  var adjustheight = 80;

  The text of the link 'more '.

  moreText var = '+ more ';

  The link text "less."

  var lessText = "-less";

  Sets the div. plus-bloc to the specified height and mask any content that overflows

  $(".more-less.more-block") .css ('height', adjustheight) .css ('overflow', 'hidden');

  The section added at the bottom of the div "more less".

  $(".more-less").append ("< class p =" continue"> [& hellip;] < /p > < a href =" # "class ="adjust"> < / has > ');

  $("a.adjust").text (moreText);

  {$(".adjust").toggle (function ()}

  $(this).parents("div:first").find (". plus-block").css('height',_'auto').css ("overflow", "visible");

  Hide the [...] when it is developed

  $(this).parents("div:first").find ("p.continued") .css ('display', 'none');

  $(this) .text (lessText);

  }, function() {}

  $(this).parents("div:first").find (". plus-block").css('height',_adjustheight).css ('overflow', 'hidden');

  $(this).parents("div:first").find ("p.continued") .css ('display', 'block');

  $(this) .text (moreText);

  });

  });

  And then in the HTML example

  Digital Concierge service < /p >

  < div id = "container" > < div class = "more less" >

  < p > your Concierge happened < /p >

  " < p > WEST PALM BEACH, FL. Service and experience customer is a top priority for the < a href =" http://digitaldealershipsystem.com/ "> digital concession system < /a >." This month, the company is improving it is offering based on the customer feedback by adding a Digital Concierge Service to the product line. < /p >

  < div class = "plus-block" >

  < p > DDSConcierge offer a solution for customers who want to have their screen maintained and updated, without having to access the software. This service updates the screens with sales,

  You can see in the source view.

  Thank you.

  You have links in your page for the .js files that are blocked by my firewall of the company...

  This will happen to other spectators of yours as well.

  You can download a copy of the files that these links are intended to point to your pages a link to the local version, then download them. If these files are never moved or renamed, you will lose them and the parts of your site that use them will stop working.

  I don't know if they have something to do with your current number, but it's something to think about.

• Help: Search record set where the value is not between adjacent records

  I need to find a record of database. I find it too complex for my current knowledge of SQL. Please help, thanks.
  

  --set 1
      select 1 id, 1 a, 2 e from dual union
      select 1 id, 2 a, 3 e from dual union
      select 1 id, 5 a, 6 e from dual union
      select 1 id, 6 a, 7 e from dual union
      select 1 id, 9 a, 10 e from dual union
  
  --set 2
      select 2 id, 1 a, 3 e from dual union
      select 2 id, 2 a, 3 e from dual union
      select 2 id, 3 a, 4 e from dual union
      select 2 id, 6 a, 7 e from dual union
      select 2 id, 9 a, 10 e from dual 

  input: output:
  1 norec
  2 norec
  3 norec
  4 id = 1
  5 id = 2
  8 id = 1 id = 2

  Maybe that's what you want

  Use your parameter instead of numbers.

  SQL> CREATE TABLE test1 AS  SELECT 1 ID, 1 A, 2 E FROM dual UNION
    2      SELECT 1 ID, 2 A, 3 E FROM dual UNION
    3      SELECT 1 ID, 5 A, 6 E FROM dual UNION
    4      SELECT 1 ID, 6 A, 7 E FROM dual UNION
    5      SELECT 1 ID, 9 A, 10 E FROM dual UNION
    6      SELECT 2 ID, 1 A, 3 E FROM dual UNION
    7      SELECT 2 ID, 2 A, 3 E FROM dual UNION
    8      SELECT 2 ID, 3 A, 4 E FROM dual UNION
    9      SELECT 2 ID, 6 A, 7 E FROM dual UNION
   10      SELECT 2 ID, 9 A, 10 E FROM dual;
  
  Table created.
  
  SQL>
  SQL> SELECT DISTINCT ID
    2    FROM test1 t1
    3   WHERE NOT EXISTS
    4            (SELECT ID
    5               FROM test1 t2
    6              WHERE     1 <= E
    7                    AND 1 >= A
    8                    AND t1.ID = t2.ID);
  
  no rows selected
  
  SQL>
  SQL> SELECT DISTINCT ID
    2    FROM test1 t1
    3   WHERE NOT EXISTS
    4            (SELECT ID
    5               FROM test1 t2
    6              WHERE     4 <= E
    7                    AND 4 >= A
    8                    AND t1.ID = t2.ID);
  
          ID
  ----------
           1
  
  SQL>
  SQL> SELECT DISTINCT ID
    2    FROM test1 t1
    3   WHERE NOT EXISTS
    4            (SELECT ID
    5               FROM test1 t2
    6              WHERE     8 <= E
    7                    AND 8 >= A
    8                    AND t1.ID = t2.ID);
  
          ID
  ----------
           1
           2
  
  SQL> 
  

  If you would like your reesults in the same line then

  SQL> SELECT LTRIM (MAX (SYS_CONNECT_BY_PATH (str, ',')), ',') result
    2    FROM (SELECT DISTINCT ID,'id='||ID str, ROWNUM rn
    3            FROM test1 t1
    4           WHERE NOT EXISTS
    5                    (SELECT ID
    6                       FROM test1 t2
    7                      WHERE     8 <= E AND 8 >= A AND t1.ID = t2.ID) ORDER BY ID)
    8  START WITH rn = 1
    9  CONNECT BY PRIOR ID < ID;
  
  RESULT
  ---------------------------------------------------------------------------------------
  id=1,id=2
  
  SQL> 
  

  G.

  Published by: Ganesh aboumagahrif on March 21, 2011 12:18 AM

• Interesting question of sql 2

  Hi all

  I want to compare the data of the current column to another column of data, but for all values.

  Version: 11g

  with

  a as (

  Select 1 col1, 5 col2 from dual

  Union all

  Select 2, 10 from dual

  Union all

  Select 3, 15 from dual

  Union all

  Select 4, 20 from dual

  Union all

  Select 5, 25 from dual

  Union all

  Select 6, 30 from dual

  Union all

  Select 7, 35 from dual

  Union all

  Select 8, 40 from dual

  Union all

  Select 9, 45 from dual

  Union all

  Select 10, 50 from dual

  Select * from a;

  For example, I want to compare for each given col2 to all data in col1. I want to create a new column and if col1 contains 5 then he should write Yes, another no. If col1 contains 10 then yes other no. So for the example above, the output should be as below.

  1    5   Yes

  2    10   Yes

  3    15   No

  4    20   No

  5    25   No

  6    30   No

  7    35   No

  8    40   No

  9    45   No

  10    50   No

  Thank you

  Hello

  I suggest EXISTS, as Rahul showed in response #7.  To get the exact results you requested, use it like this:

  SELECT a.*

  CASE

  WHEN THERE IS)

  SELECT 1

  Of an a2

  WHERE a2.col1 = a.col2

  )

  THEN '' Yes. ''

  ANOTHER 'no '.

  Flag of the END as the

  A

  ORDER BY col1

  ;

  You can use a subquery IN rather than an EXISTS subquery, like this:

  SELECT a.*

  CASE

  WHEN IN col2 ( )

  SELECT col1

  A

  )

  THEN '' Yes. ''

  ANOTHER 'no '.

  Flag of the END as the

  A

  ORDER BY col1

  ;

  An outer join, as suggested in the response to #4, Nimish is good, too, but if col1 is not unique, you may need to use SELECT DISTINCT (depending on your needs) which will be ineffective.  Solutions using the set operators UNION or LESS will be as ineffective.

  3018678 wrote:

  Is there a solution with the analytical functions windowing or something like that?

  Yes, but it's inefficient and complex.  If you really want to try this, see:Re: getting the value of a column based on another column

  Why do you want to use an analytical function?   What is the problem with solutions already posted?

• Surprised!

  Hi all

  I'm just surprised with this...

  Select deptno from scott.emp deptno order;

  DEPTNO

  --------

  10

  10

  10

  20

  20

  20

  20

  20

  30

  30

  30

  30

  30

  30

  14 ranks...

  Select distinct deptno from scott.emp deptno order;

  DEPTNO

  --------

  10

  20

  30

  3 rows...

  Select deptno from scott.emp

  Union

  Select 1 double;

  DEPTNO

  --------

  1

  10

  20

  30

  4 rows...

  Select deptno from scott.emp

  Union

  Select deptno from scott.emp

  DEPTNO

  --------

  10

  20

  30

  3 rows...

  I know that Union will limit the duplicates, but I've never thought like that...

  all set operators (allow UNION ALL) return only distinct values. I think that it is in accordance with the definition of the sets in mathematics: "a set is a collection of distinct objects" - set (mathematics) - Wikipedia, the free encyclopedia.

• How can I get output to join two queries

  Hi guru,.

  I have a requirement like this

  Select query3.empname

  Of

  (

  (select col1, col2 from emp) query1

  full outer join

  (select col1, col2 from emp1) query1

  ) query3

  Hello

  ODI_NewUser wrote:

  Hi guru,.

  I have a requirement like this

  Select query3.empname

  Of

  (

  (select col1, col2 from emp) query1

  full outer join

  (select col1, col2 from emp1) query1

  ) query3

  What is the requirement?

  What you posted is an attempt to meet a requirement, but if this is the right way or not, it is not the condition.  A response is not the same as a question.

  Whenever you have a question, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) for all of the tables involved and the results desired from these data.
  Explain, using specific examples, how you get these results from these data.
  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: https://forums.oracle.com/message/9362002#9362002

  FULL OUTER JOIN is never the only way to get any results.  Sometimes, it's the best way, but sometimes there are other means that are simpler and more effective.  The set operators, such as the UNION (as suggested earlier) sometimes are a better solution.

• Connection to SQL rules

  Hello

  Simple question, I managed to use SQL together with rules in Essbase file, but given that you are forced to

  SELECT < code here > < code here > WHERE < code here >

  Is anyway to order data, as this can be critical with metadata?

  Is anyway use UNION / UNION ALL / UNMIS etc, set operators in short?

  Thanks for your comments,

  Robert.

  Robert,

  You can place the select statement together in the first box (chic), just don't forget to remove the word "select" from your query. You can put in the group, of the order by, union, etc. without problem.  Just make sure you don't have anything in the other two boxes (to where).

• Query components are in the order

  The query results cannot be guaranteed without one would ORDER BY. What happens if the query contains several application components. Although the spare parts request return unordered records, are the parties themselves in order?

  SELECT 'First' IN UNION double all THE

  SELECT 'Second' FROM Dual;

  Is guaranteed second come second?

  BrianTkatch wrote:

  Solomon, is a good example.

  However, in both cases, the t2 were returned after t1. The only thing that changed was the order within the query part itself.

  Can you show a case where this is not the case?

  I mustn't. Just check set operators: set operators combine the results of two queries of component in one result - not to mention what component query results go first. Same topic:

  UNION ALL

  All of the rows selected by a query including all duplicates

  Once again, no metioning order. So if today Oracle returns the results of the first query first, we cannot count on it. Oracle is free to change in future versions.

  SY.

• Rewrite the query with joins, and group by

  Hello
  
  It's an interview question.
  
  Table names: bookshelf_checkout
  virtual library
  
  And the join condition between these two tables is title
  
  We need to rewrite under request without using the join condition and group by clause?
  
  

  SELECT b.title,max(bc.returned_date - bc.checkout_date) "Most Days Out"
             FROM bookshelf_checkout bc,bookshelf b
             WHERE bc.title(+)=b.title
             GROUP BY b.title;

  When I was in College, I read most of SELECT statements can be replaced by operations base SQL (DEFINE the OPERATORS). Now, I am rewriting the query with SET operators, but not able to get the exact result.
  
  Kindly help me on this.
  
  Thank you
  Suri

  Something like that?

    1  WITH books AS (
    2  SELECT 'title 1' title FROM dual UNION ALL
    3  SELECT 'title 2' FROM dual UNION ALL
    4  SELECT 'title 3' FROM dual ),
    5  bookshelf AS (
    6  SELECT 'title 1' title, DATE '2012-05-01' checkout_date, DATE '2012-05-15' returned_date FROM dual UNION ALL
    7  SELECT 'title 1' title, DATE '2012-05-16' checkout_date, DATE '2012-05-20' returned_date FROM dual UNION ALL
    8  SELECT 'title 2' title, DATE '2012-04-01' checkout_date, DATE '2012-05-15' returned_date FROM dual )
    9  SELECT bs.title, MAX(bs.returned_date - bs.checkout_date) OVER (PARTITION BY title) FROM bookshelf bs
   10  UNION
   11  (SELECT b.title, NULL FROM books b
   12  MINUS
   13* SELECT bs.title, NULL FROM bookshelf bs)
  SQL> /
  
  TITLE   MAX(BS.RETURNED_DATE-BS.CHECKOUT_DATE)OVER(PARTITIONBYTITLE)
  ------- ------------------------------------------------------------
  title 1                                                           14
  title 2                                                           44
  title 3
  

  Lukasz