Reg: Without SET operators

All,

How to find the nums, which contains the onum 'x' and 'y' and 'z' (three in combination).

WITH t1 AS

(SELECT 1 nums, 'x' double onum

UNION

SELECT 1 nums 'y' onum dual FROM

UNION

SELECT 1 nums, 'z' onum FROM dual

UNION

SELECT 2 nums, 'x' double onum

UNION

SELECT 2 nums, 'z' onum FROM dual

UNION

SELECT 2 nums, 'a' onum dual FROM

)

SELECT * FROM t1;

I wrote this below one. Another way without using the set operators.

Nums SELECT FROM t1 WHERE onum = 'x '.

INTERSECT

Nums SELECT FROM t1 WHERE onum = 'y '.

INTERSECT

Nums SELECT FROM t1 WHERE onum = "z";

Thank you

Why not use the value operators?

In any case, try:

Select the nums

from t1

where onum in ('x', 'y', 'z')

having count (*) = 3

Group of nums;

Note: it depends on here are not duplicated nes/onums - it is not the same

What to do with crosses, he gives the same answer with your data set.

Or as others have said

Select the nums

from t1

where onum in ('x', 'y', 'z')

having count (distinct onum) = 3

Group of nums;

(missed that one!)

Post edited by: Paul Horth

Tags: Database

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