List drop-down list of reading value

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• Drop-down selection w/export value sent to another field.

  Good afternoon

  I managed to create a drop-down menu field called Dropdown1 with a list of user names. Each user name has a value of unique export assigned to them.

  I then created a second text called Text1 field where the value of exports is complete. In this area, I've added the following script Adobe to send the value of exports of Dropdown1 successfully to Text1

  Event.Value = this.getField("Dropdown1").value;

  However, I need allow the user to make manual changes to both Dropdown1 and Text1 without the script of the substitution of manual entry. Is there a solution?

  Thank you!

  Ed

  I guess that's a custom calculation script. I think a better approach is to set the value of the text field when the user makes a selection in the drop-down list by using a script customized to the key sequence in the dropdown menu, something like:

  Custom keystroke for drop-down list script

  If (! event.willCommit) {}

  getField("Text1").value = event.changeEx;

  }

  Don't forget to delete the calculation script if you do this. In addition, it is best that you also set the option "Commit selected value immediately" for the drop-down list.

• Drop-down Option menu: first value

  In the drop-down list option.
  
  status: new entry finished, cancel, assets.
  
  These option in the User Interface.
  
  My doubt is,
  
  If you need of new ways - ' (initial values)
  
  Entry is complete - need - 'E' (initial values)
  
  Cancel - 'C' (initial values)
  
  Enabled - 'A' (initial values).
  
  
  These (initial values) are only stored in the database.
  
  I tried a lot of things. But cant he finished. Please someone help to complete.

  see you said you use a fixed list.

  Why don't create you your own list instead of drag drop an attribute of the data control and create fixed list. (In your case all that you specify is taken as the value label not is why you are getting New)

  You can get to select a choice of component palette item and then select Create list here you can specify item label and the value of the element.
  where your label is New, and the value will be n.

  then all the click submit you get this value and perform an operation. (can be updated in db)

  There are other options as well to create LOV if you do not want to hardcode the page, you can create a separate class and assign values y for your LOV.

  Published by: Nikhil Gokhale July 13, 2011 15:12

• Change the background color on a menu drop down based on the value

  Hello

  I am new to LiveCycle Designer and I need a little help.

  I try to make a ComboBox with 3 options (lets say in January, February and March). When I selected one of these options, I want the bottom to automatically change (say January in yellow, for February in red and blue March).

  Your help will be much appreciated,

  Adrian

  Hi Adrien,.

  I suspect that the form is not set to automatically save changes to script. If you go to file > form properties > default tab and select Auto in the option buttons:

  

  That seems to work here.

  Niall

• List drop-down list box action

  Hi all

  I am new to create my own forms, so I hope you can help me.

  I work for a University and is trying to create an application form for students to put their notes.  I have 2 boxes in the following order, 1 which is a fill in the box with a number of units (Units.0), and the other is a drop-down list with grades (Grade.0).  The drop also has options to select 'in progress', "Credit of AP" and "N/a".  If one of these choices of non-quality is selected, I want to delete the contents of the box of units and make it white.  Can someone please help me to set up on my form?

  Thank you!!!

  Use this code in the script of custom validation of your notes menu drop-down:

  If (event.value == "In progress" | event.value == "AP credit" |)

  Event.Value is "S/o")

  getField("Units.0").value = "";

• Can not get a text field to atuo fill based on a drop-down list selection

  I have a drop down box with 3 values that can be selected:

  Dropdown2 is 101-3 subd. A

  101-3 subd. B

  101-3 subd. C

  I'm trying to get a field of text automatically fill based on selection:

  If Dropdown2 = 101-3 subd. A Text4 then = 'a. '.

  If Dropdown2 = 101-3 subd. B then Text4 = 'b. '.

  If Dropdown2 = 101-3 subd. C then Text4 = 'ValueC.

  I tried to create a custom for Text4 calculation script:

  var v = getfiled("Dropdown2").value;

  If (v = "subd 101-3. A") event.value ="A."

  ElseIf (v = "subd 101-3. B") event.value ="B."

  ElseIf (v = "subd 101-3. C') event.value = "ValueC."

  else event.value = "";

  I walked into this script and syntax seems to be OK. (At least for Acrobat XI.  I'm not know programmer and have just enough knowledge to be dangerous).  When I select a value in Dropdown2 nothing happens.  No value appears in Text4.  I checked the "selected value immediately commit" in the Dropdown2 option by google'ing.  I don't understand why the values do not appear.  Any help would be appreciated.

  Thank you

  You made a mistake... The comparison operator is "is" (or ' = '), not of '=', which is used to assign a value.

  So replace all these:

  If (v = "subd 101-3. A")

  To do this:

  If (v is "subd 101-3. A")

• Fill a drop down another drop down.

  Hello...

  I have a drop down hidden field whose values are filled for a response from the web service.

  I need to fill another drop down according to these values.

  Just need some advice in the following script...

  DD1-> Drop Down list 1 and DD2-> downgrade Drop 2

  var number = DD1.length;

  for (var i = 0; i < count; i ++)

  {

  xfa.resolveNode (". IN_TAB DATA [" this.parent.index ' "] '"). DD2. AddItem (DD1.items [i] .value);

  }

  The part

  DD1. Items [i] .value

  does not work... How to access a menu drop down based on index value? I tried various combinations but have not found a good solution... Can I use a picture instead? I know I'm missing out on something really stupid

  Any help would be appreciated...

  Hello

  First you resolved the node as Acrobat/Reader will work with objects in the same container.

  The property you are looking for is "getDisplayItem":

  var nItems = DD1.length; 
  
  for (var i=0; i
  Take a look at this example: http://assure.ly/jcTahK. Look at the example of environment.
  Hope that helps,
  Niall
  PS: This script is located in the DD2 preOpen event.
  		   

• Drop-down box and a dynamic presence

  I hope this makes sense.

  I have a drop down box with multiple values inside. Based on the user's selection, subforms and the different areas will be visible or hidden. To do this, I built a switch statement on the output of the dropdown event. The statement works fine until I have start to introduce dynamic properties to one of the subforms.

  Two of a repeating subform fields should be hidden or has visible again according to the choice in the drop-down list. However, once you have added multiple instances of the subform, it only mask/displays the FIRST field in the subform. I need to hide/display-ALL fields when the subform is repeated.

  To do this in the first selection, I created a statement through all instances and all these fields to be hidden or visible value as required. However, it does not work. Not at all. Even in the first instance as before.

  I hope I'm making sense. Here is the code that I use for my statement:

  var indNum = xfa.resolveNodes("RequestDetails.RepeatingSection[*].serialNum");
  for (var i=0; i < indNum.length; i++) {
      xfa.form.form1.Page1.RequestDetails.RepeatingSection(i).serialNum.presence = "visible";
      xfa.form.form1.Page1.RequestDetails.RepeatingSection(i).requestedNum.presence = "hidden";
  }
  

  Then, I realized most myself. Even if EVERY bit of documentation I see says reference fields like this:

  xfa.resolveNode("OuterSubform.InnerRepeatingSubform[i]");
  

  I found that he doesn't know what to do with the media, so I have:

  .InnerRepeatingSubform["+i+"]");
  

  So my final code ended up looking like this:

  var indNum = xfa.form.form1.Page1.RequestDetails.RepeatingSection.instanceManager.count;
  for (var i=0; i < indNum; i++) {
      xfa.resolveNode("RequestDetails.RepeatingSection["+i+"]").serialNum.presence = "hidden";
      xfa.resolveNode("RequestDetails.RepeatingSection["+i+"]").requestedNum.presence = "hidden";
  }
  

  I still have a problem, however. If I already added the subforms and then select the option drop-down list, it works great! However, if I select a menu item drop-down, THEN add lines, added lines have visible fields I would like to stay hidden. Is it possible that I can call the case statement when clicking on a button? Or I have to put in another switch or if the declaration on the buttons? I think it would be easier if I could just remember the swtich on the drop statement. Unfortuantely, I don't know how to do this.

• Drop Down Menu parameters (width / width uniform)

  Is it possible to have my menu main level adjust the width of the value while my drop down portion is the value of uniform width?

  I want to have my main navigation bar, put in place where all elements are centered in their block.  The terms "Home" and "Empty train" are very different in size, so adjust the width is needed.  However, all my submenu items seem horrible to be centered.  Is there a way to align left them with uniform width for this part of the menu only?

  In addition, Muse seems to have a horrible time, try to change the menu with a large site.  Maybe it's something that can be solved.

  Hey,.

  If you need to download articles in the menu, follow the steps in my screenshot and if it comes to put links up on the page to take a look at this FAQ here.

  See you soon,.

  Cristian

• Try to change the menu drop-down

  I created a form that uses a lot of drop-down menus and trying to get the menu drop-down see the descriptions and have actually filled area with a number of coin instead of the description. I am not against XML encoding if necessary I am new to it but played around a little bit. Ideas or direction would be greatly appreciated thanks.

  Yes. To descriptions in the menu drop down and then specify values in the binding tab. In the event for the menu output drop-down put the code (in formcalc):

  If ($.rawValue == 1) then

  $.formattedValue = "109323" / / put all part number is here

  ElseIf ($.rawValue == 2) then

  $.formattedValue = "109324" / / etc

  endif

  the rawValue is the value of the option, the person has chosen in the menu and the formattedValue is what the box displays the exit event has run.

• Load default setting drop Downs

  Hello

  I have two drop downs.  The second is filled (via a table) based on the choice of the first descent down.  What I would do, is that when the first drop down menu is selected, the second drop-down displays a default value that the user can change if they want one of the other choices.

  It's a job application form that I create, must drop two downs to describe the work and these choices then fill the cost. When they do not use the second fall down the cost does not appear and it seems that it's free!  Not what I want.

  Any help would be greatly appreciated

  You can set the selectedIndex property to display the default after loading the second dropdown.

  DropDownList2.selectedIndex = '0 '.

  Index starts at 0 for the listitems. For example, you can set the selectedIndex property to the index of the default value.

  Thank you

  Srini

• Remove the default value drop-down list

  I am currently working with Acrobat Pro XI version. I want to know if it is possible to remove the default value in a drop-down list.

  When the list less than 4 elements, it is possible to deselect the default value by pressing the spaces below. However, when there are no more elements, it is more possible.

  I read that you need to include white space as a component in the list of elements, however, then you will see an empty list item when people work with the pdf that is not preferable.

  So, nobody how to remove the default value in a drop-down list?

  Thank you!

  OK, I found a perfect solution to my problem by using FormsCentral for Acrobat. Here's what you need to do:

  Step 1:

  -Open FormsCentral

  -Create new form (choose the blank form)

  -Click the drop-down menu to create a new drop-down list

  -Fill out the items in the list by clicking on the timeline (you can also add a label if you want)

  -Click on: file > save as PDF form...

  Step 2:

  -Open the PDF saved (you will now see a blank pdf with a menu drop-down)

  -Click on: Tools > forms > Edit Form (when a pop-up window indicates that you should save a copy of the document in order to make changes, press 'Save a copy' and open the file with Acrobat pdf copy)

  -Select the drop-down list, the drop-down list to copy and paste it into the desired document

  Now you have a drop down without a default choice. Remember that you can not change the items in the drop-down list, because we will choose a default choice and you must use the copy pdf file once again. As long as you do not click on a list item, it is not choose a default choice.

  It is not a perfect solution, but it works for me.

  Good luck and thanks!

• Binded based on drop-down list values in a table of fluid

  Can anyone help me please with my form of practice?  I'm just started learning make a fillable pdf form. I did my practical form modeled after the purchase order example provided with the installation of livecyle.  I want my table to automatically display the unit price when I select an item in the drop-down list.  I managed to do it using the script below.  The problem comes when I add my guard selection by returning to the first item on the drop-down list or on my first selection on the first row of lines. I would like to add something, the script below.  Help, please.

  

  RefreshmentOrderform.RefreshmentOrder.details.detail [0]. item::change - (JavaScript, client)

  unitprice.rawValue = this.boundItem (xfa.event.newText);

  unitprice.value = xfa.event.newText;

  Hello

  The problem you are having is because the ID of the drop-down list values are duplicated, if I choose cherry slice that get a 3 id (which is supposed to mean $3.00), but it is also the id of the Ambassador (as well as Brownies and coffee).  If similar problem with chocolate tarts going assorted Mini Cookies.

  If you keep the unique id.  At first, I thought that you must assign the id 1,2,3,4... and a search in the table for the price, but I liked your idea to keep it all in the drop-down menu control, so if you changed do so their unique, something like 1: 3. 00, 2:1. 50, 3:3. 00,... you could strip the part before the colon by changing your code change event;

  unitprice.rawValue = this.boundItem (xfa.event.newText).split(":") [1];

  That transforms the id in a table and takes the second element.

  In addition, there are a few errors in your form.  In Acrobat (or reader) you should turn on 'See the console on errors and messages', which is located under preferences... JavaScript.

  The second line in your change event causes a runtime error as the value property of a numeric field is its default value and to reference properly, you need to use.

  unitprice.value.oneOfChild.value

  But you do not have this line at all in this case.

  There is also a problem with the initialization script in numServiceChargerate, that looks like a problem of displacement of FormCalc in some parts of the JavaScript form in others, I would try and stick with one or the other.

  Good luck

  Bruce

• 2 values can be added to a drop-down list item?

  I probably need to explain what it is I'm doing first. It could even impossible the way I'm doing it. So if there's a better way, please do help. But I try to have items listed in a drop-down list. More precisely the elements that are of different lengths with different numbers. I have been using the value of the elements to do simple calculations to work. But I also want it so that once an item is selected the item to a list of material later in the form printed. I'm sure I can set the value of the element as the item number and I the number displayed next to the item (in another column) later in the order form. But I want to be able to always perform the calculations in the subform where is the original drop-down list. Is it possible to assign 2 values (one for use with calculations) and one for use as an item number? Or is there a better way to do what I'm doing? I know I could just name the list drop-down list item and contain the number of point in the name using addItem. But I don't want to confuse the user with numbers, they did not need to see. Only the person who sells the materials needs to know the number of points, not the user.

  Back again...

  Think - the behavior is expected because the values specified in the binding tab lead the overall binding for the drop down menus.

  So if the first dropdown the text resulting from elements such as the display values AND the second dropdown has numbers of items like display settings - then it will work. As long as the two drop-down lists have the same number of elements and sequence in the specified values is the same.

  This means that you must keep two drop-down lists.

  It may be a good idea to have the second dropdown (numbers) configured to read only so that the user cannot interact with it.

  Good luck

  Niall

• How Pre-select value in list drop-down auto

  Hello

  I have an automatically populated drop-down list, and I'm trying to show with a value selected (in example 5). I didn't know where to start, so I changed the code in Dreamweaver for "set value equal to" leave the function of dynamic list. List views, but the default value 0. What Miss me?

  <? PHP
  echo "< select name ="firstnumber"id = ' number' > ';"
  for ($j = 0; $j < 11; $j += 1)
  {
  echo "< option value =------' $j\ ' <? PHP if (!) ((strcmp (\"$j\",5)))) {echo \"selected=\"selected\"\ ';}? "> $j < / option > \n";
  }
  echo "< / select >.
  ? >

  Thank you

  Tim

  The problem is that you have nested PHP tags inside a PHP block. You can't do that. In fact, it is surprising that the code works at all. Normally, nesting tags PHP inside a block of PHP code will cause a syntax error.

  In addition, your code is very hard to read because of the way you use double quotes all the time. It is best to use single quotes for strings, except when you need display the value of a variable inside a string. You can also nest the double quotes inside a string in single quotes and vice versa, for code that is easier to read without the backslashes.

  That's how I rewrote your code:

  
  $j\n";
  }
  ?>