LKM row by row (aggregate)

Hello

I have an interface in ODI with a "AGGREGATE". I uses this component to extract the separate lines with the function MAX (column), that it works perfectly for a record, but my LKM don't work line by line and a single record from...

I need to run rank by rank to extract all records in the table. I use the 'LKM SQL for oracle"and I tried with"LKM SQL for SQL (line by line)"

What knowledge module can be used to insert a line by line?

Thank you

I have change the IKM and everything works properly!

I use the 'IKM SQL incremental update (line by line)"

Thank you

Tags: Business Intelligence

Similar Questions

  • Rank as aggregate function - help

    Hi all

    I am trying to learn oracle RANK as an aggregate function.

    After that I run under request.

    with temp (No., name, dept, sal) as

    (select 1, 'aaa', 20, 32254 double Union all

    Select 2, 'eee', 20, 45615 double Union all

    Select 3, 'fff', 10, double union all 34645

    Select 4, 'bbb', 30, double union all 45734

    Select 9, 'mmm', 30, 23225 double Union all

    Select 8, "nnn", 20, double union all 43565

    Select 5, 'bbb', 20, double union all 56116

    Select 7, "ccc", 30, double union all 45166

    Select 6, 'ccc', 20, double 75166)

    Select

    Rank (45166) WITHIN GROUP (order by sal) as rank_1,

    Rank (10,45166) WITHIN GROUP (stopped by the Department, sal) as rank_2,

    Rank (45166,2) GROUP WITHIN (order by sal, no.) as rank_3

    temp;

    I get the output voltage:

    rank_1 > 5

    rank_2 > 2

    rank_3 > 5

    Here, how is the value of rank_2 is 2 and rank_3 is 5, I expect that two column should be zero because it does not correspond with the records.

    Please help me understand, how does the row aggregate function is the species.

    Thanks for all help you. Please let me know for further details.

    If possible, any study link to learn the rank of aggregate function.

    Oracle version:

    Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production

    PL/SQL Release 11.2.0.3.0 - Production

    "CORE 11.2.0.3.0 Production."

    AMT for Linux: Version 11.2.0.3.0 - Production

    NLSRTL Version 11.2.0.3.0 - Production

    Its says not where is the match - but where it appears in the list - game or not.

    It's your list sorted by dept, sal

    SAL DEPT

    ---------- ----------

    10 34645

    32254 20

    20 43565

    20 45615

    20 56116

    20 75166

    30 23225

    45166 30

    30 45734

    10,45166 would appear in the slot 2

  • Need to group by using a Table WITH

    Hello

    I use a database of XE 11.g.  I have the following query, and it works.  It generates the XML code for an email I send.  I need to make a change.  I think I need a group so I can can insert empty lines when the use_date_time field has changed in the output.

    I put comment where I think that the Group By clause must go.  When I try a comment this line and run the query, I get an ORA-00979: not a GROUP BY expression error.

    Thanks for looking at this.

    DECLARE

    l_html_header varchar2 (1024);

    CLOB l_html_body;

    l_html_footer varchar2 (1024);

    CLOB l_html_total;

    BEGIN

    l_html_body: = ' < div >

    < table >

    < b >

    < tr / >

    < th Width = "180" Align = "left" > mass Date time < /th >

    < th Width = "100" Align = "left" > anthem Type < /th >

    < th Width = "275" Align = "left" > name < /th > anthem

    < th Width = "200" Align = "left" > definition < /th >

    < th Width = "200" Align = "left" > < /th > interpreter

    < /tr > ';

    I'm in)

    With html_table as)

    Select hm.use_date_time

    hm.use_type

    hm.hymn_full_name

    hm.gather_number

    hm.setting

    hm.performer

    hm.use_type_key

    Of HYMN_MAILING hm

    order of use_date_time)

    Select

    use_date_time

    use_type

    hymn_full_name

    gather_number

    setting

    interpreter

    use_type_key

    Html_table t

    -Group By t.use_date_time

    Order of t.use_date_time, t.use_type_key

    ) Loop

    l_html_body: = l_html_body | "< tr >";

    l_html_body: = l_html_body | "< td >" | TO_CHAR (i.use_date_time, ' MM/DD/YYYY HH: mi AM' ') | '< table > ";

    l_html_body: = l_html_body | "< td >" | i.use_type | "< table >";

    l_html_body: = l_html_body | "< td >" | i.hymn_full_name | "< table >";

    l_html_body: = l_html_body | "< td >" | i.Setting | "< table >";

    l_html_body: = l_html_body | "< td >" | i.performer | "< table >";

    l_html_body: = l_html_body | "< /tr >";

    end loop;

    l_html_body: = l_html_body | '< /table > ';

    l_html_header: = ' <! DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 / / IN" ""http://www.w3.org/TR/html4/strict.dtd"> ".

    < html > < head > < title > anthem reminder < / title > < / head > < body > ';

    l_html_footer: = ' < / div > < body / > < / html > ';

    l_html_total: = l_html_header | l_html_body | l_html_footer;

    dbms_output.put_line (l_html_total);

    -html_email (p_to = > ' [email protected]', )

    --          p_from          => ' [email protected] ',

    -p_subject = > 'Message of Test using subject and UTL_SMTP.

    -p_text = > "This is a test message."

    -p_html = > l_html_total,

    -p_smtp_hostname = > "mail.site.org"

    -p_smtp_portnum = > 587);

    END;

    /

    Hello

    I don't know what you want, either.

    In pure SQL, you can use the GROUP BY ROLLUP to produce an additional line (called a Super row aggregate) at the end of each group.

    However, given that you are using PL/SQL and stopping after each line, it is simpler test a change of value at that time here.  (As a general rule, you want the back-end to retrieve data and nothing else.  How do you present this data is best done by front end.)

    For example, that you want to add a couple of
    items between different values of use_date_time:

    DECLARE

    prev_use_date_time html_table.use_date_time%TYPE;

    l_html_header varchar2 (1024);

    ...

    hm.hymn_full_name

    -Joke the anthem:

    -(Q) what was the name of Ralph Vaughn Williams's dog?

    -(A) AMPNEY

    ...

    ) Loop

    IF prev_use_date_time <> i.use_date_time

    THEN

    l_html_body: = l_html_body | '

    ';

    END IF;

    prev_use_date_time: = i.use_date_time;

    l_html_body: = l_html_body | '';

    ...

    The rest of your code can remain unchanged.

  • Oracle Apex: Aggregate also show row

    Hi all

    Currently I use an interactive report Oracle Apex

    Column1 Column2

    A1         1             2

    A2         2             3

    A3         3             4

    A4         4             5

    ----------------------

    10 14

    After the display of data, make some calculations as Column1, Column2, using the SUM aggregate function of interactive report

    But the result shows that the last line of the report , so I have to scroll to see the result

    How to display the result in the first row of the report?

    Column1 Column2

    10 14

    ----------------------

    A1         1             2

    A2         2             3

    A3         3             4

    A4         4             5

    I found the solution

    1. Add void querry to compute the sum
    2. Union with existed result
    3. Use to highlight the service to catch up with the new line

  • Aggregate XML columns in a single row in Oracle

    Hello

    I have a table named TMTABLE HT and it followed columns:

    ID, NAME, TEXT
    1 orders XML1
    2 orders XML2
    3 orders for XML3

    where XML1, XML2 and XML3 follow:

    XML1:

    <? XML version = "1.0" encoding = "utf-8"? >
    The <>rowsets
    rowset <>
    < row >
    < Uom IN. = "" > < DB > 4500005146
    < Uom of line = "" > 10 < / Line >
    < / row >
    < / lines >
    < / sets of lines >

    XML2:

    <? XML version = "1.0" encoding = "utf-8"? >
    The <>rowsets
    rowset <>
    < row >
    < Uom IN. = "" > < DB > 4500005147
    < Uom of line = "" > 10 < / Line >
    < / row >
    < / lines >
    < / sets of lines >

    XML3:

    <? XML version = "1.0" encoding = "utf-8"? >
    The <>rowsets
    rowset <>
    < row >
    < Uom IN. = "" > < DB > 4500005148
    < Uom of line = "" > 10 < / Line >
    < / row >
    < / lines >
    < / sets of lines >

    Now, I want to query Oracle get this XML1, XML2 and XML3 in a single row, in the following format:

    <? XML version = "1.0" encoding = "utf-8"? >
    rowset <>
    < row >
    < Uom IN. = "" > < DB > 4500005146
    < Uom of line = "" > 10 < / Line >
    < / row >
    < row >
    < Uom IN. = "" > < DB > 4500005147
    < Uom of line = "" > 10 < / Line >
    < / row >
    < row >
    < Uom IN. = "" > < DB > 4500005148
    < Uom of line = "" > 10 < / Line >
    < / row >
    < / lines >

    I tried various queries, but not able to do this. Can someone help me please how to do in this regard?

    Hello

    Assuming that TEXT column of XMLType data type:

    SQL> select xmlelement("Rowset",
  2           xmlagg(x.column_value)
  3         ) as result
  4  from tmtable t
  5     , xmltable('/Rowsets/Rowset/Row' passing t.text) x
  6  ;

RESULT
--------------------------------------------------------------------------------

  4500005146
  10


  4500005147
  10


  4500005148
  10

  • SQL question - aggregate rows based on the value of the columns

    Hi all

    DBA_EXTENTS reports on the number of starting point of measurement (column BLOCK_ID) and the size of the scale in the Oracle (BLOCKS column) blocks.

    I'm trying to combine the lines of the segments of same as if their associated extensions are adjacent.

    For example, assume that the data in the view are as follows:

    Nom_segment Block_id BLOCKS
    EMP108
    EMP188
    DEPARTMENTS2616
    DEPARTMENTS428

    EMP

    5016EMP668

    And I want to do a set of results that looks like this:

    Nom_segment Block_id BLOCKS
    EMP1016
    DEPARTMENTS2624
    EMP5016

    I thought to use an analytical query, but I couldn't find something that meets this requirement.

    Can you please help?

    Hello

    Here's a way to do that using the analytical SUM function:

    WITH got_grp AS

    (

    SELECT nom_segment, block_id, blocks

    , block_id - SUM (blocks) over (PARTITION BY nom_segment

    ORDER BY block_id

    ) AS the grp

    FROM the data

    )

    SELECT nom_segment

    MIN (block_id) AS grp_block_id

    SUM (blocks) AS grp_blocks

    OF got_grp

    GROUP BY nom_segment, grp

    ORDER BY grp_block_id

    ;

    The data you posted in response to #3:

    Pini Dibask wrote:

    Thanks Frank,.

    If you would care to post CREATE TABLE and INSERT to your sample data and the version of your database, then I could show you exactly.

    The Oracle version is 11.2.0.4

    This is the CREATE TABLE and INSERT statements for the sample data:

    CREATE THE TABLE DATA (NOM_SEGMENT VARCHAR2 (20), BLOCK_ID NUMBER, NUMBER OF BLOCKS);

    INSERT IN DATA VALUES ("EMP", 10, 8);

    INSERT IN DATA VALUES ("EMP", 18: 8);

    INSERT IN DATA VALUES ("DEPARTMENTS", 28, 16);

    INSERT IN DATA VALUES ("DEPARTMENTS", 42, 8);

    INSERT IN DATA VALUES ("EMP", 50, 8);

    INSERT IN DATA VALUES ("EMP", 66, 8);

    is not the same as the data in your first post and the results are not the same, either.

    The fixed difference technique involves lines don't overlap.  In the sample data in response #3, 'DEPARTMENTS' lines overlap, i.e. blocks 42 and 43 belong to two segments.

  • Column not null in rows in SQL query

    I have the below query,

    WITH t

    Did YOU (SELECT NULL col_1, col_2, 'C' FROM DUAL col_3 NULL

    UNION ALL

    SELECT 'A' col_1, col_2 NULL, NULL FROM DUAL col_3

    UNION ALL

    NULL SELECT col_1, col_2 "B", NULL FROM DUAL col_3)

    SELECT *.

    T;

    who will pick up three rows, on which single column will have a value for each row.
    And the other columns are left out as below.

    COL_1 COL_2 COL_3
    C
    A
    B

    I don't need that values should be extracted in the column name that is not null.

    as

    COL_1 COL_2 COL_3
    ABC


    Please advise me

    You can use the MAX aggregate function. But do not know what you are trying to reach.

  • Stupid old backpacker (me) cannot understand why this query returns 1 row

    Hi all

    In reference to {: identifier of the thread = 2456973}, why do
    select sum(count(decode(job, 'CLERK', 1, null))) CLERKS
, sum(count(decode(job, 'SALESMAN', 1, null))) SALESMANS
from emp group by job;
    only 1 rank and not 1 for each task? In fact, I had to test it myself to believe.

    It returns the data as if the query were
    select sum(CLERKS), sum(SALESMANS)
from (select count(decode(job, 'CLERK', 1, null)) CLERKS, count(decode(job, 'SALESMAN', 1, null)) SALESMANS
         from emp group by job)
    Using only a single aggregate (count or sum) returns 1 row per job, as expected

    John Stegeman wrote:
    It returns the data as if the query were

    select sum(CLERKS), sum(SALESMANS)
from (select count(decode(job, 'CLERK', 1, null)) CLERKS, count(decode(job, 'SALESMAN', 1, null)) SALESMANS
from emp group by job)

    Exactly the point ;-)

    It seems that Oracle actually do, a group of 'double' in the same operation.
    Attend plans to explain in this example:

    SQL> select count(decode(job, 'CLERK', 1, null)) CLERKS
  2       , count(decode(job, 'SALESMAN', 1, null)) SALESMANS
  3  from scott.emp group by job;

    CLERKS  SALESMANS
---------- ----------
         0          0
         0          0
         0          0
         0          4
         4          0

Execution Plan
----------------------------------------------------------
Plan hash value: 1697595674

---------------------------------------------------------------------------
| Id  | Operation          | Name | Rows  | Bytes | Cost (%CPU)| Time     |
---------------------------------------------------------------------------
|   0 | SELECT STATEMENT   |      |     5 |    40 |     4  (25)| 00:00:01 |
|   1 |  HASH GROUP BY     |      |     5 |    40 |     4  (25)| 00:00:01 |
|   2 |   TABLE ACCESS FULL| EMP  |    14 |   112 |     3   (0)| 00:00:01 |
---------------------------------------------------------------------------

    And compare it to the one with the double aggregates:

    SQL> select sum(count(decode(job, 'CLERK', 1, null))) CLERKS
  2       , sum(count(decode(job, 'SALESMAN', 1, null))) SALESMANS
  3  from scott.emp group by job;

    CLERKS  SALESMANS
---------- ----------
         4          4

Execution Plan
----------------------------------------------------------
Plan hash value: 417468012

----------------------------------------------------------------------------
| Id  | Operation           | Name | Rows  | Bytes | Cost (%CPU)| Time     |
----------------------------------------------------------------------------
|   0 | SELECT STATEMENT    |      |     1 |     8 |     4  (25)| 00:00:01 |
|   1 |  SORT AGGREGATE     |      |     1 |     8 |     4  (25)| 00:00:01 |
|   2 |   HASH GROUP BY     |      |     1 |     8 |     4  (25)| 00:00:01 |
|   3 |    TABLE ACCESS FULL| EMP  |    14 |   112 |     3   (0)| 00:00:01 |
----------------------------------------------------------------------------

    There are GROUP BY hash and SORT GLOBAL times.

    It is really unnecessary to an aggregate on an aggregate - if two aggregates are used "in the same group level.
    Sum() aggregates are used on an already aggregated value, so it doesn't look like Oracle which actually cures like 'first do the internal aggregate using the group specified by and then do the external aggregation on the result with any group.'

    Look at this example where I combine aggregates "double" with "single" aggregates:

    SQL> select sum(count(decode(job, 'CLERK', 1, null))) CLERKS
  2       , sum(count(decode(job, 'SALESMAN', 1, null))) SALESMANS
  3       , count(decode(job, 'SALESMAN', 1, null)) SALESMANS2
  4       , count(*) COUNTS
  5  from scott.emp group by job;

    CLERKS  SALESMANS SALESMANS2     COUNTS
---------- ---------- ---------- ----------
         4          4          1          5

Execution Plan
----------------------------------------------------------
Plan hash value: 417468012

----------------------------------------------------------------------------
| Id  | Operation           | Name | Rows  | Bytes | Cost (%CPU)| Time     |
----------------------------------------------------------------------------
|   0 | SELECT STATEMENT    |      |     1 |     8 |     4  (25)| 00:00:01 |
|   1 |  SORT AGGREGATE     |      |     1 |     8 |     4  (25)| 00:00:01 |
|   2 |   HASH GROUP BY     |      |     1 |     8 |     4  (25)| 00:00:01 |
|   3 |    TABLE ACCESS FULL| EMP  |    14 |   112 |     3   (0)| 00:00:01 |
----------------------------------------------------------------------------

    When you mix "doubles" and "single" aggregates, Oracle decides that unique aggregates belong to the 'outer' aggregation
    SALESMAN2 did a count on the aggregated work column which is the result of the 'internal' group by - so only 1.
    The count (*) is also the result of the aggregation of the 'internal '.

    I don't know if it's documented or if it is an 'effect' of internal code used for GROUPING SETS or the internal code used to enable the analytical functions like this:

    SQL> select count(decode(job, 'CLERK', 1, null)) CLERKS
  2       , count(decode(job, 'SALESMAN', 1, null)) SALESMANS
  3       , sum(count(decode(job, 'CLERK', 1, null))) over () CLERKS2
  4       , sum(count(decode(job, 'SALESMAN', 1, null))) over () SALESMANS2
  5  from scott.emp group by job;

    CLERKS  SALESMANS    CLERKS2 SALESMANS2
---------- ---------- ---------- ----------
         0          0          4          4
         4          0          4          4
         0          0          4          4
         0          0          4          4
         0          4          4          4

Execution Plan
----------------------------------------------------------
Plan hash value: 4115955660

----------------------------------------------------------------------------
| Id  | Operation           | Name | Rows  | Bytes | Cost (%CPU)| Time     |
----------------------------------------------------------------------------
|   0 | SELECT STATEMENT    |      |     5 |    40 |     4  (25)| 00:00:01 |
|   1 |  WINDOW BUFFER      |      |     5 |    40 |     4  (25)| 00:00:01 |
|   2 |   SORT GROUP BY     |      |     5 |    40 |     4  (25)| 00:00:01 |
|   3 |    TABLE ACCESS FULL| EMP  |    14 |   112 |     3   (0)| 00:00:01 |
----------------------------------------------------------------------------

    Personally, I think that I would have preferred if Oracle has raised an error on this "double aggregation" and therefore require me to write this way (if it's the result I wanted):

    select sum(CLERKS), sum(SALESMANS)
from (select count(decode(job, 'CLERK', 1, null)) CLERKS, count(decode(job, 'SALESMAN', 1, null)) SALESMANS
         from emp group by job)

    I don't really see a good use case for aggregations of 'double'-, but rather that he could give you undetected bugs in your code, if you happen to do double aggregation without noticing.

    Interesting thing to know ;-)

  • Group using the order of rows

    Hi all

    one of my friends asked me a question and I think it's possible but how?

    without using PLSQL, can it be done by sql?

    We have a table and its data like this:
    X   Y
----------
A   S
B   S
C   S
D   T
E   T
F   S
G   S
H   R
    I want to order these data be field X (which is already happening in this example) and aggregate that data by field Y but if in the order of the value of the field changes, it means that it will be a new group.

    I mean, for this example, A, B and C Archives is a group, D, and E are another group and E and F are one group to another. as you see ABC records and EF has same value Y (which is S) but I would like to assume they are different groups because of the order.

    If I give a number of groups, it looks like this:
    X   Y
----------
A   S      1
B   S      1
C   S      1
D   T      2
E   T      2
F   S      3
G   S      3
H   R      4
    I have 4 different group here. any idea?

    PS: we do not want just sql, plsql

    If you don't care about the group being sequential numbers:

    with t as (
           select 'A' x,'S' y from dual union all
           select 'B','S' from dual union all
           select 'C','S' from dual union all
           select 'D','T' from dual union all
           select 'E','T' from dual union all
           select 'F','S' from dual union all
           select 'G','S' from dual union all
           select 'H','R' from dual
          )
select  x,
        y,
        row_number() over(order by x) - row_number() over(partition by y order by x) rn
  from  t
  order by x
/

X Y         RN
- - ----------
A S          0
B S          0
C S          0
D T          3
E T          3
F S          2
G S          2
H R          7

8 rows selected.

SQL>

    SY.

  • request for a row of each distinct column value

    Let's say theres employee table with the columns name, id and title. How do you get a line for each separate title. What line is it of okay as long as your result set covers all the possible titles used. How can I do this? Thank you

    Hello

    I think that you may have about a Request of Top - N .
    As you post a version of your table, I'll use scott.emp to illustrate.
    The following query illustrates exactly one line of output for each separate work:

    WITH        got_r_num         AS
(
     SELECT     empno, ename, job
     ,     ROW_NUMBER () OVER ( PARTITION BY  job
                               ORDER BY          ename
                             ) AS r_num
     FROM    scott.emp
)
SELECT     empno, ename, job
FROM     got_r_num
WHERE     r_num     = 1
;

    Output:

    `    EMPNO ENAME      JOB
---------- ---------- ---------
      7902 FORD       ANALYST
      7876 ADAMS      CLERK
      7698 BLAKE      MANAGER
      7839 KING       PRESIDENT
      7499 ALLEN      SALESMAN

    The lines you see are actually the rows in the table, not aggregates. In other words, you can be sure that there is a line in the table with empno = 7902, ename = 'FORD' and employment = "ANALYST."

    I hope that answers your question.
    If not, post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.
    If the expected results are not unique, in other words, if you want to be just as pleased at a number of games of different results, then after a few examples from the same data of the sample.

  • Select the last row inserted into the table

    Hello
    I have an app that inserts a line in two columns (stamp that contains the time of creation of the line and a float) each seconde.1. I have another app that bed that reads lateset inserted each seconde.1. I had this on SQL Server where I just chose the DateTime max line and had surgery no clustered index on the datetime column. But since I'm moving this course at Oracle I wanted to know if there is a better way to do it. The table will keep up to 30 days of data is about 26 million lines. So I need this facility where querying for last place among the 26 million lines continue with timer deuxieme.1 of my application.

    Here's my insert:
    Insert in testlog (hz, ctime) values (: hz_value, localtimestamp (2))

    Here is my selection:
    Select hz, ctime testlog where ctime = (select max (ctime) of testlog)

    Thank you

    I would use:

    Select hz, ctime of (select hz, ctime, dense_rank() over (order by desc ctime) rnk of testlog) where rnk = 1;

    For example:

    SQL> explain plan for
  2  select * from emp where empno = (select max(empno) from emp)
  3  /

Explained.

SQL> @?\rdbms\admin\utlxpls

PLAN_TABLE_OUTPUT
------------------------------------------------------------------------------------------------------------------------------------
Plan hash value: 1674692883

---------------------------------------------------------------------------------------
| Id  | Operation                    | Name   | Rows  | Bytes | Cost (%CPU)| Time     |
---------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT             |        |     1 |    37 |     2   (0)| 00:00:01 |
|   1 |  TABLE ACCESS BY INDEX ROWID | EMP    |     1 |    37 |     1   (0)| 00:00:01 |
|*  2 |   INDEX UNIQUE SCAN          | PK_EMP |     1 |       |     0   (0)| 00:00:01 |
|   3 |    SORT AGGREGATE            |        |     1 |     4 |            |          |
|   4 |     INDEX FULL SCAN (MIN/MAX)| PK_EMP |    14 |    56 |     1   (0)| 00:00:01 |
---------------------------------------------------------------------------------------

PLAN_TABLE_OUTPUT
------------------------------------------------------------------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   2 - access("EMPNO"= (SELECT MAX("EMPNO") FROM "EMP" "EMP"))

16 rows selected.

SQL> explain plan for
  2  select * from (select e.*,dense_rank() over(order by empno desc) rn from emp e) where rn = 1
  3  /

Explained.

SQL> @?\rdbms\admin\utlxpls

PLAN_TABLE_OUTPUT
------------------------------------------------------------------------------------------------------------------------------------
Plan hash value: 2150023773

----------------------------------------------------------------------------------------
| Id  | Operation                     | Name   | Rows  | Bytes | Cost (%CPU)| Time     |
----------------------------------------------------------------------------------------
|   0 | SELECT STATEMENT              |        |    14 |  1400 |     2   (0)| 00:00:01 |
|*  1 |  VIEW                         |        |    14 |  1400 |     2   (0)| 00:00:01 |
|*  2 |   WINDOW NOSORT STOPKEY       |        |    14 |   518 |     2   (0)| 00:00:01 |
|   3 |    TABLE ACCESS BY INDEX ROWID| EMP    |    14 |   518 |     2   (0)| 00:00:01 |
|   4 |     INDEX FULL SCAN DESCENDING| PK_EMP |    14 |       |     1   (0)| 00:00:01 |
----------------------------------------------------------------------------------------

PLAN_TABLE_OUTPUT
------------------------------------------------------------------------------------------------------------------------------------

Predicate Information (identified by operation id):
---------------------------------------------------

   1 - filter("RN"=1)
   2 - filter(DENSE_RANK() OVER ( ORDER BY INTERNAL_FUNCTION("EMPNO") DESC )<=1)

17 rows selected.

SQL>

    SY.

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    50

    30

    60

    40

    30

    25

    25

    20

    20

    25

    20

    15

    10

    10

    1

    381

    1

    1

    1

    1

    1

    1

    1

    1

    1

    1

    1

    1

    1

    1

    1

    50

    1

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    30

    0

    1

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    60

    0

    0

    1

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    40

    0

    0

    0

    1

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    30

    0

    0

    0

    0

    1

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    25

    0

    0

    0

    0

    0

    1

    0

    0

    0

    0

    0

    0

    0

    0

    0

    25

    0

    0

    0

    0

    0

    0

    1

    0

    0

    0

    0

    0

    0

    0

    0

    20

    0

    0

    0

    0

    0

    0

    0

    1

    0

    0

    0

    0

    0

    0

    0

    20

    0

    0

    0

    0

    0

    0

    0

    0

    1

    0

    0

    0

    0

    0

    0

    25

    0

    0

    0

    0

    0

    0

    0

    0

    0

    1

    0

    0

    0

    0

    0

    20

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    1

    0

    0

    0

    0

    15

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    1

    0

    0

    0

    10

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    1

    0

    0

    10

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    1

    0

    1

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    0

    1

    50

    1

    60

    1

    30

    1

    20

    1

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