Logging in to the application using the credentials of the database table and not APEX default

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  Hi all

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• Earphone is not upward or the database service is not registered with her

  Hello

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  IG] $

  
  

  [oracle@gds-bgl-oradb db_1] $ cat network/admin/listener.ora

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  LISTENER =

  (DESCRIPTION_LIST =

  (DESCRIPTION =

  (ADDRESS = (PROTOCOL = CIP)(KEY = EXTPROC1521))

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  tnsnames.ora # Network Configuration file: /u01/app/oracle/product/11.2.0/db_1/network/admin/tnsnames.ora

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  LISTENER_ORCL =

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  (DESCRIPTION =

  (ADDRESS = (PROTOCOL = TCP) (HOST = gds-bgl-oradb)(PORT = 1521))

  (CONNECT_DATA =

  (SERVER = DEDICATED)

  (SERVICE_NAME = orcl.cisco.com)

  )

  )

  ADR_BASE_LISTENER = / u01/app/oracle

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  LSNRCTL for Linux: Version 11.2.0.1.0 - Production on June 5, 2014 09:30

  Copyright (c) 1991, 2009, Oracle.  All rights reserved.

  Connection to (DESCRIPTION = (ADDRESS = (PROTOCOL = IPC) (KEY = EXTPROC1521)))

  STATUS of the LISTENER

  ------------------------

  Alias LISTENER

  Version TNSLSNR for Linux: Version 11.2.0.1.0 - Production

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  Uptime 0 days 0 hours 34 min 56 s

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  Security ON: OS Local Authentication

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  Parameter Listener of the /u01/app/oracle/product/11.2.0/db_1/network/admin/listener.ora file

  The listener log file /U01/app/Oracle/diag/tnslsnr/GDS-BGL-OraDB/listener/alert/log.XML

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  Summary of services...

  Service "ORCL" has 1 instance (s).

  Instance "ORCL", State LOAN, has 1 operation for this service...

  Service 'orclXDB' has 1 instance (s).

  Instance "ORCL", State LOAN, has 1 operation for this service...

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• Left join of the two tables and multiple values into a single value separated by commas

  Hello

  I have following tables with their structures and their data as below.

  CREATE TABLE 'BETODI '. "" BETINFO ".

  (

  VARCHAR2 (8 BYTE) "CURRENTPRESS."

  ENABLE 'TYPEIDCONTAINER' VARCHAR2 (30 BYTE) NOT NULL

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  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A24G', 'PMC');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A24D', 'Pensky-MARTENS');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ("A25D", "CMP");

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A25G', 'PMC');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A26D', 'PMC');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A26G', 'PMC');

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ("A32G", "V-BFC3");

  INSERT INTO Betinfo (Currentpress, typeidcontainer) VALUES ('A32D', "V-BFC2");

  CREATE TABLE 'BETODI '. "" BETMASTER ".

  (

  ACTIVATE THE "CUREPRESS" TANK (5 BYTES) NOT NULL,

  ACTIVATE THE "TYPE" VARCHAR2 (5 BYTE) NOT NULL,

  NUMBER (5.0) "LASTPCIRIM".

  )

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A24', '45 M 8', 15);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A25', 42 16', 15);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A26", 16' 45, 15);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A27", '45 M 34', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A28', '45 M 34', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A29', '45 M 34', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A30', '45MCH', 15);

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  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A32', '45MCH', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ('A33', '45MCH', 16);

  INSERT INTO BetMaster (Curepress, type, lastpcirim) VALUES ("A34", "45MCH", 16);

  These two tables have left join as

  BETMASTER. CUREPRESS = substr (BETINFO. CURRENTPRESS, 1, 3)

  now I want to have the data in the two tables with fields Curepress, Lastpcirim, typeidcontainer.

  Also something like

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  So, for example above, we should be given as

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  A28 16 (NULL)

  A30 15 (NULL)

  A31 16 (NULL)

  A32 16 BFC2-V; V BFC3

  A33 16 (NULL)

  A34 16 (NULL)

  How could do?

  My current request is as

  Select distinct Curepress, lastpcirim, typeidcontainer

  BETMASTER STD left join INF BETINFO

  on the trim (STD. CUREPRESS) = substr (trim (INF. CURRENTPRESS), 1, 3)

  but I am unable to get the values separated by commas.

  Any help would be appreciated.

  Thank you

  Mahesh.

  Hi, Mahesh,

  If you want to only 1 row of output for each distinct combination of currentpress and lastpcirim?  This sounds like a job for GROUP BY.

  And you want the row to contain a list of all different typidcontainers-delimited?  This sounds like a job for the aggregate LISTAGG function.

  WITH joined_data AS

  (

  SELECT DISTINCT

  MST.curepress, mst.lastpcirim, inf.typeidcontainer

  OF betmaster STD

  LEFT JOIN betinfo ON TRIM (mst.curepress) inf = SUBSTR (TRIM (inf.currentpress)

  1

  3

  )

  )

  SELECT curepress, lastpcirim

  LISTAGG (typeidcontainer, ',')

  THE Group (ORDER BY typeidcontainer) AS container_list

  OF joined_data

  Curepress GROUP, lastpcirim

  ;

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  Thanks for posting the CREATE TABLE and INSERT statements; It is very useful.  Don't forget to tell what version of Oracle you are using.  LISTAGG was new in Oracle 11.2.

  Why not add CHECK constraints (and perhaps triggers) to your tables, so that curepress and currentpress are not stored with the head or trailing spaces?  Then you wouldn't need to use the PAD in queries like this, and your code would be simpler and more effective.

• How to assign values to the nested table and passes as a parameter for the procedure?

  How to assign values to the nested table and passes as a parameter for the procedure?
  
  Here are the object and its type
  
  create or replace type test_object1 as an object
  (
  val1 varchar2 (50).
  val2 varchar2 (50).
  VARCHAR2 (50) val3
  );
  
  
  create or replace type test_type1 is table of the test_object1;
  
  
  create or replace type test_object2 as an object
  (
  val1 varchar2 (50).
  val2 varchar2 (50).
  VARCHAR2 (50) val3
  );
  
  
  create or replace type test_type2 is table of the test_object2;
  
  
  GRANT ALL ON test_object1 to PUBLIC;
  
  
  GRANT ALL ON test_type1 to PUBLIC;
  
  
  GRANT ALL ON test_object2 to PUBLIC;
  
  
  GRANT ALL ON test_type2 to PUBLIC;
  
  Here is the table object type:
  
  create the table test_object_tpe
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  NESTED TABLE main_val1 STORE AS tot1
  NESTED TABLE main_val2 STORE AS earlier2;
  
  
  -----------------------------------------------------------------------------------------------------------
  
  Here is the procedure that inserts values into the nested table:
  
  PROCEDURE INSERT_TEST_DATA (sl_num in NUMBER,
  Description in VARCHAR2,
  p_main_val1 IN test_type1,
  p_main_val2 IN test_type2
  )
  IS
  BEGIN
  
  FOR rec in p_main_val1.first... p_main_val1. Last
  LOOP
  
  INSERT INTO xxdl.test_object_tpe
  (
  sl_num,
  Description,
  main_val1,
  main_val2
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  VALUES
  (
  sl_num
  description
  test_type1 (test_object1)
  p_main_val1 .val1 (CRE),
  p_main_val1 .val2 (CRE),
  p_main_val1 .val3 (rec)
  )
  )
  test_type2 (test_object2 (p_main_val2 .val1 (CRE),
  p_main_val2 .val2 (CRE),
  p_main_val2 .val3 (rec)
  )
  )
  
  );
  
  END LOOP;
  
  commit;
  
  END INSERT_TEST_DATA;
  
  -------------------------------------------------------------------------------------------
  
  Here are the block anonymoys what values attributed to the object type and pass values in the procedure:
  
  Set serveroutput on;
  
  declare
  
  p_sl_num NUMBER: = 1001;
  p_description VARCHAR2 (50): = 'Test Val1;
  
  inval1 test_type1: = test_type1();
  inval2 test_type2: = test_type2();
  
  Start
  
  
  inval1 (1) .val1: = "testx1";
  inval1 (1) .val2: = "testx2";
  inval1 (1) .val3: = "testx3";
  
  inval2 (1) .val1: = "testy1";
  inval2 (1) .val2: = "testy2";
  inval2 (1) .val3: = "testy3";
  
  CSI_PKG. INSERT_TEST_DATA (sl_num = > p_sl_num,)
  Description = > p_description,
  p_main_val1 = > inval1,
  p_main_val2 = > inval2
  );
  
  end;
  /
  Someone can correct me.
  
  Thank you
  Lavan

  Thanks for posting the DOF and the sample code but whenever you post provide your Oracle version 4-digit (result of SELECT * FROM V$ VERSION).
  >
  How to assign values to the nested table and passes as a parameter for the procedure?
  >
  Well you do almost everything bad that could be hurt.

  Here is the code that works to insert data into your table (the procedure is not even necessary).

  declare
  p_sl_num NUMBER := 1001;
  p_description VARCHAR2(50) := 'Testing Val1';
  inval1 test_type1 := test_type1();
  inval2 test_type2 := test_type2();
  begin
  inval1.extend();
  inval1(1) := test_object1('testx1', 'testx2', 'testx3');
  inval2.extend();
  inval2(1) := test_object2('testy1', 'testy2', 'testy3');
  
  INSERT INTO test_object_tpe
  (
  sl_num,
  description,
  main_val1,
  main_val2
  )
  VALUES
  (p_sl_num, p_description, inval1, inval2);
  commit;
  end;
  /
  

  See example 5-15 making reference to an element of nested Table Chapter 5 using PL/SQL collections and records in the PL/SQL doc
  http://docs.Oracle.com/CD/B28359_01/AppDev.111/b28370/Collections.htm#CJABEBEA

  1. you don't even have the procedure because it is a simple INSERTION in the table you can do directly (see my above code)

  inval1(1).val1 := 'testx1';
  

  Since you have not yet created all the elements, there is no element 1 "inval1". You need EXTEND the collection to add an element

  inval1.extend();
  

  And then, there is an empty element, but "inval1" is a container for objects of type 'test_object1' not for scalars as "val1", "val2", and "val3".
  If you can not do

  inval1(1).val1 := 'testx1';
  

  You must create an instance of 'test_object1 '.

  inval1(1) := test_object1('testx1', 'testx2', 'testx3');
  

  And so on for the other collection

  You don't need the procedure (as my code example shows), but once you fill in the variables correctly it will work.

• Check if e-mail exist in the database table

  I stumbled on this a few times before, but I'm not familiar with this system, whenever you enter an emailaddress, you see as a clock indicating the system checks if the e-mail address may be used, in other words, is not yet in a table. I would like something similar and when the "audit" is done and the emailaddress is not in the DB table, the rest of the form appears, otherwise, an error message indicates the address is already in use. I guess this could be done using Javascript, but is there also a PHP way to do this?

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• Cut 1,000 LP records in securities - the simpler procedure and not a lot of time

  Dear friends,

  in the national and University Library Slovenian we would save in digital form and do the restore at least 1000 LPs. We save our LPs on our hard drive. We would then cut them into smaller units (securities). Does anyone know the simplest procedure and not a lot of time in Adobe Audition?

  For example:

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  Thank you for your response.

  National Library Slovenia wrote:

  We decided to keep the original files because they are (saved on the hard drive) and do no repairs (for example a hiss reduction, clik and pop eliminator...).

  1. we want to mark the silences between tracks (we decided do not fade and fade out)

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  Now you have a list of beaches of marker in the markers list, you will find that there is a button of batch process at the bottom that you can use. This will automatically save each of the ranges mark marked in a separate file, either using name information that you have entered, or by using the schema that you mentioned above. You can choose the prefix - that could be the name of LP - and it is the tracks sequentially from any number you choose - so if you do the second side of the LP, you could start with, say, {lp-name} _006.wav. The only other thing you need to do is where you want to save the files.

• LOV inside the inner table does not!

  Hello
  
  I have a Master Advanced Table and an internal Table (more advanced) retail. (I know it's a performance problem, but..)  :()
  
  I have a number of customer LOV in internal table. But when I select a row in the LOV I don't get the value returned to my return of goods. Page popup LOV just stay there without responding to any request post.
  
  I'm on 11.5.10 RUP4.
  
  Thank you
  Wine

  In my view, that this feature is not supported as indicated in the dev guide:

  "The inner table does not support LOVs. You must use a different user interface.