MAX() UNIQUE NUMBER

Hi, I'm trying to choose the max (APP_NUMBER) when you have selected I would only the DISTINCTE ID that has the FLAG as Y

I have the below sql

However I would like only 1 being robbed by ID

Select the MAXIMUM (APP_NUMBER) first and then look at the flag of Y

SELECT ID, PERIOD, V_DATE, APP_NUMBER, FLAG,

MAX (APP_NUMBER)

OF DAN_GR7

WHERE FLAG = "Y".

PERIOD OF GROUP BY ID, V_DATE, APP_NUMBER, FLAG

CREATE TABLE DAN_GR7

(VARCHAR2 (12) ID,)

PERIOD VARCHAR2 (12),

DATE OF V_DATE,

APP_NUMBER VARCHAR2 (12),

PAVILION VARCHAR2 (12));

INSERT INTO DAN_GR7 (ID, FLAG, PERIOD, V_DATE, APP_NUMBER) VALUES (' 1 ', ' 2014 ', 17 JANUARY 14 ', ' 00038615', 'Y');

INSERT INTO DAN_GR7 (ID, FLAG, PERIOD, V_DATE, APP_NUMBER) VALUES (' 1 ', ' 2014 ', 17 JANUARY 14 ', ' 00038623', 'Y');

INSERT INTO DAN_GR7 (ID, PERIOD, V_DATE, APP_NUMBER, FLAG) VALUES (2, 'AND ' 2013', 17 NOVEMBER 12 ', ' 00049625', 'Y');

INSERT INTO DAN_GR7 (ID, PERIOD, V_DATE, APP_NUMBER, FLAG) VALUES (2, 'AND ' 2013', 17 NOVEMBER 12 ', ' 00049615', 'Y');

INSERT INTO DAN_GR7 (ID, FLAG, PERIOD, V_DATE, APP_NUMBER) VALUES (3 ', ' 2012', NOVEMBER 16, 11 ', '00056915',' don't);

HAVE:

IDPERIODV_DATEAPP_NUMBERFLAG
1201417 January 1438615THERE
1201417 January 1438623THERE
2201317 November 1249625THERE
2201317 November 1249615THERE
32012November 16, 1156915N

WANTED:

IDPERIODV_DATEAPP_NUMBERFLAG
1201417 January 1438623THERE
2201317 November 1249625THERE

Thank you

Select distinct id, period, V_DATE, max (app_number) on app_number (partition by id), flag

of dan_gr7 where the flag = "Y".

V_DATE, APP_NUMBER, ID, PERIOD INDICATOR,

1,2014,1/17/2014,00038623, Y

2 201 311 / 17 / 2012,00049625, Y

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