MAX() UNIQUE NUMBER
Hi, I'm trying to choose the max (APP_NUMBER) when you have selected I would only the DISTINCTE ID that has the FLAG as Y
I have the below sql
However I would like only 1 being robbed by ID
Select the MAXIMUM (APP_NUMBER) first and then look at the flag of Y
SELECT ID, PERIOD, V_DATE, APP_NUMBER, FLAG,
MAX (APP_NUMBER)
OF DAN_GR7
WHERE FLAG = "Y".
PERIOD OF GROUP BY ID, V_DATE, APP_NUMBER, FLAG
CREATE TABLE DAN_GR7
(VARCHAR2 (12) ID,)
PERIOD VARCHAR2 (12),
DATE OF V_DATE,
APP_NUMBER VARCHAR2 (12),
PAVILION VARCHAR2 (12));
INSERT INTO DAN_GR7 (ID, FLAG, PERIOD, V_DATE, APP_NUMBER) VALUES (' 1 ', ' 2014 ', 17 JANUARY 14 ', ' 00038615', 'Y');
INSERT INTO DAN_GR7 (ID, FLAG, PERIOD, V_DATE, APP_NUMBER) VALUES (' 1 ', ' 2014 ', 17 JANUARY 14 ', ' 00038623', 'Y');
INSERT INTO DAN_GR7 (ID, PERIOD, V_DATE, APP_NUMBER, FLAG) VALUES (2, 'AND ' 2013', 17 NOVEMBER 12 ', ' 00049625', 'Y');
INSERT INTO DAN_GR7 (ID, PERIOD, V_DATE, APP_NUMBER, FLAG) VALUES (2, 'AND ' 2013', 17 NOVEMBER 12 ', ' 00049615', 'Y');
INSERT INTO DAN_GR7 (ID, FLAG, PERIOD, V_DATE, APP_NUMBER) VALUES (3 ', ' 2012', NOVEMBER 16, 11 ', '00056915',' don't);
HAVE:
ID | PERIOD | V_DATE | APP_NUMBER | FLAG |
1 | 2014 | 17 January 14 | 38615 | THERE |
1 | 2014 | 17 January 14 | 38623 | THERE |
2 | 2013 | 17 November 12 | 49625 | THERE |
2 | 2013 | 17 November 12 | 49615 | THERE |
3 | 2012 | November 16, 11 | 56915 | N |
WANTED:
ID | PERIOD | V_DATE | APP_NUMBER | FLAG |
1 | 2014 | 17 January 14 | 38623 | THERE |
2 | 2013 | 17 November 12 | 49625 | THERE |
Thank you
Select distinct id, period, V_DATE, max (app_number) on app_number (partition by id), flag
of dan_gr7 where the flag = "Y".
V_DATE, APP_NUMBER, ID, PERIOD INDICATOR,
1,2014,1/17/2014,00038623, Y
2 201 311 / 17 / 2012,00049625, Y
Tags: Database
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