Merge Partition - Space Question

We have a large table in 10g which has been partitioned from list. As the time has passed data with a valid value is not in any of the lists of the partitions has been inserted several times. These data fall into the default partition

So we have something like this:

Table ERRORS

Partition E_1 values ('A', 'B', 'C')

Partition E_2 values ('L', ', 'n')-size 600G

Partition by default E_DEFAULT (but contains data of a single value 'Z') - size 50 G

Now the seller would like to fix this by adding the values of 'Z' to E_2.

They offer the following:

ALTER table split partition (partition E_TEMP, E_DEFAULT) E_DEFAULT ERRORS;

ALTER table merge E_TEMP, E_2 partition in partition E_2 ERRORS.

I'm fine with the strategy. I have no doubt that it will work.

I'm afraid that because the size of the partition is so great the merger will require a 650G extra free in the tablespace. Sellers seem to think that it will just add the 50G to 600G.

Looking at the documentation, the merge partition section shows:

"Use the ALTER TABLE ... M ERGE PARTITION statement allows you to merge the contents of two partitions into a single partition. "The two original partitions are deleted, as are all the correspondents index."

This means to me that it takes two and creates a third, thus requiring the 650G of extra free space.

But is this always the case if the third partition is actually one of the two being merged?

For what it's worth, my plan was:

Failure to Split

Change the new partition with an empty temp table

remove the new partition

Edit E_2 to add the new value

Insert ERROR select * from temporary table.

drop temporary table

I think that this requires free space of 50G.

Thank you

My main question, however, and this that I can't test (or do not know how to test) is the solution of partition of merger proposed by the seller requires free space equal to two partitions (in this case 650G) original to work? The seller says no. I think, but can not find documentation or evidence, Yes.

If the seller says no, ask them for proof. I'm not aware that the internal process has been documented. But you should be able to test quite easily.

The only reason why a new segment will be created being is if the data would actually be moved. In order to test whether the data is transferred.

If the data is not moved, it's the same segment as before.

1 put a line in P1 - examine the IDENTIFIER line

2 put a line in P2 - examine the IDENTIFIER line

3 MERGE P2 P1

4. determine if the data transferred - what ROWID changed?

The ID will be different if the data has been moved to a new segment.

create table part_list (State varchar2 (2))
list partition (State)
(values of partition p_ca ('CA'),
values of partition p_wa ('WA'),
values (default) partition p_default
);

insert into part_list values ('CA');

insert into part_list values ('WA');

insert into part_list values ("NV");

Select a State, rowid RID, DBMS_ROWID. ROWID_RELATIVE_FNO (ROWID) fno,

DBMS_ROWID. ROWID_BLOCK_NUMBER (ROWID) blkno,

DBMS_ROWID. ROWID_ROW_NUMBER (ROWID) rowno

of part_list

STATE, RID, FNO, BLKNO, ROWNO

CA, AAAV71AAEAAAAs0AAA, 4, 2868, 0

WA, AAAV72AAEAAAAtEAAA, 4, 2884, 0

NV, AAAV73AAEAAAAtcAAA, 4, 2908, 0

ALTER table merge partitions p_ca, p_wa part_list in the p_ca partition

Select a State, rowid RID, DBMS_ROWID. ROWID_RELATIVE_FNO (ROWID) fno,

DBMS_ROWID. ROWID_BLOCK_NUMBER (ROWID) blkno,

DBMS_ROWID. ROWID_ROW_NUMBER (ROWID) rowno

of part_list

STATE, RID, FNO, BLKNO, ROWNO

CA, AAAV74AAEAAAAtjAAA, 4, 2915, 0

WA, AAAV74AAEAAAAtjAAB, 4, 2915, 1

NV, AAAV73AAEAAAAtcAAA, 4, 2908, 0

Note that the ROWID for 'CA' and 'WA' values are different. This means that the lines have been moved. The file number is the same, but the block numbers have changed as to have the line number for 'WA '.

The fact that existing lines have been moved at all should answer your question about what really makes Oracle. In other words, is NOT just to add the 'WA' line for the existing partitions.

If you do a SPLIT, but the data of the existing partitions is NOT affected, no data movement is performed. Check this example and see that all existing ROWID components remain the same

ALTER table part_list split partition p_default ('OR') values

in (p_or partition, partition p_default)

He has not given "GOLD" in the partition by default so that Oracle has simply ignored this segment and created a new one for the new partition.

Tags: Database

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