missing the conversion of string number of digits

Similar Questions

• the conversion character in number

  Hi all
  
  I want to know., if we can able to convert characters in number as follows.
  
  EG.,.
  
  Select * ABCD;
  
  Values
  --------------------
  four thousand and fifty
  three thousand
  two thousand
  
  I want the o/p as: -.
  
  values
  --------------------
  4050
  3000
  2000
  
  Is it possible to get the desired result. Please help me.
  
  Thanks in advance!

  While oracle provides a nice way to make numbers into words, it provides so much to get back the other way.

  Here's a little something I wrote earlier...

  create or replace function word2num(p_words IN VARCHAR2) return number is
    p_word varchar2(4000) := p_words;
    type mynums is table of number index by varchar2(30);
    type myquals is table of number index by varchar2(30);
    v_nums mynums;
    v_quals myquals;
    v_word VARCHAR2(30);
    v_resval NUMBER := 0;
    v_tmpresval NUMBER := 0;
    v_val    NUMBER;
    v_switch NUMBER := 0;
    FUNCTION get_word(v_str IN OUT VARCHAR2) RETURN varchar2 IS
      v_ret VARCHAR2(30);
    BEGIN
      IF INSTR(v_str,' ') = 0 THEN
        v_ret := v_str;
        v_str := '';
      ELSE
        v_ret := SUBSTR(v_str, 1, INSTR(v_str, ' ')-1);
        v_str := SUBSTR(v_str, INSTR(v_str, ' ')+1);
      END IF;
      RETURN v_ret;
    END;
  begin
    v_nums('ZERO') := 0;
    v_nums('ONE') := 1;
    v_nums('TWO') := 2;
    v_nums('THREE') := 3;
    v_nums('FOUR') := 4;
    v_nums('FIVE') := 5;
    v_nums('SIX') := 6;
    v_nums('SEVEN') := 7;
    v_nums('EIGHT') := 8;
    v_nums('NINE') := 9;
    v_nums('TEN') := 10;
    v_nums('ELEVEN') := 11;
    v_nums('TWELVE') := 12;
    v_nums('THIRTEEN') := 13;
    v_nums('FOURTEEN') := 14;
    v_nums('FIFTEEN') := 15;
    v_nums('SIXTEEN') := 16;
    v_nums('SEVENTEEN') := 17;
    v_nums('EIGHTEEN') := 18;
    v_nums('NINETEEN') := 19;
    v_nums('TWENTY') := 20;
    v_nums('THIRTY') := 30;
    v_nums('FORTY') := 40;
    v_nums('FIFTY') := 50;
    v_nums('SIXTY') := 60;
    v_nums('SEVENTY') := 70;
    v_nums('EIGHTY') := 80;
    v_nums('NINETY') := 90;
    v_quals('HUNDRED') := 100;
    v_quals('THOUSAND') := 1000;
    v_quals('MILLION') := 1000000;
    v_quals('BILLION') := 1000000000;
    v_quals('TRILLION') := 1000000000000;
    v_quals('QUADRILLION') := 1000000000000000;
    v_quals('QUINTILLION') := 1000000000000000000;
    v_quals('SEXTILLION') := 1000000000000000000000;
    v_quals('SEPTILLION') := 1000000000000000000000000;
    v_quals('OCTILLION') := 1000000000000000000000000000;
    v_quals('NONILLION') := 1000000000000000000000000000000;
    v_quals('DECILLION') := 1000000000000000000000000000000000;
    v_quals('UNDECILLION') := 1000000000000000000000000000000000000;
    v_quals('DUODECILLION') := 1000000000000000000000000000000000000000;
    LOOP
      EXIT WHEN p_word IS NULL;
      v_word := get_word(p_word);
      BEGIN
        v_val := v_nums(v_word);
        v_resval := v_resval + v_tmpresval;
        v_tmpresval := v_val;
      EXCEPTION
        WHEN NO_DATA_FOUND THEN
          BEGIN
            v_val := v_quals(v_word);
            IF v_val >= v_switch THEN
              v_resval := v_resval*v_val;
            END IF;
            v_tmpresval := v_tmpresval*v_val;
            v_switch := v_val;
          EXCEPTION
            WHEN NO_DATA_FOUND THEN
              DBMS_OUTPUT.PUT_LINE('Error In Number String : '||v_word);
          END;
      END;
    END LOOP;
    v_resval := v_resval + v_tmpresval;
    RETURN v_resval;
  END;
  /
  
  SQL> col result format 9999999999999999999999999999
  SQL> select word2num('FOUR TRILLION THIRTY THOUSAND SEVENTY FOUR') as result from dual;
  
                         RESULT
  -----------------------------
                  4000000030074
  
  SQL>
  

  Published by: BluShadow on September 3, 2009 13:35
  Please note that the management of exceptions is not set up ideally. This function was created for fun.

• Table 1 d to the Conversion chain

  Hello

  How can I convert a D 1 String table?

  Please find the attached VI.

  -mfp.

  Hi mfp.

  I don't know what your question is about. When I look at your code, I see a table which is an array of 2D channels where index you some lines (I have a feeling you want columns).

  Not to mention you want to get two characters in strings and which convert to digital.

  Your table is empty (please fill with the data, right-click on the table and select "Operations on the data-> default font of the current value" before posting).

  You can directly index since a table 2D in unique items by adding an entry in the column index as well as the function "array index.

  Or you could feed the column of strings in the function 'hexadecimal string number

  Tone

• ORA-06502: PL/SQL: digital error: error in the conversion of char to number

  Hello world.

  I have a strange problem here. I'll try to explain better. I work with APEX 4.2 and of Oracle Database 11 g Enterprise Edition Release 11.2.0.3.0 - 64 bit Production.

  Here are my parameters NLS_SESSION_PARAMETER and NLS_DATABASE_PARAMETER: NLS_NUMERIC_CHARACTERS,.

  
  

  I have a table with a lot of body numbers, and when I imported a MS Access application data, all fields were imported with the comma as decimal separator.

  
  

  Now, I have a form with several fields of number and when I leave a numeric field, a body of numbers of amount total is calculated and automatically filled with a bit of javascript.

  
  

  Now the problem: calculating fields (sum) succeeds only when I use the decimal as the delimiter. If I use the comma, I get a NaN value in the total amount field. I managed to convert all commas in points with javascript, so the total amount is calculated.

  When I try to save the record, I get the error: ORA-06502: PL/SQL: digital error: error in the conversion of char to number because I'm trying to save the separator point in my number fields.

  
  

  I tried to use REPLACE function to replace the. by one, before winning but does not solve the problem.

  
  

  This sounds familiar to anyone?

  
  

  Thanks in advance.

  
  

  
  

  OK, the problem is solved people.

  Somehow, the registration procedure had an influence on another calculation of my form and the error came from this process. So I put a to_number and replace stated in the calculation and all records very well and it shows my total.

• string conversion appropriate type based on the content of string

  Hello

  I have a CSV with string values, and I want to assign them to good type in labview, then assing them to some pre-existing teststand properties.

  I think a particular way in a digital chain of detection should be in labview somewhere, but I can't seem to find it.  There is certainly decimal string number and string of fractional number, but an error during their passage of a string like "blah".  They just return 0.

  So my main challenge here is to feel a digital channel, either with a single point decimal or not and the impression that it is a 'number '.

  Example:

  Takes the string->

  1.234-> is the number

  1234-> is the number

  192.168.1.12-> is not a number

  I could write a vi to do this, but I was wondering if it wasn't already obvious tool in labview, which is escaping at that time.  I don't like to reinvent the wheel, even for something so simple.

  Thank you

  David J.

  david_jenkinson wrote:

  So my main challenge here is to feel a digital channel, either with a single point decimal or not and the impression that it is a 'number '.

  Example:

  Takes the string->

  1.234-> is the number

  1234-> is the number

  192.168.1.12-> is not a number

  In the more general case, you must also be able to properly analyze, for example - 10e6, 85.83E - 3 and such good number to floating point. Also your last example is basically a number U32, just formatted in the style of IP address.

  You must use 'analysis of the string' %f format and NaN as a default value. Then also check if the string is an empty string. If this isn't the case, then it is not a number according to your narrow definition.

  

• How to concatenate the string with a digital command?

  Hello

  How to concatenate the string with a digital command?

  Thank you.

  

  I think I forgot to add the semicolon, what you can do is, drag the CONCATENATE function and add semicolon.

• In Keithley 2410, string number read voltage conversion

  Hello

  I want to drive the current and voltage with Keithley 2410 to read.

  However, I can read the correct voltage value in the screen of the device, I can't read the correct voltage value in the display of laboratory program. The problem occurs while the voltage read (string) is converted to a number. I use String Fract/Exp number for this. However, I can read only the first digit of the value. for example, in the screen of the device, I read 1.3784e - 5 (the actual voltage value), in the indicator of software, I have read only 1.

  I am new to laboratory. can someone help me on this you problem.

  My Magic 8-Ball says that your system settings have the comma is the decimal separator.  The Keithley instrument will always be the decimal point as the decimal separator.  Fortunately, there are a Boolean input on the Fract/Exp to string number which affects whether to use the system separator.  Make sure you set that to FALSE.

• Serial number is not valid. I went to the conversation of support and they directed me here.

  I get this error here: incorrect serial number. This isn't a valid serial number. Please go back and re enter the serial number. I went to the conversation of support and they had me on their cat for 45 minutes. Finally, they said to go on the forums.

  Remind you that serial number is from a previous PC that we replace. Please contact me with assistance.

  Hi drichmond,

  Could you please post a screenshot of the screen when you enter the serial number?

  Would it not be possible to send the serial number via private message?

  Here is a link to 'How to send private message'?- How can I send a private Message

  Please follow the steps given in this link -error: "serial number is not valid for this product". Adobe Creative Suite .

  Let us know the results.

  Thank you!

  Shivam

• Impossible to retrieve the serial number (no invoice number of digital river useless for the adobe customer service) - how can this be resolved

  I bought PS CS5 of adobe business store 3 years ago - the serial number does not show under my account

  Contact customer via chat and they can't help me because the invoice from the adobe site is provided by digital river and they are unable to track the purchase - they need to order number that is not on the invoice

  I don't understand how adobe can not keep a purchase according to the invoice is provided on their own Web site

  The site gave me a hotline number that has a message recorded for products CS saying Adobe does not offer telephone support for products cs - go to site

  A bit frustrating - the reception in Sydney adobe phone number even goes to a messaging speech just as the number of licenses in volume on the invoice

  Anyone at adobe can really help? -even find one at the end of a phone would be a good thing.

  Thanks in advance

  Simon

  Hi Simon

  Volume licensing and their serial numbers can be retrieved from the Web Site licenses (LWS) - see site licenses Adobe | Serial numbers | Orders | Accounts

  Thank you

  Bev

• Why can't change anything after the conversion in .docx?  Missing functions the tool bar?

  Why can't change anything after the conversion in .docx?  Missing functions the tool bar?

  Hi larrys57575985,

  To change a file that you converted to Word format, you will need to download it first and then open it in Word. To download your file, sign in to your account on https://cloud.acrobat.com/files, select the file you want to download and click download at the top of the list of files. Your file will be downloaded in the download on your computer folder. In Word, you may need to click Activate the change at the top of the document.

  Best,

  Sara

• Largest number of digits for the NUMBER data type?

  What length more of a NUMBER that Oracle will "support"?

  The documentation says the following:

  Limitations of the data type says:

  «Can be represented in a comprehensive precision 38 digits»

  NUMBER of Data Types says:

  "Oracle guarantees portability of numbers with precision of up to 20 digits of base-100, which equals 39 or 40 decimal digits according to the position of the decimal point."

  I realize account that if I define a column as simply NUMBER, I can insert numbers with a size up to 126 characters.  However, Oracle seems to maintain only the first 40 digits in MOST cases.  The largest number of digits, it seems to allow is 40 before it begins to be replaced by 0.

  With numbers that have more than 40 figures, Oracle will sometimes replace all numbers according to the 38th numbers with a 0 and sometimes replace 0 after the digit 39th or 40th.

  Therefore, what is the largest number of digits, can be trusted to safely store Oracle?

  This is the code I used for this testing process.

  create the table max_num (num number);

  declare

  number of l_x;

  Start

  for x in 1.200

  loop

  l_x: = x;

  insert into max_num values (rpad (1, x, 1));

  end loop;

  exception

  while others then

  dbms_output.put_line ('STOP: ' | l_x);

  dbms_output.put_line (SQLERRM);

  end;

  /

  Select num, length (replace (num, 0)) of max_num;

  What length more of a NUMBER that Oracle will "support"?

  You have already given your own answer. If 'length': the maximum number of digits is written the doc gives you the answer:

  999... (38 9's) x 10 value maximum¹²⁵

  The 38/39/40, hereinafter referred to as the doc means "significant digits". This is why rounding or truncation occurs if you provide more significant digits of 38/39/40.

  Oracle stores the numbers internally in a binary format 21 bytes using a documented structure in the doc of the OIC in the section 'NUMBER'.

  http://docs.Oracle.com/CD/E11882_01/AppDev.112/e10646/oci03typ.htm#i423684

  Oracle database stores the values of the NUMBER data type in a variable length format. The first byte is the exponent and is followed by 1 to 20 mantissa bytes. The high bit of the exponent byte is the sign bit; It is defined for positive numbers, and it is cleared for negative numbers. The lower 7 bits represent the exponent, which is a number of base-100 with an offset of 65.

  This article from doc continues to show you how to convert the internal format to the real value.

  An additional byte of 1 is used for all types of data to store the length; That's why you often see docs saying numbers can take 22 bytes.

• Missing foreign character in the conversation display sets

  I chat with several friends in different countries (Norway, Germany, Czech Republic). I have sets of characters for these languages installed in windows.

  When I write a message in the message box, the characters appear as they should. But after clicking on entry, the message appears in the conversation area with foreign characters as empty boxes. This used to be not a problem: the foreign letters displayed correctly my message box and the conversation area.

  I think that something happened during an upgrade "to improve my Skype experience" because she seems to start to happen at the same time that several new emoticons is appeared.

  How can I reset it back as it was before (and I'm not really sure what "it" is).

  Thank you

  Richard

  Tools-> Options-> appearance IM: is the cat police, the default Segoe UI?

• The clob to string conversion

  In the database for a column of type clob I value as follows:
  

  <span style="FONT-SIZE: 11pt; LINE-HEIGHT: 115%; FONT-FAMILY: 'Arial Narrow','sans-serif'; mso-bidi-font-family: 'Times New Roman'; mso-fareast-font-family: Calibri; mso-fareast-theme-font: minor-latin; mso-bidi-theme-font: minor-bidi; mso-ansi-language: EN-US; mso-fareast-language: EN-US; mso-bidi-language: AR-SA">AIRPORT IS OPEN 24 HRS <span style="mso-spacerun: yes"> </span></span>
  <p></p> 

  I want to get the value as string output... I don't want all these tags html... I found an article like the one mentioned below, but still it gives me only clob value
  

  dbms_lob.substr( clob_column, for_how_many_bytes, from_which_byte );
  
  for example:
  
    select dbms_lob.substr( Column, 4000, 1 ) from Table;

  That's a big if, but if the HTML content is in fact XHTML, we can do this:

  SQL> with my_table (my_clob) as (
    2    select to_clob(q'#AIRPORT IS OPEN 24 HRS  
    3  
  #')
    4    from dual
    5  )
    6  select '"' ||
    7         xmlcast(xmlparse(content my_clob) as clob)
    8         || '"' as result
    9  from my_table ;
  
  RESULT
  --------------------------------------------------------------------------------
  "AIRPORT IS OPEN 24 HRS  "
   
  

  (Different methods are available depending on the version, works on 11.2 above)

• Optimize the conversion of SGL data chain

  As the title indicates, I'm looking to pronounce on a more efficient way (as appropriate) to convert a string into an array of SGL.

  The detachment is just to get feedback on the best ways of doing things from a personal educational point of view. I don't actually have to improve performance... (Just keep improving my skills of codeing.)

  'More effective' here must take to be less cycles of CPU and low memory footprint, in that order. (That is, most small load on CPU is preferred, if smaller memory footprint is at the expense of the other cycles CPU, the hit on memory footprint is preferred).

  The length of the input string comes from a TCP read and contains only the raw bytes of the expected (in this case, SGL) format without any header/footer of meta-data.

  Currently, my implementation is very simple and given that the expected table size is known, I am relying on the loop being smart in his automatic indexation allowance.

  For the conversion, I do a right type-Gallery of 4 characters at once.

  

  The code below, the for loop is simply intended to give a 'real' output boolean if the string length is the length of expected as determined by the input string 'number of track points. No additional error handling is required or necessary.

  I suspect the "subset of string" combined with the iterations (for loop) are the two worst performance in this VI hits, but I can't think of a good way to do the conversion as a table, and if I could, then I should at least do a conversion in 'string to array U8' first.

  Thanks to all who took the time to read and watch. Your time and your contribution is appreciated as always!

  Q

  Hi Q,

  Why don't convert you directly in a table of SGL? No need of a loop FOR, nor for StringSubset...

• A design of query for the conversion of time difference in days, hours, Minutes

  Hi all

  A design of query for the conversion of time difference of time in number of days remaining remaining hours minutes and rest in seconds. Made this one till now. Please suggest for all modifications, until now, it seems to work very well, kindly highlight for any anomaly.

  WITH DATA (startDAte, EndDate, Datediff) AS (SELECT to_date ('2015-10-01 10:00:59 ',' yyyy-mm-dd hh24:mi:ss'), to_date ('2015-20-01 03:00:49 ',' yyyy-mm-dd hh24:mi:ss'), to_date('2015-10-01 10:00','yyyy-dd-mm hh24:mi:ss')-to_date('2015-20-01 03:00','yyyy-dd-mm hh24:mi:ss') FROM dual)

  UNION ALL SELECT to_date ('2015-10-01 10:00:39 ',' yyyy-mm-dd hh24:mi:ss'), to_date ('2015-20-01 03:00:40 ',' yyyy-mm-dd hh24:mi:ss'), to_date('2015-10-01 10:00','yyyy-dd-mm hh24:mi:ss')-to_date('2015-20-01 03:00','yyyy-dd-mm hh24:mi:ss') FROM dual

  UNION ALL SELECT to_date ('2015-11-01 10:30:45 ',' yyyy-mm-dd hh24:mi:ss'), to_date ('2015-11-01 11:00:50 ',' yyyy-mm-dd hh24:mi:ss'), to_date('2015-11-01 10:30','yyyy-dd-mm hh24:mi:ss')-to_date ('2015-11-01 11:00 ',' yyyy-mm-dd hh24:mi:ss') FROM dual

  UNION ALL SELECT to_date ('2015-11-01 09:00:50 ',' yyyy-mm-dd hh24:mi:ss'), to_date ('2015-11-01 10:00:59 ',' yyyy-mm-dd hh24:mi:ss'), to_date('2015-11-01 09:00','yyyy-dd-mm hh24:mi:ss')-to_date ('2015-11-01 10:00 ',' yyyy-mm-dd hh24:mi:ss') FROM dual

  UNION ALL SELECT to_date ('2015-11-01 08:30:49 ',' yyyy-mm-dd hh24:mi:ss'), to_date ('2015-11-01 09:30:59 ',' yyyy-mm-dd hh24:mi:ss'), to_date('2015-11-01 08:30','yyyy-dd-mm hh24:mi:ss')-to_date('2015-11-01 09:30','yyyy-dd-mm hh24:mi:ss') FROM dual

  )

  Select

  trunc ((EndDate-StartDate)) days.

  trunc (((enddate-startdate)-to_number (trunc ((enddate-startdate))) * 24) hours)

  trunc (to_number (((enddate-startdate)-to_number (trunc ((enddate-startdate))) * 24-trunc (((enddate-startdate)-to_number (trunc ((enddate-startdate))) * 24)) * 60) Minutes,))

  (to_number (((enddate-startdate)-to_number (trunc ((enddate-startdate))) * 24-trunc (((enddate-startdate)-to_number (trunc ((enddate-startdate))) * 24)) * 60 - trunc (to_number (((enddate-startdate)-to_number (trunc ((enddate-startdate))) * 24-trunc (((enddate-startdate)-to_number (trunc ((enddate-startdate))) * 24)) * 60)) * 60 seconds))))

  data;

  Thanks for the answers in advance.

  AHA!

  TO_TIMESTAMP expects a string as input, so it first makes an implicit conversion from DATE to a string, in the format of NSL_DATE_FORMAT.

  To convert the TIMESTAMP DATE independently NLS_DATE_FORMAT, use

  CAST ( AS TIMESTAMP)