name of the foreign key column

I'm new to the SQL Developer Data Modeler, I try to use it so that I can recommend to peers.

in the logic model, I created 2 entities:

entity: order_headers

attributes: header_id (primary key), order_number

entity: order_lines

attributes: line_id (primary key), item_code

and then I create a relationship 1: n to order_headers to order_lines

Now if I find out the attributes of order_lines, there are 3 attributes:

line_id, item_code and header_id

I do an "engineer of the relational model

in the Relational_1, I see that my order_lines table has a field: order_headers_header_id

How can I configure step 'Engineer to the relational model' to use 'header_id' instead of 'order_headers_header_id '?

I use Oracle SQL Developer Data model version 4.0.1.836 build 836

Hello

You must change the name for "Foreign key column" model in the design properties dialog box - "settings > Naming Standard > models.

It should be {column Ref} only to get required name.

Philippe

Tags: Database

Similar Questions

  • Term plurals changes the name of the foreign key in the relational model

    Hello

    I use a glossary with plurals for entities such as Budget turned to the budgets of the table in the relational model. Unfortunately (for me) it also changes the name of the foreign key. In the related entity, an attribute (for example) is Budget_fiscal year, I expect in the relational model, being the same, but it is transformed into budgets_fiscal_year (budgets in the plural rather than keep him in singular form).

    How can I avoid any change in the attribute names (in the process of engineering in the relational model) but always turn the names of entities from the singular to the plural names for tables?

    Thank you and best regards

    Robert

    Hi Philippe

    Your suggestion 1) works - thank you! budgets_fiscal_year is the attribute of pk exercise in my budget of the entity. It seems a standard behavior of the Data Modeler to compose the UID of the relationship of budgets_fiscal_year (for some reason, this column is not taken the logical model, but the relational model). I would prefer that it be appointed budget_fiscal_year.

    I have not defined any parameter for this (intentionally). But maybe somewhere there by default. Could you tell me where the design parameters in Data Modeler to learn how to configure the definitions mentioned in 2)?

    As I'm always busy with the model of reverse engineering data, I'll wait for DM 4.1.1.888.

    Best regards

    Robert

  • How knowledge column expression defined in the foreign key?

    Guys,

    How do I know what defined in the foreign key column expression?

    Thank you
    Hari

    Hello

    If you have permissions on this table, use all_cons_columns view.

    Kind regards

  • Rename the foreign key constraint

    Hello

    I have table tbl_a with a column a_col1 SEO tbl_b.b_col1

    I want to create the name of the foreign key as FK_A_COL1 constraint which is FK_ < COLUMN NAME OF the CHILD >.

    Foreign naming key standards does not have the use of the name of the child under the name column.

    Is there any other solution/script to achieve this?

    Thank you.
    fkeys = model.getFKIndexAssociationSet().toArray();
    for (var i = 0; i;//also can use fk.getTable().getAbbreviation()fkname = "FK_"+fk.getTable().getName();cols = fk.getColumns();for( var k = 0;k
    
                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                    
    
  • Identify the foreign key table

    I have a table that has a few constraints that are foreign keys to other tables (see column FK_ETHNIC below). My naming conventions are consistent so they all start with 'FK_ ". In SQL, how can I find the table that the foreign key column references? I have a process that must find this table and then get all of its columns.
    Thank you!

    CREATE TABLE STU_BASE
    (PK_ID VARCHAR2 (32), sys_guid() by default)
    CONSTRAINT pk_stu_base
    KEY ELEMENTARY SCHOOL
    With the HELP of INDEX TABLESPACE sis_express_index
    STORAGE (INITIAL 524288
    NEXT 524288
    PCTINCREASE 0),.
    STUDENT_ID VARCHAR2 (15).
    Fk_stu_base_ethnic FK_ETHNIC VARCHAR2 (32) CONSTRAINT
    REFERENCES
    Ethnic (PK_ID)
    REMOVE THE NULL VALUE;

    CREATE TABLE ETHNIC
    (PK_ID VARCHAR2 (32), sys_guid() by default)
    CONSTRAINT pk_ethnic
    KEY ELEMENTARY SCHOOL
    With the HELP of INDEX TABLESPACE sis_express_index
    STORAGE (4096 INITIAL
    NEXT 4096
    PCTINCREASE 0),.
    VARCHAR2 (2) ETHNIC,.
    ETHNIC_DESC VARCHAR2 (30),
    STATE_CODE VARCHAR2 (2),
    FEDERAL_CODE VARCHAR2 (2))

    You could do a self-join with CONSTRAINTS (USER, ALL, s/n) views. You can search a constrainttype of 'R' and you can attach it to itself based on the R_OWNER and R_CONSTRAINT_NAME columns.

    For example:

    SELECT r1.owner      AS child_owner
         , r1.table_name AS child_table
         , r2.owner      AS parent_owner
         , r2.table_name AS parent_table
    FROM   all_constraints r1
    JOIN   all_constraints r2 ON  r2.owner           = r1.r_owner
                              AND r2.constraint_name = r1.r_constraint_name
    WHERE  r1.constraint_type = 'R'
    ;
    

    Published by: Centinul on February 16, 2012 15:36

  • How can I get the data in the foreign key?  PHP/mysql

    I managed to create registration, log-in and results pages appear for accounts of client with PHP/Mysql/Dreamweaver 8. I have another page for more information to be contained in a child table, I used the Insert Wizard to create. I can't make it work. I get either a foreign key cannot be null error or a foreign key constraint.

    If I include the foreign key in the form on the page, I can manually enter the appropriate identification number, and it works. How to automatically enter the id into the foreign key column?

    I got the authentication of users using e-mail, password and user type.

    Thanks for your help

    When someone connects, Dreamweaver creates a session variable called $_SESSION ['MM_Username"]. Use this session variable to create a recordset object to get the ID of the user, who can then be entered in the child table's foreign key field.

    Dreamweaver automatically updates the code for recordsets immediately above the DOCTYPE declaration, then you will need to move above the code for the server behavior insert record. So it must be in the following order:

    1. Recordset to get the user ID
    2. Insert the record to the child table
  • Rename the Parent - foreign key columns

    I need to rename a bunch of parent columns that are referenced in the foreign key constraints. Is it possible to get the child column get automatically updated with the new name of the parent column?

    IE, I have a table named 'subject' with a PK named subjectID. I have a child table addresses that child has a FK to subject.subjectID and the column is automatically named subject_subjectID.

    Now, I want to rename just subject.subjectID "ID". I want this rename also take place in the referencing table "address" so the name change should be translated as subject_ID.


    Thank you!

    You can set {ref column} as for 'Foreign key column' "tools > preferences > Data Modeler > designation standard > Templates.
    And to request that it uses "Apply to keys and constraints naming standards" in the context menu for relational model in the browser tree. Select only "foreign key column" it.

    Philippe

  • Can I remove Logical columns that I will not use in the layer of presentation as the id or foreign key columns?

    Hello

    Can I remove Logical columns at the level of the business layer that I'm not going to use the layer of presentation as the ID or foreign key columns? It will not affect the relations to the business layer?

    Kind regards

    Nestor

    Hi Nestor,.

    It won't unless they are used as keys, columns sort order, the ID column or the likes. But you can leave them in the MDB layer and expose just in the presentation layer - just in case you need it later. It is not use all the resources or generate overhead. More: Developer of the RPD should be used to work with loads of columns

  • Add the foreign key refers to a different schema

    Hello

    We have a database with schemaA and schemaB and we use a data model for schemaA with SQL Data Modeler.

    Our data model is based on SchemaA and we do not want add schemaB or create subview in our current model for schemaB since our dev team do not want schemaB in the model

    We have created a synonym in tableB schemaB shcemaA after granting select them, references to schemaA

    We have added a foreign key on tableA in referencing TableB on schemaB schemaA.

    for example. Add ALTER table tableA foreign constraint key(column-name) references tableB(colum-name)

    So far so good.

    But if we try to produce the DDL for tableA it has not provided the ALTAR of the foreign key that is based on shcmeaB

    We know that we cannot add foreign key on dblinks.

    How can I get the Modeler DDL from SQL data for tableA, including the foreign key

    We appreciate the answers

    Kind regards

    Zafar

    Hi zak,.

    We have created a synonym in tableB schemaB shcemaA after granting select them, references to schemaA

    We have added a foreign key on tableA in referencing TableB on schemaB schemaA.

    You can do it in the database because TableB exists in the database and DB knows its definition, including the existing constraint of PK/UK.

    This is the same model of data Modeler - you must have the definition of the table referenced in order to create the FK that refer to the constraint of PK/UK.

    As it works now (we can change it) you can have modeled for SchemaA and ModelB for SchemaB. Then, you can drag & drop tableB form the Navigator to the diagram of the ModelA and TableB there will exist as an object remote read-only, you can use to create the FK.

    With the help of subviews, DDL generation and configurations of reports, you can display the dev team than objects that they want to see - on the charts in generated DDL and reports.

    Philippe

  • Please, I have the following question on the foreign key and the ora-00904

    Thanks in advance!

    I created the table:

    Create the Department table
    (
    DNAME varchar (15) NOT NULL,
    deptID number (5) NOT NULL,
    Primary key (dname, deptid)
    )

    then...

    Create table Manager
    (
    MgrID number (10) not null,
    Not null, name varchar (10)
    Start_date date not null,
    Primary key (mgrid),

    CONSTRAINT fk_department
    FOREIGN KEY (dname, deptip)
    Department of REFERENCES (dname, deptid)
    )

    Trying to create the table with the constraint, it yeilds one:

    ORA-00904: "DNAME": invalid identifier
    +.. .with an asterisk under "dname" in line: FOREIGN KEY (dname, deptip) +.

    I tried joining my name of the column with quotation marks ("" "); capitalized for consistency; and we tried creating and editing then - all to nothing will do. I also tried to use the user interface with Oracle Express Edition and the moment where I click on create, the same error appears. Could someone help please straighten out me up - was this threat for four days.

    Thanks again!

    Hello

    Welcome to the forum!

    Columns that will reference the other table must be declared just like all the other columns; including the names in a FOREIGN KEY constraint is not auotmatically define them.
    It works:

    CREATE TABLE Manager
    (       mgrid          NUMBER (10)     NOT NULL,
         Name          VARCHAR (10)     NOT NULL,
         Start_date      DATE          NOT NULL,
         dname          VARCHAR2 (15),               -- New
         deptid          NUMBER (5),               -- New
    PRIMARY KEY (mgrid),
         --
    CONSTRAINT fk_department
    FOREIGN KEY           (dname, deptid)
    REFERENCES department (dname, deptid)
    );
    

    (assuming that the departments table, you posted, there).

    Is there a reason why you use VARCHAR instead of VARCHAR2?

    In the departments table, do you really need both dname and deptid in the primary key? For example, if you have a line with name = "ACCOUNTING" and deptid = 10; is it possible that you could have another line with deptid = 10 and some different dname, say 'REASEARCH '? It is more common to only have a deptid as primary key and have columns in the foreign key constraints that reference.

  • SQL statement error INSERT The conflicted with the FOREIGN KEY constraint

    I recently installed a reporting for vmware vsphere software, but I get a SQL error. I opened a request for assistance with vmware, but so far they have not come up with a solution. The error is caused by: com.microsoft.sqlserver.jdbc.SQLServerException: instruction INSERT The conflicted with the FOREIGN KEY constraint 'FK_CB_VSM_NETWORK_VC_ID '. The conflict occurred in database 'VCChargebackVCC02', table "dbo." " CB_VSM_SERVER', column 'VC_ID '. I don't know a lot about SQL, so I'm lost in the extent of troubleshooting is concerned. If anyone has any ideas I'd love to hear them.

    SQL questions are better posed on Technet.  They are better equipped to manage the

    http://social.technet.Microsoft.com/forums/en-us/categories/

  • How can I make sure that changes in a primary key (in the parent table) would also appear directly in the FOREIGN KEY in the child table?

    Forgive my question. I am very new to Oracle.

    How can I make sure that changes in the key primary supplier_id (concerning the supplier table) would also appear directly in the FOREIGN KEY (supplier_id) in the products table?

    Is that not all the primary key and FOREIGN KEY on?

    My paintings:

    I created 2 tables and connect to apply in the data base referential integrity, as I learned.

    CREATE TABLE - parent provider

    (the numeric (10) of supplier_id not null,)

    supplier_name varchar2 (50) not null,

    Contact_Name varchar2 (50).

    CONSTRAINT supplier_pk PRIMARY KEY (supplier_id)

    );

    CREATE TABLE - child products

    (the numeric (10) of product_id not null,)

    supplier_id numeric (10) not null,

    CONSTRAINT fk_supplier

    FOREIGN KEY (supplier_id)

    REFERENCES beg (supplier_id)

    );

    I inserted the following text:

    INSERT INTO provider

    (supplier_id, supplier_name, contact_name)

    VALUES

    (5000, 'Apple', 'first name');

    I expect that the supplier_id (5000) to the provider of the table also appears in the products table under key supplier_id having the same value which is 5000. But this does not happen.

    How to get there?

    Thanks in advance!

    Hello

    What is a foreign key in Oracle?

    A foreign key is a way to ensure referential integrity in your Oracle database. A foreign key means that the values of a table must appear also in another table.

    Ok!??

    What is now the right way to implement referential integrity in your Oracle database that the values of a table must also be included in another table?

    A foreign key referential integrity indeed enfore in ensuring that the value in the child table must have a corresponding parent key (otherwise you will encounter an error, as evidenced by "SomeoneElse"). However, it will never automatically insert a row in the other table.

    If you are looking for a solution that automatically inserts a record in the other table, maybe you should go for triggers:

    See:

  • How to refer to the primary key column of newly inserted rows of tabular form

    Hello

    I use APEX 4.2.0.00.27 with Oracle DB 11.2.0.3.0.

    I work with a tabular presentation wizard-created for insert and update a table using the integrated SRM process (sequence 10).  I'm trying to use a process of anonymous block of PL/SQL (sequence 30) to make another manipulation of table after the records were inserted or updated.  The manual process is associated with my tabular form and I use the variables of name of column binding in my program block.

    My (rsn_test) table has 3 columns: test_id (number), test_nbr (number), test_id2 (number).  Test_id column is identified as the primary key and the type of the source already exists a sequence rsn_test_seq.  Column test_id2 gets its default value 0 to a hidden page element.

    I would use my manual process for updating the value of the test_id2 column.  If it's 0 then I want to put the value of the column test_id.  If it is any other value, then it must remain at this value.  My logic works very well for an existing line, but I'm running into a problem with the newly added lines.  The new lines get inserted, but the test_id2 column remains the default value 0.  I can tell the debugger that the SRM process is triggered first and inserts the line, then my manual dealing with fires.  The problem seems to be that the connection variable: TEST_ID for the primary key column remains NULL after insertion.  I don't know how to get the value of the column test_id of my newly created line to use in my PL/SQL block to my update.

    Process of PL/SQL:

    DECLARE
    BEGIN
       :P7_SHOW := NULL;
       :P7_SHOW := NVL(:TEST_ID2,555) || ' and ' || NVL(:TEST_ID,787) || ' and ' || NVL(:TEST_NBR,9999);
       IF :TEST_ID2 = 0 AND :TEST_ID IS NOT NULL THEN
          UPDATE rsn_test
             SET test_id2 = :TEST_ID
           WHERE test_id = :TEST_ID;
       ELSE
          :TEST_ID2 := :TEST_ID2;
       END IF;
    END;
    
    

    Excerpt from the debugger:

    0.01625 0.00010 Processes - point: ON_SUBMIT_BEFORE_COMPUTATION
    0.01635 0.00008 Branch point: Before Computation
    0.01643 0.00003 Process point: AFTER_SUBMIT
    0.01646 0.00022 Tabs: Perform Branching for Tab Requests
    0.01668 0.00008 Branch point: Before Validation
    0.01676 0.00024 Validations:
    0.01700 0.00135 Perform basic and predefined validations:
    0.01835 0.00020 Perform custom validations:
    0.01855 0.00049 ...Validation "TEST_NBR must be numeric" - Type: ITEM_IS_NUMERIC
    0.01904 0.00007 ......Skip for row 1 because row hasn't changed
    0.01911 0.00016 ......Skip for row 2 because row hasn't changed
    0.01927 0.00012 ...Validation "TEST_ID2 must be numeric" - Type: ITEM_IS_NUMERIC
    0.01939 0.00007 ......Skip for row 1 because row hasn't changed
    0.01945 0.00018 ......Skip for row 2 because row hasn't changed
    0.01964 0.00005 Branch point: Before Processing
    0.01968 0.00004 Processes - point: AFTER_SUBMIT
    0.01972 0.00588 ...Process "ApplyMRU" - Type: MULTI_ROW_UPDATE
    0.02560 0.00154 ...Execute Statement: declare function x return varchar2 is begin begin for c1 in ( select "RSN_TEST_SEQ".nextval pk from sys.dual ) loop return c1.pk; end loop; end; return null; end; begin wwv_flow.g_value := x; end;
    0.02714 0.00140 ......Row 3: insert into "APPPCSRSN"."RSN_TEST" ( "TEST_ID", "TEST_NBR", "TEST_ID2") values ( :b1, :b2, :b3)
    0.02854 0.00011 ...Process "ApplyMRD" - Type: MULTI_ROW_DELETE
    0.02865 0.00004 ......Skip because condition or authorization evaluates to FALSE
    0.02869 0.00015 ...Process "Process Submit" - Type: PLSQL
    0.02884 0.00007 ......Skip for row 1 because row hasn't changed
    0.02891 0.00012 ......Skip for row 2 because row hasn't changed
    0.02903 0.00012 ......Process row 3
    0.02915 0.00429 ...Execute Statement: begin DECLARE BEGIN :P7_SHOW := NULL; :P7_SHOW := NVL(:TEST_ID2,555) || ' and ' || NVL(:TEST_ID,787) || ' and ' || NVL(:TEST_NBR,9999); IF :TEST_ID2 = 0 AND :TEST_ID IS NOT NULL THEN UPDATE rsn_test SET test_id2 = :TEST_NBR WHERE test_id = :TEST_ID; ELSE :TEST_ID2 := :TEST_ID2; END IF; END; end;
    0.03344 0.00013 ...Session State: Saved Item "P7_SHOW" New Value="0 and 787 and 1300"
    0.03356 0.00004 Branch point: After Processing
    0.03360 0.00048 ...Evaluating Branch: "AFTER_PROCESSING" Type: REDIRECT_URL Button: (No Button Pressed) Condition: (Unconditional)
    0.03407 0.00013 Redirecting to f?p=290:7:8717971109610:::::&success_msg=0%20row(s)%20updated%2C%201%20row(s)%20inserted.Success%2FEBD244168556408CBA714E3974918C09%2F
    0.03420 0.00012 Stop APEX Engine detected
    0.03432 0.00007 Stop APEX Engine detected
    0.03439 - Final commit
    
    

    Any suggestions?

    I have run tests on

    https://apex.Oracle.com/pls/apex/f?p=83488:1 demo/demo

    to see your problem.

    I have 2 solution for your problem.
    I add trial NOT tabular just usual block of PL/SQL

    BEGIN
    I'm IN (SELECT TEST_ID FROM RSN_TEST WHERE TEST_ID2 = 0)
    LOOP
          UPDATE RSN_TEST
             SET test_id2 = TEST_ID
           WHERE test_id = i.TEST_ID;
      END LOOP;
    END;

    and works very well, you can see in the sample.

    The other solution is to show new generated TEST_ID

    Adding a sequence as a default value for a column in a table field

    And to execute your procedure.

    I get how is with the good luck of time.

    By

  • Renaming of the foreign keys in the relational model

    Hello


    I'm new to the Data Modeler, we use v 3.0.0.66.5 and Oracle 11 g, and I am trying to build a logic and a relational model for a new application.

    We always call our primary keys as the ID, this causes me a problem with my names of foreign keys in the relational model, as they show as ID #. Is it possible to add the abbreviated of the table of the foreign key?

    Thanks in advance

    Sue

    Yes it is.

    Take a look at the tools > preferences, select Data Modeler > naming Standard > model, you can specify the standard you want to use for your foreign key. You can apply this designation to existing models and all new created FK uses the same model. To apply the standard to existing templates, select the relational model in the browser, right-click to display the context menu and select the menu "apply Naming standards... ».

    Sue

  • How can I update the primary key column

    Hello
    Can you suggest me best workaround/algorithm for task below:

    (Oracle 10g, Solaris OS.)
    Location:
    Table a primary key column P 'Code', tables children F1, F2,..., reference to F15 "Code_P' foreign key column"P.Code"column, and we do not know which of the child tables data available for a particular value"P.Code.
    Task:
    Change the value "P.Code" from 100 to 200. So that the result would be that record P [Code = 100] should be updated:
    update P set
    Code = 200
    where Code = 100;
    And child tables 'Code_P' column should be updated as:
    update F1, F2, .., F15 set
    P_code = 200
    where P_code = 100;
    The best solution would be that you can easily repeat this task.

    Edited by: CharlesRoos the 28.12.2010 12:10

    Will there be FK constraints in place?
    If so, you may need to modify them so that their application may be temporarily deferred.

    The gameplan would be something like this:

    -Making of CF can be deferred, immediate departure.
    -Alter FK set delay.
    -Update of Parent table.
    -Update of the children tables.
    -Immediate constraints set
    s ' engage;

Maybe you are looking for

  • TECRA M9 - drivers Vista x64bit

    Can anyone help to track down these x 2 required x 64 bit drivers for Windows Vista? The Device Manager console tree Vista requires the following (unknown drivers) which are actually (1) TOSHIBA HDD Protection - sensor shock (driver for Vista x 64) (

  • Blue Screen Windows 7 on consecutive weeks. Need help with mini dump APC INDEX MISMATCH

    Computer crash on 8/3, and then again on 8/10, around the same time. 8/10 have not spared no dump file, but I was able to get the mini dump 8/3. Microsoft (R) Windows debug 10.0.14321.1024 AMD64 VersionCopyright (c) Microsoft Corporation. All rights

  • payment of the proceeds

    Hey, if you purchase the plan for the year of $49.99, I have to pay throughout the year immediately or can I just pay the monthly cost of $49.99 now?

  • You can never really argue with adobe?

    You can never really argue with adobe? I can't access an option to actually speak with an officer of Adobe.

  • Help drivers HP Pavilion dv3-2013tx Xp

    I like Vista, but then all of my related work program does not work with it and only Compatible XP... Please help me find the driver WINDOWS XP for my Pavilion DV3-2013TX... Please help me!