Newb question: SQL query on an imported table

Similar Questions

• pl - sql query with index by table errors

  Hello once again
  
  I'm stuck again with the following query
  
  I want to display the name of the Department, employee id name count and avg sal
  
  rec type is rendered
  (
  not a number (8.0).
  DNAME varchar2 (40),
  mgr_nm varchar2 (55),
  d_hc number (8.0).
  SAL number (8.2)
  );
  rec1 is the rec index table directory.
  Start
  for rec1 in)
  Select a1.dnm, a1.nm, b.did, b.hc, b.sal
  Of
  (
  Select d.department_id as did e1.first_name |' '|| E1.last_name like nm, d.department_name as dnm
  of hr.employees e1, hr.departments d
  where e1.department_id = d.department_id) a1.
  (
  Select d.department_id as did, count (e1.employee_id) as hc, avg (e1.salary) as sal
  of hr.employees e1, hr.departments d
  where e1.department_id = d.department_id
  D.department_id group) b
  where a1.did = b.did)
  loop
  dbms_output.put_line (REC1);
  end loop;
  end;
  /
  
  my error is
  
  ORA-00900: invalid SQL statement
  
  Help, please
  
  Thank you!!!

  Try this:

  begin
    for rec1 in ( select a1.dnm
                  ,      a1.nm
                  ,      b.did
                  ,      b.hc
                  ,      b.sal
                  from ( select d.department_id as did
                         ,      e1.first_name||' '||e1.last_name as nm
                         ,      d.department_name as dnm
                         from   hr.employees e1
                         ,      hr.departments d
                         where  e1.department_id=d.department_id
                       ) a1
                  ,    ( select d.department_id as did
                         ,      count(e1.employee_id) as hc
                         ,      avg(e1.salary)as sal
                         from   hr.employees e1
                         ,      hr.departments d
                         where  e1.department_id=d.department_id
                         group by d.department_id
                        ) b
                  where a1.did=b.did
                )
    loop
      dbms_output.put_line(rec1.dnm||' - '||rec1.nm||' - '||rec1.did||' - '||rec1.hc||' - '||rec1.sal);
    end loop;
  end;
  /
  

  Edit
  Use code tags when you post for example, keep formatting and indenting.
  See: http://wiki.oracle.com/page/Oracle+Discussion+Forums+FAQ (scroll down a bit)

  Published by: hoek on November 24, 2009 16:01

• newbie question: sql runs under sqlplus but does not compile in pl/sql?

  I have the following two tables, I have a SQL in pl/sql packages so I can use dbms_jobs to automate it however, I get the compile time error. It seems to me that pl/sql dislikes my sql that works well in sqlplus. Here is the error message and my test case?
  
  mdb_user@cmd > view the error
  PACKAGE BODY DATA_QUALITY_REPORT_P errors:
  
  LINE/COL ERROR
  -------- -----------------------------------------------------------------
  10/1 PL/SQL: statement ignored
  13/42 PL/SQL: ORA-00942: table or view does not exist
  
  
  
  
  
  create the table S_ORG_EXT
  (
  accnt_type_cd varchar2 (100),
  cust_stat_cd varchar2 (100)
  )
  /
  
  insert into s_org_ext
  Select column_name, data_type for user_tab_columns where rownum < = 100
  /
  
  Select * from s_org_ext
  /
  
  
  create the table data_quality_report
  (
  RunId number not null,
  report_type number of non-null, - type of report as dup dup or not other measures
  org_level number not null, - organization level nsgn, sgn, shipto
  loc_level number of non-null, - local level by city, by country, by region, grand_total
  name varchar2 (100) not null,-the line output of the tot name.
  Value number not null, - line value of the tot.
  rundate date default sysdate
  )
  /
  
  create sequence data_quality_report_seq with 1000
  INCREMENT BY 1
  NOCACHE
  NOCYCLE
  /
  
  
  insert into data_quality_report
  Select data_quality_report_seq.nextval, 3, 99, 99, accnt_type_cd, cnt, sysdate from
  (
  Select accnt_type_cd, count cnt (*) of S_ORG_EXT where cust_stat_cd = 'VARCHAR2' group by accnt_type_cd by 2 desc order
  )
  /
  
  Select * from data_quality_report
  /
  
  
  
  truncate table data_quality_report
  
  CREATE or replace PACKAGE data_quality_report_p AS
  function pull_data return data_quality_report.runid%type;
  END data_quality_report_p;
  /
  
  
  create or replace package body data_quality_report_p as
  function pull_data return data_quality_report.runid%type is
  
  new_rid data_quality_report.runid%type;
  
  
  Start
  Select data_quality_report_seq.nextval in the double new_rid;
  
  insert into data_quality_report
  Select new_rid, 3, 999999, 999999, accnt_type_cd, cnt, sysdate from
  (
  Select accnt_type_cd, count cnt (*) of S_ORG_EXT where cust_stat_cd = 'VARCHAR2' group by accnt_type_cd by 2 desc order
  );
  
  
  Return new_rid;
  exception
  When no_data_found then
  DBMS_OUTPUT. Put_line ("NO_DATA_FOUND handles the exception.");
  while others then
  DBMS_OUTPUT. Put_line ("' handling ANOTHER exception.");
  
  
  end; -end pull_data
  
  end data_quality_report_p;
  /

  Hello

  Sorry, I was not clear about that.
  The owner of the package needs direct privileges (not only privileges through a role) to compile the code, whehter it is DEFINE AUTHID or AUTHID CURRENT_USER. Option (3) does not help in this case; my mistake.

  I usually create packages in the same schema tables they use, which was option (2) in my previous message. There may be good reasons why you can't do that; for example, the package may reference multiple schemas tables. In this case, grant the necessary privileges directly to the owner of the whole.

• pl - sql query with indexes per table

  Hello again,
  
  I'm stuck with this query, I want to display the full name of all employees, using the HR schema table.
  
  DECLARE
  Employee_table_struct TYPE IS an ARRAY OF
  HR. Employees.first_name%type
  INDEX OF DIRECTORY;
  
  employee_table employee_table_struct;
  
  Employee_cursor CURSOR IS
  SELECT first_name
  OF hr.employees;
  
  
  v_row NUMBER: = 1;
  BEGIN
  
  OPEN employee_cursor;
  
  LOOP
  OUTPUT WHEN employee_cursor % NOTFOUND;
  
  DBMS_OUTPUT. Put_line (employee_table (v_row));
  
  -populated the next time the loop * /.
  v_row: = v_row + 1;
  END LOOP;
  
  CLOSE Employee_cursor;
  END;
  /
  
  Its gives me error saying:
  
  ORA-01403: no data found
  ORA-06512: at line 21
  
  Help, please
  Thank you

  Why not use a clear FOR the loop?
  It allows you to save saying stuff and it does the same thing, showing first_name for all employees:

  begin
    for rec in ( select first_name
                 from   hr.employees
               )
    loop
      dbms_output.put_line(rec.first_name);
    end loop;
  end;
  /
  

• LabVIEW sql query

  HI HI... I'm a student doing a project related to labview. My task is to create a vi, type a user name and password to continue the whole VI.

  As I am a newbie to SQL query language, can anyone help me this?... This isn't like the VI with password lock

  There is a connection of the user called button in my main façade... u by clicking on it, a pop-up window will come out asking you a user name and a password. If the user name and the password is correct, then you can proceed. The problem is that I'm stuck with database...
  Help me pls!

  with respect,

  Ray

  Hello

  You have two cases:

  (1) connect to the database with string (link a string of connection information), and then type something like this:
  Driver is SQL Native Client;. Server = IP. Add.re.SS; UID = username; PW = *** ; Database = MyDatabase (depends on your database)

  (2) use a UDL file (you can configure it to connect to your database, with specific format). Remember that the connection is successful with test button.

  There is a UDL file that you can edit here: C:\Program NIUninstaller Instruments\LabVIEW 2010\examples\database\Labview.udl

  Edit: The connection dropped, you can set the path to an mdb file, and I think you can give the path of your accdb file.

  Kind regards

• What will happen to the SQL Query based object View (EmployeesVO)

  Schema used: HR

  1. I created a view through SQL Query view object object (Table Employees - EmployeesVO).
  2. Creates an entity of the Employees (EmployeesEO) table object.
  3. In the section EmployeesVO (View object) entity objects, I chose EmployeesEO (entity object).

  What will happen to the View SQL Query object based on (EmployeesVO) will it change to VO based on entities or still to be based query VO.

  It is there because you can still base your query based Vo EO according to Vo.

  After that you base your VO on EO you can now use 'Add the attribute of the entity' to base your attribute on the atrributes of EO. Or if you skilled enough you can manually change the XML to VO

• Urgent need for sql query

  Hi all
  Sorry I can't speak English very well
  =======================
  I have a table that contains two columns
  table name: total_sal
  column name: hire_date
  column name: salary
  
  table syntax
  
  create table total_sal (hire_date date
  number (6.2)) of salary;
  _________________________________________
  Example of data in table format
  
  hire_date | salary
  01/01/2011 | 1000
  01/02/2011 | 2000
  01/05/2011 | 500
  01/09/2011 | 400
  
  
  I NEED a SQL QUERY to display the table, as in this example
  
  OF | TO|||||||||||| TOTALSALAY
  01/01/2011 | 01/02/2011 | 3000
  07/05/2011 | 01/09/2011 | 900
  |||||||||||||||||||||||||||||||||| 3900

  /* Formatted on 9/23/2011 10:14:40 AM (QP5 v5.149.1003.31008) */
  WITH t
          AS (SELECT TO_DATE ('1/1/2011', 'mm/dd/yyyy') hire_date, 1000 salary
                FROM DUAL
              UNION
              SELECT TO_DATE ('2/1/2011', 'mm/dd/yyyy'), 2000 FROM DUAL
              UNION
              SELECT TO_DATE ('5/1/2011', 'mm/dd/yyyy'), 500 FROM DUAL
              UNION
              SELECT TO_DATE ('9/1/2011', 'mm/dd/yyyy'), 400 FROM DUAL)
  SELECT "From", "To", totalsalary
    FROM (SELECT hire_date "From",
                 LEAD (hire_date) OVER (ORDER BY hire_date) "To",
                 salary + LEAD (salary) OVER (ORDER BY hire_date) totalsalary,
                 ROW_NUMBER () OVER (ORDER BY hire_date) rn
            FROM t)
   WHERE MOD (rn, 2) = 1
  UNION ALL
  SELECT NULL, NULL, SUM (salary) FROM t
  

  From     To     TOTALSALARY
  1/1/2011     2/1/2011     3000
  5/1/2011     9/1/2011     900
            3900
  

• Newbie question re: 'break' a path

  Hello... Sorry for the newbie question... I imported this vector image in Illustrator CS5:

  

  I want to isolate each of the children, so I can use the live paint to color to each child a different color.

  I can do this:

  

  But I want every child to be a different color. And it's all a way.

  Thank you.

  I find the tool knife difficult to control unless it is a straight line, but you can draw a path and with the selected path only, choose object > path > divide objects below. The image below shows a path that I draw pretty closely with the pencil tool. You can also correct and refine tracks selected by drawing the wire segments of them using the pencil tool and all in using it, holding that alt will smooth the path. To control how the pencil tool behave click twice on the tool in the tool box and it will display a window with options.

  

  However, in this case, most likely I'll do it in another way.

  First of all, copy the path and paste it at the front 5 times (for 5 children). While the path top of the stack is still selected, change the color of it with the color for the first child, and then using the pencil tool as described above, correct the path to limit it to the silhouette of the first child. The red line on the image below shows where I've drawn with the pencil tool to limit the upper path for the first child. Important during the correction of the paths with the pencil tool is to begin and end the segment based on the original path, or if you start or finish too far from the path, you will create a new path instead of correct that you selected. After correcting the path for the first child, you can select the following path and continue as it fix the paths for each child. Alternatively, instead of paste all roads at the beginning you can stick behind or in front after having corrected the path for each child. Also, except for children at the ends, he must correct the path for other children with both hands. The advantage of this method in the first (with dividing the items below) is that you can move and the path of each child space independently and the hands will look always complete.

  

• Single SQL query for the analysis of the date of customs declaration under the table of Stock codes

  Dear all,

  
  

  Please tell us a single SQL query for the below,
  

  We have a Table of Stock as shown below,

  STOCK_TABLE

   

  ITEM_CODE (item code)

  BAT_NO

  (lot no.)

  TXN_CODE

  (transaction code)

  DOC_NO

  (number)

  BOE_DT

  (date of the customs declaration)

  I1

  B1

  I1

  I2

  I3

  B70

  I4

  B80

  I5

  B90

  T102

  1234

  JULY 2, 2015

  I6

  B100

  We have to find the date of customs declaration (i.e. the date when the items have come under this particular table) for items that are not attached to any document (that is, who have TXN_CODE, DOC_NO and BOE_DT fields with a NULL value).

  For each item in the table of actions, which is not attached to any document, the customs declaration date is calculated as follows.

  1. If (code section, lot number) combination is present under HISTORY_TABLE, the date of customs declaration will receive the UPDT_DT, the transaction code (TXN_CODE) is an IN or transactions (which can be analyzed from the TRANSACTIONS table).

  2. If (code section, lot number) combination is NOT currently at the HISTORY_TABLE (or) the transaction code respective to item - batch number combination code is an operation then customs declaration date will be the date of the document (DOC_DT) that we receive from one of the 3 tables IN_TABLE_HEAD that contains the element of that particular lot.

• If the case 1 and case 2 fails, our customs declaration date will be the last date of document (DOC_DT) that we receive from one of the 3 tables IN_TABLE_HEAD containing that particular item and the BAT_NO in expected results will be that corresponding to this document, as appropriate, to another NULL.

• If the case 1 or case 2 is successful, the value of the last field (in the output expected, shown further below) BATCH_YN will be 'Y', because it fits the lot. Otherwise it will be 'n'.

HISTORY_TABLE

 

ITEM_CODE

BAT_NO

TXN_CODE

DOC_NO

UPDT_DT

I1

B1

T1

1234

JANUARY 3, 2015

I1

B20

T20

4567

MARCH 3, 2015

I1

B30

T30

7890

FEBRUARY 5, 2015

I2

B40

T20

1234

JANUARY 1, 2015

TRANSACTION

 

TXN_CODE	TXN_TYPE
T1	IN
T20

OFF

T30

ALL THE

T50

IN

T80

IN

T90

IN

T60

ALL THE

T70

ALL THE

T40

ALL THE

IN_TABLE_HEAD_1

 

H1_SYS_ID (primary key)

TXN_CODE

DOC_NO

DOC_DATE

H1ID1

T1

1234

JANUARY 1, 2015

H1ID2

T70

1234

FEBRUARY 1, 2015

IN_TABLE_ITEM_1

 

I1_SYS_ID

H1_SYS_ID

(foreign key referencing H1_SYS_ID in IN_TABLE_HEAD_1)

ITEM_CODE

I1ID1

H1ID1

I1

I1ID2

H1ID1

I100

I1ID3

H1ID2

I3

IN_TABLE_BATCH_1

 

B1_SYS_ID

TXN_CODE                DOC_NO (now in IN_TABLE_HEAD_1)

BAT_NO

B1ID1

T1

1234

B1 / can be empty

B1ID2

T70

1234

B70

IN_TABLE_HEAD_2

 

H2_SYS_ID (primary key)

TXN_CODE

DOC_NO

DOC_DATE

H2ID1

T30

4567

FEBRUARY 3, 2015

H2ID2

T60

1234

JANUARY 3, 2015

IN_TABLE_ITEM_2

 

I2_SYS_ID	H2_SYS_ID (foreign key referencing H2_SYS_ID in IN_TABLE_HEAD_2)	ITEM_CODE
I2ID1	H2ID1

I1

I2ID2

H2ID1

I200

I2ID3

H2ID2

I2

IN_TABLE_BATCH_2

 

B2_SYS_ID

I2_SYS_ID

(foreign key referencing I2_SYS_ID in IN_TABLE_ITEM_2)

BAT_NO

B2ID1

I2ID1

B30 / null

B2ID2

I2ID2

B90

B2ID2

I2ID3

B60

IN_TABLE_HEAD_3

 

H3_SYS_ID (primary key)	TXN_CODE	DOC_NO	DOC_DATE
H3ID1

T50

1234

JANUARY 2, 2015

H3ID2

T80

1234

JANUARY 3, 2015

H3ID3

T90

1234

JANUARY 4, 2015

H3ID4

T40

1234

AUGUST 5, 2015

IN_TABLE_ITEM_3

 

I3_SYS_ID

H3_SYS_ID

(foreign key referencing H3_SYS_ID in IN_TABLE_HEAD_3)

ITEM_CODE

BAT_NO

I3ID1

H31D1

I2

B50

I3ID2

H3ID2

I4

B40

I3ID3

H3ID3

I4

I3ID4

H3ID4

I6

There is no IN_TABLE_BATCH_3

Please find below the expected results.

OUTPUT

 

ITEM_CODE

BAT_NO

TXN_CODE

DOC_NO

BOE_DT

BATCH_YN

I1

B1

T1

1234

JANUARY 3, 2015

THERE

I1

B30

T30

7890

FEBRUARY 5, 2015

N

I2

B60

T60

1234

JANUARY 3, 2015

N

I3

B70

T70

1234

FEBRUARY 1, 2015

THERE

I4

T90

1234

JANUARY 4, 2015

N

I6

T40

1234

AUGUST 5, 2015

N

Controls database to create the tables above and insert the records.

CREATE TABLE stock_table()item_code VARCHAR2()80),bat_no VARCHAR2()80),txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), boe_dt DATE );

INSERT EN stock_table

   VALUES ('I1', 'B1', '', '', '');

INSERT EN stock_table

   VALUES ('I1', '', '', '', '');

INSERT IN stock_table

   VALUES ('I2', '', '', '', '');

INSERT EN stock_table

   VALUES ('I3', 'B70', '', '', '');

INSERT EN stock_table

   VALUES ('I4', 'B80', '', '', '');

INSERT EN stock_table

   VALUES ('I5', 'B90', 'T102', '1234', '02-JUL-2015');

INSERT EN stock_table

   VALUES ('I6', 'B100', '', '', '');

SELECT *

FROM stock_table










 

CREATE TABLE history_table()item_code VARCHAR2()80),bat_no VARCHAR2()80),txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), updt_dt DATE );

INSERT IN history_table

   VALUES ('I1', 'B1', 'T1', '1234', '03-JAN-2015');

INSERT IN history_table

   VALUES ('I1', 'B20', 'T20', '4567', '03-MAR-2015');

INSERT IN history_table

   VALUES ('I1', 'B30', 'T30', '7890', '05-FEB-2015');

INSERT IN history_table

   VALUES ('I2', 'B40', 'T20', '1234', '01-JAN-2015');

SELECT *

FROM history_table










 

CREATE TABLE transaction1()txn_code VARCHAR()80),txn_type VARCHAR()80));




INSERT INTO transaction1

   VALUES ('T1', 'IN');




INSERT INTO transaction1

   VALUES ('T20', 'OUT');

INSERT INTO transaction1

   VALUES ('T30', 'ALL');

INSERT INTO transaction1

   VALUES ('T40', 'ALL');

INSERT INTO transaction1

   VALUES ('T50', 'IN');

INSERT INTO transaction1

   VALUES ('T60', 'ALL');

INSERT INTO transaction1

   VALUES ('T70', 'ALL');

INSERT INTO transaction1

   VALUES ('T80', 'IN');

INSERT INTO transaction1

   VALUES ('T90', 'IN');

SELECT *

FROM transaction1










 

CREATE TABLE in_table_head_1()h1_sys_id VARCHAR2()80) PRIMARY KEY,txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), doc_dt DATE );

CREATE TABLE in_table_head_2()h2_sys_id VARCHAR2()80) PRIMARY KEY,txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), doc_dt DATE );

CREATE TABLE in_table_head_3()h3_sys_id VARCHAR2()80) PRIMARY KEY,txn_code VARCHAR2()80),

doc_no VARCHAR2 (80), doc_dt DATE );

 

INSERT IN in_table_head_1

   VALUES ('H1ID1', 'T1', '1234', '01-JAN-2015');

INSERT IN in_table_head_1

   VALUES ('H1ID2', 'T70', '1234', '01-FEB-2015');

INSERT IN in_table_head_2

   VALUES ('H2ID1', 'T30', '4567', '03-FEB-2015');

INSERT IN in_table_head_2

   VALUES ('H2ID2', 'T60', '1234', '03-JAN-2015');

INSERT IN in_table_head_3

   VALUES ('H3ID1', 'T50', '1234', '02-JAN-2015');

INSERT IN in_table_head_3

   VALUES ('H3ID2', 'T80', '1234', '03-JAN-2015');

INSERT IN in_table_head_3

   VALUES ('H3ID3', 'T90', '1234', '05-JAN-2015');

INSERT IN in_table_head_3

   VALUES ('H3ID4', 'T40', '1234', '05-AUG-2015');










 

CREATE TABLE in_table_item_1()i1_sys_id VARCHAR2()80) PRIMARY KEY,

h1_sys_id VARCHAR2 (80) REFERENCES in_table_head_1()h1_sys_id),item_code VARCHAR2()80));

CREATE TABLE in_table_item_2()i2_sys_id VARCHAR2()80) PRIMARY KEY,

h2_sys_id VARCHAR2 (80) REFERENCES in_table_head_2()h2_sys_id),item_code VARCHAR2()80));

CREATE TABLE in_table_item_3(i3_sys_id VARCHAR2(80) PRIMARY KEY,

h3_sys_id VARCHAR2 (80) REFERENCES in_table_head_3()h3_sys_id),item_code VARCHAR2()80),

bat_no VARCHAR2 (80));

 

INSERT IN in_table_item_1

   VALUES ('I1ID1', 'H1ID1', 'I1');

INSERT IN in_table_item_1

   VALUES ('I1ID2', 'H1ID1', 'I100');

INSERT IN in_table_item_1

   VALUES ('I1ID3', 'H1ID2', 'I3');

INSERT IN in_table_item_2

   VALUES ('I2ID1', 'H2ID1', 'I1');

INSERT IN in_table_item_2

   VALUES ('I2ID2', 'H2ID1', 'I200');

INSERT IN in_table_item_2

   VALUES ('I2ID3', 'H2ID2', 'I2');

INSERT IN in_table_item_3

   VALUES ('I3ID1', 'H3ID1', 'I2','B50');

INSERT IN in_table_item_3

   VALUES ('I3ID2', 'H3ID2', 'I4','B40');

INSERT IN in_table_item_3

   VALUES ('I3ID3', 'H3ID3', 'I4','');

INSERT IN in_table_item_3

   VALUES ('I3ID4', 'H3ID4', 'I6','');

SELECT *

FROM in_table_item_1

SELECT *

FROM in_table_item_2

SELECT *

FROM in_table_item_3










 

CREATE TABLE in_table_batch_1()b1_sys_id VARCHAR2()80) PRIMARY KEY,

txn_code VARCHAR2 (80), doc_no VARCHAR2 (80), bat_no VARCHAR2 (80));

CREATE TABLE in_table_batch_2()b2_sys_id VARCHAR2()80) PRIMARY KEY,

i2_sys_id VARCHAR2 (80) REFERENCES in_table_item_2()i2_sys_id),bat_no VARCHAR2()80));

 

INSERT IN in_table_batch_1

   VALUES ('B1ID1', 'T1', '1234', 'B1');

INSERT IN in_table_batch_1

   VALUES ('B1ID2', 'T70', '1234', 'B70');

INSERT IN in_table_batch_2

   VALUES ('B2ID1', 'I2ID1', 'B30');

INSERT IN in_table_batch_2

   VALUES ('B2ID2', 'I2ID2', 'B90');

INSERT IN in_table_batch_2

   VALUES ('B2ID3', 'I2ID3', 'B60');

Please advise a solution for the same.

Thank you and best regards,

Séverine Suresh

very forced (question subfactoring used to allow easy testing/verification - could work with these test data only)

with

case_1 as

(select s.item_code,

s.bat_no,

h.txn_code,

h.doc_no,

h.updt_dt boe_dt,

cases where s.bat_no = h.bat_no then 'Y' else ' n end batch_yn.

cases where h.txn_code is not null

and h.doc_no is not null

and h.updt_dt is not null

then 'case 1' '.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, boe_dt

of w_stock_table

where bat_no is null

or txn_code is null

or doc_no is null

or boe_dt is null

) s

left outer join

w_history_table h

On s.item_code = h.item_code

and s.bat_no = h.bat_no

and exists (select null

of w_transaction1

where txn_code = nvl (s.txn_code, h.txn_code)

and txn_type in ('IN', 'ALL')

)

),

case_2 as

(select s.item_code,

NVL (s.bat_no, h.bat_no) bat_no.

NVL (s.txn_code, h.txn_code) txn_code.

NVL (s.doc_no, h.doc_no) doc_no.

NVL (s.boe_dt, h.updt_dt) updt_dt.

cases where s.bat_no = h.bat_no then 'Y' else ' n end batch_yn.

cases where h.txn_code is not null

and h.doc_no is not null

and h.updt_dt is not null

then 'case 2'.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, boe_dt

of case_1

where refers_to is null

) s

left outer join

w_history_table h

On s.item_code = h.item_code

and exists (select null

of w_transaction1

where txn_code = nvl (s.txn_code, h.txn_code)

and txn_type in ('IN', 'ALL')

)

and not exists (select null

of case_1

where item_code = h.item_code

and bat_no = h.bat_no

and txn_code = h.txn_code

and doc_no = h.doc_no

and updt_dt = h.updt_dt

)

),

case_31 as

(select s1.item_code,

NVL (S1.bat_no, W1.bat_no) bat_no.

NVL (S1.txn_code, W1.txn_code) txn_code.

NVL (S1.doc_no, W1.doc_no) doc_no.

NVL (S1.updt_dt, W1.doc_dt) updt_dt.

cases where s1.bat_no = w1.bat_no then 'Y' else ' n end batch_yn.

cases where w1.txn_code is not null

and w1.doc_no is not null

and w1.doc_dt is not null

then "case 31'.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn, refers_to

of case_2

where refers_to is null

) s1

left outer join

(select i1.item_code, h1.txn_code, h1.doc_no, h1.doc_dt, b1.bat_no

of w_in_table_item_1 i1

inner join

w_in_table_head_1 h1

On i1.h1_sys_id = h1.h1_sys_id

inner join

w_in_table_batch_1 b1

On h1.txn_code = b1.txn_code

and h1.doc_no = b1.doc_no

) w1

On s1.item_code = w1.item_code

),

case_32 as

(select s2.item_code,

NVL (S2.bat_no, W2.bat_no) bat_no.

NVL (S2.txn_code, W2.txn_code) txn_code.

NVL (S2.doc_no, W2.doc_no) doc_no.

NVL (S2.updt_dt, W2.doc_dt) updt_dt.

cases where s2.bat_no = w2.bat_no then 'Y' else ' n end batch_yn.

cases where w2.txn_code is not null

and w2.doc_no is not null

and w2.doc_dt is not null

then "case 32'.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn, refers_to

of case_2

where refers_to is null

) s2

left outer join

(select i2.item_code, h2.txn_code, h2.doc_no, h2.doc_dt, b2.bat_no

of w_in_table_item_2 i2

inner join

w_in_table_head_2 h2

On i2.h2_sys_id = h2.h2_sys_id

inner join

w_in_table_batch_2 b2

On i2.i2_sys_id = b2.i2_sys_id

) w2

On s2.item_code = w2.item_code

),

case_33 as

(select s3.item_code,

w3.bat_no,

NVL (S3.txn_code, w3.txn_code) txn_code.

NVL (S3.doc_no, w3.doc_no) doc_no.

NVL (S3.updt_dt, w3.doc_dt) updt_dt.

cases where s3.bat_no = w3.bat_no then 'Y' else ' n end batch_yn.

cases where w3.txn_code is not null

and w3.doc_no is not null

and w3.doc_dt is not null

then "case 33'.

end refers_to

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn, refers_to

of case_2

where refers_to is null

) s3

left outer join

(select i3.item_code, h3.txn_code, h3.doc_no, h3.doc_dt, i3.bat_no

of w_in_table_item_3 i3

inner join

w_in_table_head_3 h3

On i3.h3_sys_id = h3.h3_sys_id

) w3

On s3.item_code = w3.item_code

)

Select item_code, bat_no, txn_code, doc_no, boe_dt, batch_yn

of case_1

where refers_to is not null

Union of all the

Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

of case_2

where refers_to is not null

Union of all the

Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn,

ROW_NUMBER() over (partition by item_code of updt_dt desc order) rn

from (select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

of case_31

where refers_to is not null

Union of all the

Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

of case_32

where refers_to is not null

Union of all the

Select item_code, bat_no, txn_code, doc_no, updt_dt, batch_yn

of case_33

where refers_to is not null

)

)

where rn = 1

ITEM_CODE	BAT_NO	TXN_CODE	DOC_NO	BOE_DT	BATCH_YN
I1	B1	T1	1234	JANUARY 3, 2015	THERE
I1	B30	T30	7890	FEBRUARY 5, 2015	N
I2	B60	T60	1234	JANUARY 3, 2015	N
I3	B70	T70	1234	FEBRUARY 1, 2015	THERE
I4	-	T90	1234	JANUARY 5, 2015	N
I6	-	T40	1234	AUGUST 5, 2015	N

Concerning

Etbin

• Tables and SQL query

  Hello
  
  I post this question for clarification. I have a report that is based on a SQL query area.
  
  Place automatically APEX sql in the tables, all THE results of a query if it is in a region of report? Or y at - it a step that the developer must do to retrieve the columns of the sql query in a table.
  
  I'm working with checkboxes, and I read up on top of the api APEX_APPLICATION. This part is still unclear.
  
  Your comments would be appreciated!
  
  Keisha

  Hi Keisha,

  You should have a read of: [http://download-uk.oracle.com/docs/cd/B31036_01/doc/appdev.22/b28839/check_box.htm#CHDHFACG] that explains the use of checkboxes on the reports.

  I guess the 'picture' you refer to are APEX_APPLICATION. G_F01 up APEX_APPLICATION. Paintings of G_F50? If so, they are built when you submit the page and are based on elements with attributes of 'name' of 'f01' up to 'f50' in the HTML tags. You don't need to do anything beforehand to create these, which is done automatically for you by the Apex. But, notes, however, that only the checked boxes are presented with a page - so if your username is checked, say, 3 of the 10 boxes, table will contain only 3 points not 10 (with each element of the table that contains the attribute 'value' of a checkbox).

  Andy

• merge 2 tables (from sql query)

  Ahoj!
  
  I have 4-sql queries, each with the same structure, but it is not possible to do in a single query. for example:
  Query 1: extension, County a-> table 1 report
  Query 2: extension, County b-> report table 2
  Query 3: extension, County-> report table 3 c
  Question 4: extension, County d-> report table 4
  
  the result in the apex is now, I have 4 different tables. is it possible to merge these 4 tables table 1 apex?
  extension, number a, b number, County c County d-> report table
  
  I use the standard sql-report, non-interactive.
  
  THX,
  Christian

  You can try something like this (not a not test it):

  SELECT A.EXTENSION, $A.COUNT, C.COUNT, B.COUNT, D.COUNT
  Of
  (SELECT the extension, County)
  A
  ) a
  ,
  (SELECT the extension, County)
  B
  ) b
  ,
  (SELECT the extension, County)
  C
  ) c
  ,
  (SELECT the extension, County)
  D
  ) d
  WHERE a.extension = b.extension
  AND b.extension = c.extension
  AND c.extension = d.extension

  Concerning
  Roel

• SQL query to retrieve a single record for each employee of the following table?

  Hi all

  Help me on the writing of SQL query to retrieve a single record for each employee of the following table? preferably a standard SQL.

  CREATE TABLE xxc_contact)

  empnum NUMBER,

  alternatecontact VARCHAR2 (100),

  relationship VARCHAR2 (10),

  phtype VARCHAR2 (10),

  Phone NUMBER

  );

  insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Cell', 9999999999)

  insert into xxc_contact values (123456, 'Rick Grimes', 'SP', 'Work', 8888888888)

  insert into xxc_contact values (123457, 'Daryl Dixon', 'EN', 'Work', 7777777777)

  insert into xxc_contact values (123457, 'Daryl Dixon', 'EN', 'Home', 3333333333)

  insert into xxc_contact values (123456, 'Maggie Greene', 'CH', 'Cell', 9999999999)

  insert into xxc_contact values (123456, 'Maggie Greene', 'CH', 'Home', 9999999999)

  expected result:

  EmpNum AlternateContact Relationship PhType Phone       

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  Thanks in advance.

  994122 wrote:

  Thank you all, that I got a result

  http://www.orafaq.com/Forum/m/620305/#msg_620305

  By Lalit Kumar B...

  Specifically, the two simple solutions provided were:

  1 using the row_number, entitled Oracle ranking based on descending order of the inside telephone each empnum group. And finally selects the lines which has least rank (of least since that order is descending for phone).

  SQL > column alternatecontact format A20;

  SQL >

  SQL > SELECT empnum, alternatecontact, relationship, phtype, phone

  2 from (SELECT a.*, row_number() over r (PARTITION BY empnum ORDER BY phone / / DESC))

  3 FROM xxc_contact one)

  4. WHEN r = 1

  /

  EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE

  ---------- -------------------- ---------- ---------- ----------

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  2. with the help of MAX, Oracle automatically assigns the maximum phone for all the rows in each group of empnum. And finally selects the rows with the maximum phone. Order by clause is omitted here intentionally. You can find out why.

  SQL > SELECT empnum, alternatecontact, relationship, phtype, phone

  2 (SELECT a.*, MAX (phone) over (PARTITION BY empnum) rn FROM xxc_contact one)

  3 WHERE phone = rn

  4.

  EMPNUM ALTERNATECONTACT RELATIONSHIP PHTYPE PHONE

  ---------- -------------------- ---------- ---------- ----------

  123456 rick Grimes SP cell 9999999999

  Daryl Dixon EN work 7777777777 123457

  Home 123458 Maggie Greene CH 6666666666

  Kind regards

  Lalit

• SQL query: number of occurrence of cellData more thann a column of tabl

  I used table contains the sequence of lines.

  INSERT INTO employee VALUES (105, 'Srinath','vijay','Aeronautics', 27, 33000); 
  INSERT INTO employee VALUES (105, 'Kumble','Anil','Aeronautics', 27, 33000);
  INSERT INTO employee VALUES (105, 'Prabhakar','Manoj','Aeronautics', 27, 33000);
  INSERT INTO employee VALUES (105, 'Srinath','Jawagal','Aeronautics', 27, 33000);
  INSERT INTO employee VALUES (105, 'Jawagal','Srinath','Aeronautics', 27, 33000);
  INSERT INTO employee VALUES (105, 'Mishra','Anil','Aeronautics', 27, 33000);
  INSERT INTO employee VALUES (105, 'Kumble','Prabhakar','Aeronautics', 27, 33000);

  Select first_name separate firstName, count (1) on firstNameCount (partition name) of the employee;
  and I got the following result.
  (Srinath 2, Kumble 2, Prabhakar 1, Jawagal 1, Mishra 1)
  
  Now I want to examine the second and third column the two and want to number of occurrence of data in the table in these two columns

  (Srinath 3,Kumble 2,Prabhakar 2,Jawagal 2,Mishra 1,vijay 1,Anil 2,Manoj 1)

  As Srinath just 3 times, kumble 2 times, Prabhakar 2 Jawagal 2 times, Mishra 1 time, 1 time vijay times, Anil 2 times and Maury 1 times.
  
  What will be my sql query?

  Try this

  select name, count(name) over(partition by name) cnt
    from (select first_name from employee union all select last_name from employee)
  

• SQL query and question CFOUTPUT

  Hello

  I am trying to compare two tables in a database.  I need a few fields in a table of output, to compare a field between the two tables.  Users choose the tables.  I've written a SQL query that does what I need:

  < cfquery name = "getitems" datasource = "snapshot" >
  Select #endtable # .field9 #endtable # .field12, #endtable # .field4, #endtable # .field13, #endtable # .field2, #endtable # .field3, #starttable # .field3
  of #endtable #, #starttable #.
  "where #endtable # .field5 =' #form.field5 #"
  and #starttable # .field2 = #endtable # .field2
  < / cfquery >

  Problem is on the output.  You can see that I am selecting field3 in two tables.  I want also to two output field3 values.

  < cfoutput query = "getitems" >

  #field3 #.

  < / cfoutput >

  This gives me the value that was chosen as #endtable # .field3.

  How can I exit the other - .field3 of # #starttable?

  As mentioned, the table names are variable being passed in the query...  Thank you!

  Peter

  How can I exit the other - .field3 of # #starttable?

  Use an alias to give different names fields IE table.column AS unnom. Otherwise, cfquery do not know what field do you mean when you say "field3".

  Select #endtable # .field9, #endtable # .field12,.

  Be careful when using this type of sql. According to the source of your variables, this can pose a risk of sql injection.

• SQL query question, how to improve it?

  Hello everyone, I want to create a query with result in the following output. Each first-person Department starts with the letter A and goes to the top like this:
  
  Name Department
  A Person1 3
  B Person2 3
  C channels3 3
  D Individu4 3
  Person10 E 3
  
  A 10 Person6
  Person7 10 B
  Person8 C 10
  
  An Individu4 13
  B Person9 13
  
  
  It must be a SQL query, unfortunately no PL/SQL
  
  I was able to create this query, but its lack. Department_id will be a variable, a person can choose a Department or several departments, so the request varies in size.
  
  Select department_id, chr (64 + rownum)
  from (select name, department_id
  employees
  where department_id = 3
  order of id_but, naam
  )
  Union
  Select department_id, chr (64 + rownum)
  from (select name, department_id
  employees
  where department_id = 10
  order of id_but, naam
  )
  Union
  Select department_id, chr (64 + rownum)
  from (select name, department_id
  employees
  where department_id = 13
  order of id_but, naam
  )
  order of id_but, naam
  
  
  
  The employees table has the following columns:
  ID, name, department_id
  
  Can someone help me with this query? Perhaps with the With clause?

  Hello

  You can use the analytic ROW_NUMBER function instead of ROWNUM. Like all analytical functions, ROW_NUMBER can do a calculation separated for each unique value in the PARTITION BY clause:

  select        chr ( 64
             + ROW_NUMBER () OVER ( PARTITION BY  department_id
                           ORDER BY        id_but
                           ,             naam
                         )
             )     AS r_num
  ,        name
  ,       department_id
  from       employees
  where       department_id     IN (3, 10, 13)
  order by  id_but
  ,       naam
  ;
  

  If you do this in SQL * Plus, you can save for the departemnts user input (if it is a list separated by commas as ' 3, 10, 13', or a single value as "99") in a substitution variable (let's call it deptartment_id_list) and use the following WHERE clause:

  where       department_id     IN (&department_id_list)