No matching REGEXP_REPLACE channels in the same line

CREATE TABLE EXPRESSION_TEST (NAMES VARCHAR2(100));

INSERT INTO EXPRESSION_TEST (NAMES) VALUES ('Name=="ABCD" && Address=="India"');
INSERT INTO EXPRESSION_TEST (NAMES) VALUES ('(Name=="XYZ" || Name=="PQR") && Address="Nepal"');
INSERT INTO EXPRESSION_TEST (NAMES) VALUES ('(Name=="EFGH" || Name=="IJK" || Name=="LMN")');

I want to replace the names with XXXX that aren't in the list ("PQR", "IJK").

output must be

NAME == "XXXX" & & address = "India."

(Name == "XXXX" |) Name = "PQR") & & address = 'Nepal '.

(Name == "XXXX" |) Name == "IJK" | Name is "XXXX")

I tried to use

Select regexp_replace (columnname, "name =" ([^ PQR] |)) [^ IJK]. * ?) "',' name = 'XXXX" ') TableName; "

but output is not as expected

I am new to regular expressions, please help.

This is impossible with simple regexp for several reasons.

One is that you can not calculate the number of X easily.

with req (names, rep, I) like)

Select

names of

regexp_substr(names,'Name=="[^"]+"') rep

regexp_count(names,'Name=="[^"]+"')

of test_expression

Union of all the

Select

case

When not rep in ('name is "PQR" "," Name is "IJK" ')

and not translate(rep,'#X"','#') = 'name is'

then replace ("names, rep, ' name ==" "|") LPAD ('X', length (rep)-2, 'X') |'"')

other names

end

, regexp_substr (names,'Name == "[^" "] +"', 1, i)

, i - 1

req

where

I have 0 >

)

Select

names of

req

where i = 0

NAMES OF
Name == "XXXXXXXXXX" & address == "India."
(Name == "XXXXXXXXX" \|) Name == "PQR") & address = 'Nepal '.
(Name == "XXXXXXXXXX" \|) Name == "IJK" \| Name is 'XXXXXXXXX')

Post edited by: sorry chris227, missed that the replacement should be only names of RPF. Added to this now

Post edited by: chris227
Finally ;-)

Tags: Database

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