Use of analytic functions

Similar Questions

• Using the analytic function

  Oracle 11g Release 2

  I'm assuming that the best solution is the use of analytical functions.

  create table test3
  ( part_type_id  varchar2(50)
  ,group_id      number
  ,part_desc_id  number
  ,part_cmt      varchar2(50)
  )
  /
  
  insert into test3 values( 'ABC123',1,10,'comment1');
  insert into test3 values( 'ABC123',1,10,'comment2');
  insert into test3 values( 'ABC123',2,15,'comment1');
  insert into test3 values( 'ABC123',2,15,'comment2');
  insert into test3 values( 'EFG123',25,75,'comment3');
  insert into test3 values( 'EFG123',25,75,'comment4');
  insert into test3 values( 'EFG123',25,75,'comment5');
  insert into test3 values( 'XYZ123',1,10,'comment6');
  insert into test3 values( 'XYZ123',2,15,'comment7');
  commit;
  
  select * from test3;
  
  PART_TYPE_ID           GROUP_ID PART_DESC_ID PART_CMT
  -------------------- ---------- ------------ --------------------
  ABC123                        1           10 comment1
  ABC123                        1           10 comment2
  ABC123                        2           15 comment1
  ABC123                        2           15 comment2
  EDG123                        25          75 comment3
  EDG123                        25          75 comment4
  EDG123                        25          75 comment5
  XYZ123                        1           10 comment6
  XYZ123                        2           15 comment7
  
  9 rows selected.
  
  Desired output:
  
  PART_TYPE_ID           GROUP_ID PART_DESC_ID PART_CMT
  -------------------- ---------- ------------ --------------------
  ABC123                        1           10 comment1 
  ABC123                        2           15 comment1
  XYZ123                        1           10 comment1
  XYZ123                        2           15 comment2
  
  RULE: where one part_type_id has multiple (2 or more distinct combinations) of group_id/part_desc_id
  
  NOTE: There are about 12 columns in the table, for brevity I only included 4.
  
  
  
  

  Post edited by: orclrunner was updated desired output and rule

  Hello

  Here's one way:

  WITH got_d_count AS

  (

  SELECT part_type_id, group_id, part_desc_id

  MIN (part_cmt) AS min_part_cmt

  COUNT AS d_count (*) OVER (PARTITION BY part_type_id)

  OF test3

  GROUP BY part_type_id, group_id, part_desc_id

  )

  SELECT DISTINCT

  group_id, part_desc_id, part_type_id, min_part_cmt

  OF got_d_count

  WHERE d_count > 1

  ;

  Output:

  GROUP_ID PART_DESC_ID MIN_PART_CMT PART_TYPE_ID

  ------------ ---------- ------------ ------------

  ABC123 1 10 comment1

  ABC123 2 15 comment1

  XYZ123 1 10 comment6

  XYZ123 2 15 comment7

  Analytical functions, such as the COUNTY and MIN, many global versions, in addition, it can give the same results.  Use the analytical versions when each row of output corresponds to exactly 1 row of input and the aggregate and GROUP BY version when each line of output corresponds to a group of lines 1 or more input.  In this issue, each line of output appears to be a group of input lines having the same group_id, part_type_id, and part_desc_id (I'm guessing just, this only has never stated), so I used GROUP BY to get 1 row of output for every input lines.

• SQL using the analytic function

  
  Hi all

  I want a help in the creation of my SQL query to retrieve the data described below:

  I have a test of sample table containing data as below:

  State ID Desc

  MICHAEL 1 T1

  ACTIVE 2 T2

  T3 3 SUCCESS

  DISABLE THE T4 4

  The thing I want to do is to select all the lines with an ACTIVE status in the table but is there is no ACTIVE status, my request will give me the last line with MICHAEL status.

  I can do this in a single request by using the analytical function for example, if yes can yiu help me on the request of unpacking.

  Kind regards

  Raluce

  Something like that?

  I had to fix it.

  with testdata until)
  Select 1 id, "T1" dsc "DISABLED" status of Union double all the
  Select 2 id, 'T2' dsc, the status "ACTIVE" of all the double union
  Select id 3, "T3" dsc, the status of 'SUCCESS' of all the double union
  Select 4 id, "T4" dsc "DISABLED" status of double
  )

  Select
  ID
  dsc
  status
  of testdata
  where
  status =
  -case when (select count (*) in testdata where status = 'ACTIVE') > 0
  then 'ACTIVE '.
  Another 'DISABLED '.
  end
  and)
  ID in (select id from testdata where status = ' ACTIVE')
  or
  ID = (select max (id) in testdata when status = 'DISABLED')
  )

  STATE ID DSC

  '2' 'T2' 'ACTIVE '.

  Maybe it's more efficient

  Select
  ID
  dsc
  status
  of testdata
  where
  status =
  -case when (select count (*) in testdata where status = 'ACTIVE') > 0
  then 'ACTIVE '.
  Another 'DISABLED '.
  end
  and
  ID =)
  -case when (select count (*) in testdata where status = 'ACTIVE') > 0
  then id
  on the other
  (select max (id) in testdata when status = 'DISABLED')
  end
  )

  Post edited by: correction of chris227

  Post edited by: chris227
  extended

• Nth salary using the analytic function

  I use under function to calculate second highest with empno and deptno salary.

  Is it possible to get the same result with another query without using Assembly only analytical functions condition.using and windows function is possible to get the desired output?

  SELECT e.empno,

  e.DEPTNO,

  tmp. SAL as second_higher_salary

  FROM emp e,.

  (SELECT Empno,

  DEPTNO,

  SAL,

  DENSE_RANK() (PARTITION BY deptno ORDER of sal) AS rnk

  WCP

  ) tmp

  WHERE tmp.deptno = e.deptno

  and tmp.rnk = 2

  EMPNO DEPTNO SAL

  ---------- ---------- ----------

  7934 10 2450

  7782 10 2450

  7839 10 2450

  7876 20 1100

  7369 20 1100

  7902 20 1100

  7788 20 1100

  7566 20 1100

  7900 30 1250

  7844 30 1250

  7654 30 1250

  7521 30 1250

  7499 30 1250

  7698 30 1250

  7900 30 1250

  7844 30 1250

  7654 30 1250

  7521 30 1250

  7499 30 1250

  7698 30 1250

  Here's my solution:

  Select empno,

  DEPTNO,

  FIRST_VALUE (sal) (PARTITION BY deptno ORDER by sal desc)

  de)

  SELECT EmpNo,

  DEPTNO,

  Decode (DENSE_RANK () OVER (PARTITION BY deptno order by sal desc), 1,-sal, sal) sal

  WCP

  )

  /

  EMPNO

  DEPTNO FIRST_VALUE (SAL) OVER (PARTITIONBYDEPTNOORDERBYSALDESC)

  ---------- ---------- -----------------------------------------------------

  	7782	10	2450
  	7934	10	2450
  	7839	10	2450
  	7566	20	2975
  	7876	20	2975
  	7369	20	2975
  	7788	20	2975
  	7902	20	2975
  	7499	30	1600
  	7844	30	1600
  	7654	30	1600
  	7521	30	1600
  	7900	30	1600
  	7698	30	1600

• by using the analytical function to get the right output.

  Hello all;
  
  I have the following date of sample below
  

  create table temp_one
  (
         id number(30),   
        placeid varchar2(400),
        issuedate  date,
        person varchar2(400),
        failures number(30),
        primary key(id)
  );
  
  insert into temp_one values (1, 'NY', to_date('03/04/2011', 'MM/DD/YYYY'), 'John', 3);
  
  insert into temp_one values (2, 'NY', to_date('03/03/2011', 'MM/DD/YYYY'), 'Adam', 7);
  
  insert into temp_one values (3, 'Mexico', to_date('03/04/2011', 'MM/DD/YYYY'), 'Wendy', 3);
  
  insert into temp_one values (4, 'Mexico', to_date('03/14/2011', 'MM/DD/YYYY'), 'Gerry', 3);
  
  insert into temp_one values (5, 'Mexico', to_date('03/15/2011', 'MM/DD/YYYY'), 'Zick', 9);
  
  insert into temp_one values (6, 'London', to_date('03/16/2011', 'MM/DD/YYYY'), 'Mike', 8);

  It's the output I want
  

  placeid       issueperiod                               failures
  NY              02/28/2011 - 03/06/2011          10
  Mexico       02/28/2011 - 03/06/2011           3
  Mexico        03/14/2011 - 03/20/2011          12
  London        03/14/2011 - 03/20/2011          8

  Any help is appreciated. I'll post my request as soon as I can think of a good logic for this...

  Hello

  user13328581 wrote:
  ... Please note, I'm still learning how to use analytical functions.

  It doesn't matter; analytical functions will not help in this problem. The SUM aggregate function is all you need.
  But what do you need to GROUP BY? What is the value of each row of the result will represent? A placeid? Yes, each line will represent only placedid, but it will be divided further. You want a separate line of the output for each placeid and every week, then you'll want of the week and GROUP BY placeid. You don't want to GROUP BY the raw issuedate; that would put on 3 March and 4 March in separate groups. And you don't want to GROUP BY failures; This would mean that a line with 3 failures could never be in the same group in line with 9 failures.

  This becomes the output you posted from the sample data you posted:

  SELECT       placeid
  ,             TO_CHAR ( TRUNC (issuedate, 'IW')
                , 'MM/DD/YYYY'
              ) || ' - '|| TO_CHAR ( TRUNC (issuedate, 'IW') + 6
                                           , 'MM/DD/YYY'
                             )     AS issueperiod
  ,       SUM (failures)                  AS sumfailures
  FROM        temp_one
  GROUP BY  placeid
  ,            TRUNC (issuedate, 'IW')
  ;
  

  You can use a subquery to calculate TRUNC (issuedate, 'IW') once. The code would be of about as complicated, efficiency probably will not improve substantially and the results would be the same.

• How to achieve this using an analytic function - please help

  version 10g.
  This code works very well with my requirement. I'm tyring learn analytical functions and implement than in the query below. I tried to use row_number,
  but I could nt achieve the desired results. Please give me some ideas.
  
  

  SELECT c.tax_idntfctn_nmbr irs_number, c.legal_name irs_name,
         f.prvdr_lctn_iid
    FROM tax_entity_detail c,
         provider_detail e,
         provider_location f,
         provider_location_detail pld
   WHERE c.tax_entity_sid = e.tax_entity_sid
     AND e.prvdr_sid = f.prvdr_sid
     AND pld.prvdr_lctn_iid = f.prvdr_lctn_iid
     AND c.oprtnl_flag = 'A'
     AND c.status_cid = 2
     AND e.oprtnl_flag = 'A'
     AND e.status_cid = 2
     AND (c.from_date) =
            (SELECT MAX (c1.from_date)
               FROM tax_entity_detail c1
              WHERE c1.tax_entity_sid = c.tax_entity_sid
                AND c1.oprtnl_flag = 'A'
                AND c1.status_cid = 2)
     AND (e.from_date) =
            (SELECT MAX (c1.from_date)
               FROM provider_detail c1
              WHERE c1.prvdr_sid = e.prvdr_sid
                AND c1.oprtnl_flag = 'A'
                AND c1.status_cid = 2)
     AND pld.oprtnl_flag = 'A'
     AND pld.status_cid = 2
     AND (pld.from_date) =
            (SELECT MAX (a1.from_date)
               FROM provider_location_detail a1
              WHERE a1.prvdr_lctn_iid = pld.prvdr_lctn_iid
                AND a1.oprtnl_flag = 'A'
                AND a1.status_cid = 2)

  Thank you
  
  Published by: new learner on May 24, 2010 07:53
  
  Published by: new learner on May 24, 2010 10:50

  Can be like that not tested...

  Select *.
  Of
  (

  SELECT c.tax_idntfctn_nmbr irs_number, c.legal_name irs_name,
  f.prvdr_lctn_iid, c.from_date as c_from_date, max (c.from_date) more (partition c.tax_entity_sid) as max_c_from_date,
  e.from_date as e_from_date, max (e.from_date) more (partition e.prvdr_sid) as max_e_from_date,
  PLD.from_date as pld_from_date, max (pld.from_date) more (pld.prvdr_lctn_iid partition) as max_pld_from_date

  OF tax_entity_detail c,.
  e provider_detail
  provider_location f,
  LDP provider_location_detail
  WHERE c.tax_entity_sid = e.tax_entity_sid
  AND e.prvdr_sid = f.prvdr_sid
  AND pld.prvdr_lctn_iid = f.prvdr_lctn_iid
  AND c.oprtnl_flag = 'A '.
  AND c.status_cid = 2
  AND e.oprtnl_flag = 'A '.
  AND e.status_cid = 2
  AND pld.oprtnl_flag = 'A '.
  AND pld.status_cid = 2

  ) X
  where c_from_date = max_c_from_date AND e_from_date = max_e_from_date AND
  pld_from_date = max_pld_from_date

• [8i] can I use an analytical function, or do I need a subquery?

  Hi all...
  
  This should be a quick. I hope I can solve my problem with an analytic function, but I don't know if it's possible. Can I use a subquery if I have to, but I'd really rather not.
  
  Here is a very simple version of what I'm trying to do:
  

  CREATE TABLE     test123
  (     field1          VARCHAR2(10)
  ,     field2          VARCHAR2(10)
  ,     my_date          DATE
  );
  
  INSERT INTO     test123
  VALUES     ('value1', 'a',TO_DATE('12/31/1900','mm/dd/yyyy'));
  INSERT INTO     test123
  VALUES     ('value1', 'b',TO_DATE('01/02/2010','mm/dd/yyyy'));
  INSERT INTO     test123
  VALUES     ('value1', 'c',TO_DATE('01/05/2010','mm/dd/yyyy'));
  
  INSERT INTO     test123
  VALUES     ('value2', 'a',TO_DATE('12/31/1900','mm/dd/yyyy'));
  INSERT INTO     test123
  VALUES     ('value2', 'b',TO_DATE('01/01/2010','mm/dd/yyyy'));
  INSERT INTO     test123
  VALUES     ('value2', 'c',TO_DATE('01/15/2010','mm/dd/yyyy'));

  I want the results:

  FIELD1     FIELD2
  --------------
  value2     a
  value2     b
  value2     c
  value1     a
  value1     b
  value1     c

  I started with the following query:

  SELECT     field1
  ,          field2
  FROM     test123
  ORDER BY     MIN(my_date)     OVER     (
                                               PARTITION BY     field1
                                               )                                -- removed DESC here
  ,               field2

  But the problem is the database has a date of 31 December 1900 ' as default / initial for any date field. I don't want these default values taken into account in my calculation of min. I tried to put a WHERE clause in my analytical function [WHERE my_date <>TO_DATE (' 12/31/1900 ',' mm/dd/yyyy')], but I kept getting an error message "missing right parenthesis", so it seems that you can not have a WHERE clause here... or I'm just something wrong?
  
  Moreover, it is a 8i database...
  
  Edited by: user11033437 may 20, 2010 17:16: took the 'DESC' criteria out of my order by clause. In my real application, I need DESC, but not the example.

  Hello

  A WHERE clause excludes rows in the results set. Whenever you want you can have a WHERE clause that was more limited (for example, something that would simply exclude MIN calculating values in the ORDER BY clause), then think CASE:

  SELECT       field1
  ,       field2
  FROM       test123
  ORDER BY  MIN ( CASE
                WHEN  my_date > TO_DATE ( '12/31/1900'
                               , 'MM/DD/YYYY'
                               )
                THEN  my_date
            END
             )     OVER     (PARTITION BY     field1)      DESC
  ,       field2
  ;
  

  This puts the lines for "Value1" first.
  The minimum my_date for "Value1" (after excluding the values of 1900) is later than the minimum for "Value2", so I think that you either made a mistake in the desired output, or you do not want sorted by descending order.

  As always, thanks for the display of the data of the sample and the results so clearly.

• Using the analytical function.

  Hello
  
  I have this scenario.
  

  with t as 
  (
  select 21009 item_id,9 primary_available,450 max_qty,100 bulk_available,12122 bulk_locator_id 
  from dual union all
  select 21009 item_id,9 primary_available,450 max_qty,2775 bulk_available,8704 bulk_locator_id 
  from dual union all
  select 21009 item_id,9 primary_available,450 max_qty,524 bulk_available,15614 bulk_locator_id 
  from dual union all
  select 21009 item_id,9 primary_available,450 max_qty,3300 bulk_available,15654 bulk_locator_id
  from dual)
  select  t.* from t;

  We have two locations for a given item_id. Primary and in bulk.
  
  I'm trying to get a select statement out of this point of view, where I will be restock the primary AMOUNT of sites in bulk, BUT the smaller bulk first. Once she gets up, I shouldn't take more product.
  
  There is an analytic function that would do this?
  
  That's the max I could come up with.
  

  with t as 
  (
  select 21009 item_id,9 primary_available,450 max_qty,100 bulk_available,12122 bulk_locator_id 
  from dual union all
  select 21009 item_id,9 primary_available,450 max_qty,2775 bulk_available,8704 bulk_locator_id 
  from dual union all
  select 21009 item_id,9 primary_available,450 max_qty,524 bulk_available,15614 bulk_locator_id 
  from dual union all
  select 21009 item_id,9 primary_available,450 max_qty,3300 bulk_available,15654 bulk_locator_id
  from dual)
  select  t.*, max_qty -
                 (primary_available + SUM(bulk_available)
                  over(PARTITION BY item_id ORDER BY bulk_available)) replen_this_much 
                  from t;

  So, in this scenario, I want to replen bulk_locator_id 100 ' 12122 'and ' 15614 bulk_locator_id 341'. That's all. ZERO of the other rentals (bulk_locator_id). If the question is not clear, please let me know.
  
  Published by: RPuttagunta on September 11, 2009 16:23

  Hello

  Thanks for posting the sample data.
  It would be useful that you also posted the output you want. Is this?

  .                                 BULK_         REPLEN_
  ITEM_ PRIMARY_   MAX_  BULK_      LOCATOR_        THIS_
  ID    AVAILABLE  QTY   AVAILABLE  ID               MUCH
  ----- ---------- ----- ---------- ---------- ----------
  21009 9          450   100        12122             100
  21009 9          450   524        15614             341
  21009 9          450   2775       8704                0
  21009 9          450   3300       15654               0
  

  If so, you can get to this:

  SELECT       t.*
  ,       GREATEST ( 0
               , LEAST ( TO_NUMBER (bulk_available)
                       , TO_NUMBER (max_qty)
                      - ( TO_NUMBER (primary_available)
                        + NVL ( SUM (TO_NUMBER (bulk_available))
                                OVER ( PARTITION BY  item_id
                                       ORDER BY      TO_NUMBER (bulk_available)
                                 ROWS BETWEEN  UNBOUNDED PRECEDING
                                   AND      1           PRECEDING
                               )
                           , 0
                           )
                        )
                    )
               ) AS replen_this_much
  FROM       t
  ORDER BY  item_id
  ,            TO_NUMBER (bulk_available)
  ;
  

  You should really store your numbers in NUMBER of columns.

  You essentially posted all what you need analytical functions. The problem was just wrapping this analytical function (or something very close to it) and LESS and more GRAND, so that the replen_this_much column is always between 0 and TO_NUMBER (bulk_available).

• By using the analytical function to sort without showing this column in the result.

  Hello

  We use the Oracle 11.2

  How to use Oracle Analytics to sort the output of a query without showing this column in the result?

  Here's my query:

  Select distinct nvl(SRC_CHR_NM,'0') | » #'|| NVL(EXPL_SRC,'0') | » #'|| NVL(DIM_NM,'0') | » #'|| NVL(DIM_CHR_NM,'0') | » #'|| NVL(DIM_CHR_ABR,'0') | » #'||

  Decode (InStr (NVL(SRC_COL_NM,'0'), 'trim ('),'1 ', Replace (NVL(SRC_COL_NM,'0'),'trim (',' trim(PRM_DTL.'), '0',' PRM_DTL.)))) » || NVL(SRC_COL_NM,'0')) AS ALLOFIT,

  DIM_NM

  from EXPL_CONFIG where SBJ_AREA_CD = 'PRMDTL. '

  I want to use analytical to sort by DIM_NM but I do not want to show. I want to just just the ALLOFIT column to show in the output.

  Something like "row_number() over (order by DIM_NM desc).

  Thank you!

  Hello

  If you SELECT SEPARATE, then you can only ORDER OF things in the SELECT clause. (Do you really need to do SELECT DISTINCT?  Often, it's just an inefficient way to remove the lines that do not need to be there at all).

  Move making the SELECT DISTINCT in a subquery and make the ORDER BY (and nothing else) in the main query.

  I hope that answers your question.

  If this isn't the case, please post a small example data (CREATE TABLE and only relevant columns, INSERT statements) and also publish outcomes from these data.

  Explain, using specific examples, how you get these results from these data.

  Always say what version of Oracle you are using (for example, 11.2.0.2.0).

  See the FAQ forum: https://forums.oracle.com/message/9362002#9362002

• Using SQL analytic functions

  Thanks in advance to anyone who might help
  
  I am writing a storage report. Try to calculate the use of space over a period of time. I need for a db_nm, tblsp_nm find the collections of the first and the last, and then find the difference in the space_used
  
  The structure of the table is like this
  

  drop table tstg
  /
  create table tstg (db_nm varchar(10),
                    tblsp_nm varchar(15),
                    space_used number,
                    collection_time date)
  /
  insert into tstg values ( 'EDW', 'SYSTEM',100,to_date('01/07/2011','DD/MM/YYYY'));
  insert into tstg values ( 'EDW', 'SYSTEM',120,to_date('05/07/2011','DD/MM/YYYY'));
  insert into tstg values ( 'EDW', 'SYSTEM',150,to_date('10/07/2011','DD/MM/YYYY'));
  insert into tstg values ( 'EDW', 'SYSAUX',10,to_date('01/07/2011','DD/MM/YYYY'));
  insert into tstg values ( 'EDW', 'SYSAUX',12,to_date('05/07/2011','DD/MM/YYYY'));
  insert into tstg values ( 'EDW', 'SYSAUX',15,to_date('10/07/2011','DD/MM/YYYY'));
  commit;

  Expected result is
  

  DB_NM      TBLSP_NM        SPACE_USED COLLECTIO       DIFF
  ---------- --------------- ---------- --------- ----------
  EDW        SYSAUX                  15      10-JUL-11          5
  EDW        SYSTEM                 150      10-JUL-11         50

  I use
  

  select db_nm,tblsp_nm,space_used,collection_time,
  last_value(space_used) OVER (partition by DB_NM,Tblsp_nm order by collection_time ASC) -
  first_value(space_used) OVER (partition by DB_NM,Tblsp_nm order by collection_time ASC) diff
  from
  tstg

  but gives more lines in the result I want

  DB_NM      TBLSP_NM        SPACE_USED COLLECTIO       DIFF
  ---------- --------------- ---------- --------- ----------
  EDW        SYSAUX                  10      01-JUL-11          0
  EDW        SYSAUX                  12      05-JUL-11          2
  EDW        SYSAUX                  15      10-JUL-11          5
  EDW        SYSTEM                 100      01-JUL-11          0
  EDW        SYSTEM                 120      05-JUL-11         20
  EDW        SYSTEM                 150      10-JUL-11         50

  /
  
  
  Thank you
  Eduardo

  Hello

  Thanks for the sample data.

  Here's a solution using the FIRST/LAST functions:

  select db_nm
       , tblsp_nm
       , max(collection_time) as collection_time
       , max(space_used) keep (dense_rank last order by collection_time) as space_used
       , max(space_used) keep (dense_rank last order by collection_time)
         - max(space_used) keep (dense_rank first order by collection_time) as diff
  from tstg
  group by db_nm
         , tblsp_nm
  ;
  

• Using Oracle analytic function

  Hi all

  I use Oracle 10 g Release 10.0.2

  Here's the situation:

  I visited in my table of looks like this:

  Cust_id beg_dt end_dt sg_cd

  264321502 1 MAY 97 19 MARCH 98 1

  264321502 21 MAY 98 15 OCTOBER 98 6

  264321502 20 OCTOBER 98 22 APRIL 99 6

  264321502 23 APRIL 99 25 APRIL 00 6

  264321502 27 APRIL 00 20 JANUARY 02 6

  264321502 25 JANUARY 02 15 MAY 02 6

  264321502 MAY 21 02 27 MAY 02 6

  264321502 31 MAY 02 17 FEBRUARY 03 6

  264321502 21 FEBRUARY 06 03-7.-04 1

  264321502 25 FEBRUARY 03 25 FEBRUARY 03 1

  264321502 31 MARCH 03 30 APRIL 03 1

  264321502 07 - SEP - 04 26 DECEMBER 04 6

  264321502 29 DECEMBER 04 3 JANUARY 06 6

  264321502 4 JANUARY 06 3 JANUARY 07 12

  264321502 4 JANUARY 06 3 JANUARY 07 12

  264321502 4 JANUARY 06 3 JANUARY 07 12

  I need the results of the query as

  Cust_id beg_dt end_dt sg_cd

  264321502 1 MAY 97 19 MARCH 98 1

  264321502 21 MAY 98 17 FEBRUARY 03 6

  264321502 21 FEBRUARY 03 30 APRIL 03 1

  264321502 07 - SEP - 04 3 JANUARY 06 6

  264321502 4 JANUARY 06 3 JANUARY 07 12

  Basically, I need take a min max (end_dt) of sg_cd for this cust id (beg_dt).

  Any help is very much appreciated:

  My query is like that

  Select cust_id, end_dt, beg_dt, sg_cd,

  min (beg_dt) more (partition of cust_id, sg_Cd) as new_beg_dt,

  Max (end_dt) more (partition of cust_id, sg_cd) as end_Dt_nw

  of cust_tab.

  can be like that?

  1 data

  () 2

  3 select Cust_id 264321502, to_date('01-MAY-97','dd-mon-rr') beg_dt, to_date('19-MAR-98','dd-mon-rr') end_dt, 1 sg_cd of all the double union

  4. Select 264321502, to_date('21-MAY-98','dd-mon-rr'), to_date('15-OCT-98','dd-mon-rr'), 6 Union double all the

  5 select 264321502, to_date('20-OCT-98','dd-mon-rr'), to_date('22-APR-99','dd-mon-rr'), 6 Union double all the

  6. Select 264321502, to_date('23-APR-99','dd-mon-rr'), to_date('25-APR-00','dd-mon-rr'), 6 Union double all the

  7. Select 264321502, to_date('27-APR-00','dd-mon-rr'), to_date('20-JAN-02','dd-mon-rr'), 6 Union double all the

  8 select 264321502, to_date('25-JAN-02','dd-mon-rr'), to_date('15-MAY-02','dd-mon-rr'), 6 Union double all the

  9. Select 264321502, to_date('21-MAY-02','dd-mon-rr'), to_date('27-MAY-02','dd-mon-rr'), 6 Union double all the

  10. Select 264321502, to_date('31-MAY-02','dd-mon-rr'), to_date('17-FEB-03','dd-mon-rr'), 6 Union double all the

  11. Select 264321502, to_date('21-FEB-03','dd-mon-rr'), to_date('06-SEP-04','dd-mon-rr'), 1 Union double all the

  12 select 264321502, to_date('25-FEB-03','dd-mon-rr'), to_date('25-FEB-03','dd-mon-rr'), 1 Union double all the

  13 select 264321502, to_date('31-MAR-03','dd-mon-rr'), to_date('30-APR-03','dd-mon-rr'), 1 Union double all the

  14 select 264321502, to_date('07-SEP-04','dd-mon-rr'), to_date('26-DEC-04','dd-mon-rr'), 6 Union double all the

  15 select 264321502, to_date('29-DEC-04','dd-mon-rr'), to_date('03-JAN-06','dd-mon-rr'), 6 Union double all the

  16 select 264321502, to_date('04-JAN-06','dd-mon-rr'), to_date('03-JAN-07','dd-mon-rr'), 12 Union double all the

  17 select 264321502, to_date('04-JAN-06','dd-mon-rr'), to_date('03-JAN-07','dd-mon-rr'), 12 Union double all the

  18 select 264321502, to_date('04-JAN-06','dd-mon-rr'), to_date('03-JAN-07','dd-mon-rr'), 12 of the double

  (19) - select * from data

  20. Select Cust_id, beg_dt, max (end_dt) as end_dt, min (beg_dt), sg_cd

  21 of

  (22)

  23 select x.*, sum (flg) over (order by end_dt Cust_id partition) as grp

  24 of

  (25)

  26 select

  27 wagneur, case when lag (sg_cd, 1-9) over (order by end_dt Cust_id partition)! sg_cd = 1 END so that flg

  28 from data d

  x 29)

  x 30)

  Group 31 by Cust_id, sg_cd, grp

  32 * order of Cust_id, end_dt

  CUST_ID BEG_DT END_DT SG_CD

  ---------- --------- --------- ----------

  264321502 1 MAY 97 19 MARCH 98 1

  264321502 21 MAY 98 17 FEBRUARY 03 6

  264321502 21 FEBRUARY 06 03-7.-04 1

  264321502 07 - SEP - 04 3 JANUARY 06 6

  264321502 4 JANUARY 06 3 JANUARY 07 12

• understand row_number() and its use in analytic function

  Hello all;
  
  I've been playing with row_number and trying to figure out how to use it, and yet I still can't understand...
  
  I have the following code below
  

  create table Employee(
      ID                 VARCHAR2(4 BYTE)         NOT NULL,
     First_Name         VARCHAR2(10 BYTE),
     Last_Name          VARCHAR2(10 BYTE),
      Start_Date         DATE,
      End_Date           DATE,
       Salary             Number(8,2),
     City               VARCHAR2(10 BYTE),
      Description        VARCHAR2(15 BYTE)
   )
   
  
  insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
               values ('01','Jason',    'Martin',  to_date('19960725','YYYYMMDD'), to_date('20060725','YYYYMMDD'), 1234.56, 'Toronto',  'Programmer');
  
  
  
  
  insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
                values('02','Alison',   'Mathews', to_date('19760321','YYYYMMDD'), to_date('19860221','YYYYMMDD'), 6661.78, 'Vancouver','Tester')
  
  
  
  
   insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
               values('03','James',    'Smith',   to_date('19781212','YYYYMMDD'), to_date('19900315','YYYYMMDD'), 6544.78, 'Vancouver','Tester')
  
  
  
  
  insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
                values('04','Celia',    'Rice',    to_date('19821024','YYYYMMDD'), to_date('19990421','YYYYMMDD'), 2344.78, 'Vancouver','Manager')
  
  
  
  
  insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary,  City,       Description)
                values('05','Robert',   'Black',   to_date('19840115','YYYYMMDD'), to_date('19980808','YYYYMMDD'), 2334.78, 'Vancouver','Tester')
  
  
  
  
   insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
                values('06','Linda',    'Green',   to_date('19870730','YYYYMMDD'), to_date('19960104','YYYYMMDD'), 4322.78,'New York',  'Tester')
  
  
  
  
  insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
                values('07','David',    'Larry',   to_date('19901231','YYYYMMDD'), to_date('19980212','YYYYMMDD'), 7897.78,'New York',  'Manager')
  
  
  
  
  insert into Employee(ID,  First_Name, Last_Name, Start_Date,                     End_Date,                       Salary, City,        Description)
                 values('08','James',    'Cat',     to_date('19960917','YYYYMMDD'), to_date('20020415','YYYYMMDD'), 1232.78,'Vancouver', 'Tester')

  I made a simple select statement
  
  Select * from employee
  
  and it returns it below

  ID   FIRST_NAME LAST_NAME  START_DAT END_DATE      SALARY CITY       DESCRIPTION
  ---- ---------- ---------- --------- --------- ---------- ---------- ---------------
  01   Jason      Martin     25-JUL-96 25-JUL-06    1234.56 Toronto    Programmer
  02   Alison     Mathews    21-MAR-76 21-FEB-86    6661.78 Vancouver  Tester
  03   James      Smith      12-DEC-78 15-MAR-90    6544.78 Vancouver  Tester
  04   Celia      Rice       24-OCT-82 21-APR-99    2344.78 Vancouver  Manager
  05   Robert     Black      15-JAN-84 08-AUG-98    2334.78 Vancouver  Tester
  06   Linda      Green      30-JUL-87 04-JAN-96    4322.78 New York   Tester
  07   David      Larry      31-DEC-90 12-FEB-98    7897.78 New York   Manager
  08   James      Cat        17-SEP-96 15-APR-02    1232.78 Vancouver  Tester

  I wrote another select statement with row_number. See below
  

  SELECT first_name, last_name, salary, city, description, id,
     ROW_NUMBER() OVER(PARTITION BY description ORDER BY city desc) "Test#"
     FROM employee
     

  and I get this result
  

  First_name  last_name   Salary         City             Description         ID         Test#
  Celina          Rice         2344.78      Vancouver    Manager             04          1
  David          Larry         7897.78      New York    Manager             07          2
  Jason          Martin       1234.56      Toronto      Programmer        01          1
  Alison         Mathews    6661.78      Vancouver   Tester               02          1  
  James         Cat           1232.78      Vancouver    Tester              08          2
  Robert        Black         2334.78     Vancouver     Tester              05          3
  James        Smith         6544.78     Vancouver     Tester              03          4
  Linda         Green        4322.78      New York      Tester             06           5

  I understand the partition by which means basically for each associated group a unique number wiill be assigned for that row, so in this case since tester is one group, manager is another group, and programmer is another group then tester gets its own unique number for each row, manager as well and etc.

  What is throwing me, that's the order of and how these numbers are assigned. Why is
  
  1 assigned to Alison Mathews for the tester group and 2 assigned to James Cat and assigned 3 Robert Black
  
  I apologize if this is a stupid question, I tried to read about this online and looking at the oracle documentation, but still do not understand why.

  user13328581 wrote:
  What is throwing me, that's the order of and how these numbers are assigned. Why is

  1 assigned to Alison Mathews for the tester group and 2 assigned to James Cat and assigned 3 Robert Black

  Description (partition by column) and city (control column) values are same for Alison, James and Robert, no sort order of these 3 records be held valid.
  Oracle just happened to choose a. What do you think should be the numbering "correct"?

• update the table by using the analytic function

  I have a table like this one:
  

  create table fred (test varchar2(50), seq_no number(18,0));
  
  
  insert into fred (test) values ('A');
  insert into fred (test) values ('A');
  insert into fred (test) values ('A');
  insert into fred (test) values ('B');
  insert into fred (test) values ('C');
  insert into fred (test) values ('D');
  insert into fred (test) values ('D');
  insert into fred (test) values ('D');
  insert into fred (test) values ('D');
  insert into fred (test) values ('E');
  insert into fred (test) values ('E');
  insert into fred (test) values ('E');

  I want a single statement that will update seq_no with a unique number for each test in seq_no insert value
  
  for example like this:
  

  SQL 001> select test, row_number() over (partition by test order by test) from fred
    2  /
  
  TEST                                               ROW_NUMBER()OVER(PARTITIONBYTESTORDERBYTEST)
  -------------------------------------------------- --------------------------------------------
  A                                                                                             1
  A                                                                                             2
  A                                                                                             3
  B                                                                                             1
  C                                                                                             1
  D                                                                                             1
  D                                                                                             2
  D                                                                                             3
  D                                                                                             4
  E                                                                                             1
  E                                                                                             2
  E                                                                                             3

  I am sure that this should be an easy thing, but for the life of me I can't figure out how do it in a single statement. I should know this... hangs head in shame

  Use MERGE

  SQL> merge into fred
    2  using (select rowid rid, test, row_number() over (partition by test order by test) sno
    3      from fred) fred1
    4     on (fred.rowid = fred1.rid)
    5  when matched then update
    6     set seq_no = sno
    7  /
  
  12 rows merged.
  
  SQL> select * from fred
    2  /
  
  TEST                                                   SEQ_NO
  -------------------------------------------------- ----------
  A                                                           1
  A                                                           2
  A                                                           3
  B                                                           1
  C                                                           1
  D                                                           1
  D                                                           4
  D                                                           3
  D                                                           2
  E                                                           1
  E                                                           2
  
  TEST                                                   SEQ_NO
  -------------------------------------------------- ----------
  E                                                           3
  
  12 rows selected.
  

• How to achieve using the analytical functions - please help

  Oracle version: 10g
  -999 means that all THE values for this key

  with input_parameters as (select 10 filter_key , '10ACCC' filter_value from dual union all
  select 50 filter_key ,'10ACCC0001' filter_value from dual union all
  select 60 filter_key , 'PIP' filter_value from dual union all
  select 70 filter_key , 'A' filter_value from dual) select * from input_parameters;
  
  
  with profile_search as(
  select 100 profile_id , 10 filter_key , '10ACCC' filter_value from dual union all 
  select 100 profile_id , 50 filter_key , '10ACCC0001' filter_value from dual union all
  select 100 profile_id , 50 filter_key , '10ACCC0002' filter_value from dual union all
  select 100 profile_id , 60 filter_key , '999' filter_value from dual union all
  select 100 profile_id , 70 filter_key , '999' filter_value from dual union all
  select 101 profile_id , 10 filter_key , '10ACCC' filter_value from dual union all
  select 101 profile_id , 50 filter_key , '10ACCC001' filter_value from dual union all
  select 101 profile_id , 60 filter_key , 'PIP' filter_value from dual union all
  select 101 profile_id , 70 filter_key , '999' filter_value from dual union all
  select 102 profile_id , 10 filter_key , '10ACCC' filter_value from dual union all
  select 102 profile_id , 50 filter_key , '10ACCC0001' filter_value from dual union all
  select 102 profile_id , 60 filter_key , 'PIP' filter_value from dual union all
  select 102 profile_id , 70 filter_key , 'A' filter_value from dual)
  select filter_key , wm_concat(filter_value) from profile_search group by profile_id, filter_key ;

  need to identify profile that matches input parameters
  ---------------------------------------------------------------------------
  
  102 is first match because it matches exactly
  101 is second match because 999 can match any value
  100 is third match 

  70 KEY HAS THE HIGHEST WEIGHT,
  A next highest weight KEY 60 and 50 next highest weight BUTTON
  
  
  required results:
  profile_id: 102
  
  Published by: devarade on January 19, 2010 20:01
  
  Published by: devarade on January 19, 2010 20:01

  I guess that there is a typing error in your sample:

  Select 101 profile_id, 50 filter_key, '10ACCC001' filter_value from all the double union

  must be:

  Select 101 profile_id, 50 filter_key, '01' filter_value from all 10ACCC00 the double union

  Then:

  with input_parameters as (
                            select 10 filter_key , '10ACCC' filter_value from dual union all
                            select 50 filter_key ,'10ACCC0001' filter_value from dual union all
                            select 60 filter_key , 'PIP' filter_value from dual union all
                            select 70 filter_key , 'A' filter_value from dual
                           ),
          profile_search as(
                            select 100 profile_id , 10 filter_key , '10ACCC' filter_value from dual union all
                            select 100 profile_id , 50 filter_key , '10ACCC0001' filter_value from dual union all
                            select 100 profile_id , 50 filter_key , '10ACCC0002' filter_value from dual union all
                            select 100 profile_id , 60 filter_key , '999' filter_value from dual union all
                            select 100 profile_id , 70 filter_key , '999' filter_value from dual union all
                            select 101 profile_id , 10 filter_key , '10ACCC' filter_value from dual union all
                            select 101 profile_id , 50 filter_key , '10ACCC0001' filter_value from dual union all
                            select 101 profile_id , 60 filter_key , 'PIP' filter_value from dual union all
                            select 101 profile_id , 70 filter_key , '999' filter_value from dual union all
                            select 102 profile_id , 10 filter_key , '10ACCC' filter_value from dual union all
                            select 102 profile_id , 50 filter_key , '10ACCC0001' filter_value from dual union all
                            select 102 profile_id , 60 filter_key , 'PIP' filter_value from dual union all
                            select 102 profile_id , 70 filter_key , 'A' filter_value from dual
                           )
  select  profile_id,
          sum(direct_match_cnt) || ' direct matches out of ' || (select count(*) from input_parameters) match
    from  (
           select  b.profile_id,
                   b.filter_key,
                   b.filter_value,
                   sum(case when b.filter_value = a.filter_value then 1 else 0 end) direct_match_cnt
             from  input_parameters a,
                   profile_search b
             where b.filter_key = a.filter_key
               and (b.filter_value = a.filter_value or b.filter_value = '999')
             group by b.profile_id,
                      b.filter_key,
                      b.filter_value
          ) x
    group by profile_id
    having count(*) = (select count(*) from input_parameters)
    order by sum(direct_match_cnt) desc
  /
  
  PROFILE_ID MATCH
  ---------- ----------------------------------------
         102 4 direct matches out of 4
         101 3 direct matches out of 4
         100 2 direct matches out of 4
  
  SQL> 
  

  SY.

• date ranges - possible to use analytical functions?

  The following datastructure must be converted into a daterange datastructure.
  

  START_DATE END_DATE      AMMOUNT
  ---------- ---------- ----------
  01-01-2010 28-02-2010         10
  01-02-2010 31-03-2010         20
  01-03-2010 31-05-2010         30
  01-09-2010 31-12-2010         40

  Working solution:

  with date_ranges
  as   ( select to_date('01-01-2010','dd-mm-yyyy') start_date
         ,      to_date('28-02-2010','dd-mm-yyyy') end_date
         ,      10                                 ammount
         from   dual
         union all
         select to_date('01-02-2010','dd-mm-yyyy') start_date
         ,      to_date('31-03-2010','dd-mm-yyyy') end_date
         ,      20                                 ammount
         from   dual
         union all
         select to_date('01-03-2010','dd-mm-yyyy') start_date
         ,      to_date('31-05-2010','dd-mm-yyyy') end_date
         ,      30                                 ammount
         from   dual
         union all
         select to_date('01-09-2010','dd-mm-yyyy') start_date
         ,      to_date('31-12-2010','dd-mm-yyyy') end_date
         ,      40                                 ammount
         from   dual
        )
  select   rne.start_date
  ,        lead (rne.start_date-1,1)  over (order by rne.start_date) end_date
  ,        ( select sum(dre2.ammount)
             from   date_ranges dre2
             where  rne.start_date >= dre2.start_date
             and    rne.start_date <= dre2.end_date
           ) range_ammount
  from     ( select dre.start_date
             from   date_ranges dre
             union -- implicit distinct
             select dre.end_date + 1
             from   date_ranges dre
           ) rne
  order by rne.start_date
  /

  Output:

  START_DATE END_DATE   RANGE_AMMOUNT
  ---------- ---------- -------------
  01-01-2010 31-01-2010            10
  01-02-2010 28-02-2010            30
  01-03-2010 31-03-2010            50
  01-04-2010 31-05-2010            30
  01-06-2010 31-08-2010
  01-09-2010 31-12-2010            40
  01-01-2011
  
  7 rows selected.

  However, I would like to use an analytical function to calculate the range_ammount. Is this possible?
  
  Published by: user5909557 on July 29, 2010 06:19

  Hello

  Welcome to the forum!

  Yes, you can replace the scalar sub-queriy with a SUMMARY, like this:

  WITH  change_data   AS
  (
       SELECT     start_date     AS change_date
       ,     ammount          AS net_amount
       FROM     date_ranges
            --
      UNION
            --
       SELECT     end_date + 1     AS change_date
       ,     -ammount        AS net_amount
       FROM     date_ranges
  )
  ,     got_range_amount     AS
  (
       SELECT     change_date          AS start_date
       ,     LEAD (change_date) OVER (ORDER BY  change_date) - 1
                                   AS end_date
       ,     SUM (net_amount)   OVER (ORDER BY  change_date)
                                  AS range_amount
       FROM    change_data
  )
  ,     got_grp          AS
  (
       SELECT     start_date
       ,     end_date
       ,     range_amount
       ,     ROW_NUMBER () OVER ( ORDER BY        start_date, end_date)
             - ROW_NUMBER () OVER ( PARTITION BY  range_amount
                                       ORDER BY          start_date, end_date
                         )         AS grp
       FROM    got_range_amount
  )
  SELECT       MIN (start_date)     AS start_date
  ,       MAX (end_date)     AS end_date
  ,       range_amount
  FROM       got_grp
  GROUP BY  grp
  ,            range_amount
  ORDER BY  grp
  ;
  

  This should be much more effective.

  The code is longer than what you posted. It is largely because it includes consecutive groups with the same amount.
  For example, if you add this line the sample data:

  --
         union all
         select to_date('02-01-2010','dd-mm-yyyy') start_date
         ,      to_date('30-12-2010','dd-mm-yyyy') end_date
         ,      0                                 ammount
         from   dual
  

  The query that you posted the product:

  START_DAT END_DATE  RANGE_AMMOUNT
  --------- --------- -------------
  01-JAN-10 01-JAN-10            10
  02-JAN-10 31-JAN-10            10
  01-FEB-10 28-FEB-10            30
  01-MAR-10 31-MAR-10            50
  01-APR-10 31-MAY-10            30
  01-JUN-10 31-AUG-10             0
  01-SEP-10 30-DEC-10            40
  31-DEC-10 31-DEC-10            40
  01-JAN-11
  

  I suppose you want only a new production line where the changes of range_amount., it is:

  START_DAT END_DATE  RANGE_AMOUNT
  --------- --------- ------------
  01-JAN-10 31-JAN-10           10
  01-FEB-10 28-FEB-10           30
  01-MAR-10 31-MAR-10           50
  01-APR-10 31-MAY-10           30
  01-JUN-10 31-AUG-10            0
  01-SEP-10 31-DEC-10           40
  01-JAN-11                      0
  

  Of course, you can change the original query so that it did, but it would eventually just as complex as the above query, but less effective.
  Conversely, if you prefer the longer output, then you need not got_grp Tahina-query in the above query.

  Thanks for posting the CREATE TABLE and INSERT statements; It is very useful.
  There are people who use this forum for years and have yet to be begged to do.