NUMBER of rows in the partition - shows null Calc.

Similar Questions

• Number of rows in each partition is displayed with a NULL value for a table partitioned in user_tab_partitions. Why?

  I created a table and partitioned on the date of the entry and added a local partitioned index.

  Now, I use a query to extract "num_rows" of user_tab_partitions to know the number of rows in each partition.

  Getting this value as null num_rows, wonder why?

  After looking to explain the Plan after interrogation ("select * from my_table1 where entry_date = 1 January 2015" ;))

  to find out if she actually partitioned table and its data in different partitions, I interpreted in effect because the query plan had a line like Partition_range (Single).

  My Question is:

  (a) is actually partitioned data (have I misinterpreted the Explain plan)

  (b) why is the num_rows null column in the query (Pasted below)

  (c) also in addition what difference it would have been if I had created a Global Index instead of the Local Index in my case?

  The following code Snippet:

  ----------------------------------------------------------------------------------------------

  create the table my_table1
  (
  roll_no number constraint my_table1_pk primary key,
  date of entry_date
  )
  partition of range (entry_date)
  (
  PARTITION data_p1 VALUES LESS THAN (TO_DATE (December 31, 2014 ',' DD-MM-YYYY ""));
  PARTITION data_p2 VALUES LESS THAN (MAXVALUE)
  );

  
  create an index only my_table1_indx on my_table1 (entry_date) local;

  ----------------------------------------------------------------------------------------------

  I now insert two lines:
  insert into my_table1 values (1, to_date ('01-01-2015', ' dd-mm-yyyy'));
  insert into my_table1 values (2, to_date('01-02-2015','dd-mm-yyyy'));

  ----------------------------------------------------------------------------------------------

  These have been inserted successfully, now using the query below shows num_rows column as null. I don't know why?

  SELECT table_name, num_rows, high_value, nom_partition
  Of user_tab_partitions
  where table_name = 'MY_TABLE1 '.
  ORDER BY table_name, nom_partition;

  ----------------------------------------------------------------------------------------------

  
  

  (a) is actually partitioned data (have I misinterpreted the Explain plan)

  Yes, it is partitioned. You can query this particular partition SELECT * FROM my_table1 (data_p1) PARTITION to check that.

  (b) why is the num_rows null column in the query (Pasted below)

  As already mentioned that you have not collected statistics.

  (c) also in addition what difference it would have been if I had created a Global Index instead of the Local Index in my case?

  In fact, you have created two types of indexes without knowing (can be)! One is not partitioned (although this column is not partition key) and another is partitioned (LOCAL). They are MY_TABLE1_PK and MY_TABLE1_INDX. You can check that USER_INDEXES.

  You can read this article to get an early jump on the partitioning of decision. Partition: Partition decisions

• Error creating a salary. ORA-01422: exact fetch returns more than the requested number of rows in the hr_maintain_proposal_swi procedure insert_salary_proposal package

  Hi all

  We try to add new proposal for a salary of some employees from form August 1, 2015 (the Date of the beginning of employee)

  There is no existing salary proposal doesn't exist for these employees.

  We get below error.

  
  

  ORA-01422: exact fetch returns more than the requested number of rows in the hr_maintain_proposal_swi procedure insert_salary_proposal package

  
  

  Help, please.

  Thank you

  Tarun

  Hi John,.

  If it helps, take a look at the following note:

  ORA-01422 exact Fetch returns more than number of lines requested in Hr_maintain_proposal_swi (Doc ID 1673527.1)

  Kind regards

  Rajen

• Get the number of rows in the oracle table

  Hi all
  I want to get the total number of rows in the sql to the appmodule table.
  After you apply the criteria to view some on the view object. If he try with getallrowsinrange the number of rows found within the viewobject was but I want a total number of rows in the sql table.
  
  How can I get that
  
  I use jdev 11.1.1.5
  
  Thanks in advance

  I threw something together, quick and dirty, don't hesitate to optimize.

  Assuming you want the County table, I put the code in a subclass of EntityDefImpl since it is representing a table in the middle tier.

  public class EmpDefImpl
        extends EntityDefImpl {
    /**
     * This is the default constructor (do not remove).
     */
    public EmpDefImpl( ) {}
  
    //~ Methods ****************************************************************************
  
    public long getTableRowCount( DBTransaction transaction ) {
      String query = getQuery( );
      String countQuery = String.format( "SELECT COUNT(*) FROM (%s)", query );
      long count = 0;
  
      ViewObject vo = transaction.createViewObjectFromQueryStmt( countQuery );
  
      try {
        vo.executeQuery( );
  
        Row row = vo.first( );
        Number number = (Number)row.getAttribute( 0 );
        count = number.longValue( );
      } finally {
        vo.remove( );
      }
  
      return count;
    }
  }
  

  Depending on your card type, you may not get an oracle.jbo.domain.Number, but something else, so the cast may need correction.

  Usage example:

  public class EmpEditViewImpl extends ViewObjectImpl {
    public EmpEditViewImpl() {
    }
  
    protected void executeQueryForCollection( Object object, Object[] object2, int i ) {
      super.executeQueryForCollection( object, object2, i );
  
      EmpDefImpl def = ( EmpDefImpl )getEntityDef( 0 );
      long tableRowCount = def.getTableRowCount( getDBTransaction() ) );
  
      // Do something with it
    }
  }
  

  As you can see, the code is fairly generic. Also, you might be able to put this in a base extension ADF class.

  Sascha

  Published by: Sascha Herrmann on June 7, 2012 14:39

• Display the option button if the number of rows in the table is equal to 1

  I'm having issues there buy maybe a simple script out there.

  I have a table which can have up to four lines. If the table contains only one row, an option button can be clicked to change the format/entry of cells in this row. I have to hide this box of a user option, if they added more of a line to the table and make it available again if they reduce the number of lines to one.

  I have everything else works well (radio buttons change line format, add/delete rows in the table using buttons, number of rows in the first column)

  Anyone have any ideas?

  See you soon

  Bobby

  You can place it in the code that adds more lines when running... If you have questions send the fomr to [email protected] so I can check it out...

  Thank you

  Srini

• number of rows in the table

  Hi master,

  I have a requirement. During the passage of a table, I need to get the number of rows in this table. Sometimes, when I spend 2 or more table names, I need to get the same count of result of lines. I got the below function. but it shows all the rows in the table. I want pariticular tabels only. How I can I get it.

  Select table_name, num_rows from all_tables where table_name in ('EMP', 'Department');  I tried.  I need to a procedure or function. who will pass the name of the table as a parameter and 1 or more than the name of a table if I pass, I need to display information from table name and number of lines.

  CREATE OR REPLACE

  TYPE t1_obj AS OBJECT)

  table-name VARCHAR2 (30),

  CNT NUMBER

  )

  /

  CREATE OR REPLACE

  TYPE t1_obj_tbl AS THE t1_obj TABLE

  /

  CREATE OR REPLACE

  FUNCTION (f1)

  p_schema_name VARCHAR2

  )

  RETURN t1_obj_tbl

  PIPELINED

  IS

  v_retval t1_obj: = t1_obj (null, null);

  BEGIN

  FOR v_rec IN (SELECT table_name FROM dba_tables where owner = upper (p_schema_name) and nvl (iot_type, 'X')! = "IOT_OVERFLOW") LOOP

  v_retval.table_name: = v_rec.table_name;

  RUN IMMEDIATELY "SELECT COUNT (*) FROM" | p_schema_name | '.' || v_rec.table_name

  IN v_retval.cnt;

  PIPE ROW (v_retval);

  END LOOP;

  RETURN;

  END;

  Select * from table (f1 ('scott'));

  The above function returns information from the table in SCOTT scheama. I need only perticular table info.

  Please notify.

  AR.

  Hi Sven,

  Front end people ask me the requirement. They wanted a proc or function as I want.

  Please help me.

  Concerning

  AR

• See the number of rows affected the performance of sqlplus to a sql file

  Hello

  It's just we have a sql file that contains a bunch of select/update/insert statements.

  I have a unix script that calls sqlplus on this sql file. However, at the exit I don't get the number of rows affected.

  Without adding any code in the input sql file, how can I change the code of sqlplus shell script to print the number of rows affected for each statement in the sql file?

  ${ORACLE_HOME}/bin/sqlplus -L >> ${LOG_FILE} 2>&1  << EOF
    ${ORAID}/${ORAPASS}@${ORAINS}
    whenever sqlerror exit sql.sqlcode;
    set echo on;
    set feedback off;
    set serveroutput on;
    @${SQL_FILE};
    exit;
  EOF
  RC=$?
  

  The SQL_FILE of entry content is:

  select 12 "col1" from dual;
  select 'abcd' "col2" from dual;
  select;
  select 13 'col3' from dual;
  

  The result of the race of sqlplus is (LOG_FILE):

  SQL*Plus: Release 11.2.0.2.0 Production on Fri Jun 6 14:28:00 2014
  
  Copyright (c) 1982, 2010, Oracle.  All rights reserved.
  
  Enter user-name: 
  Connected to:
  Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
  With the Partitioning, Real Application Clusters, Automatic Storage Management, OLAP,
  Data Mining and Real Application Testing options
  
  SQL> SQL> SQL> SQL> SQL> SQL> select 12 "col1" from dual;
  
        col1
  ----------
          12
  SQL> select 'abcd' "col2" from dual;
  
  col2
  ----
  abcd
  SQL> select;
  select
       *
  ERROR at line 1:
  ORA-00936: missing expression
  
  
  Disconnected from Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
  With the Partitioning, Real Application Clusters, Automatic Storage Management, OLAP,
  Data Mining and Real Application Testing options
  

  Thank you

  Srinivas - y.

  1. echo setting
  2. Set feedback off;

  use

  Set of feedback on

• Check the number and size of the partitions on VMware ESX

  As I am not responsible of the ESX host facilities, but will be responsible for the final ESX cluster I would check the configured partitions configured by our Tec facility to ensure that all hosts are configured correctly.

  Does anyone know of a CLI command to view the partitions (points of size and editing) of an ESX host.

  Paul

  P.S. I've tried using the df - h command, but I'm only displays a limited number of partitions, i.e.; / Boot and/var/log

  Evening,

  VDH h will show you all partitions, including those controlled by the VMKernel.

  Thank you

  Glen

• Question on the number of rows in the table bean

  Hello
  
  I have a table with the name of column to column, change the image...
  
  I 100 columns like that, and I set the number of lines to display in the 30
  
  Suppose that when I am in the 55th row in the table by clicking next... I clicked on the image for that particular line, it opens the new page. And now if I select Cancel button on this new page... I go to the previous screen that has table.
  But what my problem is it shows lines from the opening of the table... not the page (55th place) where I went to the new page. Is it possible to go to previously visited set of rows in the table?
  
  Please solve my problem.

  Hello

  When you browse the page, you can capture the index of the scope of the
  current line selected in the object attached to the table view and store
  the session

  OAViewObject oaviewobject = (OAViewObject) oaapplicationmodule.findViewObject ("YourVOName")
  int l = oaviewobject.getRangeStart ();
  pageContext.putSessionValue ("range", l);

  so when you return to the page and in process request you can reset the index of the range as previously selected.

  Range of String = (String) pageContext.getSessionValue ("range");
  int k = (int) Integer.parseInt (range);
  oaviewobject.setRangeStart (k);

  Thank you
  Gerard

• How to determine the number of rows in the database and save the result to a local variable?

  Hello

  I'm a newbie in the use of TestStand, databases and SQL, and now I've met difficulties. I use TestStand 2014 (32 bit).

  I have a need to know the number of rows in a database and save that number in a local variable. I tried to practice using the database of the Types of step provided with TS. I tried to use the following in a SQL statement:

  Locals.NumberOfRows = ("SELECT COUNT (*) FROM TEST_TABLE")

  It returns an error: specified value is not the expected type. My goal is possible in this way, or I'm doing this completely wrong?

  -RautSa

  Thank you for your response, Norbert. I have a database of who wins new values at random, and sometimes I need the exact number of rows in this table.

  I managed to achieve my goal by using the SQL statement: "SELECT COUNT (*) as Rowcount OF TEST_TABLE", followed by a data GET operation, which records that number of lines in a local variable.

  -RautSa

• How can I get the number of rows in the table using Sunopsis API target in ODI 10 g?

  Hi guys,.
  
  In fact, I want to send an alert message as soon as the interface is run from a package. I've included alert OdiSendMail that sends an email once the interface is running.
  
  Could someone please tell how to get the number of rows inserted into the table the Sunopsis API target.
  
  I tried to use < % = odiRef.getNbRows () % >, but this has not worked for me. Since I am a beginner, could you please help out me
  
  This is my mail to send ODI format
  
  "The population of data managed to < % = odiRef.getSysDate () % >
  
  Total of lines in the target table is: < - need an API code-> "
  
  
  Kind regards
  
  Clinton
  
  Published by: LawrenceClinton on February 25, 2013 20:53

  Hello

  Create the project with details below variable

  Nom_de_variable: Total_Row_Count

  Type of variable: Variable discount

  Definition tab:
  Data type: digital
  Action: No persistent

  Refresh the tab:
  Schema: provide the schema of your repository to work and be

  SELECT log.nb_row
  THE journal of snp_step_log, snp_scen_step step
  WHERE log.nno = step.nno
  AND step.scen_no = (SELECT scen_no FROM snp_scen_step WHERE step_name='<%=odiRef.getPrevStepLog ('STEP_NAME") % > ')
  AND log.sess_no = '< % = odiRef.getSession ("SESS_NO") % >' code at low
  AND step.step_name = ' < % = odiRef.getPrevStepLog ("STEP_NAME") % > '

  Note: add this variable after the stage of interface in your package (after the interface anywhere you can place), you can add this variable before ODISendEmailNotification in your package

  call this varciable * #Total_Row_Count * in the Notification of ODISendEmail

  for example :

  Data has been fulfilled successfully in < % = odiRef.getSysDate () % >
  Total no of lines filled are: * #Total_Row_Count *

  it will work

  cordially,
  Phanikanth

  edited by: Phanikanth on February 28, 2013 01:13

  edited by: Phanikanth on February 28, 2013 01:14

• Displays the number of rows in the table displaying a named criteria query data

  I created a test named for my View, called 'Criteria1' and Criteria1 to create a group of ADF with Table query. I want to display the number of rows in result when a search is performed. How can I do?
  
  Thanks in advance,
  Tom

  As mentioned, you can add outputText and you must give OutputText partialTriggers as query component your Id. Thus, when you give a search on the query component, it will refresh the outputText with the number of lines.

  
  ID = "ot1" partialTriggers = "id of the component of motion here" / > ""

• Add the number of rows in the table on the Page Framework OA

  Hi all
  
  I need to add a line at the bottom of a table in the OA framework to display the number of lines for the underlying table VO. Can someone point me in the right direction to get there?
  
  Thanks in advance!
  
  Kristopher

  Hi Kristopher,

  As directed by your post, my understanding is that you want to have a line at the bottom of the table that contains a field that displays the number of rows found in the t... RT?

  You can implement the same in the following way,
  You can add a footer to your table and add a messageStyledText point in it. At this point, you can assign the value of VO.getFetchedRowCount ().

  Hope this is what you are looking for.

  Kind regards
  REDA Papdeja

• Calculation of the number of rows in the query object

  Hi all
  I have a question:
  
  Is there a way to get the number of rows in a query object without running it twice?
  I need this for a calculation of total pages.
  I can't do something like:
  "SELECT COUNT (e) FROM employee e"
  because I have a WHERE clause in my expression.
  
  Thank you

  I don't think I've had this a simple that you would like to, but I was able to reuse the same query named to account real pagination queries request.

  I defined a named query:

          @NamedQuery(name = "Employee.findByNames", query = "select e from Employee e WHERE e.firstName LIKE :FNAME AND e.lastName LIKE :LNAME AND e.gender = :GENDER ORDER BY e.lastName, e.firstName")
  

  Now in the app, I can create an instance of the query for this named query and fill in the parameters using the:

          Query query = em.createNamedQuery("Employee.findByNames");
          query.setParameter("FNAME", "%");
          query.setParameter("LNAME", "%");
          query.setParameter("GENDER", "M");
  

  If I run this query I get all the lines, but instead, I'd like to create an account using the underlying native API query

          ReadAllQuery raq = JpaHelper.getReadAllQuery(query);
          ReportQuery reportQuery = new ReportQuery(raq.getReferenceClass(), new ExpressionBuilder());
          reportQuery.setSelectionCriteria(raq.getSelectionCriteria());
          reportQuery.setOrderByExpressions(raq.getOrderByExpressions());
          reportQuery.setShouldReturnSingleValue(true);
          reportQuery.addCount();
          Query countQuery = JpaHelper.createQuery(reportQuery, em);
  
          countQuery.setParameter("FNAME", "%");
          countQuery.setParameter("LNAME", "%");
          countQuery.setParameter("GENDER", "M");
  
          int count = ((Number)countQuery.getSingleResult()).intValue();
  

  Then, for each page of entities wanted the original query is executed as:

          query.setFirstResult(0);
          query.setMaxResults(5);
          List emps = query.getResultList();
  

  Doug

• Sign up between 2 tables without correspondence with values and keep the number of rows in the first Table

  Hello Experts,

  I have a problem that is a little tricky. Requirement is if 2 columns (region and Code in the tables below) match exactly, then it is Best Fit, if one of the columns match while it is average in shape, if the two columns do not match then it's worse to adapt.

  Create Table Table1 (varchar2 (10), varchar2 (10) of the filter region, Code varchar2 (10), revenue Number (15), owner varchar2 (5));

  Table1:

  Insert into Table1 values ('Test1', 'Midwest', '0900', 3000286, 'P1')

  Insert into Table1 values ('Test1', 'Midwest', '0899', 36472323, 'P2')

  Insert into Table1 values ('Test1', 'Midwest', '0898', 22472742, "P3")

  Insert into Table1 values ('Test1', 'West', '0901', 375237423, 'P1')

  Insert into Table1 values ('Test1', 'West', '0700', 34737523, null)

  Insert into Table1 values ('Test1', 'West', '0701', 95862077, "P3")

  Insert into Table1 values ('Test1', 'South', '0703', 73438953, 'P4')

  Insert into Table1 values ('Test1', 'South', '0704', 87332089, 'P1')

  Insert into Table1 values ('Test1', 'South', '0705', 98735162, 'P4')

  Insert into Table1 values ('Test1', 'South', '0706', 173894762, "P9")

  Insert into Table1 values ('Test1', 'South', '0902', 72642511, 'P6')

  Create Table Table2 (filter varchar2 (10), region varchar2 (10), Code varchar2 (10), plafond1 Number (15), Limit2 Number (15));

  Table2

  Insert into Table2 Values ('Test1', 'ALL', ' 0902', 15000, 10000)

  Insert into Table2 Values ('Test1', 'ALL', 'ALL', 20000, 12000)

  Insert into Table2 Values ('Test1', 'Midwest' ' 0900', 10000, 5000)

  Insert into Table2 Values ('Test1', 'Midwest', 'ALL', 18000, 8000)

  Insert into Table2 Values ('Test1', 'West', 'ALL', 16000, 6000)

  Insert into Table2 Values ('Test1', 'West', '0901', 10000, 5000)

  Final output

  Filter the income Code region owner plafond1 Limit2

  Test1 0900 3000286 P1 10 000 5 000 - Best Midwest (region because both Code Matches)

  Test1 0899 36472323 P2 Midwest 18 000 8 000 - way (because the region corresponds to only), we consider 'ALL' for the Code

  Test1 0898 22472742 P3 Midwest 18 000 8 000 - way (because the region corresponds to only), we consider 'ALL' for the Code

  Test1 West 0901 375237423 10 000 5 000 - Best P1 (region because both Code Matches)

  Test1 West 0700 34737523 16 000 6 000 - medium (because the area corresponds to only), we consider 'ALL' for the Code

  Test1 West 0701 95862077 P3 16 000 6 000 - way (because the region corresponds to only), we consider 'ALL' for the Code

  Test1 South 0703 73438953 P4 20 000 12 000 - worse (because region both Code DON T Match ' "), we consider option as worst 'ALL', 'ALL '.

  Test1 South 0704 87332089 P1 20 000 12 000 - worse (because region both Code DON T Match ' "), we consider option as worst 'ALL', 'ALL '.

  Test1 South 0705 98735162 P4 20 000 12 000 - worse (because region both Code DON T Match ' "), we consider option as worst 'ALL', 'ALL '.

  Test1 South 0706 173894762 P9 20 000 12 000 - worse (because region both Code DON T Match ' "), we consider option as worst 'ALL', 'ALL '.

  Test1 South 0902 72642511 P6 15 000 10 000 - way (because the Code corresponds to only) we consider 'ALL' for the region

  In the final result, we should have row count equal to Table1, and as soon as there's game (best first, then middle, then the worst), then if is once again, that we should ignore.

  There are other columns in the tables as well.

  Thank you very much!

  As you wish...

  select filter, region, code, region2, code2,
  revenue, owner, limit1, limit2, match
  from (
    select filter, region, code, region2, code2,
    revenue, owner, limit1, limit2, match,
    row_number() over(
      partition by filter, region, code order by match
    ) priority
    from (
      select a.filter, a.region, a.code, a.revenue, a.owner,
      b.region region2, b.code code2, b.limit1, b.limit2,
      case
        when (a.region, a.code) = ((b.region, b.code)) then 'Best'
        when a.region = b.region or a.code = b.code then 'Medium'
        else 'Worst'
      end match
      from table1 a
      join table2 b
      on a.filter = b.filter
      and (b.region, b.code) in (
        (a.region, a.code),
        (a.region, 'ALL'),
        ('ALL', a.code),
        ('ALL', 'ALL')
      )
    )
  )
  where priority = 1
  order by region, code;