Number Total between Gap

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• When count sum ID number total < 300

  Afternoon Folks,
  
  I was wondering if someone could help me with a query of code?
  
  I'm counting the number of Packs of Service where the total payment of the amount for each separate sp_id is less than 300 pounds and also more than 300 pounds.
  
  This is the code I have so far:
  
  Select the specialty
  count (distinct sp_id) "Service Packs",
  Sum (payment_total) "Total paid £»,
  round (sum (payment_total) / count (distinct sp_id), 0) 'average spend by MS.
  of a3_fact_sms_service_inv
  where specialized ("podiatry", "Podiatry")
  and service_date between '01 Jan 11' and 31 Dec 11'
  Specialty group
  
  This is the table that I want it to look
  
  SPECIALTY Service Packs Total paid £ average spend by SP * < 300 * > 300 *.
  Podiatry 129 25682,26 199 * 107 * 22 *.
  Podiatry 622 206651,08 332 * 403 * 219 *.
  
  I'm currently running application 10 g
  
  Concerning
  Farming :)

  First of all, ' 01 Jan 11' is not a date, but rather a string. Use literals date (or at least to_date):

  with t as (
             select  specialty,
                     sp_id,
                     sum(payment_total) sp_id_total
               from  a3_fact_sms_service_inv
               where specialty in ('Chiropody','Podiatry')
                 and service_date between date '2011-01-01' and date '2011-12-31'
               group by specialty,
                        sp_id
            )
  select  specialty,
          count(sp_id) "Service Packs",
          sum(sp_id_total) "Total Paid £",
          round(sum(sp_id_total) / count(sp_id)) "Average Spend per SP",
          count(case when sp_id_total < 300 then 1 end) "Service Packs Less £300",
          count(case when sp_id_total = 300 then 1 end) "Service Packs Equal £300",
          count(case when sp_id_total > 300 then 1 end) "Service Packs Greater £300"
    from  t
    group by specialty
  /
  

  SY.

• PIX-limit connections embrionic &amp; total between INSIDE and OUTSIDE.

  It is medium possible and straight forward to limit the number of connections embrionic and total if a PIX from the outside to the inside by using the parms in the NAT and STATIC commands.

  This list is possible to limit the embrionic connections and total from one host to the PIX INSIDE make the connections to the outside?

  Follow these steps exactly the same way. Assume that the host inside is 10.1.1.1.

  Keep in mind that if you have the following:

  public static 50.50.50.50 (Interior, exterior) 10.1.1.1 netmask 255.255.255.255 1000 25

  Then, it creates a static for the inside host 10.1.1.1 and will limit connections to or FROM this host to 1000.

  If you do not want to chew a static (and an external address) for this inside the host, you can do something like the following:

  Global interface 20 (external)

  NAT (inside) 20 10.1.1.1 1000 25

  and outbound connections to this host will be PAT had the address of the external interface, but will be limited to 1000 connections or semi-open 25.

• How do I see the number Total of Hits looking for Windows 7?

  The Windows XP search companion always informed the user the number of visits ("found 50 to date"), even in real time. In Windows 7, it is a confidential information jealously guarded, or so it seems.

  TIA,

  -RFH

  Hi Ray Cambridge,.

  If you want to know the number of files found after research all you have to do is you have to select all the files by pressing on Ctrl + A so that all the files will choose and then on the lower left corner, it will show the total number of files count.

  Hope this information is helpful and let us know if you need more assistance. We will be happy to help.

• Number of table gap

  RDBMS Version: 11.2.0.4

  OS: RHEL 6.6

  Total number of tables in this schema is 282. But, why East-County of user_segments.segment_type = 'TABLE' watch only 119? What is there such a difference?

  SQL > select count (*) from user_Tables;

  COUNT (*)

  ----------

  282

  SQL > select count (*) from user_objects where type_objet = "TABLE";

  COUNT (*)

  ----------

  282

  SQL >

  SQL > select count (*) from WHERE user_segments where segment_type = 'TABLE ';

  COUNT (*)

  ----------

  119

  -Various types of objects in this diagram and the number

  SQL > select segment_type, count (*) group WHERE user_segments by order segment_type of count (*) desc;

  SEGMENT_TYPE COUNT (*)

  ------------------ ----------

  INDEX 158

  TABLE                     119

  66 INDEX PARTITION

  LOBSEGMENT 33

  33 TABLE PARTITION

  LOBINDEX 33

  LOB PARTITION 33

  7 selected lines.

  Empty tables with delayed segment usually have a row in user_segments WHERE

• Obligation to print page numbers: number/Total reset Invoic to the Page level

  Hi all
  
  We have a requirement to print as page numbers below:
  
  4597 1/4. In this example, the number of trx is 4597 and it has 4 pages and the current page is number 1. To page 2, he printed at 4597 2/4. Page 3, to printed 4597 3/4 page 4, she to printed 4597 4/4.
  
  We are facing questions during reset the count at the level of the page as if we then head charge page numbers are displayed as: 2/1.
  
  Can you please help how we can solve this problem in the XML reports.
  
  Kind regards
  Suresh Reddy

  Do you use

  Concerning
  Charlotte

• Does Oracle 10g - Record Count/Total number of records.

  Hello, I'm looking to display the current records of number / total Records at the bottom left of a custom form. Please see below, made me know how this is done. Enjoy it!

  

  Thanks, Naveen.

  Your question is unclear.  Forms already did what you mentioned and appears as such in the image you downloaded.  If you don't see it in a particular form, open the form in the report generator and check at the level of the 'form', property 'The Console window' is not NULL and properly reflects the name of the appropriate window.  A NULL value prevents the message bar appears.

• No sales the total number of fotografías en vidéoconférence del ano (No. leaves the total number of photos in the year of the record)

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• JavaScript anomaly on the number of days between two dates

  Use ApEx 4.0, I found an anomaly in a javascript code that calculates the number of days between two dates, the current_date and the past_date. If the past and present is the or before March 10, 2013, and the current_date lies between 10 March 2013 and November 3, 2013, the number of days will be from 1 day to less than the actual number. Between November 3, 2013 and on 4 November 2013, the increments of number by 2, then the count will be accurate from this date forward.
  
  Here are some examples:
  
  March 10, 2013 = 69 days of December 31, 2012
  March 11, 2013 = 69 days of December 31, 2012
  March 12, 2013 = 70 days of December 31, 2012
  
  November 3, 2013 = 306 days in December 31, 2012
  November 4, 2013 = 308 days in December 31, 2012
  
  11 March should be 70 and 12 March should be 71. November 3 is 307 and 4 November corrects the number of fake, which began March 11.
  
  Change the past_date to March 10, 2013 produces the following:
  
  March 10, 2013 = 0 days of March 10, 2013
  March 11, 2013 = 0 days of March 10, 2013
  March 12, 2013 = 1 days of March 10, 2013
  
  But change the past_date to 11 March 2013, product of the correct numbers:
  
  March 11, 2013 = 0 days of March 11, 2013
  March 12, 2013 = 1 days of March 11, 2013
  March 13, 2013 = 2 days of March 11, 2013
  
  I would certainly all help to determine the cause of this anomaly. Here's the javascript code:
  
  var w1 = ($v ("P48_PAST_DATE"));
  W1 = (w1.toString ());
  vmon var = (w1.substr (3.3));
  vyr var = (w1.substr (7));
  var r = (vyr.length);
  If (r == 2)
  vyr. = (parseFloat (vyr) + 2000);
  vday var = (w1.substr (0.2));
  var y = (vmon.concat ("", vday, ",", vyr));
  y = Date.parse (y);
  
  var w2 = ($v ("P48_CURRENT_DATE"));
  var vmon2 = (w2.substr (3.3));
  var vyr2 = (w2.substr (7));
  var vday2 = (w2.substr (0.2));
  var x = (vmon2.concat ("", vday2, ",", vyr2));
  x = Date.parse (x);
  
  var numdays = (x - y);
  numdays = (Math.floor(numdays / 86400000));
  $s ("P48_NUMBEROFDAYS", numdays);

  Did you google for something like "javascript number of days between two dates. I think you will find the explanation to this observation:

  This method does not work correctly if there is an advanced economies jump between the two dates.

  There are examples available to calculate the difference between two dates.

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  Hello

  Click on the button down until the Tools option appears highlighted, and then click OK.

  Scrool up to the State of the printer report amd click OK.

  The printer Status Report list the number Total of Pages in the section printing information.

• calculate the percentage of error in the table with a reference number

  

  Hello

  I am able to make the mistake of column 0, table...

  How I would be writing the code for the column 1, 2, as well as the n column?

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• Total count repeated in each rtf page

  Hi all

  
  

  Here is the example of rtf code. Everything works fine, except the number Total is to repeat on each page. We want to show that ultimately not in every page. Any suggestions!

  
  

  Thank you

  
  

  Sushil
  

  
  

  
  

  <? for-each-group@section:G_1;. / REGION? > <? sorting: current-group () / REGION; ' ascending '; data-type = "text"? >

  Region: <? REGION of? >

  State: <? STATE? >

  <? start: body? > <? for-each-group@section:current-group();. / STATE? > <? sorting: current-group () / STATE; ' ascending '; data-type = "text"? >

  <? start: body? > <? for-each - group:current-group();. / STATUS_NAME? > <? sorting: current-group () / STATUS_NAME; ' ascending '; data-type = "text"? >

  EMP ID	CITY	COUNTY OF
  F EMP_ID	CITY_NAME	COUNTY_NAME E

  <? end for each group -? >

  <? : slim body? >

  <? end for each group -? >

  <? : slim body? >

  <? end for each group -? >

  Total: County EMP_ID                                                                                                                                              

  Since you are using for-each@section - County appeared on all pages.

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  Syntax:

  See the user guide on the use of the Designer's Guide report Oracle Fusion Middleware for Oracle Business Intelligence Publisher

• How to caluclate tat between two dates of a timestamp field

  Hello
  could help to caluclate days between two dates and unique timestamp filed with this
  query
  Select * from m_activity_transaction where actn_opp_id in)
  Select actn_opp_id in the m_activity_transaction where ACTN_ACTV_ID = 218
  Actn_opp_id group
  view count (*) > 1) and ACTN_ACTV_ID = 218
  order of actn_performed_on
  IAM get output is
  
  ACTN_ID ACTN_OPP_ID ACTN_PERFORMED_ON
  319415 95831 JANUARY 27, 12 AM 11.06.20.000000
  315249 95831 8 FEBRUARY 12 05.32.54.000000 PM
  301927 103509 20 DECEMBER 11 04.01.43.000000 PM
  301458 103509 19 DECEMBER 11 04.51.03.000000 PM
  294841 115840 10 JANUARY 12 03.20.12.000000 PM
  312062 115840 11 JANUARY 12 05.17.06.000000 PM
  
  Normand to caluclate number days between two dates like January 27, 12 AM 11.06.20.000000 and I 05.32.54.000000 8 February 12 PM where actn_id is unique AND ACTN_OPP_ID IS NOT UNIQUE.
  Thanks in advance,
  VVR.

  In this way.

  with data as
  (
  select 315249 a, 95831 b, to_date('27-JAN-12 11.06.20 AM', 'DD-MON-RR HH.MI.SS AM') dt from dual union all
  select 319415, 95831, to_date('08-FEB-12 05.32.54 PM', 'DD-MON-RR HH.MI.SS AM') from dual union all
  select 301927, 103509 , to_date('20-DEC-11 04.51.03 PM', 'DD-MON-RR HH.MI.SS AM') from dual union all
  select 301458 , 103509 , to_date('19-DEC-11 04.01.43 PM', 'DD-MON-RR HH.MI.SS AM') from dual union all
  select 363810 , 144656 , to_date('27-JUN-12 12.43.28 PM', 'DD-MON-RR HH.MI.SS AM') from dual union all
  select 363500 , 144656 , to_date('26-JUN-12 11.41.50 AM', 'DD-MON-RR HH.MI.SS AM') from dual union all
  select 363354 , 144656 , to_date('25-JUN-13 12.41.13 PM', 'DD-MON-RR HH.MI.SS AM') from dual
  )
  select a, b, diff_in_days
    from (
          select a, b, trunc(dt - lag(dt) over (partition by b order by dt, a)) diff_in_days
            from data
         ) tab
   where tab.diff_in_days is not null;
  
  A                      B                      DIFF_IN_DAYS
  ---------------------- ---------------------- ----------------------
  319415                 95831                  12
  301927                 103509                 1
  363810                 144656                 1
  363354                 144656                 362