% of column based on one of the lines in the previous column

Similar Questions

• Need to sort the instances of an entity or assign a rank to each of them based on one of the attributes.

  I need to assign a rank to each instance of an entity called 'Campaign', based on one of the attributes of the entity of campaign called "recipes". So, essentially, that we need to check the current instance with all other insatnces of campaign, assign the relative to the current row.

  Emergency assistance would be much appreciated. Thanks in advance.

  A common method is to create a relationship of self-esteem for the campaign.  Call it something like "lower income".

  Rule 1 creates relationships for campaigns that have a lower income:

  Campaign (target) is a member of the decline in revenues, if

  Revenue from target< compaign="">

  2 account rule the number of relationships to create a ranking (and puts the number in a variable called 'Campaign order number'):

  Campaign sequence number = the number of the decline in revenues

  The 'Order of campaign number' attribute in each entity now has your order in it.

• How to query the master block based on one of the values of the detail block

  Hello
  In the form of version 6i, I have a field in data block which is not defined as a database element. I use this field to store a block of retail value. If I want to ask the form using this field (which represents one of the values of retail block), how should I do this? Pointers?
  
  TIA,

  Yes, as Ammad10786 says, the ID's I mentioned are just placeholders for your real values. And done MASTERBLOCKID refers to columns in the masterblock which is the primary key or the join condition to the retail block.

• How to join two tables if you transpose the rows, columns and rows in one of the table

  Hi guys,.

  can someone help me please in the write request

  I have two tables

  Agents and Agent phones but in the agent phones table for the id of an agent it displays 4 rows because one of the column there types of different phones (office, mobile, home, fax)

  So instead of display 4 rows, I used max(case...) to convert rows to columns

  now how to reach it with another table

  Requirement:

  Database: 11.2.0.2.0

  create the table AGENT_PHONE

  (

  agent_id NUMBER (20) not null,

  agent_type_code VARCHAR2 (10) not null,

  agent_type_prefix VARCHAR2 (10) not null,

  Phone_Number VARCHAR2 (16) not null,

  phone_type_code VARCHAR2 (10) not null

  )

  CREATE TABLEAGENTS

  (

  agent_id NUMBER (20) not null,

  agent_type_code VARCHAR2 (10) not null,

  agent_type_prefix VARCHAR2 (10) not null,

  NAME VARCHAR2 (40) NOT NULL

  )

  INSERT INTO AGENT_PHONE(AGENT_ID,AGENT_TYPE_CODE,AGENT_TYPE_PREFIX,PHONE_NUMBER,PHONE_TYPE_CODE)

  VALUES (29709, ARE ', 'OFFICE', '4805551436', 'CELL');

  INSERT INTO AGENT_PHONE(AGENT_ID,AGENT_TYPE_CODE,AGENT_TYPE_PREFIX,PHONE_NUMBER,PHONE_TYPE_CODE)

  VALUES (29709, ARE ', 'OFFICE', '1111111111', 'PHONE');

  INSERT INTO AGENT_PHONE(AGENT_ID,AGENT_TYPE_CODE,AGENT_TYPE_PREFIX,PHONE_NUMBER,PHONE_TYPE_CODE)

  VALUES (29709, ARE ', 'OFFICE', '2223334444',' OFF');

  INSERT INTO AGENT_PHONE(AGENT_ID,AGENT_TYPE_CODE,AGENT_TYPE_PREFIX,PHONE_NUMBER,PHONE_TYPE_CODE)

  VALUES (29709, ARE ', 'OFFICE', '5556667788', 'FAX');

  INSERT INTO VALUES AGENTS

  (29709, ARE ', 'OFFICE', 'FLY');

  INSERT INTO VALUES AGENTS

  (1234, ARE ', 'OFFICE', 'MIKE');

  SELECT * FROM AGENT_PHONES

  AGENT_ID

  AGENT_TYPE_CODE

  AGENT_TYPE_PREFIX

  PHONE_NUMBER

  PHONE_TYPE_CODE

  ---------------------------------------------------------------------------------------------

  	29709			RE					OFFICE				4805551436		CELL
  	29709			RE					OFFICE				1111111111		PHONE
  	29709			RE					OFFICE				2223334444		OFF
  	29709			RE					OFFICE				5556667788		FAX

  SELECT * AGENTS

  AGENT_ID

  AGENT_TYPE_CODE

  AGENT_TYPE_PREFIX

  NAME

  29709

  RE

  OFFICE

  ROB

  1234

  RE

  OFFICE

  MIKE

  This is so the data we have in both table

  Now, I transposed rows to columns in the table of agent phones so I used the following query

  SELECT AP. AGENT_ID,. AGENT_TYPE_CODE,. AGENT_TYPE_PREFIX.

  MAX (CASE WHEN AP. PHONE_TYPE_CODE = 'CELL' THEN AP. PHONE_NUMBER END) AS CELL.

  MAX (CASE WHEN AP. PHONE_TYPE_CODE = 'OFF' THEN AP PHONE_NUMBER END) AS TURNED OFF.

  MAX (CASE WHEN AP. PHONE_TYPE_CODE = 'FAX' THEN AP. PHONE_NUMBER END) LIKE FAX,.

  MAX (CASE WHEN PHONE_TYPE_CODE = 'PHONE'. THEN AP PHONE_NUMBER END) AS PHONE

  AGENT_PHONE AP

  WHERE AP. AGENT_ID = 29709

  GROUP OF AP. AGENT_ID, AP. AGENT_TYPE_CODE, AP. AGENT_TYPE_PREFIX.

  	AGENT_ID	AGENT_TYPE_CODE	AGENT_TYPE_PREFIX	CELL	OFF	FAX	PHONE
  1	29709	RE	OFFICE	4805551436	2223334444	5556667788	1111111111

  My question is how this to join the agents table so that my output should be like this...

  I want to display all the results in the table of the Agent, even if they are not in the table of agent phones. As you can see there are other agent id 1234 is also populated

  AGENT_ID

  AGENT_TYPE_CODE

  AGENT_TYPE_PREFIX

  NAME

  AGENT_ID

  AGENT_TYPE_CODE

  AGENT_TYPE_PREFIX

  CELL

  PHONE

  OFF

  FAX

  --------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------

  	29709		RE					OFFICE					ROB			29709		RE					OFFICE				4805551436		1111111111		2223334444		5556667788
  	1234		RE					OFFICE					MIKE

  Currently, I run this query and I get the output as below

  SELECT *.

  AGENTS HAS

  LEFT OUTER JOIN AGENT_PHONE AP

  ON A.AGENT_ID = AP. AGENT_ID

  AND A.AGENT_TYPE_CODE = AGENT_TYPE_CODE.

  AND A.AGENT_TYPE_PREFIX = AGENT_TYPE_PREFIX.

  	AGENT_ID	AGENT_TYPE_CODE	AGENT_TYPE_PREFIX	NAME	AGENT_ID	AGENT_TYPE_CODE	AGENT_TYPE_PREFIX	PHONE_NUMBER	PHONE_TYPE_CODE
  1	29709	RE	OFFICE	ROB	29709	RE	OFFICE	4805551436	CELL
  2	29709	RE	OFFICE	ROB	29709	RE	OFFICE	1111111111	PHONE
  3	29709	RE	OFFICE	ROB	29709	RE	OFFICE	2223334444	OFF
  4	29709	RE	OFFICE	ROB	29709	RE	OFFICE	5556667788	FAX
  5	1234	RE	OFFICE	MIKE

  I want id 29709 agent in a line with 1234 agent also id to display

  You can rotate your phone number of agent in columns

  Select *.

  of AGENT_PHONE

  pivot)

  min (PHONE_NUMBER)

  for PHONE_TYPE_CODE in ('CELL' as a 'CELL', 'PHONE' like 'PHONE', 'OFF' in the 'OFF', 'FAX' as 'FAX')

  )

  AGENT_ID	AGENT_TYPE_CODE	AGENT_TYPE_PREFIX	CELL	PHONE	OFF	FAX
  29709	RE	OFFICE	4805551436	1111111111	2223334444	5556667788

  Then you can join to view inline or CTE

  with AGENT_PHONE_PIVOT like)

  Select *.

  of AGENT_PHONE

  pivot)

  min (PHONE_NUMBER)

  for PHONE_TYPE_CODE in ('CELL' as a 'CELL', 'PHONE' like 'PHONE', 'OFF' in the 'OFF', 'FAX' as 'FAX')

  )

  )

  SELECT *.

  AGENTS HAS

  LEFT OUTER JOIN AGENT_PHONE_PIVOT AP

  ON A.AGENT_ID = AP. AGENT_ID

  AND A.AGENT_TYPE_CODE = AGENT_TYPE_CODE.

  AND A.AGENT_TYPE_PREFIX = AGENT_TYPE_PREFIX.

  AGENT_ID	AGENT_TYPE_CODE	AGENT_TYPE_PREFIX	NAME	AGENT_ID	AGENT_TYPE_CODE	AGENT_TYPE_PREFIX	CELL	PHONE	OFF	FAX
  29709	RE	OFFICE	ROB	29709	RE	OFFICE	4805551436	1111111111	2223334444	5556667788
  1234	RE	OFFICE	MIKE	-	-	-	-	-	-	-

  Is that what you're looking for?

• How to upgrade one of the two lines in double

  I use 11.2.0.3.0

  Is it possible using a CASE statement to find the rows that are double and one of the two lines was updated so that they are all unique?

  What I get is something like this

  Col1	Col2	COL3	COL4	Col5
  1	1	1	1	1
  1	1	1	1	1
  2	2	2	2	2
  2	2	2	2	2
  3	3	3	3	3
  3	3	3	3	3
  4	4	4	4	4
  4	4	4	4	4
  5	5	5	5	5
  5	5	5	5	5

  I would change one of the columns in the two lines that makes the unique lines like this

  Col1	Col2	COL3	COL4	Col5
  1	1	1	1	1
  1	2	1	1	1
  2	3	2	2	2
  2	4	2	2	2
  3	5	3	3	3
  3	6	3	3	3
  4	7	4	4	4
  4	8	4	4	4
  5	9	5	5	5
  5	0	5	5	5

  Hello

  I don't see how a CASE expression would contribute to this problem.

  In your original message, you said you wanted to update the table, in other words, to permanently change some of the values stored in the table.

  In response, #2, looks like you want to change what is in the table, you just want to replace by new values for col2 in this query, without permanently changing table.  You can do this by using the ROW_NUMBER right in the query, when you thought using a CASE expression.

• How to give more relevance to one of the column in multi-column data store

  Hi gurus,
  
  When using multi-column datastore necessary to give more importance to one of the other column. How can we achieve the same?
  

  SQL > create table test_sh4 (text1, text2 clob clob);
  
  Table created.
  
  SQL > alter table test_sh4 Add (Text3 clob);
  
  Modified table.
  
  SQL > start
  2 ctx_ddl.create_preference ('nd_mcd', 'multi_column_datastore');
  3 ctx_ddl.set_attribute
  4 ("nd_mcd",
  5 "columns."
  6 ' replace (Text1, "", "") nd, Text1 text1, replace (Text1, "", "') nd, Text1 text1');
  7 ctx_ddl.set_attribute ('nd_mcd', 'separator', 'new line');
  8 ctx_ddl.create_preference ('test_lex1', 'basic_lexer');
  9 ctx_ddl.set_attribute ('test_lex1', 'spaces', ' /--------|-_ + "");
  10 end;
  11.
  
  PL/SQL procedure successfully completed.
  
  SQL > create index IX_test_sh4 on test_sh4 (Text3)
  indexType is ctxsys.context
  parameters
  ("nd_mcd of the data store
  lexer test_lex1')
  / 2 3 4 5 6
  
  Index created.

  Here, while querying how can I give more relevant for the text1 Text2 column as column?

  I gave an example below. I added some data to your example. You had tags and columns duplicated in your multi_column_datastore, so I fixed it those. I removed the newline delimiter and added a section with sections of field group and add this section to the index settings group. Allows you to search in each section of field and apply different fats. You can apply weights by multiplying by a value entre.1 and 10 or several times multiplier to reduce or increase the score for a particular section.

  SCOTT@orcl_11gR2> -- table structure you provided:
  SCOTT@orcl_11gR2> create table test_sh4 (text1 clob,text2 clob);
  
  Table created.
  
  SCOTT@orcl_11gR2> alter table test_sh4 add (text3 clob);
  
  Table altered.
  
  SCOTT@orcl_11gR2> -- added data:
  SCOTT@orcl_11gR2> insert all
    2  into test_sh4 (text1, text2, text3)
    3    values ('testword', 'word2', 'word3')
    4  into test_sh4 (text1, text2, text3)
    5    values ('word4', 'testword', 'word5')
    6  into test_sh4 (text1, text2, text3)
    7    values ('test word', 'word2', 'word3')
    8  into test_sh4 (text1, text2, text3)
    9    values ('word4', 'test word', 'word5')
   10  select * from dual
   11  /
  
  4 rows created.
  
  SCOTT@orcl_11gR2> -- fixed duplicate column names and tags and
  SCOTT@orcl_11gR2> -- removed newline delimiter and
  SCOTT@orcl_11gR2> -- added section group with field sections:
  SCOTT@orcl_11gR2> begin
    2    ctx_ddl.create_preference ('nd_mcd', 'multi_column_datastore');
    3    ctx_ddl.set_attribute
    4        ('nd_mcd',
    5         'columns',
    6         'replace (text1, '' '', '''') nd1,
    7          text1 text1,
    8          replace (text2, '' '', '''') nd2,
    9          text2 text2');
   10    ctx_ddl.create_preference ('test_lex1', 'basic_lexer');
   11    ctx_ddl.set_attribute ('test_lex1', 'whitespace', '/\|-_+');
   12    ctx_ddl.create_section_group ('test_sg', 'basic_section_group');
   13    ctx_ddl.add_field_section ('test_sg', 'text1', 'text1', true);
   14    ctx_ddl.add_field_section ('test_sg', 'nd1', 'nd1', true);
   15    ctx_ddl.add_field_section ('test_sg', 'text2', 'text2', true);
   16    ctx_ddl.add_field_section ('test_sg', 'nd2', 'nd2', true);
   17  end;
   18  /
  
  PL/SQL procedure successfully completed.
  
  SCOTT@orcl_11gR2> -- added section group to index:
  SCOTT@orcl_11gR2> create index IX_test_sh4 on test_sh4 (text3)
    2  indextype is ctxsys.context
    3  parameters
    4    ('datastore     nd_mcd
    5        lexer          test_lex1
    6        section group     test_sg')
    7  /
  
  Index created.
  
  SCOTT@orcl_11gR2> column text1 format a10
  SCOTT@orcl_11gR2> column text2 format a10
  SCOTT@orcl_11gR2> column text3 format a10
  SCOTT@orcl_11gR2> -- without weighting:
  SCOTT@orcl_11gR2> select score (1), t.* from test_sh4 t
    2  where  contains
    3             (t.text3,
    4              'testword',
    5              1) > 0
    6  /
  
    SCORE(1) TEXT1      TEXT2      TEXT3
  ---------- ---------- ---------- ----------
           6 testword   word2      word3
           6 word4      testword   word5
           3 test word  word2      word3
           3 word4      test word  word5
  
  4 rows selected.
  
  SCOTT@orcl_11gR2> -- with weighting:
  SCOTT@orcl_11gR2> select score (1), t.* from test_sh4 t
    2  where  contains
    3             (t.text3,
    4              '(testword within text1) * 10 or
    5            (testword within nd1)     *  5 or
    6            (testword within text2) * .5 or
    7            (testword within nd2)     * .1',
    8              1) > 0
    9  order  by score (1) desc
   10  /
  
    SCORE(1) TEXT1      TEXT2      TEXT3
  ---------- ---------- ---------- ----------
          48 testword   word2      word3
          20 test word  word2      word3
           2 word4      testword   word5
           1 word4      test word  word5
  
  4 rows selected.
  

• Find all the lines from the previous column value difference lines

  I have an interesting requirement. There is a DATE column and a user in one table and I have to find all the lines for all users for which the previous and the current line has lagged in lets say more than 30 minutes. The rows are already sorted in time.
  
  For example in the following table, we need to ID 4 and 6 for user 1.
  
  
  Date of the user ID
  1 1 today 1 hr. 0 Min. 0 sec.
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  Today 3 1 1 hour 29 min 0 s
  * 4-1 today 1 hour 59 min 3s *.
  5 1 today 2 hours 10 min 2 sec
  * 6 1 today 2 hours 50 min 7 s *.
  
  Published by: user733179 on March 5, 2009 12:00

  Hello

  To obtain a separate calculation for each value of the usr, start the analytical clause with "BY usr PARTITION":

  WITH     got_dif     AS
  (
       SELECT     id,     dt,     usr
       ,     (dt - LAG (dt)
                  OVER ( PARTITION BY  usr
                            ORDER BY          dt
                          )
            )             -- difference in days
                * 24 * 60  AS minutes_dif
       FROM     table_x
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  )
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  FROM     got_dif
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  ;
  

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  Printer HP 2050 all-in-one

  Windows 7 Prof 64

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• APEX 4.2.5: How reference a column element in the previous line?

  Good afternoon

  I have the following problem:

  I have an IR on a table that contains the values of daily clock of energy (gas and electricity).

  Now, I want to set up a calculated column that contains the daily consumption.
  Power_actual_row - power_previous line.

  Is this possible and if yes how can I achieve this?

  Kind regards.

  Wilfried

  Baerenmarke wrote:

  I have the following problem:

  I have an IR on a table that contains the values of daily consumption of energy (gas & electricity) clock.

  Now, I want to set up a calculated column that contains the daily consumption.
  Power_actual_row - power_previous line.

  Is this possible and if yes how can I achieve this?

  Add a POWER_PREVIOUS column to your report query using the analytical function LAG to access the value of the POWER of the previous row. Use the ORDER byclause in the function to determine the order of the lines. The calculation of the IR then simply uses the POWER and POWER_PREVIOUS values for the same line.

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  Hello

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  < b >

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  }

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  text-align: left;

  }

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  }

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• How can I get a continuous square wave to the duty cycle of 50% on one of the analog lines?

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• Conditional formula using one of the two operations

  How to create a conditional formula where the results are a choice between two formulas based on the cell to two cells has a value greater than 0?  More specifically, I have to add value in a cell (in the column headed "added amount") to a cell in a column of the running totals if the value of this cell is greater than 0, or subtract the value of a different cell (in the column headed "amount withdrawn") in the same line, if the value of this cell is greater than 0.  Only one of the two will have a value in a given line.

  Hi George,.

  If you only have a value in a column, then you have even a logical formula. You can do this:

  

  A2 is an input value, it could be called "balance forward".

  A3 is filled down.

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