On Google, Ffox 3.6.12 shows only 10 results even when I specify 100; Mac G4 10.4.11. other browsers show 100 without problem.
On my Mac G4 two-way to 1.25 GHz Power PC with OS X 10.4.11 and Firefox 3.6.12, when I opened Google and specify 100 results like this...
http://www.Google.com/advanced_search?hl=en & num = 100
.. .it always shows just 10 results. While Opera and Safari (I don't use Internet Extorter) show 100 results no problem to use this URL.
Problem was occurring at least since Firefox 3.6.9 if I remember correctly. Not sure if it was going on before that.
Google has recently made a few changes on the site to Google search with the addition of instant search and who made the adjustment of the number of results in the settings of Google to stop working.
If Instant Search is enabled in the settings of Google search page (link at the top right) then you get only 10 results.
You must disable Instant Search and reload the result page, and then set the number of results to your preferred choice.
It may not work if you change both at the same time.
There is a link directly to the right of the Google search box on the Google results page.
It's a button with a drop-down list: moment is On / Off.
There is also a radio check box in the page settings of Google, which has replaced the previously used Suggestions.
Tags: Firefox
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Dear Sir/Madam,
I am a user of windows from win98, and I never had a problem with the printer that I couldn't solve. But now, my printer prints only half of the document, and troubleshooting said: there is no problem, I printed the rpinter windows test page, but I only got half! in view of this, I wonder if you would be so kind as to send me the solution to my problem, my resources and understanding have exhausted. Thank you in anticipation of your kind cooperation.Hi Sergio,
We would like to ask after the details with you to help you to come.
(1) what is the brand and model of your computer?
(2) don't you make changes to the printer settings prior to this problem?
(3) is the issue limited to any particular document?
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You might face this question when the printer drivers are corrupt or if the Windows service does not work properly. Follow the troubleshooting methods listed below.
Solve printer problems
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Why can I not print?
http://Windows.Microsoft.com/en-in/Windows7/why-cant-i-print
Check the question and write us with the State of the question. We will help you if you need assistance.
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See the question. That's all what it!
This has happened
Each time Firefox opened
Uninstall ask
Several free programs will install Ask 'Special Edition '. Foxit Reader, you have installed, is one of these. You must not choose on these items or to download the free program or during the installation of the free program. Foxit Reader, the opt-out is during the installation of Foxit Reader. See the image attached to the opt-out Foxit Reader.First try to disable or uninstall the Ask.com toolbar in Firefox via "tools-> Add-ons-> Extensions". See: disable or remove modules.
In some cases, you may need to uninstall the Ask toolbar, using the Windows Control Panel. See cannot uninstall an add-on - uninstall of Windows Add/Remove Programs.
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See: http://kb.mozillazine.org/Keyword.URL for more details.See:
http://KB.mozillazine.org/Problematic_extensions#Ask_Toolbar
http://KB.mozillazine.org/Uninstalling_toolbarsOther topics: ~ ~ Red: you have installed the plug-ins with known security issues. You must update them immediately. ~ ~
Java Update: your worm. 1.6.0.17; current version 1.6.0.20 (important update 15/04/2010)
(Firefox 3.6 and above requires Java 1.6.0.10 or above; see: http://support.mozilla.com/en-US/kb/Java-related+issues#Java_does_not_work_in_Firefox_3_6 )
(Windows users: do the update manually, very easy.)
~ ~ Red: check your version here ~ ~: http://www.mozilla.com/en-US/plugincheck/
See: Java Update
Do the update with Firefox closed.NOTE: there is no need to have 2 PDF readers, you have Adobe Reader and Foxit Reader. Uninstalling one is made using the setting > Control Panel > Add / Remove Programs (with Firefox closed).
If you intend to keep Adobe Reader:
You ~ ~ Red:PEUT~ ~ need to update Adobe Reader for Firefox (aka Adobe PDF plug-in for Firefox): your worm s/o; current version 9.3.3 (updated security important release 29/06/2010; See: http://www.adobe.com/support/security/bulletins/apsb10-15.html)
~ ~ Red: check your version here ~ ~: http://www.mozilla.com/en-US/plugincheck/
See: http://support.mozilla.com/en-US/kb/Using+the+Adobe+Reader+plugin+with+Firefox#Installing_and_updating_Adobe_Reader
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If you go to the Adobe site to download the course Adobe Reader:
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I just upgraded to 25.0 FireFox and I have problems of visualization of Google ads and Facebook comments and love on my site (wellfitstyle.com). All other browsers show Google adds comments in the right sidebar and Facebook and like below each post. Many people in Eastern Europe (where I am) using FireFox and I would like to know how this problem can be solved.
TNX.
Try Firefox Safe mode to see if the problem goes away. Safe mode is a troubleshooting mode, which disables most of the modules.
(If you use it, switch to the default theme).
- Under Windows, you can open Firefox 4.0 + in Safe Mode holding the key SHIFT key when you open the desktop Firefox or shortcut in the start menu.
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Once you get the pop-up, simply select "" boot mode safe. "
If the issue is not present in Firefox Safe Mode, your problem is probably caused by an extension, and you need to understand that one. To do this, please follow article Troubleshooting extensions, themes and problems of hardware acceleration to resolve common Firefox problems .
To exit safe mode of Firefox, simply close Firefox and wait a few seconds before you open Firefox for normal use again.
The report please come back shortly.
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Hi, Urbisoler,
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Best way to details data and show of force only last result in Group
Hi all! First, just let all the world know that it is a great place to explore and learn Oracle - I learned more here than I have in some classes. Come and explore the forums and looking for an answer lead me to the functions that I hadn't known otherwise existed.
Here's what I'm trying to do now... Let's say I have a table that contains information about the family - if two or more persons associated with a family (determined by a separate table) then it should return the person identification and then the details of the group.
For example, the following data are contained in two tables, the follow-up of current results and then the result, that I'm looking...
PERSONS TABLE ---------------------- PERSON PERSON_ID ADDRESS John Smith 101 1 Oracle Drive Jane Smith 102 1 Oracle Drive
A simple query would result in the following text:RELATIONSHIPS TABLE ----------------------------- PERSON_ID RELATEDPERSON_ID 101 102 102 101
RESULTWITH PERSONS AS ( SELECT 'John Smith' AS person, 101 AS person_id, '101 Oracle Drive' AS address FROM dual union all SELECT 'Jane Smith', 102, '101 Oracle Drive' FROM dual ) , RELATIONSHIPS AS ( SELECT 101 AS person_id, 102 AS relatedperson_id FROM dual union all SELECT 102, 101 FROM dual ) SELECT person , address FROM PERSONS p JOIN RELATIONSHIPS r ON r.person_id = p.person_id
I'm looking to produce the following result, but I do not know how... I am convinced that it is something simple.PERSON ADDRESS John Smith 101 Oracle Drive Jane Smith 101 Oracle Drive
DESIRED RESULT
Note that the address for members of the family is not displayed until the last member of the family is returned. It repeats this process for each family.PERSON ADDRESS John Smith Jane Smith 101 Oracle Drive
Thank you all for any help you can provide! 31%
Published by: nage62587 on October 16, 2012 20:20Hello
nage62587 wrote:
I did a lot of searching the forum and revised my question a bit hopefully make things a little clearer... I got a request Frank wrote and revised to meet my criteria.The forum search (and other places on the web) is great! Not only are you things, but the people on this forum are more likely to help you when they see you do everything you can.
If you find something that you are trying to adapt, post a link to it. Seeing the correct way to adapt it can be very instructive.essentially, if I can determine which members of the family someone is, then I can create a unique "FAMILY_ID" for them - once I have that, it would seem that I could then use the FAMILY_ID to combine their addresses and other information.
The problem I have is that if a RELATEDPERSON_ID is linked to a PERSON_ID (PERSON_ID related RELATEDPERSON_ID works very well), he attributes them a new FAMILY_ID, rather than include them in the correct family.
Here is my sql
WITH PERSONS AS ( SELECT 'John Smith' AS person, 101 AS person_id, '1 Oracle Drive' AS address FROM dual union all SELECT 'Jane Smith', 102, '1 Oracle Drive' FROM dual union all SELECT 'Jack Smith', 103, '8 Oracle Drive' FROM dual union all SELECT 'John Doe', 104, '10 Oracle Drive' FROM dual union all SELECT 'Jane Doe', 105, '10 Oracle Drive' FROM dual union all SELECT 'Pete Smith', 106, '1 Oracle Drive' FROM dual ) , RELATIONSHIPS AS ( SELECT 101 AS person_id, 102 AS relatedperson_id FROM dual union all SELECT 102, 101 FROM dual union all SELECT 104, 105 FROM dual union all SELECT 105, 104 FROM dual union all SELECT 106, 101 FROM dual ) , table_x AS ( SELECT person_id AS col1 , relatedperson_id AS col2 FROM relationships ) , got_relatives AS ( SELECT col1 , CONNECT_BY_ROOT col2 AS relative FROM table_x CONNECT BY NOCYCLE col1 = col2 OR col2 = col1 ) SELECT col1 , DENSE_RANK () OVER ( ORDER BY MIN (relative) ) AS family_id FROM got_relatives GROUP BY col1
I think the result is:
COL1 FAMILY_ID ----- ---------- 102 1 106 1 101 1 105 2 104 2
I suspect that whatever you copied originally had the FIRST keyword somewhere in the CONNECT BY clause.
Here's a way to do what you want:
WITH all_relationships AS ( SELECT person_id , relatedperson_id FROM relationships UNION SELECT relatedperson_id AS person_id , person_id AS relatedperson_id FROM relationships ) , got_relatives AS ( SELECT CONNECT_BY_ROOT person_id AS person_id , relatedperson_id FROM all_relationships CONNECT BY NOCYCLE person_id = PRIOR relatedperson_id OR relatedperson_id = PRIOR person_id ) , got_family_id AS ( SELECT person_id , MIN (relatedperson_id) AS family_id , ROW_NUMBER () OVER ( PARTITION BY MIN (relatedperson_id) ORDER BY person_id DESC ) AS r_num FROM got_relatives GROUP BY person_id ) SELECT p.person , CASE WHEN f.r_num = 1 THEN p.address END AS address , p.person_id , f.family_id FROM got_family_id f JOIN persons p ON p.person_id = f.person_id ORDER BY family_id , person_id ;
Output:
PERSON ADDRESS PERSON_ID FAMILY_ID ---------- --------------- ---------- ---------- John Smith 101 101 Jane Smith 102 101 Pete Smith 1 Oracle Drive 106 101 John Doe 104 104 Jane Doe 10 Oracle Drive 105 104
Obviously, you don't have to see all the columns, I posted above in your first post, you said you wanted only person and address. In your last message, you said you wanted only person_id and family_id. change the SELECT main clause just as you wish.
I used the lowest person_id in each family as the family_id. You can use DENSE_RANK if you really want to have families numbered 1, 2, 3,..., but I suspect that you really care what family_id, as long as all the members of the family have the same value.
Table of relationship a you certain symmetrical, such as relationships
SELECT 104, 105 FROM dual union all SELECT 105, 104 FROM dual union all
and a few asymmetric relations. For example, the only relationship involving person_id = 106 is
SELECT 106, 101 FROM dual
in other words, there is no line of mirror-image:
-- SELECT 101, 106 FROM dual union all -- THIS IS NOT IN THE SAMPLE DATA
I guess it didn't matter to that. As long as 101 and 106 appear on the same line, they are in the same family, regardless of the person_id and which is the relatedperson_id.
The first thing I did above was therefore to ensure that all lines of the mirror-image were represented. This is what all_relationships does.
The following subquery, got_relatives, is probably what you mean to adapt, but you let him operators PREREQUISITES.
Got_family_id does the grouping and also calculates r_num to determine which is the last member of the family. Address of this member of the family only will be displayed in the main query.
You could combine got_family_id and the main request; you don't need really a subquery for this. It would be a little less coding, but I wrote it that way because I think it's a little easier to understand and maintain. -
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Indexing by a double seems to be ok in Labview. I understand the problem however. The labview functions actually worked, I was just incorrect printing. I was really stupid and my printf statement was printf ("%d", value) printf ("% lf, value) which is what you need for the double rooms, and he did print always 0. Thanks for your help though guys.
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