Operations of the large pool and user sessions

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• Ask the operation slow with large SGA and fast with little CMS

  Hello

  We have a situation where one of the insert is running slow and fast QA in PROD. Both are the same versions of database - Oracle 10.2.0.4 on HP Unix 11.31. To avoid the cause of databases running on another server, we copied from our Production database to the same server where the QA database is running and began with init.ora PROD that has 7 GB 6 GB SGA_TARGET and SGA_MAX_SIZE. For the QA database, SGA_MAX_SIZE is 700 MB and SGA_TARGET is 600 MB. Both are running on the same server, and with the same data. We have refreshed QA with data from PROD. If we start with PROD init.ora QA database, QA also behaves the same way PROD.

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  call the query of disc elapsed to cpu count current lines
  ------- ------  -------- ---------- ---------- ---------- ----------  ----------
  Parse        1      0.00       0.00          0          0          0           0
  Run 1 56710.39 56067,75 7343 311186373 0 0
  Fetch        0      0.00       0.00          0          0          0           0
  ------- ------  -------- ---------- ---------- ---------- ----------  ----------
  Total 2 56710.39 56067,76 7343 311186373 0 0

  Chess in the library during parsing cache: 1
  Optimizer mode: CHOOSE
  The analysis of the user id: 27 (TEST)

  Rows Row Source operation
  -------  ---------------------------------------------------
  0 CRDETAIL of SEQUENCE (cr = 0 pr = 0 pw = time 0 = 29 US)
  0 REVIEWS (cr = 0 pr = 0 pw = time 0 = 21 US)
  0 SORT GROUP BY (cr = 0 pr = 0 pw = time 0 = 20 US)
  401 HASH RIGHT SEMI JOIN (cr = 23299915 pr 7343 pw = time = 0 = 93982966 en)
  237 TABLE ACCESS BY INDEX ROWID CR_STRUCTURE_VALUES2 (cr = 96 pr = 0 pw = time 0 = 504 en)
  253 CR_STRUCTURE_VALUES2_PK INDEX RANGE SCAN (cr = 4 pr = 0 pw = time 0 = 278 en)(object id 1467582)
  TABLE ACCESS BY INDEX ROWID CR_COST_REPOSITORY 841 (cr = 23306003 pr 7343 pw = time = 0 = 94546465 en)
  1317368058 NESTED LOOPS (cr = 79721182 pr 7343 pw = time = 0 = 18565176955 en)
  VIEW 26912 (cr = pr 9874 7343 pw = time = 0 = 5269231 en)
  26912 MINUS (cr = pr 9874 7343 pw = time = 0 = 5242317 en)
  27462 SORT UNIQUE (cr = 9627 pr = 7329 pw = time 0 = 5040815 en)
  271564 CR_STRUCTURE_VALUES2 TABLE FULL ACCESS (cr = 9627 pr = 7329 pw = time 0 = 1357961 en)
  568 SORT UNIQUE (cr = 247 pr = 14 pw = time 0 = 43467 US)
  TABLE ACCESS BY INDEX ROWID CR_STRUCTURE_VALUES2 2357 (cr = 247 pr = 14 pw = time 0 = US 14751)
  2357 CR_STRUCTURE_VALUES2_PK INDEX RANGE SCAN (cr = pr 11 = 14 pw = time 0 = 10028)(object id 1467582) US
  INDEX RANGE SCAN CRCR_MN_IX 1317341146 (cr = 79711308 pr = 0 pw = time 0 = 50420511 US)(object id 1469401)

  
  Implementation plan of lines
  -------  ---------------------------------------------------
  0 THE INSERT STATEMENT MODE: CHOOSE
  SEQUENCE "CRDETAIL" 0 (SEQUENCE)
  0 REVIEWS
  0 TRI (GROUP BY)
  401 HASH JOIN (RIGHT HALF)
  HOW TO ACCESS THE TABLE 237: ANALYSES (BY INDEX ROWID) OF
  "CR_STRUCTURE_VALUES2" (TABLE)
  INDEX 253 MODE: SCANNED (SCAN INTERVAL) OF
  "CR_STRUCTURE_VALUES2_PK" ((UNIQUE) INDEX)
  ACCESS MODE TO THE 841 TABLE: ANALYSIS (BY INDEX ROWID) OF "CR_COST_REPOSITORY" (TABLE)
  1317368058 NESTED LOOPS
  VIEW 26912
  26912 LESS
  27462 SORT (SINGLE)
  TABLE 271564 ACCESS MODE: ANALYZED (FULL) OF
  "CR_STRUCTURE_VALUES2" (TABLE)
  568 (SINGLE) SORT
  HOW TO ACCESS THE TABLE 2357: ANALYSES (BY INDEX ROWID)
  OF "CR_STRUCTURE_VALUES2" (TABLE)
  INDEX 2357 MODE: SCANNED (SCAN INTERVAL) OF
  "CR_STRUCTURE_VALUES2_PK" ((UNIQUE) INDEX)
  MODE 1317341146 INDEX: ANALYSIS (SCAN INTERVAL) OF "CRCR_MN_IX".
  (INDEX)

  ********************************************************************************

  And here is the statement in question:

  INSERT
  INTO cr_allocations_stg
    (
      "ID",
      "COMPANY",
      "GL_ACCOUNT",
      "COST_CENTER",
      "COST_ELEMENT",
      "PROFIT_CENTER",
      "MASTER_ORDER",
      "ORDER_NUMBER",
      " FUNDING_PROJECT",
      "POSTING_ORDER",
      "POSTING_COST_CENTER",
      "ORIG_COST_ELEMENT",
      "ORIG_COST_CENTER",
      "ORIG_PROFIT_CENTER",
      "TRADING_PARTNER",
      "WORK_ORDER_NUMBER",
      "DR_CR_ID",
      "LEDGER_SIGN",
      "QUANTITY",
      "AMOUNT",
      "MONTH_NUMBER",
      "MONTH_PERIOD",
      "GL_JOURNAL_CATEGORY",
      "AMOUNT_TYPE",
      "ALLOCATION_ID",
      "TARGET_CREDIT",
      "CROSS_CHARGE_COMPANY"
    )
  SELECT crdetail.nextval,
    "COMPANY",
    "GL_ACCOUNT",
    "COST_CENTER",
    '5253000',
    "PROFIT_CENTER" ,
    "MASTER_ORDER",
    "ORDER_NUMBER",
    "FUNDING_PROJECT",
    ' ',
    "POSTING_COST_CENTER",
    "ORIG_COST_ELEMENT",
    "ORIG_COST_CENTER",
    "ORIG_PROFIT_CENTER",
    " TRADING_PARTNER",
    "WORK_ORDER_NUMBER",
    CASE
      WHEN amount > 0
      THEN 1
      ELSE -1
    END,
    1,0,
    ROUND(amount * 0.0574000000, 2),
    month_number,
    0,
    '593',
    1 ,
    7,
    'TARGET',
    ' '
  FROM
    (SELECT "COMPANY",
      "GL_ACCOUNT",
      "COST_CENTER",
      "PROFIT_CENTER",
      "MASTER_ORDER",
      "FUNDING_PROJECT",
      "POSTING_COST_CENTER",
      "ORDER_NUMBER",
      "ORIG_COST_ELEMENT",
      "ORIG_COST_CENTER",
      "ORIG_PROFIT_CENTER",
      "TRADING_PARTNER",
      "WORK_ORDER_NUMBER",
      month_n umber,
      0,
      SUM(amount) amount,
      SUM(quantity) quantity
    FROM CR_COST_REPOSITORY
    WHERE (amount_type    = 1 )
    AND (month_number     = 201404)
    AND ( "MASTER_ORDER" IN MASTER_ORDER
    AND EXISTS
      (SELECT 1
      FROM
        (SELECT SUBSTR(ELEMENT_VALUE, 1, DECODE(INSTR(ELEMENT_VALUE, ':'), 0, L ENGTH(ELEMENT_VALUE) + 1, INSTR(ELEMENT_VALUE, ':')) - 1) AS ELEMENT
        FROM CR_STRUCTURE_VALUES2
        WHERE STRUCTURE_ID       = 2
        AND DETAIL_BUDGET        = 1
        AND STATUS               = 1
        AND UPPER(PARENT_VALUE) IN ('ELECTRIC ALL OTHER','ELECTRIC COR')
        MINUS
        SELECT SUBSTR(ELEMENT_VALUE, 1, DECODE(INSTR(ELEMENT_VALUE, ':'), 0, LENGTH(ELEMENT_VALUE) + 1, INSTR(ELEMENT_VALUE, ':')) - 1) AS ELEME NT
        FROM CR_STRUCTURE_VALUES2
        WHERE STRUCTURE_ID      = 9
        AND DETAIL_BUDGET       = 1
        AND STATUS              = 1
        AND UPPER(PARENT_VALUE) = 'A&G OH ORDER EXCLUSION'
        ) Z
      WHERE Z.ELEMENT = MASTER_ORDER
      )
    AND "GL_ACCOUNT"   <> '91081001'
    AND "COST_ELEMENT" IN COST_ELEMENT
    AND EXISTS
      (SELECT 1
      FROM CR_ST RUCTURE_VALUES2 A
      WHERE A.STRUCTURE_ID = 5
      AND A.DETAIL_BUDGET  =1
      AND A.STATUS         = 1
      AND COST_ELEMENT     = A.ELEMENT_VALUE
      )
    AND "GL_ACCOUNT" NOT IN ('5100000','5325000','5327000')
    AND "SOURCE_ID"      <> '7' )
    GROUP BY "COMPANY",
      "GL_ACCOUNT",
      "COST_CENTER",
      "PROFIT_CENTER",
      "MASTER_ORDER",
      "FUNDING_PROJECT",
      "POSTING_COST_CENTER",
      "ORDER_NUMBER",
      "ORIG_COST_ELEMENT",
      "ORIG_COST_CENTER",
      "ORIG_PROFIT_CENTER",
      "TRADING_PARTNER",
      "WORK_ORDER_NUMBER",
      month_number
    )
  
  

  Enjoy your first answer on this.

  Thank you and best regards,

  Murali

  Option 1:

  You run with two different ORACLE_HOMEs - that is potentially two different copies of the Oracle executable to the patch different sets?

  Option 2:

  A change of size of SGA is unlikely to directly affect the execution plan, but it also has change the size of the PGA TOUR at the same time? A change in the pga_aggregate_target could affect the choice of the mechanism of the join optimizer. (But not to change an in a join; but hash semi-join to nested loop is possible).

  Possibility 3:

  The db_file_multiblock_read_count leaves then the size that oracle defines by default depends on the db_cache_size divided by process; so, if you have reduced the sga_target_size you (implicitly or explicitly, no doubt) reduced the db_cache_size, and if you don't reduce the process in the same way, then the default db_file_multiblock_read_count been reduced. What you did on your system stats, this could change the cost of (for example) full tablescans, which could lead to a change in execution plan.

  It would be useful to see the results of a call to explain the plan / dbms_xplan.display in both cases so that we can see the variation in estimates of Oracle.

  Concerning

  Jonathan Lewis

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  Is it OK... ? Or am I wrong anywhere... ?
  
  Can some one please clarify...
  
  Thank you very much
  AFA

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  I thought that all instances of AM are having the same class type. The values of static variables would be the same for them.

  We lose how these values while the passivation. ? >
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