ORA-01438: value larger than the precision specified for the column '

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• ORA-01438: value larger than the precision specified for this column?

  Hi guys:
  
  I'm stuck in this error when I try to do an insert into a table. My Source has 581K records, but only this code and the values described below gives me a headache.
  
  Here's the DDL for the source and the target.
  
  CREATE TABLE WRK. VL_FREED
  ('CODE' VARCHAR2 (9))
  NUMBER (15.7) "VL_FREED".
  )
  
  CREATE TABLE WRK. VL_RENEG
  ('CODE' VARCHAR2 (9))
  NUMBER (15.7) "VL_RENEG".
  )
  
  CREATE TABLE WRK. WRK_XPTO
  ('CODE' VARCHAR2 (9))
  NUMBER (15,10) "VL_XPTO".
  )
  
  ------------------------------------------------
  The values for the VL_FREED AND VL_RENEG tables:
  
  
  CODE = 458330728 (same on both)
  VL_FREED = 191245.3000000
  VL_RENEG = 74095.3800000
  
  -------------------------------------------------
  
  When I try to run this insert:
  
  INSERT INTO WRK. WRK_XPTO
  (
  CODE,
  VL_XPTO
  )
  Select
  T1. CODE,
  T1. VL_FREED - T2. VL_RENEG
  of WRK. VL_FREED T1, WRK. VL_RENEG T2
  WHERE
  (T1. CD_CODE = T2. CODE);
  
  I got the error:
  ORA-01438: value larger than the precision specified for the column
  
  But how can this be? The result of 191245.3000000 - 74095.3800000 is not greater than a number (15,10).
  
  Can someone help me on this?

  Number (15,10) means 15 total digits, 10 of which are to the right of the decimal separator, leaving only 5 on the left.

  190 000 - 75 000 = 115 000 (6 digits).

• ODI 12 C | Error ORA-01438: value larger than the precision specified for the column

  I keep getting this error when trying to load an XML file exchange rates in a table of data warehouse. I defined the type of XML data model to NUMBER (18,15), identical to the target and it works for rates with an accuracy of 1, then when the transformed with an accuracy of 4 it generates this error. This was really frustrating... There must be somewhere a temporary table created with precision different, right? Any help with this would be appreciated.

  The example data:

  Result of currency rates

  1.4454325324 COL AUD

  1.3943435826 CAD PASS

  8.9824929424 COL CNY

  4326.4323456123 COP FAIL

  You seem to be confused with the terminology you use here. The precision is the total number of digits allowed in your number in your definition, i.e. NUMBER (18,15), precision 18, which means that you can have up to 18 digits in your number. However, you have also defined a scale value of 15 that denotes the amount of numbers that are sitting to the right of the decimal point. This means that you have only allowed for the 3 digits to sit to the left of the decimal point that is precision - scale (18-15). That's why you get the error when you try and load the COP currency that your definition of data type does not support having more than 3 digits left of the decimal separator.

• While import is ORA-01438: value larger than specified precision error

  Hello
  
  I get these errors on a few tables when performing an import of tables selected in a diagram. Here's one of them:
  ++++++++++++++++++++++++++++++++++++++++++++++++++++
  . . importing table "CHARGE_DISTRIBUTE".
  IMP-00058: ORACLE error 1438
  ORA-01438: value larger than the precision specified for the column
  IMP-00028: partial import of the restored previous table: 17055 restored lines
  . . import of partition 'CM1_AGREEMENT_PARAM': 'AMAXVALUE' 327559 imported lines
  ++++++++++++++++++++++++++++++++++++++++++++++++++++
  
  How to find out on which column the problem occurs?
  
  Oracle version: 10.2.0.3.0
  OS: SunOs
  
  See you soon,.
  Malika

  Hello

  As you can see from the following link error ORA-01438 is generally linked to a numeric column:

  http://www.error-code.org.UK/view.asp?e=Oracle-ora-01438

  So you might get a description of the Table:

  desc CHARGE_DISTRIBUTE;
  

  The offending column is probably one with a NUMBER data type.

  Next to the notice already posted, you can compare the data type of the columns in the Source and the target Table.

  Hope this helps.
  Best regards
  Jean Valentine

• Catch the live ORA-01438 / value larger than specified precision allowed for

  I have an another question! Is it possible to intercept the error ORA-01438 immediately before that the user sends data?
  I have a db column that is used to store numbers of length 3.0. When you enter the 4 digits, the ORA-01438 is triggered.
  The Apexlib does not work, since I have some conditional regions on the page in question.
  
  Thanks for posting your thoughts and advice.
  
  Kind regards
  
  SEB

  SEB,

  Simply create a validation and check the length of user input.

  brgds,
  Peter

  -----
  Blog: http://www.oracle-and-apex.com
  ApexLib: http://apexlib.oracleapex.info
  Work: http://www.click-click.at
  Training: http://www.click-click.at/apex-4-0-workshops

• ORA-01438: how to find the name of the column?

  Hello
  
  I'm trying to find the column which is causing ORA-01438 when inserting into a table.
  
  The insertion is made by a C program that reads from a socket and written in an oracle 10 g database using Oracle Pro * C.
  
  I tried to identify the column by printing the values (about 250) just before the insert statement is executed, but check these values has been a task heavy and error prone and did not help to correct the mistake (I found a bunch of values which out of reach, but changing these values has not resolved the issue).
  
  Abandon this idea, I tried to track the session to help
  (1) DBMS_SYSTEM. SET_SQL_TRACE_IN_SESSION,
  (2) DBMS_MONITOR.session_trace_enable/disable and still
  (3) change the context name system set events 10046 trace forever, level 12' and;
  (4) alter system set sql_trace = true scope = mΘmoire;
  
  DBMS_MONITOR.session_trace_enable only gave me a few tips (the insert statement) in a trace file. But it worked for a simple example of a test database.
  
  When I try to turn on tracing on the database, where the error occurs, then I'm still not able to set SQL_TRACE in V$ SESSION true, even if no error is returned by the statement "DBMS_MONITOR.session_trace_enable". The value of SQL_TRACE in V$ SESSION does not change and I have no idea why. On the test database, it works fine and I can find the trace file in the user_dump_destination directory.
  
  Anyone have any suggestions on how to fix this?
  
  Any help is appreciated.
  Thanks in advance!

  Just check this:

  SQL > conn osama/osama ;
  SQL> create table test as select * from scott.dept ;
  
  SQL> select * from test ;
  
      DEPTNO DNAME          LOC
  ---------- -------------- -------------
          10 ACCOUNTING     NEW YORK
          20 RESEARCH       DALLAS
          30 SALES          CHICAGO
          40 OPERATIONS     BOSTON
  
  SQL> alter system set events='1438 trace name Errorstack forever,level 10';
  
  SQL> insert into test values (100000000000000000,'osama','JOR');
  insert into test values (100000000000000000,'osama','JOR')
                           *
  ERROR at line 1:
  ORA-01438: value larger than specified precision allowed for this column
  
  In Trace File :
  
  ORA-01438: value larger than specified precision allowed for this column
  Current SQL statement for this session:
  insert into test values (100000000000000000,'osama','JOR')
  

• Error: The file size for all drives of paging can be a little larger than the size you specified, when you open windows in Windows 7

  Original title: paging notice when open windows on mac, divide the hard disk

  I have a split hardrive on a MAC and windows, and quickbooks installed on this drive.  When I open windows, I get a notice of paging file.  -size of the paging file.  "The file size for all drives of paging can be a little larger than the specified size.  IM using Bootcamp for the windows side.  It is to show the memory almost full and I did not yet get many date in QB.  Don't know what I have to do.

  Hello

  1. have you done any software or changes to the material on the computer before this problem?

  2. it worked correctly previously?

  3. how many hard drives are in the computer?

  4. is the problem with a partition or a particular hard drive?

  Try the steps from the link.

  Change the size of virtual memory

  http://Windows.Microsoft.com/en-us/Windows7/change-the-size-of-virtual-memory

  What is virtual memory?
  http://Windows.Microsoft.com/en-us/Windows7/what-is-virtual-memory

  Hope this information is useful.

• The size of the estimated value of the project is larger than the chosen target support

  I am at a loss for trying to create a project using Adobe Encore.  I tried initially to the author of the project using the CS2 version.  When you try to export, I received the following message is displayed:

  "The size of the estimated value of the project is larger than the chosen target support.  While it is an estimate, the project may not build. »

  I have created hundreds of projects in the past, but have never received this message before.  I first thought that the problem was with the release of still I used, but I got the exact error that even trying to create the project with Encore CS5.

  The project itself has a menu, a motion menu, and a single video file.  The video file 152 last minute, and I was trying to export that to a double layer DVD.  I tried from the file using CS5.5 Adobe Premier export using a variety of parameters.  I'm trying to export it to a file DVD-2, with the attributes of soure game being the highest value.  The parameter on the main concept MPEG encoder is set to 5. I tried to export the file by using the constant and variable bitrates.

  When I recently exported the file using a contant 6.5 sampling rate, I still 650,4 Mo still remaining on my project.  I still received the same error message on the size of the project, and so I think that something is wrong.

  I even exported the video file into an AVI file compressed and then tried to coding again using CS5.5 Adobe Premier and Adobe encoder.  I always get the same error message on the size of the file.

  Any help or suggestions on how to solve this problem would be greatly appreciated.  Thank you!

  If you do not finish with wasted discs...

  Create an ISO (yet), or a folder on your hard drive (still or Premiere Elements), then use the FREE http://www.imgburn.com/index.php?act=download to write files or folders or ISO on DVD or BluRay drive (send the author a PayPal donation if you like his program)

  .

  ImgBurn will read the mark of REAL from the disk drive, which isn't always the same as the label for the box (Memorex is known for 'nothing' buy and put inside a box of Memorex)

  .

  When you write on the disk with Imgburn, use speed SLOWEST possible setting, so your burner has the best chance to create "good, well trained" laser drill holes... Since no DVD drive is required to read a burned disc, have a 'good' after a try to white high quality will help

  .

  Use Taiyo Yuden simple layer or layer two Verbatim

  Or Falcon Pro for inkjet printable two layer

• Remove values lower than the desired increment

  Hello

  When you perform a simulation of multi-body with a step size fix that I receive some additional values smaller than the normal increment in output data or values are duplicated. The time channel looks like:

  0

  0.0002738

  0.001

  0.002

  0.002

  0.003

  0.004

  ....

  I think that with a simple script I can remove the extra valuues (in this case 0.0002738, 0.002).

  E offer this code, but it does not work:

  Hello Fischerg,

  I would like to know how it works:

  Option Explicit
  Dim timechannel, CLength CNumber, dBase, limit, K, CurrValue, Epsilon, Delta

  timechannel = "[1] / TIME."
  CLength = Val (ChnPropGet (timechannel, 'length'))
  CNumber = NOC (timechannel)

  Epsilon = 0.00001
  Limit = 0.001 - Epsilon

  dBase = CHDx(1,CNumber)
  For K = 2-CLength
  CurrValue = CHDx (K, CNumber)
  Delta = CurrValue-dBase
  "Compare using the value of the Epsilon. Compare float numbers
  "with '=' does not always work
  If (Delta< limit="" )="" then="">
  CHDx (K, CNumber) = NULL
  On the other
  "Set new base
  CurrValue = dBase
  End If
  Next
  Call ChnCharacter (timechannel)
  'Delete tagged values. If there are more channels in parallel to the string "TIME."
  "those who can be adjusted with the same call. See the online help for ChnNovHandle for more details
  Call ChnNovHandle(timechannel,"","Delete","X",1,1,0)

• Now, the screen moves as the surface is larger than the actual size of the screen. I checked its display options, but how do I disable this screen oversized?

  Hello

  My mother was a member of the family to try to help inrease size but Bobo and now its screen in any program or simply from bottom of screen size is larger than the size of the screen.  She can move the mouse to the left to bring the extreme left veiw and then the same thing right but never have all the screen in veiw now.  How to restore to normal for her.  I tried control - display, but not... help her please help me

  Hi M Carmel,

  Thanks for posting in the Microsoft community.

  I understand that you are facing the issue with the resolution of the screen display.

  I suggest you to see the links and check.

  Change the resolution of your monitor

  http://Windows.Microsoft.com/en-us/Windows-XP/help/Setup/change-monitor-resolution

  Change your screen resolution

  http://Windows.Microsoft.com/en-us/Windows-XP/help/change-screen-resolution

  Please follow these recommended steps, review the additional information provided and after back if you still experience the issue. I will be happy to provide you with additional options available that you can use to get this resolved.

• Make the wallpaper slightly larger than the screen

  Hello

  I work with the simulator of the storm. I know that the screen size is fixed (obviously; "I think it's 320 x 480), but I want to make a slightly larger background image and allow scrolling horizontally and vertically.

  In other words, I want to be able to make a pan larger than the image of the screen; An image that has limits.

  I say, "which has limits," because I tried this, but the image is tiled, instead of being a single. A TI seems constantly to the left and down. Any help please.

  USE_ALL_HEIGHT and USE_ALL_WIDTH are a problem, as I predicted. Since you give your MyScreen VERTICAL_SCROLL and HORIZONTAL_SCROLL, it gives her children a height and a width of Integer.MAX_VALUE > 1. USE_ALL_HEIGHT and USE_ALL_WIDTH do all that great width and height.

  In order to make the screen exactly the size you want to substitute sublayout and take a look at net.rim.device.api.ui.Manager setVirtualExtent and setExtent methods. Some of the best examples of the override of this method are found in the code of

  Implement advanced buttons, fields and managers

  This code can be considered a bible of the BlackBerry user interface programming (Finally, at least for non touchscreen devices).

• Videos larger than the window display.

  I recently started having a problem with my g6 Pavilion by watching videos.  I noticed first on YouTube, but also can't play .mp4 files in Media Player.  I see that a small part of the video, it is larger than the window full screen, or display in this mode.

  After making sure the flash drive was up to date and quicktime (was grabbing at straws) I found that AMD video Steady was the issue.  Disabled and viola, playing the videos properly.

  Thanks for the suggestions anyway.

• Updated data are larger than the buffer cache

  Hi Experts,

  I have a small request. I have a table called CONTENT to have 12 GB of data. Here, I pulled a single update statement that updates to 8 GB of CONTENTS table of data using 1 GB of database buffer cache?

  How 1 GB of the Database Buffer Cache will be used to update the 8 GB of data? Level architectural any additional changes will happen (than usual) when executing "Updated data is larger than the buffer cache"?

  Could someone of you please response. Thank you

  Database: 10.2.0.5

  OS: Power 5-64 bit AIX system

  Hello

  the basic mechanism is the following:

  needed to update data blocks are read from the data files and cached in memory (buffer cache), the update is made to the buffer cache and the front of the (UNDO) image is stored in the segments of cancellation, operation (update here) is re-encoded to redo buffer until it goes again files If the buffer is samll or we need more space in the buffer cache, or we have a control point or... Oracle writes back the block modified data files to free the memory buffer for the more blocks.

  While the other runs the update of transactions can read before you change the image of CANCEL if validation, at the end of the transaction done change is confirmed and validation is recorded in the redo. If the cancellation is made at the end of the transaction before the image is "restored" and rollback is saved in do it again.

  Concerning

• First paragraph of the text is larger than the following paragraphs

  I have a page with a lot of text on the subject. For some reason, the first paragraph seems larger than the following paragraphs. But all that I checked shows that they are identical in terms of specs. I copied/pasted/no formatted/spruced up... but no matter what I do, that first paragraph is looking to be bigger! Is this some secret parameter that I don't know?

  I took screenshots and they are indeed the same size. But that first paragraph seems just different! Why would it be?

  I have attached a screenshot. Let me know if my client and I are just seeing things.

  Julie

  

  Seems to be the same size.

  See the image below, the first line of paragraph 2, overlapping the first paragraph. (o during even as o in the company)

  Can be an illusion of perspective due to all caps in the first paragraph.

  

• &lt; Unspecified file name &gt; file is larger than the maximum size supported by datastore '&lt; indeterminate datastore &gt;.

  I know that this issue has much spoken in the forums, but the answers are always to make sure that your block sizes are set to 8 MB - mine are already. Let me explain:

  I have a virtual machine with a large amount of connected storage - something along the lines of discs 10 x 1.99 to. Sit all VMDK on partitions of the VMFS of 8 MB of size block, including the configuration of the VM (location of the pagefile).

  Every time I try and snapshot of the virtual machine, I see the "< unspecified file name > file is larger than the maximum size supported by the data store ' < unspecified datastore >. All other virtual machines instant fine, but any other VM has a similar amount of storage as the VM problem.

  I have now moved the configuration files of the virtual machine to a new partition VMFS 5 of 1.91 TB, but the instant error persists. Most of the readers is sitting on VMFS 3.33 or 3.46. It will take me a while to move all VMFS 5 to see if that solves the problem.

  VMware.log for VM reports:

  2011-10-09T09:55:55.328Z| vcpu-0|  DiskLibCreateCustom: Unsupported disk capacity or disk capacity (2186928627712 bytes) is too large for vmfs file size.
  2011-10-09T09:55:55.328Z| vcpu-0| DISKLIB-LIB   : Failed to create link: The destination file system does not support large files (12)
  2011-10-09T09:55:55.328Z| vcpu-0| SNAPSHOT: SnapshotBranchDisk: Failed to branch disk: '/vmfs/volumes/4dc30ba3-b13c5026-92d8-d485643a1de4/spoon-app/spoon-app_2.vmdk' -> '/vmfs/volumes/4dc30ba3-b13c5026-92d8-d485643a1de4/spoon-app/spoon-app_2-000001.vmdk' : The destination file system does not support large files (12)
  
  

  My VMDK and volumes are smaller than 2032GB. I don't understand why, it's be a problem.

  Anyone have any ideas?

  Although ESXi 5 supports larger LUN as a raw physical devices (up to 64 TB), the maximum size of a virtual disk has not yet changed.

  André