Oracle function to retrieve the records randomly

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• Do we not have an oracle function to select the non-null columns at the beginning

  Hello
  
  I have 8 columns. Some of them may be null.
  
  I want to display all 8 columns in my result. Columns not null will be first and no one at the end.
  
  Here is an example of data:
  
  Employee table:

   Employee_id   Emp_fname  emp_lname  emp_mname  dept salary emp_height  emp_weight
     1               aaa        ddd                d1   100      6           180
     2               bbb                ccc             120                 169
     3               dfe                           d2            5.9         223

  The expected result is:

  result1 result2   result3 result4  result5  result6 result7 result8
  1        aaa        ddd     d1       100     6        180
  2        bbb        ccc     120      169
  3        dfe        d2      5.9      223

  Thank you.
  
  Published by: BluShadow on July 12, 2012 16:12
  addition of {noformat}

  {noformat} tags for readability.  Please read {message:id=9360002} and do this yourself in future.                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                        

  945559 wrote:
  I'm using Oracle Database 11 g Release 11.2.0.3.0.

  Here is my sample data.

  CREATE TABLE saleshist (product VARCHAR2 (30), q1 NUMBER NUMBER of q2, q3 NUMBER, NUMBER of T4);
  INSERT INTO saleshist VALUES ('EE Oracle', 100, 123, null, 128);
  INSERT INTO saleshist VALUES (null, 'Partitioning', 100, 130, 128);

  desired output:
  col1, col2, col3 col4
  'Oracle EE', 100, 123, 128, null
  "Partitioning", 100,130,128, null

  It seems that you have 4 column headers, but 5 columns.

  Assuming that the character ' ~' never occurs in one of the columns:

  WITH   got_list           AS
  (
       SELECT     '~' || product
            || '~' || TO_CHAR (q1)
            || '~' || TO_CHAR (q2)
            || '~' || TO_CHAR (q3)
            || '~' || TO_CHAR (q4)     AS list
       FROM    saleshist
  )
  SELECT  REGEXP_SUBSTR (list,  '[^~]+', 1, 1)     AS col1
  ,       REGEXP_SUBSTR (list,  '[^~]+', 1, 2)     AS col2
  ,       REGEXP_SUBSTR (list,  '[^~]+', 1, 3)     AS col3
  ,       REGEXP_SUBSTR (list,  '[^~]+', 1, 4)     AS col4
  ,       REGEXP_SUBSTR (list,  '[^~]+', 1, 5)     AS col5
  FROM    got_list
  ;
  

  Output:

  COL1            COL2       COL3       COL4       COL5
  --------------- ---------- ---------- ---------- ----------
  Oracle EE       100        123        128
  Partitioning    100        130        128
  

  If you need a multiple character string, such as '? ~', to delimit the columns, then the same basic approach works, but the regular expression is messier.

  Product is just another column in this solution. Can be NULL, and it doesn't have to be unique.

• Function to retrieve the first day of the month.

  Select (sysdate, 'IW') of double
  
  I know it takes the date of Monday. Is there a function like above that has the date of return to the first Monday of the month?
  
  Thanks in advance.

  Hello

  NEXT_DAY is very convenient, but it is dependent on the NLS_DATE_LANGUAGE, and you cannot pass an argument to override that.
  TRUNC (dt, 'IW') is not in the NLS settings, then you may prefer this:

  TRUNC ( 6 + TRUNC (SYSDATE, 'MONTH')
        , 'IW'
        )          AS first_monday
  

  1st Monday of the month is fixed to the Monday or before the 7th of the month.

• Is it possible to retrieve the record date of maximum in one step?

  Look for not having to create two steps for these data (for example, create a table with the values I want and then in the second stage, link to these maximum values)
  
  So, what I have is:
  
  SELECT
  a.mbr_id
  b.address_1
  b.address_start_date
  
  Of
  Member has,
  b address
  
  WHERE a.mbr_id = b.member_id
  
  GROUP BY
  a.mbr_id
  b.address_1
  
  
  There may be a mbr_id attached to many address_1 in the address (but only a record of mbr_id by Member to Member). So, I want to, on one line, address_1, which is attached to the maximum address_start_date.
  
  Is it possible to do in 1 (one) step? Or what I need to create a table with the values maximum address_start_date first, then link to this table in a second time to get the max address_1 values?
  
  NOTE: in the SQL above, I added address_start_date just to show that this field exists in the address, I know that I must remove this, if there is another way to get what I want.
  
  Thanks for any help...

  Hello!

  Try the following SQL code:

  SELECT
  a.mbr_id
  substr (MAX (to_char (b.address_start_date, ' ' YYYY/MM/DD HH24:MI:SS) | b.address_1), 20)-if 20 is not OK try 19 or 21

  Of
  Member has,
  b address

  WHERE a.mbr_id = b.member_id

  GROUP BY
  a.mbr_id

  Explanations:
  1. "to_char (b.address_start_date, ' ' YYYY/MM/DD HH24:MI:SS) | b.address_1' allows you to link an address on the date indicated on the same line and the date is in a format that is well ordered as VARCHAR2.
  2 MAX (...) will build on the first 19 characters (the length of the day)
  3 SUBSTR (...) allows you to eliminate the date (which was used only for the order) and have the address only.

  Please please tell me if this solves your problem.

  Published by: user1810145 on October 27, 2010 08:07

• displaying the records randomly after 24 hours

  Hello

  SQL> desc videos
   Name                                      Null?    Type
   ----------------------------------------- -------- ----------------------------
   V_ID                                      NOT NULL NUMBER(14)
   VIDEODATE                                          TIMESTAMP(0)
   CATEGORY                                           NUMBER(5)
   VIDEOIMAGE                                         VARCHAR2(110)
   VIDEO                                              VARCHAR2(110)
   TITLE                                              VARCHAR2(110)
   ACTIVE                                             NUMBER(2)

  Can I show random files after 24 hours?
  
  Best regards

  Try this

  select * from videos
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• How to retrieve the values of character without using single quotes

  Hi all

  How to retrieve the values of character without the use of single quotes. Its Possible in Oracle SQL

  Please answer me...

  For example

  Is actual query-> Select * from employees where name like in("SCOTT", "JAMES", "ALBERT",...);

  I want to--> Select * from employees where name like(SCOTT, JAMES, ALBERT...); -without the use of single quotes.

  Why I need this application, I need to retrieve the records more than 200 employees in a select statement by using name in where clause.

  shagarmahabubjan wrote:

  Hi all

  How to retrieve the values of character without the use of single quotes. Its Possible in Oracle SQL

  Please answer me...

  For example

  Actual query is---> Select * from employees where name like in("SCOTT", "JAMES", "ALBERT",...);

  I want to---> Select * from employees where name like(SCOTT, JAMES, ALBERT...); -without the use of single quotes.

  Why I need this application, I need to retrieve the records more than 200 employees in a select statement by using name in where clause.

  In short... you can't.  The channels are channels, and SQL and PL languages dictate that the string literals are provided within single quotes.

  I don't see how trying to retrieve more than 200 records of employees in the select statement means that you must get rid of the quotes.

  Be clear in what you ask: Re: 2. How can I ask a question on the forums?

  and take note of the FAQ link davidp provided the solution "variable IN the list.