Oracle LISTAGG function

Similar Questions

• Listagg function excdding 4000 characters

  Hi all
  

  Oracle Database 11g Enterprise Edition Release 11.2.0.3.0 - 64bit Production
  PL/SQL Release 11.2.0.3.0 - Production
  CORE     11.2.0.3.0     Production
  TNS for Linux: Version 11.2.0.3.0 - Production
  NLSRTL Version 11.2.0.3.0 - Production
  
  I'm using listagg function to concatenate the column values. I have nearly 4000 records in the table. I guess listagg function can concatenate till 4000 characters and if it exceeds 4000 then I'm getting an Ora error which says 'results of string concatenation is too long'. 
  
  case 1:
  select listagg(id, ',') within group (order by id) from (select level as id from dual connect by level < 1000);
  No Issue.
  
  Case 2:
  select listagg(id, ',') within group (order by id) from (select level as id from dual connect by level < 1050);
  Ora-01489
  
  How to handle the issue? 

  Thank you
  Rod.

  SQL> set long 10000
  SQL> select listagg(id, ',') within group (order by id)
    2    from (select level as id from dual connect by level < 1050)
    3  /
    from (select level as id from dual connect by level < 1050)
                                  *
  ERROR at line 2:
  ORA-01489: result of string concatenation is too long
  
  SQL> select rtrim(xmlagg(xmlelement(e,id,',').extract('//text()') order by id).GetClobVal(),',')
    2    from (select level as id from dual connect by level < 1050)
    3  /
  
  RTRIM(XMLAGG(XMLELEMENT(E,ID,',').EXTRACT('//TEXT()')ORDERBYID).GETCLOBVAL(),','
  --------------------------------------------------------------------------------
  1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30
  ,31,32,33,34,35,36,37,38,39,40,41,42,43,44,45,46,47,48,49,50,51,52,53,54,55,56,5
  7,58,59,60,61,62,63,64,65,66,67,68,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,
  84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99,100,101,102,103,104,105,106,107,
  108,109,110,111,112,113,114,115,116,117,118,119,120,121,122,123,124,125,126,127,
  128,129,130,131,132,133,134,135,136,137,138,139,140,141,142,143,144,145,146,147,
  148,149,150,151,152,153,154,155,156,157,158,159,160,161,162,163,164,165,166,167,
  168,169,170,171,172,173,174,175,176,177,178,179,180,181,182,183,184,185,186,187,
  188,189,190,191,192,193,194,195,196,197,198,199,200,201,202,203,204,205,206,207,
  208,209,210,211,212,213,214,215,216,217,218,219,220,221,222,223,224,225,226,227,
  228,229,230,231,232,233,234,235,236,237,238,239,240,241,242,243,244,245,246,247,
  
  RTRIM(XMLAGG(XMLELEMENT(E,ID,',').EXTRACT('//TEXT()')ORDERBYID).GETCLOBVAL(),','
  --------------------------------------------------------------------------------
  248,249,250,251,252,253,254,255,256,257,258,259,260,261,262,263,264,265,266,267,
  268,269,270,271,272,273,274,275,276,277,278,279,280,281,282,283,284,285,286,287,
  288,289,290,291,292,293,294,295,296,297,298,299,300,301,302,303,304,305,306,307,
  308,309,310,311,312,313,314,315,316,317,318,319,320,321,322,323,324,325,326,327,
  328,329,330,331,332,333,334,335,336,337,338,339,340,341,342,343,344,345,346,347,
  348,349,350,351,352,353,354,355,356,357,358,359,360,361,362,363,364,365,366,367,
  368,369,370,371,372,373,374,375,376,377,378,379,380,381,382,383,384,385,386,387,
  388,389,390,391,392,393,394,395,396,397,398,399,400,401,402,403,404,405,406,407,
  408,409,410,411,412,413,414,415,416,417,418,419,420,421,422,423,424,425,426,427,
  428,429,430,431,432,433,434,435,436,437,438,439,440,441,442,443,444,445,446,447,
  448,449,450,451,452,453,454,455,456,457,458,459,460,461,462,463,464,465,466,467,
  
  RTRIM(XMLAGG(XMLELEMENT(E,ID,',').EXTRACT('//TEXT()')ORDERBYID).GETCLOBVAL(),','
  --------------------------------------------------------------------------------
  468,469,470,471,472,473,474,475,476,477,478,479,480,481,482,483,484,485,486,487,
  488,489,490,491,492,493,494,495,496,497,498,499,500,501,502,503,504,505,506,507,
  508,509,510,511,512,513,514,515,516,517,518,519,520,521,522,523,524,525,526,527,
  528,529,530,531,532,533,534,535,536,537,538,539,540,541,542,543,544,545,546,547,
  548,549,550,551,552,553,554,555,556,557,558,559,560,561,562,563,564,565,566,567,
  568,569,570,571,572,573,574,575,576,577,578,579,580,581,582,583,584,585,586,587,
  588,589,590,591,592,593,594,595,596,597,598,599,600,601,602,603,604,605,606,607,
  608,609,610,611,612,613,614,615,616,617,618,619,620,621,622,623,624,625,626,627,
  628,629,630,631,632,633,634,635,636,637,638,639,640,641,642,643,644,645,646,647,
  648,649,650,651,652,653,654,655,656,657,658,659,660,661,662,663,664,665,666,667,
  668,669,670,671,672,673,674,675,676,677,678,679,680,681,682,683,684,685,686,687,
  
  RTRIM(XMLAGG(XMLELEMENT(E,ID,',').EXTRACT('//TEXT()')ORDERBYID).GETCLOBVAL(),','
  --------------------------------------------------------------------------------
  688,689,690,691,692,693,694,695,696,697,698,699,700,701,702,703,704,705,706,707,
  708,709,710,711,712,713,714,715,716,717,718,719,720,721,722,723,724,725,726,727,
  728,729,730,731,732,733,734,735,736,737,738,739,740,741,742,743,744,745,746,747,
  748,749,750,751,752,753,754,755,756,757,758,759,760,761,762,763,764,765,766,767,
  768,769,770,771,772,773,774,775,776,777,778,779,780,781,782,783,784,785,786,787,
  788,789,790,791,792,793,794,795,796,797,798,799,800,801,802,803,804,805,806,807,
  808,809,810,811,812,813,814,815,816,817,818,819,820,821,822,823,824,825,826,827,
  828,829,830,831,832,833,834,835,836,837,838,839,840,841,842,843,844,845,846,847,
  848,849,850,851,852,853,854,855,856,857,858,859,860,861,862,863,864,865,866,867,
  868,869,870,871,872,873,874,875,876,877,878,879,880,881,882,883,884,885,886,887,
  888,889,890,891,892,893,894,895,896,897,898,899,900,901,902,903,904,905,906,907,
  
  RTRIM(XMLAGG(XMLELEMENT(E,ID,',').EXTRACT('//TEXT()')ORDERBYID).GETCLOBVAL(),','
  --------------------------------------------------------------------------------
  908,909,910,911,912,913,914,915,916,917,918,919,920,921,922,923,924,925,926,927,
  928,929,930,931,932,933,934,935,936,937,938,939,940,941,942,943,944,945,946,947,
  948,949,950,951,952,953,954,955,956,957,958,959,960,961,962,963,964,965,966,967,
  968,969,970,971,972,973,974,975,976,977,978,979,980,981,982,983,984,985,986,987,
  988,989,990,991,992,993,994,995,996,997,998,999,1000,1001,1002,1003,1004,1005,10
  06,1007,1008,1009,1010,1011,1012,1013,1014,1015,1016,1017,1018,1019,1020,1021,10
  22,1023,1024,1025,1026,1027,1028,1029,1030,1031,1032,1033,1034,1035,1036,1037,10
  38,1039,1040,1041,1042,1043,1044,1045,1046,1047,1048,1049
  
  SQL>
  

  SY.

• LISTAGG function: "result of concatenating string is too long."

  Hello
  
  I use Oracle SQL developer 3.0.04 version. I tried using the LISTAGG function to group the data.
  

  CREATE TABLE FINAL_LOG AS
  SELECT SESSION_DT, C_IP, CS_USER_AGENT,
  listagg(WEB_LINK, ' ')
       WITHIN GROUP(ORDER BY C_IP, CS_USER_AGENT) "WEB_LINKS"
       FROM webviews
       GROUP BY C_IP, CS_USER_AGENT, SESSION_DT
       ORDER BY SESSION_DT

  However, I get the error message,
  
  SQL error: ORA-01489: result of concatenating string is too long
  
  Is it possible to go around it, or are there other alternatives?

  Tim Hall has a page on the various techniques of aggregation of chain that guides you through an example of creating and using a user-defined aggregate.

  On AskTom referenced by Tim page, there is an implementation of an aggregation function of string that returns a CLOB that you can use.

  If you want to understand what makes the user-defined aggregate function, it may look a bit complex, especially if you have never looked at object types in PL/SQL. You don't need to understand all the details of the implementation if you use just the code, however, you can simply create the function and use it as you would with any other aggregate function.

  Justin

• listagg function problem

  Hello

  I'm not able to get the data using the listagg function.

  DB: 11g

  CREATE TABLE HAS

  (NAME, VARCHAR2 (10))

  VAL VARCHAR2 (10));

  INSERT INTO A VALUES ('LTR', ' 111');

  INSERT INTO A VALUES ('LTR', ' 112');

  INSERT INTO A VALUES ('LTR', ' 113');

  COMMIT;

  SELECT * FROM A;

  SELECT * FROM WHERE A VAL IN (SELECT LISTAGG (A1. VAL, ",") THE GROUP (RANKING BY A1. (VAL) AN A1);

  
  

  Break down the problem.

  your subquery is:

  SELECT LISTAGG (A1. VAL, ",") THE GROUP (RANKING BY A1. VAL) AN A1;

  which returns the following STRING:

  LISTAGG (A1. VAL, ",") WITHINGROUP (ORDERBYA1. VAL)

  --------------------------------------------------------------------------------

  111,112,113

  Then use one to find... so basically, you do this:

  SELECT * FROM WHERE A VAL IN ('111,112,113');

  See the problem yet?

  Looking around 'dynamic IN the list... "

  I don't have the links, however, it is fairly easy to find in this search string

• Listagg function gives ORA-00979: not a GROUP BY expression error

  Hello

  I have an environment that supports the Listagg function. Suite works perfectly:

  Select task_code, LISTAGG(ename||) e ('| role |') (',',') WITHIN GROUP (ORDER BY ename) as employees

  team

  where task_code = '01.07.05'

  Task_code group

  However, this is just a test request, the real is a little wider and I can't get the function works, I get ORA-00979: not a GROUP BY expression error.

  Here's my query (the column names are in Dutch, but that shouldn't really be a problem):

  SELECT distinct op_sod.sod_code, op_sod.sod_omschr_lang, op_ood.ood_code, op_ood.ood_omschr_lang, op_activiteit.act_code, op_activiteit.act_omschr_lang, op_taak.taak_code, op_taak.taak_omschr_lang, op_afdeling___master.afd_code, op_taak.belmo, op_taak_j.planning_la,

  LISTAGG (op_ploeg.wn_naam |) ' ('| op_ploeg.rol |') (',',') WITHIN GROUP (ORDER BY op_ploeg.wn_naam) as employees.

  "Write subtaak/mijlpaal toe."

  op_teamplanning.subtaak_mijlpaal as subtaak_of_mijlpaal,

  op_teamplanning.subtaak_omschr | -case when op_teamplanning.subtaak_mijlpaal = 'BELMO Mijlpaal' then ' (BRUNO mijlpaalnr: ' | nvl (op_teamplanning.nummer, 0) |) ')' other ' ' end

  as subtaak_mijlpaal_omschrijving, op_teamplanning.deadline as date limit, op_teamplanning.status as status,

  trim (both

  case when op_teamplanning.vlag1 = 'Geen' and op_teamplanning.vlag2 = 'Geen' and op_teamplanning.vlag3 = 'Geen' and op_teamplanning.vlag4 = 'Geen'

  and op_teamplanning.vlag5 = 'Geen' or op_teamplanning.vlag1 is null and op_teamplanning.vlag2 is null and op_teamplanning.vlag3 is null

  op_teamplanning.vlag5 is null and op_teamplanning.vlag4 is null then 'Geen '.

  Another pad (both case when op_teamplanning.vlag1 = 'Geen' then "else trim (both from op_teamplanning.vlag1) end) |

  trim (both case when op_teamplanning.vlag2 = 'Geen' then "another ',' | trim (both from op_teamplanning.vlag2) end) |

  trim (both case when op_teamplanning.vlag3 = 'Geen' then "another ',' | trim (both from op_teamplanning.vlag3) end) |

  trim (both case when op_teamplanning.vlag4 = 'Geen' then "another ',' | trim (both from op_teamplanning.vlag4) end) |

  trim (both case when op_teamplanning.vlag5 = 'Geen' then "another ',' | trim (both from op_teamplanning.vlag5) end) end) as Beleidsvlaggen,

  op_teamplanning.naam_verantw as quotation, op_teamplanning.subtaak_id as subtaak_id, nvl (op_teamplanning.nummer, 0) as Nummer, nvl (op_teamplanning.regelgevingsagenda, 'Nee') as

  Regelgeving, op_teamplan_subsubtaak.subsubtaak_submijlpaal as subsubtaak_submijlpaal, op_teamplan_subsubtaak.subsubtaak_id as subsubtaak_id, op_teamplan_subsubtaak.subsubtaak_omschr

  like subsubtaak_omschr, op_teamplan_subsubtaak.deadline, sub_deadline, op_teamplan_subsubtaak.status as sub_status, op_teamplan_subsubtaak.naam_verantw as naam_verantw

  Of...

  WHERE THE...

  Group of op_sod.sod_code, op_sod.sod_omschr_lang, op_ood.ood_code, op_ood.ood_omschr_lang, op_activiteit.act_code, op_activiteit.act_omschr_lang, op_taak.taak_code, op_taak.taak_omschr_lang, op_afdeling___master.afd_code, op_taak.belmo, op_taak_j.planning_la

  
  

  Can someone tell me the reason for this error?

  Thanks in advance!

  Kind regards

  NDG

  NDG123 wrote:

  I don't really understand your other question:

  Is below for example, a group of expression?

  op_teamplanning.subtaak_mijlpaal

  After some additional research:

  The group by mistake is not appear anymore when I delete all fields after the listagg field, that might be a clue to the solution.

  It is not difficult to understand. You can have other columns not aggregated in your projection on the side of those listed in the group by expression.

  The reason for ORA-01489 is that the resulting string will become long and exceeds 4000 bytes.

  You will find several solution in this forum.

  For example

  Re: Listagg function excdding 4000 characters

• limit the number of values in the listagg function and create several games

  Hi all
  
  I have a requirement where I would like to group one of the fields in a field based on the number of records. Lets say if we have an employee with multiple CODEZONE. Please see the example below. I want concatenation of each 10 EMPNO records into one. If she has more than 10 records for a given EMPNO, it should show in the form of another record.
  For example:
  EMPNO CODEZONE
  A111 AL
  A111 AK
  A111 AZ
  A111 AR
  A111 CA
  A111 CO
  A111 CT
  TO A111
  A111 DC
  A111 FL
  A111 GA
  A111 HI
  B222 AL
  B222 AK
  B222 AZ
  B222 AI
  B222 KS
  B222 KY
  THE B222
  B222 ME
  B222 MD
  MY B222
  B222 MI
  B222 CA
  B222 CO
  B222 CT
  B222 OF
  
  Result set:
  EMPNO CODEZONE
  A111 AL | AK | AZ | AR | CA | CO | CT | OF | DC | FL
  A111 GA | HI
  B222 AL | AK | AZ | AI | KS |     KY | THE | ME | MD | MY
  B222 MI | CA | CO | CT | OF
  
  The above example can have any number of area CODE for a given EMPNO, the end result should show only a maximum of 10 codes for an EMPNO in each record. If she has more than 10 CODEZONE, it should show as another record. Please provide me with a generic statement to solve this problem. I was not able to control by setting the limit on records for an EMPNO gave to the LISTAGG function. Any ideas are much appreciated.
  
  Thank you

  1008754 wrote:
  Hi all

  I have a requirement where I would like to group one of the fields in a field based on the number of records. Lets say if we have an employee with multiple CODEZONE. Please see the example below. I want concatenation of each 10 EMPNO records into one. If she has more than 10 records for a given EMPNO, it should show in the form of another record.
  For example:
  EMPNO CODEZONE
  A111 AL
  A111 AK
  A111 AZ
  A111 AR
  A111 CA
  A111 CO
  A111 CT
  TO A111
  A111 DC
  A111 FL
  A111 GA
  A111 HI
  B222 AL
  B222 AK
  B222 AZ
  B222 AI
  B222 KS
  B222 KY
  THE B222
  B222 ME
  B222 MD
  MY B222
  B222 MI
  B222 CA
  B222 CO
  B222 CT
  B222 OF

  Result set:
  EMPNO CODEZONE
  A111 AL | AK | AZ | AR | CA | CO | CT | OF | DC | FL
  A111 GA | HI
  B222 AL | AK | AZ | AI | KS |     KY | THE | ME | MD | MY
  B222 MI | CA | CO | CT | OF

  The above example can have any number of area CODE for a given EMPNO, the end result should show only a maximum of 10 codes for an EMPNO in each record. If she has more than 10 CODEZONE, it should show as another record. Please provide me with a generic statement to solve this problem. I was not able to control by setting the limit on records for an EMPNO gave to the LISTAGG function. Any ideas are much appreciated.

  Thank you

  ME_XE?with data (empno, areacode) as
    2  (
    3     select 'A111', 'AL' from dual union all
    4     select 'A111', 'AK' from dual union all
    5     select 'A111', 'AZ' from dual union all
    6     select 'A111', 'AR' from dual union all
    7     select 'A111', 'CA' from dual union all
    8     select 'A111', 'CO' from dual union all
    9     select 'A111', 'CT' from dual union all
   10     select 'A111', 'DE' from dual union all
   11     select 'A111', 'DC' from dual union all
   12     select 'A111', 'FL' from dual union all
   13     select 'A111', 'GA' from dual union all
   14     select 'A111', 'HI' from dual union all
   15     select 'B222', 'AL' from dual union all
   16     select 'B222', 'AK' from dual union all
   17     select 'B222', 'AZ' from dual union all
   18     select 'B222', 'IA' from dual union all
   19     select 'B222', 'KS' from dual union all
   20     select 'B222', 'KY' from dual union all
   21     select 'B222', 'LA' from dual union all
   22     select 'B222', 'ME' from dual union all
   23     select 'B222', 'MD' from dual union all
   24     select 'B222', 'MA' from dual union all
   25     select 'B222', 'MI' from dual union all
   26     select 'B222', 'CA' from dual union all
   27     select 'B222', 'CO' from dual union all
   28     select 'B222', 'CT' from dual union all
   29     select 'B222', 'DE' from dual
   30  )
   31  select
   32     empno, listagg(areacode, ',') within group (order by emp_grp)   as emp_list
   33  from
   34  (
   35     select
   36             ceil(row_number() over (partition by empno order by areacode) / 10) as emp_grp,
   37             empno,
   38             areacode
   39     from data
   40  )
   41  group by empno, emp_grp;
  
  EMPNO                          EMP_LIST
  ------------------------------ ------------------------------
  A111                           AK,AL,AR,AZ,CA,CO,CT,DC,DE,FL
  A111                           GA,HI
  B222                           AK,AL,AZ,CA,CO,CT,DE,IA,KS,KY
  B222                           LA,MA,MD,ME,MI
  
  4 rows selected.
  
  Elapsed: 00:00:00.05
  ME_XE?
  

  In the future, it would be nice if you could provide baseline data.

  See you soon,.

• Oracle 11g LISTAGG function

  Hello
  
  Hello. I tried to use the new feature in Oracle 11 g: LISTAGG, but I received an error:
  
  SQL * more: Production release 11.2.0.1.0 Wed Mar 28 15:36:47 2012
  
  Copyright (c) 1982, 2010, Oracle. All rights reserved.
  
  Enter the user name: lbihrreader@LTMQA
  Enter the password:
  
  Connected to:
  Oracle Database 11 g Enterprise Edition Release 11.1.0.7.0 - 64 bit Production
  SQL > SELECT DEVELOPMENTACTIVITY sc.
  SC.' SESSION '.
  LISTAGG (sc. CLASSDATE, ';') THE Group (ORDER BY sc. DEVELOPMENTACTIVITY, sc."SESSION")
  OF LTM. SESSIONCLASS sc
  WHERE sc. HRORGANIZATION = "800"
  AND TS. DELETEFLAG = "00000000000000000000000000000000"
  GROUP BY sc. DEVELOPMENTACTIVITY
  SC.' SESSION ';
  
  ERROR at line 3:
  ORA-00923: THE KEYWORD not found where expected
  
  Help, please.
  
  Thank you
  Helen

  In addition,

  THE Group (ORDER BY sc. DEVELOPMENTACTIVITY, sc."SESSION")

  doesn't make much sense in terms of ORDER BY. "" "You been group by sc. DEVELOPMENTACTIVITY, sc." SESSION "all GROUP lines will have same DEVELOPMENTACTIVITY, sc. ms." SESSION. " In any case, use:

  SELECT sc.DEVELOPMENTACTIVITY
  ,sc."SESSION"
  ,rtrim(xmlagg(xmlelement(s,sc.CLASSDATE,';').extract('//text()') order by sc.CLASSDATE),',')
  FROM LTM.SESSIONCLASS sc
  WHERE sc.HRORGANIZATION = '800'
  AND sc.DELETEFLAG = '00000000000000000000000000000000'
  GROUP BY sc.DEVELOPMENTACTIVITY
  ,sc."SESSION";
  

  For example:

  select  deptno,
          job,
          rtrim(xmlagg(xmlelement(s,sal,';').extract('//text()') order by sal),',') list
  from emp
  group by deptno,job
  /
  
      DEPTNO JOB       LIST
  ---------- --------- -------------------------
          10 CLERK     1300;
          10 MANAGER   2450;
          10 PRESIDENT 5000;
          20 CLERK     800;1100;
          20 ANALYST   3000;3000;
          20 MANAGER   2975;
          30 CLERK     950;
          30 MANAGER   2850;
          30 SALESMAN  1250;1250;1500;1600;
  
  9 rows selected.
  
  SQL> 
  

  SY.

• without using the listagg function

  Hi Sir,

  Today my Bishop asked me to write a sql query to display comma separated values using listagg, sys_connect_by_path, wm_concat?

  I said, we can write with the cursor... without predefined oracle functions? is this correct? or a Counselor about it?

  Please help me

  Concerning

  AR

  SQL > create table SEPM (deptno number (2), ename varchar2 (2));

  Table created

  SQL > insert all
  2 in samp (deptno, ename) values (10, 'A')
  3 in the SEPM (deptno, ename) values (20, 'd')
  4 in the samp (deptno, ename) values (20, 'E')
  5 SELECT * FROM DUAL;

  3 lines inserted

  SQL > SELECT * FROM SAMP;

  DEPTNO ENAME
  ------ -----
  10A
  20 D
  20 E

  Need to display like this

  10A

  20 D, E

  http://www.sqlsnippets.com/en/topic-11787.html

• Listagg function displays the keyword not found error message

  is version of Oracle 11 g

  create or replace
  function fn_months_attended
  return number is
  v_array varchar2(1000);
  begin
    select LISTAGG(c.act_id,',') within group (order by c.act_id desc) INTO V_ARRAY from 
            programmes a,campaigns b,activities c
          where  a.pro_id=b.cam_pro_id 
          and    b.cam_id=c.act_act_id 
          order by act_id DESC ;
  return v_array;
  end;
  
  Error i received 
  Error(6,3): PL/SQL: SQL Statement ignored
  Error(6,39): PL/SQL: ORA-00923: FROM keyword not found where expected

  can you please suggest me to find exactly the problem

  Hello

  In the LIST of 11 GR 1 tot material. function does not work. It works in only 11 GR 2.

  Kind regards
  Champion.

• In Oracle lag function

  Hi all

  I want to understand the inner workings of the Lag function in Oracle, which could help to solve my problem.

  I have the table as the structure below.

  P_ID	ENTRY_TIMESTAMP	SIZE	C_ID
  15287	1 NOVEMBER 15 05.45.00 PM	30	92
  15295	06.00.00 PM 1ST NOVEMBER 15	15	92
  15306	06.00.00 PM 1ST NOVEMBER 15	1	92

  Now, when I write a query as below:

  Select the size, CURR_TIMESTAMP TO_TIMESTAMP (TO_CHAR (ENTRY_TIMESTAMP, 'YYYYMMDDHH24MI'), 'YYYYMMDDHH24MI'),

  TO_TIMESTAMP (TO_CHAR (LAG (ENTRY_TIMESTAMP) OVER (PARTITION BY ORDER BY ENTRY_TIMESTAMP ASC C_ID), 'YYYYMMDDHH24MI'), 'YYYYMMDDHH24MI') LAG_TIMESTAMP

  OF Entry_log

  where ENTRY_TIMESTAMP BETWEEN to_date (1 November 15 18.00.00','DD-MON-YY HH24.MI.) SS') AND to_date (1 November 15 18.00.00','DD-MON-YY HH24.MI.) SS')

  Query will lead to give Lag_timestamp as 06.00.00 PM for size = 1 but will be NULL for size = 15.

  Why is that Oracle will never lag_timestamp = 06.00.00 PM for size = 15.

  Could someone please explain this behavior.

  I'm using Oracle 11 g.

  Thank you

  I had a small mistake in the above query. now, I fixed it

• Need help with the listagg function

  Hi all

  I try to use Listagg in the query below, but not able to get the answer. It is throwing an error message saying ORA-00979: not a GROUP BY expression.

  If I try to remove the Group By function and run the query, I get the following error ORA-00937: not a function of simple-group.

  Help, please.

  Select Distinct V.User_X, V.Original_Request_Id, (V.Support_Group_Name, ',') listagg Group (order of V.Support_group_name) as Group1,

  T.Individualassignedto, T.Status, T.Groupassignedto, T.Ticketcategory, T.Tickettype, T.orgcompany, T.submitter,

  T.Orgassignedto, T.Urgency

  Display V

  INNER JOIN K_TICKET T ON T.TICKETNUMBER = V.ORIGINAL_REQUEST_ID

  V.Original_Request_ID group

  Because you use a GROUP BY, you don't need SEPARATE.

  All the columns you are not aggregate (list) should be in the GROUP BY.

• Oracle Spatial function to find the closest channel line according to lat/long

  Hello
  
  Here's my scenario. I have a table that contains the geometries of type line (road network) channels. The line geomteries are of type Ohio state South (SRID 41104) plan.
  I have a requirement - given a lat/long, find the string line that aligns with this lat/long or the nearest set of strings of line at 0.02 miles.
  It is a typical example of an attempt to identify an accident on our road network situation. Accidents reported us in lat/long through the GPS system.
  How can I achieve this through any space function?
  
  Thanks for the help in advance.
  
  Thank you
  L.

  Hello L,

  SELECT
    r.
  FROM
    roadsegments r
  WHERE SDO_NN(r.geometry,
               sdo_geometry(2001, 41104, sdo_point_type(lat,lon,NULL), NULL, NULL),
               'sdo_num_res=2 distance=0.02 unit=mile') = 'TRUE';
  

  This will give you the two segments of road nearest you at 0.02 miles. See [url http://docs.oracle.com/cd/E11882_01/appdev.112/e11830/sdo_operat.htm#i78067] documentation on the operator SDO_NN, especially the bit about the use of the index indicator.

  HTH,
  Stefan

• Oracle form functions and procedures in the APEX, how?

  I'm working to recreate in the APEX, already existing read only forms in Oracle Forms. Report features interactive APEX among other things, in fact worth as well as to target a different audience than utilizies versions of Oracle Form. Versions of Oracle Forms use a lot of pre and post query triggers, PLSQL functions.
  
  In Oracle Forms that places, these functions can be found in the "Units of program" section of the form. A feature typical of this kind, based on a particular Mission ID route, collecting names of regular passengers, is shaped with a comma and a space after each of them, in a single string that is returned and displayed the list of passengers of a line.
  
  I have all of this written code so I can move most of the main request of the Oracle form in an interactive report. These functions and triggers called in the form of the "Units of program" section of the Oracle form rather than stored in the database schema in a package, where they would go inside the APEX? Can I create a 'shortcut' in the APEX and call it from the interactive report "Source Région"? I can create the PLSQL function at the level of the region of the interactive report or page level? Or, my best bet creates a package that is stored in the database, all these functions and/or proecedures I might need the original form of Oracle?
  
  Some advice would be greatly appreciated.

  RLBickham wrote:
  I don't think I've been pretty clear in the description of the specific thing I want to do, simply, it does not reach the level of forms of conversion of the APEX. It is basically a problem of PLSQL function.

  I have an interactive report which is currently 90 percent of what I want however, each line, which represents a Mission may have several feet. Each arm has two places or ICAO codes attached to it. Based on the number of Mission, I want to loop through the array of leg, collect all the codes of ICAO for this Mission, put them together in 1 variable separated by a coma and add this variable to display the columns in this interactive report as the last column.

  In Oracle Forms, I have a function registered in the database, which is called in the main query. Maybe I ask a question that does not need to be asked, but anyway my question is can I put this function currently in the database somewhere within the interactive report and somehow reference it via Http, or should I just stick with set of functions and procedures in the packages stored in the database and called the conventional way?

  You could switch the function to the database and call it from the report query, but it sounds as if it were superfluous. In the report query using any form of Re: 4. How can I convert rows to columns? is appropriate for your version of the (unspecified) database.

  -----

  When you have a problem, you will get an answer faster, more efficient including information as much information as possible from the outset. This should include:

• Full version of APEX
  
• Complete operating system DB, version, edition, host
  
• Architecture of Web server (EPG, SST or APEX listener/host operating system)
  
• Browser (s) and version (s) used
  
• Theme
  
• Model (s)


• Region/section type (s) (particularly as to distinguish if a 'report' is a standard report, an interactive report, or indeed a 'update report' (i.e. a tabular presentation))

  With APEX, we also had the chance to have a great resource in apex.oracle.com where we can reproduce and share problems. Reproduce things is the best way to solve most of the questions, particularly those relating to the layout and Visual formatting. If you expect a detailed response it is appropriate that you take on an important part of the effort by getting as much as possible with an example of the problem on apex.oracle.com before asking for help on specific issues, then we can see firsthand.

• No support for oracle sql functions

  Hi all
  
  Please can someone explain why the B-tree indexes are not capable of supporting SQL queries using the built-in functions of Oracle.
  
  We have indexes of tree b on account_no column.
  
  Select * from test_table where account_no = 11005208
  
  the above query use the index on account_no
  
  Select * from test_table where superior (account_no) = 11005208
  
  But this query does not use the index on the account_no, going for the full table scan.
  
  My question here is account_no is the numeric data type.
  Then, there is no difference between the data in the columns account_no and upper (account_no) column data, so why he does not use index when using sql functions in an sql query?

  Hello

  If you apply the upper function, Oracle implicitly converts its argument to a string, so your query is actually upper (to_char (account_no)).
  There is none HAVE fully functional in the optimizer and you do not expect to know everything and do all the conclusions that a human being can do. Why should Oracle re - write this type of query analysis the data type of the columns and features when it seems more natural programmer write a correct query (without capital letters in this example) or, if necessary, create an index based on a function?

• Oracle to_number function pramaters

  I have problems with TO_NUMBER function second and third parameters. One dependent on the other? How does the nls_params parameter? I don't understand how the result of the query
  
  SELECT TO_NUMBER ('17,000, 23',
  "999G999D99,"
  ' nls_numeric_characters = ",". ')
  REFORMATTED_NUMBER
  FROM DUAL;
  
  can be 17000.23. Could someone please explain the above conversion process. I looked towards the top of the documentation, but it is not explanatory eneogh.
  
  P.S. The query above is taken from a book of preperation certificate Expert Oracle database SQL.

  See
  TO_NUMBER problem
  Re: number format