Oracle Spatial function to find the closest channel line according to lat/long

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  Paste your file xml here, patients show us how count.

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  use

• Given Oracle Spatial are stored in the database tables?

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• 1 - where is the search function to find the authors muse a list?

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• Find the closest CMYK Pantone spot colors?

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  I know it's easy in Photoshop using the color picker, but there must be a way to do that in Illustrator.

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• How to find the closest higher value?

  Hi all
  
  I want to select the closest higher value in my data (test data are below):
  

  with test_data as
  ( select 0.21 as val1, 0.19 as val2 from dual
    union all
    select 0.21 as val1, 0.29 as val2 from dual
    union all
    select 0.21 as val1, 0.49 as val2 from dual
    union all
    select 0.67 as val1, 0.49 as val2 from dual
    union all
    select 0.67 as val1, 0.69 as val2 from dual
  )
  select * from 
  (
  select 
  val1,
  val2,
  rank() over (order by abs(val2 - val1)) nearest
  from test_data
  )
  where nearest = 1;

  output:

  VAL1    VAL2    NEAREST
  0.21     0.19     1
  0.67     0.69     1

  Output of this query is the NEAREST value to the value in the column of VAL1. But I would get the SUPERIOR value CLOSEST. As below the value at the higher value 0.21 closest isn't 0.29 0.19.
  
  desired output:

  VAL1    VAL2
  0.21     0.29
  0.67     0.69

  Is it possible to get the features you want using analytical functions?
  
  Thx for the help!
  
  Kind regards
  
  Jiri
  
  Published by: Jiri n. 10 October 2012 01:14

  with test_data as
  ( select 0.21 as val1, 0.19 as val2 from dual
    union all
    select 0.21 as val1, 0.29 as val2 from dual
    union all
    select 0.21 as val1, 0.49 as val2 from dual
    union all
    select 0.67 as val1, 0.49 as val2 from dual
    union all
    select 0.67 as val1, 0.69 as val2 from dual
  )
  
  select
   val1
  ,val2
  ,first_value(val2) over (partition by val1 order by
     case when val2 >= val1 then 1 else 2 end
     , val2
   ) nearest
  from test_data
  
  VAL1 VAL2 NEAREST
  .21 .29 .29
  .21 .49 .29
  .21 .19 .29
  .67 .69 .69
  .67 .49 .69 
  

• Function to find the County of ocurrances of an XML tag in developer j

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  Kindy suggerez_ me on this.

  Hello

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  Kind regards
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  Pointers on the same are appreciatable

  Use absolute funcion.
  

• find the closest value in table

  Hi all

  I need to find the values in the "C" line which is equal or close to the values 'A' in the 2D array, and then I want to show the values of 'B', corresponding to the values of 'C' in table 2D.

  How can I fix it?

  Thank you!

  

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• Function to find the name of the nth month [V 10 g]

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  Simply use a variable?

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  SQL > exec: n: = 3

  PL/SQL procedure successfully completed.

  SQL > select to_char (add_months (sysdate,: n), 'Month') twice;

  TO_CHAR (ADD_MONTHS (SYSDATE,: N), 'MOUNT)
  ------------------------------------
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  1 selected line.

  SQL > exec: n: = - 1

  PL/SQL procedure successfully completed.

  SQL > select to_char (add_months (sysdate,: n), 'Month') twice;

  TO_CHAR (ADD_MONTHS (SYSDATE,: N), 'MOUNT)
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  1 selected line.

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  PL/SQL procedure successfully completed.

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  TO_CHAR (ADD_MONTHS (SYSDATE,: N), 'MOUNT)
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• Find the nearest parallel line and ignore perpendicular line

  Hello
  
  We have two sets of linear facilities. We would like to find the nearest line of the other set of geometry, but preference should be given to the parallel lines as the perpendicular ones more.
  
  I was intending to use the suite response I see in this forum.
  extract the parallel roads
  
  Is another way?
  
  Thank you
  Frédéric

  Frederick,

  It really depends on what you're trying to determine from your data. I noticed that you included 'street' in your tags. Are you trying to link Street - axis facades, utilities or the plots?

  If you use buffering as John suggested, get an account for characteristics how target your buffer interacts with. In some cases (say the intersections of streets) where you will get multiple occurrences, you can compare the angles/slopes to identify the one who more parallel.

  Note that line buffering will produce a Cheeto (right, with well rounded rectangle). The Cheeto may interact with more than 1 target function if your buffer is too big and the characteristics of the target are tip-to-tail connected - and each of these objectives can be parallel to your line. If it's a problem, you can calculate distances to your targets and choose Next. You will probably always compare the slopes to eliminate false positives at intersections.

  In support of geocoding, I once to the streets adjacent plots and tried the above approaches and found that they do not have sufficient accuracy to dead end or corner-bulbs bulbs. Instead, I used the rotation value of the parcel labels (always placed perpendicular to the street) to generate features of research at the intersection of the adjacent streets. These search functions have variable length depending on the type of street. There were still a few false positives due to errors of data (e.g., misguidance label type, incorrect of streets, etc.), but little enough to dump a body to.

  Kind regards
  Noel

• Find the end of line

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  I have attached a picture of what I want to do.

  The text in the image is Hebrew (language R2L) and the end of the line is on the left.

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  Hello

  Assuming that your text is inside one or more blocks of text that are connected. Select one of them and run this:

  -------------

  myLines = app.selection [0].parentStory.lines;

  for (k = 0; k

  If (myLines [k] .characters [-1] == "\r") / / If there is an end of paragraph

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  }

  ------------

  It's just to show the way.

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• How to find the number of lines in the content of the text?

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  Note that all lines end with the SHIFT + ENTER.

  Example,

  It is a

  sample.

  After the line there is a there is (SHIFT + ENTER).

  Thanks for any help.

  Whenever the user enters the shift-enter, Photoshop inserts a control [EOT] (end of text) (\x03 or \u0003) character in the string.

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  Try replacing:

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  BTW, you can improve performance by explicitly asking the textKey for the current object of the layer property.

  Try using:

     ref.putProperty( charIDToTypeID("Prpr"), stringIDToTypeID("textKey") );
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  HTH...

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