Parent child query
I got the exit for parent-child relationshipsSelect
LPAD (' ', 2 * level) | child
Of
prune_test
Start by
parent is null
connect
child precondition = parent
as
1
-12
-120
-124
-127
-712
-7122
-7125
-7127
But I want like
Parent child Child1 2 child3
1
1 12
1 12 120
1-12-124
1-12-127
1 12 712
1 12 712 7122
1 12 712 7125
1 12 712 7127
Can someone help me...
Thank you
Mani
Published by: Mani on November 4, 2010 18:54
Do you just need a sys link by road
with prune_test as
(select null parent, 1 child from dual union all
select 1, 12 from dual union all
select 12, 120 from dual union all
select 12, 124 from dual union all
select 12, 127 from dual union all
select 12, 712 from dual union all
select 712,71522 from dual union all
select 712, 7125 from dual union all
select 712, 7127 from dual
)
select
lpad(' ', 2*level) || child, sys_connect_by_path(child,' ')
from
prune_test
start with
parent is null
connect by
prior child=parent
LPAD('',2*LEVEL)||CHILD SYS_CONNECT_BY_PATH(CHILD,'')
1 1
12 1 12
120 1 12 120
124 1 12 124
127 1 12 127
712 1 12 712
71522 1 12 712 71522
7125 1 12 712 7125
7127 1 12 712 7127
Tags: Database
Similar Questions
-
in the query and parent/child relationship
WITH the data AS
(
SELECT '213NY1' lfrom, NULL, '215ZVD' mi lto, "215ZV9 ' id, 1 January 2014' sdate, January 2, 2014' edate, 3 January, 2014 'mdate' January 5, 2014 medate double UNION ALL.
Lfrom SELECT NULL, '215ZVD' mi, id "213NY1", "215ZV9" lto 4 January 2014 'sdate', 6 January 2014 edate, January 7, 2014 'mdate', 8 January 2014 medate double UNION ALL
SELECT '216TVZ' lfrom, NULL, "213JW7" e "217LVQ" id lto, 21 January, 2014 'sdate' January 9, 2014 edate, 10 January 2014 'mdate', 11 January 2014 medate double UNION ALL
SELECT lfrom "215Y71", "217LVQ" lto, mi, "216TVZ" id "213JW7", 22 January, 2014 'sdate' January 23, 2014 edate, 24 January, 2014 'mdate' January 25, 2014 medate double UNION ALL
SELECT '234IJF' lfrom, NULL, "234YU" e "3IUED" id lto, 26 January 2014 'sdate', 27 January 2014 edate, 28 January 2014 'mdate', 29 January 2014 medate OF double
)
some lines have parent/child relationship and some does not. for example, the first two query (data) are link together. online, the value of lto (215ZV9) corresponds to the id value
in line 1. the value of lfrom in row1 (213NY1) corresponds to the value of online id.
the same scenario occurs in rows 3 and 4. 5th doesn't have any line which is a child. tier 5 is a single parent
I want to WRITE a query that gives the following result.
Mid id initial_date final_date
=======================================
215ZVD 215ZV9 1 January 2014 "January 5, 2014"
"215ZVD 213NY1 7 January 2014" January 6, 2014 "
"213JW7 217LVQ 21 January 2014 ' 11 January 2014"
"213JW7 216TVZ 24 January 2014 ' 23 January 2014"
"234YU 3IUED 26 January 2014 ' 27 January 2014"
ONLY WHEN there is a parent/child relationship, initial DATE AND follow the final data WHAT such as
FIRST date of deadline DATE
< Mdate > < EDate > - for child
< SDate > < MEDate > - for parent
WHEN there is no relationship of parent/child (e.g. ONLY a parent ROW) THEN
FIRST date of deadline DATE
< SDate > < EDate-> parent
can someone help me write a query for the above output
with tt AS
(SELECT a.*,
ROW_NUMBER () ON LV (MIDDLE ORDER BY SDATE PARTITION),
CASE
WHEN ID = NVL (ADVANCE (lto, 1) OVER (PARTITION BY Middle ORDER BY sdate), LAG (lfrom) OVER (ORDER BY sdate Middle PARTITION))
THEN 1
END flg
DATA one
)
SELECT THE MIDDLE,
ID,
CASE
WHEN flg IS NOT NULL
THEN
CASE
WHAT LV = 1
THEN SDATE
WHAT LV = 2
THEN mDATE
END
Of ANOTHER sdate
END INITIALDATE
CASE
WHEN flg IS NOT NULL
THEN
CASE
WHAT LV = 1
THEN mEDATE
WHAT LV = 2
THEN EDATE
END
Of ANOTHER edate
END FINALDATE
TT;
Output:
-------------
MID ID INITIALDATE FINALDATE
213JW7 217LVQ 21 January 2014 January 11, 2014
213JW7 216TVZ 24 January 2014 23 January 2014
215ZVD 215ZV9 January 1, 2014 5 January 2014
215ZVD 213NY1 January 7, 2014 6 January 2014
234YU 3IUED 26 January 2014 January 27, 2014
-
Stuck on a sql query to search for records that have the same parent child records
Oracle 10 g 2 Enterprise Edition.
Hello
I'm writing a logic to find records in a parent table, who have the same values in a child table.
This is part of a larger application, but I am stuck on that part for now, so I have mocked some of the below simplified tables to capture the heart of the
the problem is that I'm stuck.
Let's say I have a responsible parent, child employee table table and there are a number of many relationships between them.
The aptly named Join_Table manages the relationship between them. If a manager can manage several employees, an employee can be managed by
many managers.
I have a feeling it's stupidly easy, but it seems to me having a bad episode of brain freeze today!
If I ask for Manager John, so I want to find other managers who manage the exact list and even employees.-- parent table CREATE TABLE manager ( id number primary key, name varchar2(100)); -- child table CREATE TABLE employee ( id number primary key, name varchar2(100)); -- link table CREATE TABLE join_table ( manager_id NUMBER, employee_id NUMBER, CONSTRAINT join_table_pk PRIMARY KEY (manager_id, employee_id), CONSTRAINT manager_fk FOREIGN KEY (manager_id) REFERENCES manager(id), CONSTRAINT employee_fk FOREIGN KEY (employee_id) REFERENCES employee(id) ); -- Insert some managers INSERT INTO manager (id, name) VALUES (1, 'John'); INSERT INTO manager (id, name) VALUES (2, 'Bob'); INSERT INTO manager (id, name) VALUES (3, 'Mary'); INSERT INTO manager (id, name) VALUES (4, 'Sue'); INSERT INTO manager (id, name) VALUES (5, 'Alan'); INSERT INTO manager (id, name) VALUES (6, 'Mike'); -- Insert some employees INSERT INTO employee (id, name) VALUES (101, 'Paul'); INSERT INTO employee (id, name) VALUES (102, 'Simon'); INSERT INTO employee (id, name) VALUES (103, 'Ken'); INSERT INTO employee (id, name) VALUES (104, 'Kevin'); INSERT INTO employee (id, name) VALUES (105, 'Jack'); INSERT INTO employee (id, name) VALUES (106, 'Jennifer'); INSERT INTO employee (id, name) VALUES (107, 'Tim'); -- Insert the links -- John manages Paul, Simon, Ken INSERT INTO join_table (manager_id, employee_id) VALUES (1, 101); INSERT INTO join_table (manager_id, employee_id) VALUES (1, 102); INSERT INTO join_table (manager_id, employee_id) VALUES (1, 103); -- Bob manages Paul, Simon, Kevin, Jack INSERT INTO join_table (manager_id, employee_id) VALUES (2, 101); INSERT INTO join_table (manager_id, employee_id) VALUES (2, 102); INSERT INTO join_table (manager_id, employee_id) VALUES (2, 104); INSERT INTO join_table (manager_id, employee_id) VALUES (2, 105); -- Mary manages Jennifer, Tim INSERT INTO join_table (manager_id, employee_id) VALUES (3, 106); INSERT INTO join_table (manager_id, employee_id) VALUES (3, 107); -- Sue manages Jennifer, Tim INSERT INTO join_table (manager_id, employee_id) VALUES (4, 106); INSERT INTO join_table (manager_id, employee_id) VALUES (4, 107); -- Alan manages Paul, Simon, Ken, Jennifer, Tim INSERT INTO join_table (manager_id, employee_id) VALUES (5, 101); INSERT INTO join_table (manager_id, employee_id) VALUES (5, 102); INSERT INTO join_table (manager_id, employee_id) VALUES (5, 103); INSERT INTO join_table (manager_id, employee_id) VALUES (5, 106); INSERT INTO join_table (manager_id, employee_id) VALUES (5, 107); -- Mike manages Paul, Simon, Ken INSERT INTO join_table (manager_id, employee_id) VALUES (6, 101); INSERT INTO join_table (manager_id, employee_id) VALUES (6, 102); INSERT INTO join_table (manager_id, employee_id) VALUES (6, 103); -- For sanity CREATE UNIQUE INDEX employee_name_uidx ON employee(name);
Answer should be Mike.
If I ask for Manager of Mary, the answer should be Sue.
This query will give me the list of managers who manage some of the same employees as John, but not the same employees accurate...
I thought about using set operations to find managers with a list of employees less than my employees is null and where my employees under their list of employees is null. But there must be an easier way more elegant.SELECT DISTINCT m.name AS manager FROM manager m, join_table jt, employee e WHERE m.id = jt.manager_id AND jt.employee_id = e.id AND e.id IN ( SELECT e.id FROM manager m, join_table jt, employee e WHERE m.id = jt.manager_id AND jt.employee_id = e.id AND m.name = 'John') ORDER BY 1;
Any ideas?
BTW, I need to run as a batch on tables with > 20 million rows so the efficiency of queries is key.What about...
WITH manager_list AS ( SELECT name, LTRIM(MAX(SYS_CONNECT_BY_PATH(id,',')) KEEP (DENSE_RANK LAST ORDER BY curr),',') AS employees FROM (SELECT m.name, e.id, ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) AS curr, ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) -1 AS prev FROM manager m, join_table jt, employee e WHERE m.id = jt.manager_id AND jt.employee_id = e.id AND m.name = :P_MANAGER) GROUP BY name CONNECT BY prev = PRIOR curr AND name = PRIOR name START WITH curr = 1 ), all_list AS ( SELECT name, LTRIM(MAX(SYS_CONNECT_BY_PATH(id,',')) KEEP (DENSE_RANK LAST ORDER BY curr),',') AS employees FROM (SELECT m.name, e.id, ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) AS curr, ROW_NUMBER() OVER (PARTITION BY m.name ORDER BY e.id) -1 AS prev FROM manager m, join_table jt, employee e WHERE m.id = jt.manager_id AND jt.employee_id = e.id) GROUP BY name CONNECT BY prev = PRIOR curr AND name = PRIOR name START WITH curr = 1 ) SELECT a.* FROM manager_list m, all_list a WHERE m.employees = a.employees
Would be easier in 11g, but I do not have a facility here so this is based on 10g.
See you soon
Ben
-
Oracle query convert recursive parent-child level columns
Dear gurus,
I have a Hyperion extracted dimension table with my COA in a parent/child layout:
parent, child
Acc01, acc001
acc001, acc0001 etc.
I need to convert to the:
level 2, level 1, Level0
Acc01, acc001, acc0001 etc.
Please advise, need to feed table table schema for reporting.
Concerning
Yannis
with
data in the form of
(select "C01" parent, child 'C001' Union double all the)
Select 'C001', 'C0001' from dual union all
Select 'C001', 'C0002"dual union all
Select "C01", "C002' from dual union all
Select "C0001', 'C00001' from dual union all
Select "C00001', 'C000001' from dual union all
Select 'C000001', 'C0000001' from dual
)
Select leve1_1, level_2, level_3, level_4, level_5, level_6
from (select root0, lvl0, regexp_substr(path,'[^,]+',1,level) VAC, level lvl
of (lvl0 level select,
connect_by_root parent root0,
parent connect_by_root | path of SYS_CONNECT_BY_PATH (Child, ',')
from the data
where connect_by_isleaf = 1
Start with parent (select parent
data d
If not exists (select null
from the data
where child = d.parent
)
)
connect by prior child = parent
)
connect by level<=>=>
and prior root0 = root0
and prior lvl0 = lvl0
and prior sys_guid() is not null
)
Pivot (max (VAC) for lvl 1 as leve1_1, 2 level_2, 3 level_3, 4 level_4, 5 level_5, 6 level_6)
LEVE1_1 LEVEL_2 LEVEL_3 LEVEL_4 LEVEL_5 LEVEL_6 C01 C002 - - - - C01 C001 C0002 - - - C01 C001 C0001 C00001 C000001 C0000001 Concerning
Etbin
-
Blockages with parent/child tables
Guys,
We have a parent-child of tables in our database with the DDL below:
CREATE TABLE 'ACCOUNT '.
(SELECT 'ACCOUNT_ID' VARCHAR2 (32 BYTE) NOT NULL,)
X, Y, Z,...),
'XPK_ACCOUNT' CONSTRAINT PRIMARY KEY ('ACCOUNT_ID');
CREATE TABLE ACCOUNT_PARTITION ".
(SELECT 'ACCOUNT_ID' VARCHAR2 (32 BYTE) ENABLE NOT NULL, "BALANCE" NUMBER (5.0) NOT NULL,)
X, Y, Z,...),
'XPK_ACCOUNT_PARTITION' CONSTRAINT PRIMARY KEY ('ID_COMPTE', 'BALANCE')
KEY FOREIGN CONSTRAINT 'ACCOUNT_PARTITION_FK1' ('ACCOUNT_ID')
SELECT THE 'ACCOUNT' ('ACCOUNT_ID') REFERENCES);
"Lately, we cross " ""ORA-00060: Deadlock detected while you wait for resources ' errors while DELETING in the tables above. Please note that the tables of the child is not any clue except KP index.
Could someone please suggest resolution for us to minimize the error of blocking?
Respect,
Bugs
Imagine you remove account, Oracle must verify there is no record of the child in ACCOUNT_PARTITION, this is because as your FK is restrict the deletions (do not allow the removal if there are child records). As ACCOUNT_PARTITION. Account_id is indexed so it will be an exclusive table lock to find this, locks the table.
Another way of thinking is, imagine that you have performed the following query without and ACCOUNT_ID index:
Select *.
of ACCOUNT_PARTITION
where ACCOUNT_ID =
He SHOULD do a full table scan right? Well well, even on a deletion of the parent. It attempts to identify lines for the purpose of blocking,
As a general rule, it is always a good idea to index FKs.
-
Get the parent-child hierarchy of column delimited
I've been on this forum once before, and someone helped me, so I hope I can get help again!
4-15-5987');
Thus, the hierarchy is divided on the hyphen. first parent being 4245, then the next value is-4 (including the hyphen) and what follows is - 1, for example
CREATE TABLE REGEXTEST ( ITEM VARCHAR(20)); INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4'); INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-1'); INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-10'); INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-11'); INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-12'); INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-13'); INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-14'); INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-15'); INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-15-59A7'); INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-15-59D7'); INSERT INTO REGEXTEST (ITEM) VALUES ('4245-4-15-59F7'); INSERT INTO REGEXTEST (ITEM) VALUES ('4245-
I have to be able to bind-1, -4, 4245. Perhaps the simplest is to build a new table with a primary key where it is assigned the id of the parent to the child.
I just can't understand how to divide the individual elements and maintain the hierarchy. As previously mentioned, someone helped me with another part of the problem before where I needed to maintain the entire path of each child with the following query:select nvl(prior item,item) parent, nvl2(prior item,item,null) child from REGEXTEST connect by substr(item,1,instr(item,'-',-1) - 1) = prior item order by child,parent
Now, if I could extrapolate that into a new table:
CREATE TABLE FileHierarchy (ItemID INT NOT NULL PRIMARY KEY, ItemName varchar(50) NOT NULL, ParentID INT NULL);
ItemName is the 4245 or - 4 or - 1 (only) - Yes, including the hyphen.
The ID of the parent-1 would be the ID-4, etc...
Thank you very much in advance!
J.F. Larente
Solution for not having stored the high level:
SQL > select *.
regextest 2
3.POINT LEV
-------------------- ----------
4245 4
4245 4-1
4245 4-10
4245 4-11
4245 4-12
4245 4-13
4245 4-14
4245 4-15
4245 4-15-59 A 7
4245 4-15-59 D 7
4245-4-15-59F711 selected lines.
SQL > with t1 as)
2. Select item
regextest 3
4 Union all the
5 select distinct substr (item, 1, instr(item,'-',1))
6 of regextest
7 ),
8 t2 as)
9. select element,
10 row_number() on id (order by article)
11 from t1
12 )
13. select id,
14 regexp_substr (rtrim (point,'-'), case level when 1 then ' [^-] + $' other '-[^-] + $' end) child.
parentID 15 prior id,
16 regexp_substr (prior rtrim (point,'-'), case level - 1 when 1 then ' [^-] + $' other '-[^-] + $' end) parent
17 of t2
beginning 18 with substr(item,-1) = '-'
19 connect by substr (item, 1, instr(item,'-',-1) - 1) = prior rtrim(item,'-')
20 and article! point prior =
21.ID PARENTID PARENT CHILD
---------- -------------------- ---------- --------------------
1 4245
2 -4 1 4245
3 -1 2 -4
4 -10 2 -4
5 -11 2 -4
6 -12 2 -4
7 -13 2 -4
8 -14 2 -4
9 -15 2 -4
10-59A 7 9-15
11 59 D 7 9 - 15ID PARENTID PARENT CHILD
---------- -------------------- ---------- --------------------
12 59F7 9-1512 selected lines.
SQL >
SY.
-
parent/child relationship hirarchy
Hi everyone, consider the sample data
SELECT LFROM '1TR1Y6', NULL LTO, MID '11ZFDD', '21XHK7' double UNION ALL TID-
SELECT '1TR1YF' LFROM, LTO NULL, '11ZFDD' MI '21XHK5' TID FROM dual UNION ALL-
SELECT '1TR1X1' LFROM, LTO NULL, '11ZFDD' MI '21XHK8' TID FROM dual UNION ALL-
SELECT '1LSZX1' LFROM, LTO NULL, '11ZFDD' MI '1TR1YD' TID FROM dual UNION ALL-
SELECT LFROM "1LSZWQ", "21XHK7" LTO, MID '11ZFDD', '1TR1Y6' TID FROM dual UNION ALL-
SELECT LFROM "1LSZX2", "21XHK5" LTO, MID '11ZFDD', '1TR1YF' TID FROM dual UNION ALL-
SELECT LFROM "1LSZVG", "21XHK8" LTO, MID '11ZFDD', '1TR1X1' TID FROM dual UNION ALL-
SELECT LFROM "4LSSVG", "21XHK9" LTO "11AAA' MI '1TR1X1' TID double UNION ALL
SELECT "AAAAA" LFROM, LTO NULL, '11ABB' e, 'CCCCCC' double UNION ALL TID
SELECT "BATH" LFROM, 'CCCCCC' LTO, MID '11ABB', 'AAAAA' double UNION ALL TID
some of them have a parent/child releationship. for example, let take rank with LFROM = 1TR1Y6
1TR1Y6 (lfrom) corresponds to the fifth line with TID 1TR1Y6. TID 1TR1Y6 LTO COLUMN value corresponds to the first line TID (21XHK7)
It before these two LINES are IN a parent/child relationship.
lets take another example. LINE two WITH LFROM = 1TR1YF matches sixth RANK WITH TID 1TR1YF. the sixth LINE LTO COLUMN (21XHK5) corresponds to the SECOND TID of LINE.
Once again the parent child relationship. There are two lines that do not have the relationship of parent/child (ex. line 8)
Im trying to write a query that can partition the data in the middle column and find the parent/child relationship. the output of the above data should be
LTO LFROM MIDDLE TID FLAG
1TR1Y6 NULL 11ZFDD 21XHK7 1
1LSZWQ 21XHK7 11ZFDD 1TR1Y6 1
1TR1YF NULL 11ZFDD 21XHK5 1
1LSZX2 21XHK5 11ZFDD 1TR1YF 1
1TR1X1 NULL 11ZFDD 21XHK8 1
1LSZVG 21XHK8 11ZFDD 1TR1X1 1
1LSZX1 NULL 11ZFDD 1TR1YD 0
4LSSVG 21XHK9 11AAA 1TR1X1 0
ABDELKÉBIR 11ABB CCCCCC NULL 1
CCCCCC 11ABB AAAAA BATH 1
For simplicity, I posted the release with parent/child, side by side in the sequence. the order does not matter as long as the flag column (pull the column) is set to an appropriate value (1 if parent/child, 0 no parent/child)
the flag column value is derived from column to indicate the parent/child relationship was found.
I try using lead, the lag function but I have problem of sorting data from parent and child line could come at random order (they are not side by side).
It is therefore difficult to use lead because you don't know how many lines to carry forward.
can someone help me write a query that displays the output above
SELECT T1. LFROM,
T1. LTO,
T1. ENVIRONMENT,
T1. TID,
(
SELECT COUNT (*)
OF TBL T2
WHERE)
T2. TID = T1. LFROM
OR
T2. LFROM = T1. TID
)
AND T2. MI = T1. MID
) FLAG
OF TBL T1
/
LTO LFROM MIDDLE TID FLAG
------ ------ ------ ------ ----------
1LSZWQ 21XHK7 11ZFDD 1TR1Y6 1
1LSZX2 21XHK5 11ZFDD 1TR1YF 1
1LSZVG 21XHK8 11ZFDD 1TR1X1 1
CCCCCC 11ABB AAAAA BATH 1
1TR1X1 11ZFDD 21XHK8 1
1TR1X1 11ZFDD 21XHK8 1
1LSZX1 11ZFDD 1TR1YD 0
1TR1Y6 11ZFDD 21XHK7 1
ABDELKÉBIR 11ABB CCCCCC 1
1TR1YF 11ZFDD 21XHK5 1
4LSSVG 21XHK9 11AAA 1TR1X1 011 selected lines.
SQL >
SY.
-
Hierarchy parent child scenario
Hi friends,
Im just working on the parent-child hierarchy by using the link below with the sample data.
http://www.Oracle.com/WebFolder/technetwork/tutorials/OBE/FMW/bi/bi11115/biadmin11g_02/biadmin11g.htm_
I tried to implement the same hierarchy using my local data instead of referring to the sample data.
I have a query that returns the Manager as well as the position of the employee at the employee below
Im looking forward to implement the same result in my BI with a parent-child hierarchy.select distinct papf.person_id, papf.full_name "Employee Name", supf.person_id "Manager Id", supf.full_name "Manager Name", pj.name "Position Name" from per_all_people_f papf, per_all_assignments_f paaf, per_all_people_f supf, per_jobs pj where papf.person_id = paaf.person_id and supf.person_id = paaf.supervisor_id and paaf.job_id = pj.job_id and trunc(sysdate) between paaf.effective_start_date and paaf.effective_end_date and trunc(sysdate) between papf.effective_start_date and papf.effective_end_date
Since then, I imported three tables to my physical layer
For the creation of parent-child in BI, we need to have a table of separate Parent child which consist of four columns like ancestorkey, memberkey, distance, sheet.per_all_people_f------------Dimension per_all_assignments_f-----Fact per_jobs---------------------Dimension
In the column above, I can understand the meaning as
But I could not the meaning of the column distance as the meaning suggest, as a distance b/w the two column of the worksheet in the sense suggest as one sheet What leaf member it refers.For Ancestorkey-->Managerid Memberkey------->Employeeid
I also have the link below then too could not get the feel for it
http://www.rittmanmead.com/2010/08/Oracle-BI-EE-11g-Parent-Child-Hierarchies-Differing-Aggregations/+.
How do I train the child parent table for the BI of my three tables above in the HRMS.
Thank you
Kind regards
SaroHi friends,
I think I found a link to
http://prasadmadhasi.com/2011/11/15/hierarchies-parent-child-hierarchy-in-OBIEE-11g/
Let me try this and will update accordingly.
Thanks for your point of view.
Kind regards
Saro -
Error with BIEE11.1.1.5 Parent-child hierarchies
Hello
I use BIEE11.1.1.5, I created a logic Dimensions with Parent-child hierarchies.
In response, I move named 'H5 Sales Rep' hierarchies, and then display the results,
There error, the following error message:
ODBC driver returned an error (SQLExecDirectW).
Error details
Error codes: OPR4ONWY:U9IM8TAC:OI2DL65P
State: HY000. Code: 10058. [NQODBC] [SQL_STATE: HY000] [nQSError: 10058] A general error occurred. [nQSError: 43113] The message returned by OBIS. [nQSError: 43119] Query Failed: [nQSError: 22056] to use the line functions, you must associate a Table close Source logical Table "LTS1 Sales Rep. (HY000)
Publ. SQL: SELECT 0 s_0, "Sample Sales". "" Sales Rep ". "" Sales Rep Name ' s_1, CASE WHEN ISLEAF ("Sample Sales" "." ") Sales Rep. ("' H5 Sales Rep") THEN 1 ELSE 0 END s_2, IDOF ("Sample Sales" "." ") Sales Rep. ("' S_3 H5 Sales Rep"), PARENT ("" Sample Sales "". "") Sales Rep. ("' S_4 H5 Sales Rep") OF "Sample Sales" WHERE ISROOT ("" Sample Sales "". "") Sales Rep. ("' H5 sales representative")
someone knows why?
Thank you!Hi Leo,
You have configured table of closing? http://www.rittmanmead.com/2010/11/Oracle-BI-EE-11g-parent-child-hierarchies-multiple-modeling-methods/
Also, be sure to make the changes to hierarchy in offline mode.
Kind regards
DpKa -
Sum of a stand-alone parent-child table
I have two tables - a 'key' table containing a parent-child relationship of multi-layer and a table 'amount' that contains the keys for the nodes in the key as well as table of numeric values (for example the amounts).
I want a query that returns each line in the table of key as well as the sum of the amount amounts of the table for the set of nodes of this key (so the root node would be the sum of all values of quantity).
Here's what I mean: I have two tables, the KEY and the AMOUNT
KEY has two columns, keys, and parent_key; key and parent_key have a relationship CONNECT BY parent_key = prior key (with null for the root parent_key):
AMOUNT a two columns, keys, and amount; key points to KEY.key and amount is a value for that particular keyKEY PARENT_KEY 0 null 1 0 2 0 3 0 1A 1 2A 2 2B 2 3A 3 3B 3 3C 3 1A1 1A 1A2 1A 2A1 2A 2A2 2A 2B1 2B 3A1 3A 3A2 3A 3C1 3C 3C2 3C
(Note that all key values are leaf nodes in the KEY table)
What I want is a result that looks like this, where the amount of each key is the sum of the amounts of its possible keys sheetKEY AMOUNT 1A1 1 1A2 2 2A1 3 2A2 4 2B1 5 3A1 6 3A2 7 3C1 8 3C2 9
For example, the value of the key 2 a, 7, is the sum of the values of 2 a 1 and a 2, 2; key value of 3 is the sum of 3 a 1, a 3, 2, 3, C 1 and 2 of 3.KEY AMOUNT 0 45 1 3 2 12 3 30 1A 3 2A 7 2B 5 3A 13 3B 0 3C 17 1A1 1 1A2 2 2A1 3 2A2 4 2B1 5 3A1 6 3A2 7 3C1 8 3C2 9
Is it possible to do this with a single query?
The idea I came with is, do a select on the KEY with a "Key CONNECT_BY_PATH" column so that each line contains a string that contains the keys of all his ancestors and then do a join on AMOUNT with IN the CONNECT_BY_PATH amount.key column; However, with a large amount of data, it takes a little time. Is there a way faster / more obvious to achieve?OK you have almost everything you need. Outer join just your two tables, and then perform a hierarchical query, noting the key root of each tree. Then group the data set resulting:
with t1 as (select '0' "KEY", '' parent_key from dual union all select '1', '0' from dual union all select '2', '0' from dual union all select '3', '0' from dual union all select '1A', '1' from dual union all select '2A', '2' from dual union all select '2B', '2' from dual union all select '3A', '3' from dual union all select '3B', '3' from dual union all select '3C', '3' from dual union all select '1A1', '1A' from dual union all select '1A2', '1A' from dual union all select '2A1', '2A' from dual union all select '2A2', '2A' from dual union all select '2B1', '2B' from dual union all select '3A1', '3A' from dual union all select '3A2', '3A' from dual union all select '3C1', '3C' from dual union all select '3C2', '3C' from dual ), t2 as (select '1A1' "KEY", 1 amount from dual union all select '1A2', 2 from dual union all select '2A1', 3 from dual union all select '2A2', 4 from dual union all select '2B1', 5 from dual union all select '3A1', 6 from dual union all select '3A2', 7 from dual union all select '3C1', 8 from dual union all select '3C2', 9 from dual ), t3 as ( select t1.key, parent_key, amount from t1 left join t2 on t1.key = t2.key ), t4 as ( select CONNECT_BY_ROOT key root_key , level lv , t3.* from t3 connect by prior t3.key = parent_key ) select root_key "KEY", sum(amount) amount from t4 group by root_key order by length(root_key), root_key;
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Add an object 3d without parent/child relationship.
Hello
I have a scene of 3d picture control, I have two objects in there, but when I created the scene I had to use the add object invoke node objects in the scene, so there is a parent/child relationship between the objects, which means that if I move the parent, I also move the child object. Is there a way to create a scene with several objects without the parent/child relationship.
Thank you.
-Luis
Hello, I solved it by first moving the objects and then adding them to the scene. -Luis
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Parent - child relationship constraint Unique 5.0 apex oracle
Oky so I will try to avoid duplicate values get inserted in the parent-child node.
So basically when there's a node parent (Mobile) I can't create same node with the same name.
Even for the child node, if there is a child node name there may be another named A.
Structure:
Mobile (parent) /Android (Child) /KitKat (subchild) (allowed)
Mobile/apple/ios(Now allowed Same Parent name)
Win7/Windows/win7(not allowed same child)
So a big child and the parent must be unique at any time.
create an index of single "TEST_UK" on tablename (parent_id, upper (child_name));
see this too for a case-insensitive unique constraint
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ADF Parent-child tables of rules
Hello
I use JDeveloper and ADF 12.1.3. Now, I have a set of related tables, and each of them have only a child table.
I have a jsf page master / detail for each child table. Inside it, I can insert a row in the parent table and several rows in the child table. Commit the button is clicked validate monkey for the booth tables. Link between the master (parent table) and retail (child table) is done via the partnership link and view for the user interface.
Now, here's the rule I would apply: I can't commit newly created at the table parent without at least a new inserted row in child table.
Because I have several parent-child tables in this case of use, I wanted to replace the EntityImpl class and add newly created to each parent table class, so I bussines logic in one place for this tables.
We will look and taste to the table of one of the parents (not overloaded class EntityImpl):
The Interior has generated parent EO class
@Override
{} public void beforeCommit (TransactionEvent transactionEvent)
TODO implement this method
If (! validateParentChildNumber()) {}
throw new local ("not allowed.");
}
super.beforeCommit (transactionEvent);
}
public boolean validateParentChildNumber() {}
If (getParentChild (). GetRowCount() > 0)
Returns true;
on the other
Returns false;
}
This works well. If I inserts a row in the parent table and one or more rows in the child table passes validation. But if I get a line inside the parent table and no line of children tables I'm not allowed message in my browser.
So here's where problem read. Once I'm getting now authorized message, no matter if I insert the new line of Herald, I cannot commit until what I restar my app. Why? Because now, I constantly have this message:
It's like I can't hire the existing parent row I inserted before the child missing line. Why is this happening? I should replace postChanges method and what to put in it?
Thx a lot
Yes, you should do it in all cases, but point of my post is - put this code in the method of beforeCommit() of the primary entity. Only you need to do in beforeCommit(), is to count the child related entities.
In your java master entity impl class, you will have the method which returns a RowIterator with associated children, entities, something like that
public getChildsEO() {} RowIterator
return (RowIterator)...;
}
then, just call this method in beforeCommit() and see if there is at least a child entity...
You have a point?
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Navigation in Parent child Hiearachy is a bug in OBIEE 11.1.1.6?
Hi all
Look in one of my previous posts
OBIEE 11g - Navigation in the Parent child hierarchy does not
One of my friends Ram told me that it is a Bug of Oracle in 11.1.1.6. It's that I just wanted to know if someone has faced the same problem and this was reported as a bug in Oracle. Unfortunately, I do not have the privileges to log a bug or review the information in bug, can someone please provide any information on that?
Thank you
RonnyHello
This problem is fixed in Version 11.1.1.7.0 Obiee (here next year released Q1: currently his patch not published)
Thank you
Deva -
Default filters that users can delete (in the parent/child Setup)?
Is it possible in Latitude 2.2.2 to have filters (filters of the range, refinement filters etc.) applied by default (which means that users see these filters when they log-in), but they can also remove (using bread crumbs portlet) if they wanted to? We tried to use the source of data (JSON) filters (using 'baseFunctions' setting) where we have a parent/child Setup, but it seems these filters cannot be removed once applied. Note that filters can be removed if we do not have a parent/child relationship between the data sources, but as soon as we introduce a parent/child relationship between the data sources (which we need), the GET of sticky filters and cannot be deleted. Any reason why the parent/child relationship causes the filters becoming sticky? Any way (alternate) to reach what we want?I think that it is a known problem (LSTUDIO-5088) and there could be a fix for this. You can contact technical support to obtain the fix.
Dave
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