Parsing XML in ColdFusion 5

Similar Questions

• Problem in parsing XML

  Hello

  Any1 can you please tell me how to do Xml parsing in Blackberry. I'm a bit confused by it.

  Assume that it is my link:

  {keyword: "keword", url: "videoUrl"}

  While parsing xml:

  String keyword1 ="";

  element.getName.equalsIgnoreCase ("keyword");

  keyword1 = Element.GetText ();

  is she writing?

  Hey its done.

• Parsing XML and get the attributes of a tag

  Hello

  When parsing XML for application of Cascades in C++, I am able to get the value of a tag as follows:

  00000

  But I also want to get the attributes of a tag:

  But I don't know how to get the 'CA' and 'California' attributes with my current code.  Can anyone help?  Here is the code I use to parse the XML code:

  void CMController::requestFinished(QNetworkReply* reply) {
  
      if (reply->error() == QNetworkReply::NoError) {
  
          QXmlStreamReader xml;
  
          QByteArray data = reply->readAll();
          xml.addData(data);
  
          QString zip;
          QString id;
          QString location;
  
          while (!xml.atEnd() && !xml.hasError()) {
  
              /* Read next element.*/
              QXmlStreamReader::TokenType token = xml.readNext();
  
              /* If token is just StartDocument, we'll go to next.*/
              if (token == QXmlStreamReader::StartDocument) {
                  continue;
              }
  
              /* If token is StartElement, we'll see if we can read it.*/
              if (token == QXmlStreamReader::StartElement) {
  
                  if (xml.name() == "zip") {
                      zip = xml.readElementText();
                  }
  
                  if (xml.name() == "id") {
                      ???
                  }
  
                  if (xml.name() == "location") {
                      ???
                  }
  
              }
  
          }
  
          emit succeeded(result);
  
      } else {
          emit failed();
      }
  
      reply->deleteLater();
  
  }
  

  Thank you!

  I found a working example:

  if(xml.name() == "state"){
      QXmlStreamAttributes attrib = xml.attributes();
      QStringRef ref = attrib.value("location");
      qDebug() << "location: " << ref;
  }
  

• Widget to the Web service, parsing XML

  I worked on the communication with my web services and back to my widget.

  By using the code below, I was able to perform a GET and repay the XML, but I can't find data where I expect it to be node-wise when parsing XML. I return an object with 3 variables attached to it. I expect to be child nodes 1, 2, and 3. They proved to be 1, 3 and 5 nodes.

  Any ideas on why or how? I feel I'm missing just a simple thing in all of this.

  XML response

  
  - http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://tempuri.org/">
    1000
    Test Station
    105.285
    
  

  The widget code

  //****************** Ajax Logic ******************
  var xmlHttp;
  function getStationUpdate() {
  
      alert("in station update");
      xmlHttp = new XMLHttpRequest();
  
      var Posturl = "http://MachineIPGoesHERE:51107/Service1.asmx/HelloWorld2?";
      alert("after post url");
      xmlHttp.onreadystatechange = updateData;
      alert("after onReadyStateChange");
      xmlHttp.open("GET", Posturl, true);
      alert("after GET");
  
      xmlHttp.send(null);
  }
  
  function updateData() {
      if (xmlHttp.readyState == 4) {
          alert(xmlHttp.responseText);
          parser = new DOMParser();
          var xmlDoc = parser.parseFromString(xmlHttp.responseText, "text/xml");
  
          alert(xmlDoc.documentElement.childNodes[1].tagName + " " + xmlDoc.documentElement.childNodes[1].childNodes[0].nodeValue);
          //alert(xmlDoc.documentElement.childNodes[1].childNodes.length);
          //alert(xmlDoc.documentElement.childNodes[1].hasChildNodes());
          //alert(xmlDoc.documentElement.childNodes[2].hasChildNodes());
          //alert(xmlDoc.documentElement.childNodes[2].tagName + " " + xmlDoc.documentElement.childNodes[2].childNodes[0].nodeValue);
          alert(xmlDoc.documentElement.childNodes[3].tagName + " " + xmlDoc.documentElement.childNodes[3].childNodes[0].nodeValue);
          alert(xmlDoc.documentElement.childNodes[5].tagName + " " + xmlDoc.documentElement.childNodes[5].childNodes[0].nodeValue);
  
          alert(xmlDoc.documentElement.childNodes.length);
      }
  

  Web service

  using System;
  using System.Collections.Generic;
  using System.Linq;
  using System.Web;
  using System.Web.Services;
  using System.Xml.Serialization;
  
  namespace WebService1
  {
      /// 
  
      /// Summary description for Service1
      /// 
      [WebService(Namespace = "http://tempuri.org/")]
      [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)]
      [System.ComponentModel.ToolboxItem(false)]
      // To allow this Web Service to be called from script, using ASP.NET AJAX, uncomment the following line.
       [System.Web.Script.Services.ScriptService]
      public class Service1 : System.Web.Services.WebService
      {
  
          [WebMethod]
          public string HelloWorld()
          {
              return "Hello World";
          }
  
          [WebMethod]
          public myTestObj HelloWorld2()
          {
              myTestObj test = new myTestObj();
              return test;
          }
      }
  
      [Serializable]
      public class myTestObj
      {
          private int _StationID;
          private string _StationName;
          private double _Volume;
  
          [XmlElementAttribute(Order = 0)]
          public int StationID
          {
              get
              {
                  return this._StationID;
              }
              set
              {
                  this._StationID = value;
              }
          }
  
          [XmlElementAttribute(Order = 1)]
          public string StationName
          {
              get
              {
                  return this._StationName;
              }
              set
              {
                  this._StationName = value;
              }
          }
  
          [XmlElementAttribute(Order = 2)]
          public double Volume
          {
              get
              {
                  return this._Volume;
              }
              set
              {
                  this._Volume = value;
              }
          }
  
          public myTestObj()
          {
              StationID = 1000;
              StationName = "Test Station";
              Volume = 105.285;
          }
      }
  }
  

  > Any ideas on why or how? I feel I'm missing just a simple thing in all of this.

  White space nodes?

• Best way to Parse XML using Dreamweaver CC 2015.3

  I was on a wild goose chase - trying to figure out how to parse XML using DW CC

  every article I read, says something about XML & XSLT, but it is no longer available in the new CC - I read about using jQuery or php, but have not yet find a resource to learn specifically "using DW CC.

  I'm willing to learn how to parse XML with DW CC but I would get a definitive direction to go before I'm trying to learn something that adobe will put in 'end of life '.

  advice or links to resources that can parse XML DW CC 2015 would be LARGELY APPRECIATED, thank you

  x 126 has written:

  What I'm asking is...

  1. What is the best procedure to insert XML into a page using DW CC 2015 as my editor?
  a. what happened to spry? b. what happened to XSLT?

  As Nancy explained, Spry has been abandoned by Adobe, a few years ago.

  XSLT server behavior has been removed at the same time as other server behaviors Dreamweaver CC. The problem with most of the PHP server behaviors was that they were based on code that has been removed from PHP 7. The XSLT server behavior didn't rely on these features, but it was not the most friendly of server behaviors. XSLT is a complex language that is to be avoided when parsing XML unless you really know what you're doing.

  The easiest way to manipulate XML in Dreamweaver should use PHP SimpleXML. I've linked to the samples page in the PHP online documentation. Believe me, it's much easier than trying to do battle with XSLT. If you have a subscription to lynda.com, you can learn more about SimpleXML to my operational with SimpleXMLclass.

• Err: ORA-31011: failed to parse XML

  Hello
  
  While inserting the XML code in the table, I faced slot problem, Pls suggest a way out of the code.
  Your help is appreciate.
  I'm using the version of Oracle - 10.2.0.2.0
  
  Err: ORA-31011: failed to parse XML
  ORA-19202: an error has occurred in the processing of XML
  LPX-00234: the 'xsi' namespace prefix is not declared
  Error on line 1
  ORA-06512: at "SYS." XMLTYPE", line 254
  ORA-06512: at line 1
  
  -Step 1
  CREATE TABLE EMP (EMPCODE NUMBER (8), EMPNAME VARCHAR2 (100), THE NUMBER OF EMPDEPTNO (8), NUMBER EMPSAL (34.2));
  /
  -Step 2
  BEGIN
  FOR X IN (SELECT * FROM USER_OBJECTS S WHERE ROWNUM < = 50)
  LOOP
  INSERT INTO VALUES EMP (X.OBJECT_ID, X.OBJECT_NAME, 20, X.OBJECT_ID + 10);
  END LOOP;
  COMMIT;
  END;
  /
  -Step 3
  create the table EMPXML (XMLCLOB XMLTYPE);
  /
  -Step 4
  DECLARE
  v_xmldata CLOB.
  v_tmpdata CLOB.
  v_xmltype XMLTYPE.
  BEGIN
  DBMS_LOB.CREATETEMPORARY (v_tmpdata, false);
  v_xmldata: = ' <? XML version = "1.0" encoding = "UTF-8"? > ';
  
  SELECT Xmlelement ("employee",
  
  XmlAttributes ("http://ns.oracle.com.tw/XSD/ORACLE/ESB/Message/EMF/ServiceEnvelope" xmlns: xsi = "http://www.w3.org/2001/XMLSchema-instance" AS ")
  "xmlns:ns0,"
  ' http://ns.oracle.com.tw/XSD/ORACLE/ESB/Message/EMF/ServiceEnvelope ServiceEnvelope.xsd > ' AS
  ("xsi: schemaLocation").
  XMLAGG (Xmlforest (AS Empcode "EmpID",
  EmpName AS "EmpName",.
  Empsal AS 'EmpSal'))) BY v_xmltype
  FROM Emp
  WHERE Empdeptno = 20;
  
  SELECT v_xmltype.getCLOBVal () IN the v_tmpdata FROM dual;
  
  DBMS_LOB. Append (v_xmldata, v_tmpdata);
  
  BEGIN
  INSERT IN EMPXML VALUES (xmltype (v_xmldata));
  EXCEPTION WHEN OTHERS THEN
  dbms_output.put_line ('Err: ' |) SQLERRM);
  END;
  END;
  /
  -Step 5
  SELECT * from empxml;
  /
  -Step 6
  DROP TABLE EMP PURGE;
  /
  -Step 7
  DROP TABLE EMPXML PURGE;
  /
  Thank you and best regards,
  Yogesh Nagle
  India

  What? Pepijn you provided the correct use of Xmlattributes and showed that your script would go without errors. What is the problem with his answer or it does not that you need it?

• parse xml timestamp labview in javascript

  Hi, im reading XML files created from labview7.1 with javascript and it works fine, the only problem is that I don't know how to parse the timestamp. For DS

  ...

  
  Date of Eximination
  
  
  4
  
  
  0
  
  
  
  0
  
  
  
  -916291696
  
  
  
  0
  
  
  

  ...

  should be the date of 2011-01-24 and

  ...

  
  Date of Eximination
  
  
  4
  
  
  0
  
  
  
  0
  
  
  
  -916205296
  
  
  
  0
  
  
  

  ...

  2011-01-25 indices?

  It seems to work

• Problem of Parsing XML

  Hi all

  I have a XML Data...

  As

  I want to get the name of node and its values...

  But I'm not able to analyze and get access those.

  I tried using DOM parser.

  Everyone please help.

  Thanks and greetings

  Stephenson

  Similar to what manojkbaghela wrote:

  DocumentBuilderFactory docFact = DocumentBuilderFactory.newInstance ();
  DocumentBuilder docBuilder = docFact.newDocumentBuilder ();

  Doc document = docBuilder.parse ({inputSource file});
  doc.getDocumentElement () .normalize ();
  NodeList listOfRecords = doc.getElementsByTagName ("node");
  int totalElements = listOfRecords.getLength ();

  for (int s = 0; s< totalelements;="" s++)="">

  Element myElement = listOfRecords.item (s) (element);

  LinkID = myElement.getAttribute ("LinkID") string;
  String subject = myElement.getAttribute ("Topic");
  Position of the string = myElement.getAttribute ("heading");

  }

• problem in parsing xml with validation

  Hello

  I use webservice and xml parsing allows to get data from it, he worked successfully when I put data valid that webservice are made up.

  But now, I want that if I put some data not valid in URLs for validation purposes.

  When I put the wrong data, it shows me exception. So, how I can handle it when the user put data not valid.

  Please help me .it's urgent.

  Thanks for the reply,

  I solved it myself.

• What happens to parsing xml?

  Hello

  I haven't checked the front for bb xml parsers and now I need to analyze a simple file, smth like:

  So, it's pretty simple. can anyone suggest me which library should I use and what start?

  concerning

  Hello, you need to use DocumentBuilderFactory:

  public class XmlReader {
  
    private static String XML_FILE = "your/xml/file/name.xml";
  
    public XmlReader() {     DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();    DocumentBuilder builder = factory.newDocumentBuilder();    InputStream inputStream = getClass().getResourceAsStream( XML_FILE);    Document document = builder.parse( inputStream );
  
      Element rootElement = document.getDocumentElement();    rootElement.normalize();
  
      Object yourObject = parse(rootElement);  }   ...  private Object parse(Node node) {....} }
  

  in the parse method (node), you use node.getChildNodes () to travel through the child of the node and create your object of the desired type, or you can view the items on the screen... This is only a sample of shortcuts, you should really look into the Blackberry JDE samples, xmldemo, located in \samples\com\rim\samples\device\xmldemo in the home directory of BlackBerry, there is nothing difficult

• Parsing XML from a Variable String

  I looked at the docs and spending the afternoon at the research on the web and can't understand this.  It's a question of combination SAX parser and java.io.  The SAX parser will be an InputStream or an InputSource, but I can't seem to find a way to transform a string containing the XML to one of them to move to the parser.  Someone knows how to do this?

  TIA,

  Allen

  Never mind!  I finally found it:

  String xml;
  ByteArrayInputStream ba= new ByteArrayInputStream(xml.getBytes());
  

  Thanks for watching!

  Allen

• Problem with parsing XML with html as part of the node content

  Hi all

  I am facing problem with XML parsin when the node has a HTML content, if the node does not have any html content then it works fine. Similar analysis logic works for Java Standard, but not for the Blackberry API. I have an obligation to remove not HTML content prior to analysis. As that would display in the browser.

                            String xml="" +
                  "<p> Dummy content </p> " +
                  "" +
                  "";
                            DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
              DocumentBuilder dBuilder;
              Document doc;
              bis = new ByteArrayInputStream(xml.getBytes("UTF-8")); 
  
              dBuilder = dbFactory.newDocumentBuilder();
  
              doc = dBuilder.parse(bis);
              doc.getDocumentElement().normalize();
  
              NodeList nList = doc.getElementsByTagName("disclaimer");
  
              Element activeTagElmnt = (Element) nList.item(0);
              NodeList activeTag = activeTagElmnt.getChildNodes(); 
  
              tagValue=((Node) activeTag.item(0)).getNodeValue();
                            System.out.println(tagValue); //This prints "<" with HTML content. If i remove HTML then "Dummy Content" is printed
  

  If I need to remove html content, then I would need to reformat the content according to the HTML as the newline to a linebreak.

  Any suggestions would be helpful.

  Thank you

  Sandeep

  I feel xml parser was mature enough to handle these characters if sills, you get the error explore CDATA. It might help you.

• Parsing XML in a string with kXML

  Hello

  I make a web service call that returns the XML in a string. I need to analyze this with kXML. The Setup is complete, but I can't find any help with regard to the analysis of the chain.

  Any help?

  Thank you

  Teja.

  Have you tried that?

   try{
              HttpConnection connection = null;
              InputStream inputStream = null;
  
              connection = (HttpConnection) Connector.open(URL + MainUI.connectionParameters,Connector.READ_WRITE, true);
              inputStream = connection.openInputStream();
  
              DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
              DocumentBuilder builder = factory.newDocumentBuilder();
              Document document = builder.parse( inputStream );
  
              Element rootElement = document.getDocumentElement();
              rootElement.normalize();
              displayNode( rootElement, 0 );
          }
          catch ( Exception e )
          {
              System.out.println( e.toString() );
          }
  

  private void displayNode( Node node, int depth )
      {        
  
          if ( node.getNodeType() == Node.ELEMENT_NODE )
          {
              StringBuffer buffer = new StringBuffer();
              //indentStringBuffer( buffer, depth );
              NodeList childNodes = node.getChildNodes();
              int numChildren = childNodes.getLength();
              Node firstChild = childNodes.item( 0 );
  
              // If the node has only one child and that child is a Text node, then it's of
              // the form  Text, so print 'Element = "Text"'.
  
  if ( numChildren == 1 && firstChild.getNodeType() == Node.TEXT_NODE )
              {
  
                          buffer.append( firstChild.getNodeValue() );
                          buffer.append( "\n" );
                          add( new RichTextField( buffer.toString() ));
                          add( new SeparatorField());
  
              }
              else
              {
  
                  parentName = node.getNodeName();
  
                  for ( int i = 0; i < numChildren; ++i )
                  {
                      displayNode( childNodes.item( i ), depth + 1 );
                  }
              }
          }
          else
          {
  
              String nodeValue = node.getNodeValue();
              if ( nodeValue.trim().length() != 0 )
              {
                  StringBuffer buffer = new StringBuffer();
                  indentStringBuffer( buffer, depth );
                  buffer.append( '"' ).append( nodeValue ).append( '"' );
                  add( new RichTextField( buffer.toString() ));
              }
          }
      }
  

• Help parsing XML (XMLParseDemo.java)

  Hello world

  I'm trying to parse the XML code in my application. Here's a sample of what I'm trying to analyze:

  
  
    http://api.netflix.com/catalog/titles/autocomplete?{-join|&|term}
    
      
    
    
      
    
    
      
    
    
      
    
  
  

  For the parser, I use the XMLDemoScreen.java that is provided in the JDE samples. What I'm trying to do is to analyze all of the

• parsing xml in blackberry jde 5.0

  Hi, I was wondering if someone could help me to analyze an XML file from a server in the channels that I can use. I'm trying to access the data are under the "ResponseChoices" tag in the following fragment:

  It is a question, nothing to do with the BlackBerry in particular generic analysis of XML. Your code does not work because it is not navigate the DOM correctly. For the XML file that you posted, x.item (0) is an element corresponding to the tag. This element has two child elements corresponding to the tags. (It can have children for the white spaces as well, depending on the configuration of the parser, it is better to browse children or reuse getElementsByTagName.) The child element for each tag has, in turn, a child of text that contains the value you want.

  So maybe a way to do this:

  NodeList x = messageElements[i].getElementsByTagName("String");
  int n = x.length();
  String[] choices = new String[n];
  for (int i = 0; i < n; ++i) {
      choices[i] = x.item(i).getFirstChild().getNodeValue();
  }
  

  If you have tags in other places, so you can first get each ResponseChoices node, cast to an element and call the getElementsByTagName method to obtain that these tags that fall under it.