partition in maintained growth index, partition of table didn't need to add space.

Similar Questions

• maintain the index ID between files

  Is it possible to copy a table from one file to the other and maintain the indexes on this table id?

  Mike

  In theory, no. The index seems to be the nth number of tables, where the first in your document is always 0 #, the #1 second and so on. If you copy the #1 table in another document where it is the first, its index is simply to '0'.

  But all is not lost. If you need to find a table that you have created or copied previously, you can assign a unique label instead. How you would prevent the addition of a new table with the same label to your document depends entirely on where they come from (all the same document? from different documents?) and, more importantly, what your intention is.

• What happens to the existing after the partition of table index and created with local index

  Hi guys,.

  / / DESC part id name number, varchar2 (100), number of wage

  In an existing table PART I add 1 column DATASEQ MORE. I wonder the part of table based on dataseq.now, the table is created with this logic of partition

  create the part table partition (identification number, name varchar2 (100), number of salary, number DATASEQ) in list (dataseq) (values partition PART_INITIAL (1));

  Suggestionn necessary. given that the table is partitioned based on DATASEQ I wonder to add local indexes on dataseq. to dataseq, I have added a local index create index idx on share (dataseq) LOCAL; Now my question is, already, there are the existing index is the column ID and salary.

  (1) IDX for dataseq is created locally so that it will be partition on each partition on the main table. Please tell me what is happening to the index on the column ID and salary... it will create again in local?

  Please suggest

  S

  Hello

  first of all, in reality 'a partition table' means create a new table a migration of existing data it (although, theoretically, you can use dbms_redefinition to partition an existing table - however, it's just doing the same thing behind the scenes). This means that you also get to decide what to do with the index - index will be local, who will be global (you can also reassess some of existing indexes and decide that they are not really necessary).

  Second of all, the choice of the partitioning key seems weird. Partitioning is a data management technique more that anything else, in order to be eligible, you must find a good partitioning key. A column recently added, named "data_seq" is not a good candidate. Can you give us more details about this column and why it was chosen as a partitioning key?

  I suspect that the person who proposed this partitioning scheme made a huge mistake. A non-partitioned table is much better in all aspects (including the ease of management and performance) that divided one wrongly.

  Best regards

  Nikolai

• Partitioning of Tables/indexes

  Hello
  
  Oracle Version 10.2.0
  O/s Version: SUSE Linux
  
  Currently, all tables and indexes are stored in the ponit of NFS mounting. I would like to know if I can partition the tables/indexes on local storage temporarily.
  
  Thank you

  Hello
  Yes you can do it. But if you have a few scores on NAS and others on the local drive, then depending on the nature of the query/DML you will see some performance issues.

  MSK

• need help to determine the type of partition for tables

  Hello
  
  I have a few tables that have millions of record. In some tables, we have data from previous years, that we do not now use. Can we create a partition of this type of tables table.
  
  On other tables, how to decide if you should use the range/list/hash partitioning on our tables.
  
  Do I need to recreate indexes for the tables after you create the partition tables.
  
  Please guide me.
  
  Best regards

  Partitioning of decisions are based on how you can access data.

  If you access date then partition by date.
  If you go through a list of values and then use the list.
  If you there is no model and you just need to break the data up into smaller compartments using hash.

  I don't see why, based on what you wrote, partitioning by date range would be not worthy of consideration.

• Dynamically partition a table based on different values of a specific column: possible?

  I'll start by explaining my problem, so that you can have a global vision of the problem and perhaps suggest another solution. Problem: I have 2 tables with millions of records. Records are added daily, and so each row in each table has a column of "insertion_date".

  C1 C2 ... C10 insertion_date (type date, ofc)
  

  lines are cleaned according to the insertion_date parameter. This can happen in two ways:

  1 - whenever an application error appears. In this case delete is based on a single day and would be like:

  delete from T1 where insertion_date=##;
  

  in other words remove us the lines added and then restart the program (business logic, can't change it)

  2. every two weeks the data associated with these two weeks are deleted because will be most used:

  delete from T1 where insertion_date between ## and ##; (a two weeks period here)   
  

  Delete is currently very slow: it takes abot 8 minutes just to remove approximately 5 M of records (with the same insertion_date), I can't even imagine the time required to delete records more.

  So, here's my idea!

  I would partition my DB according to the value of insertion_date.

  To remove case 1 I would simply delete the partion associated with this insertion date, to remove scores of cases 2 associates at that interval.

  For the needs of my application at most 15 were leaving are present each time (maybe 20 if I want to keep last at least 5 days of data), so the documented limit of 64000 partitions is not a problem.

  Real problem is that I do not know insertion_date values in advance, so my question: is it possible to automatically create a new partition every time presents itself a new value of insertion_date?

  And please correct me if I'm wrong, if I accomplish partitioning that I wouldn't need to edit above right queries? I know just the faster removal time am I correct?

  No - it isn't bog standard range partitioning partitioning interval

  But perhaps you're citing 9i documentation for a reason?

  It is a feature of 11g... then only about 10 years.

  create table t1
  (col1  date)
  partition by range (col1) interval (numtodsinterval(1,'DAY'))
  (partition po values less than (to_date('01-01-2015','DD-MM-YYYY')));
  
  table T1 created.
  
  select table_name, partition_name, high_value from user_tab_partitions where table_name = 'T1';
  
  TABLE_NAME                     PARTITION_NAME                 HIGH_VALUE
  ------------------------------ ------------------------------ --------------------------------------------------------------------------------
  T1                             PO                             TO_DATE(' 2015-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA...'
  
  insert into t1
  select trunc(sysdate,'MM')+rownum-1
  from   dual
  connect by  rownum <= 10;
  
  select table_name, partition_name, high_value from user_tab_partitions where table_name = 'T1';
  
  TABLE_NAME                     PARTITION_NAME                 HIGH_VALUE
  ------------------------------ ------------------------------ --------------------------------------------------------------------------------
  T1                             PO                             TO_DATE(' 2015-01-01 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA...'
  T1                             SYS_P450383                    TO_DATE(' 2015-07-02 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA...'
  T1                             SYS_P450384                    TO_DATE(' 2015-07-03 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450385                    TO_DATE(' 2015-07-04 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450386                    TO_DATE(' 2015-07-05 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450387                    TO_DATE(' 2015-07-06 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450388                    TO_DATE(' 2015-07-07 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450389                    TO_DATE(' 2015-07-08 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450390                    TO_DATE(' 2015-07-09 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450391                    TO_DATE(' 2015-07-10 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  T1                             SYS_P450392                    TO_DATE(' 2015-07-11 00:00:00', 'SYYYY-MM-DD HH24:MI:SS', 'NLS_CALENDAR=GREGORIA ...'
  

• Table partitioning on table MTL_SYSTEM_ITEMS_B?

  Hello
  
  We have an obligation to apply the partitioning on table MTL_SYSTEM_ITEMS_B. main reason is to improve the performance of queries.
  
  We planned to do with ORGANIZATION_ID column as the partition key.
  
  If anyone can share with your thoughts, what method of partition is good at this table to improve performance.
  
  Thank you

  Hello

  Please see these links/docs.

  Using partitioning of database with the E-Business Suite
  http://blogs.Oracle.com/stevenChan/2006/09/using_database_partitioning_wi.html

  Updated whitepaper: database, partitioning for E-Business Suite
  http://blogs.Oracle.com/stevenChan/2009/04/whitepaper_update_database_partitioning_for_ebusin.html

  Note: 554539.1 - database using partitioning with Oracle E-Business Suite

  Thank you
  Hussein

• Shrinking Bootcamp partition and add space for Macintosh HD

  Guys, after helping me with my previous question, my Macbook is almost as I want it to be. As said, I have a Macbook Pro 15 "retina end 2013 with OS X El Captain (later) and in addition, a Bootcamp with Windows partition 8.1." It's that everything works fine now, but the partition Windows 8.1 has 300 GB and my score only 80 GB hard drive Macintosh.

  I wanted to shrink the partition, Bootcamp in Windows 8, 1 with Minitool Partition software but, obviously, when I reduce this score I get unallocated space that I can't turn into a new partition because I have 4 partitions in the MBR slot. So, what is the best way to reduce my Bootcamp partition and add space on the Macintosh HD partition?

  Thank you very much!

  Remove the Boot Camp partition, and Windows using Boot Camp Assistant. Then start to affect the size of the Boot Camp partition you want.

• 'For' loop with a different number of iterations. Second, the auto-indexation of the tables with different sizes is done. It can affect the performance of the Vi?

  Hello

  I have a loop 'for' which can take different number of iterations according to the number of measures that the user wants to do.

  Inside this loop, I'm auto-indexation four different 1 d arrays. This means that the size of the tables will be different in the different phases of the execution of the program (the size will equal the number of measures).

  My question is: the auto-indexation of the tables with different sizes will affect the performance of the program? I think it slows down my Vi...

  Thank you very much.

  My first thought is that the compiler to the LabVIEW actually removes the Matlab node because the outputs are not used.  Once you son upward, LabVIEW must then call Matlab and wait for it to run.  I know from experience, the call of Matlab to run the script is SLOW.  I also recommend to do the math in native LabVIEW.

• get the index of a table display

  Hello!

  I have a question. Is it possible to get the index of a current table in the front panel?

  I have 2 tables which need to scrool simultaneously to the user, so my idea was to read the index of a table and 'write' on the second.

  Can someone give me an idea how to do that?

  Thank you

  Dear Thiago Bach,

  recently, I did (for a similar question) an example on the control to the index of the two tables and bar a scroll, please find the attached VI.

  Good luck!

• Need to consolidate space unallocated on my Vista laptop and extended partitions

  There are 4 partitions on my laptop Lenovo w/Vista. They are the main with the system OS etc. files partition, then an extended 9.7 GB partition labeled volume D: 98 GB of unallocated space and then finally the OEM with the recovery image section. I want to create a partition that is important as the C: volume with all that on it. The only other partition would be the volume of the OEM. Now when I try to use the unallocated space (create a simple volume with quick format) it says the operation cannot be completed because there is not enough space on the hard drive; that cannot be true because the unallocated space is 98 GB +. I got the OS to the factory setting thinking that it would be re - format the hard disk for the installation of 2 original score. No luck. I need help! We cannot add a lot of apps of software in the form of program files before the C: drive runs out of space. Help!

  Do NOT post the same question in 2 different Forums.

  http://www-307.IBM.com/PC/support/site.WSS/homeLenovo.do

  As you have problems with the recovery media from Lenovo not putting this back to factory settings as it should with 2 Partitions, connect with Lenovo.

  This isn't their recovery process, Microsoft.

  See you soon.

  Mick Murphy - Microsoft partner

• Creating indexes for the table

  can someone help me how to create indexes in the table. I m creating own table... I need to select a particular field in the table. So I need to calculate the index position. I use my code like this,

  This will returnthe number of columns in the table.

  Class array

  {

  private int Table_Index()
  {
  for (int x = 0; x)<>
  {
  table_index = x;
  }
  Return table_index;
  }

  }

  MainClass can I get this length of Index

  Table T1;

  int t1 is T1. Table_Index();

  This property returns my length (4) of table column

  Using this index (t1) I HAV to see what position I'm at table now...

  someone help me...

  You can use a listfield, he supports methods to get the selected row and its contents.

• Why I can't create indexes on the table of RDF data

  When I tried to create indexes on the table of RDF data, it always say the table or view does not exist. I created the RDF model using java codes:

  Oracle Oracle = new Oracle ("jdbc:oracle:thin:@localhost:1521:orcl", "system", "123");

  Chart GraphOracleSem = new GraphOracleSem (oracle, "test2");

  
  

  And used the following commands in sqlplus to create indexes:

  SQL >

  SELECT THE SEPARATE OWNER, OBJECT_NAME

  FROM DBA_OBJECTS

  WHERE TYPE_OBJET = 'TABLE '.

  4. AND OBJECT_NAME like ' % TEST2;

  OWNER

  --------------------------------------------------------------------------------

  OBJECT_NAME

  --------------------------------------------------------------------------------

  SYSTEM

  TEST2_NS

  SYSTEM

  RDFB_TEST2

  SYSTEM

  TEST2_TPL

  OWNER

  --------------------------------------------------------------------------------

  OBJECT_NAME

  --------------------------------------------------------------------------------

  SYSTEM

  RDFC_TEST2

  
  

  SQL > connect as sysdba

  Enter the password:

  Connected.

  SQL >

  SQL >

  SQL > select * from TEST2_TPL;

  Select * from TEST2_TPL

  *

  ERROR on line 1:

  ORA-00942: table or view does not exist

  SQL > CREATE INDEX test2_sub_idx ON TEST2_TPL (triple. GET_SUBJECT());

  CREATE INDEX test2_sub_idx ON TEST2_TPL (triple. GET_SUBJECT())

  *

  ERROR on line 1:

  ORA-00942: table or view does not exist

  Hi Shifu,

  It is not recommended to use the SYS or SYSTEM to store/manage schema graph RDF data.

  Can you please try the following in a SQL * more terminal?

  SQL > conn system/eu1

  Connected.

  SQL >

  SQL >

  SQL > create user graphuser identified by graphuser;

  Created by the user.

  SQL > grant connect, resources, unlimited tablespace to graphuser;

  Grant succeeded.

  SQL > conn graphuser/graphuser

  Connected.

  SQL > create table graph_tpl (triple sdo_rdf_triple_s) compress;

  Table created.

  SQL > sem_apis.create_sem_model exec ('graphic', 'graph_tpl', 'three');

  PL/SQL procedure successfully completed.

  SQL > insert into graph_tpl values (sdo_rdf_triple_s ('graph', '', '', ''));

  1 line of creation.

  SQL > select count (1) in the mdsys.rdfm_graph;

  1

  You see the same result?

  Thank you

  Zhe Wu

• indexes on a table

  Hello experts. I was told that I need to add indexes to my table, even if I'm just doing a select * from tbl_one. The index is actually justified in this case

  Hello

  user13328581 wrote:

  Hello experts. I was told that I need to add indexes to my table, even if I'm just doing a select * from tbl_one. The index is actually justified in this case

  No, if

  Select *.

  of tbl_one;

  is exactly what you do, then any index on tbl_one will do everything (faster or slower).

  If you have a WHERE clause, or an ORDER BY clause, or join you, or only some of the columns, then it's another story.

  Ask the one who told you to explain.  Maybe you didn't understand what you were told correctly.

• How to create faster index in the table of 500 GB

  Dear Experts,

  I have to create 20 index on table data-ware house. This table is of size 500 GB.

  freshen up this weekly chart using the external table.

  creating 20 indexes on this table consumes a lot of time.

  I have 40 GB of ram on 2012 box windows with 8 processors.

  I installed 11 GR 2.

  I have 4 drives C D E F

  for AN index, it takes 4 hours

  
  

  I added enough space to the tablespace

  I put the tablespace in a drive D:\
  

  
  

  I'm under control to create indexes below

  create index  X_3_INVEN_ITEM_ID_IDX  on   X_3_PV_TD_2 (INVENTORY_ITEM_ID)  parallel 32 nologging;
  
  

  output long ops

  SID, SERIAL # CONTEXT SOFAR TOTALWORK LESS TARGET % _COMPLETE TIME_REMAINING

  ---------- ---------- ---------- ---------- ---------- ---------------------------------------------------------------- ---------------------------------------------------------------- ---------- --------------

  108 10 0 3758 140973 Rowid Scan AD range. X_3_PV_TD_2                                    2.67            256

  173 23 0 5279 141470 Rowid Scan AD range. X_3_PV_TD_2                                    3.73            258

  114 6 0 10092 141786 Rowid Scan AD range. X_3_PV_TD_2                                    7.12            261

  99         59          0      46283     325908 Sort Output                                                                                                                     14.2          15207

  68        214          0      46763     323623 Sort Output                                                                                                                    14.45          14973

  35         93          0      47531     318364 Sort Output                                                                                                                    14.93          14570

  164         70          0      45058     288506 Sort Output                                                                                                                    15.62          12886

  227         31          0      44130     282285 Sort Output                                                                                                                    15.63          13011

  13          3          0      51890     309515 Sort Output                                                                                                                    16.76          12874

  222 67 0 28837 141380 Rowid Scan AD range. X_3_PV_TD_2                                    20.4            343

  73 37 0 32472 141488 Rowid Scan AD range. X_3_PV_TD_2 22.95 212

  47 8 0 34332 141154 Rowid Scan AD range. X_3_PV_TD_2 24,32 202

  176 20 0 35197 141161 Rowid Scan AD range. X_3_PV_TD_2 24.93 205

  19 7 0 35239 141325 Rowid Scan AD range. X_3_PV_TD_2 24.93 205

  80 4 0 40399 141611 Rowid Scan AD range. X_3_PV_TD_2 28,53 193

  144 20 0 44960 141481 Rowid Scan AD range. X_3_PV_TD_2 31,78 182

  233 101 0 74086 169228 Rowid Scan AD range. X_3_PV_TD_2 43,78 176

  128 165 0 78765 141436 Rowid Scan AD range. X_3_PV_TD_2 55.69 173

  235 1 0 41199796 70035728 table Scan AD. X_3_PV_TD_2 58,83 19804

  199 6 0 52748651 70035728 table Scan AD. X_3_PV_TD_2 75,32-9709

  44 2 0 53686039 70035728 table Scan AD. X_3_PV_TD_2 76,66 9022

  204 26 0 119969 141464 Rowid Scan AD range. X_3_PV_TD_2                                   84.81             40

  202 48 0 138880 162276 Rowid Scan AD range. X_3_PV_TD_2                                   85.58             43

  17 33 0 126506 141778 Rowid Scan AD range. X_3_PV_TD_2                                   89.23             28

  48 7 0 137772 141360 Rowid Scan AD range. X_3_PV_TD_2                                   97.46             15

  Temp tablespace

  
  

  USED_MB USED TOT_MB % NOM_TABLESPACE

  ------------------------------ ---------- ---------- ----------
TEMP 11533 286719 4.02

  temporary tables

  OWNER SEGMENT_NAME SEGMENT_TY TABLESPACE_NAME EXTENTS BYTES_
---------- ------------------------------ ---------- -------------------- ---------- ---------------
AD 156.1601650 TEMPORARY USERS 96 209,715,200

  Question:

  How to fix this?

  (a) run several parallel create sqlplus statement index different sessions

  (b) create a tablespace to put data files in different hard drives like D: E: F: C:

  (c) create the separate tablespace for each hard drive and map it to a single disk IO benefit

  (d) I have 8 processors but parallel 32 is not speed

  (e) how these clues I can run in parallel. Is it OK to run 20 parallel index 32 sqlplus sessions

  All that I have to create 20 index on the table of 500 GB

  target memory = 30GB

  index of names to create 20, each index is 10 GB

  his is of 80 hours (4 hours per index)

  This machine is waiting, I just used all the resources of the machine to accelerate.

  Thanks for reading this

  Thanks for the help in advance

  I was talking about your end of issue speed up construction of index, where I proposed

  orclz >

  orclz > alter session set workarea_size_policy = manual;

  Modified session.

  orclz > alter session set sort_area_size = 2147483647;

  Modified session.

  orclz > create index

  Post edited by: JohnWatson

  Sorry, I misread it: this question was not from you. My apologies. My solution should work for you, however: give yourself a big PGA, manually. Automatic PGA management using not will never give you enough.