Path of the hyperlink file includes a '&' sign

Similar Questions

• I can't export my files (raw, jpg, tiff, any). always a notification "the path of the exported file cannot contain special symbol '='. ' is displayed. Why? I don't know what is the path to the file. at least, file name is not special symbol.

  I can't export my files (raw, jpg, tiff, any). always a notification "the path of the exported file cannot contain special symbol '='. ' is displayed. Why? I don't know what is the path to the file. at least, file name is not special symbol.

  The path of the file is the full description where the file is located in the language of the operating system, including drive, directory and file name and extension.

  

  In the above example, the file path combines the two circled items-"E:\Webpix" and "BleedingHeart.JPG", the path to the file would be "E:\Webpix\BleedingHeart.JPG".  If you do not have an equal sign in the name of the file, you must have one in the folder or the equivalent.

• create a tablespace without specifying the path to the data file and the name

  Hello
  
  Is it possible to create a tablespace without specifying the name and the path of the data file.
  
  For example: just specify the name of the tablespace and the size of the data file, the data file must be created in a default location with the default name? Is this possible?

  user13364377 wrote:
  Hello

  Is it possible to create a tablespace without specifying the name and the path of the data file.

  For example: just specify the name of the tablespace and the size of the data file, the data file must be created in a default location with the default name? Is this possible?

  The use of the files managed by Oracle
  Internally, Oracle uses standard file system interfaces to create and delete files if necessary for the following data structures:

  * Tablespaces
  * Online redo logs
  * Control of files

  Through initialization parameters, you specify the directory of file system to use for a particular file type.
  EXAMPLE:
  The following parameters are included in the initialization parameter file:

  DB_CREATE_FILE_DEST = ' / u01/oradata/sample.
  DB_CREATE_ONLINE_LOG_DEST_1 = "/ u02/oradata/sample.
  DB_CREATE_ONLINE_LOG_DEST_2 = ' / u03/oradata/sample.

  The following statement is issued at the SQL prompt:

  SQL > CREATE a DATABASE sample.
  SQL > CREATE TABLESPACE tbs_2 DATAFILE SIZE 400 M;
  SQL > CREATE UNDO TABLESPACE undotbs_1;

  check the link for more information:
  http://download.Oracle.com/docs/CD/B10500_01/server.920/a96521/OMF.htm

• How to find the path to the project file programmatically

  I'm trying to find a way to get the path to the project file in the development environment.

  I have attached a small project in LV 8.5.1 with a project file, a library file and the VI. I can get the path to the file library, but not to the project. This channel is still .

  I know that the problem exists in LV 8.6.1f1 but I didn't test in LV 2009.

  I am aware that in reality he could there have more nested levels of the library files, but it doesn't matter when this simple example does not work.

  If this is related to the problem I initially created the library by using the file > new... and later, I created the project and added to the library.

  Hi Waldemar,

  Here is a small piece of code and a related link.

  http://forums.NI.com/NI/board/message?board.ID=170&message.ID=220269&requireLogin=false

  I hope this helps.

  Kind regards

  N. Ralf

  Engineering applications

  OR Germany

  PS: Don't forget the congratulations. )))))

• path of the audio file

  Hello world

  I use the path of the sound file to play with play Sounf File.vi.

  I select the file again every time I got close and open labview.

  Any suggestions as to how I can make it permanent?

  Thank you.

  Two things to do

  (1) front panel right-click on the control and select data operations-> are by default of the current value, then save

  (2) in the block diagram right-click and select replace by, constant, then save

• BACKUP QUESTION: Why is it when I backup the Lightroom Catalog (Edit |) Settings of catalog...) only the *.lrcat file included in the ZIP file... While the *., lrdata file, the preview files, ARE NOT INCLUDED?  When I restore the file *.lrcat from a backu

  BACKUP QUESTION: why is it that when I backup the Lightroom Catalog (Edit |) Settings of catalog...) only the *.lrcat file included in the ZIP file... While the *., lrdata file, the preview files, ARE NOT INCLUDED?  When I restore the *.lrcat file from a backup, WHERE ARE THE PREVIEW FILES that should be included in the ZIP to the top.  If *.lrdata (Preview file) are so important, why are not included in the zip?  [email protected]

  CraigLevine wrote:

  OK, so that's my scenario:

  • QUESTION: WHEN I USE THE [Sub-master] .lrcat, on the new computer, don't need to inculde also files .lrdata [Sub-master] on this external drive?
  • If .lrdata [Sub-master] is regenerated automatically, where he gets all the work (from the preview files) that I did, when I was working, using the .lrdata [Sub-master] when he was on the local disk.

  Thanks again for staying with me on this.  I don't know that your answer will solve my confusion. -Craig

  [email protected]

  Questions 1)

  Not because the LRDATA file is fair previews, what LR displays on your screen for a faster loading of the image and will be recreated. The previews only stored in the folder LRDATA is the basic overview created at time of importation for the display of thumbnails and previews of 1:1 for images that you have actually looked in the Loupe View or I guess that appears in the develop module.

  He get all the data to create the image themselves file extracts.

  If you have several files on your system that have pictures in them and you select one of them that you have not looked at in a while, you will notice LR creation of previews for these images, there will be 3 white dots in the upper right corner of the thumbnail. It's LR creation of previews for the thumbnail view. If you scroll quickly in the grid view, you'll notice a few thumbnails of images are gray, until you stop scrolling, then the upper left tile will come in clear view and the white dots will appear on the other images. It's LR creating previews for those of other images. Once LR created the preview of thumbnails that are on your screen, white spot will disappear. If you scroll down again, you will see more white dots

  If you switch to another folder that LR begins again create preview images in this folder. The total number of previews created and stored based on caching of the preview you have in the catalog settings dialog in the management of the files tab.

  If not, you need not the LR Previews.lrdata folder. Whenever LR is not very good this folder with a catalog he recreates it to store previews in.

  

• Enable trace in standard EBS PLSQL pkg and know the path of the trace file

  Hello
  
  I want to activate the trace in the standard package of PLSQL EBS:
  
  run immediately "alter session set sql_trace = TRUE";
  
  How can I know the path of the trace file?
  What is the name of the table to know the path of the file trace?
  
  Thank you
  Lavan

  How to find the Trace file generated for a simultaneous program? [967966.1 ID]
  How to trace a concurrent request and generate the TKPROF file [ID 453527.1]

  path tracing

  select value from v$parameter where name = 'user_dump_dest';
  

  for the package, you can set the name of the trace file after "run immediately"alter session set sql_trace = TRUE";"

  execute immediate 'alter session set tracefile_identifier="your_trace_file_name"';
  

• FileReference and path of the selected file

  Hello

  I use the FileReference class to browse a file from the file system. I would like to get the path of the selected file, but it seems impossible because of security problem.

  Isn't there any hope to do?

  Thank you very much

  Greetings

  Hello

  There is no possibility to get the path of the file selected for security reasons... However, you can only get the name of the file you selected.

  If this post answers your question or assistance, please mark it as such.

  Thank you

  Jean Claude Chari

• path of the image file that links do not correctly in the executable file

  I have a jpeg file in a project that I'm building which is not loading when run as an executable file.  The executable seems to be looking in the same directory that the image file was originally instead of the support folder where the image is deployed.  On another machine, the exe will look for the image in the directory, that were found on my machine.  When I drag the image file of the project on the block diagram Explorer, it creates a constant path of file indicates where the file is located on my machine.  This does not seem to update when I build the exe.  The image file is included in the source files.  Any help is appreciated!

  A constant path is... Yes indeed constant! It's not automatically change whenever someone might move the file too, whatever his imagination made her do. He does not maintain a link to the actual file it could use later to detect that the file has been moved elsewhere. In fact Windows has quite such a mechanism.

  So if you want to access an external file to your executable application to first do a correct path when running. My approach is to put in a directory from a VI file that I put in my application. Then in this VI use the way of getting current VI, band name the VI of it and add the location relative to the other file to it.

  If you do something like this:

  The project directory

  Directory of the utility

  My Location.vi

  Data directory

  MyResource.jpg

  in system development, then:

  The application directory

  MyApplication.exe

  Data directory

  MyResource.jpg

  in the application of the construction.

  With this provision, it doesn't matter even if you use the old format of executable LabVIEW 8.x or the new default format since LabVIEW 2009.

  My Location.vi is just a VI that takes a relative path in the entry (in this case "... / directory/MyResource.jpg data" called the "Current path to VI" node, use 'Band path' to remove the name of VI, then build to add this entry path, and this is!.)

• multiple paths to the same file come in research

  When I search for a file, I get the multiple as paths:

  C:\Users\Bill\My Documents\... file

  and

  C:\Documents and Settings\Bill\My Documents\ drop...

  The "Documents and Settings" folder contains a shortcut arrow.  There is only one folder for each of the folders in the path starting with 'Bill', that is, they are the same file in two ways.  That is this folder shortcut to, do I need, can I get rid of him and still have my files?  Have no idea how it got there.

  This is the direct download link to the usefulness of the junction box , wait approximately 5 seconds or more for the dialog "Save file" to appear, the name of the file is Junction100.zip (622 KB).  This kind of utilities are sometimes reported as virus by AV software, as long as you know the origin of the file and understand what the utility is supposed to do you will be sure to run the file, what is mentioned on the web site of the author:

  Note that this utility has undergone some fake antivirus alerts, including Norton and McAfee. The Manager of coding point of view there is nothing much that we can do about it, it seems as if some suppliers of software antivirus today write code if the trigger-happy it signals to ANY program that makes the fundamental system changes (which this must do, or it would be of no use!) as potential malware. Especially, the best AV products don't produce any these false alerts.

  Otherwise I have no way of knowing what permissions have been changed on your machine and that I have to post a playfile SubInACL to restore the permissions... believe me, the utility from the link above is much easier to use!

  John

• Defining the new path for the data files for restoring using the VALUE of NEWNAME FOR DATABASE

  Version: 11.2.0.3 Linux
  
  Today, I had to do a restore RMAN to a new server and I came across the post following RTO on the VALUE of NEWNAME FOR DATABASE
  
  ALTER database open resetlogs upgraded;         error to throw
  
  So, I thought to use it to indicate the new location of the data files to restore.
  
  That's what I did
  ===================
  
  Restore the control file and catalog items to backup using the command of CATALOGUE START WITH. Then I started the restoration

  $ rman target / cmdfile=restore.txt
  
  Recovery Manager: Release 11.2.0.3.0 - Production on Thu Jul 26 04:40:41 2012
  
  Copyright (c) 1982, 2011, Oracle and/or its affiliates.  All rights reserved.
  
  connected to target database: SPIKEY (DBID=2576163333, not open)
  
  RMAN> run
  2>  {
  3>  SET NEWNAME FOR DATABASE TO '/fnup/hwrc/oradata/spikey';
  4>  restore database  ;
  5>  }
  6>
  7>
  8>
  executing command: SET NEWNAME
  RMAN-00571: ===========================================================
  RMAN-00569: =============== ERROR MESSAGE STACK FOLLOWS ===============
  RMAN-00571: ===========================================================
  RMAN-03002: failure of set command at 07/26/2012 04:40:43
  RMAN-06970: NEWNAME '/fnup/hwrc/oradata/spikey' for database must include %f or %U format
  
  Recovery Manager complete.

  Don't know how it worked for Levi without %f or %U. So, I added %f
  

   $ vi restore.txt
   $ cat restore.txt
  run
   {
   SET NEWNAME FOR DATABASE TO '/fnup/hwrc/oradata/spikey/%f';
   restore database  ;
   }
  
  
   $ rman target / cmdfile=restore.txt
  
  Recovery Manager: Release 11.2.0.3.0 - Production on Thu Jul 26 04:45:45 2012
  
  Copyright (c) 1982, 2011, Oracle and/or its affiliates.  All rights reserved.
  
  connected to target database: SPIKEY (DBID=2576163333, not open)
  
  RMAN> run
  2>  {
  3>  SET NEWNAME FOR DATABASE TO '/fnup/hwrc/oradata/spikey/%f';
  4>  restore database  ;
  5>  }
  6>
  7>
  8>
  executing command: SET NEWNAME
  
  Starting restore at 26-JUL-12
  using target database control file instead of recovery catalog
  allocated channel: ORA_DISK_1
  channel ORA_DISK_1: SID=19 device type=DISK
  
  channel ORA_DISK_1: starting datafile backup set restore
  channel ORA_DISK_1: specifying datafile(s) to restore from backup set
  channel ORA_DISK_1: restoring datafile 00001 to /fnup/hwrc/oradata/spikey/1
  channel ORA_DISK_1: restoring datafile 00002 to /fnup/hwrc/oradata/spikey/2
  channel ORA_DISK_1: restoring datafile 00003 to /fnup/hwrc/oradata/spikey/3
  channel ORA_DISK_1: restoring datafile 00004 to /fnup/hwrc/oradata/spikey/4
  channel ORA_DISK_1: restoring datafile 00005 to /fnup/hwrc/oradata/spikey/5
  channel ORA_DISK_1: restoring datafile 00006 to /fnup/hwrc/oradata/spikey/6
  channel ORA_DISK_1: restoring datafile 00007 to /fnup/hwrc/oradata/spikey/7
  channel ORA_DISK_1: restoring datafile 00008 to /fnup/hwrc/oradata/spikey/8
  channel ORA_DISK_1: restoring datafile 00009 to /fnup/hwrc/oradata/spikey/9
  channel ORA_DISK_1: reading from backup piece /u07/bkpfolder/SPIKEY_full_01nh0028_1_1_20120725.rmbk
  channel ORA_DISK_1: errors found reading piece handle=/u07/bkpfolder/SPIKEY_full_01nh0028_1_1_20120725.rmbk
  channel ORA_DISK_1: failover to piece handle=/u07/dump/bkpfolder/SPIKEY_full_01nh0028_1_1_20120725.rmbk tag=SPIKEY_FULL
  channel ORA_DISK_1: restored backup piece 1
  channel ORA_DISK_1: restore complete, elapsed time: 00:01:56
  Finished restore at 26-JUL-12
  
  Recovery Manager complete.

  As you can see, RMAN restore data files to the desired location. But the data file names ended up as

  1
  2
  3
  .
  .      
  .
  9

  !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! -----------| Holy Cow |-----------------------------
  
  
  So I had to rename each file as below
  

  $ mv 1 /fnup/hwrc/oradata/spikey/system01.dbf
  $ mv 2 /fnup/hwrc/oradata/spikey/sysaux01.dbf
  $ mv 3 /fnup/hwrc/oradata/spikey/undotbs01.dbf

  I would have been better in execution of the order for each data below file

  SET NEWNAME FOR DATAFILE

  Now, I think, there is no advantage in using NEWNAME SET of DATABASE to. Only the disadvantages. I did anything wrong above?

  Martin;

  On the issue of the VALUE of NEWNAME FOR DATABASE, you must specify at least one of the first three of the following substitution variables to avoid collisions of names: %b f % U. see semantic entry for TO 'filename' for a description of the possible substitution variables.

  You use %f

  %b
  
  Specifies the filename without the fully qualified directory path. For example, the datafile name /oradata/prod/financial.dbf is transformed to financial.dbf. This variable enables you to preserve the names of the datafiles while you move them to different directory. During backup, it can be used for the creation of image copies. The variable cannot be used for OMF datafiles or backup sets.
  
  %f
  
  Specifies the absolute file number of the datafile for which the new name is generated. For example, if datafile 2 is duplicated, then %f generates the value 2.
  
  %U
  
  Specifies a system-generated unique filename. The name is in the following format: data-D-%d_id-%I_TS-%N_FNO-%f. The %d variable specifies the database name. For example, a possible name might be data-D-prod_id-22398754_TS-users_FNO-7.
  

  Source - E10643-01

  Backup and recovery reference

  http://docs.Oracle.com/CD/E14072_01/backup.112/e10643/rcmsynta2014.htm

  I see CKPT and I agree on that!

  Best regards

  mseberg

• How to call sequence into LabVIEW, by providing the path of the sequence files.

  Hello

  Please give me a solution for call sequence from the API ActiveX LabVIEW file by entering the path of the LabVIEW user interface sequence.

  Thank you

  Wherry

  Here is a link I gave some pointers on how to run a file opened via Single Pass sequence.

  http://forums.NI.com/T5/NI-TestStand/direct-execution-of-the-sequence-when-UI-launches/m-p/2000819#M...

  How are you going to start this sequence is the user who selects the sequence on the disk?    Is already open in a SequenceViewMgr control?

  An operator interface would be more applicable to your situation?

  Thank you

  PH

• Help with my computer! All the deleted files, including recovery! What's past and how to fix it?

  Hello. So a few days ago I restarted my computer. Literally restarted my computer (turn off then turn onn) because my shortcuts do not work (the .exe would not launch files). I restarted my computer, and when I click on the shortcut, he said that there was no such destination. Soon I relised all my files are gone. I restarted my computer and you press F8 so that I can back to factory State, but the recovery has not worked and now im stuck at the facility because it looks like this: there is no for files recovery. Idk what happened but all my files and I installed software have disappeared. Someone can you please tell me what happened and how can I solve this problem?

  100% recovery does not work! Using the computer in safe mode doesn't work.

  My system doesn't have a backup of the files. The files just disappeared. All my files actually including the files for recovery. You say I should reinstall my windows using the CD/DVD. If this is the case, I have a problem because I don't have the CD/DVD for her. The paper in my computer box indicates that you must install it in the computer (deleted files). What can I do?

  Your system does not have backups of your files/folders for you.  It is your duty to implement only or not.  If you do not the installer / make backups of your data - so you lose if/when something happens.

  (The automatic backup of the system files needed) system restore is enabled by default - but can be disabled by the system administrator.

  The "recovery" you used is not a feature of Microsoft or setup - which was created by the computer manufacturer.  They decided that it would be more easy/better to put the backup of the system installation media in the same place the user puts all their stuff - on the physical hard disk in the machine.  It is destructive or not is determined by the computer manufacturer and they even included a choice (destructive or non-destructive recovery) _ at the time use you it.  Each of them has been/is different.

  You can contact the manufacturer of the computer and HOPE they always support of recovery for your computer and not you charge (or charge you a large part) to get the media said.

  Can read this - it might help:
  http://www.ZDNet.com/blog/Bott/lost-your-Windows-discs-how-to-get-replacement-media-legally/4320

• Retrieve the bytes of the image of the path of the image file

  Hello

  I was unable to find a post that details how to retrieve the bytes of the image of an image (given the path to the file of the image on the device).  Basically, using the FilePicker, I'm able to get the path of an image chosen by the user:

  There you go:

  Pass just your file as method parameter name.

   public static byte[] getBytesFromFile(String filename) throws IOException {
          FileConnection fconn = null;
          InputStream is = null;
          try {
              fconn = (FileConnection) Connector.open(filename, Connector.READ);
              is = fconn.openInputStream();
  
              return IOUtilities.streamToBytes(is);
          } finally {
              if (is != null) {
                  is.close();
              }
              if (fconn != null) {
                  fconn.close();
              }
          }
      }
  

• Set the path to the jar file

  Sorry for the noob question, but could you tell me please what I did wrong when I try to set the path to the file in my application jar.

  I have app that works with the xml file. I have the following project structure:

  /project_root_directory

  | / lib _

  | /resources/file.XML _

  | / SRC _

  So, I need set my jar file, because when I correctly by running the IDE, it works well.

  By default, it seems:

  private File file;
  private StreamResult streamResult;
  file = new File("resources/file.xml");
  streamResult = new StreamResult(file);
  
  
  
  

  And methods where I can change the DOM structure via transformer end methods:

  transformer.transform(source, streamResult);
  
  
  
  

  So, I tried sets the path to the file:

  private URL url;
  ...
  
  file = new File(url.getPath());
  streamResult = new StreamResult(file);
  
  
  
  

  But it does not, because when I try to get resources by the following condition

  url = getClass().getResource("resources/file.xml");
  
  
  
  

  (" url = getClass().getResource("resources/file.xml "); URL = getClass () .getResource ("url = getClass().getResource("resources/file.xml "); (" resources/file.xml ');

  URL - is null

  OK...

  I tried the following solution

  InputStream input = getClass().getResourceAsStream("resources/file.xml");

  Here, I myself also null...

  This solution I found here

  Also, I tried in absolute path

  filePath = file.getAbsolutePath();
  file = new File(filePath);
  streamResult = new StreamResult(file);
  
  
  
  

  But he also didn't work. There I got message seems to be: "Cannot find the /User/user1/Desktop/program1/resources/file.xml resource" - but it really is absoulte path to a file.

  Also, I tried using System.getProperty

  String filename = "file.xml";
  String workingDir = System.getProperty("user.dir");
  finalfile = workingDir + File.separator + "resources" + File.separator + filename;
  file = new File(finalfile);
  
  
  

  I also did test unit that finished with the 'green light', but potted his wrong with the message "unable to find /User/user1/Desktop/program1/resources/file.xm resource.

  Could you tell me please what I did wrong?

  file:\c:\Users\user1\Desktop\myapp.jar!\psswd.XML is what getResource() book you as the URL of the entry of the pot (notice I didn't say file, but the entrance of pot).

  The meaning is: the psswd.xml of the entrance lies at the root of the C:\Users\user1\Desktop\myapp.jar pot.

  Now, without taking into account my tips, you want to turn this into a file. If Java puts in front of it in the current directory. If you use Windows Explorer, you have such a file?

  psswd.XML is not just a file. In any case, given that your StreamResult is supposed to write something, it may not be in the jar. You can not write to an entry in the pot. Jars is supposed to be read-only.

  It's like an EXE file in writing within himself. So psswd.xml should be outside the pot, a real file and forget the things of the resource. It happened to work in the IDE, because there he was jarred not yet.

  It happened to be a Windows file and a Java resource.