photo selection between two dates

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It is possible to select photos between two dates?

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is it possible to select the photos between two dates?

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Similar Questions

Select the mountains between two dates

Hi all
How can I select all months between two dates. For example, if two dates are say 2008-05-25 and 2009-07-15, then I need following output

May-2008
June-2008
July-2008
August-2008
September-2008
October-2008
November-2008
December-2008
January-2009
February-2009
March-2009
April-2008
May-2009
-June 2009
July-2009

Thank you
Sujnan

Try this one

SQL>  SELECT TO_CHAR(add_months(TRUNC(to_date('25/05/2008','DD/MM/YYYY'),'MM') ,(level-1)),'fmMonth-YYYY')
  2     FROM dual
  3    CONNECT BY level <= months_between(to_date('15/07/2009','DD/MM/YYYY'),to_date('25/05/2008','DD/MM/YYYY')) + 2;

TO_CHAR(ADD_MO
--------------
May-2008
June-2008
July-2008
August-2008
September-2008
October-2008
November-2008
December-2008
January-2009
February-2009
March-2009

TO_CHAR(ADD_MO
--------------
April-2009
May-2009
June-2009
July-2009

15 rows selected.

SQL>

Dynamic calculation of the number of days between two dates in a table

Hello
I'm working on request where I dynamically calculate the number of days between two dates in a table.
The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.
APEX version: 5.0

Hi BO123,

BO123 wrote:

Hello

I'm working on request where I dynamically calculate the number of days between two dates in a table.

The calculation must be dynamic, i.e., when I recover the Start_date and End_date and move to the field following (call_duration) in the same row, the difference must be calculated dynamically in this area and make sure the field read-only.

APEX version: 5.0

one of the way to do this by calling ajax on change of end_date.

See the sample code given below to fetch the resulting duration and making the field read only after calculation

Step 1: Change your page

under CSS-> Inline, put the code below
```
.row_item_disabled {
  cursor: default;
  opacity: 0.5;
  filter: alpha(opacity=50);
  pointer-events: none;
}
```
Step 2: Create on demand Ajax process I say CALC_DURATION

Please check Procces Ajax, see line 6.7 How to assign a value to the variable sent by ajax call
```
Declare
  p_start_date  date;
  p_end_date    date;
  p_duration number;
Begin
  p_start_date  := to_date(apex_application.g_x01);
  p_end_date    := to_date(apex_application.g_x02);

   --do your calculation and assign the output to the variable p_duration
  select p_end_date - p_start_date into p_duration
    from dual;

  -- return calculated duration
  sys.htp.p(p_duration);
End;
```
Step 3: Create the javascript function

Change your page-> the function and the declaration of the Global Variable-> put the javascript function

You must extract the rowid in the first place, for which you want to set the time, see line 2

assuming f06, f07 and f08 is the id of the start date, and end date columns respectively, and duration

See no line no 8 how set the value returned by the process of ajax at the duration column

Replace your column to the respective column identifiers in the code below
```
function f_calulate_duration(pThis) {
  var row_id  = pThis.id.substr(4);
  var start_date = $('#f06_'+row_id).val();
  apex.server.process ( "CALC_DURATION", {
  x01: start_date,x02: $(pThis).val()
}, { success: function( pData ) {
// set duration to duration column
$('#f08_'+row_id).val(pData);
// disable duration column
$("#f08_" + row_id).attr("readonly", true).addClass('row_item_disabled'); }
});
}
```
Step 4: choose the end date call the javascript function

Go to report attributes-> edit your Date column end-> column-> Attrbiutes element attributes-> put the code below
```
onchange="javascript:f_calulate_duration(this);"
```
hope this helps you,

Kind regards

Jitendra

difference between two dates in the year/month/day in Obiee

Hi gurus,
I know this question have been asked and answered several times but I have a requirement that is a little different, then the previous ones.
I want to calculate the difference between two dates in OBIEE10g in year/month/day format similar to the below SQL output
SQL > select end_date, start_date,
trunc (months_between (end_date, start_date) / 12) years.
months of mod (trunc (months_between (end_date, start_date)), 12).
End_date - add_months (start_date, trunc (months_between (end_date, start_date))) days
t
Thanks in advance
SK

Search for this

"TIMESTAMPDIFF IN THE FORM OF MTHS # YEARS."

or else

To get the current mandate of employees since the date of hiring in the form of # years # mths or # year (s) # month (s)

Concat (concat (cast (TIMESTAMPDIFF (SQL_TSI_Month, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) / 12 as char),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Month (s)'))

Concat (concat (CAST (TIMESTAMPDIFF (SQL_TSI_YEAR, "Employee attributes". (((' ' Hiring last Date employee ", CURRENT_DATE) as CHAR),"Year (s)"), concat (cast (MOD (TIMESTAMPDIFF (SQL_TSI_Month,"Employee attributes". (((((' ' Hiring last Date employee ", CURRENT_DATE), 12) as char), 'Mth (s)'))

Number of Saturdays between two dates

Hello

How can I get number of Saturdays between two dates, including the two dates?

for example number of Saturdays between 09/05/2014 and 10/05/2014 is five

Help, please

I use oracle 10g

SQL> with t
  2  as
  3  (
  4  select to_date('05/09/2014 ', 'dd/mm/yyyy') from_dt
  5       , to_date('05/10/2014 ', 'dd/mm/yyyy') to_dt
  6    from dual
  7  )
  8   select to_char(from_dt + (level-1), 'fmDay') day_
  9        , count(*) cnt
 10     from t
 11  connect
 12       by level <= to_dt - from_dt + 1
 13    group
 14       by to_char(from_dt + (level-1), 'fmDay');

DAY_             CNT
--------- ----------
Saturday           5
Thursday           4
Tuesday            4
Friday             5
Wednesday          4
Monday             4
Sunday             5

7 rows selected.

SQL>

Days between two dates given

Hi all
I need the days between two dates given.
Select to_date('25-mar-2014','dd-mon-yyyy') start_date, end_date to_date('30-mar-2014','dd-mon-yyyy')
of the double
Desired output:
25
26
27
28
29
30
Thanks in advance.
Kind regards
Afzal.

Select the level - 1 desired_output + to_number (to_char (start_date, 'dd'))

of (to_date('25-mar-2014','dd-mon-yyyy') select start_date, end_date to_date('30-mar-2014','dd-mon-yyyy'))

of the double

)

connect by level<= end_date="" -="" start_date="" +="">

DESIRED_OUTPUT

25

26

27

28

29

30

Concerning

Etbin

Months between two dates

Hello
I have two dates. start date and end date.
I want to extract months between two dates
months should be as
JAN
FEB
MAR
for example.
Start - 1-jan-2014
date of end - 31 - dec - 2014
How can I do this?
Thanks and greetings
CORINE

You should always use the function MONTHS_BETWEEN...

for example

SQL > ed
A written file afiedt.buf

1 with t as (select date '' 2014-01-01 as start_date date ' 2014-12-31' as double end_date)
2 --
3 end of test data
4 --
5. Select to_char (add_months (start_date, rownum-1), 'My') by month
6 t
7 * connect by rownum<=>
SQL > /.

LUN
---
Jan
Feb
Mar
Apr
May
Jun
Jul
Aug
Ms
Oct
Nov
Dec

12 selected lines.

And if you want that they display, separated by commas...

SQL > ed
A written file afiedt.buf

1 with t as (select date '' 2014-01-01 as start_date date ' 2014-12-31' as double end_date)
2 --
3 end of test data
4 --
5 Select listagg (to_char (add_months (start_date, rownum-1), 'My'), ',') group by month (order by rownum)
6 t
7 * connect by rownum<=>
SQL > /.

MONTH
-----------------------------------------------------------------------------------------------------------------
Jan, Feb, Mar, Apr, may, June, July, August, Sept, Oct, Nov, Dec

Number of occurrences of a day between two dates

Hello
I have a requirement in my code to count the number of times per day occurs between two dates. So, for example if
start date = January 1, 2014
end date = March 31, 2014
The number of times that happens day 1 is three times. That's why I want the result to be 3. My three input parameters are the number of the day, start and end dates. I know that this can be done by parsing through the days and incrementing a counter of sorts, but can it be done without any loop etc?
Looking for options of
Thank you
Birdy

SELECT COUNT (TO_CHAR (DAYS, 'DD')) IN)

SELECT DAYS START_DATE + LEVEL 1

FROM T1

CONNECT BY LEVEL<=>

WHERE TO_CHAR (DAYS, 'DD') ='&01';

Post edited by: Parth272025

How to find days between two dates in days

Hi, I want to get the days between two dates, expressed in days, how can I do this? For example, I date i.e. 1 October 10, 2013 (Thursday) and 2 as October 13, 2013 (Sunday). How can I get a production of:
Thursday, Friday, Saturday and Sunday, which are the days between Oct. 10-13, 2013. I hope you understand my point. Thank you

You can try something like this

CURSOR LOAD_PROF is

SELECT load_prof1, v_time_profile_day

OF load_profile_test

WHERE profile_day IN (select TO_CHAR(:day1+level-1,'Day')

of the double

connect by level<>

);

Kind regards

S Pax

Number of weeks between two dates that are in the same or different year

Hello
How to calculate the number of weeks between two dates?
for example. "" "17-mar-2013' and June 27, 2013" or June 15, 2013 "and" 25-mar-2014

Thanks in advance.
lukx

Hello

Looks like your date range is incorrect.

Please try the below.

SQL >-front right

SQL > select D2 - D1 "days."

2 round ((D2-D1)/7.0) "weeks."

3 round (Months_between (d1, d2), 0) 'months '.

(select 4

5 TO_DATE ('20121201', 'YYYYMMDD') D1, D2 TO_DATE ('20130116', 'YYYYMMDD')

6 from two

(7) date_range;

Elapsed days weeks months

------------ --------- ---------

46 7 1

DESIRED_OUTPUT
25
26
27
28
29
30

Calculate business hours between two dates in a cursor

Hello, its me again (?).

Yesterday, I got a solution to a problem here where I need to calculate the hours between two dates, excluding Sat/Sun and from 09:00 to 18:00. I'm now putting this login in a PL/SQL block, so I can calculate it for each record in a slider, all by looping.

with t (start_date
       ,end_date
       )
as (select  to_date('22-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') start_dt,
                       to_date('23-oct-2012 09:00:00','dd-mon-yyyy hh24:mi:ss') end_dt
    from dual
   )
, hrs (dt) as
  (select start_date
   from   t
   union all
   select dt +1/24/60
   from   hrs
   where  hrs.dt < (select end_date-1/24/60 from t)
  )
select count(*)/60
from hrs
where to_char(dt,'dy') not in ('sat','sun')
and  to_number(to_char(dt,'hh24')) not between 18 and 23
and  to_number(to_char(dt,'hh24')) not between 0 and 8
/

The logic above, I'm up here:

FOR c_record IN c_1 LOOP
//For each record, check if the two dates meet the criteria and then raise the counters accordingly
select  to_date(c_record.REPORTADA,'dd-mon-yyyy hh24:mi:ss') INTO vFch1 FROM DUAL;
SELECT  to_date(c_record.INICIOREAL,'dd-mon-yyyy hh24:mi:ss') INTO vFch2 FROM DUAL;

IF ((vHoras > 2) AND c_record.PRIORIDAD=3) THEN
  vContOk :=vContOk + 0;
  vContBad := vContBad+1;
  vContOt   := vContOt+1;
ELSE 
  vContOk :=vContOk +1;
  vContBad := vContBad+0;
  vContOt   := vContOt+1;
END
    IF;

IF ((vHoras > 4) AND c_record.PRIORIDAD=2) THEN
  vContOk :=vContOk + 0;
  vContBad := vContBad+1;
  vContOt   := vContOt+1;
ELSE
  vContOk :=vContOk +1;
  vContBad := vContBad+0;
  vContOt   := vContOt+1;
END IF;

IF ((vHoras > 16) AND c_record.PRIORIDAD=1) THEN
  vContOk :=vContOk + 0;
  vContBad := vContBad+1;
  vContOt   := vContOt+1;
ELSE
  vContOk :=vContOk +1;
  vContBad := vContBad+0;
  vContOt   := vContOt+1;
END IF;

END LOOP;

I really don't like if the performance is horrible because it will run once a month and should spend only 40-100 records.
However, I can't find a way to use this connection even in this case

Could you help me?
Thank you!

Greetings,
NACEUR

N wrote:
I need to calculate the number of minutes between two dates, only count the hours from 9 to 18hs.

CREATE OR REPLACE
  FUNCTION get_bus_minutes_between(
                                   p_start_date DATE,
                                   p_end_date DATE
                                  )
    RETURN NUMBER
    IS
        v_return NUMBER;
    BEGIN
        with t as (
                   select  case level
                             when 1 then greatest(p_start_date,trunc(p_start_date) + 9 / 24)
                             else trunc(p_start_date) + level - 15 / 24
                           end start_dt,
                           case connect_by_isleaf
                             when 1 then least(p_end_date,trunc(p_end_date) + 18 / 24)
                             else trunc(p_start_date) + level - 8 / 24
                           end end_dt
                     from  dual
                     connect by level <= trunc(p_end_date) - trunc(p_start_date) + 1
                  )
        select  sum(greatest(end_dt - start_dt,0)) * 24 * 60 work_minutes
          into  v_return
          from  t
          where trunc(start_dt) - trunc(start_dt,'iw') < 5; -- exclude weekends
        RETURN v_return;
END;
/

For example:

SQL> select get_bus_minutes_between(
  2                                 to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'),
  3                                 to_date('22-oct-2012 13:21:00','dd-mon-yyyy hh24:mi:ss')
  4                                ) work_minutes
  5    from dual
  6  /

WORK_MINUTES
------------
         261

SQL>

SY.

Calculate the hours between two dates
Hello

I have a requirement to count the hours with 2 given timestamps, something like:
```
SQL> select ((to_date('22-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss') - to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'))*24) B from dual ;

         B
----------
        48
```
However, I wish it would be that simple. I just need to count the hours between two timestamps for the hours of work for example, 08:00 - 17:00, MONDAY to Friday (excluding weekends).
So lets say I have to count the hours between two dates above the result should be 18 hours not 48 (4 hours on 20/oct, 9 hours on 21/oct to 5 hours 22/oct).
How can I achieve this? Any idea will be useful.

Thank you
My query generates a list of all the hours between the start and end time, filters on the hours that are outside of the hours of work and then account for the remaining lines. Change that to partial hours must just be a case of replace the two occurrences of 1/24 with 24/01/60, then - as say you - Division COUNT (*) by 60.

There may be performance issues using techniques of generation of line like this, if you put this in a query involving the joining of several lines of other tables (for example where the dates of beginning and end are derived from several employees?) or in several days. If you don't find it then count the number of whole days (taking weekends into account) between dates and work on the partial days after that it could be better. This would probably involve a lot of statements of case (which I don't have time to test it now).

Ben

How do the time difference between two dates?
Hi all

I use this query to get the time difference between two dates.

Select to_timestamp ('2012-10-03 12:00 ',' YYYY-MM-DD hh)-to_timestamp ('2012-10-03 11:00 ',' YYYY-MM-DD hh) as double diff;

but do not get the correct result.

Thank you
Left KEY... Left Padding of tanks.

No.of feb 29 s between two dates

Hello

I would like to calculate feb29 between two dates currently using connect by level , but it causes the problem of performance (50 M of data)

(SELECT SUM (DECODE (TO_CHAR (start_date + LEVEL - 1,'dd - my '), 29 - feb', 1, 0)) double CONNECTION OF LEVEL < = SYSDATE - start_date + 1) ' no. OF. FEB29'

using Oracle Database 11 g Enterprise Edition Release 11.2.0.2.0 - 64 bit

Thank you-

Small change required...

with t as
(select sysdate-10000 start_dt,to_date('01-Mar-2012','dd-Mon-yyyy') end_dt from dual)
select start_dt,end_dt,st_year,end_year,sum(case when mod(yr,400)=0 then 1
                when mod(yr,4) = 0 then 1
           else 0 end) cnt
from(     select start_dt,end_dt,st_year,end_year,st_year+rownum-1 yr
     from (
          select  start_dt,end_dt,
               extract(year from start_dt)+
                 case when extract(month from start_dt) < 3 then 0 else 1 end st_year,
               extract(year from end_dt)+
                 case when extract(month from end_dt) >= 3 then 0 else -1 end end_year
          from t)
     connect by st_year+rownum-1 <= end_year
    )
group by start_dt,end_dt,st_year,end_year

SQL> /

START_DT    END_DT         ST_YEAR   END_YEAR        CNT
----------- ----------- ---------- ---------- ----------
11-may-1985 28-feb-2012       1986       2011          6

SQL> /

START_DT    END_DT         ST_YEAR   END_YEAR        CNT
----------- ----------- ---------- ---------- ----------
11-may-1985 29-feb-2012       1986       2011          6

SQL> /

START_DT    END_DT         ST_YEAR   END_YEAR        CNT
----------- ----------- ---------- ---------- ----------
11-may-1985 01-mar-2012       1986       2012          7

Published by: JAC September 26, 2012 11:44
formatting

Published by: JAC September 26, 2012 12:07
Subqueries can be avoided, added the goal of understanding

How to caluclate tat between two dates of a timestamp field

Hello
could help to caluclate days between two dates and unique timestamp filed with this
query
Select * from m_activity_transaction where actn_opp_id in)
Select actn_opp_id in the m_activity_transaction where ACTN_ACTV_ID = 218
Actn_opp_id group
view count (*) > 1) and ACTN_ACTV_ID = 218
order of actn_performed_on
IAM get output is

ACTN_ID ACTN_OPP_ID ACTN_PERFORMED_ON
319415 95831 JANUARY 27, 12 AM 11.06.20.000000
315249 95831 8 FEBRUARY 12 05.32.54.000000 PM
301927 103509 20 DECEMBER 11 04.01.43.000000 PM
301458 103509 19 DECEMBER 11 04.51.03.000000 PM
294841 115840 10 JANUARY 12 03.20.12.000000 PM
312062 115840 11 JANUARY 12 05.17.06.000000 PM

Normand to caluclate number days between two dates like January 27, 12 AM 11.06.20.000000 and I 05.32.54.000000 8 February 12 PM where actn_id is unique AND ACTN_OPP_ID IS NOT UNIQUE.
Thanks in advance,
VVR.

In this way.

with data as
(
select 315249 a, 95831 b, to_date('27-JAN-12 11.06.20 AM', 'DD-MON-RR HH.MI.SS AM') dt from dual union all
select 319415, 95831, to_date('08-FEB-12 05.32.54 PM', 'DD-MON-RR HH.MI.SS AM') from dual union all
select 301927, 103509 , to_date('20-DEC-11 04.51.03 PM', 'DD-MON-RR HH.MI.SS AM') from dual union all
select 301458 , 103509 , to_date('19-DEC-11 04.01.43 PM', 'DD-MON-RR HH.MI.SS AM') from dual union all
select 363810 , 144656 , to_date('27-JUN-12 12.43.28 PM', 'DD-MON-RR HH.MI.SS AM') from dual union all
select 363500 , 144656 , to_date('26-JUN-12 11.41.50 AM', 'DD-MON-RR HH.MI.SS AM') from dual union all
select 363354 , 144656 , to_date('25-JUN-13 12.41.13 PM', 'DD-MON-RR HH.MI.SS AM') from dual
)
select a, b, diff_in_days
  from (
        select a, b, trunc(dt - lag(dt) over (partition by b order by dt, a)) diff_in_days
          from data
       ) tab
 where tab.diff_in_days is not null;

A                      B                      DIFF_IN_DAYS
---------------------- ---------------------- ----------------------
319415                 95831                  12
301927                 103509                 1
363810                 144656                 1
363354                 144656                 362

photo selection between two dates

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