Select the mountains between two dates

Similar Questions

• Calculate the hours between two dates

  Hello
  
  I have a requirement to count the hours with 2 given timestamps, something like:

  SQL> select ((to_date('22-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss') - to_date('20-oct-2012 13:00:00','dd-mon-yyyy hh24:mi:ss'))*24) B from dual ;
  
           B
  ----------
          48

  However, I wish it would be that simple. I just need to count the hours between two timestamps for the hours of work for example, 08:00 - 17:00, MONDAY to Friday (excluding weekends).
  So lets say I have to count the hours between two dates above the result should be 18 hours not 48 (4 hours on 20/oct, 9 hours on 21/oct to 5 hours 22/oct).
  How can I achieve this? Any idea will be useful.
  
  Thank you

  My query generates a list of all the hours between the start and end time, filters on the hours that are outside of the hours of work and then account for the remaining lines. Change that to partial hours must just be a case of replace the two occurrences of 1/24 with 24/01/60, then - as say you - Division COUNT (*) by 60.

  There may be performance issues using techniques of generation of line like this, if you put this in a query involving the joining of several lines of other tables (for example where the dates of beginning and end are derived from several employees?) or in several days. If you don't find it then count the number of whole days (taking weekends into account) between dates and work on the partial days after that it could be better. This would probably involve a lot of statements of case (which I don't have time to test it now).

  Ben

• Display the months between two dates

  Hello:
  I need all the months between two dates. I entered two dates as January 15, 2001 and 2011-mar-03. I want the result as below.
  
  JANUARY 15, 2011 - JANUARY 31, 2011
  February 1, 2011 - February 28, 2011
  MARCH 1, 2011 - MARCH 3, 2011
  
  I held this result of sql query in oracle. Could you please suggest me?
  Thanks in advance.
  Abhishek

  SELECT     GREATEST(st, ADD_MONTHS(TRUNC(st, 'MONTH'), (LEVEL - 1))) dt,
             LEAST(ed, LAST_DAY(ADD_MONTHS(TRUNC(st, 'MONTH'), (LEVEL - 1)))) ld
        FROM (SELECT DATE '2011-01-15' AS st, DATE '2011-03-03' AS ed
                FROM DUAL)
  CONNECT BY LEVEL <= MONTHS_BETWEEN(TRUNC(ed, 'MONTH'), TRUNC(st, 'MONTH')) + 1
    ORDER BY 1;
  
  DT                       LD
  ------------------------ ------------------------
  15.01.2011 00:00:00      31.01.2011 00:00:00
  01.02.2011 00:00:00      28.02.2011 00:00:00
  01.03.2011 00:00:00      03.03.2011 00:00:00
  

  HTH, Urs

• Find the difference between two date and time

  Hi friends,
  
  I wanted to find the difference between two date and time, but my qury is slightest error "invalid number."
  
  

  select sql_step_num,proc_name,run_seqno,start_date,end_date,(to_char(start_date,'HH24-MI-SS') - to_char(end_date,'HH24-MI-SS') ) as ed  
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate) 
  order by sql_step_num;

  You try to get the feel between two char strings.
  And more difference between two dates gives a NUMBER of days.
  Try this:

  select sql_step_num,proc_name,run_seqno,start_date,end_date,numtodsinterval(end_date-start_date,'DAY') as ed
  from eval.EVAL_RUNTIME_DETAILS
  where trunc(start_date) = trunc(sysdate)
  order by sql_step_num;
  

• How to find the difference between two dates in the presentation layer

  Hi gurus,
  
  Hello to everyone. Today, I came with the new requirement.
  
  
  I need to know the difference between a date and the current date in the formula column application presentation layer.by.
  
  
  
  Thank you and best regards,
  Prates

  Hi Navin,

  TIMESTAMPDIFF function first determines the timestamp component that corresponds to the specified interval setting. For example, SQL_TSI_DAY corresponds to the day component and SQL_TSI_MONTH corresponds to the component "month".

  If you want to display the difference between two dates in days using SQL_TSI_DAY, unlike butterflies SQL_TSI_MONTH and so on...

  hope you understand...

  Award points and to close the debate, if your question is answered.

  See you soon,.
  Aravind

• Dynamic action - Get the difference between two dates + times

  I have problems a little dynamic to work action. I'm trying to get the time between two dates with the time difference.
  
  Here is what I got (this is apex 4.0):
  
  Two date pickers + two numbers fields (date/start/end times)
  
  I created a dynamic action on the page who fires on the point lose focus (above points).
  
  The real action for the DA is the body of the PL/SQL function:

  declare
    end_date DATE;
    start_date DATE;
  Begin
    start_date := to_char(:P1_START_DATE || ' ' || :P1_START_TIME, 'DD-MON-YYYY HH:MIAM');
    end_date := to_char(:P1_END_DATE || ' ' || :P1_END_TIME, 'DD-MON-YYYY HH:MIAM');
    :P1_HOURS := end_date-start_date;
  End;

  When I change the values on the page, I get the following error:
  
  AJAX call back Server error ORA-06502: PL/SQL: digital or value error: character number conversion error to set the value.
  
  I'm guessing that there is a problem with the date formatting, but I can't make it work. Thanks in advance!

  Hi djston,

  because you chose the dynamic action of 'Set value' with the "Body of the PL/SQL function" type you need to return the value. Try the following code

  declare
    end_date DATE;
    start_date DATE;
  Begin
    start_date := to_date(:P1_START_DATE || ' ' || :P1_START_TIME, 'DD-MM-YYYY HH:MIAM');
    end_date := to_date(:P1_END_DATE || ' ' || :P1_END_TIME, 'DD-MM-YYYY HH:MIAM');
    RETURN (end_date-start_date)*24;
  End;
  

  and P1_REQUESTED_HOURS like 'item affected. "

  Concerning
  Patrick
  -----------
  My Blog: http://www.inside-oracle-apex.com
  APEX 4.0 Plug-Ins: http://apex.oracle.com/plugins
  Twitter: http://www.twitter.com/patrickwolf

  Published by: Patrick Wolf on January 17, 2011 10:54

• counting the days between two dates

  I have 3 columns in my table
  
  date of purchase date sold days
  computer 24 April 09-11 May 09
  
  
  How can I write that a sql statement will help me to create a new column days and days between date bought and sold
  
  
  Thank you

  872959 wrote:
  I have 3 columns in my table

  date of purchase date sold days
  computer 24 April 09-11 May 09

  How can I write that a sql statement will help me to create a new column days and days between date bought and sold

  Thank you

  just subtract two dates & the difference will be in units of days

  SQL > select to_date('11-MAY-09','DD-MON-YY') - double TO_DATE('24-APR-09','DD-MON-YY');

  TO_DATE('11-MAY-09','DD-MON-YY')-TO_DATE('24-APR-09','DD-MON-YY')
  -----------------------------------------------------------------
  17

  Published by: sb92075 on July 19, 2011 10:26

• Formula to determine if a specific day of the week between two dates?

  I am creating a spreadsheet to track my time PD & holiday. I usually work weekends, and my vacation allowance includes a specific maximum number of Sundays a year. Is there a way to calculate how much Sunday fall between a date range (or any day of the week, by the way)?

  (i.e. If my vacation starts February 1, 2016 and ends March 2, 2016, Sunday how are included?)

  I know that I can calculate how many weeks have passed, using = Quotient (DateDiff (Start_Date, End_Date), 7), but it is possible to include two Sundays in a period of 7 days.

  Hi Eric,.

  Here is one approach.

  

  C2 = A2 + (7−WEEKDAY(A2,2))

  This concludes the first Sunday following the start date.

  

  D2 = STRIPDURATION ((B2−C2) ÷7)

  I formatted this column without decimal places to see full weeks of the first numbers Sunday.

  Quinn

• Excerpt from the hours between two dates

  Hello

  This is the value stored in the table of my database.

  I want to extract betwwen hours two dates. How can I extract it.

  I try to run like this

  Select to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM') double, but it gives the answer as the format 21:10:00.000000000 + 000000365

  I want simple hours, minutes, and seconds

  What is the format of this value as "dd-MON-yy."

  27 JANUARY 14 01.30.00.000000 PM

  26 JANUARY 14 06.22.32.170033 PM

  Use the Extract function. Like this.

  () AS T1 (C1)

  Select to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM') of double)

  SELECT EXTRACT (DAY OF C1) | ' DAYS '.

  EXTRACT (HOUR OF C1) | ' HOURS '.

  EXTRACT (MINUTE OF C1) | ' MINUTES '.

  EXTRACT (SECOND C1) | ' SECONDS

  FROM T1;

  OUTPUT:

  365 DAYS 21 HOURS 10 MINUTES 0 SECONDS

  If not try it.

  SELECT EXTRACT (DAY OF to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM')) | ' DAYS '.

  EXTRACT (HOUR FROM to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM')) | ' HOURS '.

  EXTRACT (to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM') MINUTE) | ' MINUTES '.

  EXCERPT ((SECOND from to_timestamp('27-JAN-14 05.30.00.000000 PM')-to_timestamp('26-JAN-13 08.20.00.000000 PM')) |) ' SECONDS

  DOUBLE;

  Post edited by: Parth272025

• How to find the difference between two dates in time except Sunday

  Hi all
  
  I have a table, as shown below.

  SQL> select * from test;
  
  TR_ID                                              CREATE_TIME                                                                       CODE
  -------------------------------------------------- --------------------------------------------------------------------------- ----------
  S12341                                             05-JUN-12 12.20.52.403000 AM                                                      1003
  S12342                                             11-JUN-12 11.15.33.182000 AM                                                      1003
  S12342                                             07-JUN-12 12.00.36.573000 PM                                                      1002
  S12343                                             20-JUN-12 12.34.37.102000 AM                                                      1003
  S12343                                             15-JUN-12 11.34.27.141000 PM                                                      1002
  S12344                                             01-JUL-12 10.01.06.657000 PM                                                      1002
  S12344                                             06-JUL-12 12.01.04.188000 AM                                                      1003
  S12341                                             31-MAY-12 11.20.38.529000 PM                                                      1002

  I would like to know the difference between same tr_ids create_time, which should give out in hours except Sunday.
  
  For example:
  
  TR_ID: S12344
  1002_Create_time: July 1, 12 PM 10.01.06.657000 (i.e. Sunday)
  1003_Create_time: 12.01.04.188000 AM 6 July 12
  
  1002 create time is 22:00 Sunday.
  
  If the query must exclude only the hours of Sunday which is 10 p.m. to Monday 00 h which is 2 Hrs.
  
  I tried the sub query after doing a search on this forum but I am not getting the desired output.
  

  SELECT count(*) FROM (SELECT ROWNUM RNUM,tr_id,create_time CT_1002 FROM test c WHERE c.tr_id='S12344' and 
  ROWNUM <= (select (cast(a.create_time as date)-cast((select create_time from test b where a.tr_id=b.tr_id and code=1002) as date)) 
  from test a where a.code=1003 and a.tr_id=c.tr_id) + 1) d 
  WHERE to_char(cast((select create_time from test e where e.tr_id=d.tr_id and code=1002) as date) + RNUM - 1, 'DY') NOT IN('SUN');

  Need help to get the desired o/p

  Hello

  If I unederstand the problem correctly, that's what you want:

  WITH       got_extrema     AS
  (
       SELECT       tr_id
       ,       CAST (MIN (create_time) AS DATE)     AS start_date
       ,       CAST (MAX (create_time) AS DATE)     AS end_date
       FROM       test
       GROUP BY  tr_id
  )
  SELECT       tr_id
  ,       start_date, end_date          -- If wanted
  ,       24 * ( ( ( TRUNC (end_date,   'IW')          -- Count -1 day for every full week
                      - TRUNC (start_date, 'IW')
               )
             / -7
                )
              + LEAST ( end_date               -- If end_date is a Sunday
                          , TRUNC (end_date, 'IW') + 6     -- consider it 00:00:00 on Sunday
                   )
              - CASE
                        WHEN  start_date >= TRUNC (start_date, 'IW') + 6     -- If start_date is a Sunday
                 THEN  TRUNC (start_date, 'IW') + 6               -- consider it 00:00:00 Sunday
                 ELSE  start_date
                    END
              )     AS total_hours
  FROM      got_extrema
  ;
  

  I guess that you don't need to worry about fractions of a second. As you did in the code you have posted, I am to convert the TIMESTAMP to date values, because of DATE arithmetic and functions are so much better than what is available for timestamps.

  Basically, it's just to find the number of days between start_date and end_date and multiplying by 24, with these twists:
  (a) 1 day is deducted for each week between start_date and end_date
  (b) if End_date is a Sunday, none of the end_date himself hours are counted
  (c) If start_date is a Sunday, then all the start_date himself hours are counted. Why these hours should be counted? Because 1 day is already being deducted for the week which includes start_date, which contains only this Sunday.

  TRUNC (dt, 'IW') is the beginning of the ISO week containing dt; in other words, 00:00:00 the or before the dt last Monday. This is not the NLS parameters.

  Of course, I can't test without some sample data and the exact results you want from these data. You may need a little something more If start_date and end_date are both on the same Sunday.
  Whenever you have a problem, please post a small example of data (CREATE TABLE and only relevant columns, INSERT statements) of all of the tables involved.
  Also post the results you want from this data, as well as an explanation of how you get these results from these data, with specific examples.
  Always tell what version of Oracle you are using.
  See the FAQ forum {message identifier: = 9360002}

• By selecting the difference between two images

  Hello

  I have two photos exactly the same thing that I took using a tripod, studio lighting and general conditions. However, in the second photo, I inserted a subject - in this case a sculpture complex. Photoshop can merge these two images together AND choose so the difference between the two images - in this case the sculpture complex?
  
  

  Basically, I need to select the sculpture and do not want to spend time manually selecting due to its complexity. I need to separate the background and the sculpture for editing on their own layers.

  Thank you

  Stephen-CS3

  You posted this in the two forums, its been answered in the mac forum.

• How to tell the difference between two dates

  Hello:
  
  I have a question on how to get the difference in quantities for two dates in the replies and dashboard.
  
  This is the scenario. I have two guests date and three columns. The first column must be the sum of the amounts for the first quick date. The second column should be the sum of the amounts for the second fast date. And the third column is the difference between the first two columns.
  
  Basically, I'm trying to do something similar to a function of sum of two lines but trying to get the difference between the two rows. Any help to solve this problem would be appreciated.

  Use the COLUMN FILTERS level...

  the first column with the first variable of date quick presentation of the filter

  Similarly, the second column in the second variable of quick overview of date filter

  Kind regards
  Rambeau

• How to calculate the hours between two dates by the numbers

  If I update 09:00 start time 17:00 end time of shift in C3 and B3, how to use a D3 formula to calculate the number of hours between the two?  Then I can just copy down the lines for nth years...

  It is a spreadsheet of the part-time staff payroll.

  I'm sure that a lot of people out there have done that.

  Help, please.

  Thank you.

  Eddie

  What program of worksheet that you are using? Since you have a newer iMac running El Capitan, I can safely assume that you use NOT AppleWorks, which is a Power PC application that can run on any OS newer than the snow leopard, OS X 10.6.8.

  If you use numbers, try to repost your question in numbers for Mac forum. If you use Microsoft Excel, try posting in the Microsoft forums. LibreOffice also has community support.

• Calculation of the sum between two dates

  Hello

  I had a requirement I need to calculate the total call volume between start and end date in the repository. Can someone help me with logic?

  Thank you

  Try this

  BOX WHEN DATE BETWEEN START_DATE AND END_DATE THEN

  END OF COUNT (CALL_VOLUME), 0 OTHERWISE.

  Thank you

  Sasi nanou...

• photo selection between two dates

  In Photos

  It is possible to select photos between two dates?

  In Photos,.

  is it possible to select the photos between two dates?

  Thank you, thank you

  Yes.  With a smart album like this: