pl sql join and select the join columns. """" t"" c": invalid when debugging
I noticed the error to the cc. Countries that appears because cc is not yet there at compile time (I had thatSearch this forum).
is it not a small bit of developer of sql oracle is not a compilation from the outside to the inside/core but
rather in the form of top-down?
I'm fine with my conclusion? If so, how to do otherwise, that is, by specifying that cc.country is
a column of countrycodes attached with table 6?
SELECT DISTINCT 0,
2,
SUBSTR ("metable', 0, 1"): "_ABC";
"ABC_". "metable,"
"ABC". CC. country,
'+'
FROM table 6
LEFT JOIN COUNTRYCODE cc
ON cc. Code = metable
WHERE metable IS NOT NULL
AND <>metable "
OK, but this:
SELECT DISTINCT 0,
2,
SUBSTR('metable', 0, 1) || '_ABC',
'ABC_' || 'metable',
'ABC ' ||cc.Country ,
'+'
FROM table6
LEFT JOIN COUNTRYCODE cc
ON cc.Code = metable
WHERE metable IS NOT NULL
AND metable ''
Is not a correct SQL statement - there are very obvious errors, so the error you get is maybe not quite relevant.
It works:
SELECT COUNT(cc.Country)
FROM table6
LEFT JOIN COUNTRYCODE cc
ON cc.Code = metable
WHERE metable IS NOT NULL;
So, get a simple query that works first.
Tags: Database
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Hello..
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Hello
SQL & gt; Select * from
version of v$.
BANNER
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Table 1 name: TEST1 _
Bq. LNID------NEW_AN8------OLD_AN8------OLD_DESC------2--------123002------100001------C2370------125846------CS24 100001------123024------100028------C2392------125868------CS25 100028------123025------C2393 100036------125869------100036 123026 CS26------100116------C2394------125870------100116------CS
_ Test2
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123 002 100 001 100 001 C
125 846 CS 100 001 100 001
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UPDATE LPLSCHEMA. LPL_F0101Z2_CUSTOMER C SET (SZAN82) =
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Published by: Ananda on January 2, 2009 18:30
Published by: Ananda on January 2, 2009 18:30
Published by: Ananda on January 2, 2009 18:34
Published by: Ananda on January 2, 2009 18:37UPDATE LPLSCHEMA.LPL_F0101Z2_CUSTOMER C SET SZAN82 = ( SELECT NEW_AN8 FROM LPL_CROSS_CUSTOMER B WHERE C.SZAT1='CS' AND B.OLD_DESC='CS' AND C.szan82=B.old_an8 ) WHERE EXISTS ( SELECT 1 FROM LPL_CROSS_CUSTOMER B WHERE C.SZAT1='CS' AND B.OLD_DESC='CS' AND C.szan82=B.old_an8 );
SY.
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Concerning
CORINE
Hi Maxence,
CORINE wrote:
Hello
I used this link http://carlback.blogspot.com/2007/09/mini-check-all-howto.html
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