Problem of coordinates on OS 4.6

Similar Questions

• VBAI: Problem of coordinate reference system

  In a stage of my VB AI application, I'm set a mark at the center of a circular object correctly.  In the next step, I do a 'find circular edge', including the "Reposition region of interest" value to a coordinate system.

  However, when the object is moving, and the coordinate system with it, find a circular RIM does not follow this coordinate system, but rather remains fixed in space.

  What should I do to have find a circular rim move with the coordinate system?

  Make sure that when you set up the step of the coordinate system, you put up-to-date in the X direction and Y. By default it puts just updated in the X direction, and even if the overlay appears updated in both directions, this can be misleading. If this isn't the problem, you can include a simple inspection with some images to illustrate how you got in this State.

  Thank you

  Brad

• problem with coordinates and child index

  

  Hi guys,.

  In my application I view contacts as card according to the image, so, for example, if the user clicks "Contact 2" he should come to "communicate with 3" position and "Touch 3" should return to "Contact 2" s.

  I've been swapping coordinated and child index of these sprites, but it didn't work like I wanted...

  can someone suggest a better logic?

  Thanks in advance

  Hi guys,.

  I solved it myself, silly me!

  All I had to do was:

  1. move the child 'index' to numChildren - 1

  2. move the numChildren child - 2 to "index".

  Phew!!!!!!!!!!!!!!!!

• coordinates of rotation problem

  Hello world

  I'll try to be clear, but I just have a problem with the coordinate on a rectangle of rotation.

  So, first of all, I have this data, and when I put in Excel I a rectangle to the right.
  

  SO now I know I need to change the data in the rotation, that's what I did.

  

  It worked great, I tried with graphic and to change the degree of rotation, it was perfect, I had good rotated rectangle.
  My next and last stop was just to put the coordinate to Excel and to reproduce the same rectangle on a chart in Excel.
  And that is where I met the problem.

  

  I have no idea why, and I don't see what to change to fix that...

  I now just a rotation of 90 degrees, it is sufficient to correct the position but where can change something?

  

  If somenody know something or have the solution, you are welcome.

  Sorry about that big post but I think is more clear with the image that more text.

  Thanks again for your answers (in advance)

  Maxim

  Direction of rotation?

  In Excel, it looks like a postive rotation causes rotation in the clockwise direction.

  I did not dig your math, but in many programs (such as Autocad), a rotation angle positive hour meter follows the right hand rule.  Where 0 is the + axis X and a line there turns towards the + Y axis with a + angle.

• Problem updating the coordinates of CC payment for teams

  Hello

  I tried these last weeks update my payment for my CC for subscription information teams. Whenever I click on the "Billing information Edit" button, I get the error message:

  We're sorry, something seems to go wrong on our end. Please try again later.

  I have tried to contact the customer service by phone to solve this problem, but gave up after 45 minutes on hold.

  Can someone please look at this?

  See you soon

  Hi dverschoylegs,

  I apologise for the inconvenience that you have been facing. Please see the Ko: http://helpx.adobe.com/x-productkb/policy-pricing/membership-subscription-troubleshooting-creative-cloud.html and contact our conversation of support in case of additional questions.

  Kind regards

  Romit Sinha

• coordinates annotation problem

  Hello

  When I add an annotation such as:

  annot var = this.addAnnot ();

  annot.setProps({)

  Author: "vshariphashvili."

  content: "my content"

  name: "myname"

  page: 0.

  print: true,

  Rect: [68.66091918945312,444.60260009765625,526.6072387695312,691.9005126953125],

  strokeColor: ['RGB', 1,0.5, 0.4].

  style: "S."

  type: "text",

  Width: 1

  });

  It works, my annotation is added, and when I print its properties without problem, they are complete

  When I add that highlight annotation, I add another cleaning too: quads

  annot var = this.addAnnot ();

  annot.setProps({)

  Author: "vshariphashvili."

  content: "my content"

  name: "myname"

  page: 0.

  print: true,

  quads: [238.6269989013672,691.4669799804688,356.6456298828125,691.4669799804688,238.626998901367 2,677.5950927734375,356.6456298828125,677.5950927734375,76.28500366210938,594.80078125,518 8671875,86.281005859375,548.6007690429688,508.9884033203125,548.6007690429688,86.281005859.983154296875,594.80078125,76.28500366210938,566.2410888671875,518.983154296875,566.241088 375,520.0410766601562,508.9884033203125,520.0410766601562,212.9290008544922,474.0547790527 344,382.34405517578125,474.0547790527344,212.9290008544922,445.4950866699219,382.344055175 78125,445.4950866699219],.

  Rect: [68.66091918945312,444.60260009765625,526.6072387695312,691.9005126953125],

  strokeColor: ['RGB', 1,0.5, 0.4].

  style: "S."

  type: "Select."

  Width: 1

  });

  annotation is added to the right bar (annotation list) not on my document and when I print its properties

  • I rect values such as: [-32768-32768 32768, 32768]
  • Quad is empty

  Why? What is the problem?

  I would like to start by learning more about the use of JavaScript for annotations of palce, Automation of positioning of Annotations by Thom Parker

  And I'd also look to see that the values in the script are numbers and not the strings of numbers. It seems that you have an overflow of integer.

• Coordinate - problem of learning system

  Hello

  I created a sample project to epxlain my problem.

  There are two paintings in the main application. OuterSpace canvas and canvas innerspace.

  innerspace canvas has a Visual Component 'mainBox '.

  and there is also a visual component in outerspace canvas named "overBox.

  now I want the card user xis - x and of y - xis overBox to mainBox, so when the user will click re - arrange, overbox will completely cover the mainBox.

  This is actually a problem of co-oridatane systems and I don't know how to map them into a single.

  Here's the code.

  The application file

  <?xml version="1.0" encoding="utf-8"?>
  <mx:Application xmlns:mx="http://www.adobe.com/2006/mxml" layout="absolute" xmlns:ns1="*">
       <mx:Script>
            <![CDATA[
                 
                      private function arrange(event:MouseEvent):void{
                           
                           var point:Point = mainBox.localToGlobal(new Point());
                           overBox.x = point.x;
                           overBox.y = point.y;
                      }          
                 
                 
            ]]>
       </mx:Script>
       
       <mx:Canvas width="80%" height="80%" horizontalCenter="0" verticalCenter="0" id="outerSpace" backgroundColor="#A9A9A9">
            <mx:Canvas width="80%" height="80%" horizontalCenter="0" verticalCenter="0" id="innerSpace" backgroundColor="#8DB5FF">
                 <ns1:Node horizontalCenter="0" verticalCenter="0" width="100" height="100" id="mainBox">
                 </ns1:Node>
            </mx:Canvas>
            <ns1:Node x="21" y="10" id="overBox" width="100" height="100" backgroundColor="#FFA352">
            </ns1:Node>
       </mx:Canvas>
       <mx:Button label="Re-Arrange" click="arrange(event)" left="10" top="10"/>
  </mx:Application>
  
  

  Project is also attached.

  Thank you

  Just see below. But it won't work if you resize the view, because it is centered

  private

  function arrange(event:MouseEvent):void

  {

  Get mainbox coord local system, i.e. from innerSpace

  var p1:Point = new Point (mainBox.x, mainBox.y);

  Convert to global coord of innerSpace

  var p2:Point = innerSpace.localToGlobal (p1);

  Convert local coord - from outerSpace

  var p3:Point = outerSpace.globalToLocal (p2);

  overBox.x = p3.x;

  overBox.y = p3.y;

  }

• problem of permutation of coordinates of PNG stored in table 2D

  Hello
  
  I use the class interactive png found here
  
  I am loading in the delivery date for an XML that is structured as follows
  
  <? XML version = "1.0"? >
  < theData >
  < _title_ > photos! < / _title_ >
  < __url__ > images / < / __url__ >
  < slides >
  < sub image = "images.png" region = "Region1" info = _url 'region 1 info - links to bbc' =' " http://www.bbc.co.uk ' xLoc = position"0"= image2 ="images2.png"/"0">"
  < / slides >
  < / name >
  
  the images are loaded into a loader and stored as interactivePNG. I give them an x, coord y but on working capital I need them to exchange contact information. I put the interactivePNG in available space in the regionArray that is stored in the mapArray.
  
  So I need to swap the png interactive currentTargets x and coordinate with the png interactive x and coordinate that is in the same regionArray but a position later. That is, if the first is mapArray [0] [8] I need to swap x and y with mapArray [0] [8]
  
  How can I get them to swap, I can't do... If tried to use indexOf the currentTarget in the mapArray, but it returns-1.
  
  Please help, thanks in advance
  
  Greg
  
  

  Try to create an empty class that extends from InteractivePNG and declare this class as dynamic:

  Dynamics/public class MyInteractivePNG extends InteractivePNG

  Then instantiate this new class and you will be able to add dynamic properties.

  TS

• IPhone problem

  Hi all

  Note: Hope I get appropriate reason and solution on your side against my phone or replacement of the device of m.

  Problems/questions :

  • Bbattery heating
  • Mobile suspension question
  • Suddenly phone operation at idle
  • Display problem
  • Does not properly
  • sound quality during the call and song speakers
  • Headset voice (songs in listen)
  • Heating
  • Hanging for mobile device
  • Charging problem

  My device coordinates: -.

  Product - iPhone 5 s

  Model - 5s IPHONE 16 GB GREY

  IMEI no - 352084072673492

  Serial number: DX5QW3LCFRC4

  Take a bar make genius with Apple for an assessment.

  FSAA (Apple authorized Service Provider) or your country.

• GPS coordinates that are deleted by the Application Photos

  Since June 2015, when I copy a photo in the Photos on my MacBook Pro app, it seems to remove the GPS data. More specifically,.

  • The photos are taken by a Nexus 5 phone. I don't have this problem when the pictures come from my partner's iPhone.
  • I have a MacBook Pro from 2014 (not retina that base).
  • I always run the latest version of Photos. The problem seemed only to appear in June last year. Before added photos then appear to be fine.

  I checked the original version of the photo that I stored in (Finder), and this seems to be very well. Only once I have copy in Photos and then look in the file that comes out, the GPS data are gone.

  Why is what happens, and is there a solution?

  Only once I have copy in Photos and then look in the file that comes out, the GPS data are gone.

  How do check you "files that come out?

  • The GPS coordinates are removed, if you export Photos photo with "file > export > export original unmodified for a single photo?
  • The GPS coordinates are removed, if you export Photos photo with "file > export > export 1 photo" and select "include location information?

  

  If you do not file > export, but the menu share, GPS information will be deleted, unless you enable 'Include the location information for published items' in the Photos > Preferences > general Panel.

• Premium HP: HP Premium - problems with the TRIANGLE_P command in the programs.

  I have version 2015 7 28 (8151) firmware and can not be updated any further because I have only the Android app.

  Maybe the next problem has also been fixed already in a more recent update, as a previous problem of mine. We'll see.

  I want a 3-dimensional triangle of the project on the screen using the advanced form of TRIANGLE_P.

  First the good news.

  The following program works:

  EXPORT experiment1
  
    BEGIN
  
       LOCAL P1, P2, P3;
  
       RECT_P();                   Clears the screen
  
  P1: = {100,100,75};
  
       P2: = {200,100,75};
  
       P3: = {100,200,225};
  TRIANGLE_P ({P1, P2, P3}, {{1,2,3, #FF}});
  GEL;
  
    END;

  Explanation: I define three dimensions 3 points P1, P2, P3 and insert them in a list in the triangle command. What are the angles of the triangle.

  In the second argument, I defined the triangle specifying these points in the first list indices, which are 1,2,3. #FF means that it is blue.

  Here is the result:

  

  It's not very spectacular, because the only thing that the program leaves the coordinate z points away and drawing of the triangle 2 dimensions resulting. So there is not a lot 3-dimensionality thereon. In fact nothing.

  Now, I'll try to do a little more complicated by the third argument, I have left aside until now. The first 2 arguments are the 2 lists of lists.

  The simplest form is a rotation matrix or list trivial-{1}:

  Syntax: TRIANGLE_P ([G], points_definition, triangle_definitions,

  rotation_matrix or {rotation_matrix or - 1, ["N"], [{eye_x, eye_y, eye_z}

  or - 1], [{3Dxmin, 3Dxmax, 3Dymin, 3Dymax, 3Dzmin, 3Dzmax}]}, [zstring])

  User manual

  The simplest rotation matrix is the identity matrix which consists of all zeros except the diagonal elements, which are 1. So I create this way M1.

  Now, I have replace the triangle command by:

  TRIANGLE_P ({P1, P2, P3}, {{1,2,3, #FF}}, M1);

  Or

  TRIANGLE_P ({P1, P2, P3}, {{1,2,3, #FF}}, {-1});

  "Two return output programs: ' error: invalid entry.

  "I tried several forms of the third argument, for example by specifying all possible sub arguments, but all what I try, I always get nothing else than: ' error: entry invalid.

  So I would like to know if if my firmware update is the cause, or I did something wrong or it is a bug.

  Hello

  I thought about it...

  The 'problem' is that, with only 3 entries in the first list and matrice matrix of a rotation, think the system, the first review, 3 3 points x, y parameters are, z coordinates for each of the 3 points. On second review, we see that they are not valid and an error. This stems from the fact that the Triangle can take so many different types of arguments and that it is not always easy to distinguish between the different forms.

  You can make sure the system interprets the input data in the form that you want to ensure that the list of the point has at least 5 Articles (even if they are not used). Then, he will work as in:

  EXPORT tt
  BEGIN
  LOCAL P1, P2, P3;
  RECT_P();                   Clears the screen
  
  P1: = {100,100,75};
  P2: = {200,100,75};
  P3: = {100,200,225};
  
  TRIANGLE_P ({P1, P2, P3, P1, P1}, {{1,2,3, #FF}}, [[0.5,1,0,0], [0,2,0,0], [0,0,1,0], [0,0,0,0]]);
  
  GEL;
  END;

  Cyrille

• Problem to claim a VI help script DIADEM

  I get the "LabVIEW: the VI is not executable...» "error message when you try to load a VI using DIAdem scripts. However, the VI loads and runs fine when it runs from labview. I've isolated the problem to a sub VI called "Cartesian coordinates 3D Rotation (branch) VI. This VI is packed with labview and is in the "palette geometry of screws.  If I remove this subroutine VI, then the VI I want to call is in charge within the tiara. Any idea to do this job properly would be appreciated.

  Thank you.

  Hi PRinOR,

  You do 2 things just right.  You must create a source distribution that includes all the SubVIs, even those of vi.lib, and you must match the LVRuntime.Init version exactly with the LV of the VI version that you load.  I noticed in your VBScript post that you do not specifically set the LV version, but take the default value.  Have you managed to call a simple VI of tiara which has no SubVIs, like a VI that adds 2 numbers?

  Brad Turpin
  Tiara Product Support Engineer
  National Instruments

• Space coordinate in LabVIEW

  Hello

  I use the getting started with NI 951 x Modules in the series C and LabVIEW tutorial and I can't seem to make it work. I followed step by step and when I clicked on run on the front, I got the following error. Error code: 70028

  Linear displacement during the definition of the position [] on the test Section.
  The resource is not large enough to perform the specified operation.

  «"" "String of full appeal:»»"»
  nimc.getLastErrorOnInterface.vi
  nimc.fb.straightLineMove.startStraightLineMove.coordinate.modeAbsolute.0.vi:1
  Straight line move 2. VI

  I didn't create a 3-axis coordinate space and tutorial for two calls. I tried to remove one axis and by using only two, but that did not work. My diagram looks the same as that of the example except that I seem to have only a SINGLE coordinated in my system (notice down left the wire connected to the position [] has only one box coordinated instead of two as in the example). I tried to leave and the recreation of the coordinate axis and the VI with the same result. Am I missing something? It seems that my coordinate system appears in table 1 x 0 instead of a table 1 x 3 or something?

  I tried to restart the cRIO and start a whole new project, essentially from step 1 excluding the installation of the software on the cRIO. Please let me know if you have any advice or have had the same problems. Thank you

  
  

• HP Envy 15 1195eo problem of USB Ports!

  I am facing a problem with my usb ports on my HP Envy 15 1195eo. I tried a number of things to make them work, but nothing did. Basically, when I connect a usb device, it will connect, stay tuned for a very few seconds, then disconnect for a few seconds and then connect for a few seconds again, and he repeats like that of infinity. So I'd like prompting assistance works again!

  News of the computer:

  Model: HP Envy 15-1195eo

  OS: Windows 7 64-bit

  Hello again Unboxeremail.

  That solves the problem at the origin?  This can be useful information.

  I took a look inside the laptop and noticed three ports (2 ports standard right) USB and eSATA/USB port a combination on the left, what port is non-functional?  In addition, the image of the motherboard indicates that the USB ports are not on a panel separated from the motherboard so a connection problem is very unlikely here.

  

  Do you have a multimeter?  Check the USB port to see if the connection is down at random would check it like a hardware problem.
  
  If the problem persists after a new installation of Windows, then this indicates a hardware problem.  This laptop is guaranteed?  You can see here.  If it is under warranty, you should contact HP support and let them know about the issue. The number for US / Canadian customers is 1-800-474-6836.  If you are in another part of the world, you visit HP's Support around the world to find the coordinates for your region.

• Coordinates of a VI within the secondary screen

  Hello

  I have a problem with the Panel function convert to the screen coordinates. If a VI is inside a secondary, this function return wrong coordinates. Otherwise, this function works correctly.

  Attachments explains the error.

  Hi Bruno.

  I did a test using a different approach, and it looks like ok for me, try to replace your V2.vi by the attached file.

  Kind regards