Procedure to extract several substring of a string

Similar Questions

• Extract the substring of the string

  For the life of me I can not find a function to extract a substring of an existing string.  The closest I could find was SearchSplit String and replace substring, but none of them do what I want.

  That's what I want to do:

  Assuming that the string "Test String", the letters are in positions as follows:

  T e s t _ S t r i e n t
  0 1 2 3 4 5 6 7 8 9 10

  Now correct the substring offset 5 on position 7 (length 3):

  Substring = r t S

  5 6 7

  In Java, for example, you can easily do this using the code below:

  String str = "Test String";

  Substring of String = str.substring (5.7);

  There are no simple function to do this in LabVIEW?  If not, what is the best way to do it?

  Use String subset of index 5 and length 3.

• How to extract the same part of the substring of two strings?

  How can I retrieve the first identical substring of two strings?
  version: 10 gr 2
  as for example:

  Given:
  str1: randomStringWith123abc
  str2: randomStringfor345abc
  
  Get:
  substr:randomString
  
  Given:
  str3: dummyhowareu
  str4: dummyiamfine
  
  Get:
  substr:dummy

  As you can see, the size of the substring is unknown.
  
  any ideas?

  Hello

  something like this:

  with x as (select 'dummyhowareu' str1, 'dummyiamfine' str2 from dual)
  select replace(str1,ltrim(str1,str2))
  from x
  

  Herald tiomela
  http://htendam.WordPress.com

• How to extract a substring of the subject of actionEvent.getSource ()?

  Hello
  
  I am trying to extract a substring of the form actionEvent.getSource (), but when I use the javascript substring it works doesn´t work. It sounds simple, but it does not work.
  When I apply alert (actionEvent.getSource ()) it produces ' AdfRichCommandToolbarButton [oracle.adf.RichCommandToolbarButton] id = zoomine, but when
  It is used with actionEvent.getSource () .substring (1, 5), it doesn´t work.
  
  It's the code of the function:
  
  function tClick (actionEvent)
  {actionEvent.cancel ();
  eventSource var = actionEvent.getSource ();
  var x = eventSource.substring (1, 5);
  Alert (x);
  }
  
  Can someone help me?
  
  Thank you
  
  Ku

  The problem is that actionEvent.getSource () returns a string. It returns an object.
  try actionEvent.getSource (m:System.NET.SocketAddress.ToString () .substring (1, 5))
  or even better explain what you are trying to archive. We can help you get a better solution to your problem.

  Timo

• Extract an a piece of string starting with a number

  Hello
  
  I'm new to SQL, I can use some help with the following problem. I need to extract the number of contract of a string, but the position of the contract number and the text inside the string may vary, which means that it is important to link the SELECT statement with the number. Extract only numbers would help too, because the contract number contains letters and other characters. For example, if there is a "Payment for a contract nr 1100/70HE" string, the SELECT statement must be able to extract only '1100/70HE' this string.
  
  Thank you in advance,
  Keit

  1007555 wrote:
  The first three characters of a certain number of contracts are always numbers. If the application needs to find a piece of string, where three characters are numbers. The global chain can look like 'Payment for a contract number 1100/70HE', "Payment of 1100/70HE of the contract", "1100/70HE contract payment" etc. I hope that clarifies it a bit.

  SQL> ed
  Wrote file afiedt.buf
  
    1  with t as
    2   (select '"Payment to a contract nr 1100/70HE payment' as str from dual)
    3  select regexp_substr(str,'[0-9]{3}[^ ]+') con
    4* from t
    5  /
  
  CON
  ---------
  1100/70HE
  {code}                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                
  

• How can I extract a substring in WHERE Clause < CFQUERY >?

  Is it possible to extract a substring in the WHERE clause of either < CFQUERY > or in a query of queries?  I try to use the following query to find all e-mail addresses with the domain "comcast.net" (i.e., everything that follows the '@' in the email address).  I ask an MS-Access database table.

  < cfquery name='test' datasource='membership'>
  SELECT Email_address
  OF tblMembers
  WHERE the MID (email_address, INSTR (email_address, ' @') + 1) = "comcast.net"
  < / cfquery >

  
  

  If I try this as a query, I get the error message "[Macromedia] [SequeLink JDBC Driver] [ODBC Socket] [Microsoft] [ODBC Microsoft Access driver] data type incompatible in criteria expression."

  
  

  If I try it as a t/t, I get the error message " " Met 'MID (e-mail1.,. Incorrect conditional expression, waiting for one of [as | null | between | in | comparison] condition,'.

  I would be very grateful for any help on finding something that works!  Thanks for your help!

  
  

  You couldn't do a LIKE in where clause instead:

  SELECT Email_address

  OF tblMembers

  WHERE email_address LIKE ' %@comcast.net'

  You should get the addresses you're looking for.

  -Carl V.

• Procedure to insert several lines

  create or replace procedure relevent_doc_after_insert (JOBNUMBER IN varchar2,
  DOCNAME IN VARCHAR2)
  IS
  PRAGMA AUTONOMOUS_TRANSACTION;
  vDocName VARCHAR2 (80);
  
  CURSOR insertAfterdata
  IS
  SELECT mnd_doc_name
  OF clm_min_doc_to_process
  WHERE mnd_doc_name! = DOCNAME;
  
  
  BEGIN
  OPEN insertAfterdata.
  LOOP
  EXTRACTION insertAfterdata
  IN
  vDocName;
  
  EXIT WHEN insertAfterdata % NOTFOUND;
  
  INSERT INTO clm_relevent_doc (rd_id,
  rd_job_no,
  rd_doc_name,
  rd_created_user,
  rd_created_date,
  rd_status)
  VALUES (relevant_doc_sequence. NEXTVAL,
  JOBNUMBER,
  vDocName,
  'system ', he said.
  To_char (SYSDATE, "yyyy-mm-dd HH12:MI:SS"),
  'pending');
  
  COMMIT;
  END LOOP;
  CLOSE InsertAfterdata;
  
  EXCEPTION
  WHILE OTHERS THEN
  NULL;
  
  END;
  
  
  
  Above is my procedure
  
  I pass below the settings during the execution
  JOBNUMBER = 123
  DOCNAME = driving licence
  
  
  
  When the CURSOR query get the 3rows as a result but insert several rows in the clm_relevent_doc table, why did this happen.

  It does not work properly, is it not? If this isn't the case, then please point where.

  Also as knani questioned, and so I did (although not confirmed), you really need the independent transaction? can you justify using autonomous transactions, in this procedure?

  select *
    from clm_min_doc_to_process;
  
  MND_ID                 MND_DOC_NAME       MND_DOC_CODE
  ---------------------- ------------------ --------------------
  1                      Driving Licence    DL
  2                      SA Report          SARPT
  3                      Estimate           EST
  4                      Photos             PHOT    
  
  select *
    from clm_relevent_doc;
  
  RD_ID                  RD_JOB_NO       RD_DOC_NAME    RD_CREATED_USER   RD_CREATED_DATE  RD_ADD_DOC_NAME  RD_UPDATE_USER   RD_REQUEST RD_REQUEST_METHOD RD_STATUS RD_RECEIVED_DATE_TIME
  ---------------------- --------------- -------------- ----------------- ---------------- ---------------- ---------------- ---------- ----------------- --------- --------------------- 
  
  set serveroutput on;
  begin
    relevent_doc_after_insert(123, 'Photos');
  end;
  
  anonymous block completed
  3 rows inserted
  
  select *
    from clm_relevent_doc;
  
  RD_ID                  RD_JOB_NO       RD_DOC_NAME     RD_CREATED_USER RD_CREATED_DATE     RD_ADD_DOC_NAME RD_UPDATE_USER RD_REQUEST RD_REQUEST_METHOD RD_STATUS RD_RECEIVED_DATE_TIME
  ---------------------- --------------- --------------- --------------- ------------------- --------------- -------------- ---------- ----------------- --------- ---------------------
  1                      123             Driving Licence system          2013-01-21 06:43:23                                                             pending
  2                      123             SA Report       system          2013-01-21 06:43:23                                                             pending
  3                      123             Estimate        system          2013-01-21 06:43:23                                                             pending                        
  

• Need help to extract the data into a string of separate brackets

  Hello
  
  I have a scenario where I have to extract data into a string that is enclosed in [].
  
  Here's what I want to do...
  
  entry:
  
  [name_first] [name_mi] [name_last]
  
  required output: this must return all data that are placed between square brackets.
  name_first
  name_mi
  name_last
  
  I tried the "REGEXP_SUBSTR' but my version of the database is 9i, and it is available only from 10 g.
  
  Thanks in advance.

  Hello

  You can use SUBSTR and INSTR
  This should work in Oracle 9:

  WITH     cntr     AS
  (
       SELECT     LEVEL     AS n
       FROM     dual
       CONNECT BY     LEVEL <= 3
  )
  ,     got_pos          AS
  (
       SELECT     x.txt
       ,     c.n
       ,     INSTR (x.txt, '[', 1, c.n)     AS l_pos
       ,     INSTR (x.txt, ']', 1, c.n)     AS r_pos
       FROM           table_x  x
       CROSS JOIN    cntr     c
  )
  SELECT        txt
  ,        n
  ,        SUBSTR ( txt
                 , l_pos + 1
              , r_pos - (l_pos + 1)
                 )     AS sub_txt
  FROM        got_pos
  ORDER BY   txt
  ,             n
  ;
  

  Sorry, I don't have an Oracle 9 database now; I had to test this in Oracle 10.

  jimmy437 wrote:
  ... I tried the "REGEXP_SUBSTR' but my version of the database is 9i, and it is available only from 10 g.

  It's true. Regular expressions are very useful, but they are not available in Oracle 9 (or earlier).
  Oracle 9 has a package supplied by Oracle, OWA_PATTERN, which provides regular expression features:
  http://docs.Oracle.com/CD/B12037_01/AppDev.101/b10802/w_patt.htm
  I know it's the Oracle 10, documentation, but there are in Oracle 9, too.

  Oracle 9 is very old. You should consider the upgrade.

• Extraction of the bracketed text string data

  I have a bit of SQL to retrieve the text in brackets at the end of a string:
  

  WITH test_data AS
       (
       SELECT 'Joseph Bloggs (Joe) (THIS)' v1 FROM DUAL UNION ALL
        SELECT 'Robert Holnas (Bob) (THAT)' FROM DUAL UNION ALL
        SELECT 'Mary Mild (THIS)' FROM DUAL UNION ALL
        SELECT 'Jack Jill (THIS)' FROM DUAL
       )
  SELECT v1
      , INSTR(v1, '(') start_bracket_pos
      , INSTR(v1, ')') end_bracket_pos
      , TRIM(SUBSTR(v1,INSTR(v1, '(')+1,INSTR(v1, ')')-INSTR(v1, '(')-1)) current_label
      , (LENGTH(v1) - LENGTH(REPLACE(v1, ')'))) / LENGTH(')') "ct_("
      , (LENGTH(v1) - LENGTH(REPLACE(v1, ')'))) / LENGTH(')') "ct_)"
    FROM test_data;

  Still, it extracts data from the media at the end of the string.
  
  I was wondering if I can change it to be able to extract the text between for example two sets of brackets - for the above test data, it would be useful to be able to extract the 'Joe' and 'Bob', but also 'CE' and 'WHO' at the end as well. It would be useful to have a column that contains the first support content and the 2nd set of content in another column.
  
  Is there a switch that I can use for example an INSTR() to return the position of the first open bracket and the 2nd and so on?
  
  Any advice much appreciated
  
  Thank you

  A way, using reg exp:

  SQL> WITH test_data AS
    2       (
    3       SELECT 'Joseph Bloggs (Joe) (THIS)' v1 FROM DUAL UNION ALL
    4        SELECT 'Robert Holnas (Bob) (THAT)' FROM DUAL UNION ALL
    5        SELECT 'Mary Mild (THIS)' FROM DUAL UNION ALL
    6        SELECT 'Jack Jill (THIS)' FROM DUAL
    7       )
    8  SELECT v1
    9      , regexp_substr(v1,'\((.*?)\)',1,1,null,1) bracket1
   10      , regexp_substr(v1,'\((.*?)\)',1,2,null,1) bracket2
   11    FROM test_data;
  
  V1                         BRACKET1                   BRACKET2
  -------------------------- -------------------------- --------------------------
  Joseph Bloggs (Joe) (THIS) Joe                        THIS
  Robert Holnas (Bob) (THAT) Bob                        THAT
  Mary Mild (THIS)           THIS
  Jack Jill (THIS)           THIS
  

  The regular expression find something in parentheses (the? makes not greedy, it's important.)
  1 means start over from the beginning of the string.
  Next number means bracket1 "first occurrence", bracket2 is "second occurrence" - you can continue with 3, 4, etc.
  null value uses only the default options for reg exp (here could be option for example for sensitive cases in search).
  Final 1 means that the result is the first 'group' in the reg exp - this only receives us the text in brackets and not the media themselves.

• extract a portion of a string in a complete chain

  Hello
  
  I have a large string separated by "->" character. In my case I want to extract the characters between the 2nd and 3rd "->", characters after 4th "->". I tried a lot of location functions but could not achieve what I wanted. Help, please.
  
  Example of
  
  John->->-> Roger Sam Robert
  
  to get the Sam as a value in the column and Roger in column B. There is also a special case like a few times, I have only
  
  John-Robert-> Sam >
  
  And want to get Sam in column A and not specified in column B.
  
  Thank you
  Ravi

  Hi Ravi,

  The functions below can be used to achieve this:

  Locate (str1, str2)
  Locate(str1,str2,startPost) - Note We use Locate and not LocateN
  SUBSTRING (long expr FOR startPos)

  Assuming that your string is - John-> Robert-> Sam-> Roger. To find

  first position (FP) of->: LOCATE('->','John->Robert->Sam->Roger') //pos = 5
  second position (SP) of->: LOCATE ('->', 'John-> Robert-> Sam-> Roger', LOCATE('->','John->Robert->Sam->Roger') + 2) / / pos = 13
  -> third position (TP): LOCATE ('->', 'John-> Robert-> Sam-> Roger', LOCATE ('->', 'John-> Robert-> Sam-> Roger', LOCATE ('->', ' John-> Robert-> Sam-> Roger') + 2) + 2) //pos=18

  Your A pass where you get Sam, we need to check first if it the 3rd-> present or not. To do this, we verify the existence of the third position (TP) of->. If it is not present TP returns 0 your fx should be like:

  -case when TP = 0 then
  FOR the Substring('John->Robert->Sam->Roger' from (SP + 2) (length ('John-> Robert-> Sam-> Roger') - (SP + 1)))
  on the other
  SUBSTRING ("John-> Robert-> Sam-> Roger" (SP + 2) FOR ((TP-2) - SP))
  end

  Your pass B where you get Roger, we need to check first if it the 3rd-> present or not. To do this, we verify the existence of the third position (TP) of->. If it is not present TP returns 0 your fx should be like:

  -case when TP = 0 then
  NULL VALUE
  on the other
  For the Substring('John->Robert->Sam->Roger' from (TP + 2) (length ('John-> Robert-> Sam-> Roger') - (TP + 1)))
  end

  Replace the PS, SP and TP with real functions mentioned at the beginning. Also, replace the string with the name of your actual column.

  It really works, but there may be better ways to do it.

  Thank you

• Use INSTR to extract a piece of the string?

  The guys from morning and Happy Friday.
  
  I have a situation where I have to take advantage of the string by using a select statement.
  
  Here's the chain I have to get the content between the 2nd and 3rd backslash. So basically I have to extract marypoppins. Any ideas?
  

  C:\USERS\marypoppins\Docs\Specification

  Here's where I started... and I've fallen on trying to find the 3rd backslash. I can easily start the INSTR 4 because I know that he will always be "C:\". »

  select select substr(C:\USERS\marypoppins\Docs\Specification',
                              INSTRB('C:\USERS\marypoppins\Docs\Specification', '\', 4), .....) from dual;

  WITH abc AS
       (SELECT 'C:\USERS\marypoppins\Docs\Specification' a
          FROM DUAL)
  SELECT SUBSTR (a,
                 INSTR (a, '\', 1, 2) + 1,
                 INSTR (a, '\', 1, 3) - INSTR (a, '\', 1, 2) - 1
                )
    FROM abc;
  

• How to extract the time to a string with lots of information?

  Well guys,.

  I have a question here...

  I need to extract only the TIME to a string. But that chain has a lot of information

  as a 'Identification' text data and time...

  This "Identification" may be only letters or numbers or words of 2 or 3...

  Anyone know a good way to do that?

  I tried:

  

  But only works if 'Identification' is only 1 Word...

  I'm using LabVIEW 7.1

  and the format is: ID - 14/04/2010 - 13:32:25

  Thank you

  Regular expression matching is available in 7.1?

  

  Match pattern works, too.
  

• Extract text from a text string

  I have this text in a text field: "555-555-5555 PAUL ADRIANO 11596 MAIN ST 03/01/2013" there at - there a way for me to extract just the phone number and put in another field of own text?

  Sure. In this case, you can divide the string with the comma as a delimiter and then deal with the elements in the resulting table.

  It will look something like this:

  var myString = "702-555-5555,GASTELUM NOEL & GALLEGO-EGURROLA MARIBEL,1328 N SLOAN LN,1/4/2013";
  var items = myString.split(",");
  if (items.length==4) {
      var phoneNumber = items[0];
      var name = items[1];
      var address = items[2];
      var date = items[3]
  }
  

• How to upgrade to the substring of a string value?

  UPDATE table1
  SET  SUBSTR  (TO_CHAR(field_value),3,2) = ' 50'  and SUBSTR (TO_CHAR(field_value),5,2)  =  '50'
  where  ( SUBSTR(TO_CHAR(field_value), 3, 2) =  '100' ) or ( SUBSTR(TO_CHAR(field_value), 5, 2) =  '100' )

  tried that precedes a TOAD and I had ' ORA-00927: lack of equal sign. " Help, please!
  
  data type for field_value's number. is version of Oracle 10 g
  
  Thank you

  Here is an example of how you can do:

  SQL> CREATE TABLE x
    2  AS
    3  SELECT 'SOME50HERE' AS field_x
    4  FROM dual;
  
  Table created.
  
  SQL> SELECT * FROM x;
  
  FIELD_X
  ----------
  SOME50HERE
  
  1 row selected.
  
  SQL> UPDATE x
    2  SET    field_x =  SUBSTR(field_x,1,4)
    3                 || '75'
    4                 || SUBSTR(field_x,7)
    5  ;
  
  1 row updated.
  
  SQL> SELECT * FROM x;
  
  FIELD_X
  ----------
  SOME75HERE
  

  Basically, it must break your string into three parts:

  1. the foregoing text you want to change.
  2. the text that you want to change.
  3. the part after the text you want to change.

  Then you concatenate them all together.

  If #1 is not a fixed number of characters, you can still use SUBSTR, by searching for the string you want to edit as follows:

  UPDATE x
  SET    field_x =  SUBSTR(field_x,1,INSTR(field_x,'50') - 1)
                 || '75'
                 || SUBSTR(field_x,7)
  ;
  

• Substring of a string in report

  Hello
  I have some values such as ' / shared, outstanding, _portal, outstanding ' & ' shared/SalesAnalytics/_portal/sales' under a column in OBIEE report.
  Now instead of display the full path to the result I want to display only the string after the _portal/"...like"in the above case.
  
  'Outstanding' & 'dirty '.
  
  Please let me know how can we achieve this in the answers?
  
  Thank you

  Hi user,

  Try something like this,

  Substring ("YourColumnName" of (position (in 'YourColumnName', ' _') + 8))

  Rgds,
  DpKa