Extract the substring of the string
For the life of me I can not find a function to extract a substring of an existing string. The closest I could find was SearchSplit String and replace substring, but none of them do what I want.
That's what I want to do:
Assuming that the string "Test String", the letters are in positions as follows:
T e s t _ S t r i e n t
0 1 2 3 4 5 6 7 8 9 10
Now correct the substring offset 5 on position 7 (length 3):
Substring = r t S
5 6 7
In Java, for example, you can easily do this using the code below:
String str = "Test String";
Substring of String = str.substring (5.7);
There are no simple function to do this in LabVIEW? If not, what is the best way to do it?
Use String subset of index 5 and length 3.
Tags: NI Software
Similar Questions
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I'm trying to extract the strings and load them into a text-helpplease file
I'm trying to extract the strings and load them into a file text without space between them - see below
p_csa = ISCC M4 DP
where p_csa is a tring to load into a text file
Code:
SELECT SUBSTR (p_csa, 0, 0) INTO v_telco FROM DUAL;
SELECT SUBSTR (p_csa, 1, 4) INTO v_comp FROM DUAL;
SELECT SUBSTR (p_csa, 5.3) INTO v_csa_prefix FROM DUAL;
SELECT SUBSTR (p_csa, 8, 4) INTO v_csa_type FROM DUAL;
fileidinvoice: = UTL_FILE. FOPEN (c_data_location, filenameinvoice, 'W');
fileidlog: = UTL_FILE. FOPEN (c_data_location, filenamelog, 'W');
UTL_FILE. PUT_LINE)
fileidinvoice, v_telco | » '|| v_comp | "|" | v_csa_prefix: "| v_csa_type);
-the content of the file-
ISCC M4 DP
=====================
I want to remove the space between the chain above for the content of the file should look like this:
-the content of the file-
GCSIM4DPHello
976253 wrote:
I'm trying to extract the strings and load them into a file text without space between them - see belowp_csa = ISCC M4 DP
where p_csa is a tring to load into a text file
Code:
SELECT SUBSTR (p_csa, 0, 0) INTO v_telco FROM DUAL;
Is it always NULL?
SELECT SUBSTR (p_csa, 1, 4) INTO v_comp FROM DUAL;
You don't need the double table much in PL/SQL. You can simply say
v_comp := SUBSTR (p_csa, 1, 4);
Almost all integrated single-row functions work in PL/SQL. (NVL2 is the only one I know who does not work in PL/SQL).
SELECT SUBSTR (p_csa, 5.3) INTO v_csa_prefix FROM DUAL;
SELECT SUBSTR (p_csa, 8, 4) INTO v_csa_type FROM DUAL;fileidinvoice: = UTL_FILE. FOPEN (c_data_location, filenameinvoice, 'W');
fileidlog: = UTL_FILE. FOPEN (c_data_location, filenamelog, 'W');UTL_FILE. PUT_LINE)
fileidinvoice, v_telco | » '|| v_comp | "|" | v_csa_prefix: "| v_csa_type);What are you trying to do here? For example, what you're trying to put between c_comp and v_csa_prefix?
-the content of the file-
ISCC M4 DP
=====================
I want to remove the space between the chain above for the content of the file should look like this:-the content of the file-
GCSIM4DP
If you don't want space, then only concatenate all the spaces in the string before you write it and REPLACE allows you to delete all the spaces that have been copied from p_csa. For example:
UTL_FILE.PUT_LINE ( fileidinvoice , REPLACE ( v_telco || v_comp || v_csa_prefix || v_csa_type , ' ' ) );
I guess you need the v_comp of separate variables, the v_csa_prefix and the v_csa_type for something.
I hope that answers your question.
If this isn't the case, after a complete script that people can run to recreate the problem and test their ideas. Display the results you want (in other words, the contents of the file created).
Always say what version of Oracle you are using (for example, 11.2.0.3.0).
See the FAQ forum {message identifier: = 9360002} -
Analyzes the string and extract the string delimiter
Hello
Basic questions. Is this possible with the scan of regular expression of the string to extract the string that are in the specified delimiters. Here is an example:
Name of the \\Name of the folder 1\Name to the folder 2\Name to the folder 3\File
Chain analysis can produce the following by specifying the regular expression on the right:
1 folder name
Name of the folder 2
Name of the folder 3
File name
I tried \\\%s\\%s\\%s\\%s but the %s stops on the first white space.
Thank you
Michel
RavensFan suggested the service appropriate for your condition, but you can also use an alternative, which is "spreadsheet of array of strings.
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Extract the string from the chain - separator = ' | '?
Hi people!
I want to know how to extract the a string with delimiter = XE field ' |'.
For example:
String = "field1 |" Field2 |... | fieldX |... | filedn | »
I want to extract fieldX.
Thanks for your help, regards.Use the functions like this substr and instr
substr(string, instr( string,'|', 1, xth_occurrence)+1, instr( string,'|', 1,xth_occurrence+1) - instr(string,'|', 1, xth_occurrence))
Luca
Please, mark the reply as useful/correct if it is
Published by: Luka on January 26, 2010 10:42
Published by: Luka on January 26, 2010 10:42
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extract the string reg expression?
How to extract P '89' 84 of this field?
CSOM 50, HON 93, P '89' 84 JASPER YOUR L
The string P I could start anywhere in the string, but is always followed by an apostrophe. It could be any length with a series of apostrophes and the years ending with a white or the end of the field.
I think that regular expressions should solve this problem, but I can't understand it. Any help is appreciated.Hello
Here's one way:
REGEXP_SUBSTR ( txt , 'P' || -- The letter P '(' || -- Begin \1 '''' || -- apostophe '[0-9]+' || -- 1 or more digits (see below for alternative) ')+' || -- End \1, which may occur 1 or more times '( |$)' -- Either space or end-of-string )
If the years must be exactly two digits, then change the line 5 to:
... '[0-9]{2}' || -- exactly 2 digits
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Procedure to extract several substring of a string
Hi all
I was wondering how can I extract substring of a string. I would write a procedure to update data in the table and by mistake if the string doesnot match the pattern.
Example of a string: [1594374: "SFD"] [1597251: 'TTT'] [1601085: 'SSS']
Using this channel, I would update as table 'test' which has columns ID and TYPE.
Updates of the statements will be:
UPDATE TEST SET type is 'DFS' where id = 1594374;.
UPDATE TEST SET type is 'TTT' where id = 1597251;.
UPDATE TEST SET type is 'TTT' where id = 1597251;.
I would be grateful if someone could help me with this.
Thank youSQL> create table test( 2 id number, 3 type varchar2(10) 4 ) 5 / Table created. SQL> insert into test(id) values(1594374) 2 / 1 row created. SQL> insert into test(id) values(1597251) 2 / 1 row created. SQL> insert into test(id) values(1601085) 2 / 1 row created. SQL> select * from test 2 / ID TYPE ---------- ---------- 1594374 1597251 1601085 SQL> merge 2 into test a 3 using ( 4 select ltrim(regexp_substr('[1594374:''DYC''][1597251:''TTT''][1601085:''SSS'']','\[(\d+)',1,level),'[') id, 5 ltrim(regexp_substr('[1594374:''DYC''][1597251:''TTT''][1601085:''SSS'']',':''[^'']+',1,level),':''') type 6 from dual 7 connect by level <= length(regexp_replace('[1594374:''DYC''][1597251:''TTT''][1601085:''SSS'']','[^[]')) 8 ) b 9 on (a.id = b.id) 10 when matched 11 then 12 update set a.type = b.type 13 / 3 rows merged. SQL> select * from test 2 / ID TYPE ---------- ---------- 1594374 DYC 1597251 TTT 1601085 SSS SQL>
SY.
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Extract the string from the string
Hello guys,.
I have a small question. I would like to extract a string to another string. Imagine the following string:
param1 = value1 param2 = value2, param3 = value3, param4 = value4
I would like to be able to extract value2 and value3 to this string. I know that the design of the db is not perfect and should be like this. but it is historical and I have to use this way. Any suggestion?
Thank you
to retrieve param2
Select
substr (s
, instr (s, '=', 1, 2) + 1
, instr (s, ',', 1, 2) - instr (s, '=', 1, 2) - 1
) r
from (select "param1 = value1 param2 = value2, param3 = value3, param4 = value4's double)
or
Select regexp_substr (your_string, "[^,] +' 1, 4") from your_table
for example
Select regexp_substr ("param1 = value1 param2 = value2, param3 = value3, param4 = value4 ',' [^,] +' 1, 4") param2 double
PARAM2
'value2 '.
Post edited by: chris227
Corrected solution substr (sorry was before the first coffee ;-)) -
How to extract the string values
Hello
Database: 11.2.0.3.0
I have a JSON string like below. I want to extract only the propetyvalues. Can you help me with the query:
{
'documents':]
{
'document':]
{
'propertyname': 'Id',
'propertyvalue': "{1C236CB2-AB97-4982-8117-DE0BE6D7DB46}".
}
]
},
{
'document':]
{
'propertyname': 'Id',
'propertyvalue': "{1318AC90-C321-4D3D-9558-6547EFE49A7E}".
}
]
}
]
}
Hello
Too bad, that you do not have version 12. Then, you can use the function JSON_VALUE mentioned previously.
Here's something you can do in your version:
SELECT LEVEL AS n
, REGEXP_SUBSTR (: str)
, ' "propertyvalue": "([^"]*) "
1
LEVEL
NULL
1
) AS propertyvalue
OF the double
CONNECT BY LEVEL<= regexp_count="" (:str,="">=>
;
If you want to know that adapts to your specific problem, post CREATE TABLE and INSERT statements for some sample data and the exact results you want from these sample data.
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I know that I did it in before CVI...
Only, I don't remember how I did it...
(braindead today?!?)
Here goes:
Take a string:
"Mary had a little lamb".
FindPattern "little."
resulting string: "" Mary had a lamb.
What I have works to find the model and it is place.
-sigh-
I know I'll get because from what I remember, this is a very simple solution... I can't just think of him...
And I vaguely remember the name of the function that I used...
R
You could try something like this:
-
Retrieve the string after the symbol @.
Hello
I need a suggestion how to extract the string after the symbol ' @' in the string.
The user will pass the Email that I need to extract the domain name of the string
> > Eg: [email protected]
She must return to gmail.com under the domain name, please suggest me
Thank you
SudhirTry:
select substr('[email protected]', instr('[email protected]', '@')+1) from dual
-
Problem with regexp_substr if the string with null values between commas.
Hi all
My version of DB is 10.1.0.5.0
I want to extract the string values using query below, but I am unable to provide the correct result.
My required result as below.WITH t AS ( select '123,1,3,22' col FROM DUAL UNION ALL SELECT '123,,2,1' FROM DUAL UNION ALL SELECT '5,1,2,,' FROM DUAL ) SELECT regexp_substr(t.col,'[^,]*',1,1) ,regexp_substr(t.col,'[^,]*',1,2) ,regexp_substr(t.col,'[^,]*',1,3) ,regexp_substr(t.col,'[^,]*',1,4) FROM DUAL,t ;
Please help me to get the required result by using regular expressions.123 1 3 22 123 2 1 5 1 2
Thanks, RamHello
In Oracle 10, you can do so by combining REGEXP_SUBSTR with something else like RTRIM:
SELECT RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 1), ',') AS part_1 , RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 2), ',') AS part_2 , RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 3), ',') AS part_3 , RTRIM (REGEXP_SUBSTR (col, '[^,]*(,|$)', 1, 4), ',') AS part_4 FROM t ;
Starting Oracle 11 REGEXP_SUBSTR alone can do.
But look at the first response; regular expressions will be probably less effective than less powerful features, especially when all channels have the same number of separators.
Published by: Frank Kulash on 29 December 2012 08:36
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How to extract the same part of the substring of two strings?
How can I retrieve the first identical substring of two strings?
version: 10 gr 2
as for example:
As you can see, the size of the substring is unknown.Given: str1: randomStringWith123abc str2: randomStringfor345abc Get: substr:randomString Given: str3: dummyhowareu str4: dummyiamfine Get: substr:dummy
any ideas?Hello
something like this:
with x as (select 'dummyhowareu' str1, 'dummyiamfine' str2 from dual) select replace(str1,ltrim(str1,str2)) from x
Herald tiomela
http://htendam.WordPress.com -
I haven't used regular expressions before, and I can't find a regular expression to extract a subset of the string between two markers.
The chain;
Stuff of header I want
Stuff of header I want
Stuff of header I wantStuff of header I want
Stuff of header I want
Stuff of header I want6 ERRORS
Info I want to line 1
Info I want line 2
Info I want line 3
Info I want to line 4
Info I want to line 5
Info I want line 6
END_ERRORSFrom the string above (it is read from a text file), I try to extract the subset of string between ERRORS 6 and END_ERRORS. The number of errors (6 in this case) can be any number from 1 to 32, and the number of lines I want to extract will correspond with this number. I can provide this number of a caller VI if necessary.
My current solution, which works, but is not very elegant;
(1) using Match Regular Expression for the return of the string after you have synchronized the 6 ERRORS
(2) uses the Regular Expression matches to return all characters before game END_ERRORS of the string returned by (1)
Is there a way this can be accomplished using 1 Regular Expression Match? If so someone could suggest how, as well as an explanation of the work of the given regular expression.
Thank you very much
Alan
I used a character class to catch any word or whitespace characters. This put inside parentheses a substring matching the criteria that you can get by developing the node for regular expression matching. The \d matches the numbers and the two * s repetition of the previous term. So, \d* will find the '6', as well as "123456".
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Extract the subset of data in the query string
Hi all
I am using query strings in Eloqua for some time and found the implementation of them quite simple. I recently ran well across a scenario where it is not set up as a standard string.
The URL ends up looking like this:
http://Sub.domain.com/LP=123/?var=AB-business-_-AB-BusinessAB-_-TRK1AB23_hm_comp2-e_abcdefg_s
The 'TRK1AB23' is the component I want to extract and place in a field.
When I use the following code, I find myself everything of value, I want to pull all the way to the end of the string. What should I do to this code to retrieve only the characters that I need?
function getQueryStringParamValue (strQStrParam) {}
strURL var = document.location.href; var strQStrParamValue = ""; If (strURL.indexOf('?')! = - 1) {} strQStrParamValue = strURL.substr (strURL.indexOf('?') + 1); If (strQStrParamValue.indexOf (strQStrParam)! = - 1) {} strQStrParamValue = strQStrParamValue.substr (strQStrParamValue.indexOf (strQStrParam)); strQStrParamValue = strQStrParamValue.substr (strQStrParamValue.indexOf ('TRK') + 1); If (strQStrParamValue.indexOf('&')! = - 1) strQStrParamValue = strQStrParamValue.substr (0, strQStrParamValue.indexOf ('&')); Return strQStrParamValue; } else {} strQStrParamValue = defaultHiddenFieldNameValue; Return strQStrParamValue; } } else {} strQStrParamValue = defaultHiddenFieldNameValue; Return strQStrParamValue; } }
Insert here the name of the form
var form = 'generic ';
function setCampaign() {}
var elqForm = return [form]; Repeat for each field to be completed elqForm.elements ['singleLineText'] .value = getQueryStringParamValue ('var'); }
Window.OnLoad = setCampaign;
< /script >
Egan,
Your answer actually has helped me tremendously. I learned to look closer the code and found that it was an option of substring. I changed the substring to look at the first three characters of the code (which are always consistent) and then adjusted to shoot only the eight characters containing the code.
It is not the prettiest or most appropriate code but it does exactly what I need to!
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How to extract a substring of the subject of actionEvent.getSource ()?
Hello
I am trying to extract a substring of the form actionEvent.getSource (), but when I use the javascript substring it works doesn´t work. It sounds simple, but it does not work.
When I apply alert (actionEvent.getSource ()) it produces ' AdfRichCommandToolbarButton [oracle.adf.RichCommandToolbarButton] id = zoomine, but when
It is used with actionEvent.getSource () .substring (1, 5), it doesn´t work.
It's the code of the function:
function tClick (actionEvent)
{actionEvent.cancel ();
eventSource var = actionEvent.getSource ();
var x = eventSource.substring (1, 5);
Alert (x);
}
Can someone help me?
Thank you
KuThe problem is that actionEvent.getSource () returns a string. It returns an object.
try actionEvent.getSource (m:System.NET.SocketAddress.ToString () .substring (1, 5))
or even better explain what you are trying to archive. We can help you get a better solution to your problem.Timo
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