Query function lead unable to fill the last record

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• Format the first and the last record of query result

  Hello
  I have the following query
  
  < tt > select 1 seq, "This is the first record" data from dual union of all the
  Select 2, 'Data ' | tNom tab Union all
  Select 3, "It was last last record" double
  order by 1 < /tt >
  
  When I have the coil this summary to a listfile with col seq noprint option I get:
  
  This is the first record
  Data MLA_ACCESS_LIST
  Data MLA_APPLICATIONS
  Data MLA_VPD_PCK
  Data MLA_VPD_TABLES
  It was the last last record
  
  But I want to:
  
  It's first record MLA_ACCESS_LIST
  Data MLA_APPLICATIONS
  Data MLA_VPD_PCK
  MLA_VPD_TABLES it was save finally last record
  
  I tried with 1 statement with the use of lead and lag, because first and last record stand the other result record. But I get ORA-30484: lack of specification of the window for this function
  
  Is this possible with 1 statement or am I've sentenced to modify the results by myself?
  
  Thank you Auke

  Select row_number() case above (tNom control)
  When 1 then 'it's the first record
  end | tNom |
  -case row_number() over (order by desc tNom)
  When 1 then 'it was the last record. "
  end
  tab
  order by tNom

  HTH

• Select the last record of each month

  Hello

  to select the last docnumber and qty of every month

  Structure

  Name Null?    Type

  ------------------------------- -------- ----

  PRODUCTCODE NUMBER

  NUMBER NUMBER

  DATE OF PLANFORMONTH

  NUMBER OF CLEXPECTEDQTY

  NUMBER OF CLCONFIRMQTY

  NUMBER OF CLFGBUFFERQTY

  NUMBER OF CLTOTPRINTBUFFER

  in this select query if I take the sum he required all records where, as I want the last record of each month

  SELECT productcode docnumber MAX (Number), planformonth, SUM (clexpectedqty) clexpectedqty (planformonth) MAX.

  SUM (clconfirmqty) clconfirmqty, SUM (clfgbufferqty) clfgbufferqty, cltotprintbuffer OF FGSALESPLAN of the SUM (cltotprintbuffer)

  GROUP BY productcode, (planformonth)

  Sandy

  Hello

  Thanks its working now the code is written as below:

  SELECT * FROM

  (SELECT

  e.*,

  ROW_NUMBER() OVER (partition by PRODUCTCODE by DOCNUMBER DESC order) r

  Of

  E FGSALESPLAN)

  WHERE r = 1 AND

  entryvalid = 'Y '.

  order by Number

  Sandy

• get the last record

  What is the best way to get the last record in a table?
  ... in addition to select * from tbl by id Desc... & then set = 1 maxrow in cfoutput.
  
  I want a quick way.
  I tried "Max (id), columns, but not worked.
  If I ' Max (id) as V ' & then turn around and make another request for ' where id = #V # "to get the rest of the record, there's more action.
  

  Quote:
  Posted by: paross1
  One way...

  SELECT all your columns
  From your_table
  WHERE your_engagement_appid = (SELECT MAX (your_id)
  From your_table)

  Phil

  Thank you guys. It worked great.
  I also tried the front joined query where the... I would have thought that.
  Thank you!

• Cursor Oracle return only the last record

  I am a newbie in oracle stored proc. I tried to select data using the slider, but it only return last record. The recording must be greater than 1.
  
  CREATE or REPLACE procedure MySchema.Test (myrefcur on sys_refcursor)
  Is
  
  Begin
  declare
  
  Cursor C1 IS
  
  Select mySerialNum from TableA;
  MyRecord C1% rowtype;
  
  Begin
  Open C1;
  Loop
  Fetch C1 into myrecord;
  When the output C1% NotFound;
  
  Open for Myrefcur
  Select SerialNumB from TableB where SerialNumB = myrecord.mySerialNum;
  
  End loop;
  Close C1;
  End;
  end;
  
  However, it only returns the last record in the list.
  
  Original case *.
  The original code is as below:
  
  1st, I'll need to select a list of ImageSerialNum of ImageSerial
  
  * 1 query:
  Select A.ImageSerialNum from ImageSerial A, ProductionOrder B, Bom C
  Where A.ProductionOrderID = B.ProductionOrderID And B.Assembly_Num = C.Model_Num and
  B.Revision = C.Revision And B.EngRevision = C.EngRevision and
  C.Bom_ID = passInVariable* and C.FactoryID = "7"
  
  2nd, I'll need to check the process of EACH series with the code below:
  
  * Low code a return process for 1 series only.
  
  Select t.processid, t.processname, t.assembly_num, t.revision, t.engrevision of
  (Select p.ProcessID, p.ProcessName, in. Assembly_Num, in. review, in. EngRevision, im.imageserialnum
  Process p, Routesequence rs, Imageserial im, ProductionOrder in.
  Where im. ImageserialNum = SerialNum* and p.ProcessID = rs. ProcessID
  And rs. RouteID = in. RouteID and rs. SequenceID = im. NextRouteSequence
  And in. ProductionOrderID = im. ProductionOrderID AND IM. STATUS OF '0'
  UNION
  SELECT A.REWORKROUTEID AS PROCESSID PROCESSNAME AS B.ROUTENAME, C.ASSEMBLY_NUM, C.REVISION, C.ENGREVISION, a.imageserialnum
  OF IMAGESERIAL A, B OF ROAD, PRODUCTIONORDER C
  WHERE A.REWORKROUTEID = B.ROUTEID AND A.IMAGESERIALNUM = SerialNum*.
  AND A.PRODUCTIONORDERID = C.PRODUCTIONORDERID and a.status = '0') t
  
  After that, I would like to combine the two in 1 stored proc code.

  in this case, you just want to join the two applications to use in the FROM clause
  As I don't have your tables, I created two tables, each representing the results of your queries. Substitute the names of table with your queries

  SQL> drop table master
    2  /
  
  Table dropped.
  
  SQL> drop table details
    2  /
  
  Table dropped.
  
  SQL>
  SQL> create table master
    2  (ImageSerialNum varchar2(25));
  
  Table created.
  
  SQL>
  SQL>
  SQL> insert into master values ('Serial1');
  
  1 row created.
  
  SQL> insert into master values ('Serial2');
  
  1 row created.
  
  SQL> insert into master values ('Serial3');
  
  1 row created.
  
  SQL> insert into master values ('Serial4');
  
  1 row created.
  
  SQL> insert into master values ('Serial5');
  
  1 row created.
  
  SQL>
  SQL> create table details
    2  (ImageSerialNum  varchar2(25)
    3  ,ProcessID  number
    4  ,ProcessName varchar2(25)
    5  );
  
  Table created.
  
  SQL>
  SQL> insert into details values ('Serial1',  1, 'Process1');
  
  1 row created.
  
  SQL> insert into details values ('Serial3',  3, 'Process3');
  
  1 row created.
  
  SQL> insert into details values ('Serial5',  5, 'Process5');
  
  1 row created.
  
  SQL>
  SQL> select m.imageserialnum
    2       , d.processid
    3       , d.processname
    4    from master m
    5    left outer
    6    join details d
    7      on (m.imageSerialnum = d.imageserialnum)
    8   order by m.imageserialnum
    9  /
  
  IMAGESERIALNUM             PROCESSID PROCESSNAME
  ------------------------- ---------- -------------------------
  Serial1                            1 Process1
  Serial2
  Serial3                            3 Process3
  Serial4
  Serial5                            5 Process5
  

  your query will be something like

  select m.imageserialnum
       , d.processid
       , d.processname
    from () m
    left outer
    join (
  

• Unable to read the work recorded, timeline is black and shortcuts

  Unable to read the work recorded.

  I started doing a few words with a song. It was not full yet so I recorded it. After a while, I returned to continue, but the timeline would not play. The video section containing the words of the timeline was black and shortened. I waited until the next day and it still the same. I tried to re-do and its not black or shortened, but the timeline would not play with or without music. Please I need help with this!

  Hello

  1. what application you're using to play the video?

  2. you receive an error message when you try to play the video?

  You can try to recreate and save the film.

  Reference:

  Demo: Create a slide show with music in Windows Movie Maker

  http://Windows.Microsoft.com/en-us/Windows-Vista/demo-create-a-slide-show-with-music-in-Windows-Movie-Maker

  Create movie customized for Windows Movie Maker settings

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  Publish a movie in Windows Movie Maker

  http://Windows.Microsoft.com/en-us/Windows-Vista/publish-a-movie-in-Windows-Movie-Maker

• Add a string to the last record

  Hello
  I was just trying to format an o/p to a table, and looking at the result, I thought it would be nice to add a piece of a chain to the last record. For example
  

  with dat as (
  select 'First Record' as COL from DUAL
  union all
  select 'Second Record'  from DUAL
  union all
  select 'Third Record'  from DUAL
  union all
  select 'Nth Record'  from DUAL )
  select * from dat
  
  o/p                                             Desired o/p
  COL                                            COL            
  -------------                                 -------------
  first RECORD                             first RECORD
  second RECORD                            second RECORD  
  THIRD RECORD                            THIRD RECORD 
  NTH RECORD                             This is the last record NTH RECORD   

  with dat as
  (
  select 'First Record' as COL from DUAL
  union all
  select 'Second Record'  from DUAL
  union all
  select 'Third Record'  from DUAL
  union all
  select 'Nth Record'  from DUAL
  ),
  ord as
  (
    select count(*) rn
      from dat
  )
  select decode(rownum, rn, 'This is Last Record ' || col, col)
    from ord, dat;
  

• get the LOV button to fill the correct record

  Hello world. In my form, I have a button that, when pressed goes to the text box correspondent and not do_key ('LIST_VALUES').
  
  It's on a record block multi and say for example I am on the first record of 10 and then press the button on the 5th record down, it would mean that I am eager to fill the 5 records down with the value that I choose from the LOV. However, it fills the first selected record previously. I guess my when shutter release button pressed I must verify that row button is on so that the focus then goes to the record number? If this is the case, no one knows how, I would go all this?
  
  Thank you.

  For the defined the navigable mouse button YES.

  -Clément

• remove the last record from the plsql table

  TYPE r_LOOPElement IS RECORD (TermID   NUMBER 
                                        );
  
  TYPE t_LOOPType IS TABLE OF r_LOOPElement INDEX BY BINARY_INTEGER;
  i_CustomerLoop      t_LOOPType ;
  
  i_CustomerLoop(1).TermID=1;
  i_CustomerLoop(2).TermID=2;
  i_CustomerLoop(3).TermID=3;

  Under certain conditions, I need to remove the last record from i_CustomerLoop
  
  whichi s the best way to do it. because I sometimes get duplicates for TermID in this plsql table.

  Hello

  See [removing items from Collection (DELETE method) | http://download.oracle.com/docs/cd/B28359_01/appdev.111/b28370/collections.htm#CJAFGFIG]

  Kind regards

• Identify the last record of node

  Hello everyone,
  
  another day, another problem.
  
  We want to display a list of commands not as multiple lines but as single line, each value divided by a comma:
  
  <? for-each: BM_AUFTRAEGE_ROW? > <? KRA_AUFTRAG_NUMMER? >, <? end foreach? >
  
  My concern is how to remove the last comma in this line? Can I calculate if it is the last recording of an if statement?
  
  Regrads,
  Stefan Dase

  To do this

  = ,

• How to get the date and time that a procedure/function has been modified for the last time?

  Hi all
  
  In Oracle Developer Tools for Visual Studio 2005 can I highlight a function, or a procedure and in the Properties window, it shows me the func/proc has been changed for the last time, and also when it was created
  
  Where can I get this information?
  
  See you soon
  CJ

  table object last_ddl_time

• Unable to show the last response after the connection

  I get an email notification of a thread, I followed.

  I click on the link in the email "go to the discussion.

  I see the answer of the e-mail, but when I connect so I can answer, the answer is no longer visible.

  My answer then sorts out of use in the thread, because I select the general answer option.

  HI Diane...

  It's ok for me.

  If you use Safari, in your Safari menu bar, click Safari > Preferences then select the Privacy tab, then click on Details and then delete all cookies for Apple.

  When finished exit then restart Safari. I hope that the next time you receive an e-mail notification the last answer will be available.

• Unable to fill the label for the accessor using xliff/properties file

  Hi all

  I have a requirement where I want to fill the label for a resource group accessor, but its not filled with the value of the key provided in the label.

  The portal bundle has after the entry:

  CUST_ADD = address of the customer

  and I'm on the underside of the piece of code in the pagedef.xml to make the address of the client on the user interface

  < accessors >

  < item Value = "custAddList".

  Label = "#{adfBundle ['PortalBundle'] ['CUST_ADD']}" / >

  < / accessors >

  But it gives following error on the user interface:

  STRINGMANAGER: Key: "#{adfBundle ['PortalBundle'] ['CUST_ADD']} ' is not in the whole"oracle.javatools.resourcebundle.ResourceBundleRT ".

  Can someone tell me how fill us this resource group label.

  Thank you

  Garima

  Hello

  I managed to solve the problem by providing the full qualified path of all the resource as shown below:

  Label = "#{adfBundle [' portal.]}" "{[PortalBundle'] ['CUST_ADD']}" / >

  Thanks for all the help!

• Display total records with the last record

  Hi all

  I have the following tables:

  create the table TRY_date_detail

  (

  item_date date,

  number of item_order

  );

  create the table TRY_date_master

  (

  date of master_date,

  number of date_amount

  );

  Insert all

  IN TRY_date_detail values (to_date('01-01-2011','DD-MM-YYYY'), 1)

  IN TRY_date_detail values (to_date('01-01-2011','DD-MM-YYYY'), 2).

  IN TRY_date_detail values (to_date('01-01-2011','DD-MM-YYYY'), 3)

  IN TRY_date_detail values (to_date('01-01-2011','DD-MM-YYYY'), 4)

  IN TRY_date_detail values (to_date('01-01-2011','DD-MM-YYYY'), 5)

  IN TRY_date_master values (to_date('01-01-2011','DD-MM-YYYY'), 6432)

  IN TRY_date_master values (to_date('01-01-2011','DD-MM-YYYY'), 1111)

  IN TRY_date_detail values (to_date('11-08-2012','DD-MM-YYYY'), 11)

  IN TRY_date_detail values (to_date('11-08-2012','DD-MM-YYYY'), 12)

  IN TRY_date_detail values (to_date('11-08-2012','DD-MM-YYYY'), 13)

  IN TRY_date_detail values (to_date('11-08-2012','DD-MM-YYYY'), 14)

  IN TRY_date_master values (to_date('11-08-2012','DD-MM-YYYY'), 8913)

  IN TRY_date_detail values (to_date('09-03-2014','DD-MM-YYYY'), 21)

  IN TRY_date_detail values (to_date('09-03-2014','DD-MM-YYYY'), 22)

  IN TRY_date_detail values (to_date('09-03-2014','DD-MM-YYYY'), 23)

  IN TRY_date_master values (to_date('09-03-2014','DD-MM-YYYY'), 1234)

  IN TRY_date_detail values (to_date('11-03-2014','DD-MM-YYYY'), 33)

  Select * twice;

  -My query is:

  SELECT ITEM_DATE, ITEM_ORDER, DATE_AMOUNT NULL

  OF TRY_date_detail

  WHERE ITEM_DATE IN (SELECT DISTINCT master_date OF TRY_date_master)

  UNION

  SELECT MASTER_DATE, NULL, SUM (DATE_AMOUNT)

  OF TRY_DATE_MASTER

  MASTER_DATE GROUP;

  -My query result:

  ITEM_DATE ITEM_ORDER DATE_AMOUNT

  January 1, 11 12:00:00 AM 1 (null)

  January 1, 11 12:00:00 AM 2 (null)

  January 1, 11 12:00:00 AM 3 (null)

  January 1, 11 12:00:00 AM 4 (null)

  January 1, 11 12:00:00 AM 5 (null)

  January 1, 11 12:00:00 AM (null) 7543

  11 Aug 12 12:00:00 AM 11 (null)

  11 Aug 12 12:00:00 AM 12 (null)

  August 11, 12 noon 13 (null)

  11 Aug 12 12:00 14 (null)

  11 Aug 12 12:00:00 AM (null) 8913

  9 March 14 12:00:00 AM 21 (null)

  9 March 14 12:00:00 AM 22 (null)

  9 March 14 12:00:00 AM 23 (null)

  9 March 14 12:00:00 AM (null) 1234

  -What I need, is to display the Date_amount with the last line of each date as follows:

  ITEM_DATE ITEM_ORDER DATE_AMOUNT

  January 1, 11 12:00:00 AM 1 (null)

  January 1, 11 12:00:00 AM 2 (null)

  January 1, 11 12:00:00 AM 3 (null)

  January 1, 11 12:00:00 AM 4 (null)

  January 1, 11 12:00:00 AM 5 7543

  11 Aug 12 12:00:00 AM 11 (null)

  11 Aug 12 12:00:00 AM 12 (null)

  August 11, 12 noon 13 (null)

  August 11, 12 12 00 14 8913 h

  9 March 14 12:00:00 AM 21 (null)

  9 March 14 12:00:00 AM 22 (null)

  9 March 14 12:00:00 AM 23 1234

  Thank you

  Ferro

  You have to JOIN to the table two

  SQL> select item_date
    2       , item_order
    3       , decode(rno, cnt, date_amount) date_amount
    4    from (
    5          select item_date
    6               , item_order
    7               , date_amount
    8               , row_number() over(partition by item_date order by item_order) rno
    9               , count(*) over(partition by item_date) cnt
   10            from try_date_detail
   11            join (
   12                   select master_date, sum(date_amount) date_amount
   13                     from try_date_master
   14                    group
   15                       by master_date
   16                 )
   17              on item_date = master_date
   18         );
  
  ITEM_DATE           ITEM_ORDER DATE_AMOUNT
  ------------------- ---------- -----------
  01/01/2011 00:00:00          1
  01/01/2011 00:00:00          2
  01/01/2011 00:00:00          3
  01/01/2011 00:00:00          4
  01/01/2011 00:00:00          5        7543
  11/08/2012 00:00:00         11
  11/08/2012 00:00:00         12
  11/08/2012 00:00:00         13
  11/08/2012 00:00:00         14        8913
  09/03/2014 00:00:00         21
  09/03/2014 00:00:00         22
  09/03/2014 00:00:00         23        1234
  
  12 rows selected.
  
  SQL>
  

• Properties of the file - Date of the last recorded

  Hello.

  I'm having trouble understanding the properties of the file, as "Last record Date" (DLS) and "Date modified" (MD).

  I asked that the last of them, MD, has been changed whenever the content has changed. But Distribution lists must be updated also.

  However, I have a file which has the DLS on 2007 and MD 2014 and the 'last impression"also is 2014.

  How is that possible?

  What has changed the date the content of the file was really the last?

  I would be grateful if someone could help me understand this.

  Thank you,

  Nuno Roque

  Modification date is when the file got changed on that hard drive.  Even if you have never opened the file, just drag-and - drop it to drive flash (for an example) would last updated date change, because the file on this disk changed really.

  Properties such as "Date of last recorded" and "date printed" are stored in the file itself, such as metadata and are updated no not by disk or operating system, but by the design (such as Word) program.