get the last record

Similar Questions

• How to get the last records of a Table

  Hey Geeks,

  I have this 'conflict '.

  I need to get the 'current balance' for each account, the newest "current_Balance".

  The table looks like this

  ACCOUNT_ID	BUSINESS_TRANSACTION_ID	CURRENT_BALANCE	TRANSACTION_AMOUNT	TRANSACTION_DATE
  1 062 570	238 043 517	51'022	-20'000	31.03.2014 17:49:00.808000
  1 062 570	238 042 407	71'022	-20'000	31.03.2014 17:33:55.666000
  1 062 570	238 042 368	91'022	-26'000	31.03.2014 17:33:20.067000
  1 062 570	238 041 273	117'022	-50,000	31.03.2014 17:18:25.189000
  1 062 570	238 041 174	167'022	-10,000	31.03.2014 17:16:59.361000
  1 062 570	238 038 702	177'022	-2'500	31.03.2014 16:44:58.332000
  5 607 555	238 046 713	1'026	-28'500	31.03.2014 18:35:16.212000
  5 607 555	238 040 592	29'526	-100,000	31.03.2014 17:10:15.474000

  I need this result:

  ACCOUNT_ID CURRENT_BALANCE

  5 607 555 1'026

  1 062 570 51'022                   

  
  

  How we handle this?

  
  

  Thxs for your help

  
  

  Ineffective :-)

  SELECT Account_id

  MAX (current_balance) KEEP (DENSE_RANK LAST ORDER BY transaction_date) current_balance

  MAX (business_transaction_id) KEEP (DENSE_RANK LAST ORDER BY transaction_date) business_transaction_id

  Of account_balances

  GROUP BY account_id

  See on Oracle: clause to keep

  Concerning

  Marcus

• How to get the last row and the sum of all columns in a query

  Hello

  is there a way to get the last record for a column and the sum of all the Archives to another column in the same query.

  Best regards

  You must set your needs correctly volunteers to help here...

  Your data are not good enough to bring you a precise solution. Purpose, you do not have a column, which draws a distinction between the first and the last entry.

  The solution becomes easy based on your design.

  I introduced a grouping called 'id' column and a time column called 'time_of_insert' (only this way you can say with confidence that you can differentiate between the first and last (also a foolproof solution) - you can possibly use sequence (instead of date but if you say that you can insert two lines at the same time) ((and then likely sequence would be a better choice to differentiate instead of a timestamp field) etc...)

  With your sample data, something like this can be done to get the desired results.

  -----------------------------------------------------------------------------------------------------------------------

  WITH dataset AS

  (SELECT 1 id, 10 used, 8 remain, systimestamp + 1/24 time_of_insert FROM DUAL

  UNION ALL

  SELECT the 1 id, 1, 7, systimestamp + 2/24 FROM DUAL

  UNION ALL

  SELECT the id 1, 2, 5, systimestamp + 3/24 FROM DUAL

  UNION ALL

  SELECT 1 id, 1, 0, systimestamp + 4/24 FROM DUAL

  UNION ALL

  SELECT 1 id, 0, 0, systimestamp + 5/24 FROM DUAL

  UNION ALL

  SELECT the 1 id, 1, 4, systimestamp + 6/24 FROM DUAL)

  SELECT *.

  (SELECT SUM (used) ON sum_all)

  FIRST_VALUE (stay)

  COURSES (PARTITION BY id ORDER BY time_of_insert DESC)

  last_row

  Of THE dataset)

  WHERE ROWNUM = 1;

  Output:

  ------------------------

  SUM_ALL LAST_ROW

  ------------------------------

  15                  4

  See you soon,.

  Manik.

• How to get the particular record last

  Hello
  
  I want the query because if a particular record available when enter as a last record.
  
  Ex,
  
  name
  ----------
  s
  t
  h
  
  but t is always the last record. How to get?
  
  
  Thank you
  Alphadi.

  Welcome to the forum.

  Do you mean you want to 'h' to appear as the last record?
  Try:

  SQL> -- generating sample data:
  SQL> with t as (
    2  select 'h' name from dual union
    3  select 's' from dual union
    4  select 't' from dual
    5  )
    6  --
    7  -- actual query:
    8  --
    9  select name
   10  from   t
   11  order by case
   12             when name = 'h' then 2
   13             else 1
   14           end;
  
  NAME
  --------------------
  s
  t
  h
  
  3 rows selected.
  

• Get the last disc based on the date

  Version of database
  
  Oracle9i Enterprise Edition Release 9.2.0.8.0 - 64 bit Production
  PL/SQL Release 9.2.0.8.0 - Production
  CORE Production 9.2.0.8.0
  AMT for HP - UX: 9.2.0.8.0 - Production Version
  NLSRTL Version 9.2.0.8.0 - Production
  
  data and model table
  
  
  CREATE TABLE EXAMPLE
  (
  UNIT_ID1 VARCHAR2 (15 BYTE) NOT NULL,
  COLL_DATE1 DAY,
  ATTRIB_CODE1 VARCHAR2 (4 BYTE) NOT NULL,
  UNIT_ID2 VARCHAR2 (15 BYTE),
  COLL_DATE2 DAY,
  ATTRIB_CODE2 VARCHAR2 (4 BYTE),
  DATE OF AUDIT_INSERT_DATS NOT NULL
  )
  
  
  
  
  
  Insert into SAMPLE
  (UNIT_ID1, COLL_DATE1, ATTRIB_CODE1, UNIT_ID2, COLL_DATE2,
  ATTRIB_CODE2, AUDIT_INSERT_DATS)
  Values
  ('W039712008646', TO_DATE (OCTOBER 8, 2012 00:00:00 ',' DD/MM/YYYY HH24:MI:SS'), 'DP', 'W039712008646', TO_DATE (OCTOBER 8, 2012 00:00:00 ',' DD/MM/YYYY HH24:MI:SS'),)
  'PP', TO_DATE (OCTOBER 9, 2012 11:10:56 "," MM/DD/YYYY HH24:MI:SS'));)
  Insert into SAMPLE
  (UNIT_ID1, COLL_DATE1, ATTRIB_CODE1, UNIT_ID2, COLL_DATE2,
  ATTRIB_CODE2, AUDIT_INSERT_DATS)
  Values
  ('W039712008646', TO_DATE (OCTOBER 8, 2012 00:00:00 "," MM/DD/YYYY HH24:MI:SS'), 'DP', NULL, NULL,)
  'DP', TO_DATE (OCTOBER 9, 2012 11:11:02 "," MM/DD/YYYY HH24:MI:SS'));)
  Insert into SAMPLE
  (UNIT_ID1, COLL_DATE1, ATTRIB_CODE1, UNIT_ID2, COLL_DATE2,
  ATTRIB_CODE2, AUDIT_INSERT_DATS)
  Values
  ('W039712008647', TO_DATE (OCTOBER 8, 2012 00:00:00 "," MM/DD/YYYY HH24:MI:SS'), 'DP', NULL, NULL,)
  'DP', TO_DATE (OCTOBER 9, 2012 11:15:18 ',' DD/MM/YYYY HH24:MI:SS'));)
  Insert into SAMPLE
  (UNIT_ID1, COLL_DATE1, ATTRIB_CODE1, UNIT_ID2, COLL_DATE2,
  ATTRIB_CODE2, AUDIT_INSERT_DATS)
  Values
  ('W039712008649', TO_DATE (OCTOBER 8, 2012 00:00:00 "," MM/DD/YYYY HH24:MI:SS'), 'TP', NULL, NULL,)
  'TP', TO_DATE (OCTOBER 9, 2012 11:15:39 ',' DD/MM/YYYY HH24:MI:SS'));)
  Insert into SAMPLE
  (UNIT_ID1, COLL_DATE1, ATTRIB_CODE1, UNIT_ID2, COLL_DATE2,
  ATTRIB_CODE2, AUDIT_INSERT_DATS)
  Values
  ('W039712008650', TO_DATE (OCTOBER 8, 2012 00:00:00 "," MM/DD/YYYY HH24:MI:SS'), 'RD', NULL, NULL,)
  'RD', TO_DATE (OCTOBER 9, 2012 11:16:10 ',' DD/MM/YYYY HH24:MI:SS'));)
  Insert into SAMPLE
  (UNIT_ID1, COLL_DATE1, ATTRIB_CODE1, UNIT_ID2, COLL_DATE2,
  ATTRIB_CODE2, AUDIT_INSERT_DATS)
  Values
  ('W039712008653', TO_DATE (OCTOBER 8, 2012 00:00:00 ',' DD/MM/YYYY HH24:MI:SS'), 'CX', NULL, NULL,)
  'CX', TO_DATE (OCTOBER 9, 2012 11:17:23 ',' DD/MM/YYYY HH24:MI:SS'));)
  COMMIT;
  
  -----------------------
  
  unit_id W039712008646 has two records. I need a query to get the last disk based on audit_insert_dats. Any help is appreciated.
  I tried to use max (audit_insert_dats) but not able to get a record

  user_anumoses wrote:
  unit_id W039712008646 has two records. I need a query to get the last disk based on audit_insert_dats.

  You can use the ROW_NUMBER() analytic function

  SQL> select *
    2  from
    3   (select a.*,
    4     row_number() over(partition by UNIT_ID1 order by AUDIT_INSERT_DATS desc) rn
    5    from sample a)
    6  where rn = 1;
  
  UNIT_ID1        COLL_DATE ATTR UNIT_ID2        COLL_DATE ATTR AUDIT_INS         RN
  --------------- --------- ---- --------------- --------- ---- --------- ----------
  W039712008646   08-OCT-12 DP                             DP   09-OCT-12          1
  W039712008647   08-OCT-12 DP                             DP   09-OCT-12          1
  W039712008649   08-OCT-12 TP                             TP   09-OCT-12          1
  W039712008650   08-OCT-12 RD                             RD   09-OCT-12          1
  W039712008653   08-OCT-12 CX                             CX   09-OCT-12          1
  

• remove the last record from the plsql table

  TYPE r_LOOPElement IS RECORD (TermID   NUMBER 
                                        );
  
  TYPE t_LOOPType IS TABLE OF r_LOOPElement INDEX BY BINARY_INTEGER;
  i_CustomerLoop      t_LOOPType ;
  
  i_CustomerLoop(1).TermID=1;
  i_CustomerLoop(2).TermID=2;
  i_CustomerLoop(3).TermID=3;

  Under certain conditions, I need to remove the last record from i_CustomerLoop
  
  whichi s the best way to do it. because I sometimes get duplicates for TermID in this plsql table.

  Hello

  See [removing items from Collection (DELETE method) | http://download.oracle.com/docs/cd/B28359_01/appdev.111/b28370/collections.htm#CJAFGFIG]

  Kind regards

• Format the first and the last record of query result

  Hello
  I have the following query
  
  < tt > select 1 seq, "This is the first record" data from dual union of all the
  Select 2, 'Data ' | tNom tab Union all
  Select 3, "It was last last record" double
  order by 1 < /tt >
  
  When I have the coil this summary to a listfile with col seq noprint option I get:
  
  This is the first record
  Data MLA_ACCESS_LIST
  Data MLA_APPLICATIONS
  Data MLA_VPD_PCK
  Data MLA_VPD_TABLES
  It was the last last record
  
  But I want to:
  
  It's first record MLA_ACCESS_LIST
  Data MLA_APPLICATIONS
  Data MLA_VPD_PCK
  MLA_VPD_TABLES it was save finally last record
  
  I tried with 1 statement with the use of lead and lag, because first and last record stand the other result record. But I get ORA-30484: lack of specification of the window for this function
  
  Is this possible with 1 statement or am I've sentenced to modify the results by myself?
  
  Thank you Auke

  Select row_number() case above (tNom control)
  When 1 then 'it's the first record
  end | tNom |
  -case row_number() over (order by desc tNom)
  When 1 then 'it was the last record. "
  end
  tab
  order by tNom

  HTH

• How to get the last message received in the Inbox?

  Currently I am using the following code to the list of messages in the Inbox.

  Folder[] folders = store.list(Folder.INBOX);Folder inbox = folders[0];Message[] msgs = inbox.getMessages();
  

  But, how could I do the last message that was received in my inbox at the moment?

  I have a lot of unread messages in my Inbox and I can even receive the same message from sender twice at the same time, but I need access to the last message you received.

  Thank you

  As I have a implements FolderListener, I need to get the last message of FolderEvent object. But, I tried to access the last Inbox message, which will not always be there!

  Thanks Deepesh

• How to get the last date of 3 days for the current month?

  Hello. Guy

  How to get the last date of 3 days for the current month?

  MY OUTPUT WOULD LOOK LIKE THIS

  JANUARY 29, 2016

  JANUARY 30, 2016

  JANUARY 31, 2016

  
  

  GUYS HELP ME / / /...
  

  SQL > select last_day (sysdate) - level + 1 double connect by level<= 3="" order="" by="">

  LAST_DAY)

  ---------

  29 JANUARY 16

  30 JANUARY 16

  31 JANUARY 16

• Select the last record of each month

  Hello

  to select the last docnumber and qty of every month

  Structure

  Name Null?    Type

  ------------------------------- -------- ----

  PRODUCTCODE NUMBER

  NUMBER NUMBER

  DATE OF PLANFORMONTH

  NUMBER OF CLEXPECTEDQTY

  NUMBER OF CLCONFIRMQTY

  NUMBER OF CLFGBUFFERQTY

  NUMBER OF CLTOTPRINTBUFFER

  in this select query if I take the sum he required all records where, as I want the last record of each month

  SELECT productcode docnumber MAX (Number), planformonth, SUM (clexpectedqty) clexpectedqty (planformonth) MAX.

  SUM (clconfirmqty) clconfirmqty, SUM (clfgbufferqty) clfgbufferqty, cltotprintbuffer OF FGSALESPLAN of the SUM (cltotprintbuffer)

  GROUP BY productcode, (planformonth)

  Sandy

  Hello

  Thanks its working now the code is written as below:

  SELECT * FROM

  (SELECT

  e.*,

  ROW_NUMBER() OVER (partition by PRODUCTCODE by DOCNUMBER DESC order) r

  Of

  E FGSALESPLAN)

  WHERE r = 1 AND

  entryvalid = 'Y '.

  order by Number

  Sandy

• How to get the last business day of the previous month?

  Hi all

  We need the user as below,

  If the user select 18 June 2015 ' quick dashboard as the input value, and then they want to see last month last day of work (business date: 29-may-2015) amount in report, if you have an idea please share with us.thanks

  Note:

  use under request we can able to get the last day of the previous month, we want to for the last business day of the last month, based on the date of entry of the user?

  TIMESTAMPADD (SQL_TSI_DAY,-(1), TIMESTAMPADD (SQL_TSI_DAY, DAYOFMONTH ("DIM_TIME". ("" DataDate ") *-(1) + 1,"DIM_TIME ". (("" DataDate "))

  Thank you

  Deva

  Try this,

  case when Dayofweek (timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1, Date ' 2015-06-15')) = 1 then timestampadd (sql_tsi_day, (Dayofmonth(Date '2015-06-15') *-1)-2, Date '' 2015-06-15) when Dayofweek (timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1, Date ' 2015-06-15')) = 7 then timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1-1, Date '' 2015-06-15) another timestampadd (sql_tsi_day, Dayofmonth(Date '2015-06-15') *-1, Date ' 2015-06-15') end

  As Ftsiot said in this post, it will work only to exclude the sat and Sun. Another one if you want to exclude regional holiday, you may need a calendar in DB table.

  Thank you

  AJ

• I have been using Photoshop CS5 for some time for photos products (jewelry). What are my best options to get the last Photoshop.

  I have been using Photoshop CS5 for some time for photos products (jewelry). What are my best options to get the last Photoshop.

  Hi michaelb.

  You can subscribe to Plan photography for $9.99 a month, which will give the latest version of Photoshop CC 2015, CC 2015 Lightroom and Adobe Bridge.

  Lightroom and Photoshop | Plan of cloud of Adobe's creative photography

  Kind regards

  Mohit

• How to get the last day of the weekend rather than a month

  Hi all

  Is the request appropriate and preferable to use to get the last business day of the month below?

  SELECT to_date('13.08.2014','dd.mm.yyyy') + MAX(RNUM) LastDay(nonweekend)
     FROM   (SELECT ROWNUM RNUM
            FROM   ALL_OBJECTS where rownum <=31)
    WHERE   ROWNUM <= 31 ANd
       TO_CHAR(to_date('13.08.2014','dd.mm.yyyy') + RNUM, 'DY','NLS_DATE_LANGUAGE=ENGLISH' ) NOT IN ('SAT' , 'SUN')
       and to_date('13.08.2014','dd.mm.yyyy') + RNUM <= last_day(to_date('13.08.2014','dd.mm.yyyy'))
  

  I have to use this motion for production.

  East - recommended to use?

  You can change your query this way:

  WITH t AS (SELECT trunc (to_date ('& calc_date', 'dd.mm.yyyy'), 'mm') + level - 1 calc_date)

  OF THE DOUBLE

  CONNECT BY LEVEL<= last_day(to_date('&calc_date',="" 'dd.mm.yyyy'))="" -="" trunc(to_date('&calc_date',="" 'dd.mm.yyyy'),="" 'mm')="" +="">

  )

  Select max (calc_date)

  t

  where to_char (calc_date, 'DY', 'NLS_DATE_LANGUAGE = ENGLISH') NOT IN ("SAT", "Sun");

• How to get the last day of a month for every 2 months for a given period?

  Hello

  Can is it some please let me know how to get the last day, last day of the week, the weekend last day, last Monday, one month for every 2 months for a given period?

  Thanks in advance.

  Try the below

  SELECT LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))) lastday.

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'SAT '.

  SO LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-1

  WHERE TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'Sun '.

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))-2

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  END as lastweekday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') IN ('Sam', 'SUN')

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  -(TO_NUMBER (TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))),' from)) - 1).

  END as lastweekendday,

  BOX WHEN TO_CHAR (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), 'DY') = 'MY

  THEN LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2)))

  Of OTHER NEXT_DAY (LAST_DAY (ADD_MONTHS (TRUNC(startdate,'MM'), ((LEVEL*2)-2))), "LUN")-7

  END AS lastmonday

  FROM (SELECT SYSDATE startdate,

  SYSDATE + 300 enddate

  THE DOUBLE)

  CONNECT BY LEVEL<=>

• tried to get the last update. Update froze at 2%. Help

  Tried to get the last update. It froze at 2%. Any help much appreciated.

  Hello

  Go close before the creative Cloud Desktop Application and also all related processes for the same if it's windows, the Manager of tasks and activity monitor if it's the Mac.

  Very close to the AAMUpdater, Core Sync and IPCBroke process.

  So go ahead and uninstall the Cloud Desktop creative Application from the link below.

  Using creative cloud | Uninstall the creative cloud desktop application

  and install the above from the link below.

  https://creative.Adobe.com/products/creative-cloud

  Concerning

  Maansee