QUESTION OF REDUNDANCY NORMAL ASM
Hi allDocument Oracle ASM NORMAL QUESTION of REDUNDANCY [1480954.1 ID] says the statement, I find it difficult to understand the line which is marked in italics below.
To determine the appropriate size of a diskgroup which is protected with redundancy of ASM, sufficient free space must exist in the diskgroup
so that when a drive goes down, it can automatically rebuild the contents of the drive failed on another drive in the diskgroup. The database should stay online if sufficient space is available. The amount of space required to ensure ASM can restore redundancy if there is no disc is in the REQUIRED_MIRROR_FREE_MB column in the view V$ ASM_DISKGROUP. The amount of free space that can be used safely in a disk group, taking into account, mirroring and still be able to restore redundancy after a drive failure is in the USABLE_FILE_MB column in the view V$ ASM_DISKGROUP. USABLE_FILE_MB must always be greater than zero. If USABLE_FILE_MB falls below zero, most records should be added to the disk group.
DOUBT: why what he have reconstitute the content of the disc failed on another drive in the diskgroup when scopes in mirror and I do not understand when the disc itself is failed how they can access it and rebuild its contents to another drive.
Concerning
DOUBT: why need restore the contents of the drive failed on another drive in the diskgroup when there mirrored scopes
because the data on the failed drive is not more in the opposite direction (no additional copies) and to ensure a level of normal redundancy, we'll build a new mirror copy of data
I do not understand when the disc itself broke down how they can access it and rebuild its contents to another drive.
data always available, mirrored
to explain it simply:
everything is stored with 2 copies (original + mirror)
When 1 is lost, a new copy will be rebuilt among others the 1, so there will be 2 copies again
Tags: Database
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See example below (d = data extended)
FG1 | FG2 | FG3
========|===============|=========
d1 | d1_copy:
| d2 | d2_copy
d3_copy | | d3
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==========================
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Top - three way mirror. Group of two failed.
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Hi all
REDUNDANCY NORMAL == NEED 2 GROUPS of FAILURE (I'm clear)
I am trying to create diskgroup with REDUNDANCY NORMAL (only with 2 raw devices).
Command line == > I can't create disk with REDUNDANCY NORMAL group
Through DBCA == > I can.
select GROUP_NUMBER, name, ALLOCATION_UNIT_SIZE AU_SZ, STATE, TYPE, TOTAL_MB, FREE_MB, OFFLINE_DISKS from v$asm_diskgroup; GROUP_NUMBER NAME AU_SZ STATE TYPE TOTAL_MB FREE_MB OFFLINE_DISKS ------------ ------------------------------ ---------- ----------- ------ ---------- ---------- ------------- 1 ASM_DG_DATA 1048576 MOUNTED NORMAL 20472 14142 0 2 ASM_DG_FRA 1048576 MOUNTED EXTERN 10236 7143 0
SQL> create diskgroup DATA NORMAL REDUNDANCY 2 failgroup disk1 Disk 3 '/dev/raw/raw5' name data1, 4 '/dev/raw/raw6' name data2; create diskgroup DATA NORMAL REDUNDANCY * ERROR at line 1: ORA-15018: diskgroup cannot be created ORA-15072: command requires at least 2 failure groups, discovered only 1
But through dbca, I can create diskgroup only with 2 drives
SQL> select GROUP_NUMBER, name, ALLOCATION_UNIT_SIZE AU_SZ, STATE, TYPE, TOTAL_MB, FREE_MB, OFFLINE_DISKS from v$asm_diskgroup; GROUP_NUMBER NAME AU_SZ STATE TYPE TOTAL_MB FREE_MB OFFLINE_DISKS ------------ ------------------------------ ---------- ----------- ------ ---------- ---------- ------------- 1 ASM_DG_DATA 1048576 MOUNTED NORMAL 20472 14142 0 2 ASM_DG_FRA 1048576 MOUNTED EXTERN 10236 7143 0 3 ASM_DATA 1048576 MOUNTED NORMAL 40946 40844 0
SQL> select a.disk_number, b.group_number, a.path, b.name, b.type from v$asm_disk a, v$asm_diskgroup b where a.group_number=b.group_number; DISK_NUMBER GROUP_NUMBER PATH NAME TYPE ----------- ------------ ---------------------- ------------------------------ ------ 0 3 /dev/raw/raw6 ASM_DATA NORMAL 1 3 /dev/raw/raw5 ASM_DATA NORMAL 0 2 /dev/raw/raw3 ASM_DG_FRA EXTERN 1 1 /dev/raw/raw2 ASM_DG_DATA NORMAL 0 1 /dev/raw/raw1 ASM_DG_DATA NORMAL
...
..
My question/confusion is only 2 discs,
I can create a diskgroup (redundancy = normal) using DBCA, but similar operation cannot perform through command line.
DB version: 10.2.0.5 on RHEL
Shows your screenshot of the ASMCA you assign disk/dev/raw/raw5 in FailGroup FG1 and disk/dev/raw/raw6 in FailGroup FG2 - two * different * FailGroups. Each disc is in a separate FailGroup.
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Kind regards
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