Question of TIMESTAMPADD (SQL_TSA_YEAR) (with leap years)

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• Bug or error during the handling of leap years with WDS/DS

  Hi all
  
  I discovered a difference in results with the construction and to debug (without frame) and generate and debug with the revisions of Web or server of determinations when calculating the days in leap years.
  I use the DayDifferenceInclusive function to calculate the number of days in a period of insurance.
  
  the number of days of insurance period = DayDifferenceInclusive (the start date of the insurance, the date of the end of insurance)
  
  With the tester of regression or generation and debugging (without frame), I get the following result for the following entry:
  
  * 93 = DayDifferenceInclusive (02-29-2008, 05-31-2008) *.
  
  When we use the revisions of Web or server of determinations we get the value of * 92 * for exactly the same data entry when it should be 93.
  Is this a bug in the java code? How can we fix this or is there a work around it?
  
  We are in the middle of integration testing system for a huge project to help is very appreciated!
  
  Best regards
  Niels Roest

  Niels,

  Thanks for that - and it seems that in the Netherlands DST began March 30, 2008, that is, as far as I know, the trigger for this error.

  I have reproduced the issue against 10.1 using the period from 1st October 2010 to 30 October 2010, which contains the date this summer time began in Australia.

  Regarding the ways to work around the problem, I can offer 3:

  * wait 10.2 - it is in beta at the moment (but given your opening remarks, may not be an option for you)
  * set your locale of the server to that which has no DST
  * work around the issue in the rules:

  First of all, the question is that the retail version fails because it does not realize that one of these days is shorter than the standard 24 hours.

  The trick is to replace the DayDifference function with the HourDifference function and round up the number of days.

  Thus given a rule that looks like:

  result = DayDifference (date one, date two)

  It can be rewritten in the form:

  The result = round (HourDifference (one at 00:00:00, date two to 00:00:00) / 24, 0)

  * the "at 00:00:00 ' is necessary because HourDifference works on dates/hours, not dates.

  Sorry for the inconvenience.

  Concerning
  Andrew

• Bug with interval and leap years

  select to_date('2012-feb-29','yyyy-mon-dd') + interval '1' year as dt from dual;
  
  ORA-01839: date not valid for month specified
  01839. 00000 -  "date not valid for month specified"
  *Cause:    
  *Action:
  
  select to_date('2012-feb-29','yyyy-mon-dd') + interval '2' year as dt from dual;
  
  ORA-01839: date not valid for month specified
  01839. 00000 -  "date not valid for month specified"
  *Cause:    
  *Action:
  
  select to_date('2012-feb-29','yyyy-mon-dd') + interval '3' year as dt from dual;
  
  ORA-01839: date not valid for month specified
  01839. 00000 -  "date not valid for month specified"
  *Cause:    
  *Action:
  
  select to_date('2012-feb-29','yyyy-mon-dd') + interval '4' year as dt from dual;
  
  29-FEB-16 00:00:00
  
  
  select to_date('2012-feb-29','yyyy-mon-dd') + interval '1' day as dt from dual;
  
  01-MAR-12 00:00:00
  
  select to_date('2012-feb-29','yyyy-mon-dd') + interval '1' month as dt from dual;
  
  29-MAR-12 00:00:00

  The problem exists in 10.2.0.4 and 11.2.0.3
  
  Published by: birlenbach-Chase February 29, 2012 09:20

  Hello

  That's just how the intervals of work. Leap years are the least of the problem; Adding 1 month to 31 March results in the same error.
  If you want to make sure that the result is a valid DATE, use ADD_MONTHS. (There is no separate function for adding years; use ADD_MONTH (SYSDATE, 12 * n) to get the DATE which is n years.)

• Leap year TMS Scheduler

  We have MSD and MSD Smart Scheduler.  When users of planning meetings in the smart Scheduler for Monday 2/29, they are listed as Tuesday 3/1, I guess because of the leap year.  However, it shows the correct date when you click the meeting and in the TMS itself.  I checked to make sure that the time zone settings are correct.  Is that going to the issue of Monday?

  Turns out just a cosmetic defect with Smart Scheduler, see CSCuy19844.

• How to check leap year between the years earn a new degree?

  Hi all
  I developed a report to print a report of emplyees who earn a new degree between towing dates entered by two parameters of the user.
  I used this code to do this:
  
  SELECT ALL E.EMP_SID, E.EMP_FULL_NAME, E.FINANCIAL_NO
  (CASE WHEN E.qualification_sid = 1104 AND E.degree_sid = 8 THEN
  (TO_DATE (E.degree_DATE, 'DD-MM-RR') +(365*M.spe_per) + 1).
  ON THE OTHER
  (TO_DATE (E.degree_DATE, 'DD-MM-RR') +(365*M.yea_per) + 1).
  END)
  COMM_degree,
  OF INDUSTSRIE E, M DEGREES
  WHERE (CASE WHEN E.qualification_sid = 1104 AND E.degree_sid = 8 THEN
  (TO_DATE (E.degree_DATE, 'DD-MM-RR') +(365*M.spe_per) + 1).
  ON THE OTHER
  (TO_DATE (E.degree_DATE, 'DD-MM-RR') +(365*M.yea_per) + 1).
  END)
  
  BETWEEN TO_DATE (: P_F_DATE, 'DD-MM-RR') AND TO_DATE (: P_L_DATE, 'DD-MM-RR')
  AND (E.degree_SID = M.SID)
  ORDER BY M.SID DESC, E.EMP_FULL_NAME
  
  Now there is an error in the data led to some employees with a leap year in the year to earn income
  for example: an employee has a degree date of 10/01/2011 and win it supposed the next level is 10/01/2016 but the report gives as 30/09/2016 because there's one year leap year 2012 which have 366 days 365 days I count in the code!
  If there is something mysterious in the code, please do not hesitate to ask!
  Please how to fix this?
  
  Note: I use reports 6i.

  Hello

  Try ADD_MONTHS(SYSDATE,12) - instead of 365 DAYS

  IF ANY PROBLEM WE THE KNOW

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• I read this topic (I have a lot of questions about Xperia Z2 with lollipop)

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• interval + "1" [year | month | day] does not take into account leap years?

  Hi all
  
  The Version of database: Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - 64bi
  Database version: PL/SQL Release 10.2.0.5.0 - Production
  
  I just realized that the function of the interval is not account of leap years.
  

  SQL> select to_date('29-02-2008','dd-mm-yyyy') + interval '1' year 
    2    from dual;
  select to_date('29-02-2008','dd-mm-yyyy') + interval '1' year
                                        *
  ERROR at line 1:
  ORA-01839: date not valid for month specified

  I looked through the documentation as much as I can and could find no mention of this.
  
  If I want to add a year to date, I have to calculate the number of days or do something like incrementing only the part of the year and then manually check that it does not fall on February 29 if it is not a leap year manually?
  
  Edit:
  
  just to clarify, day and minute seem to work for example but do not have month and year:
  

  SQL> select to_date('28-02-2009','dd-mm-yyyy') + interval '1' day
    2    from dual;
  
  TO_DATE('
  ---------
  01/MAR/09
  
  1 row selected.
  
  Elapsed: 00:00:00.00
  SQL> 
  SQL> select to_date('28-02-2009 23:59','dd-mm-yyyy hh24:mi') + interval '1' minute 
    2    from dual;
  
  TO_DATE('
  ---------
  01/MAR/09
  
  1 row selected.
  
  Elapsed: 00:00:00.00
  SQL> 
  SQL> select to_date('29-01-2009','dd-mm-yyyy') + interval '1' month
    2    from dual;
  select to_date('29-01-2009','dd-mm-yyyy') + interval '1' month
                                        *
  ERROR at line 1:
  ORA-01839: date not valid for month specified
  
  
  Elapsed: 00:00:00.00
  SQL> 
  SQL> select to_date('29-02-2008','dd-mm-yyyy') + interval '1' year
    2    from dual; 
  select to_date('29-02-2008','dd-mm-yyyy') + interval '1' year
                                        *
  ERROR at line 1:
  ORA-01839: date not valid for month specified

  Published by: WhiteHat on July 14, 2011 10:31

  Hello

  It is true; in the INTERVAL arithmetic + x (or) d - x, where x is the months or years, the result will be the same day of the month as d. If this date does not exist, then you will get an error
  Another example is:

  SQL> SELECT  DATE '2011-03-31' + INTERVAL '1' MONTH  FROM dual;
  SELECT  DATE '2011-03-31' + INTERVAL '1' MONTH  FROM dual
                            *
  ERROR at line 1:
  ORA-01839: date not valid for month specified
  

  To avoid triggering an error, use ADD_MONTHS and/or arithmetic DATE instead.

• How I replace perfectly my record excel sheet with ability of database? + General questions about computing distributed with LabVIEW

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• Questions of getting started with Service contracts to small businesses

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