Leap year TMS Scheduler

Similar Questions

• Wrong date. A day off. Does not take into account leap years.

  We don't want the date on my iMac. It is a day of rest. On March 3, it shows March 2. Of course, it didn't take leap years into account. When I tried to change it after you have unlocked the date/time, he wouldn't let me to change the date. It is automatically defined under Apple Americas/U.S. (time.apple.com site), but the automatic setting is false. How do override us the auto setting or have them repaired?

  Oops! My watch was the one who was wrong. Apple is very well. Sorry about that.

• How to check leap year between the years earn a new degree?

  Hi all
  I developed a report to print a report of emplyees who earn a new degree between towing dates entered by two parameters of the user.
  I used this code to do this:
  
  SELECT ALL E.EMP_SID, E.EMP_FULL_NAME, E.FINANCIAL_NO
  (CASE WHEN E.qualification_sid = 1104 AND E.degree_sid = 8 THEN
  (TO_DATE (E.degree_DATE, 'DD-MM-RR') +(365*M.spe_per) + 1).
  ON THE OTHER
  (TO_DATE (E.degree_DATE, 'DD-MM-RR') +(365*M.yea_per) + 1).
  END)
  COMM_degree,
  OF INDUSTSRIE E, M DEGREES
  WHERE (CASE WHEN E.qualification_sid = 1104 AND E.degree_sid = 8 THEN
  (TO_DATE (E.degree_DATE, 'DD-MM-RR') +(365*M.spe_per) + 1).
  ON THE OTHER
  (TO_DATE (E.degree_DATE, 'DD-MM-RR') +(365*M.yea_per) + 1).
  END)
  
  BETWEEN TO_DATE (: P_F_DATE, 'DD-MM-RR') AND TO_DATE (: P_L_DATE, 'DD-MM-RR')
  AND (E.degree_SID = M.SID)
  ORDER BY M.SID DESC, E.EMP_FULL_NAME
  
  Now there is an error in the data led to some employees with a leap year in the year to earn income
  for example: an employee has a degree date of 10/01/2011 and win it supposed the next level is 10/01/2016 but the report gives as 30/09/2016 because there's one year leap year 2012 which have 366 days 365 days I count in the code!
  If there is something mysterious in the code, please do not hesitate to ask!
  Please how to fix this?
  
  Note: I use reports 6i.

  Hello

  Try ADD_MONTHS(SYSDATE,12) - instead of 365 DAYS

  IF ANY PROBLEM WE THE KNOW

• Bug with interval and leap years

  select to_date('2012-feb-29','yyyy-mon-dd') + interval '1' year as dt from dual;
  
  ORA-01839: date not valid for month specified
  01839. 00000 -  "date not valid for month specified"
  *Cause:    
  *Action:
  
  select to_date('2012-feb-29','yyyy-mon-dd') + interval '2' year as dt from dual;
  
  ORA-01839: date not valid for month specified
  01839. 00000 -  "date not valid for month specified"
  *Cause:    
  *Action:
  
  select to_date('2012-feb-29','yyyy-mon-dd') + interval '3' year as dt from dual;
  
  ORA-01839: date not valid for month specified
  01839. 00000 -  "date not valid for month specified"
  *Cause:    
  *Action:
  
  select to_date('2012-feb-29','yyyy-mon-dd') + interval '4' year as dt from dual;
  
  29-FEB-16 00:00:00
  
  
  select to_date('2012-feb-29','yyyy-mon-dd') + interval '1' day as dt from dual;
  
  01-MAR-12 00:00:00
  
  select to_date('2012-feb-29','yyyy-mon-dd') + interval '1' month as dt from dual;
  
  29-MAR-12 00:00:00

  The problem exists in 10.2.0.4 and 11.2.0.3
  
  Published by: birlenbach-Chase February 29, 2012 09:20

  Hello

  That's just how the intervals of work. Leap years are the least of the problem; Adding 1 month to 31 March results in the same error.
  If you want to make sure that the result is a valid DATE, use ADD_MONTHS. (There is no separate function for adding years; use ADD_MONTH (SYSDATE, 12 * n) to get the DATE which is n years.)

• interval + "1" [year | month | day] does not take into account leap years?

  Hi all
  
  The Version of database: Oracle Database 10g Enterprise Edition Release 10.2.0.5.0 - 64bi
  Database version: PL/SQL Release 10.2.0.5.0 - Production
  
  I just realized that the function of the interval is not account of leap years.
  

  SQL> select to_date('29-02-2008','dd-mm-yyyy') + interval '1' year 
    2    from dual;
  select to_date('29-02-2008','dd-mm-yyyy') + interval '1' year
                                        *
  ERROR at line 1:
  ORA-01839: date not valid for month specified

  I looked through the documentation as much as I can and could find no mention of this.
  
  If I want to add a year to date, I have to calculate the number of days or do something like incrementing only the part of the year and then manually check that it does not fall on February 29 if it is not a leap year manually?
  
  Edit:
  
  just to clarify, day and minute seem to work for example but do not have month and year:
  

  SQL> select to_date('28-02-2009','dd-mm-yyyy') + interval '1' day
    2    from dual;
  
  TO_DATE('
  ---------
  01/MAR/09
  
  1 row selected.
  
  Elapsed: 00:00:00.00
  SQL> 
  SQL> select to_date('28-02-2009 23:59','dd-mm-yyyy hh24:mi') + interval '1' minute 
    2    from dual;
  
  TO_DATE('
  ---------
  01/MAR/09
  
  1 row selected.
  
  Elapsed: 00:00:00.00
  SQL> 
  SQL> select to_date('29-01-2009','dd-mm-yyyy') + interval '1' month
    2    from dual;
  select to_date('29-01-2009','dd-mm-yyyy') + interval '1' month
                                        *
  ERROR at line 1:
  ORA-01839: date not valid for month specified
  
  
  Elapsed: 00:00:00.00
  SQL> 
  SQL> select to_date('29-02-2008','dd-mm-yyyy') + interval '1' year
    2    from dual; 
  select to_date('29-02-2008','dd-mm-yyyy') + interval '1' year
                                        *
  ERROR at line 1:
  ORA-01839: date not valid for month specified

  Published by: WhiteHat on July 14, 2011 10:31

  Hello

  It is true; in the INTERVAL arithmetic + x (or) d - x, where x is the months or years, the result will be the same day of the month as d. If this date does not exist, then you will get an error
  Another example is:

  SQL> SELECT  DATE '2011-03-31' + INTERVAL '1' MONTH  FROM dual;
  SELECT  DATE '2011-03-31' + INTERVAL '1' MONTH  FROM dual
                            *
  ERROR at line 1:
  ORA-01839: date not valid for month specified
  

  To avoid triggering an error, use ADD_MONTHS and/or arithmetic DATE instead.

• Bug or error during the handling of leap years with WDS/DS

  Hi all
  
  I discovered a difference in results with the construction and to debug (without frame) and generate and debug with the revisions of Web or server of determinations when calculating the days in leap years.
  I use the DayDifferenceInclusive function to calculate the number of days in a period of insurance.
  
  the number of days of insurance period = DayDifferenceInclusive (the start date of the insurance, the date of the end of insurance)
  
  With the tester of regression or generation and debugging (without frame), I get the following result for the following entry:
  
  * 93 = DayDifferenceInclusive (02-29-2008, 05-31-2008) *.
  
  When we use the revisions of Web or server of determinations we get the value of * 92 * for exactly the same data entry when it should be 93.
  Is this a bug in the java code? How can we fix this or is there a work around it?
  
  We are in the middle of integration testing system for a huge project to help is very appreciated!
  
  Best regards
  Niels Roest

  Niels,

  Thanks for that - and it seems that in the Netherlands DST began March 30, 2008, that is, as far as I know, the trigger for this error.

  I have reproduced the issue against 10.1 using the period from 1st October 2010 to 30 October 2010, which contains the date this summer time began in Australia.

  Regarding the ways to work around the problem, I can offer 3:

  * wait 10.2 - it is in beta at the moment (but given your opening remarks, may not be an option for you)
  * set your locale of the server to that which has no DST
  * work around the issue in the rules:

  First of all, the question is that the retail version fails because it does not realize that one of these days is shorter than the standard 24 hours.

  The trick is to replace the DayDifference function with the HourDifference function and round up the number of days.

  Thus given a rule that looks like:

  result = DayDifference (date one, date two)

  It can be rewritten in the form:

  The result = round (HourDifference (one at 00:00:00, date two to 00:00:00) / 24, 0)

  * the "at 00:00:00 ' is necessary because HourDifference works on dates/hours, not dates.

  Sorry for the inconvenience.

  Concerning
  Andrew

• TMS-> Scheduler conductor calls

  Hello

  I m configuration of a conductor (x3.0.3) with a microcontroller for planning appeals in tms 14.6. Previosly, I set up requires ad hoc and appointment and works very well.

  At tms, I added the conductor, but when I added the alias configuration, an error "unable to connect the driver to telepresence to check the configuration of the alias. I think that the configuration is correct, name, alias boss and priority it s even the configuration of the alias the conductor.

  I read another post but I Don t know if it s mandatory that the bridge, bridge pool and services preferences are dedicated for Scheduler calls. I have only 1 mcu, then I have can´t set several bridge...

  Can you help me add aliases on MSDS?

  Kind regards!

  The match of alias in TMS must be in the format of the actual address, not a regular expression.  The only exception is if you plan to use a variable in your speech that represent the numbers that are filled by a digital ID in the settings of conductor in MSDS.  See tasks 3 and 7 of the guide I linked in the my first answer on MSDS alias configuration ID and numeric base.

  Example of my config TMS and conductor.  Note the {\d{3} in the driver alias correspond to the digital ID 3-digit base where TMS will insert it into the alias instead of the %, which will allow any person handing Chief conductor to match the alias TMS generated since it is adding 3 numbers because of the digital ID.

  • Alias of conductor - (871005\d{3})(@domain\.com)?
  • TMS alias - [email protected]/ * /.
  • MSD digital ID base - 100

  Looking at the alias you are trying to configure, you want to have some numbers inserted into the address represented by \d.  According to what your digital ID base, I would do the following.

  • Conductor alias - 51\d{#}(@domain\.com)?
    • # number must represent the number of digits of your digital card, if you are only using a single digit, and then use only \d and remove the {#}.
  • TMS alias - [email protected]/ * /.

  (@domain\ .com)? helps the driver to match the alias with and without the portion of the field incoming calls.

• Time format hurt TMS Scheduler

  Much of community support.

  As you can see on the screenshot that the problem with the German version of the Planner, is that the time is not indicated, after 12:45 it shows 01:00 instead of 13:00, you are aware of this problem?

  Kind regards

  Christian

  Hi this case has been resolved

  It's in the registry server TMS under HKEY_USER\. Default\Control Panel\International

  

  These two fields missing AM and PM when re-filled the AM PM problem disappeared.

  

  This area has changed in hh: mm which has initiated the German time to show in 24-hour format.

  Then, the problem has been resolved.

  / Magnus

• TMS scheduling for a limited time.

  Hello all, I already know it there are no solution, but is not to ask

  My client has a solution with integration of TMS with excenge, he asks me if it is possible to limit the maximum time for planning a meeting.

  Thanks in advance.

  Greetings

  Sandra

  Hello

  You can check this on the side of the Exchange. If you want the maximum duration is for example three-hour meeting, you can set the value of maximum (minutes) on the Exchange resource to 180.

  For more information:

  • http://www.MSExchange.org/articles-tutorials/Exchange-Server-2010/management-administration/resource-mailboxes-Exchange-2010-part3.html

  Kind regards

  Kjetil

• Question of TIMESTAMPADD (SQL_TSA_YEAR) (with leap years)

  Dear community OBIEE,

  Any who have suffered no problems when you use timestampadd (SQL_TSI_YEAR, 55, 'Date of birth')?  Most of the result were correct with the exception of a few minute question when a DOB fell 2/28/20... (number pair year). Is there a work around for a such minute but difficult behavior OBIEE?

  Kind regards.

  -Felix

  For me, it's showing as expected.

  See below. in my case I have not value date 28/02/1977 so formulated according to the needs. Maybe this would be a reason to see the 28/02/2032

  

• Leap year Date issue (example)

  Please see the link to the document:

  Dropbox - DateIssue.pdf

  When the drop-down list FROM 28/02/2016 chosen, the date of Monday throws an error.

  The rest of the dates change, but Monday does not change because it is supposed to be on 02/29 (see the screenshot). Any help is appreciate! Thank you!!

  

  First of all, you have an error in another script that causes this error message to show whenever you make a change in the menu drop-down:

  TypeError: DeptData [cDeptName] is undefined

  5:field:keystroke

  In addition, there is a bug in your code for the custom calculation of the field Monday. The last line of it is:

  Event.Value = util.printd ("mm/dd /", d);

  It should be:

  Event.Value = util.printd ("mm/dd", d);

  However, what you see is most likely caused by a bug in Acrobat itself. You can overcome by simply removing the size of your fields of date setting. You don't really need anyway because their values are calculated and allows you to determine what format they need in the calculation script.

• How handle the date of the leap year in the query?

  Dear Exparts
  Hope you will be fine.
  Here is my banner

  Oracle Database 10g Enterprise Edition Release 10.2.0.3.0 - Prod

  I have a date field name birth_date where I stored the date of birth. I need to choose the date of birth in a given range. For example

  BIRTH_DATE
  -------------------------
  01-FEB-1980
  12-FEB-1984
  29-FEB-1992
  01-MAR-1986
  01-APR-1986
  22-APR-1988
  01-MAR-1992

  The setting of my research is

  brith_date between 01/02/13 and 01/04/13

  I want the file

  01-FEB-1980
  12-FEB-1984
  29-FEB-1992
  01-MAR-1986
  01-APR-1986

  Here is the script
  create table

  CREATE TABLE DATE_OF_BIRTH 
  (
    BIRTH_DATE DATE 
  );

  inserting data

  insert into DATE_OF_BIRTH 
  values(to_date('01-FEB-1980','DD-MON-RRRR'));
  insert into DATE_OF_BIRTH 
  values(to_date('12-FEB-1984','DD-MON-RRRR'));
  insert into DATE_OF_BIRTH 
  values(to_date('29-FEB-1992','DD-MON-RRRR'));
  insert into DATE_OF_BIRTH 
  values(to_date('01-MAR-1986','DD-MON-RRRR'));
  insert into DATE_OF_BIRTH 
  values(to_date('01-APR-1986','DD-MON-RRRR'));

  Thanks in advance... (Thanks to Frank Kulash)
  
  ask2Learn
  
  Published by: asked to learn, on 24 February 2013 19:40

  select  *
    from  date_of_birth
    where to_char(birth_date,'mmdd') between '0201' and '0401'
  /
  
  BIRTH_DAT
  ---------
  01-FEB-80
  12-FEB-84
  29-FEB-92
  01-MAR-86
  01-APR-86
  
  SQL>
  

  SY.

• Count of the number of days in a calendar month according to the year

  Hi all

  On my table, column 1 is the list of months over several years.

  Column 2 is the activity number od each month.

  Column 3 I want an average rate of activity per day during the month, which should be: (C2 / number of days according to C1) %

  Problem: I can't find a fomula give me the number of days, particularly in February when the year is leap.

  Any help is appreciated.

  Thank you all,

  Lopez

  PS: by the way, with this new version of Apple Comunity I seem to have lost my previous questions about the numbers.

  

  Hey Lopez,

  EOMONTH(A1,0) (end of month) will GET help you.

  Column B is Date & time format to display only the month and year (actually the 1st of the month, but the day is not displayed).

  

  Formula in C2 (fill down)

  = EOMONTH(B2,0)

  The end of the month 0 months later.

  

  Formula in D2 (fill down)

  = DAY (C2)

  February 2015 (non-leap years) shows 28

  February 2016 (leap year) shows 29

  Kind regards

  Ian.

• Leap day scam?

  Then, I got an email from app store (at) News (dot) itunes (dot) com with the subject, free 'big five Apps - February 29 only.' The link led me to the iTunes download page. So, I opened iTunes and tested on... Clicked on buy and was charged. It seems that the email came with the same address my other emails on AppStore, so I don't know what is happening. I asked for a refund, but I don't know if anyone else has got his email.

  < Email published by host >

  There are 5 free apps, today only, and all are free. You find the list of leap year on the page of the App Store.

  

• Number of weeks in a given year

  Dear community members-

  When you make the calendar in Apple 3.5.3 many experiences I came across the following surprise regarding the WEEKNUM function, which is described as follows:

  The WEEKNUM function returns the week number in the year for a date/time value or a date string.

  • WEEKNUM (date, day)
    • Date: a string date or the date/time value.
    • first day: a modal value that specifies whether the weeks start Sunday or Monday.
      • Sunday is 1 (1 or omitted): Sunday is the first day (day 1) week and Saturday is day 7.
      • Monday is 1 (2): Monday is the first day (day 1) week and Sunday is day 7.

  According to https://en.wiki2.org/wiki/Year_2012 2012 is a leap year starting on Sunday. As such, he had 52 weeks according to ISO 8601 as 31/12/2012 was part of week 1 of 2013. Treat the documentation for the function as a specification of the function must return never any value other than 52 or 53.

  What is someone is able to explain the result shown in the screenshot?

  

  Automiser Hello,

  I don't know what you have in the cell that displays 2012.

  I don't think you need the DATE function in the third column.

  Try this.

  While playing with Dates in 2012 and 2016... Dates in column A and column B are the same. Date & time formats are different. (Format panel > cell > Format data > Date & time > no times)

  

  Formula in C2 (fill down)

  = WEEKNUM(B2,2)

  Who is?

  Kind regards

  Ian.