Question on connect by level 2 records

Similar Questions

• Connect by level using the count of the records collection

  Hello:
  
  PROBLEM:
  ...
  ), (select rownum number months of double connect by level < = Cnt)
  
  Causes not valid ORA-00904 identifier. Why can I not use "Cnt" of my main as request by using a constant in the works?
  
  The value of count is determined for each date range in the section, I return the records that I need?
  
  Thank you, Sidney
  
  BACKGROUND:
  I have to be able to display a list of tax returns to my users and the status of these statements. There's no physical feedback so it is necessary to create data dynamically records using appropriate selection. It's not hard and I thought that would be enough to use a connection by level to give me the date, statements of information so that I can calculate and display the individual. However oracle gives me an ORA-00904 when I try to send the "Cnt" value to connect by level. Everything works fine when I provided a constant instead of "CNT". The "CNT" value is determined by a complex process that calculates start and end for several types of return dates, etc as well as the number of periods and frequency of production. The data must be generated dynamically using a master record, which then gives the history of coding in which my collection of basic records is selected. Here is the result of this process:
  
  TaxpayerNo, TaxClass TaxCode, FilingFequency, StartDate, StopDate, Cnt, frequency
  
  10 S 1 M 12-18 6/1/2007-11/30/2008
  10 S 2 M 12 10 30/11/2008-9/30/2009
  10 S, 2 Q 4 3 11/30/2010-8/18/2011
  L 10 8 6/1/2007 9/30/2009 3 1
  L 10 8 11/30/1 / 2010 8/18/2011 1
  
  According to the results, I have needs a record for each every month, quarter, etc. ie:
  
  10 S 1 M 6/1/2007 11/30/2008 18 12 6/1/2007
  10 S 1 M 6/1/2007 11/30/2008 18 12 7/1/2007
  10 S 1 M 6/1/2007 11/30/2008 18 12 8/1/2007
  10 S 1 M 6/1/2007 11/30/2008 18 12 9/1/2007
  ...
  10 S 2 M 30/11/2008-9/30/2009 10 12 11/30/2008
  10 S 2 M 30/11/2008-9/30/2009 10 12 12/30/2008
  ...
  etc.
  
  DOES NOT WORK
  Select y.*, MonthNo, Add_Months(StartDate,MonthNo*Frequency) in)
  Select x.*,
  (case when FilingFrequency = am' then Ceil (Months_Between (StopDate, StartDate)))
  When FilingFrequency = 'Q' then Ceil (Months_Between(StopDate,StartDate)/3)
  When FilingFrequency = 'A' Ceil (Months_Between(StopDate,StartDate)/12) then
  0 otherwise
  end) NTC,
  (case when FilingFrequency = am' then 1)
  When FilingFrequency = 'Q' then 3
  When FilingFrequency = 'A' then 12
  end) frequency
  de)
  ... a code complex to calculate values of start and stop dates required above...
  ) x
  ), (select rownum number months of double connect by level < = Cnt)
  ERROR MESSAGE
  The result is ORA-00904: "CNT": invalid identifier. I do not get an error if I use a constant:
  
  WORK WITH THE HELP OF A CONSTANT, BUT MUST HAVE THE VALUE OF THE ACTUAL CNT
  ... Same code for generating data...
  ), (select rownum number months of double connect by level < = 3)
  
  How can I get it works using the "CNT" value instead of a constant?

  A technique like this should solve your problem.

  TUBBY_TUBBZ?with data (col1, cnt) as
    2  (
    3    select 1, 3 from dual
    4      union all
    5    select 2, 2 from dual
    6  )
    7  select
    8    d.col1,
    9    t.column_value
   10  from
   11    data  d,
   12    table(cast(multiset(select level from dual connect by level <= d.cnt) as sys.OdciNumberList)) t;
  
                COL1       COLUMN_VALUE
  ------------------ ------------------
                   1                  1
                   1                  2
                   1                  3
                   2                  1
                   2                  2
  
  5 rows selected.
  
  Elapsed: 00:00:00.00
  TUBBY_TUBBZ?
  

  Contrary to what you have now, which is basically this

  TUBBY_TUBBZ?with data (col1, cnt) as
    2  (
    3    select 1, 3 from dual
    4      union all
    5    select 2, 2 from dual
    6  )
    7  select
    8    d.col1,
    9    level
   10  from
   11    data  d
   12  connect by level <= d.cnt;
  
                COL1              LEVEL
  ------------------ ------------------
                   1                  1
                   1                  2
                   1                  3
                   2                  2
                   1                  3
                   2                  1
                   1                  2
                   1                  3
                   2                  2
                   1                  3
  
  10 rows selected.
  
  Elapsed: 00:00:00.00
  TUBBY_TUBBZ?
  

• My laptop suddenly stopped opening my Hotmail emails. I can connect to Hotmail and records are regularly updated with new emails, but nothing happens when I try to read an email.

  My laptop suddenly stopped opening my Hotmail emails.  I can connect to Hotmail and records are regularly updated with new emails, but nothing happens when I try to read an email.  The cursor will just highlight the particular word on what it is and do nothing.  As far as I know, nothing else was done on my computer.  This could be the cause?

  original title: cannot open emails.

  Hello

  The best place to ask your question of Windows Live is inside Windows Live help forums. Experts specialize in all things, Windows Live, and would be delighted to help you with your questions. Please choose a product below to be redirected to the appropriate community:

   

  Windows Live Mail

  Windows Live Hotmail

  Windows Live Messenger

   

  Looking for a different product to Windows Live? Visit the home page Windows Live Help for the complete list of Windows Live forums to www.windowslivehelp.com.

• Use of RegExp and connect by level in Oracle SQL

  Hello
  
  Can someone help me to know about the use of regular expressions and the concept connect by level in oracle SQL?
  
  Thanks adavance

  Prakash wrote:
  Hello

  select regexp_substr(str, '[^,]+', 1, level) val
  from (select 'a,b,c,d' str from dual)
  connect by level <= length(str) - length(replace(str,','))+1
  
  i  tried my level to understand it but couldn't
  
  Please explain  how it works
  

  Please only put code in tags code, otherwise it's hard to see what you're asking.

  In response to your question look at the query...

  SQL> select regexp_substr(str, '[^,]+', 1, level) val
    2      from (select 'a,b,c,d' str from dual)
    3   connect by level <= length(str) - length(replace(str,','))+1
    4  /
  
  VAL
  -------
  a
  b
  c
  d
  

  OK, so clearly it's split the string anywhere where there is a comma, then, how he does it.

  Firsly we look at connect by clause it when we use it as a generator of line...

  SQL> select level from dual connect by level <= 4;
  
       LEVEL
  ----------
           1
           2
           3
           4
  

  Now, look at how the number 4 is calculated from the string...

  SQL> select length('a,b,c,d') - length(replace('a,b,c,d',','))+1 from dual;
  
  LENGTH('A,B,C,D')-LENGTH(REPLACE('A,B,C,D',','))+1
  --------------------------------------------------
                                                   4
  

  ... looking at the length of the string and the length of it without comma, we can determine how many commas are in the chain and the surmize that there must be 1 more value there are commas.

  Now look at the regular expression...

  SQL> select regexp_substr('a,b,c,d', '[^,]+', 1, 1) from dual;
  
  R
  -
  a
  
  SQL> select regexp_substr('a,b,c,d', '[^,]+', 1, 2) from dual;
  
  R
  -
  b
  
  SQL> select regexp_substr('a,b,c,d', '[^,]+', 1, 3) from dual;
  
  R
  -
  c
  
  SQL> select regexp_substr('a,b,c,d', '[^,]+', 1, 4) from dual;
  
  R
  -
  d
  

  The 4th parameter of the regexp_substr function is the 'presence' of the search string to return.

  The actual regular expression itself is looking for 1 or more characters (sign +) who are not (the ^ symbol) a comma.

  Is that more clear?

• SQL - connect by level problem

  Hello
  
  Under query returns only first 50 records but his having 233 files.
  
  SELECT TO_CHAR (INN. START_DATE + LEVEL-1, ' DD/MM/YYYY') GENERATION_DATE OF
  (SELECT TO_DATE (3 JULY 2011 ', ' DD/MM/YYYY') START_DATE, TO_DATE (OCTOBER 25, 2011 ', ' DD/MM/YYYY') END_DATE DOUBLE) INN
  CONNECTION OF LEVEL between 1 and INN. END_DATE-INN. START_DATE + 1;
  
  
  What is the exact problem in the operator level. Please suggest me.
  
  
  
  Concerning
  Sudhakar P.

  What are you talking about?

  SQL> select count(*) from(
    2  SELECT TO_CHAR(INN.START_DATE+LEVEL-1, 'DD/MM/YYYY') GENERATION_DATE FROM
    3  (SELECT TO_DATE( '07/03/2011' ,'DD/MM/YYYY') START_DATE, TO_DATE( '25/10/2011' ,'DD/MM/YYYY') E
  ND_DATE FROM DUAL) INN
    4  CONNECT BY LEVEL between 1 and INN.END_DATE-INN.START_DATE+1);
  
    COUNT(*)
  ----------
         233
  
  1 row selected.
  
  Elapsed: 00:00:00.00
  

  He returns 233 records.

• Connection issues - connection of a tape recorder to the computer (Windows 7)

  I was connecting a recorder to the computer (Windows 7) in order to play music on cassettes, a cable connecting the recorder output to the audio jack on the back of the computer.

  It has always worked perfectly, but I suddenly lost the sound. Going to "Control Panel - Sound" shows "line in" Panel "not connected". Certainly, it is plugged! I tried disconnecting and reconnecting the cable, restarting the computer, connect an another cassette recorder and I have now run out of ideas. Everything I try, in 'line' service continues to insist that it is "unplugged". (The function "StΘrΘo in" still works perfectly).

  When you plug the plug at the end of the head of the tape recorder, I receive a message saying "you have just plugged a device in the audio Jack" so presumably the decision itself is not defective.

  Any ideas?

  Former title: connection problems

  I was connecting a recorder to the computer (Windows 7) in order to play music on cassettes, a cable connecting the recorder output to the audio jack on the back of the computer.

  It has always worked perfectly, but I suddenly lost the sound. Going to "Control Panel - Sound" shows "line in" Panel "not connected". Certainly, it is plugged! I tried disconnecting and reconnecting the cable, restarting the computer, connect an another cassette recorder and I have now run out of ideas. Everything I try, in 'line' service continues to insist that it is "unplugged". (The function "StΘrΘo in" still works perfectly).

  When you plug the plug at the end of the head of the tape recorder, I receive a message saying "you have just plugged a device in the audio Jack" so presumably the decision itself is not defective.

  Any ideas?

  The problem has been resolved. I called our local computer store and they took the remote control of my computer and decided that, in the window manager Audio Realtek, the 'speaker setup' DD was somehow got moved from "Stereo" 5.1 speakers"fix that solves the problem but I'm perplexed that a configuration setting incorrect speaker should block the function 'In Line' leaving all other sound effects works perfectly; However, he seems to have done the trick. If this is not the first instance of parameters change in Windows 7 on their own accord.

  RF

• Explanation connect by level

  Hi gurus. Can someone explain to me under requests, why connect by the work in this way. Differences between 2 requests is marked by red color.

  WITH TAB(KEY_ID,KEY_1) AS
  (SELECT 1,'Z/D/YYYY/MM' FROM DUAL
    UNION ALL
   SELECT 2,'YYYY/MM/Z/D' FROM DUAL)
        SELECT LISTAGG(CASE
                        WHEN KEY_1 = 'Z' THEN
                          'TEST_Z'
                        WHEN KEY_1 = 'D' THEN
                          TO_CHAR(EXTRACT(DAY FROM SYSDATE))
                        WHEN KEY_1 = 'YYYY' THEN
                          TO_CHAR(EXTRACT(YEAR FROM SYSDATE))
                        WHEN KEY_1 = 'MM' THEN
                          TO_CHAR(EXTRACT(MONTH FROM SYSDATE))
                        END, '/') WITHIN GROUP (ORDER BY LVL)CONVERT_KEY, MAX(KEY_ID) KEY_ID,
                        COUNT(DISTINCT KEY_ID) CNT
        FROM (SELECT REGEXP_SUBSTR(REGEXP_REPLACE(KEY_1, '[^[:graph:]]', ''), '[^/]+', 1, LEVEL)KEY_1,
                     LEVEL LVL, KEY_ID
                FROM(SELECT * 
                       FROM TAB
                      WHERE KEY_ID = 1)
             CONNECT BY LEVEL <= LENGTH(REGEXP_REPLACE(KEY_1, '[^/]+')) + 1);
  

  Correct output:

  convert_key	Key_ID	cnt
  TEST_Z/20/2015/4	1	1

  WITH TAB(KEY_ID,KEY_1) AS
  (SELECT 1,'Z/D/YYYY/MM' FROM DUAL
    UNION ALL
   SELECT 2,'YYYY/MM/Z/D' FROM DUAL)
        SELECT LISTAGG(CASE
                        WHEN KEY_1 = 'Z' THEN
                          'TEST_Z'
                        WHEN KEY_1 = 'D' THEN
                          TO_CHAR(EXTRACT(DAY FROM SYSDATE))
                        WHEN KEY_1 = 'YYYY' THEN
                          TO_CHAR(EXTRACT(YEAR FROM SYSDATE))
                        WHEN KEY_1 = 'MM' THEN
                          TO_CHAR(EXTRACT(MONTH FROM SYSDATE))
                        END, '/') WITHIN GROUP (ORDER BY LVL)CONVERT_KEY, MAX(KEY_ID) KEY_ID,
                        COUNT(DISTINCT KEY_ID) CNT
        FROM (SELECT REGEXP_SUBSTR(REGEXP_REPLACE(KEY_1, '[^[:graph:]]', ''), '[^/]+', 1, LEVEL)KEY_1,
                     LEVEL LVL, KEY_ID
                FROM TAB
               WHERE KEY_ID = 1
             CONNECT BY LEVEL <= LENGTH(REGEXP_REPLACE(KEY_1, '[^/]+')) + 1);
  

  Poor performance:

  convert_key	Key_ID	CNT
  TEST_Z/20/20/2015/2015/2015/2015/4/4/4/4/4/4/4/4	1	1

  WHERE in hierarchical queries this clause is applied AFTER the construction of a hierarchy.

  SY.

• Generation SQL line with connection by level

  Hello

  I'm looking for generate lines based on a quantity of part numbers.  I have looked all around several techniques for the generation of the line, but have failed to address this problem.  The current method, it seems pulls a permutation of all possible combinations, and the result is rising quickly to millions / billions of documents... which is not the answer.  Someone out there who could help writing a query to do this?

  What I try to achieve if a quantity of part 5, I want to display 5 Qty 1 documents.  If the Qty 12, then 12 Qty 1 documents.  So on and so forth.

  Out Oracle 10.2.0.4 operation

  Sample data:

  drop table test;

  create table test (part varchar2 (20), number of quantity);

  Insert test values ('WIDGET', 12);

  Insert test values ('FOO', 5);

  Insert test values ('THING', 3);

  Insert test values ("WAD", 8);

  commit;

  -This query does not work... I think it's getting all the possible permutations

  -Select a part, 1

  -to test

  -connect by level < = Qty

  -what I want to see...

  Part Qty.

  ------      ----

  WIDGET 1

  WIDGET 1

  WIDGET 1

  WIDGET 1

  WIDGET 1

  WIDGET 1

  WIDGET 1

  WIDGET 1

  WIDGET 1

  WIDGET 1

  WIDGET 1

  WIDGET 1

  FOO 1

  FOO 1

  FOO 1

  FOO 1

  FOO 1

  THING 1

  THING 1

  THING 1

  BUNDLE 1

  BUNDLE 1

  BUNDLE 1

  BUNDLE 1

  BUNDLE 1

  BUNDLE 1

  BUNDLE 1

  BUNDLE 1

  Hello

  You want something like this:

  SELECT part

  Qty. 1

  OF the test

  CONNECT NOCYCLE LEVEL<=>

  AND an EARLIER part = part

  AND PRIOR SYS_GUID () IS NOT NULL

  ;

  You may have copied the request of something that just use the array of double.  When you have more than 1 row of the table, then you need by using the PRIOR operator in the CONNECT BY clause.

• Connect by PRIOR vrs Connect by LEVEL

  Hello

  I'm trying to understand the difference between CONNECT BY PRIOR and CONNECT BY LEVEL

  I know that CONNECT BY PRIOR is basically specifying a hierarchy and which column / field is the parent (using the PRIOR)

  for example

  SELECT employe_id, employee_name, level

  Employees

  CONNECT BY PRIOR employee_id = manager_id;

  
  Q1. What is CONNECT BY LEVEL (for example as shown below) practice? What type of relationship normally described? (below, it is just producucing a series of integers)

  SELECT the level

  OF the double

  CONNECT BY LEVEL < = 10;

  T2. Use LEVEL with CONNECT BY in this way, a subversive use of the CONNECT IN knowledge is really intended to be used this way?

  any advice appreciated,

  Jim

  Hi, Jim,.

  Jimbo wrote:

  Hello

  I'm trying to understand the difference between CONNECT BY PRIOR and CONNECT BY LEVEL

  I know that CONNECT BY PRIOR is basically specifying a hierarchy and which column / field is the parent (using the PRIOR)

  for example

  SELECT employe_id, employee_name, level

  Employees

  CONNECT BY PRIOR employee_id = manager_id;

  Sometimes, CONNECT BY using hierarchical data, such as a tree.  In these cases, it may be useful to use the terns as "parent" and "child."  The query above is one of these cases.

  In more general terms, CONNECT BY returns the union (UNION ALL, specifically) of lines found by the START WITH clause (LEVEL = 1) and lines found by the clause CONNECT BY (LEVEL > 1).  If there is no START WITH clause, every row in the table will appear on LEVEL = 1.

  If there is no line on LEVEL = N, then Oracle research lines that meet the CONNECT BY clause, to search for the lines that are connected to each line level = N, for put the LEVEL N + 1.  If the CONNECT BY clause is set to TRUE for a given row, while the rank will appear on level N + 1 =.  Often (but not always) the CONNECT BY clause uses the PRIOR operator.  After PRIOR consent refers to something = N level.

  Q1. What is CONNECT BY LEVEL (for example as shown below) practice? What type of relationship normally described? (below, it is just producucing a series of integers)

  SELECT the level

  OF the double

  CONNECT BY LEVEL<>

  Since there is no START WITH clause, each line of the double table will be LEVEL = 1.

  The CONNECT BY clause means that CONNECT BY always means: If there is a line at = N, then it will be connected to any line that fills the CONNECT BY conditions.

  So that the lines will be added to the level = 2?  All the lines where condition 2<= 10="" is="" true,="" so="" every="" row="" in="" the="" dual="" table="" will="" be="" on="" level="">

  What lines will be added to the level = 3?  All the lines where condition 3<= 10="" is="" true,="" so="" every="" row="" in="" the="" dual="" table="" will="" be="" on="" level="">

  ...

  What lines will be added to the level = 10?  All the lines where the condition of 10<= 10="" is="" true,="" so="" every="" row="" in="" the="" dual="" table="" will="" be="" on="" level="10." 10="" is="" true,="" so="" every="" row="" in="" the="" dual="" table="" will="" be="" on="" level="">

  What lines will be added to the level = 11?  All the lines where condition 11<= 10="" is="" true,="" so="" no="" row="" in="" the="" dual="" table="" will="" be="" on="" level="">

  Since no rows are added to the LEVEL = 11, CONNECT BY query stop right there.

  Q2. Use LEVEL with CONNECT BY in this way, a subversive use of the CONNECT IN knowledge is really intended to be used this way?

  You can think of it as being subversive.  It was certainly not how planners and the deveopers at Oracle for CONNECT BY work in versions 2 to 8; you got an error if you tried in these versions.  It is also an exception to the rule that no line can be his own ancestor.

• Need help with a query of type "connect by level.

  Hello, I recently met 'connect by level' and I think he can solve my problem, but maybe not. I would like to create rows of data where the number of rows created varies according to the data from the original table.

  It works:

  with times like

  (select to_date (' 26/01/2014 01:00 ',' dd/mm/yyyy hh24:mi:ss') starttime,)

  TO_DATE (' 27/01/2014 00:00:00 ',' dd/mm/yyyy hh24:mi:ss') stoptime

  the double)

  Select starttime, stoptime, starttime + rownum / 24

  of the time

  connect by level < =.

  (Select trunc ((stoptime-starttime) * 24: 2) at the time)

  I would like to do something similar for several lines (following does not work)

  with times like

  (select to_date (' 26/01/2014 01:00 ',' dd/mm/yyyy hh24:mi:ss') starttime,)

  TO_DATE (' 27/01/2014 00:00:00 ',' dd/mm/yyyy hh24:mi:ss') stoptime

  of the double

  Union

  Select to_date (' 25/01/2014 18:00 ',' dd/mm/yyyy hh24:mi:ss') starttime.

  TO_DATE (' 27/01/2014 00:00:00 ',' dd/mm/yyyy hh24:mi:ss') stoptime

  the double)

  Select starttime, stoptime, starttime + rownum / 24

  of the time

  connect by level < =.

  (Select trunc ((stoptime-starttime) * 24: 2) at the time)

  I need to stay away from solutions of PL/SQL, this query will be wrapped in an application that can not handle the PL/SQL, going and coming from the database (I also suck in PL/SQL).

  Any help would be greatly appreciated, I have no knowledge here, I tried to read some of the documentation on hierarchical queries, but it is not yet clicking.

  Thank you!

  Or also:

  SQL > WITH times

  2 ALSO (SELECT TO_DATE (' 01:00 26/01/2014 ', "hh24:mi:ss dd/mm/yyyy") Starttime)

  3, TO_DATE (' 01/26/2014 03:00 ', 'hh24:mi:ss dd/mm/yyyy') Stoptime

  4 FROM TWO

  5 UNION

  6 SELECT TO_DATE (' 25/01/2014 18:00 ', "hh24:mi:ss mm/dd/yyyy") Starttime

  7, TO_DATE (' 25/01/2014 22:00 ', 'hh24:mi:ss dd/mm/yyyy') Stoptime

  8 DOUBLE)

  9. SELECT T.*, Starttime + Lvl / 24

  10. OF time T

  11, (SELECT LEVEL Lvl

  THE DOUBLE 12

  13 CONNECT BY LEVEL<>

  14 (SELECT MAX (TRUNC ((Stoptime-Starttime) * 24)))

  15 AT the time)):

  16. WHERE the lvl<= trunc="" (="" (stoptime="" -="" starttime)="" *="">

  17 ORDER 1, 3

  18.

  STARTTIME STOPTIME-STARTTIME + LVL/24

  ----------------------------- ----------------------------- -----------------------------

  January 25, 2014 18:00 January 25, 2014 22:00 January 25, 2014 19:00

  January 25, 2014 18:00 January 25, 2014 22:00 January 25, 2014 20:00

  January 25, 2014 18:00 January 25, 2014 22:00 January 25, 2014 21:00

  January 25, 2014 18:00 January 25, 2014 22:00 January 25, 2014 22:00

  26 January 2014 01:00 26 January 2014 03:00 January 26, 2014 02:00

  26 January 2014 01:00 26 January 2014 03:00 January 26, 2014 03:00

  6 selected lines.

• Connect by level - with several lines of inpur

  Very simplified, I have this table - it has a 'table' as a variable-length structure.
  
  I need x line of output for each input line (do not use pipelining og PL/SQL function)
  Wih a single line as input of the "log in"-it works of course.
  

  drop table test3;
  create table test3 (id number, tekst varchar2(20));
  
  insert into test3 values (1, 'acbdef');
  insert into test3 values (2, '123');
  insert into test3 values (3, 'HUUGHFTT');
  insert into test3 values (4, 'A');
  insert into test3 values (5, 'AKAJKSHKJASHKAJSHJKJ');
  commit;
  
  with tal as
  (
  select * from
  (select a.*, rownum rn
  from test3 a)
  where rn < 2)
  ------
  select tekst, level , 
  substr(tekst,(level-1)*1+1, 1) content
  from tal
  connect by level < length(tekst) 
  ;

  How to achieve the same thing for several input lines?
  I know I can do it in PL/SQL using plan either pl or just a function in the pipeline, but I prefer a clean if possible SQL.
  I tried to do in a cross join test3 and (select different values of double the test3 table) and other versions, but all with syntax errors
  

  with tal as
  (
  select * from
  (select a.*, rownum rn
  from test3 a)
  where rn < 3)
  ------
  select * from test3 cross join table 
  (
  select tekst, level , 
  substr(tekst,(level-1)*1+1, 1) content
  from dual
  connect by level < length(tekst)
  )
  ;

  Oracle version will be 10.2 and 11 +.

  I think it's kind of what you're looking for:

  with tal as
  ( select 1 id, 'acbdef' tekst         from dual union
    select 2   , '123'                  from dual union
    select 3   , 'HUUGHFTT'             from dual union
    select 4   , 'A'                    from dual )
  ------
  select  id, tekst, level, substr(tekst,(level-1)*1+1, 1) content
    from  tal
  connect by (    level <= length(tekst)
             and  prior id = id
             and  prior dbms_random.value is not null
             )
  ;
  
          ID TEKST         LEVEL CONTENT
  ---------- -------- ---------- -------
           1 acbdef            1 a
           1 acbdef            2 c
           1 acbdef            3 b
           1 acbdef            4 d
           1 acbdef            5 e
           1 acbdef            6 f
           2 123               1 1
           2 123               2 2
           2 123               3 3
           3 HUUGHFTT          1 H
           3 HUUGHFTT          2 U
           3 HUUGHFTT          3 U
           3 HUUGHFTT          4 G
           3 HUUGHFTT          5 H
           3 HUUGHFTT          6 F
           3 HUUGHFTT          7 T
           3 HUUGHFTT          8 T
           4 A                 1 A       
  

• ORA-01446 tabular with CONNECTION BY LEVEL &lt; = 2

  I created a tabular presentation where I want the 2 last lines be empty so that the user can enter new lines immediately (for example, the first time that no data is found).
  Here's the sql code of the form of tables:

  select 
  "ID",
  "REQ_ID",
  "QUANTITY",
  "FRAME_SIZE",
  "FRAME_TYPE",
  "PROTECTIVE_COVERING",
  "MATT",
  "MATT_COLOR"
  from "#OWNER#"."CREATIVE_SVC_DESIGN_FRAMING"
  union all
  select
  null id,
  null req_id,
  null quantity,
  null frame_size,
  null frame_type,
  null protective_covering,
  null matt,
  null matt_color
  from dual
  connect by level <= 2 

  I get the following error:
  Failed to parse the SQL query:
  ORA-01446: cannot select ROWID, or sample, a view with DISTINCT, GROUP BY, etc.
  
  The query is not access ROWID view at all. And, as you can see, it does not use a DISTINCT, GROUP BY, etc...
  
  My APEX is Application Express 4.0.2.00.07
  My database is 10g (10.2.0.5.0)
  
  Help, please!
  
  Robert
  http://apexjscss.blogspot.com

  Robert,

  I wish I had a better explanation for you, but I know something again with 4.1 broke this trick union for tabular forms. I had to do a dynamic action that runs when the page loads and calls the javascript function of the: AddRow(). I think it has something to do with the validation of the form in a table, but I'm not sure.

  See you soon,.
  Janet Tyson

• CONNECTION BY level/prior/root

  Hi all
  
  I'm trying to CONNECT BY level/prior/root. But I can barely decipher what it actually does. I think it is a very useful method provided by oracle and can have several uses. can someone help me on this please.
  
  I googled on this topic but everywhere I could find only employee and manager problem that will be solved by query below.
  

   SELECT employee_id, last_name, manager_id
     FROM employees
     CONNECT BY PRIOR employee_id = manager_id;

  But if we just query as below, we can get the employee and his manage without CONNECT BY.

  SELECT employee_id, last_name, manager_id
     FROM employees;

  Other queries is obtained to connect by is below, but he could not also include:

   select SYSDATE-41 + level - 1 the_date
                              from dual
                            connect by level <= SYSDATE - SYSDATE-41 + 1

  Please help me.
  
  Published by: J2EE_Life on December 6, 2011 08:12

  J2EE_Life wrote:
  Hi all

  I'm trying to CONNECT BY level/prior/root. But I can barely decipher what it actually does. I think it is a very useful method provided by oracle and can have several uses. can someone help me on this please.

  I googled on this topic but everywhere I could find only employee and manager problem that will be solved by query below.

  SELECT employe_id, last_name, manager_id
  Employees
  CONNECT BY PRIOR employee_id = manager_id;

  But if we just query as below, we can get the employee and his manage without CONNECT BY.

  SELECT employe_id, last_name, manager_id
  Employees;

  In fact, those who are not the same.
  If you use the standard table of hr.employees, the CONNECT BY query above returns 315 lines, but the secoind query return lines only 107.

  CONNECTION is useful to show the recursive relationships. It can show you, for example, not only that reports directly to a data manager, but the whole hierarchy of persons under a given head. For example, the following shows the hierarchy starting with an employee named "Rooster":

  SELECT  employee_id, last_name, manager_id
  ,     LEVEL                         AS lvl
  ,     SYS_CONNECT_BY_PATH (last_name, '/')     AS path
  FROM    hr.employees
  START WITH      last_name          = 'De Haan'
  CONNECT BY       PRIOR employee_id      = manager_id;
  
  SELECT     SYSDATE - SYSDATE-41 + 1
  FROM DUAL;
  

  Output:

  EMPLOYEE_ID LAST_NAME  MANAGER_ID LVL PATH
  ----------- ---------- ---------- --- --------------------------
          102 De Haan           100   1 /De Haan
          103 Hunold            102   2 /De Haan/Hunold
          104 Ernst             103   3 /De Haan/Hunold/Ernst
          105 Austin            103   3 /De Haan/Hunold/Austin
          106 Pataballa         103   3 /De Haan/Hunold/Pataballa
          107 Lorentz           103   3 /De Haan/Hunold/Lorentz
  

  Very briefly, here's how it works.
  The result set of a query CONNECT BY is the UNION ALL of several queries, all sharing a common SELECT clause.
  Any line that meets the conditions of the START WITH clause is supposed to be at LEVEL 1. So you can think of the first branch of the UNION of ALL being (in this case):

  SELECT  employee_id, last_name, manager_id
  ,     LEVEL                         AS lvl
  ,     SYS_CONNECT_BY_PATH (last_name, '/')     AS path
  FROM    hr.employees
  WHERE   last_name     = 'De Haan'
  UNION ALL ...
  

  Other rows in the result set will be LEVEL = N if the conditions of the CONNECT BY clause, where the PRIOR operator refers to any line level = N - 1.
  For example, the line with name = "Hunold" satisfies the condition to connect BY when the FIRST line is the line where last_name = "Rooster", Hunold is in the game with the LEVEL of results = 2.
  Another example: the line with name = 'Lorentz' meets the condition to connect BY when the FIRST line is the line where last_name = "Hunold", Hunold is in the result set with LEVEL = 3.
  This is a classic example of a tree structure, where the rows in the table are connected to other lines in a parent-child relationship. In a tree, each row has 0 or 1 of the parents, but a line can have any humber children. Haan has 0 parent and 1 child (that is, Hunold). Hunold has 1 parent (De Haan) and 4 children. CONNECT BY queries are useful to deal with the trees like this, especially when the parent-child relationship may extend to a number any levels.

  Other queries is obtained to connect by is below, but he could not also include:

  Select the level - 1 the_date + SYSDATE-41
  of the double
  connect by level<= sysdate="" -="" sysdate-41="" +="">

  I don't understand whether you.
  SYSDATE-SYSDATE is just 0
  0 - 41 + 1 is just-40, so you might as well say:

  select SYSDATE-41 + level - 1 the_date
                              from dual
                            connect by level <= -40;
  

  In addition, LEVEL is always a positive integer, then the CONNECT BY State will never have the value TRUE, and if the CONNECT BY clause can never be TRUE, there is no reason to have a CONNECT BY clause.
  A more reasonable request is:

  SELECT     SYSDATE + LEVEL - 1     AS the_date
  FROM      dual
  CONNECT BY     LEVEL     <= 4     -- or any positive number
  ;
  

  which produces this output, the given number of days (4 in this example) from today:

  THE_DATE
  --------------------
  06-Dec-2011 11:08:24
  07-Dec-2011 11:08:24
  08-Dec-2011 11:08:24
  09-Dec-2011 11:08:24
  

  This is a very common way to generate a Counter of Table (a table, or, as in this case, a result set, that matters). For example, if you need for the aggregates per day in a table and you want to show 0 for days that never exist in the table, then you outer join in a table of counter like the one shown above.
  This is a common use of CONNECT BY, but this is an unusual exception to the rules that is prohibited govern CONNECT BY queries. I suggest you uderstand how the query on hr.employees, above, the work before you start trying to figure out how it works.

  Published by: Frank Kulash, December 6, 2011 11:15

  The pages below are introductions to CONNECT BY:
  http://asktom.Oracle.com/pls/asktom/f?p=100:11:0:P11_QUESTION_ID:489772591421
  http://Philip.Greenspun.com/SQL/trees

• Connection by level: is there a difference between 10g and 9i?

  Hello
  
  When I run the following query

   Select level from dual connect by level <= 2 

  using Oracle10g Release2 database, I have a set of two lines:

  1
  2

  .
  But when I run the same query by using Oracle 9i database, I have an a single row result set:

  1

  .
  Please, help me understand why this difference?
  Thank you.

  Yes, there is. In the earlier versions as 9i, you must use see online:

  select  *
    from  (
           select  level
             from  dual
             connect by level <= 2
          )
  /
  

  SY.

• CONNECT BY LEVEL

  Y at - it something I do wrong below? I need generate 9 lines instead of 39. Can someone please?
  
  Thanks in advance.
  
  With the help of 10g and 11g
  

  CREATE TABLE V9_MONTHLY (
  S_ID        VARCHAR2(4),
  P_ID        VARCHAR2(4),
  F_ID        VARCHAR2(4),
  ELIGIBLE_MONTH  DATE,
  CONTRACT    VARCHAR2(4),
  S_ADDRESS_SUFFIX VARCHAR2(1),
  REV     FLOAT,
  EXPENSE     FLOAT,
  NI      FLOAT ) ;
   
  INSERT INTO V9_MONTHLY ( S_ID, P_ID, F_ID, ELIGIBLE_MONTH, CONTRACT, S_ADDRESS_SUFFIX, REV, EXPENSE, NI ) VALUES ( 'S001', 'P001', 'F001', '01-DEC-2009', 'C001', 'B', '300', '200', '100' ) ;
  INSERT INTO V9_MONTHLY ( S_ID, P_ID, F_ID, ELIGIBLE_MONTH, CONTRACT, S_ADDRESS_SUFFIX, REV, EXPENSE, NI ) VALUES ( 'S001', 'P001', 'F001', '01-JAN-2010', 'C001', 'B', '100', '1000', '-900' ) ;
  INSERT INTO V9_MONTHLY ( S_ID, P_ID, F_ID, ELIGIBLE_MONTH, CONTRACT, S_ADDRESS_SUFFIX, REV, EXPENSE, NI ) VALUES ( 'S001', 'P002', 'F002', '01-FEB-2010', 'C001', 'B', '200', '10000', '-9800' ) ;
  
  
   (    SELECT s_id, p_id, f_id, ADD_MONTHS(ELIGIBLE_MONTH,LEVEL-1) ELIGIBLE_MONTH FROM
                                                                                                                                                      ( SELECT s_id, p_id, f_id, ELIGIBLE_MONTH 
                                                                                                                                                                                                                                                                      FROM V9_MONTHLY   ) 
                                                                                                                                                                                                                                                                                     CONNECT BY LEVEL <= 3 ) 

  could you pass your connection by level go out and do his own table

  WITH counter AS (    SELECT LEVEL cnt
                         FROM DUAL
                   CONNECT BY LEVEL <= 3)
  SELECT  s_id,
         p_id,
         f_id,
         ADD_MONTHS (ELIGIBLE_MONTH, cnt - 1) ELIGIBLE_MONTH
    FROM V9_MONTHLY, counter;
  

  S_ID     P_ID     F_ID     ELIGIBLE_MONTH
  S001     P001     F001     12/1/2009
  S001     P001     F001     1/1/2010
  S001     P002     F002     2/1/2010
  S001     P001     F001     1/1/2010
  S001     P001     F001     2/1/2010
  S001     P002     F002     3/1/2010
  S001     P001     F001     2/1/2010
  S001     P001     F001     3/1/2010
  S001     P002     F002     4/1/2010
  

  believe this should work if you're a fan of the model clause

  /* Formatted on 12/10/2010 2:30:51 PM (QP5 v5.149.1003.31008) */
  SELECT s_id,
         p_id,
         f_id,
         ELIGIBLE_MONTH
    FROM V9_MONTHLY
  MODEL
     PARTITION BY (s_id, p_id, f_id, ELIGIBLE_MONTH x)
     DIMENSION BY (0 d)
     MEASURES (eligible_month)
     RULES
        ITERATE (3)
        (eligible_month [ITERATION_NUMBER] =
              ADD_MONTHS (eligible_month[0], ITERATION_NUMBER));
  

  Published by: pollywog on December 10, 2010 14:38

  and once again using recursive with

  * Formatted on 12/10/2010 3:56:49 PM (QP5 v5.149.1003.31008) */
      WITH t ( s_id,
                 p_id,
                 f_id,
                 nbr,
                ELIGIBLE_MONTH
                 ) AS
                (
                SELECT
                 s_id,
                  p_id,
                  f_id,
                  1,
                   ELIGIBLE_MONTH
                   FROM V9_MONTHLY
                   UNION /**/ALL
                    SELECT s_id,
                             p_id,
                             f_id,
                             nbr + 1,
                             ADD_MONTHS(ELIGIBLE_MONTH, 1) FROM t WHERE nbr <= 2
                   )
                   SELECT S_ID, P_ID, ELIGIBLE_MONTH FROM t
        
  

  Published by: pollywog on December 10, 2010 15:57