Range input signal

Similar Questions

• clean install of windows XP to input signal out of range

  Hi I recently took my old pc xp out of the dusty closet.
  I discovered that the operating system has been corrupted then decided to do a clean install of windows xp.
  However after that it says press any key to boot from the disk and I press a button, then it went to a screen blank and says on the monitor says "Input Signal out of range at 1280 x 1024 60hrz. change."
  I also did a reset factory monitor and hooked up the old pc to the tv.
  So I would like to know how to solve the problem, any help would be much appreciated.

  Hello

  First you using a discrete graphics card or graphics are integrated with the motherboard? Change BIOS battery (or whatever it is in the BIOS change to any method) will not change anything to do with a graphics card discrete and not likley to do much for either integrated graphics card.

  What it sounds like to me, is that the key to the race to start from the CD is not recognized and that Windows is actually booting from the hard drive with a resolution taken not supported by your monitor. But, being not there, I can't be sure of this so here are some ideas of diagnostic.

  Start the PC without the CD inserted, do you have the same problem?

  The keyboard is correctly connected?

  If a PS/2 keyboard is it plugged into the outlet of PS/2 mouse by mistake (keyboard taken are normally purple, green mouse normally Sockets)?

  Is the keyboard PS/2 or USB? You can try another keyboard ideally with the other type of interface?

  You can get in the setup of the BIOS by the appropriate key combination (usually F2 or DEL but I saw others also, look for the message at startup upwards)? If you can not it would indicate a keyboard problem.

  If you can remove the keyboard as a problem, I would return to my original question on a discrete graphics card. If there is a discreet graphics card, the motherboard is also a graphic? If this is the case, remove the discrete card and try windows set up again. Or even try installing windows with a spare graphics card if you can get your hands on one. Turn off the computer and unplug it from the socket before to remove/replace all internal components.

  Finally, what of the installation CD? Is this the one supplied with the PC? It is the recovery of the real manufacturer CD or CD from Microsoft genuine?

  Tricky

• Error, input signal is out of range on installing Windows 7

  Hello again, I install Windows 7 on my computer of mothers, but when installing, restart the computer, the screen does not work it says input signal out of range can be dis is because the video card is not a driver, we have a disk with driver say but. Help thanks for all this

  I want to thank you to you all. I solved the problem, I just connect the PC to the TV via a cable VGA windows starts normally and I go to control panel and then to the system and security, then the administrator tools, then the configuration system. When the system configuration window opens I go to the page "boot" and click on "basic video" and then apply the settings and then click on "ok" and I restart the computer. When the computer restarts I unplug the TV and plugged VGA on the monitor cable. I expect windows to load and load successfully when all was fine with the monitor. I change the screen resolution to the highest that my monitor supports. And now everything is fine. Thank you.

• off message input signal range by turning on pc - monitor hp s2031

  Hello

  I have a HP S2031's monitor I got a few weeks ago.  After I got a new video / graphics card in the computer (because the original card couldn't handle all around 1600 x 900 (60 Hz) great things.)  However, I just noticed that when I turn on the monitor and the pc - first before windows starts it is a message indicating that the input signal is out of reach of the settings at 1600 x 900 at 60 Hz.

  Now, I don't remember see this message when the original video card was in the pc ~ but I also don't always stay right there while windows starts so I can't say with certainty that the message did not exist with the original video card.

  I go to the menu on the screen section and settings are set for 1600 x 900 at 60 hz and I also right click on the desktop and in the display so that settings can also be programmed correctly it and everything is set correctly.

  This isn't a problem, unless I'm trying to access the bios.    I tried to go into bios to see what kind of options are there for the video configuration and the only options we configuration video AGP Aperture Size (64 MB). Main (AGP) graphics card. AGP hardware detected - AGP card. Only problem was that at the time where I got this far in the bios that the monitor went to sleep on me. which makes it difficult to get out of the bios and boot the computer normally on the monitor going to sleep on me.

  Anyone has an idea as to why I'm getting that message about the input signal and how do I fix as well as how do I stop the monitor going to sleep while I'm in the bios?

  I am running Windows XP Professional with sp3 and all updates and the monitor is the HP S2031.  The graphics card is a NVIDIA GeForce FX5200 and the monitor is connected to the pc with the monitor's DVI port since this card has only 2 ports dvi on it. I had an old card in the pc (which has the VGA port) but he could not show the 1600 x 900 with this card (and I'm not sure that the message was there with the old card, since most of the time that I'm not just sitting there waiting to start everything)

  I didn't notice the message until today and nothing has changed - other than the new video card and who is in the pc for about 2 weeks now.

  Any help would be much appreciate.

  Hello

  Sorry that it took so long to get back to you, but things have been very busy here (between the two to get hit with a foot of snow before Halloween and loss of power for a week still to go back to normal)

  In any case, as for the video card - it is a card ASUS NVidia GeForce FX 5200 which has 2 DVI connectors which him.  According to the information on the map

  

  Expansion / connectivity Compatible Slots 1 x AGP connectivity Interfaces

  1 x S-video input - 4 pin mini-DIN (with adapter), 1 x S-video output - 4pin mini DIN (with adapter), 1 x video composite input - RCA (with adapter), 1 x video output composite - RCA (with adapter), 2 x DVI - I - 29 pin combined DVI, VGA - HD D - Sub (HD-15) 15-pin (with adapter)

  Anyway, I tried to plug the monitor into the other DVI port, and it now works fine.  I guess that a port is bad or it is not intended for making that comes with this monitor.

  Thanks for the help and suggestions.  So they were very much appreciated.

  
  

• In Labview 8.5, what happens if the input signal exceeds the scope of the signal defined by the DAQ Assistant?

  Hi all

  This should be a pretty simple question, but I can't seem to find the answer online and currently do not have the functionality to test this:

  I'm using LabVIEW 8.5 and have a VI that imports data from sensor through the DAQ Assistant. In the configuration tab, there is a range of signal input. What happens if my sensor exceeds this range? I get a warning? The default value is the maximum (or minimum)? I was interested in writing a code to display an error that I approach the limits of this range, but did not know if I also need to include code to display an error if the scope is exceeded as well.

  Thanks for the help,

  Tristan

  Hello, Tristan,.

  The behavior depends on the selected range and the device you are using.

  If you are using a device with a single input range is valid, we will use this range, even if you set a smaller minimum and maximum in the DAQ Assistant.  So, if your device only supports ±10V and you set the range to ±8V, you will still continue to get valid data after your top sensor 8V until what you approach 10V.  When you reach the limit of the extent of your device, the output will be 'rail', and simply return the maximum value until the signal is less than the maximum value again.

  Note: A device that is nominally ±10V usually has a go-around (such as ±10.2V) which are usually specced in the manual.

  However, if you use a device with several ranges of entry then things become more complex.

  NOR-DAQmx player will choose the smallest range that entirely covers the interval you choose.  For example, suppose that your device supports the following input range: ±0.2V, ±1, ±5V, ±10V and you choose 0V - 3V as the range in the DAQ assistant.  The NOR-DAQmx driver will focus on the input range and the list of the entry lines that your hardware supports and choose the smallest encompassing the entire range that you set.  This would be the ±5V, because this is the only beach that contains up to 3V.  Thus, all between ±5V input signal is returned and none outside this range will be 'rail' to the maximum or minimum value.

  We do this because using small beaches make more efficient use of the resolution of the ADC.  So, we try to use the most effective range based on what you ask without picking up a range that will make you miss data.

  Let me know if I can clarify it more.

• How to compare analog input signals?

  Hi all

  I use PCIe6363 DAQ to collect the analog input signals. Mode of input signal is continuous and single channel several example. The sampling frequency is 2 ms/s, number of sample 100KS or less. This means DAQ 100KS of collect and draw a line/curve. I want to compare the two curves. The problem is DAQ continuously collects data and plot also continuously. Would you please is it possible to compare the curves of this operation continuous operation. The main goal is to justify whether or not the signal of incomeing maintain consistency.

  Thank you very much

  Azim

  You can store a waveform in a shift register.  Then you have in memory compared to the new waveform.

• VI to convert input signals NI 9402 in a RPM value, based on the frequency of the pulses

  Hello

  I'm looking for a VI convert an input signal NI 9402 in a RPM value, based on the frequency of the pulses. Is there such a thing that exists in the library of national instruments?

  I run LAbview 2014 integrated control and monitoring on on a cRIO 9802 high performance integrated system with NEITHER 9402, 4 channels, 50 LV, LV TTL Module input/output digital, ultra high speed digital i/o for the cRIO module.

  Any help would be greatly appreciated.

  The easiest way is to use the FPGA to get the time between the edges of your pulse increase (shift registers to maintain the current situation and the time will be necessary).  This will give you the period.  If it's a single pulse per turn, then the number of laps is just 60/T, where T is the time in seconds.

• Python DAQmx triggers a reaction of output with an input signal

  Hello world

  I use a NOR-6251 Board with a python GUI.

  I want to send data on the output channel on each falling edge of the input signal when I click on a start button.

  The level of the output signal may be 5v/0/1 (0v).

  The frequency of input signal squares is 2 MHz for 50 on it (see the attachment for more information).

  I don't know if it is better to use the analog inputs or input meter for the input signal. I think I have to set a clock pulse at the frequency of 10 MHz.

  I tried several solutions with bad results.

  Does anyone have the answers to my problem?

  Thanks in advance.

  Thanks for your reply.

  It works...

• USB-6211: analog input signal affecting another of the same map AI

  Hello

  I use the DAQ-nor-6211 map and DAQmx features to read a hammer and a signal of the accelerometer and then use other LabView functions to make the FFT of these analog input signals. However, it seems that the analog inputs where the hammer and the accelerometer are connected generate a kind of noise or influence in other entries of this data that is not connected to any other sensor acquisition board.

  I've had different experiences in order to check if the problem is with reading the card: put the accelerometer and hit the dog in another table where the DAQ card table was located (to avoid the vibrations on the map and a possible noise), ai1 entry was logged on the differential mode on the dog and the ai4 of entry is connected to the output (z axis) of the accelerometer. The other 2 ai2 and ai3, entries that can also be read by my LabView program, are open (i. e., any other sensor is connected to the card). When the structure where the accelerometer is located is struck by the hammer, the signal of ai2 ("x axis" seen in the first attached document) has a curve (on the time domain) which initialize almost at the same time that the hammer and the a3 of entry has a weak signal, but with the swing as well as the signal of ai4. The document "hammer ai1 + z_axis connected_ _x_axis disconnected ai2 + y_axis ai3 ai4" images that I captured the chart created in LabView. On these graphs, it is possible to check on the FFT the ai3 signal and ai4 has the same behavior (with different intensities), and enlarged figure of time domain image, we can see that the signal of ai2 increase almost at the same time of the signal of the hammer (ai1). The signal picked up by the sensors are probably creating a sort of noise on open entries ai2 and ai3.

  Another experiment was conducted to check if the signal from a single entry that may affect the signal read from each other near the entrances: the DAQmx task Create channel had a physical channel has changed: ai3 entry has been modified by ai7 (maintain the same connection mode: differential), and the results are visible on the second attached document. In the graphs obtained in this experiment, it seems that the entrance of the hammer (ai1) affects the signal of input ai2 and ai7, which are not connected. And the ai4 signal does not seem to influence the other inputs, because he has a different curve on the graph of the FFT.

  The same experiment was conducted using the CSR connection (change threads and create the DAQmx Channel Configuration), but the results were the same as those found using differential connection.

  Finally, if the output of the accelerometer is connected on the ai2, the signal of the other open entries ai4 and ai7 seem to be affected by the signal of the accelerometer on ai2 (last document attached).

  Could you tell me if the problem I encounter is caused by the DAQ card with this information that I gave to you? And if the answer is Yes, do you know if there is a way to avoid this noise create in one entry on the other hand, it please?

  Thank you

  Maybe Ghosting or crosstalk? Just an idea.

• No input signal (4-20 my expected) on NI 9208

  Hello world.

  I'm having trouble getting the analog input signal (4-20 my) using NI 9208 mounted on the cDAQ 9188.

  Here is the configuration:

  -pressure transmitter 2-wire connected (IN: + 24V) (OUT: pin NI 9208 AI6 code) (power from an external source sharing 0V and ground with pin NI 9208 COM)

  - NI 9208: Vsup = + 24V (pin 19 & 37); COM = 0V is GND (PIN 9; 10; 28-29);. AI6 = issuer pin

  [Clip, a drawing of the wiring]

  -Pilot OR DAQmx 9.3

  -10 Labview

  -Windows 7

  Using a DAQ assistant set up to acquire the analog current signal, the value I get on screen is fluctuating between 0.001 and 0.1 my.

  I have inserted a device running on-line measurement between the transmitter OUTPUT pin and the pin of the 9208 AI6, here I actually get the signal 4-20 my.

  As additional information, I measure 28V between Vsup and COM; 0.3V between AI6 and COM; and 27.7V between Vsup and AI6.

  To make it as clear as possible I might add that first, every input channel has been connected to a transmitter, each giving the screen the value of my ~0.01 (ammeter not yet tested on each I-online the next step in my investigation, actually performed). Then I tried to identify the problem to connect to a single issuer (AI6). Result is always the same.

  As the NI 9208 once functionned well a few months earlier, I think that the problem come from a transmitter that can have been wrongly. (I'm actually cheking all connections).

  My question would be: is the 9208 comprises usually this device damaged (ADC?)? Or maybe it seems as if there is something I missunderstand?

  No matter what piece of advice would be greatly welcomed.

  Also, please forgive my English aproximous.

  Thank you for your consideration.

  Adrien QUEUCHE

  Well, that was my mistake. I was reading my where I should have read A...

  To any administrator: the subject may be deleted, I guess. Unless I deserve to be shameful for eternity...

  Thank you.

  Adrien QUEUCHE

• -Data 200141 was replaced before it can be read by the system. Mechanism of data transfer is interrupted, try to use DMA or USB in bulk. Otherwise, divide the input signal before taking the action.

  Hello

  Installation program:

  2 x PCI-6602

  Configuration:

  Sampling the five PWM signals of 50 kHz using five counters (2 on a map) and three on another for about 10-15 seconds by recording continuously.

  All meter tasks are configured for DMA transfer.

  Problem:

  I get 200141 errors from time to time.

  Question:

  I tried to increase the size of buffer and all tasks of meter are set to DMA. In the error message the last suggestion is to "divide the input signal before taking the action. I don't understand this suggestion. What is meant by "split the signal before taking the action?

  I am open to other solutions to the problem.

  /Mola

  Yes, I know that the 2 MB/s sound do not like much, but it's a way of high load very low tolerance to try to get 2 MB/s.  You have 5 DMA controllers to negotiate access to the bus and each transmits only 1 or 2 samples of 32-bit whenever he gets access.

  I've seen published baseline data where the maximum sustained rate was< 1="" million/sec="" (don't="" recall="" if="" it="" was="" mbytes="" or="" msamples). ="" as="" i="" recall,="" finite="" acquisition="" mode="" allowed="" higher="" rates="" for="" shorter="">

  Ah yes, here is a link that leads to the other links.  See the section on "The counter of the FIFO" in the first message.  Do you see a * very * significant difference in the performance of the M series for the series X-series.  Here are data for counters of the E series.  (It is fair to note that the comparative analysis was conducted with a much older PC hardware).  For the 6602 counter chip was designed between E- and M-series series, so you can probably expect performance in-between.

  Also note that the benchmarks seem to have been done with a task of window unique tent of owning all the bandwidth PCI as possible.  Since you would have 5 tasks they negotiate access, you lose definitely even more overhead.  In addition, for fair comparisons, your 50 kHz PWM would act as a measure of 100 kHz since you have 2 semiperiods to DAB per cycle of 50 kHz.

  Now that I've seen benchmarks once again, I am convinced that it is a no-go for you with just the 6602.  The good news is that the series X-series seem able to yet more ridiculously than I remembered.

  -Kevin P

• The NI 9215 input signal voltage

  Hi all

  I tried to test NI 9215 BNC in MAX. And the acquisition of data took place without input signal.

  The voltage for all 4 channels, I read is about 10.4 Volt.

  Is this fair? I thought, the voltage should be 0 without input signal.

  Best regards

  GL

  If you leave the open entry, it will tend to float to one of the rails.  From my experience, it's almost always the top, so the 10.4 volts.

  If you short-circuit the input, you'll get certainly 0 volt.  You will probably get 0 or nearby yew, you put a resistance across the entrance.

• How do I get the analog input signal and send it to output analog (real time)

  Hello world

  I do a simple task in Visual C++ and I use PCI-6221(37 pin).

  Basically, I want to send the same signal of "analog input" to the "analog output".

  at the same time (or almost), to make real-time application.

  Can someone provide me with sample program please.

  I would be grateful if you could provide me with the great tutorial that explains

  step by step everything about NOR-DAQmx for C/C++ programming.

  Best regards

  Khassan

  This is my code in C++, you can optimize it if that seems too messy. This code reads the analog input signals and exports it through the analog outputs.

  To make this code additional work of the directories include and library directories must be added to OR.

  I hope it helps someone.

  #include
  #include
  #include "NIDAQmx.h".
  #include

  #define DAQmxErrChk (functionCall) {if (DAQmxFailed (error = (functionCall))) {goto error ;}}

  int main (int argc, char * argv [])
  {
  Int32 error = 0;
  TaskHandle taskHandleRead = 0, taskHandleWrite = 0;
  Read Int32 = 0;
  float64 context [1000];
  char errBuffRead [2048] = {'\0'};
  char errBuffWrite [2048] = {'\0'};
  bool32 done = 0;
  Int32 wrote;

  DAQmxErrChk (DAQmxCreateTask("",&taskHandleRead));
  DAQmxErrChk (DAQmxCreateAIVoltageChan(taskHandleRead,"Dev1/ai0","",DAQmx_Val_Cfg_Default,-10.0,10.0,DAQmx_Val_Volts,NULL));
  DAQmxErrChk (DAQmxCfgSampClkTiming(taskHandleRead,"",100.0,DAQmx_Val_Rising,DAQmx_Val_ContSamps,0));
  DAQmxErrChk (DAQmxCreateTask("",&taskHandleWrite));
  DAQmxErrChk (DAQmxCreateAOVoltageChan(taskHandleWrite,"Dev1/ao0","",-10.0,10.0,DAQmx_Val_Volts,NULL));
  DAQmxErrChk (DAQmxCfgSampClkTiming(taskHandleWrite,"ai/SampleClock",100.0,DAQmx_Val_Rising,DAQmx_Val_ContSamps,1000));

  DAQmxErrChk (DAQmxStartTask (taskHandleRead));
  DAQmxErrChk (DAQmxStartTask (taskHandleWrite));

  While (! fact &! _kbhit())

  {

  DAQmxErrChk (DAQmxReadAnalogF64(taskHandleRead,1,10,DAQmx_Val_GroupByScanNumber,dataRead,1000,&read,));

  DAQmxErrChk (DAQmxWriteAnalogF64(taskHandleWrite,read,0,10.0,DAQmx_Val_GroupByChannel,dataRead,&written,));

  }
  _getch();

  Error:
  If (DAQmxFailed (error))

  {
  DAQmxGetExtendedErrorInfo (errBuffRead, 2048);
  DAQmxGetExtendedErrorInfo (errBuffWrite, 2048);
  }
  If (taskHandleRead! = 0)

  {

  DAQmxStopTask (taskHandleRead);
  DAQmxClearTask (taskHandleRead);
  }
  If (taskHandleWrite! = 0)

  {

  DAQmxStopTask (taskHandleWrite);
  DAQmxClearTask (taskHandleWrite);
  }
  If {(DAQmxFailed (error))
  printf ("error DAQmx: %s\n",errBuffRead); ")
  printf ("error DAQmx: %s\n",errBuffWrite); ")
  }
  printf ("end of the program, press the Enter key to quit\n");
  GetChar ();
  return 0;
  }

• Realization of comparator: constant double input signal - waveform, threshold.

  Hello

  How achieve the comparator, where the input signal's waveform type (from data acquisition) and the threshold is a double constant.

  These two types are incompatible, then a conversion must be made. Which one?

  Thank you

  Pavel

  
  

• Should I reset the FPGA FFT when changing the input signal?

  Hello

  I have an application based FlexRIO where I do FFT on several incoming signals. The signals will be ranked so that I get first for example 4096 samples of Ch1 and Ch2 4096 samples, etc. This means that I don't have to do it in parallel of the FFT and I would like to reuse the implementation of FFT and windowing to reduce the use of resources.

  I intend using the VI Express followed by the Express VI of FFT window scaling

  http://zone.NI.com/reference/en-XX/help/371599J-01/lvfpga/fpga_scaled_window/

  http://zone.NI.com/reference/en-XX/help/371599J-01/lvfpga/fpga_fft/

  and I'll use them inside a SCTL.

  This figure comes from the section using the FFT and help illustrate the issue:

  

  There is a discount to zero terminal for the fenestration and the FFT VI.

  Are there internal registers in the windowing and FFT which force the image 1, image 2,... from the same signal or is it possible for the first entry in a framework of Ch1, the next frame belonging to Ch2, Ch3 gaze and so on and always get reliable results?

  Another way to ask the same question: if I have to reset the window and FFT when changing the input signal?

  Thank you

  Anders

  Hi Cyphish,

  When using the FFT of the LabVIEW FPGA vi express and windows nationwide express vi calculations are make it point by point so there will be no problem when going through different types of measures. Therefore, you should have no problem with your application.

  Best regards

  Menelaos.K